Answer: 0.081 kilogram/cubic meter
Explanation: p=m/v so 104/1278 is 0.081377151799687 or 0.081.
What invisible force will cause you to fall to the earth if you fall off your bed?
Answer:
The answer to this is falling all the way through the Earth is impossible, since its core is molten. ... As you approached the center of the earth the pull of gravity would decline and eventually (at the center) cease, but inertia would keep you going.
Explanation:
your welcome
A roller coaster containing four cars is accelerating at 15 m/s2 before it comes to an abrupt stop at the end of the ride. The mass of one car is 200 kg. How much force was exerted on the roller coaster to bring it to a stop?
Answer: 12,000 Newton’s
Explanation: multiply by the number of cars the 200 kg.
The force exerted on the roller coaster to bring it to stop is 12000 N.
Given data:
The magnitude of acceleration of car is, [tex]a = 15 \;\rm m/s^{2}[/tex].
The mass of each car is, m = 200 kg.
As per the Newton's second law, the force is given as the product of acceleration and the mass of object. Then the force exerted on each car is,
F = ma
And the force exerted on the roller coaster is,
F' = 4F
F' = 4ma
Solving as,
[tex]F' = 4 \times 200 \times 15\\\\F' = 12000\;\rm N[/tex]
Thus, we can conclude that the force exerted on the roller coaster to bring it to stop is 12000 N.
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Which forms of energy are involved when you turn on a desk lamp and the bulb
becomes hot?
Answer:
Electric energy moves through the wire to the lamp's bulb. In the bulb, electric energy transforms into thermal energy and light energy.
Explanation:
You and your friend Peter are putting new shingles on a roof pitched at 25 ∘ . You're sitting on the very top of the roof when Peter, who is on the edge of the roof, 5.4 m away, asks you for the box of nails. Rather than carry the 2.4 kg box of nails down to Peter, you decide to give the box a push and have it slide down to him. Part A If the coefficient of kinetic friction between the box and the roof is 0.51, with what speed should you push the box to have it gently come to rest right at the edge of the roof?
Answer:
Explanation:
Frictional force acting on the box = mg cos 25 x μ where μ is coefficient of friction
= 2.4 x 9.8 x cos 25 x .51 = 10.87 N
Weight of the box acting along the incline = mg sin 25 = 9.94 N
Net force = 10.87 - 9.94 = .93 N . It will create a deceleration of .93 / 2.4
= .3875 m /s² in the box.
v² = u² - 2 a s
v = 0 , a = .3875 , s = 5.4 m
= = u² - 2 x .3875 x 5.4
u = 2.045 m /s
On dry concrete, a car can decelerate at a rate of 7.00 m/s2 , whereas on wet concrete it can decelerate at only 5.00 m/s2 . Find the distances necessary to stop a car moving at 30.0 m/s (about 110 km/h) (a) on dry concrete and (b) on wet concrete. (c) Repeat both calculations, finding the displacement from the point where the driver sees a traffic light turn red, taking into account his reaction time of 0.500 s to get his foot on the brake.
Answer:
Explanation:
a ) Let the distance required in former case be d₁ .
initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 7.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 7 x d₁
d₁ = 64.28 m
b) initial velocity u = 30 m /s , final velocity v =0 , deceleration a = 5.00 m /s²
v² = u² - 2 a s
0 = 30² - 2 x 5 x d₂
d₂ = 90 m
c)
t = .5 s
s₁ = ut - .5 at²
= 30 x .5 - .5 x 7 x .5²
= 15 - .875
= 14.125 m
t = .5 s
s₂ = ut - .5 at²
= 30 x .5 - .5 x 5 x .5²
= 15 - .625
= 14.375 m
A bug walking on the circular rim of a flower
pot completes one lap around the planter in
8.667 s.
If the radius of the planter is 13.9 cm, how
fast was it traveling?
Given parameters;
Time taken to complete a lap = 8.667s
Radius of flower = 13.9cm
convert to SI unit of m, 100cm = 1m
13.9cm gives [tex]\frac{13.9}{100}[/tex] = 0.139m
Unknown = speed
To solve this problem, we need to first find the circumference of the flower.
Circumference of the circular flower = 2 π r
where r is the radius of the flower;
Circumference = 2 x 3.142 x 0.139 = 0.87m
Now to find the how fast the bug is travelling,
Speed = [tex]\frac{distance}{time}[/tex]
Since the bug covered 1 lap, the distance is 0.87m
Now input the parameters and solve for speed;
Speed = [tex]\frac{0.87}{8.667}[/tex] = 0.1m/s
The bug is travelling at a speed of 0.1m/s
Jason took 6 hours to travel 540 km. For the first 140 km, he
took 2 hours. What was his average speed for the rest of the
journey?
km/h
Answer: 100
Explanation:
8432.0 L = ? ML (Megaliters)
Answer:
0.008432 ML
Hope this helps!
The USC Trojan football team bus is heading to an away game, traveling on a long, straight road at a constant speed of 28.0 m/s. All of a sudden, at t = 0, a car full of students from the opposing team cuts in front of the bus, at a mere distance of 70.0 m ahead of the bus, moving in the same direction with a constant velocity of 6.00 m/s. The panic brake deceleration of the bus is 3.00 m/s2 . a) (10 Points) If the bus begins braking at t = 0, how much time will elapse until the bus and car collide? b) (5 Points) How far down the road, from the original position of the bus, will the collision occur? c) (10 Points) What would the acceleration of the bus have to be for the collision to be avoided?
Answer:
a. 17.34 s. b. 104.51 m c. -7.16 m/s²
Explanation:
a. The distance, d moved by the car at constant speed v = 6.00 m/s in time t which they collide is d = vt. The distance d' moved by the bus from its initial position 70 m away from the car with a constant velocity u = 28.0 m/s and deceleration a = -3.00 m/s² is d' = 70 + ut + 1/2at².
At collision, s = d
vt = 70 + ut + 1/2at²
substituting the values of the variables, we have
6t = 70 + 28t + 1/2(-3)t²
6t = 70 + 28t - 1.5t²
collecting like terms, we have
1.5t² + 6t - 28t - 70 = 0
1.5t² - 22t - 70 = 0
using the quadratic formula to find t, we have
[tex]t = \frac{-(-22) +/- \sqrt{(-22)^{2} - 4 X -70 X 1.5} }{2 X 1.5} \\t = \frac{22 +/- \sqrt{484 + 420} }{3} \\\\t = \frac{22 +/- \sqrt{904} }{3} \\\\t = \frac{22 +/- 30.01 }{3} \\\\t = \frac{22 - 30.01 }{3} or \frac{22 + 30.01 }{3} \\t = \frac{-8.01 }{3} or \frac{52.01 }{3} \\\\t = -2.67 s or 17.34 s[/tex]
We take the positive value.
So t = 17.34 s.
So, 17.34 s elapses before the bus and car collide.
b. Since the distance covered by the bus is d' = 70 + ut + 1/2at², this is how far down the road the collision occurs.
Substituting the values of the variables, we have
d' = 70 + 28 m/s × 17.34 s + 1/2(-3 m/s²)(17.34)²
d' = 70 + 485.52 - 451.01
d'= 104.51 m
c. To just avoid the collision, the bus must decelerate in the distance of 104.51 m from the car to the speed of the car. So using
v² = u² + 2ad' where v = 6.00 m/s, u = 28.0 m/s and d' = 104.51 m
the acceleration is thus
a = (v² - u²)/d'
a = ((6 m/s)² - (28 m/s)²)/104.51 m
a = (36 m²/s² - 784 m²/s²)/104.51 m
a = -748 m²/s² ÷ 104.51 m
a = -7.16 m/s²
One consequence of Newton's third law of motion is that __________. A. every object that has mass has inertia B. a force acting upon an object increases that objects acceleration C. all actions have equal and opposite reactions D. none of the above
Answer:
C i think
Explanation:
One consequence of Newton's third law of motion is that all actions have equal and opposite reactions. that means net force on body is zero.
What is force?A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Newton's third law states that when two bodies interact, they apply forces to one another that are equal in magnitude and opposite in direction.
If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object.
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PLS HELP
A marble rolls off a table with a horizontal velocity of 8 m/s and the cliff has a height of
2.71 m. How far does the marble land from the base of the table? Round your answer to
two decimal places.
A vehicle traveling at 45km/h comes to a stop in 9s how fast did the vehicle accelerate ?
Answer:
vi=45 km/h=12.5ms-1
t=9s
vf=0
acceleration=?
a=vf-vi/t=0-45/9=1.38ms-2
Explanation:
The acceleration of the vehicle is 56.25m. In physics and engineering, average speed is calculated using the formula v = d / t.
Explain what acceleration is.The rate at which direction and velocity of the an object moving change over time. A object or object moving straight ahead is accelerated whenever it accelerates or decelerates. Regardless of whether the speed remains constant, motion on the a circle accelerates so because direction is always shifting.
Is speed acceleration?We refer to a shift in an item's velocity or direction as accelerating. The speed at which velocity varies is known as acceleration. Bear in mind that velocity has two parts: direction and speed.
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A wave travels at 48 m/s and has a frequency of 12 Hz. What is the wavelength of the wave?
0.25 m
4.0 m
36 m
60 m
Answer:
Wavelength = 4 m
Explanation:
We know that Velocity = Wavelength × Frequency
So, Wavelength = Velocity / Frequency
Here in the question , Velocity = 48 m/s & Frequency = 12 Hz.
So wavelength = 48/12 = 4 m
"How did your current and voltage measurements differ between the series and parallel circuits you created
Answer:
Series circuit:
The voltage that is measured across the circuit is different.
The current measured in a series circuit remains the same at all points in the circuit.
Parallel circuit:
The current measured across each resistor varies
The voltage measured across a parallel circuit will remain the same
Explanation:
Series and parallel circuits behave differently when it comes to the circulation of current and the interaction with a potential difference.
In a series circuit, the resistances are connected end to end. As a result, the voltage that is measured across the circuit is different once resistance is encountered. However, the current measured in a series circuit remains the same at all points in the circuit.
A parallel circuit behaves in an exactly opposite manner to the series circuit. In a parallel circuit, the resistances are connected side by side. As a result of this, the current measured across each resistor varies as there are circuit branches through which electric current can flow into. On the other hand, the voltage measured across a parallel circuit will remain the same
most of our brains activity is:
A racecar accelerates at a rate 19 m/s each second. If the mass of the race car is 1600 kg, determine the net force acting on the car.
30,400 N
8,400 N
84 N
300 N.
Answer:
[tex]19 \times 16000[/tex]
According to the question,
Mass, m = 1600 kgAcceleration, a = 19 m/sForce:We know,
→ [tex]Force = Mass\times Acceleration[/tex]
By substituting the values, we get
[tex]= 1600\times 19[/tex]
[tex]= 30400 \ N[/tex]
Thus the above answer is right.
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Identify the atom
Ве
C
H
Не
Answer:
Be: Beryllium
C: Carbon
H: Hydrogen
He: Helium
If the force of kinetic friction on a crate is 50 N and the weight of the crate is
180 N, what is the coefficient of kinetic friction?
Answer:
The coefficient of kinetic friction μ = 0.278
Explanation:
The frictional force on the crate is given by F = μN where μ = the coefficient of kinetic friction and N = normal force. The normal force equals the weight of the crate W = 180 N.
Since the kinetic friction F = 50 N, and the normal force which is the weight of the crate equals N = W = 180 N, the coefficient of kinetic friction μ is given by μ = F/N
= 50 N/180 N
= 0.278
So, the coefficient of kinetic friction μ = 0.278
Which parts of the graph represents the object moving at a constant, positive acceleration?
Answer:
W and X
Explanation:
They are both straight lines and face upwards on the graph, this means it is a positive acceleration because upwards on the graph is a higher velocity. And a constant acceleration because the line is straight.
Also it can't be Z because Z is negative acceleration because the line goes down. and it can't be Y because there is no acceleration at Y because in the graph it shows it stays at 20 m/s. That leaves W and X.
The parts of the graph that represents the object moving at a constant, positive acceleration are W and X.
How to find the function which was used to make graph?A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it.
It cannot be Z because Z is negative acceleration because the line goes down. and Y because there is no acceleration at Y because in the graph it shows it stays at 20 m/s.
That leaves W and X.
W and X are both straight lines and face upwards on the graph, this means it is a positive acceleration because upwards on the graph is a higher velocity.
Also, a constant acceleration because the line is straight.
The parts of the graph that represents the object moving at a constant, positive acceleration are W and X.
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Calculate critical angle for right angle prism with apex angle 30o and refraction index 1.5. Consider that light is incident on flat surface of prism. Calculate minimum deviation angle of prism.
Answer:
Solution:
For small angle prism
δ
1
=(μ−1)A
⟹δ
1
=(1.5−1)(4)
⟹δ
1
=2
∘
So ray is incident on plane mirror at 2
∘
,
Hence δ
2
=S
mirror
=180
∘
−2(2
∘
)=176
∘
Total reflection = δ
1
+δ
2
=176
∘
+2
∘
=178
∘
clockwise.
A design team for an electric car company finds that under some conditions the suspension system of the car performs in a way that produces unsatisfactory bouncing of the car. When they perform measurements of the vertical position of the car y as a function of time t under these conditions, they find that it is described by the relationship: y(t) = yoe-at cos(wt) where yo = 0.75 m, a = 0.95s-1, and w= 6.3s-1. In order to find the vertical velocity of the car as a function of time we will need to evaluate the dy derivative of the vertical position with respect to time, or dt As a first step, which of the following is an appropriate way to express the function y(t) as a product of two functions?
a) y(t) = f(t) · g(t), where f(t) = yoe cos and g(t) wt.
b) y(t) = f(t) · g(t), where f(t) = yoe and g(t) = cos(wt).
c) y(t) = f(t)·g(t), where f(t) = yoe cos(wt) and g(t) = -at.
d) y(t) cannot be expressed as a product of two functions.
Answer:
The answer is "Option b"
Explanation:
[tex]\to \bold{y(t) = y_0e^{-a t} cos(\omega t)}[/tex]
[tex]= y_0 e^{-\alpha t} cos(\omega t)[/tex]
and
[tex]\bold{y(t) =f(t) \cdot g(t)}[/tex]
where
[tex]\to f(t) = y_{0}\ e^{- at} \ \ \ \ \ \\\\\ \to g(t) = cos {(\omega t)}[/tex]
#8. Benny pushes Betty on her skateboard with a force of 150 N. If she accelerates at 3.0 m/s? what is her
mass? Type the formula and answer.
Answer:
50 kg
Explanation:
Force = Mass x Acceleration
150 = Mass x 3
150 = 50 x 3
A horse 1 m tall running towards a tree at a constant velocity of 20m/s,
there was a baboon on the tree which is 3m tall, if the baboon falls exactly on
the back of the horse and sped away with baboon at its back.
Calculate
I) how far was the horse from the tree and the time the baboon
falls on the horse.
The horse's position on the ground at time t is
x = (20 m/s) t
The baboon's height from the ground at time t is
y = 3 m - 1/2 g t²
where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.
The baboon falls and lands on the horse, so that the two animals meet when the baboon's height is 2 m from the ground, which happens after
2 m = 3 m - 1/2 g t²
1/2 g t² = 1 m
t² = (2 m) / (9.80 m/s²)
t ≈ 0.452 s
In this time, the horse reaches the tree, so its distance from it is
(20 m/s) * (0.452 s) ≈ 9.04 m
When the driver in the car moving with a speed of 15 ms-1 increases the
speed at a constant rate of 5 ms-2 . Calculate the speed attained by the
car, at the end of 5 s.
A ball is thrown vertically upward from the surface of the earth. The ball rises to some maximum height and falls back toward the surface of the earth. Which one of the following statements concerning this situation is true if air resistance is neglected? a) As the ball rises, its acceleration vector points upward. b) The ball is a freely falling body for the duration of its flight. c) The acceleration of the ball is zero when the ball is at its highest point. d) The velocity and acceleration of the ball always point in the same direction.
Answer:
b) The ball is a freely falling body for the duration of its flight.
Explanation:
When an object is thrown upwards, it moves against the direction of gravity. Its velocity decreases with respect to its motion, and zero at the maximum height. After which it falls back to the surface of the earth.
Since the ball moves initially against the force of gravity, its acceleration would be -9.8 m/[tex]s^{2}[/tex] at its highest point. Thus since acceleration is constant, the ball is a freely falling body for the duration of its flight.
The correct option is option (b)
The ball is a freely falling body for the duration of its flight.
Freefall:If the ball is thrown upwards, it moves against the force of gravity. The gravitational acceleration is opposite to its motion.
The velocity of the ball decreases as it moves up, and zero at the maximum height since the gravitational acceleration is opposite to the motion. After which it falls back to the surface of the earth.
After reaching the highest point, the ball returns and falls back under the influence of gravity.
Any object which experiences only the gravitational force while falling down to the surface is the freely falling body.
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question 8 how to do
Answer:
We know that the resistance of a material is its length divided by its cross-sectional area and all that multiplied by its resistivity
Hence, resistance = ρ * length(in m) / Cross-sectional area
(ρ = constant of resistivity)
If you do not understand cross-sectional area, comment on this answer
since both the wires are made of the same substance, both their resistivity will be the same
since we are told that both the wires have the same resistance,
(ρ * length 1) / cross-sectional area 1 = (ρ * length 2) / cross-sectional area 2
since they both have the same resistivity, both the ρ will cancel out
length 1 / cross-sectional area 1 = length 2 / cross-sectional area 2------(1)
Calculating the cross-sectional area
To simplify it , the cross-sectional area is the area of the circle you can currently see on either of the wire
let the radius of wire 1 = 2r
then, the radius of wire 2 = r
Cross-sectional area 1 = π (2r)^2 = 4πr^2
Cross-sectional area 2 = π (r)^2
Now, using these values in (1)
l / 4πr^2 = l' / πr^2
l / l' = 4πr^2/πr^2
l / l' = 4 / 1
the length of rod 'P' is l
from the equation, we can simplify:
l (length of rod 'P') = 4 l'(length of rod 'Q')
Therefore, we can say that the length of rod 'P' is 4 times the length of rod 'Q'
C. 5 mi., North is it a scalar or vector
Answer:
Vector.
Explanation:
A vector has both magnitude and direction.
A scalar has just magnitude.
The accompanying map shows the route traveled by a school bus.What is the magnitude of te dispacment odte school bus fo start to te end of its trip?
Answer:1,800
Explanation:
The velocity of a wave is the product of the frequency and the
A. wavelength
B. amplitude
C. time
D. distance
Answer:
option A
Explanation:
Velocity = Wavelength / Time
But we know that Frequency = 1 / Time. So ,
Velocity = Wavelength × Frequency
The velocity of a wave is the product of the frequency and the wavelength. The correct option is A.
A wave's velocity is the result of its frequency and wavelength. The equation v = f * λ, where v stands for velocity, f for frequency, and for λ wavelength, describes this relationship.
While wavelength is the separation between two identical spots on a wave, frequency is the quantity of wave cycles passing a specific point in a unit of time.
The speed at which a wave propagates across a medium is determined by the product of its frequency and wavelength.
On the other hand, amplitude has nothing to do with the wave's velocity and instead describes the maximum movement of particles in the medium. Therefore, wavelength is the right response in this case.
Thus, the correct option is A.
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What is the definition of force according to the Newton first law of motion?
Answer:
A force is any interaction that, when unopposed, will change the motion of an object
Explanation:
