Answer:
★ For example, a useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. In Addition, the main notion to convey here is that forces can act at a distance with no perceivable substance in between.
Explanation:
Hope you have a great day :)
No, objects have no need to touch for interaction.
Forces that interact with objects without touchingWe know that there are some forces which interact with the objects from far distance without touching such as gravity of the earth. The Earth's gravitational force is that the Earth can pull on objects without touching them so we can conclude that objects have no need to touch for interaction with one another.
Learn more about interaction here: https://brainly.com/question/24353040
Kepler's first law of planetary motion states that ________.
a. the Sun is at the center of the solar system
b. planets orbit the Sun in elliptical orbits, with the Sun located at one focus
c. planets orbit the Sun in circular orbits, with the Sun located at the center
d. gravity provides the force that holds the planets in orbit about the Sun
Answer:
Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)
Explanation:
Kepler's laws or laws of planetary motion are scientific laws that describe the movement of the planets around the Sun. The fundamental contribution of Kepler's laws was to show that the orbits of the planets are elliptical and not circular as was previously believed.
Kepler's laws are kinetic laws. This means that its function is to describe the planetary motion.
Kepler formulated three laws:
First Law: The planets move around the Sun describing elliptical orbits, the Sun being located in one of the focus. Second Law: The vector radius that joins the planet and the Sun sweeps equal areas in equal times. Third Law: For any planet, the square of its orbital period (time it takes to go around the Sun) is directly proportional to the cube of the mean distance from the Sun.An ellipse is a closed curve that has two symmetrical axes, called foci or fixed points. In simpler words, an ellipse can be described as a flattened circle.
The degree of flattening of a closed curve is called eccentricity. When the eccentricity is equal to 0, the curve forms a perfect circle. On the other hand, when the eccentricity is greater than 0, the sides of the curve are flattened to form an ellipse.
Kepler's first law of planetary motion states that planets orbit the Sun in elliptical orbits, with the Sun located at one focus (option b)
3. An object whose mass is 60 kg is hanging on a thin wire. The object has a
potential energy of 15000 J. How high is the object above the ground?
GPE:
M:
G:
H=
What is the Momentum of a ball that has a mass of 0.5 kg and a velocity of 20 m/s?
Suppose each object emitted a burst of light right now.Rank the objects from left to right based on the amount of time itwould take this light to reach Earth, from longest time to shortesttime:_____.
-Star on the far side of the Andromeda Galaxy
-Star on the near side of Andromeda Galaxy
-Star on far side of Milky Way Galaxy
-Star near center of the Milky Way Galaxy
-Orion Nebulla
-Alpha Centauri
-Pluto
-Sun
Answer:
the order of arrival is from highest to lowest
star other side of Andromeda> star near side of andromeda> other side of milky way > center of the milky way> nevulosa orion> Pluto> Sum
Explanation:
The light that comes from stars and galaxies travels in a vacuum so its speed is constant and with a value of c = 3 108 m / s, so time will be directly proportional to the distance to the object
x = c t
the order of arrival is from highest to lowest
star other side of Andromeda> star near side of andromeda> other side of milky way > center of the milky way> nevulosa orion> Pluto> Sum
Agnes makes a round trip at a constant speed to a star that is 16 light-years distant from Earth, while twin brother Bert remains on Earth. When Agnes returns to Earth, she reports that she has celebrated 20 birthdays during her journey. (a) What was her speed during her journey
Answer:
Speed of Agnes during her journey was 0.848c
Explanation:
Given that;
Age of Agnes t₀ = 20 years
distance d = 2 × distance of star from Earth = 2 × 16 light-years
= 32 light-years
so get her speed speed; we use the following expression
Yvt₀ = d
( v / √(1 - ([tex]\frac{v}{c}[/tex])²) )² = ( 32 light-years / 20 yrs )²
v² / (1 - ( v²/c²)) = ( 32 × c / 20 )²
v² / (1 - ( v²/c²)) = 2.56 × c²
v² / c²-v²/c² = 2.56 × c²
v²c² / c² - v² = 2.56 × c²
v² / c² - v² = 2.56
v² = 2.56 (c² - v²)
v² = 2.56 (c² - v²)
v² = 2.56c² - 2.56v²
v² + 2.56v² = 2.56c²
3.56v² = 2.56c²
v² = (2.56/3.56)c²
v = √((2.56/3.56)c²)
so v = 0.848c
Therefore, Speed of Agnes during her journey was 0.848c
Part-1: Mean Kid pushes Nice Kid off a dock into the water. Mean does this by pushing Nice horizontally. But, karma has finally caught up with Mean and at the same instant that Mean pushes Nice horizontally, the dock also collapses and Mean immediately begins to fall towards the water as well. (Karma isn't finished with Mean though, because only Nice knows how to swim.) Choose the correct statement. Select one:_______
a. Nice hits the water at the same time as Mean
b. Mean and Nice have the same speed throughout their trajectories
c. Nice hits the water first
d. Mean hits the water first
e. Mean has a greater acceleration mid-flight, than Nice in mid-flight
Part-2: Mean Kid pushes Nice Kid off a dock into the water. Mean does this by pushing Nice horizontally. But, karma has finally caught up with Mean and at the same instant that Mean pushes Nice horizontally, the dock also collapses and Mean immediately begins to fall towards the water as well. After Nice swims to shore, Karma arranges for a jelly fish to give Mean a bit of a sting. Choose the correct statement Select one:________
a. Mean and Nice hit the water with the same speed
b. Nice hits the water faster than Mean
c. Mean hits the water with a larger vertical component of speed than Nice's vertical component of speed
d. Nice hits the water slower than Mean
Answer:
Part-1: a)
Part-2: b)
Explanation:
Part-1
Since Nice is pushed horizontally, in the vertical direction, he has no initial component of velocity, due to both movements are independent each other.Since the dock collapses, this means that in the vertical direction, the movement of Mean is exactly the same as Nice's.The expression for the vertical displacement is given by the following equation:[tex]\Delta y = \frac{1}{2} * g* t^{2} (1)[/tex]So, due to the time of flight is determined by the height exclusively, and they start from the same height, we can conclude that they will hit the water at the same time.So, the right answer is the a) for Part-1.Part-2
The speed of both kids is given by the vector sum of the vertical and horizontal components of velocity when they hit the water.Mean falls vertically, with no component of velocity in the horizontal direction.In the vertical direction, Nice falls with exactly the same speed, as they hit water at the same time.However, Nice has a horizontal component of the velocity, that keeps constant during all his flight, as no external forces act in the horizontal direction.So, the magnitude of Nice's speed must be larger than Mead's, due to the vertical components are the same, and the extra horizontal component of Nice's adds to the vertical one.So, the right answer is b.) for Part-2.Which correctly describes how the energy of a wave on the electromagnetic spectrum depends on wavelength and frequency?
A.
Energy decreases with decreasing wavelength and decreasing frequency.
B.
Energy increases with decreasing wavelength and increasing frequency.
C.
Energy increases with decreasing wavelength and decreasing frequency.
D.
Energy decreases with increasing wavelength and increasing frequency.
Answer:
B. Energy increases with decreasing wavelength and increasing frequency.
Explanation:
which equation can be used to solve for accelerarion
Answer:
a = Δv/Δt
Explanation:
The little triangle stands for change and t=time and v=velocity
Answer:
a = [tex]\frac{v-u}{t}[/tex]
Sultan throws a ball horizontally from his window, 12 m above the garden. It reaches the ground after
Select........seconds.
4.0
5.0
2.4
1.6
Answer and I will give you brainiliest
Answer:
2.4Explanation:
Hope it help mark as BrainlistA 1.2 x 103 kg racecar, with a velocity of 8 m/s, collides with an unsuspecting 80 kg honey badger who is standing
still. After the collision, the racecar is traveling at 2 m/s. What is the velocity of the honey badger after the
collision if it goes flying?
Answer: 90 m/s
Explanation:
Given
mass of racecar [tex]M=1.2\times10^3\ kg[/tex]
velocity of racecar [tex]u=8\ m/s[/tex]
mass of still honeybadger [tex]m=80\ kg[/tex]
after collision race car is traveling at a speed of [tex]v_1=2\ m/s[/tex]
conserving linear momentum
[tex]Mu+m\times0=Mv_1+ mv_2\quad[v_2=\text{velocity of honeybadger after colllision}][/tex]
[tex]1.2\times10^3\times8+0=1.2\times10^3\times2+80\times v_2[/tex]
[tex]1.2\times10^3(8-2)=80v_2\\v_2=\frac{7.2\times10^3}{80}=90\ m/s[/tex]
2. A car travels 32 m/s south in 9 seconds. What is the car's displacement ?
Answer:
3.56m due south
Explanation:
Given parameters:
Velocity of the car = 32m/s
Time = 9s
Unknown:
Displacement of the car = ?
Solution:
The velocity of a body is its displacement per unit of time in a specific direction.
Velocity = [tex]\frac{displacement}{time}[/tex]
So;
Velocity = [tex]\frac{32}{9}[/tex] = 3.56m due south
The wheels of the locomotive push back on the tracks with a constant net force of 7.50 × 105 N, so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 km/h?
Answer:
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
Explanation:
Statement is incomplete. Complete description is presented below:
A freight train has a mass of [tex]1.83\times 10^{7}\,kg[/tex]. The wheels of the locomotive push back on the tracks with a constant net force of [tex]7.50\times 10^{5}\,N[/tex], so the tracks push forward on the locomotive with a force of the same magnitude. Ignore aerodynamics and friction on the other wheels of the train. How long, in seconds, would it take to increase the speed of the train from rest to 80.0 kilometers per hour?
If locomotive have a constant net force ([tex]F[/tex]), measured in newtons, then acceleration ([tex]a[/tex]), measured in meters per square second, must be constant and can be found by the following expression:
[tex]a = \frac{F}{m}[/tex] (1)
Where [tex]m[/tex] is the mass of the freight train, measured in kilograms.
If we know that [tex]F = 7.50\times 10^{5}\,N[/tex] and [tex]m = 1.83\times 10^{7}\,kg[/tex], then the acceleration experimented by the train is:
[tex]a = \frac{7.50\times 10^{5}\,N}{1.83\times 10^{7}\,kg}[/tex]
[tex]a = 4.098\times 10^{-2}\,\frac{m}{s^{2}}[/tex]
Now, the time taken to accelerate the freight train from rest ([tex]t[/tex]), measured in seconds, is determined by the following formula:
[tex]t = \frac{v-v_{o}}{a}[/tex] (2)
Where:
[tex]v[/tex] - Final speed of the train, measured in meters per second.
[tex]v_{o}[/tex] - Initial speed of the train, measured in meters per second.
If we know that [tex]a = 4.098\times 10^{-2}\,\frac{m}{s^{2}}[/tex], [tex]v_{o} = 0\,\frac{m}{s}[/tex] and [tex]v = 22.222\,\frac{m}{s}[/tex], the time taken by the freight train is:
[tex]t = \frac{22.222\,\frac{m}{s}-0\,\frac{m}{s} }{4.098\times 10^{-2}\,\frac{m}{s^{2}} }[/tex]
[tex]t = 542.265\,s[/tex]
The freight train would take 542.265 second to increase the speed of the train from rest to 80.0 kilometers per hour.
What is the displacement of a runner when he completes one lap round tract in 100 seconds.
Answer:
0m
Explanation:
The displacement of a runner when he completes one lap round track in 100s is 0m.
Displacement is the distance covered in a specific direction. This quantity is referred to as a vector because it has both magnitude and direction.
Displacement takes into account the starting and finishing position of a body. Also, the direction from start to finish gives us the vector dimension of the body. Therefore, when the runner completes a lap, the start and finishing point is the same The displacement is 0mDescribe with the help of diagram an instrument which can be used to detect a charged body.
Answer:
Electroscope is a device which is used to test if an object is carrying charge or not. It consists of 2 metal leaves which are connected to a metal rod which in turn is connected to a disc.
A projectile leaves the muzzle of a projectile launcher with a speed of 35m/s [the
launcher is oriented vertically].
a) What is the maximum height reached by the projectile?
b) How long did it take the projectile to reach its maximum height?
c) How long was the projectile in the air [ttot]?
Answer:
a. 62.44 m
b. 3.57 sec
c. 7.12 sec
Explanation:
The leaving speed is given as = 35 m/s
The launcher is oriented vertically, thus the angle is = 0 degrees
a) The maximum height reached is given as;
h= v²₀y / 2g
h=35² / 2 * 9.81
h= 62.44 m
b) Time the projectile reaches maximum height is given as;
t=v₀y / g
t=35/9.81
t= 3.57 sec
c) The trip up is a mirror of the trip down
This means the time the projectile will be in the air is ;
t= 2 * 3.57
t= 7.12 sec
Which depends on your location weight or mass
Answer:
yes he is true I too believe weight only the mass never changes.
25 POINTS!!!!!!
Check all the boxes that correspond to a particle emitted during a radioactive decay: *
Proton
Atom core
Electron
Boson
Positron
Sound waves
Neutron
Gamma ray
Alpha particle
Answer:
proton nuetron electron
Part-1: Mean Kid pushes Nice Kid off a dock into the water. Mean does this by pushing Nice horizontally. But, karma has finally caught up with Mean and at the same instant that Mean pushes Nice horizontally, the dock also collapses and Mean immediately begins to fall towards the water as well. (Karma isn't finished with Mean though, because only Nice knows how to swim.) Choose the correct statement.
a. Nice hits the water at the same time as Mean
b. Mean and Nice have the same speed throughout their trajectories
c. Nice hits the water first
d. Mean hits the water first
e. Mean has a greater acceleration mid-flight, than Nice in mid-flight
Part-2: Mean Kid pushes Nice Kid off a dock into the water. Mean does this by pushing Nice horizontally. But, karma has finally caught up with Mean and at the same instant that Mean pushes Nice horizontally, the dock also collapses and Mean immediately begins to fall towards the water as well. After Nice swims to shore, Karma arranges for a jelly fish to give Mean a bit of a sting. Choose the correct statement.
a. Mean and Nice hit the water with the same speed
b. Nice hits the water faster than Mean
c. Mean hits the water with a larger vertical component of speed than Nice's vertical component of speed
d. Nice hits the water slower than Mean
Answer:
Part-1: a)
Part-2: b)
Explanation:
Part-1
Since Nice is pushed horizontally, in the vertical direction, he has no initial component of velocity, due to both movements are independent each other. Since the dock collapses, this means that in the vertical direction, the movement of Mean is exactly the same as Nice's. The expression for the vertical displacement is given by the following equation: [tex]\Delta y = \frac{1}{2} * g*t^{2} (1)[/tex] So, due to the time of flight is determined by the height exclusively, and they start from the same height, we can conclude that they will hit the water at the same time. So, the right answer is the a) for Part-1.Part-2
The speed of both kids is given by the vector sum of the vertical and horizontal components of velocity when they hit the water. Mean falls vertically, with no component of velocity in the horizontal direction. In the vertical direction, Nice falls with exactly the same speed, as they hit water at the same time. However, Nice has a horizontal component of the velocity, that keeps constant during all his flight, as no external forces act in the horizontal direction. So, the magnitude of Nice's speed must be larger than Mead's, due to the vertical components are the same, and the extra horizontal component of Nice's adds to the vertical one. So, the right answer is b.) for Part-2.The blades in a blender rotate at a rate of 6100 rpm. When the motor is turned off during operation, the blades slow to rest in 4.1s. What is the angular acceleration as the blades slow down?
Answer:
155.80rad/s
Explanation:
Using the equation of motion to find the angular acceleration:
[tex]\omega_f = \omega_i + \alpha t[/tex]
[tex]\omega_f[/tex] is the final angular velocity in rad/s
[tex]\omega_i[/tex] is the initial angular velocity in rad/s
[tex]\alpha[/tex] is the angular acceleration
t is the time taken
Given the following
[tex]\omega_f = 6100rpm[/tex]
Time = 4.1secs
Convert the angular velocity to rad/s
1rpm = 0.10472rad/s
6100rpm = x
x = 6100 * 0.10472
x = 638.792rad/s
[tex]\omega_f = 638.792rad/s\\[/tex]
Get the angular acceleration:
Recall that:
[tex]\omega_f = \omega_i + \alpha t[/tex]
638.792 = 0 + ∝(4.1)
4.1∝ = 638.792
∝ = 638.792/4.1
∝ = 155.80rad/s
Hence the angular acceleration as the blades slow down is 155.80rad/s
Ilya and Anya each can run at a speed of 7.50 mph and walk at a speed of 4.00 mph. They set off together on a route of length 5.00 miles . Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.
Required:
a. How long does it take Anya to cover the distance of 5.00 ?
b. Find Anya's average speed.
c. How long does it take Ilya to cover the distance?
Answer:
[tex]T_A=0.93hours[/tex]
[tex]S_A=5.23mph[/tex]
[tex]T_l=0.87hour[/tex]
Explanation:
From the question we are told that
Run speed of Ilya and Anya [tex]S_r=7.50mph[/tex]
Walk speed of Ilya and Anya [tex]S_w=4.00mph[/tex]
Total distance [tex]T_d=5.00miles[/tex]
Anya Walks 1/2d and runs 1/2d
ilya walks 1/2t and runs 1/2d
Generally the distance walked by Ilay k is mathematically given by
Since ilya walks 1/2t and runs 1/2t
Therefore
[tex]\frac{k}{4}=\frac{5-k}{7.5}[/tex]
[tex]k=1.7miles[/tex]
Therefore llay runing distance is m
[tex]m=5-1.7\\m=3.3mile[/tex]
a)Generally the Time walked by Anya [tex]T_A[/tex] is mathematically given by
Anya Walks 1/2d and runs 1/2d
Therefore
[tex]t=\frac{2.5}{4.}[/tex]
[tex]t_1=0.6hours[/tex]
[tex]t=\frac{2.5}{7.5}[/tex]
[tex]t_2=0.33hours[/tex]
[tex]T_A=0.6+0.33\\[/tex]
[tex]T_A=0.93hours[/tex]
b)Generally the average speed of Anya S_A is mathematically given as
[tex]S_A=\frac{Distance}{T_t}[/tex]
[tex]S_A=\frac{5.0}{0.93}[/tex]
[tex]S_A=5.23mph[/tex]
Generally the time taken b y llay [tex]T_l[/tex] is mathematically given by
[tex]T_l=2t[/tex]
[tex]T_l=2*(\frac{1.7}{4})[/tex]
[tex]T_l=0.87hour[/tex]
A student grabs a piece of paper and tears it from the middle. Which statement best explains the forces involved?
a. The friction between the hands and the paper interacts with gravity and causes the paper to tear.
b. The normal force between the molecules of the paper is overcome by the contact force of the hands.
c. The electrostatic forces from the contact of the hands with the paper causes the paper molecules to separate.
d. The magnetic force between the hands and the paper separates the molecules of the paper.
Answer:
b. The normal force between the molecules of the paper is overcome by the contact force of the hands.
Explanation:
The paper molecules are held together by a weak bond. When the student holds the paper on both sides with the center of the paper in between, the student applies two equal forces in the opposite direction of the paper making the paper molecules weaken and separate.
Answer:
The electrostatic forces from the contact of the hands with the paper causes the paper molecules to separate.
Here's the rest of the answers
1.) Which statement is correct about the strength of forces?
Electrostatic forces are trillions of times stronger than gravitational forces.
2.) A student tries to push a book across a table. Which forces acting on the book are a result of electrostatic forces?
normal force and friction
3.) What type of force can explain how a gecko climbs up a wall?
contact forces
5.) A heavy hammer is sitting on top of a board. Which statement correctly describes why the hammer does not go through the board?
The electrostatic forces between the molecules of the board prevent the force of gravity from breaking the board apart.
TRUE or FALSE: You maintain a healthy body composition by balancing your food intake with your exercise
Answer:
Summary: Nutrition and exercise are critical for improving body composition. Keeping your calories, fiber and protein in check is a good first step. All exercise can help with fat loss, but weight training is the best way to increase muscle mass.
Explanation:
Answer: TRUE
Explanation:
What is the stretch when you pull with a force of 2.3 N on a spring with a spring constant of 19 N/m?
Answer:
x=0.12 m
Explanation:
Use the equation F=kx and isolate x because that's what you're solving for (x=F/k). Plug in your given values for F and k and solve for x [x=(2.3 N)/(19 N/m)] and you get x=0.12 m.
The wavelength of a sound in a certain material is 18 cm the frequency of a wave is 2000 Hy calculate the speed of the wave
Answer:
Speed = 360m/s
Explanation:
Given the following data;
Wavelength = 18cm to meters = 18/100 = 0.18m
Frequency = 2000Hz
To find the speed;
Speed = frequency * wavelength
Speed = 2000 * 0.18
Speed = 360m/s
Therefore, the speed of the wave is 360 meters per seconds.
In comparing molar specific heat for gases under constant pressure CP and constant volume CV, we conclude that (more than one could be correct): _______
a. CP is constant for all gases, and so is CV.
b. Specific heat increases as the number of atoms per molecule increases.
c. Specific heat at constant pressure is higher than at constant volume.
d. Monatomic gases behave like ideal gases.
Answer:
b. Specific heat increases as the number of atoms per molecule increases.
c. Specific heat at constant pressure is higher than at constant volume.
d. Monatomic gases behave like ideal gases.
Explanation:
Specific heat of the gas at constant pressure is usually higher than that of the volume.
i.e.
Cp - Cv = R
where R is usually the gas constant.
However, monoatomic gases are gases that exhibit the behavior of ideal gases. This is due to the attribute of the intermolecular forces which plays a negligible role. Nonetheless, the case is not always true for all temperatures and pressure.
Similarly, the increase in the number of atoms per molecule usually brings about an increase in specific heat. This effect is true as a result of an increase in the total number associated with the degree of freedom from which energy can be separated.
Thus, from above explanation:
Option b,c,d are correct while option (a) is incorrect.
What equal positive charges would have to be placed on two celestial objects with masses 4.69 × 1027 and 1.23 × 1025 kg to neutralize their gravitational attraction? (b) What mass of hydrogen would be needed to provide the positive charge calculated in (a)?
Answer:
q= 2.07*10¹⁶ C
m= 2.2*10⁸ kg.
Explanation:
a)
In order to neutralize their gravitational atraction (given by Newton's Universal Law of Gravitation), both masses must be repelled with an equal and opposite force, that must obey Coulomb's Law.So, we can write the following general equation:[tex]G*\frac{m_{1} *m_{2}}{r_{12}^{2}} = k * \frac{q_{1}*q_{2}}{r_{12} ^{2}} (1)[/tex]
Since G and k are universal constants, and that the distance on both sides is the same, and q₁ = q₂ = q, replacing in (1) the values of m₁ and m₂, we can solve for q, as follows:[tex]q =\sqrt{\frac{G*m_{1}*m_{2}}{k} } = \sqrt{\frac{6.67e-11*4.69e27*1.23e25}{9e9} } = 2.07e16 C (2)[/tex]
b)
Since hydrogen can carry only one elementary charge per atom, this charge will be distributed in a number of atoms that will be given by the charge q, divided by the value of the elementary charge, as follows:[tex]n_{H} = \frac{q}{e} =\frac{2.07e16C}{1.6e-19C} = 1.29e35 (3)[/tex]
Since each hydrogen has one proton and one electron, neglecting the mass of the electron, the mass of hydrogen needed to provide the positive charge q, will be just the product of the number of atoms needed (given by (3)) times the mass of the proton, as follows: [tex]m_{H} = n_{H} * m_{p} = 1.29e35*1.67e-27 kg = 2.2e8 kg (4)[/tex]A point charge, Q1 = 12.0 C, is placed at the origin (0 cm, 0 cm) and a second charge, Q2, is placed at the coordinates (4.00 cm, 0 cm). A third charge, Q3 = 15.00 C, is placed at (5.0 cm, 0 cm). The force on Q3 is F⃑ = −20.0 N î. What is the value and sign of Q2?
Answer:
q₂ = -4.80 10⁻⁴ C = - 0.48 mC, charge is negative
Explanation:
Let's use coulomb's law
F = [tex]k \frac{q_1 q_2}{r^2}[/tex]
and the sum of forces, remember that charges of the same sign repel and of different sign attract
∑ F = F₁₃ + F₂₃ (1)
Let's start by fixing a reference system located at charge 1 with the positive direction to the right. In the problem it indicates that the net force on charge 3 is F = - 20.0 N, the negative sign indicates that the force is towards the left
let's look for every force, the charge q₁ = 12 10-⁻³ C and q₃ = 15 10⁻³ C
F₁₃ =[tex]k \frac{q_1 q_3}{x_{13}^2}[/tex]
F₁₃ = 9 10⁹ 12.0 15.0 10⁻⁶ / (5-0)²
F₁₃ = 64.8 10 3 N
This force is repulsive, that is, it is directed to the right
F₂₃ = k \frac{q_2 q_3}{x_{23}^2}
F₂₃ = 9 10⁹ q₂ 15.0 10⁻³ / (5-4)²
F₂₃ = 135 10⁶ q₂ N
we substitute in equation 1
-20.0 = 64.8 10³ + 135 10⁶ q₂
q₂ = (-20 - 64.8 10³) / 135 10⁶
q₂ = -4.80 10⁻⁴ C
the sign indicates that the charge is negative
A cable that weighs 8 lb/ft is used to lift 900 lb of coal up a mine shaft 650 ft deep. Find the work done. Show how to approximate the required work by a Riemann sum.
Answer:
2275000 lb.ft
Explanation:
Let work done on the cable be denoted by: W_ca
Let work done on the coal be denoted by: W_co
Now, dividing the cable into segments, let x represent the length from top of the mine shaft to the segment.
Meanwhile let δx be the length of the segment.
We are told the cable weighs 8 lb/ft. Thus;
Work done on one segment = 8 × δx × x = 8x•δx
Therefore, work done on cable is;
W_ca = ∫8x•δx between the boundaries of 0 and 650
Thus;
W_ca = 4x² between the boundaries of 0 and 650
W_ca = 4(650²) - 4(0²)
W_ca = 1,690,000 lb.ft
Workdone on the 900 lb of coal will be calculated as;
W_co = 900 × 650
W_co = 585000 lb.ft
Thus,
Total work done = W_ca + W_co
Total workdone = 1690000 + 585000
Total workdone = 1690000 + 585000
Total workdone = 2275000 lb.ft
I don’t know what to do
Answer:
So increasing the voltage increases the charge in direct proportion to the voltage. If the voltage exceeds the capacitors rated voltage, the capacitor may fail due to breakdown of the dielectric between the two plates that make up the capacitor.
Explanation:
A option.
The temperature of 335 g of water changed from 24.5°C to 26.4°C. How much heat did this
sample absorb?
Answer:
3065.4J
Explanation:
Given parameters:
Mass of water = 335g
Initial temperature = 24.5°C
Final temperature = 26.4°C
Unknown:
How much heat is absorbed by the sample = ?
Solution:
To solve this problem, we use the expression below:
Heat absorbed = mass x specific heat of water x change in temperature
The specific heat of water = 4.816J/g°C
So;
Heat absorbed = 335 x 4.816 x (26.4 - 24.5) = 3065.4J
