1. A mountain climbing expedition establishes a base camp and two intermediate camps, A

and B. Camp A is 11,200 m east of and 3,200 m above base camp. Camp B is 8,400 m

east of and 1,700 m higher than Camp A. Determine the displacement between base camp

and Camp B.

Answers

Answer 1

Answer:

Explanation:

The diagram showing the illustration of the question is shown on the first uploaded image

Here G represents the base

So the displacement in the x -axis is mathematically represented as

[tex]X = 11200 + 8400 = 19600 \ m[/tex]

The displacement in the y -axis is mathematically represented as

[tex]Y 3200 + 1700 = 4900 \ m[/tex]

Generally the resultant displacement is

[tex]R = \sqrt{ X^2 + Y^2}[/tex]

[tex]R = \sqrt{ 19600^2 + 4900^2}[/tex]

[tex]R = 20200\ m [/tex]

Generally the direction of this resultant displacement is mathematically represented as

[tex]\theta = tan ^{-1} [\frac{Y}{X} ][/tex]

=>       [tex]\theta  =  tan ^{-1} [\frac{4900}{19600} ][/tex]

=>            [tex]\theta  = 14.03 ^o  [/tex]

Hence the direction is  [tex]14.03 ^o[\tex] from the horizontal axis

 

1. A Mountain Climbing Expedition Establishes A Base Camp And Two Intermediate Camps, Aand B. Camp A

Related Questions

what role does animals play in carbon cycle? and how does carbon cycle flow through earth?

Answers

Animals that eat plants digest the sugar molecules to get energy for their bodies. Respiration, excretion, and decomposition release the carbon back into the atmosphere or soil, continuing the cycle. The ocean plays a critical role in carbon storage, as it holds about 50 times more carbon than the atmosphere.

A blimp is moving 10 m/s East when it begin so acceelation towards the East of 2 m/^2. how far will it go in 5 s?
A. 225m
B. 75m
C. 90m
D. 125m

Answers

Answer:c

Explanation:

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.45 m/s in 3.02 s. Assuming that the player accelerates uniformly, determine the distance he runs.

Answers

Recall that average velocity v is given by

v = ∆x/∆t

where ∆x is displacement and ∆t is time.

Under constant acceleration, average velocity is also equal to the average of the initial and final velocities,

v = (v₂ + v₁)/2

The player starts at rest, so v₁ = 0, and speeds up to v₂ = 5.45 m/s in a matter of ∆t = 3.02 s. So

x = (v₂ + v₁) ∆t / 2

x = (5.45 m/s) * (3.02 s) / 2

x ≈ 8.23 m

Compute the total possible energy released from an annihilation of x-grams of anti-matter and the same quantity of matter, where x is the last two digits of your SS# or DL#. (20 points) –Use the famous Einstein’s formula for mass-energy equivalence •Compute the power output of this annihilation when the energy is released in x ns, where x is again the first two digits of your SS# or DL#. (10 points) •Compute how many cups of gasoline (8MJ) this energy corresponds to. (5 points) •Compute how many months of world electricity usage (3.6GJ/mo) this energy corresponds to. (5 points)

Answers

Answer:

i)  8.82 * 10^15 J

ii) 1.8 * 10^23 watts

iii) 1.102 * 10^9 number of cups

iv) 2.450 * 10^6  number of months

Explanation:

i)Total possible energy released

Mtotal = x + x

          = 2x * 10 ^-3 kg

when we apply the famous Einstein's formula for mass-energy equivalence

E = Mtotal * c^2

c = speed of light in free space = 3 * 10^8 m/s^-1

x = 49 g

therefore the Total energy released

E = ( 2 * 49 * 10^-3 ) * ( 3* 10^8 ) ^2  =  8.82 * 10^15 J

ii) power output

x in ns = 49 * 10^-9 s

therefore energy released per sec = Total energy released / 49 * 10^-9

= (8.82 * 10^15 ) / ( 49 * 10^-9 ) = 1.8 * 10^23 J

hence power output = 1.8 * 10^23 J  * s^-1  = 1.8 * 10^23 watts

iii) Calculate the number of cups

Total energy obtained in a cup  = 8 MJ = 8* 10^6 J

number of cups required to match of the Total energy released

n = Total energy released / energy obtained in a cup

  = ( 8.82 * 10^15 ) / ( 8 * 10^6 ) = 1.102 * 10^9 number of cups

iv) Calculate the number of months

n = Total energy released / energy obtained in a month

  = (8.82 * 10^15 ) / ( 3.6 * 10^9) = 2.450 * 10^6  number of months

1.The amount of food inside a bowl is an example of what? Mass or weight*
2. How much gravity is pulling down on a dog is an example of the dogs what?
Weight or mass

Answers

Answer:

1. Mass

2. Weight

Explanation:

1. All the physical quantities that exist in the universe that have mass, are measurable because they can be measured on instruments such as scales. For this example, the amount of food can be measured on a scale and its mass determined in grams or ounces.

2. When we talk about a mass of a body influenced by gravity we are talking about weight, weight is a force that points in the direction of Earth's gravitational acceleration. That is, weight depends on the gravitation that interacts with the body. For the example we have that the weight of the dog is equal to the product of the mass of the dog by the gravity of the Earth.

Earths gravity acts upon objects with a steady force of

Answers

Answer:

9.8 m/s²

Explanation:

Earths gravity acts upon objects with a steady force of  9.8 m/s². The force of gravity is attractive in nature. It acts between two objects. It always acts towards the ground. The force off gravity is given by :

F = W = mg

m is mass of the object and g is the acceleration due to gravity. The value of g is 9.8 m/s². Hence, Earth's gravity acts upon objects with a steady force of  9.8 m/s².

Answer:

the answer is actually D. 9.8 meters per second squared

Explanation:

I took the quiz.. please mark brainliest. Also hope you get it correct;)

Question 1: Explain how stars are formed.​

Answers

Star formation begins when the denser parts of the cloud core collapse under their own weight/gravity.

I have 22 electrons; how many protons and neutrons do I have?

Answers

Answer:

11 electrons & 11 neutrons

Explanation:

A example of a substance that has low pH is

A. Lemons, which have a pH of 2
B. Lemons, which have s pH of 12
C. Soap, which has a pH of 0
D. Lemons, which have a pH of 10

Answers

Answer:

lemons, which have a pH of 2 choice a

an object moves 12m to the right. if its acceleration was 2m/s2 and its final velocity is 25m/s, find it initial velocity.

Answers

Na a absbsbsbshawugshsbs sds

Will get 15 points AND IF. YOU ANSWER. BEST OUT OF 2. I WILL give. brainliest
Question 1 : According to the Law of Inertia, an object at rest will stay (remain) at rest unless acted upon by a(n) ____ .

force
person
gravity alone
another object at rest

Question 2: The tendency of an object to resist a change in its motion is called ________.
gravity
motion
velocity
inertia

Questions 3: An object at rest has a velocity of ___.
-2.5 m/s north
2.5 m/s east
3.5 m/s east
0

Answers

Answer:

question  1: force

question 2: velocity or inertia

question 3: 0

A.) A bullet accelerates at 8000 m/s2

as it

is fired from a 1.6m rifle. How much

time will it take to clear the barrel?

B.) How much velocity does that rifle
impart on the bullet?

Answers

Answer:

0.02 s

160 m/s

Explanation:

Given:

Δx = 1.6 m

v₀ = 0 m/s

a = 8000 m/s²

A) Find t.

Δx = v₀ t + ½ at²

1.6 m = (0 m/s) t + ½ (8000 m/s²) t²

t = 0.02 s

B) Find v.

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (8000 m/s²) (1.6 m)

v = 160 m/s

Quadrilateral A has side lengths 3, 4, 5, and 6. Quadrilateral B is a scaled copy of Quadrilateral A with a scale factor of 2. Select all of the following that are side lengths of Quadrilateral B. 5 6 7 8 9

Answers

Answer: 6 and 8 would be side lengths because if it has a scale factor of 2 then you multiply the ones on the chart.

Explanation:Go find one

The more threads a screw has the greater the holding power of the screw

true or false

Answers

Answer:

true

Explanation:

Answer:true

Explanation:

A ship with an initial speed of 6.23 m/s approaches a dock that is 255 m
away. If the ship accelerates uniformly and comes to rest in 82 s, what is
its acceleration?

Answers

Answer:

a = 0.0761 [m/s^2]

Explanation:

This problem can be solved using kinematics equations, and by means of the following equation:

[tex]x=x_{0} +v_{0}*t-(\frac{1}{2} ) *a*t^{2}[/tex]

where:

Xo = initial location = 0

x = final location = 255 [m]

Vo = initial velocity = 6.23 [m/s]

t = time = 82 [s]

a = aceleration [m/s^2]

Since the ship slows down to rest, the last expression of the equation will be taken with a negative sign

255 = 0 + (6.23*82) - (0.5*a*82^2)

255 - (6.23*82) = - 3362*a

a = 0.0761 [m/s^2]

A car is going 24.6miles per hour what is this in meters per second?

Answers

Answer:

11 m/s

Explanation:

1 mile= 1609.3 m

Hence, 24.6 miles= 39589.8 metres

1 hour=3600 seconds

Hence, [tex]\frac{24.6 miles}{hour} \\=\frac{39589.5 metres}{3600 seconds} \\=10.99[approx. 11 m/s}[/tex]

i’ll give brainliest answer to correct one, please help

Answers

Answer:

i believe its D because he is not sliding and he is applying force on the wall

Explanation:

hope this helps plz mark brainliest

why do we breath air?

Answers

Answer:

We breath air for us to supply oxygens in terms of functioning the circulatory system because oxygen can be transported as blood. We breath air because it has many minerals in it.

Explanation:

Help ASAP). Describe the Net Force lab and explain what the lab demonstrated?​ Will Mark Brainliest. Working on it now can someone please help ​

Answers

Answer: The net force acting on an object is the sum of all the force acting on it, and the net force of an object is zero. I f the forces acting on it tend to cancel each other. For example you are sit in a chair, the earth's gravity is pulling you down, but the chair is pushing you up with an equal amount of force.

There is my answer from my notebook .I hope its good :)

How is mass and weight differentiated?

Answers

Explanation:

The mass of an object is a measure of the object's inertial property, or the amount of matter it contains.

The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it.

What happens in a tug of war if the net forces are balanced and why?

Answers

Answer:

Balanced forces are responsible for unchanging motion. Balanced forces are forces where the effect of one force is cancelled out by another. A tug of war, where each team is pulling equally on the rope, is an example of balanced forces. The forces exerted on the rope are equal in size and opposite in direction.

Explanation:

The brakes of an automobile can decelerate it at -4.7m/s^2. If the automobile is traveling at the rate of 31.0m/s How far will it travel after the brakes are applied before it stops?

Please help!!!

Answers

Answer:

204.5 m

Explanation:

a = v \ t

t = v \ a

t = 31 \ 4.7 = 6.6s

v = d \ t

d = v * t

d = 31 * 6.6

d= 204.5 meters

When listening to someone in trouble, you should be

Answers

This depends on the situation, but listen to the person and find a solution I guess

A bowling ball is dropped on a moon from the height of 14 m. The acceleration of gravity on the moon is 4 m/s2. Determine the time it took for the ball to crash at the surface. Round your answer to the nearest whole number.

b. 1 s
c. 4 s
d. 3 s​

Answers

Answer:

4sec

Explanation:

Since we know the initial velocity=0, acceleration = -4; and the displacemnt =14, we use the equation d = vi • t + ½ • a • t2. So, just plug in the values and solve for t in this case it's 4 sec

A body is said to be in freefall when it moves solely under the influence of  gravity.

The time it took for the ball to crash at the surface = 3 sec.

What do you mean by the free fall?A body is said to be in freefall when it moves solely under the influence of  gravity. The ball's motion will be accelerated by an external force acting on it. This free-fall acceleration is also known as gravity acceleration.Free fall is a type of motion in which gravity is the only force acting on an object. Objects that are said to be in free fall do not encounter significant air resistance; they fall solely under the influence of gravity.

acceleration of gravity on the moon is 4 m/s^2.

the height of 14 m.

The formula for free fall:

[tex]h= \frac{1}{2}gt^2[/tex]

t^2 = 2h /g = 2 x 14 /4 = 7

t = [tex]\sqrt{7} = 2.65[/tex] sec ≅ 3 sec.

The time it took for the ball to crash at the surface = 3 sec.

To learn more about :   freefall

Ref : https://brainly.com/question/12167131

#SPJ2

The mass of the basketball shown below is 4 times the mass of the baseball.
Basketball
Baseball
If the two balls are moving at the same speed, and the basketball and the baseball has a kinetic
energy of 10.0 J, what is the kinetic energy of the basketball?
2.5 J
5.03
10.03
20.0 J

Answers

Answer:

40.0 Joules. None of the answers is correct

Explanation:

Kinetic energy of an object is expressed as;

KE = 1/2mv² where;

m is the mass of the object

V is the velocity of the object.

Let Ma be the mass of the basketball and Mb be the mass of baseball.

If the mass of the basketball shown below is 4 times the mass of the baseball, then Ma = 4Mb

KE of the basket ball = 1/2MaVa²

Va² = 2(KE)a/Ma ...... 1

KE of the baseball = 1/2MbVb²

Vb² = 2(KE)b/Mb .......... 2

Since their velocities are the same, hence Va²= Vb²

2(KE)a/Ma = 2(KE)b/Mb

Substituting Ma = 4Mb into the resulting expression.

2(KE)a/4Mb = 2(KE)b/Mb

2(KE)a/4 = 2(KE)b

Given Kinetic energy of baseball (KE)b = 10.0J, the expression becomes;

2(KE)a/4 = 2(10)

2(KE)a = 4*20

2(KE)a = 80

(KE)a = 80/2

(KE)a = 40.0J

Hence the kinetic energy of the basketball is 40.0Joules

Two blocks A and B with mA = 1.7 kg and mB = 0.88 kg are connected by a string of negligible mass. They rest on a frictionless horizontal surface. You pull on block A with a horizontal force of 7.9 N. (a) Find the magnitude of the acceleration (in m/s2) of the blocks. m/s2 (b) Determine the tension (in N) in the string connecting the two blocks. N (c) How will the tension in the string be affected if mA is increased? increase decrease remain the same

Answers

Answer:

A) 3.062 m/s2

B) 2.6946 N

C)  

If ma is increased, acceleration will decrease if the applied force remains fixed

Explanation:

Ma =1.7 kg ( Block A )

Mb = 0.88 kg ( Block B )

Force applied = 7.9 N

a) Calculate the magnitude of acceleration of blocks

F = mass * acceleration

acceleration = Force / mass

mass = ( 1.7 + 0.88 ) = 2.58 kg

Force = 7.9 N

Therefore acceleration = 7.9 / 2.58 = 3.062 N/kg =  3.062 m/s2

B) Tension in the string

Tension in string can be calculated using the relationship below considering the first block

F - T = ma * A

A = 3.062 m/s2

ma = 1.7 kg

F = 7.9 N

Hence Tension (T) = F - ma * A

                               = 7.9 - ( 1.7 * 3.062)

                               = 7.9 - 5.2054 = 2.6946 N

C)  If mA is increased, acceleration will decrease if the applied force remains fixed

Statement A: Area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.
Statement B: Area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.
Since you are not told specific numbers of significant figures to round to, you must use the rules for multiplying numbers while respecting significant figures. If you need a reminder, consult the hint.
Determine the correct relationship between the statements.

Answers

Explanation:

Formula for calculating the area of a  rectangle A = Length *width

For statement A;

Given area of a rectangle with measured length = 2.536 mm and width = 1.4 mm.

Area of the rectangle = 2.536mm * 1.4mm

Area of the rectangle = 3.5504mm²

The rule of significant figures states that we should always convert the answer to the least number of significant figure amount the given value in question. Since 1.4mm has 2 significant figure, hence we will convert our answer to 2 significant figure.

Area of the rectangle = 3.6mm² (to 2sf)

For statement B;

Given area of a rectangle with measured length = 2.536 mm and width = 1.41 mm.

Area of the rectangle = 2.536mm * 1.41mm

Area of the rectangle = 3.57576mm²

Similarly, Since 1.41mm has 3 significant figure compare to 2.536 that has 4sf, hence we will convert our answer to 3 significant figure.

Area of the rectangle = 3.58mm² (to 3sf)

Based on the conversion, it can be seen that 3.6mm²  is greater than 3.58mm², hence the area of rectangle in statement A is greater than the area of the rectangle in statement B.

A person jogs 10 miles, at a speed of 5 mi./h how long did it take ?​

Answers

Answer:

2 hours!!! 5 miles an hour so 10 miles every two hours.

Answer:

We are given that it takes 1/2 an hour for the trip. This is a time:

t = 1/2

We are given that he averages 34 miles per hour. This is a rate:

r = 34

We are asked how few he has traveled. This is a distance. We use the d=rt equation:

d = rt

= (34)(1/2)

= 17

Markus lives 17 miles from work.

Explanation:

hope this will help you

The weight of a box is found to be 30 N. What is the approximate mass of the box?
3 kg
300 kg
120 kg
30 kg

Answers

Answer:

3kg

Explanation:

3kg is the appropriate mass

Answer:

3kg

Explanation:

just took the test

HELP ME!!

Draw a force diagram of the forces acting on a person while sitting in a roller coaster
car as it accelerates up a hill. You may choose the type of restraint.

Answers

Answer:

Honey how can i draw you cant draw here

Explanation:

I wish i can help you

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