2. The Venn diagram shows the sets U, X and Y.UXY.34 246..9.512:31List the elements of the following sets:(a) X(b) Y(c) U(d) XUY(e) XnY(g) X\Y(h) Y\X(f) X'(1) (XY)2:31
Answers
Given the Venn diagram in the question, we can proceed to answer the questions as follow
[tex]\begin{gathered} X=\text{members of the subset X} \\ This\text{ gives: 1,2,3,4, and 5} \end{gathered}[/tex][tex]\begin{gathered} QuestionA\text{ } \\ X=1,2,3,4,and\text{ 5} \\ \end{gathered}[/tex]Question B
Y= members of subset Y
Y =2,4,6, and 8
Question C
U means that we should list all elements in the universal set
U = ALL members of the set
U = 1,2,3,4,5,6,7,8, and 9
Question D
This is the union of both sets X and Y. This means we will list all the members that are found in the 2 subsets
[tex]\text{XUY}=1,2,3,4,5,6,\text{ and 8}[/tex]Question E
[tex]\begin{gathered} \text{XnY means we are to find the elements that are common to both X and Y} \\ \text{XnY}=2\text{ and 4} \end{gathered}[/tex]Question F
X' means that we should find all members of the set except that of X
[tex]X^{\prime}=6,7,8,\text{ and 9}[/tex]Question G
X\Y means that we should list the elements of X that are not found in Y
X\Y= 1,3, and 5
Question H
Y\X means that we should list the elements of Y that are not found in X
Y\X= 6, and 7
Question I
To solve (XnY)' we will follow the steps below
Step 1: Find (XnY)
[tex]\text{XnY}=2\text{ and 4}[/tex]Step 2: Find (XnY)'
[tex]We\text{ will list all elements aside (XnY)}[/tex][tex](XnY)^{^{\prime}}\Rightarrow1,3,5,6,7,8,\text{and 9}[/tex]
Related Questions
2+2 is what i need help???
Answers
We have the following problem given:
[tex]2+2=4[/tex]Then the final answer for this case would be 4
If a red and a blue fair six sided die are rolled what is the probability the result is 8 or divisible by 3?
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SOLUTION:
Step 1:
In this question, we are given that;
If a red and a blue fair six-sided die are rolled.
What is the probability the result is 8 or divisible by 3?
Step 2:
The table for the two dice rolled together is as shown below:
Green 1 2 3 4 5 6
Red
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
Step 3:
The probability that the result is 8 =
[tex]\begin{gathered} =\text{ }\frac{\nu mber\text{ of 8}}{\text{Total number }} \\ =\text{ }\frac{5}{36} \end{gathered}[/tex]Next,
The probability that the result is divisible by 3
=
[tex]\frac{12}{36}[/tex]Finally, the probability that the result is 8 or divisible by 3, we have that:
[tex]\frac{5}{36}+\frac{12}{36}\text{ =}\frac{17}{36}[/tex]
In 2011, the average daily temperature in Darrtown was 65°F. In 2012, the average daily temperature increased by 3% but then decreased by 4.5% in 2013.What was the daily average temperature in Darrtown in 2013?A.62°FB.64°FC.68°FD.74°F (thank you in advanced for who helps i was having trouble with this question)
Answers
Solution
In 2011 The temperature in Darrtown is
[tex]65^{\circ}F[/tex]The temperature increased by 3% in 2012
The temperature will be
[tex](1+\frac{3}{100})\times65=(1.03)(65)=66.95^{\circ}F[/tex]The temperature decreased by 4.5% in 2013
The temperature will be
[tex]\begin{gathered} (1-\frac{4.5}{100})\times66.95=0.955\times66.95=63.93725 \\ \\ (1-\frac{4.5}{100})\times66.95=64^{\circ}F\text{ (to the nearest whole number)} \end{gathered}[/tex]Therefore, the temperature in 2013 is 64 degrees Fareheint
Option B
need help with this as soon as possible, answer quick
Answers
Answer:
Given points are,
A'(2,3) and A(3,-4), under the translation.
we get the graph as,
where B is A(3,-4) and A is A'(2,3).
A translation by 1 unit left and 7 units up.
Answer is:
A translation by 1 unit left and 7 units up.
McGraw-H….A ALEKS - Mi...O POLYNOMIAL AND RATIONAL FUNCTIONSThe Factor Theorem
Answers
SOLUTIONS
Using factor theorem to solve the equation below:
[tex]-x^3+4x^2-8=0[/tex][tex]\begin{gathered} -x^3+4x^2-8 \\ -x(x^2-4x+8) \end{gathered}[/tex]The coordinates of triangle LMN are shown.YL(-1,4)XN (4, -1)M(-1, -3)What is the length of LM? Enter the answer in the box.unit(s)
Answers
Given data:
The given coordinate of L is (-1,4).
The given coordinate of M is(-1, -3).
The expression for LM length is,
[tex]\begin{gathered} LM=\sqrt[]{(-1-(-1))^2+(-3-4)^2} \\ =\sqrt[]{0+49} \\ =7 \end{gathered}[/tex]Thus, the LM length is 7 units.
Evaluation the expression -19-9-(11)
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Then the final answer will be -17.
The court ruled that Lox Auto was liable in the death of an employee.The settlement called for the company to pay the employee's widow $60,000 at theend of each year for 20 years. Find the amount the company must set aside today,assuming 5% compounded annually.
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We have to calculate the present value PV of a annuity.
The payment is yearly and it is P=60,000.
The interest rate is 5% (r=0.05), compounded annually (m=1).
The number of periods is n=20 years.
Then, we can use the formula for the present value of a annuity:
[tex]\begin{gathered} PV=P\cdot\frac{1-\frac{1}{(1+r)^n}}{r} \\ PV=60000\cdot\frac{1-\frac{1}{1.05^{20}}}{0.05} \\ PV\approx60000\cdot\frac{1-\frac{1}{2.653}}{0.05} \\ PV\approx60000\cdot\frac{1-0.377}{0.05} \\ PV\approx60000\cdot\frac{0.623}{0.05} \\ PV\approx60000\cdot12.462 \\ PV\approx747720 \end{gathered}[/tex]Answer: the company must set aside $747,720.
I got the first part I’m not sure of the 2nd is it 38.5
Answers
We will have the following:
The surface area of the onion can be best modeled by a sphere. Base on the model, the approximate area of the onion is 38.5 square inches:
[tex]A_s=4\pi(\frac{3.5}{2})^2\Rightarrow A_s\approx38.5[/tex]Tell whether the graph would be continuous or discrete2. A pet store is selling puppies for $200 each. It has 8 puppies for sale.AcontinuousB) discrete
Answers
Given:
Cost of each puppy = $200
Number of puppies = 8
Here, the equation for total cost of puppies will be:
C = 200x
Where x represents the number of puppies sold
Cost of 1 puppy = $200
Cost of 2 puppies = $200(2) = $400
Cost of 3 puppies = $200(3) = $600
If you continue with the pattern you'll see the graph has a rate of change of 200
To determine if the graph will be continuous or discrete, we have:
For a graph to be continuous, the points on the graph must be connected with a continuos line, while for a graph to be discrete the points are series of unconnected points just like in a scatter plot.
The graph of this will be a discrete graph. A discrete graph have set of values(points)
ANSWER:
B. discrete
Find the equation of the linear function represented by the table below in slope-intercept form. Answer: y=
Answers
Answer:
y = 2x + 6
Explanation:
The slope-intercept form of a linear equation can be found as:
[tex]y=m(x-x_1)+y_1[/tex]Where m is the slope and it is calculated as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]And (x1, y1) and (x2, y2) are values from the table. So, we can replace (x1, y1) by (0,6) and (x2, y2) by (1, 8):
Then, the slope is:
[tex]m=\frac{8-6}{1-0}=\frac{2}{1}=2[/tex]Therefore, the equation of the line is:
[tex]\begin{gathered} y=2(x-0)+6 \\ y=2x+6 \end{gathered}[/tex]So, the answer is y = 2x + 6
a computer program is in Shannon's computer carries out a single mathematical operation in 1.5 * 10 over 6 seconds how much time would the program take to complete 2.5 * 10/3 mathematical operations
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Question:
Solution:
This computer program carries out a single mathematical operation in
[tex]1.5x10^{-6}\text{ seconds}[/tex]then, to complete 2.5 x 10^3 mathematical operations the program will take a time of:
[tex](1.5x10^{-6})(2.5x10^3)=3.75x10^{-3}[/tex]thus, the correct answer is:
[tex]3.75x10^{-3}[/tex]do you think you'd be able to help me with this
Answers
x = wz/y
Explanation:[tex]\frac{w}{x}=\frac{y}{z}[/tex]To solve for x, first we need to cross multiply:
[tex]w\times z\text{ = x }\times y[/tex]Now we make x the subject of the formula:
[tex]\begin{gathered} To\text{ make x stand alone, we n}ed\text{ to remove any other variable around x} \\ \text{divide both sides by y}\colon \\ \frac{w\times z}{y}\text{ =}\frac{\text{ x }\times y}{y} \end{gathered}[/tex][tex]x\text{ = }\frac{wz}{y}[/tex]Question is stated in picture. The figure is a triangular piece of cloth
Answers
Answer:
Alternative D - 8 sin(35°)
Step-by-step explanation:
Sin(x) is defined as:
[tex]\begin{gathered} \sin (x)=\frac{\text{Opposite side}}{Hypotenuse\text{ }} \\ \end{gathered}[/tex]In this exercise,
BC is the opposite side to 35°
AC is the hypotenuse and measures 8 in
Then:
[tex]\begin{gathered} \sin (35\degree)=\frac{BC}{8} \\ \sin (35\degree)\cdot8=BC \\ BC=8\sin (35\degree) \end{gathered}[/tex]1. Caitlyn is going away to college and will need to rent a truck to helpmove. The cost of the truck is $35 plus $0.79 per mile. If her collegeis 85 miles away and she budgeted $100 for the rental, will she haveenough money?
Answers
1. Caitlyn is going away to college and will need to rent a truck to help
move. The cost of the truck is $35 plus $0.79 per mile. If her college
is 85 miles away and she budgeted $100 for the rental, will she have
enough money?
we know that
The equation in slope intercept form of this situation is
y=mx+b
where
m=$0.79 per mile
b=$35
y -----> is the total cost
x -----> the number of miles
so
y=0.79x+35
so
For x=85 miles
substitute
y=0.79(85)=35
y=$102.15
we have that
102.15 > 100
therefore
she not have enough moneySelect the table of values that contains ordered pairs that, when plotted, provide the best representation of the curve of the function
Answers
As given by the question
There are given that the equation:
[tex]y=-2(x+3)^2+4[/tex]Now,
Put the value of x into the given equation and find the value of y from all the tables one-by-one and match their value of x and y are equal or not.
Then,
Form the option third,
Put x = -2 to find the value of y, then match the value of y with the given value of y in the table.
So,
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(-2+3)^2+4 \\ y=-2(1)^2+4 \\ y=-2+4 \\ y=2 \end{gathered}[/tex]Now,
Put x = -1, then:
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(-1+3)^2+4 \\ y=-2(2)^2+4 \\ y=-2(4)+4 \\ y=-8+4 \\ y=-4 \end{gathered}[/tex]Then,
Put x = 0, then:
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(0+3)^2+4 \\ y=-2(3)^2+4 \\ y=-2(9)+4 \\ y=-18+4 \\ y=-14 \end{gathered}[/tex]Then,
Put 1 into the given equation instead of x:
So,
[tex]\begin{gathered} y=-2(x+3)^2+4 \\ y=-2(1+3)^2+4 \\ y=-2(4)^2+4 \\ y=-2(16)+4 \\ y=-32+4 \\ y=-28 \end{gathered}[/tex]And,
Put x = 2, so:
[tex]\begin{gathered} y=-2(2+3)^2+4 \\ y=-2(5)^2+4 \\ y=-2(25)+4 \\ y=-50+4 \\ y=-46 \end{gathered}[/tex]Now,
From option d, all values of x and y are matched also but curve representation is matched in option D.
Hence, the correct option is D.
Consider the following equation of a parabola.y? + 4y = 8r + 4Step 1 of 3: Find the focus of the parabola.
Answers
Given the equation:
[tex]y^2+4y=8x+4[/tex]Let's find the focus of the parabola.
To find the focus of the parabola, let's first rewrite the equation in vertex form:
[tex]y=a(x-h)^2+k[/tex]We have:
[tex]undefined[/tex]In ACDE, J is the centroid. If JG=21 find CG. D F G C E H
Answers
Let's begin by identifying key information given to us:
We have triangle CDE
J is the centroid
[tex]\begin{gathered} JG=21 \\ \text{The centroid of a triangle divides }\frac{2}{3\text{ }}\text{the distance from}verte\text{x to midpoint of the sides} \\ \Rightarrow JG=\frac{2}{3}CG \\ \Rightarrow21=\frac{2}{3}CG=\frac{63}{2} \\ \therefore CG=\frac{63}{2}=31.5 \end{gathered}[/tex]Jim began a 156 mile bike trip to build up stamina . Unfortunately his bike chain broke so he finished walking. Th whole trip took 6 hours. If Jim walks at a rate of 5 miles per hour and rides at 33 miles per hour find the amount he spent on the bike.
Answers
This diagram represents the problem
We know that distance = speed*time; D=S*t
Total distance: 156 miles
time: 6 h
Speed1: 33 miles/h
Speed2: 5 miles/h
for interval 1:
[tex]\begin{gathered} D_1=S_1\cdot t_1 \\ D_1=33\cdot t_1 \end{gathered}[/tex]for interval 2:
[tex]\begin{gathered} D_2=S_2\cdot t_2 \\ D_2_{}=5\cdot t_2 \end{gathered}[/tex]for the whole trip: -Eq 1. Distance
[tex]\begin{gathered} D=D_1+D_2 \\ D=33\cdot t_1+5\cdot t_2 \\ 156=33\cdot t_1+5\cdot t_2 \end{gathered}[/tex]and also: -Eq 2. Time
[tex]\begin{gathered} t=t_1+t_2 \\ 6=t_1+t_2 \end{gathered}[/tex]Now we have a system of 2 equations with 2 unknowns.
Let's solve it!
[tex]\begin{gathered} 156=33t_1+5t_2 \\ t_1=\frac{156-53t_2}{33} \\ \frac{156-5t_2}{33}+t_2=6 \\ t_2=\frac{3}{2} \\ t_1=\frac{156-5\cdot\frac{3}{2}}{33} \\ t_1=\frac{9}{2} \end{gathered}[/tex]We can see that he spent 4.5 hours riding the bike and 1.5 h walking
Determine the angle relationship. Drag the correct answer to the blank. what is the angle relationship of < 3 & <7
Answers
we have that
between m<3 and m<7 -----> no relationship (because q and p are not parallel)
Part 2
the relationship between m<12 and m<10
is
vertical angles
m<12=m<10 ------> by vertical angles
Question 13 of 18Graph the solution to the following inequality on the number line.x² - 4x ≥ 12
Answers
Step 1
Given; Graph the solution to the following inequality on the number line.
x² - 4x ≥ 12
Step 2
[tex]\begin{gathered} x^2-4x\ge \:12 \\ Rewrite\text{ in standard form} \\ x^2-4x-12\ge \:0 \\ Factor\text{ the inequality} \\ \left(x+2\right)\left(x-6\right)\ge \:0 \end{gathered}[/tex][tex]\begin{gathered} Identify\text{ the intervals} \\ x\le \:-2\quad \mathrm{or}\quad \:x\ge \:6 \end{gathered}[/tex]Thus, the number line will look like
Answer; The solution to the inequality graphed on a number line is seen below
[tex]x\le \:-2\quad \mathrm{or}\quad \:x\ge \:6[/tex]In a robotics competition, all robots must be at least 37 inches tall to enter the competition.Read the problem. Which description best represents the heights a robot must be?Any value less than or equal to 37Any value greater than or equal to 37Any value greater than 37Any value less than 37
Answers
Solution
Since the robots must be at least 37 inches tall to enter the competition.
Therefore, the height of any robot must be Any value greater than or equal to 37
I need help please!!
Answers
A snail starts crawling toward a flower 7 feet away. The snail crawls 2 feet every hour for 3 hours. What graph represents the distance of the snail to the flower over that time period? Use the graphing tool to graph your answer
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y represents the distance of the snail to the flower, in ft
x represents time, in hours
In the beginning, the distance of the snail to the flower is 7 feet. Then, the point (0, 7) is on the graph
After the first hour, the snail crawls 2 feet, then its distance to the flower is 7 - 2 = 5 ft. Then, the point (1, 5) is on the graph.
After the second hour, the snail crawls another 2 feet, then its distance to the flower is 5 - 2 = 3 ft. Then, the point (2, 3) is on the graph.
After the third hour, the snail crawls another 2 feet, then its distance to the flower is 3 - 2 = 1 ft. Then, the point (3, 1) is on the graph.
The graph is
This year, Buffalo, New York had 45 inches of snow in January. Last year, Buffalo had 19 inches of snow in January. How much more snow did Buffalo receive this January? Show your work in the space below. Don't forget to label the units on your answer.
Answers
In January this year, 45 inches of snow. In January last year, it was 19 inches. The difference betwen the measures gives us how much more was received this year.
This difference
= 45 inches - 19 inches
= 26 inches
Find the equaton of the line in point-slope form that passes through (-4,6) and (-2,5)
Answers
Hello can you please help me with problem number 12
Answers
Turn the 48in to ft
[tex]\begin{gathered} 1ft=12in \\ \\ 48in\times\frac{1ft}{12in}=4ft \end{gathered}[/tex]Then, 48 inches is equal to 4ft.
Comparing the given quatities you get that:
48inches > (greater than) 3ftFill in the table using this function rule.
Answers
Answer:
-8, 2, 12, 22
Step-by-step explanation:
[tex]y = 5x+2\\y = 5(-2)+2\\y=-10+2\\y=-8[/tex]
[tex]y = 5x+2\\y = 5(0)+2\\y=0+2\\y=2[/tex]
[tex]y = 5x+2\\y = 5(2)+2\\y=10+2\\y=12[/tex]
[tex]y = 5x+2\\y = 5(4)+2\\y=20+2\\y=22[/tex]
f(x) = x2 + 4 and g(x) = -x + 2Step 2 of 4: Find g(d) - f(d). Simplify your answer.Answer8(d) - f(d) =
Answers
Answer:
[tex]\begin{equation*} g(d)-f(d)=-d^2-d-2 \end{equation*}[/tex]Explanation:
Given:
[tex]\begin{gathered} f(x)=x^2+4 \\ g(x)=-x+2 \end{gathered}[/tex]To find:
[tex]g(d)-f(d)[/tex]We can find g(d) by substituting x in g(x) with d, so we'll have;
[tex]g(d)=-d+2[/tex]We can find f(d) by substituting x in f(x) with d, so we'll have;
[tex]f(d)=d^2+4[/tex]We can now go ahead and subtract f(d) from g(d) and simplify as seen below;
[tex]\begin{gathered} g(d)-f(d)=(-d+2)-(d^2+4)=-d+2-d^2-4=-d^2-d+2-4 \\ =-d^2-d-2 \\ \therefore g(d)-f(d)=-d^2-d-2 \end{gathered}[/tex]Therefore, g(d) - f(d) = -d^2 - d -2
In the triangle below, if B = 69°, A = 32°, c = 5.7, use the Law of Sines to find a. Round your answer to the nearest hundredth.
Answers
We know that the interior angles have to add to 180°, then we have that:
[tex]\begin{gathered} C=180-69-32 \\ C=79 \end{gathered}[/tex]Hence angle C=79°.
Now that we know the angle C we can use the law of sines to find a; the law of sines states that:
[tex]\frac{\sin A}{a}=\frac{\sin B}{b}=\frac{\sin C}{c}[/tex]From this we have the equation:
[tex]\frac{\sin A}{a}=\frac{\sin C}{c}[/tex]Plugging the values given and solving for a we have:
[tex]\begin{gathered} \frac{\sin32}{a}=\frac{\sin 79}{5.7} \\ a=(5.7)\frac{\sin 32}{\sin 79} \\ a=3.08 \end{gathered}[/tex]Therefore a=3.08
