2-x+ 3-X-4
where a and b are integers.
Work out the value of a and the value of b.
can be written as a single fraction in the form
ax+b
x²-16

Answers

Answer 1

Answer:

2-×+3-×-4=0

Step-by-step explanation:

×=1\2

0.5,2`1


Related Questions

Is x = -2 the linear equation that matches this table of ordered pairs?Explain why or why not.Xy-2 7-2 1-2 -5(x, y)(-2,7)(-2, 1)(-2,-5)

Answers

Answer:

All the points given (-2,7) (-2,1) (-2,-5) have the x-coordinate of -2, then those points lie in the x=-2, so it matches the table.

Help on math question precalculus ChoicesVertical shift Period DomainRange Phase shift Amplitude

Answers

All the x-values that satisfy the function - Domain

Translating the sine or cosine curve up or down - Vertical shift

How long a given function takes to repeat itself - Period.

A horizontal shift of a sine or cosine function- Phase shift

All the y-values that satisfy the function- Range

Distance from the horizontal axis or midline to the maximum and minimum points - Amplitude

Solve 2/3 (6w+12) this equation

Answers

Answer:

4w+8

Step-by-step explanation:

Faith borrowed $2250 for home repairs. She paid back 24 payments of$132 each. How much did she pay in interest on the loan?a. $87.71b. $2,520c. $918d. $4.38

Answers

• We are given that Faith paid $132 for 24 months.

So; 132 * 24 = $3168

• Since we know that Faith initially borrowed $2250

Interest paid = $3168 - $2250

= $918

• Option C is the correct choice.

If a girl has 7 skirts, 9 shirts, and 5 pairs of shoes, how many outfits canshe wear?

Answers

Okay, here we have a Combination Problem, we need just multiply to get the answer, of this mode:

[tex]C=7\cdot9\cdot5=315[/tex]

She can wear 315 outfits.

The highly temperature one day was -3 the low temperature was -7 what was the difference

Answers

7-3= 4 degree difference

Compare A and B in three ways, where A = 51527 is the number of deaths due to a deadly disease in the United States in 2005 and B = 17241 is the number of deaths due to the same disease in the United States in 2009. a. Find the ratio of A to B. b. Find the ratio of B to A. c. Complete the sentence: A is ____ percent of B.

Answers

ANSWER

Ratio of A to B = 2.99 (to 2 decimal places)

Ratio of B to A = 0.33 (to 2 decimal places)

A is 299% of B (to nearest integer)

STEP BY STEP EXPLANATION

for ratio of A to B:

[tex]\begin{gathered} \frac{A}{B}\text{ = }\frac{51527}{17241}\text{ = }2.98863 \\ \text{ = 2.99 (to 2 decimal places)} \end{gathered}[/tex]

for ratio of B to A:

[tex]\begin{gathered} \frac{B}{A}\text{ = }\frac{17241}{51527}\text{ = 0.33460 } \\ \text{ = 0.33 (to 2 decimal places)} \end{gathered}[/tex]

A is x % of B:

[tex]\begin{gathered} A\text{ = }\frac{x}{100}\times B \\ x\text{ = }\frac{100\text{ }\times A}{B} \\ x\text{ = }\frac{100\text{ }\times\text{ 51527}}{17241}\text{ = 298.86} \\ x\text{ = 299\% (to nearest integer)} \end{gathered}[/tex]

Hence, the ratio of A to B = 2.99 (to 2 decimal places), B to A = 0.33 (to 2 decimal places) and A is 299% of B (to nearest integer).

(A) A shipment of 10 cameras will likely have 6 defectives. If a person buys 2 cameras, what is the probability of getting 2 defectives?(B) What are the odds in favor of getting a defective camera?

Answers

To solve the exercise, you can use the formula of the binomial distribution:

[tex]\begin{gathered} P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ \text{ Where } \\ n\text{ is the number of trials (or the number being sampled)} \\ x\text{ is the number of successes desired} \\ p\text{ is the number of getting a success in one trial} \end{gathered}[/tex]

So, in this case, we have:

[tex]\begin{gathered} n=10 \\ p=\frac{6}{10}=0.6 \end{gathered}[/tex]

Because "success" is that there are defective cameras, 6 defective cameras out of 10 in total.

For part A, we have:

[tex]\begin{gathered} x=2 \\ P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ P(2)=\binom{10}{2}\cdot0.6^2\cdot(1-0.6)^{10-2} \\ P(2)=\binom{10}{2}\cdot0.6^2\cdot(0.4)^8 \\ P(2)=45\cdot0.36\cdot0.00065536 \\ P(2)=0.0106 \end{gathered}[/tex]

Therefore, the probability of getting 2 defective cameras is 0.0106.

For part B, we have:

[tex]\begin{gathered} x=1 \\ P(x)=\binom{n}{x}p^x(1-p)^{n-x} \\ P(1)=\binom{10}{1}\cdot0.6^1\cdot(1-0.6)^{10-1} \\ P(1)=\binom{10}{1}\cdot0.6^1\cdot(0.4)^9 \\ P(1)=10\cdot0.6\cdot0.000262144 \\ P(1)=0.0016 \end{gathered}[/tex]

Therefore, the probability of getting one defective camera is 0.0016.

The diameter of circle is 20 inches. find the circumference in terms of pi

Answers

The below formula is used to find the circumference of a circle;

[tex]C=2\pi r[/tex]

But we know that the diameter of a circle is expressed as;

[tex]d=2r[/tex]

Let's replace 2r with d in the 1st equation, we'll then have;

[tex]C=\pi d[/tex]

We've been told that the diameter of the circle is 20inches, if we substitute this value into our equation, we'll have;

[tex]C=20\pi[/tex]

A pianist plans to play 4 pieces at a recital from her repertoire of 25 pieces, and is carefully consideringwhich song to play first, second, etc. to create a good flow. How many different recital programs arepossible?

Answers

Given 25 pieces of repertoire, if a pianist plans to play 4 pieces at a recital and is considering playing which song to play first, second, etc, the possible ways is,

[tex]^{25}P_4=\frac{25!}{(25-4)!}=\frac{25!}{21!}=303600\text{ possible recital programs}[/tex]

Hence, the different recital programs possible is 303600

x + y = 5 y - 2x = -4

Answers

Answer:

x = 3, y = 2

Explanations:

The equations are:

x + y = 5......................(1)

y - 2x = -4...................(2)

Make x the subject of the the formula

x = 5 - y...............(3)

Substitute equation (3) into equation (2)

y - 2(5 - y) = -4

y - 10 + 2y = -4

3y = -4 + 10

3y = 6

y = 6 / 3

y = 2

Substitute the value of y into equation (3)

x = 5 - 2

x = 3

If f (x)- VX-3, complete the following statement:x + 219) =

Answers

Given that;

[tex]f(x)=\frac{3}{x+2}-\sqrt{x-3}[/tex]

To get f(19), let's substitute 19 for x in the function f(x);

[tex]\begin{gathered} f(x)=\frac{3}{x+2}-\sqrt{x-3} \\ f(19)=\frac{3}{19+2}-\sqrt{19-3} \\ f(19)=\frac{3}{21}-\sqrt{16} \\ f(19)=\frac{1}{7}-4 \\ f(19)=-3\frac{6}{7} \end{gathered}[/tex]

Therefore, the value of f(19) is;

[tex]f(19)=-3\frac{6}{7}[/tex]

8. A boy owns 6 pairs of pants, 8 shirts, 2 ties, and 3 jackets. How many outfits can he wear to school if he must wear one of each item?

Answers

It is given that the boy owns 6 pairs of pants, 8 shirts, 2 ties, and 3 jackets.

It is also given that he must wear one of each item.

Recall the Fundamental Counting Principle:

The same is valid for any number of events following after each other.

Hence, the number of different outfits he can wear by the counting principle is:

[tex]6\times8\times2\times3[/tex]

Evaluate the product:

[tex]6\times8\times2\times3=288[/tex]

The number of different outfits he can wear is 288.

you own a pet store that sells fish tank you brought a fish tank for $35 and are going to mark it up 20% what is the selling price going to be on the fish tank

Answers

If you're marking the fish tank up by 20%, it means you're looking to sell it at 120% of its original value.

Now, let's use a rule of three to calculate such percentage:

Thereby,

[tex]x=\frac{120\cdot35}{100}\rightarrow x=42[/tex]

The selling price would be $42

Henry had a batting average of 0.341 last season (out of 1000 at-bats, he had 341 hits). Given that thisbatting average will stay the same this year, answer the following questions. What is the probability that his first hit will not occur until his 5th at-bat? Answers. 0.64. 0.083. 0.129. 0.166

Answers

The probability of success (a hit) is given by:

p = 0.341

The complement (a failure) of this probability is:

q = 1 - 0.341 = 0.659

Then, we can construct a probability distribution for the first hit until his nth at-bat:

[tex]P(x=n)=p\cdot q^{n-1}[/tex]

For his 5th at-bat, we have n = 5, then:

[tex]\begin{gathered} P(x=5)=0.341\cdot(0.659)^{5-1}=0.341\cdot0.659^4 \\ \\ \therefore P(x=5)=0.064 \end{gathered}[/tex]

URGENT!! ILL GIVE
BRAINLIEST!!!!! AND 100 POINTS!!!

Answers

70 -> between 8 and 9
5 -> between 2 and 3
81 -> exactly 9
-2/4 -> exactly -4
4/8 -> between 11 and 12

The following distribution represents the number of credit cards that customers of a bank have. Find the mean number of credit cards.Number of cards X01234Probability P(X)0.140.40.210.160.09

Answers

To solve this problem we have a formula at hand: the mean (m) number of credits cards is

[tex]m=\sum ^{}_XX\cdot P(X)[/tex]

Then,

[tex]m=0\cdot0.14+1\cdot0.4+2\cdot0.21+3\cdot0.16+4\cdot0.09=1.66[/tex]

For which pair of triangles would you use ASA to prove the congruence of the two triangles?

Answers

Solution:

Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent. According to this, the correct answer is:

C.

what is the effect on the graph of the function f(x) = x² when f(x) is changed to f(x + 8) ?A) shifted up B) shifted left C) shifted right D) shifted down

Answers

Solution

- In order to solve the question, we need to understand the rules guiding the translation of graphs. This rule is given below:

[tex]\begin{gathered} f(x)\to f(x+h) \\ \text{ If h is positive, then, the graph is shifted to the left} \\ \text{ If h is negative, then, the graph is shifted to the right} \end{gathered}[/tex]

- The question given to us has h = 8. This means that h is positive, therefore, the graph of f(x) must be shifted to the left by 8 units

Final Answer

The answer is "Shifted Left" (OPTION B)

I got the last question right that was similar so I’m unsure what I’m doing wrong for this one

Answers

[tex]6x+y=34[/tex]

Solve x:

[tex][/tex]

There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing. If you have a ticket, what is the expected payoff

Answers

Given that: There is a raffle with 250 tickets. One ticket will win a $320 prize, one ticket will win a $240 prize, one ticket will win a $180 prize, one ticket will win a $100 prize, and the remaining tickets will win nothing.

The expected payoff will be:

[tex]\begin{gathered} EV=\frac{1}{250}(320)+\frac{1}{250}(240)+\frac{1}{250}(180)+\frac{1}{250}(100)+\frac{246}{250}(0) \\ EV=\frac{320+240+180+100}{250} \\ EV=\frac{840}{250} \\ EV=3.36 \end{gathered}[/tex]

So the expected payoff will be $3.36.

12.Work backwards to write a quadratic equation that will have solutions of x = -1/2 and x = 4. (Your equation must only have integer coefficients, meaning no fractions or decimals.)

Answers

In general, a quadratic equation can be written in terms of its solutions:

[tex]y=(x-a)(x-b).[/tex]

Now, notice that:

[tex]x+\frac{1}{2}=0\text{ }[/tex]

when x= -1/2, and it is equivalent to:

[tex]2x+1=0.[/tex]

Therefore, you can write the quadratic equation as:

[tex]y=(2x+1)(x-4).[/tex]

Computing the above multiplication, you get:

[tex]y=2x^2-8x+x-4.[/tex]

Simplifying the above equation you get:

[tex]y=2x^2-7x-4.[/tex]Answer: [tex]y=2x^{2}-7x-4[/tex]

Jacob is constructing a pentagonal tent for his school carnival. The tent has a side length of 5.13 meters. What is the area of the tent? What is the perimeter of the tent? What is the sum of three of the interior angles in the tent once Jacob obtains the value of its area and perimeter?

Answers

The tent is pentagonal , this means it has 5 sides. The tent have a side length of 5.13 meters.

The area of the pentagon can be calculated below

[tex]\begin{gathered} \text{area of the tent=}\frac{perimeter\times apothem}{2} \\ \tan \text{ 36=}\frac{2.565}{a} \\ a=\frac{2.565}{\tan \text{ 36}} \\ a=\frac{2.565}{0.726542528} \\ a=3.53041962601 \\ \text{perimeter}=\text{ 5.13}\times5=25.65\text{ meters} \\ \text{area =}\frac{25.65\times3.53041962601}{2} \\ \text{area}=\frac{90.5445}{2} \\ \text{area}=45.27225 \\ \text{area}\approx45.27meter^2 \end{gathered}[/tex]

Each interior angle of a pentagon is

[tex]\begin{gathered} \text{ interior angle=}\frac{180\times3}{5}=\frac{540}{5}=108^{\circ} \\ \text{ Sum of thr}ee\text{ interior angles = 108}\times3=\text{ }324\text{ degre}e \end{gathered}[/tex]

80% of _ = 20?4-4-4-

Answers

Let

x -----> the missing number

we know that

80%=80/100=0.80

so

0.80x=20

solve the linear equation for x

Divide by 0.80 both sides

x=20/0.80

x=25

the answer is 25

Rewrite the fallowing as an exponential expression in simplest form.

Answers

SOLUTION

[tex]\begin{gathered} 5x\sqrt[]{x} \\ 5x\times\sqrt[]{x} \\ 5x^1\times x^{\frac{1}{2}} \\ 5x^{1+\frac{1}{2}} \\ 5x^{\frac{3}{2}} \\ \end{gathered}[/tex]

The answer is 57.3 provided by my teacher, I need help with the work

Answers

Apply the angles sum property in the triangle ABC,

[tex]62+90+\angle ACB=180\Rightarrow\angle ACB=180-152=28^{}[/tex]

Similarly, apply the angles sum property in triangle BCD,

[tex]20+90+\angle BCD=180\Rightarrow\angle BCD=180-110=70[/tex]

From triangle ABC,

[tex]BC=AC\sin 62=30\sin 62\approx26.5[/tex]

From triangle BDC,

[tex]BD=BC\cos 20=26.5\cos 20\approx24.9[/tex]

Now, consider that,

[tex]\angle BDE+\angle BDC=180\Rightarrow\angle BDE+90=180\Rightarrow\angle BDE=90[/tex]

So the triangle BDE is also a right triangle, and the trigonometric ratios are applicable.

Solve for 'x' as,

[tex]x=\tan ^{-1}(\frac{BD}{DE})=\tan ^{-1}(\frac{24.9}{16})=57.2764\approx57.3[/tex]

Thus, the value of the angle 'x' is 57.3 degrees approximately.ang

diameter = 10.5in.we are learning something about area of circle.

Answers

Use the formula for the area of a circle:

[tex]A=\pi\cdot r^2[/tex]

First, we need to find the radius r. Since the radius is half the diameter, then:

[tex]\begin{gathered} r=\frac{10.5\text{ in}}{2} \\ \therefore r=5.25in \end{gathered}[/tex]

Substitute the value for r in the formula for the area of the circle:

[tex]\begin{gathered} A=\pi\cdot(5.25in)^2 \\ \approx86.6in^2 \end{gathered}[/tex]

Therefore, the area of a circle of diameter 10.5 in is approximately 86.6 squared inches.

JUIVE Suppose that the amount in grams of a radioactive substance present at time t (in years) is given by A(t) = 800e 0.86t. Find the rate of change of the quantity present at the time when t = 5. 9.3 grams per year 0 -72.7 grams per year -9.3 grams per year 0 72.7 grams per year

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

A(t) = 800e^(-0.86t)

Step 02:

Rate of change

t1 = 0

A(t) = 800e^(-0.86t)

A(t) = 800e^(-0.86*0)

A(0) = 800

t2 = 5

A(t) = 800e^(-0.86t)

A(t) = 800e^(-0.86*5)

A (t) = 800e^(-4.3)

A(5) = 10.85

Step 03:

[tex]\frac{\Delta y}{\Delta x}=\frac{A(5)\text{ - A(0)}}{5-0}[/tex][tex]\frac{\Delta y}{\Delta x}=\frac{10.85-800}{5-0}=\frac{-789.15}{5}=-157.83[/tex]

See if anybody can answer this. A concession stand sells lemonade for $2 each and sports drinks for $3 each. The concession stand sells 54 cups of lemonade and sport drinks. The total money collected for these items is $204. How much money was collected on sports drinks?​

Answers

Let x = cups of lemonade
Let y = cups of sports drink

x + y = 54
2x + 3y = 204



$96 dollars were collected from selling sports drinks.

What is 175% of 48? Show work.

Answers

Let 175% of 48 be y.

This implies that

[tex]\frac{175}{100}\times48=y[/tex]

To evaluate y,

[tex]\begin{gathered} \frac{175}{100}\times48=y \\ \Rightarrow\frac{175\times48}{100}=y \\ \frac{8400}{100}=y \\ \Rightarrow y=84 \end{gathered}[/tex]

Hence, 175% of 48 is 84.

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