Answer:
[tex]\boxed {\tt 3.63636364 \ m/s}[/tex]
Explanation:
Velocity can be found using the following formula:
[tex]v=\frac{p}{m}[/tex]
where p is the momentum and m is the mass.
The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.
[tex]p= 200 \ kgm/s\\m=55 \ kg[/tex]
Substitute the values into the formula.
[tex]v=\frac{200 \ kg m/s}{55 \ kg}[/tex]
Divide. Note that the kilograms, or kg, will cancel each other out.
[tex]v=\frac{200 \ m/s}{55}[/tex]
[tex]v= 3.63636364 \ m/s[/tex]
The woman's velocity is 3.63636364 meters per second.
anyways chile , what y’all doing virtual or school ?
cise 5:
Yvette hangs a 24-N bird feeder in the middle of a rope tied between two
trees. The feeder creates a tension of 480 N in each side of the the rope.
a) If the two trees are 4.0 m apart, how much will the rope sag in the center?
b) If a bird lands on the feeder, will this have any effect on the tension in the
rope? Explain.
Answer:
The answer is below
Explanation:
a) Since the 24 N weight feeder creates a tension of 480 N on either side of the rope. Taking into consideration of one side of the rope, this means that 24/2 = 12 N creates a tension of 480 N for a length of 2 m (4/2).
Therefore, Fg = 12 N, F = 480 N
sin θ = Fg/F
sin θ = 12 / 480
sin θ = 0.025
θ = sin⁻¹ (0.025)
θ = 1.43⁰
Let the rope sag be h, hence:
tanθ = h/2 m
h = 2 m * tan (1.43)
h = 0.05 m
b) If the bird lands on the feeder, because of the birds weight, the tension on each side of the road would increase.
Explain the Big Bang and how it started
The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now (and it could still be stretching).
The short answer: The big bang is how astronomers explain the way the universe began. It is the idea that the universe began as just a single point, then expanded and stretched to grow as large as it is right now (and it could still be stretching).
The long answer: For most of human history, observers of the sky assumed it eternal and unchanging. Edwin Hubble dealt this story an experimental blow in the 1920s when his observations showed both that galaxies outside the Milky Way existed, and that their light appeared stretched — a sign that they were rushing away from Earth.
George Lemaître, a contemporary Belgian physicist, interpreted data from Hubble and others as evidence of an expanding universe, a possibility permitted by Einstein's recently published field equations of general relativity. Thinking backwards, Lemaître inferred that today's separating galaxies must have started out together in what he called the "primeval atom."
The first public use of the modern term for Lemaître's idea actually came from a critic — English astronomer Fred Hoyle. On March 28, 1949, Hoyle coined the phrase during a defense of his preferred theory of an eternal universe that created matter to cancel out the dilution of expansion. Hoyle said the notion that "all matter of the universe was created in one big bang at a particular time in the remote past," was irrational. In later interviews, Hoyle denied intentionally inventing a slanderous name, but the moniker stuck, much to the frustration of some.
"The Big Bang is a really bad term," said Paul Steinhardt, a cosmologist at Princeton. "The Big Stretch would capture the right idea." The mental image of an explosion causes all kinds of confusion, according to Steinhardt. It implies a central point, an expanding frontier, and a scene where light shrapnel flies faster than heavier chunks. But an expanding universe looks nothing like that, he said. There's no center, no edge, and galaxies large and small all slide apart in the same way (although more distant galaxies move away faster under the cosmologically recent influence of dark energy).
Regardless of its name, the Big Bang theory found widespread acceptance for its unparalleled ability to explain what we see. The balance of light with particles like protons and neutrons during the first 3 minutes, for instance, let early elements form at a rate predicting the current amounts of helium and other light atoms.
"There was a small window in time where it was possible for nuclei to form," said Glennys Farrar, a cosmologist at New York University. "After that, the universe kept expanding and they couldn't find each other, and before [the window] it was too hot."
A cloudy plasma filled the universe for the next 378,000 years, until further cooling let electrons and protons form neutral hydrogen atoms, and the fog cleared. The light emitted during this process, which has since stretched into microwaves, is the earliest known object researchers can study directly. Known as the cosmic microwave background (CMB) radiation, many researchers consider it the strongest evidence for the Big Bang.
Misconseption: Beginning at the beginning, a common question asked by laymen and some physicists is what the universe expands into. The very terminology of the ``big bang'' suggests an explosion, which flings debris out into some void. Such a picture is strongly suggested by many semi-popular descriptions, which commonly include a description of the initial instant as one ``where all the matter in the universe is gathered at a single point'', or something to that effect. This phrase can probably be traced back to Lemaître's unfortunate term ``the primaeval atom''. Describing the origin of the expansion as an explosion is probably not a good idea in any case; it suggests some input of energy that moves matter from an initial state of rest. Classically, this is false: the expansion merely appears as an initial condition. This might reasonably seem to be evading the point, and it is one of the advantages of inflationary cosmology that it supplies an explicit mechanism for starting the expansion: the repulsive effect of vacuum energy. However, if the big bang is to be thought of explosively, then it is really many explosions that happen everywhere at once; it is not possible to be outside the explosion, since it fills all of space. Because the density rises without limit as t -> 0, the mass within any sphere today (even the size of our present horizon) was once packed into an arbitrarily small volume. Nevertheless, this does not justify the ``primaeval atom'' terminology unless the universe is closed. The mass of an open universe is infinite; however far back we run the clock, there is infinitely more mass outside a given volume than inside it.
A track athlete does two and a half laps from the starting line on a track of normal shape and size. The best way to describe the difference between the athlete's distance versus displacement is
Answer:
The displacement and the distance were equal early in the run, however due to the shape of the track the distance is greater than the displacement.
List Three units commonly used to measure volume
Answer:
Three common units of volume are:
cubic centimeters.
liters.
gallons.
Explanation:
How many centimeters are there in 2.35m?
Answer:
there are 235cm in 2.35m
What contributes to the better resolution of the Hubble telescope.
Answer:
Because it is above the Earth's atmosphere. The atmosphere disturbs the starlight (a bit like looking through water) and blurs the images. So Hubble's images are much sharper than those from other telescopes.
Explanation:
Answer:
Hubble's orbit outside the distortion of Earth's atmosphere allows it to capture extremely high-resolution images with substantially lower background light than ground-based telescopes. It has recorded some of the most detailed visible light images, allowing a deep view into space.
During which process do particles of matter release energy?
freezing
During freezing, the temperature of a substance remains constant while the particles in the liquid form a crystalline solid. Because particles in a liquid have more energy than particles in a solid, energy is released during freezing. This energy is released into the surroundings.
prove that:v²= u² + 2as
What is the formula to calculate distance moved.
If the velocity of a bicycle is 15m/s,how long will it take to cover a distance of 18 kilometres.
To prove:
v^2 =u^2 + 2as
we have,
a = v-u/t
or, t= v- u/a......(i)
Again,
s = u + v /2*t...........( ii )
Substitutung the value of 't' from equation (i) in equation ( ii ) , we have,
s= (u+v/2) * ( v- u/a)
or, s=(v^2 - u^2) /2a
or, 2as = v^2 - u^2
therefore,
v^2= u^2 + 2as
proved...
hope this helps!!!!Changes in forms of energy are called energy?
Answer:
Energy transformation
Explanation:
Energy transformation is when energy changes from one form to another.
Use your understanding of d-t graphs to describe what is happening in the graph.
A car traveling south is 200 kilometers from its starting point after 2 hours. What is the average velocity of the car? (OP A. 100 kilometers/hour south B. 200 kilometers/hour C. 200 kilometers/hour north 100 kilometers/hour
Answer:
A
Explanation:
take note that v=d/t (velocity is distance over(divided by) time, so in this case it would be 200 (distance) divided by 2 (time)
A small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground. Until it reaches terminal speed, the magnitude of its acceleration is given by a = g − Bv. After falling 0.400 m, the Styrofoam effectively reaches terminal speed, and then takes 5.40 s more to reach the ground.(a) What is the value of the constant B?s-1(b) What is the acceleration at t = 0?m/s2 (down)(c) What is the acceleration when the speed is 0.150 m/s?m/s2 (down)
Answer:
Explanation:
If a small piece of Styrofoam packing material is dropped from a height of 1.90 m above the ground and reaches a terminal speed after falling 0.400m, the Change in distance will be 1.90m - 0.400 = 1.50m
If it takes 5.4secs fo r the Styrofoam to reach the ground, the terminal velocity will be expressed as;
Vt = change in distance/time
Vt = 1.5m/5.4s
Vt = 0.28m/s
Note that the Styrofoam reaches its final velocity when the acceleration is zero.
To get the constant value B from the equation a = g-Bv
a = 0m/s²
g = 9.81m/s²
v = 0.28m/s
Substituting the parameters into the formula.
0 = 9.81-0.28B
-9.81 = -0.28B
Divide both sides by -0.28
B = -9.81/-0.28
B = 35.04
b) at t = 0sec, the initial terminal velocity is also zero.
Substituting v = 0 into the equation to get the acceleration.
a = g-Bv
a = g-B(0)
a = g
Hence the acceleration at t =0s is equal to the acceleration due to gravity which is 9.81m/s²
c) Given speed v = 0.150m/s
g = 9.81m/s²
B = 35.04
Substituting the given data into the equation a = g-Bv
a = 9.81-35.04(0.15)
a = 9.81 - 5.26
a = 4.55m/s²
Answer:
a
[tex]v = 0.28 \ m/s [/tex]
b
[tex]a = 9.8 m/s^2[/tex]
c
[tex]a = 4.55 \ m/s^2[/tex]
Explanation:
From the question we are told that
The fall height is [tex]h = 1.90 \ m[/tex]
The magnitude of the acceleration is [tex]a = g -Bv[/tex]
The height at which terminal speed is attained is [tex]h_t = 0.400 \ m[/tex]
The time taken to reach the ground from the terminal velocity height is t = 5.40 s
Generally the height which object traveled with terminal velocity is
[tex]H = h- h_t[/tex]
=> [tex]H = 1.90 - 0.400[/tex]
=> [tex]H = 1.50 \ m [/tex]
Generally the terminal velocity is mathematically represented as
[tex]v = \frac{H}{t}[/tex]
=> [tex]v = \frac{1.50}{5.40}[/tex]
=> [tex]v = 0.28 \ m/s [/tex]
Generally at terminal velocity , acceleration is zero so
[tex] g -Bv = 0 [/tex]
substituting
[tex]9.8 \ m/s^2[/tex]
=> [tex] 9.8 -B (0.28) = 0 [/tex]
=> [tex] v = 35 \ m/s [/tex]
Generally at t = 0 s the velocity v = 0 (That no motion at time zero)
So from acceleration equation
[tex]a = 9.8 -35(0)[/tex]
=> [tex]a = 9.8 m/s^2[/tex]
Generally when the speed v = 0.150 m/s
The acceleration is
[tex]a = 9.8 -35(0.150)[/tex]
=> [tex]a = 4.55 \ m/s^2[/tex]
A car is moving at a velocity of 25 km/h and increases velocity to 1200 km/h in 2 min. what is the acceleration?
plz help me out, thanks guys
Answer:
a = 2.72 [m/s2]
Explanation:
To solve this problem we must use the following kinematics equation:
[tex]v_{f} =v_{o} + a*t[/tex]
where:
Vf = final velocity = 1200 [km/h]
Vo = initial velocity = 25 [km/h]
t = time = 2 [min] = 2/60 = 0.0333 [h]
1200 = 25 + (a*0.0333)
a = 35250.35 [km/h2]
if we convert these units to units of meters per second squared
[tex]35250.35[\frac{km}{h^{2} }]*(\frac{1}{3600^{2} })*[\frac{h^{2} }{s^{2} } ]*(\frac{1000}{1} )*[\frac{m}{km} ] = 2.72 [\frac{m}{s^{2} } ][/tex]
An object is sliding to the right along a straight line on a horizontal surface. The graph shows the object's velocity as a function of time. What is the object's displacement during the
time depicted in the graph?
Answer:
0mExplanation:
Velocity is the change of displacement of a body with respect to time.
Velocity = Displacement/Time
Displacement = Δv * Δt
From the graph, it can be seen that the object sliding along the horizontal has a velocity of 0m/s since it starts travelling when v = 0m/s
For the time;
Δt =t2-t1
Δt = 8-0
Δt = 8s
object's displacement = 0 * 8
Hence the object displacement is 0m
What is the speed of a jet plane that flies 7200 km in 9 hours (in km/hr)?
Explanation:
800 km per her because you have to divide 7200 by 9
Answer:
800 km/hr
Explanation:
7200 km divided by 9 hr=800 km/hr :)
What is another name for non-traditional sports?
A. Random
B. Foreign
C. Alternative
Ο Ο
D. Team
SUBMIT
Answer: C Alternative
Explanation:
Hope this helps
Another name for non-traditional sports is Alternative. Alternative sports often involve unconventional or niche activities that may appeal to specific groups or subcultures. The correct option is option (c).
Another name for non-traditional sports is "alternative sports." These are sports or physical activities that may not be as mainstream or commonly recognized as traditional sports like football, basketball, or tennis.
Alternative sports often involve unconventional or niche activities that may appeal to specific groups or subcultures.
They provide alternatives to more traditional sports and can include activities like parkour, skateboarding, rock climbing, ultimate frisbee, and many others. Therefore, The correct option is option (c).
To know more about traditional sports:
https://brainly.com/question/30096950
#SPJ6
The magnetic field lines outside a bar magnet
a originate from the South poll and end at its
north pole
b) originate from the north pole and end at
its east pole
c) Orginate from the south pole and end at its
west pole
d) origenate from the north pole and ent at its
south pole
At the bottom of a hill, a car has an initial velocity of +16.0 meters per second. The car is uniformly accelerated at -2.20 meters per second squared for 5.00 seconds as it moves up the hill. How far does the car travel during this 5.00-second interval?
1.) 107m
2.) 74.5m
3.) 52.5m
4.)25.0m
Answer:
3) 52.5 m
Explanation:
d = v₁t + 1/2at²
d = 16 m/s (5s) + 1/2(-2.2m/s²) (5s)² = 52.5 m
The car travels for 52.5m during the 5 seconds interval
In order to get the distance traveled by car, we will use the equation of motion. The equation of motion for calculating the distance is expressed as:
[tex]S = ut+\frac{1}{2}at^2[/tex] where;
u is the initial velocityt is the time takena is the accelerationGiven the following parameters
u = 16m/s
a = -2.20m/s²
t = 5secs
Substitute the given values into the expression as shown:
[tex]S = 16(5)+\frac{1}{2}(-2.20)(5)^2\\S=80-1.10(25)\\S=80-27.5\\S= 52.5m[/tex]
Hence the car travels for 52.5m during the 5 seconds interval.
Learn more here: https://brainly.com/question/13438064
Fido has a weight of 43 N. What is the mass of Fido?
m = 4.3 kg
Explanation:Hi there !
use formula
G = m×g => m = G/g
g ≈ 10N/kg
replace G ; g
m = 43N/(10N/kg)
m = 4.3 kg
Good luck !
applied to it
The acceleration of an object is always in the direction of the
OA) net force
OB) thermal energy
O C) frictional force
What happens to a football thrown in space ,and why
hdfjfAnswer:
Explanation:
nbdhfb
Answer:
In deep space, far enough away from large objects like stars and planets that gravity may be neglected, a thrown ball will travel in a straight line and the person throwing the ball will also travel in a straight line in the opposite direction.Explanation:
What what is the direction of an object’s acceleration if it is being pulled upward by a rope at a constant speed?
Answer:
the direction is towards upward.i think.
On a distance-time graph, time is usually the ____ variable ?
A. dependent
B. independent
Answer: dependent
Explanation: Hope this helps :)
A car begins from rest and accelerates at a rate of +3.0 m/s2 for 5.0 seconds. what is the car's final speed?
Answer:
15m/s
Explanation:
we know that
v = u + at
= 0+ 3*5
=15m/s
A chemist is likely to do which of the following
Answer:
I need to see the answer choices firsts silly
Explanation:
I need to see the answer choice firsts in order to answer because it can be many different answers
A 202 kg bumper car moving right at 8.50 m/s collides with a 355 kg car at rest. Find the total momentum of the system .
Answer:
I just did this problem so I promise you my answer is correct the total momentum of the system is 1717.
Explanation:
What you do is find the momentum of the first object which is simple enough 202(8.5) which equals 1717 and an object at rest will have no momentum which is shown when you have to plug in a 0 for velocity and multiply you get zero. Then to find the total you just add 1717+0 which obviously gives you 1717.
Answer:
1717
Explanation:
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a driver brings a car to a full stop in 2.0 s. if the car was initially traveling at 22 m/s, what is the acceleration
Answer: -11 m/s^2
Explanation: 22/2, it went to a full stop so it’s negative
The acceleration will be "-11 m/s²".
According to the question,
Time,
t = 2 sInitially traveling,
[tex]V_0[/tex] = 22 m/sFull stop means,
V = 0As we know, the formula:
→ [tex]V = at +V_0[/tex]
By substituting the values, we get
→ [tex]0 = a\times t+V_0[/tex]
→ [tex]0 = a\times 2+22[/tex]
→ [tex]2a = -22[/tex]
→ [tex]a = -\frac{22}{2}[/tex]
→ [tex]= -11 \ m/s^2[/tex]
Thus the solution above is appropriate one.
Learn more about acceleration here:
https://brainly.com/question/18986198
is a person believes that dreams have hidden meaning how or she would agree with Freud's ideas about _ content?
A. manifest
B. latent
C. hidden
D. lucid
Answer:B ez
Explanation:
1. Applied research observational evidence 2. Basic research the experimental factor that changes in response to a change in the independent variable 3. Control research that results in a product that can be sold for profit 4. Dependent variable a proposed explanation for a scientific problem that itself can be tested by experimentation 5. Empirical evidence a quantity in an experiment that remains unchanged or constant 6. Hypothesis research that expands knowledge in a particular area 7. Independent variable the experimental factor that is changed by the scientist
Answer:
This question is about matching each definition with its correct term. Please find the term matched with their appropriate definition below.
Explanation:
1. Empirical evidence: An empirical evidence is an observational evidence i.e an evidence gathered by observation or use of senses.
2. Dependent variable: Dependent variable is an experimental factor that changes in response to a change in the independent variable. In other words, it is dependent on the independent variable.
3. Applied research: Applied research is a type of research oriented at solving a present problem or need. It encompasses the production of products that can be sold for profit.
4. Hypothesis: A hypothesis in an experiment is a proposed explanation for a scientific problem that itself can be tested by experimentation. A hypothesis aims at providing a testable explanation to an observed problem.
5. Control: A control is a quantity in an experiment that remains unchanged or constant. It is kept the same by the experimenter for all groups in the experiment in order not to influence the outcome.
6. Basic research: Basic research is the research that expands knowledge in a particular area. It is the kind of research that aims at filling a knowledge void or satiating curiosity.
7. Independent variable: The independent variable is the experimental factor that is changed or manipulated deliberately by the scientist.
