Answer: B) hypothesis
Explanation:
Answer: B) Hypothesis
Explanation:
I got it right
Use an ideal op amp to design a differentiation circuit for which the time constant is 10‐3s usinga 10 nF capacitor. What are the gains and phase shifts found for the circuit at one‐tenth and 10times the unity‐gain frequency? A series input resistor is added to limit the gain magnitude athigh frequencies to 100 V/V. What is the associated 3‐dB frequency? What gain and phase shiftresult at 10 times the unity‐gain frequency?
Answer:
Attached below is the detailed solution
Gains at one-tenth unity gain = 0.1 v/v
Gains at 10 times unity gain = 10 v/v
phase shift at 10 times unity gain =-95.71⁰
Explanation:
a)Gain at one-tenth unity gain
w/Wc = 100/1000 = 0.1 v/v
b)Gain at 10 times unity gain
w / Wc = 10 krad/sec / 1 krad/sec = 10 v/v
3-db frequency of new differentiator = 15.915 khz
attached below is the detailed solutions
Sandstone is a sedimentary rock. Which two processes cause sand particles to form sandstone?
1. cementation and cooling
2.compaction and cementation
3.cooling and erosion
4.erosion and heating
Answer:
Compaction and cementation
Explanation:
Cementation: As ions are deposited by fluids to form a compound that hardens loose sedimentary rocks.
Compaction: As the density of sedimentary rocks on edge of them are forced together through sediments.
Answer:
number 2 is correct
Explanation:
cementation as icons are deposited by fluids to form a compound that hardens looses sedimentary rocks .
compaction is the density of sedimentary rocks on edge of them, are forced together though sediments mark me brainest add and follow me
what are the chemical symbols for carbon aluminium hydrogen oxygen and sodium
El unico que se es el del oxígeno: o2
a coin with a diameter of 2.1 cm with an initial angular speed of 19 rad/sec and rolls in a straight line. The rotation slows at an angular acceleration of magnitude 1.9 rad/s^2. What is the magnitude of the linear acceleration?
Answer:
the magnitude of the linear acceleration is [tex]=1.995 \,\,cm/s^2\\[/tex]
Explanation:
Recall that the linear acceleration (a) is associated with the angular acceleration vi the formula:
[tex]a=R\,\alpha[/tex]
where R stands for the radius of the rotational motion (in our case 2.1 cm/2 = 1.05 cm, and [tex]\alpha[/tex] stands for the angular acceleration in radians per units of time squared.
Then the linear acceleration in our case is:
[tex]a=R\,\alpha\\a=1.05 cm * (1.9\,\,\,rad/s^2)\\=1.995 \,\,cm/s^2[/tex]
What is the displacement of a student who walks 12 m North, 5 m West, 3 m South,
and finally 6 m West to get to his next class?
When you draw all 4 of those moves, you see that he winds up 9m North and 11m West of where he started.
So the magnitude of his displacement is
D = √(9² + 11²) m²
D = √(81 + 121) m²
D = √(202) m²
D = 14.2 m
The direction is arctan(-11/9) = 50.7° west of North
Help please due by 3:00
Answer:
zero
Explanation:
Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.
The acceleration is zero.
Pots A and B both have plain soil, bean seeds, and the same amount of light. Pot B receives more water (see table). After 50 days the plants are measured. Based on the data, what is the correct conclusion?
The amount of water affects the mass and the height of the plants.
What is the correct conclusion from the data obtained?The correct conclusion is the conclusion which the data obtained supports.
Plants need both water and sunlight to grow.
The variation the amount of water or sunlight that a plant receives will affect the growth rate of the plant.
Based on the data obtained from the experiment where Pots A and B both have plain soil, bean seeds, and the same amount of light, while Pot B receives more water, the amount of water affects the mass and the height of the plants.
In conclusion, plants need both water and sunlight for growth.
Learn more about water and sunlight at: https://brainly.com/question/444493
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An example of a Natural electric field is
Answer:
Lightning
Explanation
Assuming all object are moving with the same velocity, witch statement describes the object with the largest intertia?
Answer:
Mass is the quantitative measure of inertia of any object.
Explanation:
The object that have largest mass will have largest inertia as well as largest momentum.
Consider the Bell X-2 research aircraft, which was the first aircraft to achieve Mach 3 on September 27th , 1956. During this flight, the aircraft reached a velocity of 936 m/s at an altitude of 65,500 ft. Calculate the actual Mach number that the X-2 achieved during this flight. Now, consider two other conditions. Condition #1: Assuming the aircraft travels at the same velocity in Jupiter’s atmosphere at an altitude where the temperature is -145 °C. Also, assume that the atmosphere of Jupiter is made up of entirely hydrogen gas (H2) which has a molecular weight of 2.016 g/mol. Calculate the Mach number of the X-2 on Jupiter. Condition #2: Assuming the aircraft travels at the same velocity in Pluto’s atmosphere at an altitude where the temperature is -223 °C. Also, assume that the atmosphere of Pluto’s is made up of entirely nitrogen gas (N2) which has a molecular weight of 28.013 g/mol. Calculate the Mach number of the X-2 on Pluto.
Answer:
Explanation:
mach number is ratio of speed with respect to speed of sound .
speed of aircraft = 936 m /s
speed of sound at 65500 ft = 295 m /s
mach number = 936 / 295 = 3.17
velocity of sound at - 145 degree and in hydrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-145)}{2\times10^{-3}} }[/tex]
= 729 m /s
mach number
= 936 / 729 = 1.28
velocity of sound at - 223 degree and in nitrogen gas .
velocity of sound
[tex]V=\sqrt{\frac{RT}{M} }[/tex]
[tex]V=\sqrt{\frac{8.3\times(273-223)}{28.013\times10^{-3}} }[/tex]
= 122 m /s
mach number
= 936 / 122 = 7.67
question 8 how to do
Answer:
We know that the resistance of a material is its length divided by its cross-sectional area and all that multiplied by its resistivity
Hence, resistance = ρ * length(in m) / Cross-sectional area
(ρ = constant of resistivity)
If you do not understand cross-sectional area, comment on this answer
since both the wires are made of the same substance, both their resistivity will be the same
since we are told that both the wires have the same resistance,
(ρ * length 1) / cross-sectional area 1 = (ρ * length 2) / cross-sectional area 2
since they both have the same resistivity, both the ρ will cancel out
length 1 / cross-sectional area 1 = length 2 / cross-sectional area 2------(1)
Calculating the cross-sectional area
To simplify it , the cross-sectional area is the area of the circle you can currently see on either of the wire
let the radius of wire 1 = 2r
then, the radius of wire 2 = r
Cross-sectional area 1 = π (2r)^2 = 4πr^2
Cross-sectional area 2 = π (r)^2
Now, using these values in (1)
l / 4πr^2 = l' / πr^2
l / l' = 4πr^2/πr^2
l / l' = 4 / 1
the length of rod 'P' is l
from the equation, we can simplify:
l (length of rod 'P') = 4 l'(length of rod 'Q')
Therefore, we can say that the length of rod 'P' is 4 times the length of rod 'Q'
You and your friend Peter are putting new shingles on a roof pitched at 25 ∘ . You're sitting on the very top of the roof when Peter, who is on the edge of the roof, 5.4 m away, asks you for the box of nails. Rather than carry the 2.4 kg box of nails down to Peter, you decide to give the box a push and have it slide down to him. Part A If the coefficient of kinetic friction between the box and the roof is 0.51, with what speed should you push the box to have it gently come to rest right at the edge of the roof?
Answer:
Explanation:
Frictional force acting on the box = mg cos 25 x μ where μ is coefficient of friction
= 2.4 x 9.8 x cos 25 x .51 = 10.87 N
Weight of the box acting along the incline = mg sin 25 = 9.94 N
Net force = 10.87 - 9.94 = .93 N . It will create a deceleration of .93 / 2.4
= .3875 m /s² in the box.
v² = u² - 2 a s
v = 0 , a = .3875 , s = 5.4 m
= = u² - 2 x .3875 x 5.4
u = 2.045 m /s
An object is accelerating uniformly from 8.0 m/s to 16.0 m/s in 10 seconds. How far does the object travel in 10 seconds?
Answer:
Explanation:
Using the equation of motion to get the distance
average Speed =distance/ time
Distance = average speed * time
Distance = (v-u)t
Distance = (16-8)* 10
Distance =8*10
Distance = 80m
Hence the distance covered by the object is 80m
Jason took 6 hours to travel 540 km. For the first 140 km, he
took 2 hours. What was his average speed for the rest of the
journey?
km/h
Answer: 100
Explanation:
Use the picture to answer the question.
A red striped bowling ball with 3 finger holes.
Name at least three physical properties of the bowling ball.
Answer:
The physical properties is hardness shape and color, I choose hardness because I have grabbed bowling balls before and they are very hard well there could be different types of bowling balls made of different things but I have never seen one or toughed a bowling ball that is not hard. Another physical property I chose for the bowling ball was shape, The reason I chose shape was because the bowling ball is circle, the actual name for a 3-D circle is sphere. The last physical property for a bowling ball is color because mostly all bowling balls have color for example the one in the picture it is red with a little bit of pink, there is many different bowling balls that have different color different hardness but NOT different shape. That is the physical properties of a bowling ball.
Explanation:
Answer: The bowling ball is round in shape and red in color. The bowling ball is smooth and hard.
Explanation:
did it on edge
A boat Is headed due north on a river that's flowing directly east. What is the general direction of travel for this boat with respect to the land?
A. southeast
B. northeast
C. northwest
D.
east
Answer:
Its northeast. Just took the exam.
Explanation:
Answer:
See image
Explanation:
Plato
A teenager received a ticket for driving 80 miles per hour. This information describes the teenager's
Answer:
Speed
Explanation:
Ii is given that, "A teenager received a ticket for driving 80 miles per hour.". It doesn't give any information about the direction of motion. It means it represents the speed of teenager. Speed is a scalar quantity. It doesn't have direction.
Hence, the given information describes the teenager's speed.
Answer:
Speed! :)
Explanation:
There is no reference to the direction, which cancels out velocity and direction. In addition, they don't mention the initial speed and the time, so acceleration is out, leaving your answer... SPEED:)
Hope this helps, have a marvelous day!
A radar station sends a signal to a ship which is located a distance 13.9 kilometers from the station at bearing 136° clockwise from the north. At the same moment, a helicopter is at a horizontal range of 19.6 kilometers, at bearing 152° clockwise from the north, with an elevation of 2.57 kilometers. Let east be the î direction, north be the ĵ direction, and up be the direction.
(A) What is the displacement vector (in km) from the helicopter to the ship? (Express your answer in vector form. Do not include units in your answer.)
(B) What is the distance (in km) between the helicopter and ship?
(C) The ship begins to sink at a rate of 5.40 m/s. Write the position vector (in km) of the ship relative to the helicopter as a function of time as the ship sinks. Assume that the helicopter remains hovering at its initial position and that the sinking rate remains the same even after the ship sinks under the surface. (Use the following as necessary: t. Do not include units in your answer.)
(D) Evaluate the position of the ship relative to the helicopter (in km) after 1.90 h. (Express your answer in vector form. Do not include units in your answer.)
Answer:
A) d = 7.9267 km, θ = 157.19
D) d = 35.17 km
Explanation:
For this exercise the easiest way is to decompose the vectors
Ship
X axis (North)
The angle measured from the positive side of the x axis (unit vector i^ ) counterclockwise
θ = 136- 136 = 224
cos θ = x₁ / 13.9
x₁ = 13.9 cosc 224
x₁ = - 9.9988 103 m
z axis
sin 224 = z₁ / 13.9
z₁ = 13.9 sin224
z₁ = -9.6558 m
Axis y
y₁ = 0
Helicopter
x-axis (North)
θ = 360 - 152
θ = 208
cos θ = x₂ / 19.6
x₂ = 19.6 cos 208
x₂ = -17.3058 km
z axis
sin 204 = z₂ / 19.6
z₂ = 19.6 sin 204
z₂ = -7.9720 km
Axis y
y₂ = 2.57 km
It's a bit strange the way the axes give, but having the decomposition of the vectors we can answer the questions
A) They ask the displacement vector, let's start looking for the distance
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
we substitute
d =√[(17.3058 - 9.9988)² + (2.57 - 0)² + (7.9720 -9.6558)²]
d = √ [7.307² + 2.57² + 1.6838²]
d = 7.9267 km
the angle of this vector is with respect to North (x-axis)
cos θ = -7.307 / 7.9267
θ = cos⁻¹ (-0.9218)
θ = 157.19
Y-axis elevation angle
cos θ'= 2.57 / 7.9267
θ’= cos⁻¹ (0.3242)
θ’= 71.09
b) d = 7.9267 km
c) at this time the ship is sinking at constant speed, the sinking direction is the same vertical direction of the helicopter (y-axis)
the distance is
y₁ = v₁ t
let's reduce speed to km /h
v₁ = 5.4 m / s (1km/1000m ) (3600s/1h)= 19.44 km /h
y₁ = 19.44 t
the vector positions is
d = √ [(x₂-x₁)² + (y₂-y₁)² + (z₂-z₁)²]
d = √ [7.307² + (2.57 -19.44 t)² + 1.6838²]
in vertical angle is
cos θ'= (2.57 -19.44t) / d
At an angle to the x axis is
cos θ = -7.307 / d
d) let's evaluate the position for t = 1.90 h
distance
d = √ [7.307² + (2.57- 19.44 1.9)² + 1.6838²]
d = √ [7.307² + (-34.366)² + 1.6838²]
d = 35.17 km
A wildebeest and a chicken participate in a race over a 2.10 km long course. The wildebeest travels at a speed of 19.0 m/s and the chicken can do 3.30 m/s. The wildebeest runs for 1.680 km and then stops to tease the slow-moving chicken, which eventually passes by. The wildebeest waits for a while after the chicken passes and then runs toward the finish line. Both animals cross the finish line at the exact same instant. Assume both animals, when moving, move steadily at their respective speeds.
(a) how far (in m) is the chicken from the Finish Line when the wildebeest resume the race?
(b) for how long in time (in s) was the wildebeest stationary?
Answer:
Explanation:
2.1 km = 2100 m
1.68 km = 1680 m
a ) Time taken by wild beast to travel 1680 m
= 1680 / 19 = 88.42 s
Time taken by wild beast to travel 2100 m
2100 / 19 = 110.52 s
distance travelled by chicken in 88.42 s
= 88.42 x 3.3 = 291.78 s
Its distance from the end point
= 2100 - 291.78 = 1808.22m
b ) Time taken by chicken to travel 2100 m
= 2100 / 3.3 = 636.36 s
Both reach simultaneously so , time of resting by wild beast
= 636.36 - 110.52 = 525.84 s .
A bug walking on the circular rim of a flower
pot completes one lap around the planter in
8.667 s.
If the radius of the planter is 13.9 cm, how
fast was it traveling?
Given parameters;
Time taken to complete a lap = 8.667s
Radius of flower = 13.9cm
convert to SI unit of m, 100cm = 1m
13.9cm gives [tex]\frac{13.9}{100}[/tex] = 0.139m
Unknown = speed
To solve this problem, we need to first find the circumference of the flower.
Circumference of the circular flower = 2 π r
where r is the radius of the flower;
Circumference = 2 x 3.142 x 0.139 = 0.87m
Now to find the how fast the bug is travelling,
Speed = [tex]\frac{distance}{time}[/tex]
Since the bug covered 1 lap, the distance is 0.87m
Now input the parameters and solve for speed;
Speed = [tex]\frac{0.87}{8.667}[/tex] = 0.1m/s
The bug is travelling at a speed of 0.1m/s
A certain lightning bolt moves 50.0 C of charge. How many units of fundamental charge is this?
A Tennis ball falls from a height 40m above the ground the ball rebounds
with 0.5 of the velocity with which it strikes the ground. If the ball rebound
with 1/2 of the velocity with which the balls strike the ground any time the
ball striked the ground. Calculate
[i] the position of the ball after 5s from the ground
[iiafter how many bounds will the ball remain on the ground
(iii) what is the time interval between the third and fourth bounds
(iii) predicts the velocity of the ball after 6s
If the ball is dropped with no initial velocity, then its velocity v at time t before it hits the ground is
v = -g t
where g = 9.80 m/s² is the magnitude of acceleration due to gravity.
Its height y is
y = 40 m - 1/2 g t²
The ball is dropped from a 40 m height, so that it takes
0 = 40 m - 1/2 g t²
==> t = √(80/g) s ≈ 2.86 s
for it to reach the ground, after which time it attains a velocity of
v = -g (√(80/g) s)
==> v = -√(80g) m/s ≈ -28.0 m/s
During the next bounce, the ball's speed is halved, so its height is given by
y = (14 m/s) t - 1/2 g t²
Solve y = 0 for t to see how long it's airborne during this bounce:
0 = (14 m/s) t - 1/2 g t²
0 = t (14 m/s - 1/2 g t)
==> t = 28/g s ≈ 2.86 s
So the ball completes 2 bounces within approximately 5.72 s, which means that after 5 s the ball has a height of
y = (14 m/s) (5 s - 2.86 s) - 1/2 g (5 s - 2.86 s)²
==> (i) y ≈ 7.5 m
(ii) The ball will technically keep bouncing forever, since the speed of the ball is only getting halved each time it bounces. But y will converge to 0 as t gets arbitrarily larger. We can't realistically answer this question without being given some threshold for deciding when the ball is perfectly still.
During the first bounce, the ball starts with velocity 14 m/s, so the second bounce begins with 7 m/s, and the third with 3.5 m/s. The ball's height during this bounce is
y = (3.5 m/s) t - 1/2 g t²
Solve y = 0 for t :
0 = (3.5 m/s) t - 1/2 g t²
0 = t (3.5 m/s - 1/2 g t)
==> (iii) t = 7/g m/s ≈ 0.714 s
As we showed earlier, the ball is in the air for 2.86 s before hitting the ground for the first time, then in the air for another 2.86 s (total 5.72 s) before bouncing a second time. At the point, the ball starts with an initial velocity of 7 m/s, so its velocity at time t after 5.72 s (but before reaching the ground again) would be
v = 7 m/s - g t
At 6 s, the ball has velocity
(iv) v = 7 m/s - g (6 s - 5.72 s) ≈ 4.26 m/s
Real-world efficiencies are generally very high, in the 90 percent range. Please select the best answer from the choices provided. T F
Answer:
t
Explanation:
Answer: true
Explanation:
What is the difference between environmental science and environmentalism?
Explanation:
Environmental science is the pursuit of knowledge about the workings of the environment and our interactions with it. Environmentalism is a social movement dedicated to protecting the natural world. Nature makes resources at similar speeds
If a car has a mass of 1,300 kg and is moving at a constant velocity of 20 m/s, what is the net force acting on the car?
Constant velocity means there is no acceleration in the direction of the car's movement and hence no force acting on the car in this direction.
The only forces acting on the car are due to gravity and the Earth pushing back up on the car. But the car doesn't move up or down, so the net force is 0.
Determine an example of a social influence.
a brother or sister
your best friend
a community leader
All are social influences.
Answer:
all are social influences
How is electrolysis used in order to prevent materials from corrosion or rusting?
Answer:
We use electrolysis to prevent a material from rusting,
The metal forms a coating around the material and hence prevents any contact between the material and the environment
This process also gives us the physical strength of the material and the aesthetic properties of the coated metal
the metal commonly used to coat the object is Zinc and the process is called galvanisation
A minerals that help in clotting of blood?
Answer:
Calcium helps in blood clotting. Thank You !
Answer: Calcium
Explanation:
Calcium is Important for healthy bones and teeth; helps muscles relax and contract; important in nerve functioning, blood clotting, blood pressure regulation, immune system health
Halfway through Mila's run, when the music stopped playing, was there energy in Mila's phone? What is your
evidence?
Answer:
No energy
Explanation:
The dipole moment of water is p = 6.17 x 10-30 C m. If the electric field in a microwave oven is on average 94.7 x 10-6 N/C, and water molecules start anti-parallel to the external field (180o), how much energy (in Joules) is deposited into a water sample in 2.39 seconds with 13.1 of water if the direction of this field switches every 3.42 x 108 times a second and each time the electric field flips the water molecules align themselves with the new direction?
Answer:
Explanation:
Given that:
p = 6.17 × 10⁻³⁰ Cm
Electric field E = 94.7 × 10⁻⁶ N/C
Then:
[tex]U= -p^{\to} *E^{\to}[/tex]
[tex]U_i = -pE \ cos180^0 =pE \\ \\ U_f = -pE \ cos 0^0 = -pE[/tex]
∴
[tex]\Delta U = U_i - U_f = 2pE \ \ per \ dilute/per \ switch[/tex]
This implies that one switch of dipole produces 2pE energy to be deposited in the water.
mass of water = 13.1 g
The number of water molecule = [tex]\dfrac{mass}{molar \ mass}\times N_A[/tex]
=[tex]\dfrac{13.1}{18.015}\times6.023 \times 10^{23}[/tex]
= 4.38 × 10²³ molecules of water.
∴ Number of dipoles = 4.38 × 10²³
The total number of switches in 2.39 sec = switch frequency × 2.73
Number of switches = 2.39 × 3.42 × 10⁸
Number of switches = 817380000
Number of switches = 8.174 × 10⁸
The total energy Q deposited = Energy deposited per dipole × Number of dipole × no of switches
Q = (2pE) × 4.38 × 10²³ × 8.174 × 10⁸
Q = (2 × 6.17 × 10⁻³⁰ × 94.7 × 10⁻⁶ × 4.38 × 10²³ × 8.174 × 10⁸ )
Q = 0.41838 J
