To solve for j'
4j + 2 = h
subtract 2 from both-side of the equation
4j + 2-2 = h -2
4j = h-2
divide both-side of the equation by 4
4j/4 = h-2/4
[tex]j=\frac{h-2}{4}[/tex]“Use the properties to rewrite this expression with the fewest terms possible:3+7(x - y) + 2x - 5y”
Expanding 7(x - y) in the above expression gives
[tex]-5y^{}+2x+7x-7y+3[/tex]adding the like terms (2x+ 7x) and (-5y-7y) gives
[tex](-5y-7y)+(2x+7x)+3[/tex][tex]\rightarrow\textcolor{#FF7968}{-12y+8x+3.}[/tex]The last expression is the simplest form we can convert our expression into.
Hello, I had a question on how to find the leading coefficient and the degree.
Given:
given polynomial is
[tex]23v^5-2v+4v^8-18v^4[/tex]Find:
we have to find the leading coefficient and degree of the polynomial.
Explanation:
The lewading coefficient is the coefficient of highest power term of the polynomial.
Highest power of v is 8 and its coefficient is 4.
Therfore, leading coefficient is 4.
and the degree of the polynomial is equal to the highest power of v in the polynomial, which is 8.
Therefore, the leading coefficient of polynomial is 4 and degree is 8.
Been looking for help for 2 hrs hopefully you can help
Given:
[tex]\begin{gathered} \mu=19.9 \\ \sigma=33.1 \\ n=40 \end{gathered}[/tex]To Determine:
[tex]P(X>8.9)[/tex]Solution
[tex]\begin{gathered} P(X>z) \\ z=\frac{x-\mu}{\sigma}=\frac{8.9-19.9}{33.1}=\frac{-11}{33.1}=-0.3323 \end{gathered}[/tex][tex]P(X>8.9)=1-P(X<8.9)=1-0.36982=0.63018[/tex]Hence, P(x>8.9) = 0.6302 (nearest 4 d. p)
Explain how to find the point equidistant from all three vertices in the given triangle. Choose the correct answer below. A. Find the intersection of the perpendicular bisectors of each side of the triangle B. Find the intersection of all of the midsegments of the triangle, C. Find the intersection of the angle bisectors of each angle of the triangle, D. Find the midpoint of the line segment that bisects Angle B.
ANSWER:
The correct option is the following:
C. Find the intersection of the angle bisectors of each angle of the triangle,
EXPLANATION:
The point that equidistant is the point at which the three bisectors of the internal angles of the triangle intersect, and it is the center of the circumference inscribed in the triangle and equidistant from its three sides.
IMPORTANT NOTE:
Any point on the bisector of an angle of a triangle equidistant from the sides that define that angle.
Amanda and Jamie are standing 25 feet apart and spot a bird in the sky between them. The angle of elevation from Amanda to the bird is 55, and from Jamie to the bird is 63. How far away is the bird from Amanda?
We have to find how far is the bird from Amanda.
With the information given, we can draw:
We can start by finding the third angle.
The sum of the angles have to be equal to 180°, so we can find it as:
[tex]\begin{gathered} \alpha+55\degree+63\degree=180\degree \\ \alpha=180-55-63 \\ \alpha=62\degree \end{gathered}[/tex]Now, we can apply the Law of Sines to find the distance between Amanda (A) and the bird (B):
[tex]\frac{AB}{\sin J}=\frac{AJ}{\sin B}[/tex]where AJ is the distance between Amanda and Jamie and AB is the distance between the bird and Amanda.
We then can solve for AB as:
[tex]\begin{gathered} AB=AJ\cdot\frac{\sin J}{\sin B} \\ AB=25\cdot\frac{\sin63\degree}{\sin62\degree} \\ AB\approx25\cdot\frac{0.891}{0.883} \\ AB\approx25.23 \end{gathered}[/tex]Answer: 25.23 [Option A]
Given that sin(0)= 10/ 13 and 0 is in Quadrant II, what is cos(20)? Give an exact answer in the form of a fraction. ,
SOLUTION
Given the image in the question tab, the following are the solution steps to the answer
Step 1: Write out the function
[tex]\begin{gathered} \sin \theta=\frac{10}{13} \\ \text{since }\sin \theta=\frac{opp}{hyp} \\ \therefore opp=10,\text{ hyp=13} \end{gathered}[/tex]Step 2: Solve for the adjacent using the pythagoras theorem
[tex]\begin{gathered} \text{hyp}^2=opp^2+adj^2 \\ 13^2=10^2+adj^2 \\ \text{adj}^2=13^2-10^2 \\ \text{adj}=\sqrt[]{169-100} \\ \text{adj}=\sqrt[]{69} \end{gathered}[/tex]Step 3: Calculate the value of cos2Ф
[tex]\begin{gathered} cos2\theta=\cos ^2\theta-\sin ^2\theta \\ \cos 2\theta=(\frac{\text{adj}}{\text{hyp}})^2-(\frac{opp}{hyp})^2 \\ \cos 2\theta=(\frac{\sqrt[]{69}}{13})^2-(\frac{10}{13})^2 \\ \cos 2\theta=\frac{69}{169}-\frac{100}{169} \\ \cos 2\theta=-\frac{31}{169} \end{gathered}[/tex]Hence, the value of cos2Ф is -31/169.
subtract (7u^2+10u+6) from (3u^2_5u+4).
Given:
[tex]\mleft(3u^2-5u+4\mright)-(7u^2+10u+6)[/tex]The objective is to subtract both the terms.
[tex]\begin{gathered} \mleft(3u^2-5u+4\mright)-(7u^2+10u+6) \\ 3u^2-5u+4-7u^2-10u-6 \\ -4u^2-15u-2 \end{gathered}[/tex]Hence the subtraction of the given term is,
[tex]-4u^2-15u-2[/tex]10. Find the area of ABC. (A) 84 (B) 168 (C) 170 (D) 48 (E) 56A: 10B: 17C: 21Right angle: 8
we know that
the area of triangle ABC is equal to the area of two right triangles
so
triangle ABD and triangle BDC
D is a point between point A and point C
step 1
Find the length of segment AD
Applying Pythagorean Theorem in the right triangle ABD
10^2=AD^2+8^2
100=AD^2+64
AD^2=100-64
AD^2=36
AD=6
Find teh area of triangle ABD
A=AD*BD/2
A=6*8/2
A=24 units^2
step 2
Find the area of triangle BDC
A=DC*DB/2
DC=21-6=15 units
A=15*8/2
A=60 units^2
step 3
Find teh area of triangle ABC
Adds the areas
A=24+60=84 units^2
therefore
the answer is the option A 84 units^2Surface area of a cone: S = πr² + πrl;solve for l.
Answer:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]Explanation:
The surface area of a cone is calculated using the formula:
[tex]S=πr^2+πrl[/tex]We want to solve for l.
First, subtract πr² from both sides of the equation:
[tex]\begin{gathered} S-\pi r^2=\pi r^2-\pi r^2+\pi rl \\ S-\pi r^2=\pi rl \end{gathered}[/tex]Next, divide both sides by πr:
[tex]\begin{gathered} \frac{S-\pi r^2}{\pi r}=\frac{\pi rl}{\pi r} \\ l=\frac{S-\pi r^{2}}{\pi r} \end{gathered}[/tex]The equation solved for l is:
[tex]l=\frac{S-\pi r^{2}}{\pi r}[/tex]A bug is moving along a straight path with velocity v(t)= t^2-6t+8 for t ≥0. Find the total distance traveled by the bug over interval [0,6].
Answer
Explanation
Given:
A bug is moving along a straight path with velocity
[tex]V(t)=t^2-6t+8\text{ }for\text{ }t>0[/tex]What to find:
The total distance traveled by the bug over interval [0, 6].
Solution:
To find the total distance traveled by the bug over interval [0, 6], you first integrate v(t)= t² - 6t + 8
[tex]\begin{gathered} \int_0^6t^2-6t+8 \\ \\ [\frac{t^3}{3}-\frac{6t^2}{2}+8t]^6_0 \\ \\ (\frac{t^3}{3}-3t^2+8t)^6-(\frac{t^{3}}{3}-3t^2+8t)^0 \\ \\ (\frac{6^3}{3}-3(6)^2+8(6))-(\frac{0^3}{3}-3(0)^2+8(0)) \\ \\ (\frac{216}{3}-3(36)+48)-(0-0+0) \\ \\ 72-108+48-0 \\ \\ =12\text{ }units \end{gathered}[/tex]13. Puppies have 28 teeth and most adult dogs have 42 teeth. Find the primefactorization of each number. Write the result using exponents. (Example 5)
To solve our question, first we need to know that a prime factorization is a way to represent a number by a sequence of prime numbers that multiplied together gives us the original number.
So let's calculate our first prime factorization:
As we can see, we divide our number by the smallest prime number and then the factor we follow the same rule until we get "1" (for all divisions we just have integers).
Now, for the second number we have:
And both prime factorizations are our final answers.
Find the measure of Zx in the figure.
The measure of Zx isº.
57°
X
90°
...
Please help me with this
y 4 7(x-6)
x-intercept:
y-intercept:
PLEASE ANSWER FAST.
Answer: y-4=7(x-6)
x-intercept(s): (38/7,0)
y-intercept(s): (0,−38)
I believe this is right hope this helps
Step-by-step explanation:
FIVE STAR®
The cost associated with a school dance is $300 for a venue rental and $24 for each couple
that attends. This can be represented by the expression 300 + 24x.
a. Define all the variables and terms is this scenario. That means tell us what x, 24x, and
300 represent
Answer:
300 -- venue cost24 -- cost for each couplex -- the number of couples24x the cost associated with all couple300+24x -- the total cost for the danceStep-by-step explanation:
Given the scenario that cost is $300 for the venue and $24 for each couple attending a dance at that venue, you want to know the meaning of the variables and terms in 300 +24x.
ComparisonYou can compare the terms, coefficients, and variables in the given expression with the parts of the problem statement.
300 is a constant term that corresponds to "$300 for a venue rental'24 is a coefficient that corresponds to "$24 for each couple"x is a variable representing the number of "couple that attends"24x is a term representing the cost associated with "$24 for each couple that attends"That is, the cost associated with the number of people attending is $24 times the number of couples: 24x. The expression 300+24x is the total of the fixed venue cost and the per-couple costs
The population of a country dropped from 52.5 million in 1995 to 44.2 million in 2007. Assume that P(t), the population, in millions, t years after 1995, is decreasing according to the exponential decay model.a) Find the value of k, and write the equation.b) Estimate the population of the country in 2018.c) After how many years will the population of the country be million, according to this model?
we have the exponential decay function
[tex]P(t)=52.5(e)^{-0.0143t}[/tex]Part b
Estimate the population of the country in 2018
Remember that
t=0 -----> year 1995
so
t=2018-1995=23 years
substitute in the function above
[tex]\begin{gathered} P(t)=52.5(e)^{-0.0143\cdot23} \\ P(t)=37.8\text{ million} \end{gathered}[/tex]Part c
After how many years will the population of the country be 2 million, according to this model?
For P(t)=2
substitute
[tex]2=52.5(e)^{-0.0143t}[/tex]Solve for t
[tex]\frac{2}{52.5}=(e)^{-0.0143t}[/tex]Apply ln on both sides
[tex]\begin{gathered} \ln (\frac{2}{52.5})=\ln (e)^{-0.0143t} \\ \\ \ln (\frac{2}{52.5})=(-0.0143t)\ln (e)^{} \end{gathered}[/tex][tex]\ln (\frac{2}{52.5})=(-0.0143t)[/tex]t=229 years
A movie aspect ratio of 2.15:1 is shown as a letterboxed image on a TV with a width of 62.72in and a height of 35.28in what is the % of image shown on the TV
You have that the movie aspect ratio is 2.15 : 1, that is, you have following relation between width and height:
2.15/1 = 2.15 = 215%
that is, the widht is 2.15 times the height, or the width is 215% longer than height.
In order to determine what is the percentage of the image shown, you calculate the percentage that widht is more longer than height. You have a TV of 62.72 width and 35.28 in height:
62.72/35.28 = 1.77 = 177%
that is, width of TV is 1.77 times longer than height, or width is 177% longer.
Hence, on TV will be not possible to watch the complete image. And the percentage shown is of 177%.
Harold Hill borrowed $16,400 to pay for his child's education at Riverside Community College. Harold must repay the loan at the end of 15 months in one payment with 3 3/4 % of interest.
A. How much interest must Harold pay? (Round answer to the nearest cent.)
B. What is the maturity value? (Round answer to the nearest cent.)
The interest that Harold pay is $768.75 and his maturity value is $17168.75.
Harold Hill borrowed $16,400
Harold must repay the loan at the end of 15 months in one payment with 3 3/4 % of interest
First we need to calculate the interest amount
= loan amount x rate of interest x number of months
interest = (16400 x 3 3/4 x 15/12)/100
interest = $768.75
The maturity value = loan amount + interest
= 16400 + 768.75
= 17168.75
Therefore, the interest that Harold pay is $768.75 and his maturity value is $17168.75.
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Which number line represents the solution to the inequality
–4x – 12 < 12 ?
PLEASE ANSWER FAST
Answer:
x ≥ -6
Option C
Step-by-step explanation:
Hello!
We can solve the inequality by isolating x. Remember, flip the sign when you divide or multiply both sides by a negative number in an inequality.
Solve for x-4x - 12 ≤ 12-4x - 12 + 12 ≤ 12 + 12-4x ≤ 24-4x / -4 ≥ 24 / -4 => Flip the sign!x ≥ -6The answer is option c, all values greater than -6.
Illustrate the ratio 7:3 using 'X' for 7 and 'y for 3
Given the ratio:
7:3
To illustrate the ratio above using x for 7 and y for 3, we have:
All you need to do is to replace 7 with x and replace 3 with y
7 : 3 ==> x : y
ANSWER:
x : y
I need problem C solved and for the work to be shown, Solve for the variable(s) in each triangle
Given:
Given that a right triangles.
Required:
To find the value of variables in each triangle.
Explanation:
In right triangles,
[tex]hup^2=opp^2+adj^2[/tex](C)
Here,
[tex]undefined[/tex]How would I write an equation in point- slope form with inequalities, slope-intercept form with inequalities and standard form with inequalities with these three sets of points(9,7) (8,5)(2,9) (2,7)(3,5) (5,4)
a. The point-slope equation is:
[tex]y-y_1=m(x-x_1)[/tex]Where m is the slope and (x1,y1) are the coordinates of one point in the line. Also, you need to write the equation with inequalities, then you need to replace the = sign, for a <, > or <=, >= sign.
Let's start by finding the slope of the first set of points (9,7) (8,5).
The formula for the slope is:
[tex]m=\frac{y_2-y_1}{x_2-x_1_{}}[/tex]By replacing the values you obtain:
[tex]m=\frac{5-7_{}}{8_{}-9}=\frac{-2}{-1}=2[/tex]The slope is 2.
Now, replace this value into the slope-form equation and the values of the first point (9,7):
[tex]y-7_{}>2(x-9)[/tex]I choose the sign > (greater than), but you can choose anyone, the difference will be for the solution of the inequality. When you solve the inequality you will find that the x-values have to be greater than the solution you found, or less than... etc, it will depend on the sign you have in the inequality.
b. The slope-intercept equation is:
[tex]y=mx+b[/tex]Where m is the slope and b the y-intercept.
Let's use the second set of points (2,9) and (2,7)
Start by calculating the slope:
[tex]m=\frac{7-9}{2-2}=\frac{-2}{0}=\text{ undefined}[/tex]As there's no difference in the x-coordinates, the line is a vertical line at x=2.
Also, there's no y-intercept as the line never crosses the y-axis.
I will use the first set again, so you can understand the slope-intercept form.
From part a) you know that the slope is 2, let's replace it in the equation and use the first pair of coordinates to find b:
[tex]\begin{gathered} 7=2\times9+b \\ 7=18+b \\ 7-18=b \\ b=-11 \end{gathered}[/tex]Thus, the slope-intercept with inequality will be:
[tex]y<2x-11[/tex]c. The standard form equation of a line is:
[tex]ax+by=c[/tex]Let's use the third set of points (3,5) (5,4).
Start by finding the slope:
[tex]m=\frac{4-5}{5-3}=\frac{-1}{2}=-0.5[/tex]Now, you can start with the point-slope form and then convert it into the standard form:
[tex]\begin{gathered} y-5\ge-0.5(x-3) \\ Apply\text{ the distributive property} \\ y-5\ge-0.5x+1.5 \\ y\ge-0.5x+1.5+5 \\ y\ge-0.5x+6.5 \\ 0.5x+y\ge6.5 \end{gathered}[/tex]Where a=0.5, b=1 and c=6.5
A plumber charges $14 for transportation and $30 per hour for repairs. Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
A plumber charges $14 for transportation and $30 per hour for repairs.
Complete the expression that can be used to find the cost in dollars for a repair that takes h hours.
An expression that can be used to find the cost in dollars for a repair that takes h hours is ____ + ____h.
_______________________________________________________________________
Charges
14 + 30* h
________________________________
Answer
An expression that can be used to find the cost in dollars for a repair that takes h hours is _14___ + _30___h.
____________________________________________
30 per hour, if it's two hours then 60 for example
Just do all 25 points If can show how it works it will be better thanks
a) Given:
The length of the side of a square is,
[tex]\frac{1}{5}cm[/tex]To find:
The area of the square.
Explanation:
Using the formula of the area of the square,
[tex]\begin{gathered} A=a^2 \\ A=(\frac{1}{5})^2 \\ A=\frac{1}{25}cm^2 \\ A=0.04cm^2 \end{gathered}[/tex]Final answer:
The area of the square is,
[tex]0.04cm^2[/tex]a rectangle with a area of s sq feet and a width of 6 in what is the length of the rectangle
The area of the reactangle is calculates using the following formula:
[tex]A=w\cdot l[/tex]Where
A: area
w: wisth
l: lenght
You can write this formula in terms of the length by dividing the Area by the width:
[tex]l=\frac{A}{w}[/tex]If the area is A=s feet² and the width is w=6 feet, then the length is
[tex]l=\frac{s}{6}[/tex]I need help to do these composition of functions. I have a photo if needed.h(a)=4a+1g(a)=2a-5Find (h×g)(-9)
The composition of two functions is defined as follows:
[tex](h\circ g)(x)=h(g(x))[/tex]Use the given rules of correspondence of h and g to find the composition of those two functions. Then, evaluate the composition at -9:
[tex]\begin{gathered} h(a)=4a+1 \\ \Rightarrow h(g(a))=4\cdot g(a)+1 \end{gathered}[/tex][tex]\begin{gathered} g(a)=2a-5 \\ \Rightarrow4\cdot g(a)+1=4\cdot(2a-5)+1 \\ =8a-20+1 \\ =8a-19 \end{gathered}[/tex]Then:
[tex]\begin{gathered} (h\circ g)(a)=h(g(a)) \\ =4\cdot g(a)+1 \\ =8a-19 \\ \\ \therefore(h\circ g)(a)=8a-19 \end{gathered}[/tex]Evaluate the composition of h and g at a=-9:
[tex]\begin{gathered} (h\circ g)(-9)=8(-9)-19 \\ =-72-19 \\ =-91 \end{gathered}[/tex]Therefore:
[tex](h\circ g)(-9)=-91[/tex]Algebra 2 The answer choices are: A. -3 less then or equal to x less then or equal to 6B. -4 less than x less then or greater to 1C. X greater than or equal to 1D. X greater to or equal to 6
Given:
A graph is given.
Required:
Find the interval of the domain that the graph of exponential function represents.
Explanation:
The graph of the exponential function is given as:
if the area of polygon A is 72 and Q is a scaled copy and the area of Q is 5 what scale factor got 72 to 5
A area= 72
Q area =5
So, if we multiply the A area by the square of the scale factor ( since they are areas) we obtain area Q:
72 x^2 = 5
Solving for x:
x^2 = 5/72
x = √(5/72)
x= 0.26
24. The base of a 13-foot ladder stands 5 feet from a house. Sketch a drawing to model this situation. How many feet up the side of the house does the ladder reach? Explain how drawing the picture helped you solve the problem.
The draw that describes this situation looks like this:
Drawing this helped us to know that the ladder forms a right triangle with one of the walls of the house.
When we have right triangles we can apply the Pythagoras theorem, from the Pythagoras theorem we can express:
[tex]13^2=5^2+h^2[/tex]Solving for h, we get:
[tex]\begin{gathered} 13^2-5^2=5^2-5^2+h^2 \\ 13^2-5^2=h^2 \\ h=\sqrt[]{13^2-5^2}=\sqrt[]{169-25}=\sqrt[]{144}=12 \end{gathered}[/tex]Then, the ladder reach 12 feet up the side of the house
Solve the following system of linear equations by graphing.{5x - 2y = 10 {x - y = -1 Graph the equations on the same set of axes.Note: Use different points on each line when plotting the graphs.The solution point is: (_, _)
Kindly Check below
1) The first thing we need to do in this question, is to pick the method we are going to use to solve this system. Let's use the Elimination Method.
2) So, let's solve this system analytically (algebraically):
[tex]\begin{gathered} 5x-2y=10 \\ x-y=-1\:\:(\times-2) \\ \\ 5x-2y=10 \\ -2x+2y=2 \\ ------- \\ 3x=12 \\ \\ \frac{3x}{3}=\frac{12}{3} \\ \\ x=4 \end{gathered}[/tex]Now, let's plug into the 2nd original equation x=4 and solve it for y:
[tex]\begin{gathered} x-y=-1 \\ \\ 4-y=-1 \\ \\ -y=-1-4 \\ \\ y=5 \end{gathered}[/tex]So we know the solution is (4,5).
3) Now, let's graph these equations by setting two t-tables. Let's rewrite those equations from the Standard form to the Slope-intercept form.
5x-2y=10 -2y=10-5x, y=-5+5/2x
x-y=-1,-y=-1-x, y=x+1
4) Now, let's plot those points and trace the lines through them
(-2,-10), (-1,-7.5), (0,-5), (1,-2.5), (2,0)
(-2,-1), (-1,0), (0,1), (1,2), (2,3)
2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 above 3, 4 above 4, 5 above 5, 5 above 6, 2 above 7, 2 above 8, 0 above 9, 0 above 10. Plot 2 is titled seventh grade. There are 2 dots above 0, 2 above 1, 3 above 2, 5 above 3, 5 above 4, 3 above 5, 3 above 6, 1 above 7, and 0 above 8, 9, and 10.
The dot plot shows the number of hours, to the nearest hour, that a sample of 5th graders and 7th graders spend watching television each week. What are the mean and median?
The 5th-grade mean is
.
The 7th-grade mean is
.
The 5th-grade median is
.
The 7th-grade median is
.
The mean and the median for each data-set are given as follows:
5-th grade students:
Mean: 4.67Median: 5 hours.7-th grade students:
Mean: 3.46 hours.Median: 4 hours.Dot plotA dot plot shows the number of times that each observation appears on a data-set.
Hence the hours of the 5th-graders are as follows:
1, 1, 2, 2, 2, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 6, 6, 7, 7, 8, 8
The mean is the sum of all the numbers of hours divided by the number of students, hence:
Mean = (2 x 1 + 3 x 2 + 1 x 3 + 4 x 4 + 5 x 5 + 5 x 6 + 2 x 7 + 2 x 8)/(2 + 3 + 1 + 4 + 5 + 5 + 2 + 2) = 4.67.
There are 24 elements in the data-set, hence the median is the mean of the 12th and the 13th element, as follows:
Median = (5 + 5)/2 = 5.
Hence the hours of the 7th-graders are as follows:
0,0, 1, 1, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 7.
Hence the mean is:
Mean = (2 x 0 + 2 x 1 + 3 x 2 + 5 x 3 + 5 x 4 + 3 x 5 + 3 x 6 + 1 x 7)/24 = 3.46.
The 12th element is of 3, the 13th of 5, hence the median is:
Median = (3 + 5)/2 = 4.
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