What net external force is required to give a 25 kg suitcase an acceleration of 2.2 m/s2 to the right?
Answer:
there are two way to get mate and i gave them sepaert explation
Explanation:
55
N
Explanation:
Using Newton's second law of motion:
F
=
m
a
Force=mass
×
acceleration
F
=
25
×
2.2
F
=
55
N
So 55 Newtons are needed.
Answer link
Nam D.
Apr 6, 2018
55
N
Explanation:
We use Newton's second law of motion here, which states that,
F
=
m
a
m
is the mass of the object in kilograms
a
is the acceleration of the object in meters per second
F
=
25
kg
⋅
2.2
m/s
2
=
55
N
The net external force which is required to give a 25kg suitcase an acceleration of 2.2 m/s² to the right is 55N (Newton).
What is the net external force?The net external force is the vector sum of all the forces which is acting on a system from outside of the system. There may be multiple external forces which are acting on a body or a system of bodies however there will be only one net external force which is the result of all those external forces which are acting on that body or system.
The net external force on the suitcase can be calculated with the formula:
f = m × a
where, f = net external force on the object,
m = mass of the object,
a = acceleration of the object
m = 25 kg
a = 2.2m/s²
f = 25 kg × 2.2 m/s²
F = 55N (Newton)
The net external force is required to have 55N.
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Which of the following has both kinetic and potential energy?
A. A bug crawling on the ground
B. A ball rolling on the ground
C. A hot air balloon flying
D. A book sitting on a shelf
PLEASE HURRY
Answer:
c
Explanation:
The strongman lifts the pig by pulling down at position 1. How will the distance that he pulls down compare to the distance that the pig moves up?
Question options:
The distance that the pig moves up will be more than the distance that the strongman pulls down.
The distance that the pig moves up will be the same as the distance that the strongman pulls down.
The distance that the pig moves up will be less than the distance that the strongman pulls down.
It is impossible to tell from this picture.
Answer:
C
Explanation:
The distance that the pig moves up will be less than the distance that the strongman pulls down.
Explanation: The strongman is further from the fulcrum than the pig is, so the distance that he pulls down will be greater than the distance that the pig moves up.
The distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.
The given problem is based on the work done by the applied force. When some magnitude of force is applied on any object, then there will be some obvious displacement of object. This is known as work done by the object. The expression for the work done by the object is,
w = Fd
here, F is the applied force and d is the displacement.
In the given problem, the applied force will be due to the weight of man and pig. So, the modified form of work done is,
work = Wd
W = work/d
here, W is the weight.
Clearly, more the weight, less will be the displacement and vice versa. So due to heavy weight of man, he will pull the pig easily. Such that the upward distance covered by pig will be less than the distance that the strongman pulls down.
Thus, we can conclude that the distance that the pig moves up will be less than the distance that the strongman pulls down. Hence, option (C) is correct.
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The number of particles outside the nucleus in the neutral atom will always equal to…?
Answer:
2,8,8
Explanation:
im not sure really what you asking but is it this the shells
What are used for manufacturing paper along with chemical
Answer:
Dry-strength additives, or dry-strengthening agents, are chemicals that improve paper strength normal conditions. These improve the paper's compression strength, bursting strength, tensile breaking strength, and delamination resistance. Typical chemicals used include cationic starch and polyacrylamide derivatives.
How much work is done when an 8 N force moves a block 7m ?
Answer:
W = 56J
Explanation:
in physics, Work is equal to F*s
then
W = 8N*7m
W = 56J
21. For this table of data, how should the y-axis be labeled (with units)?
force applied (N)
2.5
3.2
4.8
5.4
5.5
6.3
7.6
8.2
displacement (m)
10.75
13.76
20.64
23.22
23.65
27.09
32.00
35.26
O displacement
Om
O force applied
O force applied (N)
O displacement (m)
ON
Answer:
The y-axis would be labeled with displacement (m)
Explanation:
The displacement is dependent on the force applied.
Labels should have what you measure and how your units of measure.
The x-axis would be labeleed with force applied (N)
The y-axis would be labeled with displacement (m)
I have no idea what the answer to this is
PLSS HELP ASAP
two trains are moving on parallel railways with the same direction. Width of first train is 200meters and
speed 36km/h, second - 400meters speed 108km/h. Find the time, when second train paasses first.
a) 40sec
b) 50sec
c) 60sec
d) 30sec
e) Osec
Answer:d) 30 sec
Explanation:
please answer 11-13. say if i'm right for 10 if you can.
What is the unit for work? watt joule newton meter
Answer:
Joule
Explanation:
Joule is the SI unit of work or energy.
Answer:
joule
Explanation:
edge2020
If the density of water is 1 gram/cm3, this means that the mass of 100 cm3of water should be
Answer:
100 g
Explanation:
Or 0.1 kilograms, just count
If the density of water is 1 g/cm³, the mass of 100cm³ of water should be 100g.
DENSITY:
The density of a substance is its mass in relation to its volume. According to this question, the density of water is 1 g/cm³. This means that for every 1g (mass) of water, there contains 1cm³ (volume) of solvent. Hence, for 100cm³ of water, there should be a mass of 100g of water considering the density of water.Learn more at: https://brainly.com/question/14940265?referrer=searchResults
an electric fire is connected to a 240V supply and transfers energy at a rate of 1.0kW
how much energy passes through the fire on 1.0 h?
A) 42C
B) 250C
C) 1.5 × 10⁴C
D) 2.4 × 10⁵C
I will mark brainliest if answer is correct!
Answer:
(c) 1.5 x 10^4 C
Explanation:
we have,
P=1kW=1000w
V=240V
therefore,
P=V *I
1000=240*I
I=1000/240
I=25/6A
now,we know that
I =Q/T
Q=IT
Q=25/6*60*60. [since time =1hour i.e 60*60sec]
Q=15000C
Q=1.5 x 10^4C
The required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
Given data:
The voltage supply of the electric fire is, V' = 240 V.
The rate of energy transfer is, E' = 1.0 kW = 1000 W.
The time interval is, t = 1 h = 60 × 60 = 3600 s.
In this problem, the energy passes through the fire is nothing but the electric charges. For that we need to calculate the value of charge. So, first calculate the current flow as,
E' = V × I
Solving as,
1000 = 240 × I
I = 1000/240
I = 4.167 A
Now, the energy passes through the fire is obtained as,
Q = I × t
Q = 4.167 × 3600
[tex]Q = 1.5 \times 10^{4} \;\rm C[/tex]
Thus, we can conclude that the required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
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HELP ASAP!! WILL TRY TO GIVE BRAINLIEST
How are ribosomes different from other complex animal cell organelles?
Answer:
Ribosomes are the protein factories of the cell. Composed of two subunits, they can be found floating freely in the cell’s cytoplasm or embedded within the endoplasmic reticulum. Using the templates and instructions provided by two different types of RNA, ribosomes synthesize a variety of proteins that are essential to the survival of the cell.
Hopefully, this helped! :D
Can someone spell the word hi for me I’ll give you 30 points
Answer:
hi poop
Explanation:
"Hi"
its spelled with an H & an I :^
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Answer:
The tangential velocity of a rotating object is:
v = r*w
where r is the radius, and w is the angular velocity.
w = 2*pi*f
where f is the frequency.
We know that the record plater does 11 revolutions in 20 seconds, then it does:
11 rev/20s = 0.55 rev/s = f
then we have:
w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1
The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.
then the tangential velocity is:
v = 10in*3.454 s^-1 = 34.54 in/s
A cyclist travels at 7 m/s and has a mass of 75 kg. Calculate the kinetic energy of the
cyclist.
3,675 )
262.5
1,837.5)
525 )
Answer:
1837.5 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 75 \times {7}^{2} \\ = 37.5 \times 49 \\ = 1837.5[/tex]
We have the final answer as
1837.5 JHope this helps you
4. What does the law of gravity state ?
Answer:
every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Explanation:
Answer: Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them
Explanation: More of a simple answer is a law stating that any two masses attract each other with a force equal to a constant (called the gravitational constant) multiplied by the product of the two masses and divided by the square of the distance between them.
a
2. A man standing
standing 150m before
a tower fires
gun and heard the echo 0.9 second later. Calculate the speed of the sound
Hello! For this excersice let's applicate the formula:
[tex]\boxed{\boxed{d=vt}}[/tex]
Data:
d = Distance = 150 m
v = Velocity = ¿?
t = Time = 0,9 s
Now, let's replace according the formula:
[tex]\boxed{150 \ m = v * 0,9 \ s}[/tex]
Clear v:[tex]\boxed{\dfrac{150 \ m}{0,9 \ s} = v}[/tex]
Resolving:[tex]\boxed{166,67 \ m/s = v}[/tex]
The velocity is 166,67 meters per second.
The speed of the sound will be "16.67 m/s".
The given values are:
Distance,
D = 150 mTime,
T = 0.9 secondAs we know,
→ [tex]Distance = Speed\times Time[/tex]
or,
→ [tex]Time = \frac{Distance}{Speed}[/tex]
By substituting the values, we get
→ [tex]= \frac{150}{0.9}[/tex]
→ [tex]= 16.67 \ m/s[/tex]
Thus the above is the appropriate answer.
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[Please help :^)]
Hello! I have a kinetic and potential energy project due soon, and I need to write a paragraph about that stuff, but I’m not really sure how to write the paragraph. If you can, please write a paragraph that I can rephrase and use. Thank you!!
Answer:
the potentail of kinetic and potential energy
Explanation:
first explain the concept of kinetic energy (what it is and what its used for) and give examples (cars, a basketball thrown across a hall, and airplane), and do the same with potential energy (the energy an object stores, example: a streched rubber band)
23x45 =? come here yall;) carter,kelsee, and nico
23×45=1035
Explanation:
first you multiply 5 and 3 you would get 15 tou drop the 5 and bring the 1 on top of 2 then you multiply 5 by 2 you get 10 then add 1 you get 11. once your Don's you would get 115. once your done with that cross out the five and then multiply 4 by 3 wich equals 12 drop the 2 under five and then bring 1 on top of 2 and then multiply 4 by 2 wich equals 8 and then add one and you get 9.
Tomas wants to paint his bedroom. He goes to the store and buys two cans of paint.
Which simple machine would make it easier for him to open the cans?
A a lever
B. a pulley
C. an inclined plane
D. a wheel and axle
Answer:
I think the answer is c
Explanation:
I had this problem once
An object is thrown into the air at 60m/s, straight up. What is its velocity at the highest point?
Explanation:
Whenever an object is at its highest point, the velocity and acceleration of the object is zero.
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Answer:
15 m/s
Explanation:
Given:
F = 0.7N m = 0.25g = 0.0025kg x = 40cm = 0.4m [tex]v_{0}[/tex] = 0
Since F = ma, a = F/m = 0.7N/0.0025kg = 280m/[tex]s^{2}[/tex]
Using the Big Five, [tex]v ^{2} = v_0^{2} + 2ax[/tex], [tex]v = \sqrt{0 + 2*280m/s^2*0.4m} = \sqrt{216} m/s= 15m/s[/tex]
We have that for the Question it can be said that the speed of the marshmallow as it leaves the pipe is most nearly
v=15m/s
From the question we are told
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Generally the equation for the acceleration is mathematically given as
[tex]a=\frac{Force}{mass}\\\\a=\frac{F}{m}\\\\Therefore\\\\a=\frac{0.75}{0.0025}\\\\a=280m/s^2\\\\[/tex]
Using Newtons
V^2=u^2+2as
V^2=2(280)*0.4
v=15m/s
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i will mark brainliest if your answer is correct!
The electromotive force (∈) = 2 V
Further explanationGiven
I=2 A
t = 30 s
E = 120 J
Required
The electromotive force (∈)
Solution
The electromotive force : the potential difference between two electrodes in galvanic cell
Can be formulated :
[tex]\tt \epsilon=\dfrac{E}{Q}[/tex]
E = energy, J
Q = charge , Coulomb = i.t
[tex]\tt \epsilon=\dfrac{120~J}{2~A\times 30~s}\\\\\epsilon=2~V[/tex]
Answer:
The electromotive force (∈) = 2 V
Further explanation
Given
I=2 A
t = 30 s
E = 120 J
Required
The electromotive force (∈)
Solution
The electromotive force : the potential difference between two electrodes in galvanic cell
Can be formulated :
E = energy, J
Q = charge , Coulomb = i.t
Explanation:
A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the
final velocity of the boy and the skateboard.
Answer:
The velocity of the boy and the skateboard is 24
The Demon Drop ride at the amusement park falls freely for 1.8 s after
starting from rest.
What is its displacement the end of 1.8 s?
Answer:
Explanation:
a = -g = -9.80 m/s squared
d o = 0
v o = 0
t = 1.8s
unkown:d = ?
v = ?
A kilogram is a unit of mass and when multiplied by meters per second
squared which are the units of acceleration, it yields a derived unit known as a
Answer:
it yields a derived unit known as Newton, which is the unit of Force.
Explanation:
The formula for force is given by Newton's Second Law, which states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body in the direction of force.
[tex]F = ma\\[/tex]
where, F = Force
m = mass
a = acceleration
Now, we substitute the respective S.I units of each quantity in equation:
F = Newton (N)
m = kilogram (kg)
a = acceleration = m/s²
Therefore,
[tex]N = (kg)(m/s^2)[/tex]
So, it is clear from above expression that:
When kilogram is multiplied by meter per second squared, it yields a derived unit known as Newton, which is the unit of Force.
¡¡first convert revolutions per second to
radians per second by multiplying by
2pi (2). The angular acceleration is
radius*(ang. Velocity)2
.After you find acceleration, force(tension)is just mass∗
accel. >>
An athlete whirls an 8.45 kg hammer tied
to the end of a 1.4 m chain in a simple horizontal circle where you should ignore any vertical
deviations. The hammer moves at the rate of
0.595 rev/s.
What is the centripetal acceleration of the
hammer? Assume his arm length is included
in the length given for the chain.
Answer in units of m/s
004 (part 2 of 2)
What is the tension in the chain?
Answer in units of N
Answer:
a. 5.23 m/s² b. 44.23 N
Explanation:
a. What is the centripetal acceleration of the hammer?
The centripetal acceleration a = rω² where r = radius of circle and ω = angular speed.
Now r = length of chain = 1.4 m and ω = 0.595 rev/s = 0.595 × 2π/s = 3.74 rad/s.
So a = rω²
= 1.4 m × (3.74 rad/s)²
= 5.23 m/s²
b. What is the tension in the chain?
The tension in the chain, T = ma where m = mass of hammer = 8.45 kg and a = centripetal acceleration of hammer = 5.23 m/s². This tension is the centripetal force on the hammer.
So, T = 8.45 kg × 5.23 m/s²
= 44.23 N
Please answer ASAP for 29 points
Answer:
Explanation:
The answer is B. He needs to count backwards. So if it’s 800,700,600, and 500, you might get the answer right.
