Answer:
Step-by-step explanation:
15 = 3 * 5
21 = 3 * 7
GCF = 3
15 + 21 = (3*5) + (3*7)
= 3*(5 + 7)
0.06 is 10 times as much as...
0.06 is 10 times as much as 0.006.
0.006 times 10 equals 0.06
Find the area of each circle to the nearest tenth.Use 3.14
Answer:
153.86
Step-by-step explanation:
Area = Pi*R^2
Or
3.14xRadiusx Radius= Area
so 3.14*7*7=153.86
If this helps can I get Brainliest pls.
A right cylinder has a radius of 3 cm and a height of 7 cm.
(a) Find the Surface Area of the cylinder.
(b) Find the Volume of the cylinder.(c) If you wanted more volume in your cylinder, which of these two ideas would give the most Volume?
1. Doubling the radius to 6 cm, while the height remains 7 cm.
-OR-
2. Tripling the height to 21 cm, while the radius remains 3 cm.
Answer:
a) 188.4955592
b) 197.9203372
c) 1
Step-by-step explanation:
HELP PLEASE
ITS NOT D
9.
What is the rate of decay, r (expressed as a decimal), for data best modeled by the exponential function y equals 3.31 left parenthesis 0.87 right parenthesis superscript x baseline?
r = 0.13
r = 0.87
r = 2.88
r = 3.31
The rate of decay r is -0.139.
What is a function?A function has an input and an output.
A function can be one-to-one or onto one.
It simply indicated the relationships between the input and the output.
Example:
f(x) = 2x + 1
f(1) = 2 + 1 = 3
f(2) = 2 x 2 + 1 = 4 + 1 = 5
The outputs of the functions are 3 and 5
The inputs of the function are 1 and 2.
We have,
The exponential function [tex]y = 3.31(0.87)^x[/tex] can be written in the form
[tex]y = ab^x,[/tex]
where a = 3.31 and b = 0.87.
The formula for the rate of decay for an exponential function in the form
[tex]y = ab^x[/tex]is r = ln(b)
where ln is the natural logarithm.
In this case,
r = ln(0.87) ≈ - 0.139.
Since r represents the rate of decay as a decimal, the answer is r = - 0.139.
Thus,
The rate of decay r is - 0.139.
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Use the information below to find RV.
Answer:
I think Rv = 37x but if you think not then Go with You're answer
Step-by-step explanation:
goodluck! :)
A scientist poured 2/3 of a liter of water into a cup and 3/10 of a liter of water into a jar. Which comparisons are true about the amounts of water the scientist poured?
Answer:
Step-by-step explanation:
The cup has 33.(66)% more liters than the jar.
The cup has more water than the jar.
The cup has 11/30 more liters of water than the jar.
(x = 3)
y=x+5
How would I solve this problem
Please help I’m not really sure what the answer is :£)
Please help me! I'm stuck! If you answer both a and b, you get brainliest and points!
Beth is filling a small backyard pool with a garden hose. The pool holds 30 gallons of water. After 5 minutes, the pool is about one fourth full.
a. Assuming that the water is flowing at a constant rate, about how much water is going into the pool each minute?
b. About how long will it take to fill the pool?
The water is flowing into the pool at 1.5 gallons per minute and it would take 20 minutes to be filled.
What is an EquationAn equation is used to show the relationship between two or more numbers and variables.
The pool holds 30 gallons of water. After 5 minutes, the pool is about one fourth full. Hence:
Time to full the pool = 5 minutes * 4 = 20 minutes
Rate of water flow = 30 gallons/20 minutes = 1.5 gallons per minute
The water is flowing into the pool at 1.5 gallons per minute and it would take 20 minutes to be filled.
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What is 5.316 - 1.942 btw (show ur work) :)
Answer:
3.374
Step-by-step explanation:
[tex]\mathrm{Write\:the\:numbers\:one\:under\:the\:other,\:line\:up\:the\:decimal\:points.}[/tex]
[tex]\mathrm{Add\:trailing\:zeroes\:so\:the\:numbers\:have\:the\:same\:length.}[/tex]
[tex]\begin{matrix}\:\:&5&.&3&1&6\\ -&1&.&9&4&2\end{matrix}[/tex]
[tex]\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left}[/tex]
[tex]\mathrm{In\:the\:bolded\:column,\:subtract\:the\:second\:digit\:from\:the\:first}:\quad \:6-2=4\\[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&3&1&\textbf{6}\\ -&1&.&9&4&\textbf{2}\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\:\:&\textbf{4}\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&3&\textbf{1}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&5&.&\textbf{3}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&10&\:\:&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&3&1&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{\:\:}&\:\:&\:\:&\:\:&4\end{matrix}}\\[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{13}&\:\:&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{3}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&10&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&1&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{\:\:}&\:\:&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{\:\:}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&12&\textbf{11}&\:\:\\ \:\:&\linethrough{5}&.&\linethrough{13}&\textbf{\linethrough{1}}&6\\ -&1&.&9&\textbf{4}&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\:\:&\textbf{7}&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\:\:&\textbf{12}&11&\:\:\\ \:\:&\linethrough{5}&.&\textbf{\linethrough{13}}&\linethrough{1}&6\\ -&1&.&\textbf{9}&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\:\:&\textbf{3}&7&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&4&\textbf{\:\:}&12&11&\:\:\\ \:\:&\linethrough{5}&\textbf{.}&\linethrough{13}&\linethrough{1}&6\\ -&1&\textbf{.}&9&4&2\end{matrix}}{\begin{matrix}\:\:&\:\:&\textbf{.}&3&7&4\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\:\:&\textbf{4}&\:\:&12&11&\:\:\\ \:\:&\textbf{\linethrough{5}}&.&\linethrough{13}&\linethrough{1}&6\\ -&\textbf{1}&.&9&4&2\end{matrix}}{\begin{matrix}\:\:&\textbf{3}&.&3&7&4\end{matrix}}[/tex]
=3.374
help if you can !! thank you :)
Answer:
NVM MY BAD
x=19
quadrilateral have the internal degree sum of 360
not 365
Answer:
I'm not sure if you need the value of x or the entire angle measure, so I'll give you both.
x = 19
The angle measure is 46 degrees
Step-by-step explanation:
The sum of a quadrilateral's interior angles is 360 degrees. With that knowledge, we can subtract the angle measures we have from 360. To do that, we must first add 115 + 118 + 81, which equals 314. Now, we do 360 - 314, which gives us the measure of the unknown angle, which is 46 degrees.
Now, we must find x. We write the equation 2x + 8 = 46 since we know what the angle measure is now. Then, we subtract 8 from both sides, which leaves us with 2x=38. Finally, we need to divide 2 on both sides. If your math is correct, you should end up with x = 19. Hope this helps!
Triangle ABC is similar to triangle DEF find the value of "X" and "y". What is the sum of
the perimeters of the triangles?
please solve for X!!
Since Angle XYZ equals 70 degrees, thus the sum of the Angle XYW and Angle WYZ equal 70 degrees
Angle XYW + Ange WYZ = 70
50 + (3x + 14) = 70
3x + 14 = 20
3x = 6
x = 2
Hope that helps!
Answer:
x = 2
Step-by-step explanation:
m<XYZ = 70 and
m<XYZ = m<XYW + m<WYZ
So we can conclude 50 + 3x + 14 = 70 add like terms
64 + 3x = 70 subtract 64 from both sides
3x = 6 divide both sides by 3
x = 2
1. Solve for x = 9/36 x/48
12
192
28
6.8
Answer:
x = 12
Step-by-step explanation:
I am unable to decipher what "x = 9/36 x/48" means.
I'll assume that the question is to find a value of x such that:
x/48 = 9/36
If so, cross multiply:
36x = (48*9)
36x = 432
x = 12
EASYYY!!!PLEASE HELP AND EXPLAIN!!!!POINTS
73 - 24 = 101
Answer:
z=5
Step-by-step explanation:
1. You will have to rearrange the terms, so the equation would now be z(3)=101+24
2. After that you will calculate the sum to equal z(3)=125
3. You will simplify your answer to z=3^ 125
4. Calculate. Z=5
I hope this helps!
Kim worked 9 hours and completed 3/4 of a project
of a project. If she continues to work at the same rate, how many more hours will she need to complete the project?
✨✨
My bad for not paying attention in class lol
Answer:
She'll need 3 more hours to complete the project
Step-by-step explanation:
Because (3/4) × (4/3) = 1, you can multiply 9 by 4/3 to find the total amount of time needed for the project. You'll get a total time of 12 hours. To find how many more hours needed you would do 12 - 9 = 3 hours
The number of movie tickets sold on Friday is twice as many as are sold on Sunday. The number of tickets sold on Saturday is three times as many as were sold on Sunday. If 340 tickets were sold on Sunday, how many tickets were sold over the three days?
Answer:
3400
Step-by-step explanation:
340x3=1020
1020x2=2040
340+1020+2040=3400
i need help please thanks
Answer: You simply need to match each fraction to where they belong
Step-by-step explanation:
ayúdenme a calcular el valor de x
Answer:
12m,
Step-by-step explanation:
Please answer with steps
|-10k+7|
------------- =4
3
Answer:
3.6
Step-by-step explanation:
We have I -10k + 7 I = 43Remove the I I 's-10k + 7 = 43Subtract 7 on both sides.-10k = 36Divide by -10 on both sides.k = 3.6 (it's positive because of the inequality symbols)If I am incorrect in my reasoning, please let me know so that I can plan better for my future answers. Have an amazing day.
PLEASEEEE HELPPPPPPPP ASAPPPPPP
Answer:
y=2.75x+3
Step-by-step explanation:
$2.75 per sandwich (coefficient)
Solid $3 fee (y-intercept)
y=mx+b ---> y=2.75x+3
help im unable to solve, A boy earns Rs. X in a week and spends Rs. Y in a week. His savings for the week is
Answer:
Amount of earning: X
Amount of spending: Y
So the savings = X - Y
simplify each expression
Solution (5):
Simplifying the expression.
(8x + 1) + (-x + 7)=> 8x + 1 - x + 7=> 7x + 8Solution (6):
Simplifying the expression.
(8x - 3) - (3x + 1)=> (8x - 3) + (-3x - 1)=> 8x - 3 - 3x - 1=> 5x - 4Solution (7):
Simplifying the expression.
(2x + 7) + (4x - 10)=> 2x + 7 + 4x - 10=> 6x - 3Solution (8):
Simplifying the expression.
(-7x + 2) - (3x - 3)=> (-7x + 2) - 3x + 3=> -7x + 2 - 3x + 3=> -10x + 5[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
Let's solve ~
First ~[tex]\qquad \sf \dashrightarrow \: (8x + 1) + ( - x + 7)[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x + 1 - x + 7[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - x + 1 + 7[/tex]
[tex]\qquad \sf \dashrightarrow \: 7x + 8[/tex]
Second ~[tex]\qquad \sf \dashrightarrow \: (8x - 3) - (3 x + 1)[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - 3 - 3x - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 8x - 3x - 3 - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 5x - 4[/tex]
Third ~[tex]\qquad \sf \dashrightarrow \: (2x + 7) + (4x - 10)[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x + 7 + 4x - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: 2x + 4x + 7 - 10[/tex]
[tex]\qquad \sf \dashrightarrow \: 6x - 3[/tex]
Fourth ~[tex]\qquad \sf \dashrightarrow \: (- 7x + 2) - (3x - 3)[/tex]
[tex]\qquad \sf \dashrightarrow \: - 7x + 2 - 3x + 3[/tex]
[tex]\qquad \sf \dashrightarrow \: - 7x - 3x + 2 + 3[/tex]
[tex]\qquad \sf \dashrightarrow \: - 10x + 5[/tex]
Use the qoutation below as your guide in giving example of situation on how you are going to apply your significant learnings about properties of parallel lines in real life.
"The road of life twists and turns and no two directions are ever the same. Yet our lessons come from the journey, not the destination.” - Don Williams, Jr.
What is the value of the expression ( 4 + 5 ) 2 ÷ ( 2 4 − 7 ) ?
Answer: n
Step-by-step explanation:
18/17 ≈1.058823529
if y = lim [-3x^3+2x^2-4x+5] when x--> -2
In this case to calculate the limit, you simply plug the x value of -2 into the function
[tex]y = \lim_{x \to \--2}( -3x^3+2x^2-4x+5) = 24 + 8+8+5 = 45\\[/tex]
So the limit equals 45.
Hope that helps!
Answer:
[tex]\displaystyle y = 45[/tex]
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Step-by-step explanation:
Step 1: Define
Identify.
[tex]\displaystyle y = \lim_{x \to -2} \big[ -3x^3 + 2x^2 - 4x + 5][/tex]
Step 2: Find Limit
[Limit] Limit Rule [Variable Direct Substitution]: [tex]\displaystyle y = -3(-2)^3 + 2(-2)^2 - 4(-2) + 5[/tex]Evaluate: [tex]\displaystyle y = 45[/tex]∴ the limit as x approaches -2 of the given function -3x³ + 2x² - 4x + 5 is equal to 45.
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---
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
The product of two numbers is 10 times the value of
6 × 8. Which expression shows the two numbers?
Answer:
8 x 60
Step-by-step explanation:
Hope it helps.
The two triangles are similar.
What is the value of x?
Answer:
ok so one triagnles side is 12 and the other is 12+4=16
so one triagnle is 25 percent bigger then the other one so
1.25(5x-2)=6x
distribuite
6.25x-2=6x
so 1/4x=2
x=8
Hope This Helps!!!
Triangle ABC is congruent to triangle A′′B′′C′′ . Which sequence of transformations could have been used to transform triangle ABC to produce triangle A′′B′′C′′ ? Triangle ABC was reflected across the y-axis and then translated 7 units down. Triangle ABC was translated 10 units right and then reflected across the x-axis. Triangle ABC was reflected across the x-axis and then translated 9 units right. Triangle ABC was translated 7 units down and then 9 units right. A coordinate graph with triangle A B C and triangle A double prime B double prime and C double prime. Triangle A B C has points at A begin ordered pair negative 6 comma 2 end ordered pair, B begin ordered pair negative 3 comma 6 end ordered pair, C begin ordered pair negative 3 comma 2 end ordered pair. Triangle A double prime B double prime C double prime has points at A double prime begin ordered pair 6 comma negative 5 end ordered pair, B double prime begin ordered pair 3 comma negative 1 end ordered pair, C double prime begin ordered pair 3 comma negative 5 end ordered pair.
Answer:
you must provide the image
A school held a special math event for parents. On the first night, 150 parents attended, which was 40% below the expected attendance. On the second night, 210 parents attended, exceeding the expected attendance by 40% . By what percent did the actual attendance at the special math event exceed or fall below the expected attendance for both nights?
Answer:
10.429% exceed
Step-by-step explanation:
expected:
150x [100+40]/100=210 parents were expected on first night
210x60/100=126 parents expected on the second night
210+126=326 expected
percentage difference=
210+150=360
360/326 x 100=110,429%
110,429%-100%=10,429% exceed
