In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
(4xy³y⁴)(5x²y)
Step 02:
[tex](4xy^3y^4)(5x^2y)=(4xy^7)(5x^2y)=20x^3y^8^{}[/tex]This is the solution.
[tex]20x^3y^8^{}[/tex]You must show your work as you... determine whether QR and ST are parallel, perpendicular, or neither. Q(9, 10), R(-5, 2), S(-8, -2), T(-1, 2) Parallel Perpendicular Neither
WILL MARK BRAINLIEST
PLS HELP ASAP
Slope of QR = 4/7; Slope of ST = 4/7, therefore, the lines are parallel to each other.
How to Determine if Two Lines are Parallel or Perpendicular?To determine if two given lines are perpendicular to each other or parallel to each other, find their slopes.
Slope, m = change in y / change in x.
If they have the same slope, m, then they are parallel lines. If they have slopes that are negative reciprocal to each other, then they are perpendicular lines.
Given:
Q(9, 10)
R(-5, 2)
S(-8, -2)
T(-1, 2)
Find the slope of QR and ST:
Slope of QR = (10 - 2)/(9 -(-5)) = 8/14 = 4/7
Slope of ST = (-2 - 2)/(-8 -(-1)) = -4/-7 = 4/7
The slope are the same, therefore they are parallel to each other.
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The rat population in major metropolitan city is given by the formula n(t)=40e^0.015t where t is measured in years since 1991 and n(t) is measured in millions. What does the model predict the rat population was in the year 2008?
To use the model we need to find the value of t. To do this we substract the year we want to know from the year the model began, then:
[tex]t=2008-1991=17[/tex]Now that we have t we plug it in the function:
[tex]n(17)=40e^{0.015\cdot17}=51.618[/tex]Therefore the model predict that there were 51.618 millions of rats in 2008.
how many liters of 10% salt water do you need to add to 5 liters of 25% salt to make 15% salt?
Answer:
You will need 10 liters of 10% salt water
Step-by-step explanation:
Lawn20 meters-WalkwayGazeboRHQ15 metersA bag of grass seed costs $64.26. If agardener wants to calculate the costofgrass seed required to plant the lawn,what additional information wouldhe need to know?A the location of the walkwayBthe perimeter of the lawnс the weight of one bag of grass seedD the area that can be covered byone bag of seed
He needs option D. Because the perimeter is not the total area (it is only the distance in meters/centimeters that surround the lawn, we need to know how much area a bag of grass seeds covers, for us to know how many to buy. Also, we need the area of the walkway, since it is not covered by grass
The area of a triangle is:
[tex]Area\text{ = }\frac{b(h)}{2}[/tex]But, since there is a walkway that isn't covered in grass, we need to subtract the circle area from the triangle area
Area of circle:
[tex]Area\text{ = }\pi r^2[/tex]Then the total area of the lawn :
[tex]Area\text{ Lawn = }\frac{b(h)}{2}\text{ - \lparen}\pi r^2)[/tex]Your friend Pat bought a fish tank that has a volume of 175 liters. The brochure for Pat's tank lists a "fun fact that it would take 7.43 x 1018 tanks of that sizeto fill all the oceans in the world. Pat thinks the both of you can quickly calculate the volume of all the oceans in the world using the fun fact and the size ofher tankPart a.) Given that 1 liter = 1.0 x 10-12 cubic kilometers, rewrite the size of the tank in cubic kilometers using scientific notation.b) Determine the volume of all the oceans in the world in cubic kilometers using the "fun fact"
The tank has a volume of 175 liters
Fun fact: it would take 7.43*10¹⁸ tanks that size to fill all the oceans in the world.
a) Using the convertion 1 liter = 1.0*10⁻¹²km³ you have to rewrite the size of the tank.
For this you have to use cross multiplication:
1 Lts = 1.0*10⁻¹²
175Lts=x
[tex]x=175\cdot1.0\cdot10^{-12}=1.75\cdot10^{-10}[/tex]The volume of the tank is equal to 1.75*10⁻¹⁰ km³
b)
You know that one tank has a volume of 1.75*10⁻¹⁰ km³
To know what volume would 7.43*10¹⁸ tanks of the same size have, multiply the volume of one tank by the number of tanks.
[tex]1.75\cdot10^{-10}\cdot7.43\cdot10^{18}=1300250000\operatorname{km}^3[/tex]Using the fun fact, the determined volume of all oceans in the world is 1300250000km³
Find all solutions in[0, 2pi): 2sin(x) – sin (2x) = 0
Based on the answer choices, replace the pair of given values and verify the equation, as follow:
For x = π/4, π/6
[tex]2\sin (\frac{\pi}{4})-\sin (\frac{2\pi}{4})=2\frac{\sqrt[]{2}}{2}-1\ne0[/tex]the previous result means that the given values of x are not solution. The answer must be equal to zero.
Next, for x = 0, π
[tex]\begin{gathered} 2\sin (\pi)-\sin (2\pi)=0-0=0 \\ 2\sin (0)-\sin (0)=0-0=0 \end{gathered}[/tex]For both values of x the question is verified.
The rest of the options include π/4 and π/3 as argument, you have already shown that these values of x are not solution.
Hence, the solutions for the given equation are x = 0 and π
Directions: Identify the slope and y-intercept of the line on the graph. Then, write the equation of the line in slope-intercept form.
To find out the slope, we need two points
so
looking at the graph
we take
(-4,5) and (0,-3)
m=(-3-5)/(0+4)
m=-8/4
m=-2the y-intercept (value of y when the value of x is zero) is the point (0,-3)
the equation of the line in slope-intercept form is
y=mx+b
where
m is the slope
b is the y-coordinate of the y-intercept
so
m=-2
b=-3
substitute
y=-2x-321.) Determine the distance between the points (-2, 3) and (4,9).A 142B 7146C 413D 6V222.) Infigure
The distance formula can be represented below
[tex]\begin{gathered} c^{}=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \\ \end{gathered}[/tex]Therefore,
[tex]\begin{gathered} c=\sqrt[]{(4+2)^2+(9-3)^2} \\ c=\sqrt[]{(6)^2+(6)^2} \\ c=\sqrt[]{36+36} \\ c=\sqrt[]{72} \\ c=\sqrt[]{36\times2} \\ c=6\sqrt[]{2} \end{gathered}[/tex]The answer is D.
Copper has a density of 4.44 g/cm3. What is the volume of 2.78 g of copper?
60 points please help
The volume of 2.78 g of copper is 0.626 [tex]cm^{3}[/tex].
According to the question,
We have the following information:
Density of cooper = 4.44 [tex]g/cm^{3}[/tex]
Mass of copper = 2.78 g
We know that the following formula is used to find the density of any material:
Density = Mass/volume
Let's denote the volume of copper be V.
Now, putting the values of mass and density here:
4.44 = 2.78/V
V = 2.78/4.44
V = 0.626 [tex]cm^{3}[/tex]
(Note that the units if mass, volume and density are written with the numbers. For example, in this case, the unit of mass is grams, the unit of volume is [tex]cm^{3}[/tex].)
Hence, the volume of the copper is 0.626 [tex]cm^{3}[/tex].
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Jina spends $16 each time she travels the toll roads. She started the month with $240 in her toll road account. The amount, A (in dollars), that she has left in the account after t trips on the toll roads is given by the following function.=A(t)=240-16tAnswer the following questions.(a)How much money does Jina have left in the account after 11 trips on the toll roads?$(b)How many trips on the toll roads can she take until her account is empty?trips
GIVEN:
We are told that Jina had an opening balance of $240 in her toll road account.
Also, we are told that the amount left in the toll road account is given by the function;
[tex]A(t)=240-16t[/tex]Required;
(a) To find how much money she has left in her acount after 11 trips.
(b) To find out how many trips she can take until her account is empty.
Step-by-step solution;
We first take note of the variable t, which represent the number of trips taken. Also, the function shows how many trips multiplied by 16 would be subtracted from the opening balance. The result would be how much amount (variable A) would be left in her account.
Therefore;
(a) After 11 trips, Jina would have;
[tex]\begin{gathered} A(t)=240-16t \\ \\ A(11)=240-16(11) \\ \\ A(11)=240-176 \\ A(11)=64 \\ \end{gathered}[/tex]For the (A) part, the answer is $64.
(b) For her account to be empty, then the function given would be equal to zero. That is, after an unknown number of trips, the balance would be zero. We can now re-write the function as follows;
[tex]\begin{gathered} A(t)=240-16t \\ \\ 0=240-16t \end{gathered}[/tex]Add 16t to both sides of the equation;
[tex]\begin{gathered} 16t=240-16t+16t \\ \\ 16t=240 \\ \\ Divide\text{ }both\text{ }sides\text{ }by\text{ }16: \\ \\ \frac{16t}{16}=\frac{240}{16} \\ \\ t=15 \end{gathered}[/tex]This means after 15 trips she would have emptied her toll road account.
ANSWER:
[tex]\begin{gathered} (A)=\text{\$64} \\ \\ (B)=15\text{ }trips \end{gathered}[/tex]I need help please quickly I need help
10(2 + 3) - 8 · 3.
20+50-8 times 3
70 -24
46 is answer
Answer:
10(5)-24 ----) 50-24 -----) 26
Step-by-step explanation:
answe is 26
Fart A Now that you have converted a terminating decimal number Into a fractlon, try converting a repeating decimal number Into a fraction. Repeating decimal numbers are more difficult to convert Into fractions. The first step is to assign the given decimal number to be equal to a varlable, x. For the decimal number 0.3, that means X = 0.3. if x = 0.3, what does 10x equal? Font Sizes
Given x = 0.3, we're asked to find 10x. All we need to do is multiply 10 by 0.3(which is the value of x);
[tex]10\text{ }\ast\text{ 0.3 = 3}[/tex]Therefore, 10x is equal to 3.
Question 9 of 30 Find the surface area of the polyhedron below. The area of each base is 65 cm2 7 cm 2 cm 12 cm 2 cm 2cm 3 cm 4 cm
The approach is to find the area of the individual sides and add all up
Besides the base, we can identify about 6 rectangles.
area of a rectangle, A = base x height
[tex]\begin{gathered} \text{All the rectangles have a height of 12cm as se}en\text{ in the diagram,} \\ \text{Therefore area is area of 2 bases + area of rectangles.} \end{gathered}[/tex][tex]\begin{gathered} =2(65)\text{ + (4}\times12\text{)+(3}\times12\text{) +(2}\times12\text{)+(2}\times12\text{)+(2}\times12\text{)+(7}\times12\text{)} \\ =130+\text{ 48 + }36\text{ + 24 + 24 + 24 + 84} \\ =370\text{ sq cm} \end{gathered}[/tex]What is the simplified form of the expression square root of -64
What is the simplified form of the expression square root of -64
we have
[tex]\sqrt[]{-64}[/tex]Remember that
64=2^6
and
i^2=-1
substitute
[tex]\sqrt[]{-64}=\sqrt[]{(-1)(2^6)}=\sqrt[]{i^2\cdot2^6}=2^3i=8i[/tex]option B1. The figure shows the regular triangular pyramid SABC. The base of the pyramid has an edge AB = 6 cm and the side wall has an apothem SM = √15 cm. Calculate the pyramid: 1) the base elevation AM; 2) the elevation SO; 3) the area of the base; 4) the area of the side surface; 5) the total surface area; 6) volume.
Given:
• AB = 6 cm
,• SM = √15 cm
Let's solve for the following:
• 1) the base elevation AM.
Given that we have a regular triangular pyramid, the length of the three bases are equal.
AB = BC = AC
BM = BC/2 = 6/2 = 3 cm
To solve for AM, which is the height of the base, apply Pythagorean Theorem:
[tex]\begin{gathered} AM=\sqrt{AB^2-BM^2} \\ \\ AM=\sqrt{6^2-3^2} \\ \\ AM=\sqrt{36-9} \\ \\ AM=\sqrt{27} \\ \\ AM=5.2\text{ cm} \end{gathered}[/tex]The base elevation of the pyramid is 5.2 cm.
• (2)., The elevation SO.
To find the elevation of the pyramid, apply Pythagorean Theorem:
[tex]SO=\sqrt{SM^2-MO^2}[/tex]Where:
SM = √15 cm
MO = AM/2 = 5.2/2 = 2.6 cm
Thus, we have:
[tex]\begin{gathered} SO=\sqrt{(\sqrt{15})^2-2.6^2} \\ \\ SO=\sqrt{15-6.76} \\ \\ SO=2.9\text{ cm} \end{gathered}[/tex]Length of SO = 2.9 cm
• (3). Area of the base:
To find the area of the triangular base, apply the formula:
[tex]A=\frac{1}{2}*BC*AM[/tex]Thus, we have:
[tex]\begin{gathered} A=\frac{1}{2}*6^*5.2 \\ \\ A=15.6\text{ cm}^2 \end{gathered}[/tex]The area of the base is 15.6 square cm.
• (4). Area of the side surface.
Apply the formula:
[tex]SA=\frac{1}{2}*p*h[/tex]Where:
p is the perimeter
h is the slant height, SM = √15 cm
Thus, we have:
[tex]\begin{gathered} A=\frac{1}{2}*(6*3)*\sqrt{15} \\ \\ A=34.86\text{ cm}^2 \end{gathered}[/tex]• (5). Total surface area:
To find the total surface area, apply the formula:
[tex]TSA=base\text{ area + area of side surface}[/tex]Where:
Area of base = 15.6 cm²
Area of side surface = 34.86 cm²
TSA = 15.6 + 34.86 = 50.46 cm²
The total surface area is 50.46 cm²
• (6). Volume:
To find the volume, apply the formula:
[tex]V=\frac{1}{3}*area\text{ of base *height}[/tex]Where:
Area of base = 15.6 cm²
Height, SO = 2.9 cm
Thus, we have:
[tex]\begin{gathered} V=\frac{1}{3}*15.6*2.9 \\ \\ V=15.08\text{ cm}^3 \end{gathered}[/tex]The volume is 15.08 cm³.
ANSWER:
• 1.) 5.2 cm
,• 2.) 2.9 cm
,• 3.) 15.6 cm²
,• 4.) 34.86 cm²
,• (5). 50.46 cm²
,• 6). 15.08 cm³.
Find all X values where the tangent line to the graph of the function…
Consider the function,
[tex]f(x)=6\sin x+\frac{9}{8}[/tex]The first derivative gives the slope (m) of the tangent of the curve,
[tex]\begin{gathered} m=f^{\prime}(x) \\ m=\frac{d}{dx}(6\sin x+\frac{9}{8}) \\ m=6\cos x+0 \\ m=6\cos x \end{gathered}[/tex]The equation of the line is given as,
[tex]y-3\sqrt[]{3}x=\frac{7}{3}[/tex]This can be written as,
[tex]y=3\sqrt[]{3}x+\frac{7}{3}[/tex]Comparing with the slope-intercept form of the equation of a line, it can be concluded that the given line has a slope,
[tex]m^{\prime}=3\sqrt[]{3}[/tex]Given that the tangent to the curve is parallel to this line, so their slopes must also be equal,
[tex]\begin{gathered} m=m^{\prime} \\ 6\cos x=3\sqrt[]{3} \\ \cos x=\frac{\sqrt[]{3}}{2} \\ \cos x=\cos (\frac{\pi}{6}) \end{gathered}[/tex]Consider the formula,
[tex]\cos A=\cos B\Rightarrow A=2k\pi\pm B[/tex]Applying the formula,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Thus, the required values of 'x' are,
[tex]x=2k\pi\pm\frac{\pi}{6}[/tex]Therefore, options 1st and 2nd are the correct choices.
If each machine produces nails at the same rate, how many nails can 1 machine produce in 1 hour
Divide the number of nails by the number of minutes:
16 1/5 ÷ 15 = 1 2/25 per minute
48 3/5 ÷ 45 = 1 2/25 per min
59 2/5 ÷ 55 = 1 2/25 per min
We have the number of nails produced per minute, to calculate the number of nails in an hour multiply it by 60, because 60 minutes= 1 hour:
1 2/25 x 60 = 64 4/5
Determine an algebraic model of a function that satisfies the following key features.
Solution:
Given the conditions;
[tex]As\text{ }x\rightarrow-\infty,y\rightarrow\infty\text{ and }x\rightarrow\infty,y\rightarrow\infty[/tex]When;
[tex]x\rightarrow-\infty,y\rightarrow\infty[/tex]Then, the degree of the polynomial is even.
Then, given three x-intercepts, it means one of the root could have been repeated.
Thus, the model function is;
[tex]f\lparen x)=\left(x+1\right)\left(x-3\right)\left(x^2\right)[/tex]The volume of the rectangular prism is 105 cubic yards. What is the surface area of the prism in square feet?
Answer:
198.18 is the answer
Step-by-step explanation:
the answer is 198.18
hope it helps
A net of arectangular pyramidis shown. Therectangular base haslength 24 cm andwidth 21 cm. Thenet of the pyramidhas length 69.2 cmand width 64.6 cm.Find the surfacearea of the pyramid.
Solution
The Image will be of help
To find x
[tex]\begin{gathered} x+24+x=69.2 \\ 2x+24=69.2 \\ 2x=69.2-24 \\ 2x=45.2 \\ x=\frac{45.2}{2} \\ x=22.6 \end{gathered}[/tex]To find y
[tex]\begin{gathered} y+21+y=64.6 \\ 2y+21=64.6 \\ 2y=64.6-21 \\ 2y=43.6 \\ y=\frac{43.6}{2} \\ y=21.8 \end{gathered}[/tex]The diagram below will help us to find the Surface Area of the Pyramid
The surface area is
[tex]SurfaceArea=A_1+2A_2+2A_3[/tex]To find A1
[tex]A_1=24\times21=504[/tex]To find A2
[tex]\begin{gathered} A_2=\frac{1}{2}b\times h \\ 2A_2=b\times h \\ 2A_2=21\times22.6 \\ 2A_2=474.6 \end{gathered}[/tex]To find A3
[tex]\begin{gathered} A_3=\frac{1}{2}bh \\ 2A_3=b\times h \\ 2A_3=24\times21.8 \\ 2A_3=523.2 \end{gathered}[/tex]The surface Area
[tex]\begin{gathered} SurfaceArea=A_1+2A_2+2A_3 \\ SurfaceArea=504+474.6+523.2 \\ SurfaceArea=1501.8cm^2 \end{gathered}[/tex]Thus,
[tex]SurfaceArea=1501.8cm^2[/tex]The width of a rectangle measures (4.3q - 3.1) centimeters, and its length
measures (9.6q-3.6) centimeters. Which expression represents the perimeter, in
centimeters, of the rectangle?
The expression that represents the perimeter and the of the rectangle is: 14.6q - 13.4.
What is the Perimeter of a Rectangle?A rectangle's perimeter if the length of its surrounding borders. Thus, the perimeter of a rectangle is the sum of all the length of the sides of the rectangle which can be calculated using the formula below:
Perimeter of a rectangle = 2(length + width).
Given the following:
Width of the rectangle = (4.3q - 3.1) centimetersLength of the rectangle = (9.6q - 3.6) centimetersTherefore, substitute the expression for the width and length of the rectangle into the perimeter of the rectangle formula:
Perimeter of rectangle = 2(9.6q - 3.6 + 4.3q - 3.1)
Combine like terms
Perimeter of rectangle = 2(7.3q - 6.7)
Perimeter of rectangle = 14.6q - 13.4
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Hello, can you help me with a Standard deviation question, please?
To now how many had a score under 66, we have to calculate the following probability
[tex]P(X<66)=P(Z<\frac{66-81}{5})=P(Z<-3)=0.0013[/tex]So the amount of people that had a score under 66 is
[tex]4502\cdot0.0013=5.86\approx6[/tex]So 6 people get a score under 66
Line k contains the points (-9,4) and (9,-8) in the xy-coordinate plane. What are the two other points that lie on line k?
Answer
D. (-3, 0) and (3, -4)
Explanation
Let the coordinate of the points be A(-9, 4) and B(9, -8).
We shall look for the gradient m of line using
m = (y₂ - y₁)/(x₂ - x₁)
Substitute for x₁ = -9, y₁ = 4, x₂ = 9 and y₂ = -8
m = (-8 - 4)/(9 - -9) = -12/18 = -2/3
From option A - D given, only C and D would have the same gradient of -2/3 as line AB
To know the correct option, we shall look for the equation of the line AB, that is,
(y - y₁)/(x - x₁) = (y₂ - y₁)/(x₂ - x₁)
(y - 4)/(x - -9) = (-8 - 4)/(9 - -9)
(y -4)/(x + 9) = -12/18
(y - 4)/(x + 9) = -2/3 -----------*
Between option C and D, only D satisfies the equation *
That is, using (-3, 0), we have (0 - 4)/(-3 + 9) = -4/6 = -2/3
Also, using (3, -4), we have (-4 - 4)/(3 + 9) = -8/12 = -2/3
Select the correct answerVector u has its initial point at (15, 22) and its terminal point at (5, 4). Vector v points in a direction opposite that of u, and its magnitude is twicethe magnitude of u. What is the component form of v?OA V=(-20, 36)OB. V=(-20, 52)Ocv = (20, 36)ODV= (20, 52)
Answer
Option C is correct.
v = (20, 36)
Explanation
If the initial and terminal points of a vector are given, the vector itself is obtained, per coordinate, by doing a terminal point coordinate minus initial point coordinate.
u = [(5 - 15), (4 - 22)]
u = (-10, -18)
Then, we are told that vector v points in the opposite direction as that of vector u and its magnitude is twice that of vector u too.
In mathematical terms,
v = -2u
v = -2 (-10, -18)
v = (20, 36)
Hope this Helps!!!
Determine whether each expression can be used to find the length of side RS.
ANSWER:
[tex]\begin{gathered} \sin (R)\rightarrow\text{ Yes} \\ \tan (T)\rightarrow\text{ No} \\ \cos (R)\rightarrow\text{ No} \\ tan(R)\rightarrow\text{ No} \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
Since we know a side and the hypotenuse, we can rule out tangent and cotangent, since these are related to the two legs.
Therefore, if we want to know that side we must apply sine or cosine, just like this:
[tex]\begin{gathered} \sin \theta=\frac{\text{opposite }}{\text{ hypotenuse}} \\ \text{therefore, in this case:} \\ \sin R=\frac{21}{35} \\ \cos \theta=\frac{\text{adjacent}}{\text{ hypotenuse}} \\ \cos R=\frac{\text{unknown}}{35} \end{gathered}[/tex]Therefore, the way to calculate the value of the missing side is by means of the sine of the angle R
Plot the vertex of f(x) = (x − 2)2 + 2.
Take into account that the general function of a parabola in vertex form is given by:
[tex]f(x)=a(x-h)^2+k[/tex]where (h,k) is the vertex of the parabola.
By comparing the previous general function with the given function:
[tex]f(x)=(x-2)^2+2[/tex]you can notice that:
h = 2
k = 2
Hence, you can conclude that the vertex of the given function is (2,2)
4 5 3 7 89 65Each time, you pick one card randomly and then put it back.What is the probability that the number on the card you pickfirst time is odd and the number on the second card you take isa multiple of 2? Keep your answers in simplified improperfraction form.Enter the answer
We have a total of 8 cards, where 3 of them are a multiple of 2, and 5 is an odd number. Consider that event A represents the probability of picking an odd number and event B is picking a multiple of 2. We know that the events are independent (because we put the cards back), therefore the probability of A and B can be expressed as
[tex]P(A\text{ and }B)=P(A)\cdot P(B)[/tex]Where
[tex]\begin{gathered} P(A)=\frac{5}{8} \\ \\ P(B)=\frac{3}{8} \end{gathered}[/tex]Therefore
[tex]P(A\text{ and }B)=\frac{5}{8}\cdot\frac{3}{8}=\frac{15}{64}[/tex]The final answer is
[tex]P(A\text{ and }B)=\frac{15}{64}[/tex]Give two examples when you would need to know the perimeter and two examples of when you would need to know the area.
Perimeter is the distance around a figure. The instances where we need to find perimeter include
1) The total length of the boundary of a marked field. This would involve adding the distance around it. Both the curved and straight paths
2) The length of barbed wire to be placed on a fence would require us to find the distance round the fence
The area of a shape is the space enclosed within the perimeter of the shape. The instances where we need to find area include
1) The area of a wall is calculated to determine how much paint is needed to paint it. The paint is used per square unit.
2) The area of a field is calculated to determine the cost of mowing it since the cost is calculated per unit square
n=39; i = 0.039; PMT = $196; PV =?
Given the Present Value (PV) formula
[tex]PV=PMT\times\frac{1-(\frac{1}{(1+i)^n})}{i}[/tex]Write out the parameters
[tex]\begin{gathered} PV=\text{?} \\ n=39 \\ i=0.039 \\ \text{PMT=\$196} \end{gathered}[/tex]Substitute the following values in the present value formula to find the PV
[tex]PV=196\times\frac{1-(\frac{1}{(1+0.039)^{39}})}{0.039}[/tex][tex]PV=196\times\frac{1-0.2249021697}{0.039}[/tex][tex]PV=196\times\frac{0.7750978303}{0.039}[/tex][tex]\begin{gathered} PV=196\times19.87430334 \\ PV\approx3895.36 \end{gathered}[/tex]Hence, the Present Value (PV) is approximately $3895.36
Which function has a y-intercept of 4? a. f(x) = 3(1 + 0.05)* b.f(x) = 4(0.95)* c. f(x) = 5(1.1) d. f(x) = 5(0.8)
Answer:
The correct option is D
f(x) = 5(0.8)
has y-intercept of 4
Explanation:
To know which of the given functions has a y-intercept of 4, we test them one after the other.
a. f(x) = 3(1 + 0.05)
f(x) = 3.15 WRONG
b. f(x) = 4(0.95)
f(x) = 3.8 WRONG
c. f(x) = 5(1.1)
f(x) = 5.5 WRONG
d. f(x) = 5(0.8)
f(x) = 4 CORRECT
