1. A 146 kg cubic tiger began with an initial velocity of -22 m/s [N] and, while moving away from the origin, accelerated at -0.43 m/s² [N] and moved -407 m [N]. What was the final velocity of the tiger?

Answer:

1mph

Explanation:

Answer:

The answer is "[tex]1.6\ \frac{m}{s}[/tex]"

Explanation:

Distance= 0.72 meter

time= 0.45 second

The formula for horizontal velocity:

[tex]horizontal \ velocity = \frac{distance}{time}\\\\[/tex]

                               [tex]=\frac{0.72}{ 0.45}\\\\= 1.6 \ \frac{m}{s}\\\\[/tex]

Answer:

x^2 =5^2+3^2

25+9

=

[tex] x = \sqrt{34} [/tex]

Answer:

9km isquare + 25km isquare

34km isquare

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass

v is the velocity

From the question we have

[tex]k = \frac{1}{2} \times 30 \times {15}^{2} \\ = 15 \times {15}^{2} \\ = {15}^{3} \: \: \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer: it’s c

Explanation:

Answer:

K.Eₓ = 4 K.E

K.Eₓ = 9 K.E

Explanation:

Th formula for the kinetic energy of a body is given as follows:

[tex]K.E = \frac{1}{2}mv^2\\[/tex]   ---------------equation (1)

where,

K.E = Kinetic Energy of Automobile

m = mass of automobile

v = speed of automobile

For twice speed:

vₓ = 2v

then,

[tex]K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(2v)^2\\K.E_{x} = 4\frac{1}{2}mv^2\\[/tex]

using equation (1):

K.Eₓ = 4 K.E

For thrice speed:

vₓ = 3v

then,

[tex]K.E_{x} = \frac{1}{2}mv_{x}^2\\K.E_{x} = \frac{1}{2}m(3v)^2\\K.E_{x} = 9\frac{1}{2}mv^2\\[/tex]

using equation (1):

K.Eₓ = 9 K.E

A. The kinetic energy of automobile when it moves at twice the speed is 8000 J

B. The kinetic energy of automobile when it moves at three times the speed is 18000 J

Let the mass of the automobile be constant.

Let the initial velocity be v

A. Determination of the kinetic energy of the automobile when it moves at twice the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (2v)²

2000 / v² = KE₂ / 4v²

Cancel out v²

2000  = KE₂ / 4

Cross multiply

KE₂ = 2000 × 4

KE₂ = 8000 J

B. Determination of the kinetic energy of the automobile when it moves at three times the speed.

KE₁ /v₁² = KE₂ / v₂²

2000 / v² = KE₂ / (3v)²

2000 / v² = KE₂ / 9v²

Cancel out v²

2000  = KE₂ / 9

Cross multiply

KE₂ = 2000 × 9

KE₂ = 18000 J

Learn more about kinetic energy:

https://brainly.com/question/10703928

Answer:

D

Explanation:

Answer:

increase

Explanation:

Answer:

Increase

Explanation:

A force that acts on an object causes the object to accelerate.

F=ma

When mass is kept constant, force is directly proportional to the acceleration. Meaning that if the force increases, the acceleration increases, and if force decreases the acceleration decreases.

When force is kept constant, acceleration is inversely proportional to mass.

Meaning that when the mass of the objet increases, the acceleration of the object will decrease, and if the mass of the object decreases, the acceleration will increase.

Hope this helped!

Answer:

weight hung from the spring

Explanation:

An "independent variable" refers to the variable that is being changed or manipulated in an experiment. This is being done in order to check its impact on the "dependent variables." The independent variable does not rely on any other variables.

In the experiment above, the independent variable is the "weight." This variable is being manipulated in order to know how far the spring will stretch. This is the reason why there are five different weights, which means there will be five different distances expected to be covered by the spring.

Answer:

water, it's usually because it's just the easiest to use, but yeah it's water

Answer:

D

Explanation:

Change in speed or direction is acceleration

An object accelerates when it is moving faster. Option A is corect.

The rate of velocity change concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.

The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.

[tex]\rm a = \frac{v-u}{t}[/tex]

Where,

u is the initial speed in m/sec

v is the final speed in m/sec

t is the time interval in sec

a is the acceleration in m/sec²

When an object is accelerating it speeds up.

Hence option A is correct.

To learn more about acceleration, refer to the link;

https://brainly.com/question/2437624

#SPJ2

Answer:

430.5 cm

Explanation:

first we detect point digt than

323+100+6

=429

now point digt

0.7+0.6

1.5

add both:-

429+1.5

=430.5

Answer:

[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.

Explanation:

hope this helps :)

Answer:

Lessens

Explanation:

The performance of an engine at high altitudes is lower due to the decreasing density of air with elevation, such that at high altitude, the density is much less and a given quantity of oxygen occupies much more space at high altitudes, and the oxygen content in the air drawn in is lesser at high altitude, and the combustion power is much lesser at high altitudes when the engine speed is high up to about 4000 rpm.

Answer:

500 J

Explanation:

100 X 6=600

100 X 11=1,100

1,100-600=500J

Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2. Since the zero of gravitational potential energy can be chosen at any point (like the choice of the zero of a coordinate system), the potential energy at a height h above that point is equal to the work which would be required to lift the object to that height with no net change in kinetic energy. Since the force required to lift it is equal to its weight, it follows that the gravitational potential energy is equal to its weight times the height

Gravitational potential energy is the potential energy with respect to the gravitational force. To possess gravitational potential energy, the object to be placed in a position in the gravitational field.

Potential energy of body is the energy generated by virtue of the position of the body. Whereas kinetic energy is generated by virtue of its movement.

Potential energy and kinetic energy together called as mechanical energy. The potential energy p is mathematically expressed as p = mgh. Where g s gravity, h is height and m is the mass.

The gravitational potential energy is arised in an object due the position in gravitational field. It changes with the change in position and change in height from the ground. A change in mass also alter the gravitational potential energy.

To find more on potential energy, refer here:

https://brainly.com/question/24284560

#SPJ2

Answer:kinetic energy

Explanation:

Answer:

A = 2,

Explanation:

(3 + 2) - 7

2 -  A: 2

3 + 6 + 5

14 - B: 14

YOUR WELCOME

Answer:

[tex]\mathbf{\dfrac{F}{A}= -\dfrac{( \alpha_A + \alpha _B)\Delta T}{\bigg ( \dfrac{1}{Y_A}+ \dfrac{1}{Y_B}\bigg )} }[/tex]

Explanation:

From the information given.

The formula for Youngs modulus(Y) can be illustrated as follows:

[tex]Y = \dfrac{F/A}{\Delta L /L}[/tex]

where;

F = force

A = area

ΔL / L = the fraction of the change that occurred in the length.

If we make ΔL / L the subject of the formula, the above expression can be re-written as:

[tex]\dfrac{\Delta L}{L } = \dfrac{1}{Y}\dfrac{F}{A}[/tex]

However, the total fractional change that occurred in the length can be computed as:

[tex]\dfrac{\Delta L_{compressive \ stress}}{L} = \dfrac{\Delta L_A}{L_A} + \dfrac{\Delta {L_B}}{L_B}[/tex]

where;

[tex]L = L_A = L_B[/tex]

The area of both rods is said to be equal as well.

Thus;

[tex]\dfrac{\Delta L_{compressive \ stress}}{L} = \dfrac{1}{Y_1} \dfrac{F}{A}+ \dfrac{1}{Y_2}\dfrac{F}{A}[/tex]

[tex]\dfrac{\Delta L_{compressive \ stress}}{L} =\bigg( \dfrac{1}{Y_1} + \dfrac{1}{Y_2} \bigg ) \dfrac{F}{A}[/tex] ----- Let this be equation (1)

Recall that:

[tex]\dfrac{\Delta L }{L }= \alpha \Delta T[/tex]

in which

ΔL = change in length

L = the original length of rod before extension

∝ = coefficient of linear expansion

ΔT = temperature change

Similarly:

The total fractional change in the length is:

[tex]\Delta L _{thermal} = \Delta L_A +\Delta L_B[/tex]

[tex]\Delta L _{thermal} = \alpha_AL \Delta T+\alpha_BL \Delta T[/tex]

[tex]\dfrac{\Delta L _{thermal}}{L} =( \alpha_A+ \alpha _B) \Delta T \ \ \ ---(2)[/tex]

The sum of both the thermal and compressive stress of the combined rod is equal to the fractional change.

Mathematically:

[tex]\Delta L_{net} = \Delta L_{thermal} + \Delta L_{compressive \ stress}[/tex]

where;

[tex]\Delta L_{net} =0[/tex]

∴

[tex]0 = \Delta L_{thermal} + \Delta L_{compressive \ stress}[/tex]

[tex]\Delta L_{compressive \ stress} =- \Delta L_{thermal}[/tex]

From equation (1) & (2)

[tex]\bigg( \dfrac{1}{Y_1} + \dfrac{1}{Y_2} \bigg ) \dfrac{F}{A}= - (\alpha_A + \alpha_B) \Delta T[/tex]

Making the stress [tex]\dfrac{F}{A}[/tex] the subject, we get;

[tex]\mathbf{\dfrac{F}{A}= -\dfrac{( \alpha_A + \alpha _B)\Delta T}{\bigg ( \dfrac{1}{Y_A}+ \dfrac{1}{Y_B}\bigg )} }[/tex]

Answer: Yes

Explanation: Yes

Answer:

44.492 kg

Explanation:

Convert pounds to kilograms.

1 lb = 0.454 kg

98 lb * 0.454 kg =44.492 kg

Answer:

what he said above is correct yes

Explanation:

Answer:

a, b, a, c, that should be the order from top to bottom

Answer:

C maybe

Explanation:

A bungee jumper hangs from a bungee cord with zero velocity. If the bungee cord has a spring constant of 18 N/m and the jumper has a mass of 113 kg, he streched 6.27 m.

The zero-velocity surface is a concept that relates to the N-body problem of gravity. It represents a surface a body of given energy cannot cross, since it would have zero velocity on the surface.

It was first introduced by George William Hill. The zero-velocity surface is particularly significant when working with weak gravitational interactions among orbiting bodies.

For the purpose of locating Lagrange points, the zero-velocity surface is another crucial factor. In the rotating coordinate system, these points correspond to places where the apparent potential is extreme.

Therefore, A bungee jumper hangs from a bungee cord with zero velocity. If the bungee cord has a spring constant of 18 N/m and the jumper has a mass of 113 kg, he streched 6.27 m.

To learn more about zero velocity, refer to the link:

https://brainly.com/question/18634403

#SPJ2

Answer:

Face - off

Explanation:

Face - off is a term used in ice hockey to start periods of play and also to restart the play/action after a previous stoppage.

This face - off involves two opposing players from the 2 opposing teams standing opposite each other at an approximate distance of one sticks blade with the game official dropping the puck between them. Thereafter, two players will then to try to gain possession of the puck.

During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.

Answer:

See the answer below.

Explanation:

The weight of the table should be equal to the weight of the table plus the weight of the book.

[tex]w_{table}=m_{table}*g\\w_{table}=200*9.81\\w_{table}=1962[N][/tex]

And for the book

[tex]w_{book}=m_{book}*g\\w_{book}=50*9.81\\w_{book}=490.5[N][/tex]

And the total weight

[tex]w = w_{table}+w_{book}\\w=1962+490.5\\w = 2452.5 [N][/tex]

For the system to be in balance, the reaction force exerted by the table on the book must be equal to the weight of the book. This force in physics is known as the normal force.

[tex]N_{force} = w_{book}\\N_{force}=490.5[N][/tex]