...........................

The algebraic representation of the phrase is 28+5n and when n  is 4.2, then the value is 49.

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Steps to write down the simple algebraic expression-

The statement given in the problem is that the twenty-eight plus the product of five and a number.

Let suppose the unknown number is n. Now the product of this number with 5 can be written as,

[tex]5\times n\\5n[/tex]

As, the equation is made when the number 28 is plus in this product. Thus the algebraic representation of the phrase is,

[tex]28+5n[/tex]

When the value of n is 4.2, then the value of this algebraic would be,

[tex]28+5(4.2)\\28+21\\49[/tex]

Hence, the algebraic representation of the phrase is 28+5n and when n  is 4.2, then the value is 49.

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Answer:

x = 7.5

Step-by-step explanation:

A line parallel to a side of a triangle and intersecting the other 2 sides, divides those sides proportionally, that is

[tex]\frac{8}{10}[/tex] = [tex]\frac{6}{x}[/tex] ( cross- multiply )

8x = 60 ( divide both sides by 8 )

x = [tex]\frac{60}{8}[/tex] = 7.5

Answer:

See below.

Step-by-step explanation:

-3.7x-9.1=9x+9.2

       +9.1      +9.1

-3.7x=9x+18.3

-9x    -9x

-12.7x=18.3

/-12.7   /-12.7

x=-1.44, or -1.4

-hope it helps

Answer:

65,7754.6

Step-by-step explanation:

because the tenths place is the place just right of the decimal and any number that is bigger than 4 makes the number to the left round up 5 becomes 6.

Answer:

65,754.6

Step-by-step explanation:

when there is a number greater than 5 after a number you must round just add 1 to the number you have to round

for example if you have to round 1.06 to the tenths it will just be

1.1

Answer:

that is a example of division problem if u have any other questions about division just ask I will help u the best I can

Step-by-step explanation:

Answer:

the answer is 35.2101 explained in image .

Answer:

[tex]-6.36 \times 10^{-11}[/tex]

Step-by-step explanation:

[tex]\dfrac{-6.2\times10^{-4}}{9.75\times10^6}[/tex]

[tex]\implies \dfrac{-6.2}{9.75}\times \dfrac{10^{-4}}{10^6}[/tex]

[tex]\implies \dfrac{-6.2}{9.75}=-6.36\times10^{-1}[/tex]

Apply exponent rule: [tex]\dfrac{a^b}{a^c}=a^{b-c}[/tex]

[tex]\implies \dfrac{10^{-4}}{10^6}=10^{(-4-6)}=10^{-10}[/tex]

[tex]\implies \dfrac{-6.2}{9.75}\times \dfrac{10^{-4}}{10^6}=-6.36 \times 10^{-1} \times 10^{-10}[/tex]

Apply exponent rule: [tex]a^b \times a^c=a^{(b+c)}[/tex]

[tex]\implies -6.36 \times 10^{-1} \times 10^{-10}=-6.36 \times 10^{(-1-10)}[/tex]

[tex]\implies -6.36 \times 10^{-11}[/tex]

[tex]\\ \rm\hookrightarrow \dfrac{-6.2\times 10^{-4}}{9.75\times 10^6}[/tex]

[tex]\\ \rm\hookrightarrow 0.636\times 10^{-4-6}[/tex]

[tex]\\ \rm\hookrightarrow 0.636\times 10^{-10}[/tex]

[tex]\\ \rm\hookrightarrow 6.4\times 10^{-11}[/tex]

Find the area of the square

Find the area of the circle

Subtract the area of the circle from the area of the square.

area of square = 10 x 10 = 100 sq. Cm

Area of circle = pi x r ^2 = 3.14 x 5^2 = 78.5 sq. Cm

area of shard region = 100 - 78.5 = 21.5 cm^2

72:64::x:16

72/64 = x/16

72*16 = x*64

x= 72*16/64

x= 18

Hence the answer is 18.

Correct me, if I am wrong :)

Have a great day!

Thanks!

Answer:

last year it was 80k

Step-by-step explanation:

Population increases by 5% every year

Last year it was 80,000

PRESENT POPULATION

Present population = 80,000 + 5% off 80,000

                               = 80,000 + 5/100 × 80,000

                               = 80,000 + 5 × 800

                               = 80,000 + 4,000

                               = 84,000

AFTER ONE YEAR

After this , the population again increases by 5%

Population = 84,000 + 5% off 84,000

                 = 84,000 + 5/100 × 84,000

                 = 84,000 + 5 × 840

                 = 84,000 + 4,200

                 = 88,200

ANSWERS

The population of present year is 84,000

After one year , the population becomes 88,200

Hope it helps :-)

Answer:

1. The Present population is 84,000

2. The next years population 88,200 and the year after that would be 92,610

Step-by-step explanation:

If you take the previous year and multiply it by 1.05 you you get the current population. After that you take the current population and multiply it again by 1.05 since the population increases by 5% so continue multiplying by 1.05 to get the later years and so forth

Answer:

B

Step-by-step explanation:

IQR is the higher qurtile subtracted by the lower qurtile so higher is 40 and lower is 20 so 14

Hope this helps have a great day:)

Tracker B has a greater radius and would be able to cover more area.

An equation is an expression that is used to show the relationship between two or more numbers and variables.

Tracker A has a radius of 4.102 feet, hence:

Area covered = π * 4.102² = 52.86 ft²

Tracker B has a radius of 104 feet, hence:

Area covered = π * 104² = 33979.5 ft²

Tracker B has a greater radius and would be able to cover more area.

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Answer:

14/18

Since 4 out of the 18 chocolates are white, the rest will be 14 milk chocolates

and in total there are 18 chocolates

The properties of the quadrilaterals gives the equivalent relations used

to find the lengths and the angles.

Response:

1. m∠AED = 90°

2. m∠ADE = 23°

3. m∠BAE = 67°

4. AE = 5

5. BE = 12

6. 19

7. 22

8. WXYZ is a rectangle

9. WXYZ is a square

10. [tex]\overline{QS} \cong \overline{RT}[/tex] by Corresponding Parts of Congruent Triangles Congruent, CPCTC

11. a. The diagonals are perpendicular and the given figure is not a rectangle

b. The given figure is not a rhombus

c. The figure is a square.

d. ∠AEB = 90°

e. m∠EAD = 45°

1. The  diagonals of a rhombus bisect each other at right angles

Therefore;

m∠AED = 90° (by definition of right angles)

2. m∠EAD and m∠ADE are complementary angles

Which gives;

m∠EAD + m∠ADE = 90°

m∠ADE = 90° - m∠EAD

Therefore;

m∠ADE = 90° - 67° = 23°

3. The diagonals of a rhombus bisect the angles, therefore;

m∠BAE = m∠EAD = 67°

4. The diagonals bisect each other, therefore;

AE = CE = 5

5. BE = DE = 12

6. JL = 3·x + 4

KM = 4·x - 1

Which gives;

3·x + 4 = 4·x - 1

4·x - 3·x = 4 + 1 = 5

x = 5

KM = JL = 3 × 5 + 4 = 19

7. JL = 2·x - 6

[tex]KM = \mathbf{\dfrac{3}{2} \cdot x+ 1}[/tex]

Which gives;

[tex]\frac{3}{2} \cdot x+ 1 = 2\cdot x - 6[/tex]

[tex]2\cdot x -\frac{3}{2} \cdot x = 6 + 1 = 7[/tex]

[tex]\dfrac{1}{2} \cdot x = 7[/tex]

x = 2 × 7 = 14

JL = 2 × 14 - 6 = 22

8. W(3, 1), X(3, -2), Y(-5, -2), Z(-5, 1)

WX = 1 - (-2) = 3

YZ = 1 - (-2) = 3

XY = 3 - (-5) = 8

WZ = 3 - 5 = 8

Slope of WX = (1 - (-2)) ÷ (3 - 3) = ∞

Slope of YZ = (1 - (-2)) ÷ (-5 - (-5)) = ∞

Slope of XY = (-2- (-2)) ÷ (3- (-5)) = 0

Slope of WZ = (1- 1) ÷ (3- (-5)) = 0

Therefore;

WX and YZ are perpendicular to XY and WZ

The properties of WXYZ are the properties of a quadrilateral having perpendicular sides.

9. W(4, 1), X(1, 4), Y(-2, 1), Z(1, -2)

WX = √((4 - 1)² + (1 - 4)²) = 3·√2

YZ = √((1 - (-2))² + (-2 - 1)²) = 3·√2

XY = √((1 - (-2))² + (4 - 1)²) = 3·√2

WZ = √((1 - (-2))² + (4 - 1)²) = 3·√2

Slope of WX = (4 - 1) ÷ (1 - 4) = -1

Slope of YZ = (-2 - 1) ÷ (1 - (-2)) = -1

Slope of XY = (1 - 4) ÷ ((-2) - 1) = 1

Slope of WZ = (-2 - 1) ÷ (1 - 4) = 1

Therefore;

The lengths of the sides are equal and the sides are perpendicular to each other

Therefore;

10. The two column proof is presented as follows;

Statement [tex]{}[/tex]                                            Reason

PSUR is a rectangle [tex]{}[/tex]                           Given

[tex]\overline{PR} = \overline{SU}[/tex] [tex]{}[/tex]                                             Opposite sides of a rectangle

[tex]\overline{PQ} \cong \overline{TU}[/tex]  [tex]{}[/tex]                                           Given

[tex]\overline{PQ} = \overline{TU}[/tex]  [tex]{}[/tex]                                           Definition of congruency

[tex]\overline{PR} = \overline{RQ} + \overline{PQ}[/tex] [tex]{}[/tex]                                  Segment addition postulate

[tex]\overline{SU} = \overline{ST} + \overline{TU}[/tex] [tex]{}[/tex]                                   Segment addition postulate

[tex]\overline{RQ} = \overline{ST}[/tex]    [tex]{}[/tex]                                          Addition property of equality

ΔPQS ≅ ΔTUR    [tex]{}[/tex]                                ASA rule of congruency

[tex]\overline{QS} \cong \overline{RT}[/tex]         [tex]{}[/tex]                                    CPCTC

11. The properties of a rectangle are;

The interior angles are 90°

The diagonals are not perpendicular to each other

In the given figure, the four triangles formed by the diagonals are congruent, therefore;

The angles at the vertex point of the four tringles are equal to each other and therefore, equal to 90°

Therefore;

b. The lengths of the diagonals, are equal, therefore;

e. The properties of the figure, which includes;

All sides are equal

The interior angles are 90°

d. The diagonals of a square are angle bisectors of the interior angles

Therefore;

m∠ABE = m∠CBE

m∠ABE + m∠CBE = 90° by definition of complementary angles

Therefore;

m∠ABE  = 90° ÷ 2 = 45°

Similarly;

m∠ABE = m∠BAE = 45°

m∠AEB = 180° - (m∠ABE + m∠BAE)

e. m∠EAD = m∠BAE = 45° (angles formed by the diagonal AC)

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Answer:

This is ratio. A:B = 3:5

If the 3 parts of a =90 that means 1 part =30 (90/3=30).

So B =5.

5 parts would equal 30x5= 150

B=150cm

Answer:

Ari has two pieces of ropes, a and b, their lengths are in the ratio 3:5. rope a is 90 cm long. if ari cuts of the ratio of the length of rope a to the remaining length to rope b?​

Step-by-step explanation:

Answer:

  a) 2%

  b) 0.17%

Step-by-step explanation:

Exponential growth is modeled by the equation ...

  y = a·b^x

where 'a' is the initial value, and 'b' is the growth factor.

When x is has units of time, the growth factor 'b' applies over 1 unit of x. The applicable growth factor for different units of time can be found using the rules of exponents applied to the equation written with x expressed in the different units.

The growth rate is related to the growth factor by ...

  b = 1 +r . . . . where r is the growth rate

  r = b -1 . . . . solved for r

__

Your equation is ...

  V = 300(1.02^t)

where t is expressed in years. Then the corresponding annual growth rate is ...

  b = 1.02

  r = b -1

  r = 1.02 -1 = 0.02 = 2% . . . annual rate of growth

__

When the equation is written so that t is expressed in months, it becomes ...

  V = 300(1.02)^(t/12)

  V = 300(1.02^(1/12))^t

Now, the growth factor (per month) is

  b = 1.02^(1/12)

and the monthly growth rate is ...

  r = 1.02^(1/12) -1 ≈ 1.00165158 -1 = 0.00165158

  r ≈ 0.17% . . . . monthly rate of growth

Answer:

The graph in the lower left corner does not belong.

Step-by-step explanation:

It does not belong because the other praghs have already intercected or are going to eventually like the upper right corner one.

Have a great day!

Please rate!

Answer:

9m

Step-by-step explanation:

3/4 = 0.75

each piece = 0.75

0.75x12=9

Answer:

9 meters.

Step-by-step explanation:

Because there are 12 pieces that were cut.

If each were 3/4 meters then what is 3/4 x 12= 9 meters and that were the length

Have a great afternoon Hope this helps:)

Answer:

t² + t - 3 = 0

Step-by-step explanation:

C = t - 5

B = t² - 2

2C + 2B

= 2(t - 5) + 2(t² + 2)

= 2t - 10 + 2t² + 4

= 2t² + 2t - 6

=> t² + t - 3 = 0

Answer: 4,986.875

Step-by-step explanation: Multiply 25.25 x 19.75. Then, multiply the product by 10, or shift the decimal point one place to the right.

Answer:

25/9 is the answer

the ratio of the area of PQSR to the area of FGHI is 25/9. The correct answer is:

25/9

To find the ratio of the area of quadrilateral PQSR to the area of quadrilateral FGHI, we can use the property that the ratio of the areas of two similar figures is the square of the ratio of their corresponding side lengths.

Given that quadrilateral PQSR is similar to quadrilateral FGHI, we know that the ratio of corresponding side lengths is QSGH = 5/3.

Now, let's find the ratio of the areas:

Ratio of areas = (QSGH)² = (5/3)² = 25/9

So, the ratio of the area of PQSR to the area of FGHI is 25/9. The correct answer is:

25/9

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#SPJ2

Answer:

[tex]-29[/tex]

solving steps:

[tex]\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\left(10+15\right)/1/3[/tex]

[tex]\sf \hookrightarrow -\left(-4\right)\left(-6\right)-3/5\cdot \:25/1/3[/tex]

[tex]\sf \hookrightarrow -24-3/5\cdot \:25/1/3[/tex]

[tex]\sf \hookrightarrow -24-5[/tex]

[tex]\sf \hookrightarrow -29[/tex]

Answer:

the answer is 29.

Step-by-step explanation:

use the order of operations to solve
PEMDAS

Answer:

1 1/2 miles

Step-by-step explanation:

if running 1 lap around a track is 1/2 miles then all we have to do is add it up

so we know that 1/2 miles is one lap

so if he runs two laps we would have run 1 mile

now that we know that he would have ran 1 mile in 2 laps then all we have to do it just add 1 more 1/2 mile in which would give u the answer of 1 1/2 miles or 1.5 miles

Answer: Vance has ran 2.5 miles. In other words 2 and a half miles

Step-by-step explanation:

Technically any two numbers in a ratio that are divisible by the other ratio numbers make them equivalent.

For instance,

[tex]3:6[/tex]

[tex]6:12[/tex]

[tex]Equivalent.[/tex]

Because...

[tex]\frac{3 * 2 = 6}{6 * 2 = 12}[/tex]

Or...

[tex]\frac{3}{6} = \frac{6}{12}[/tex]

The equation above represents, "Divide 3 by 6 and divide 6 by 12". From both equations to here, you now know what to multiply the numbers by to get your answer.

From here, multiply 3 by 2, and, 6 by 2, to get the equivalent ratio, 6:12.

Therefore, 6:7 and 24:28 are equal as 6:7 and 24:28 are, too.

Answer:

the answer has to be ac+ad+bc+bd

Step-by-step explanation:

Answer:

[tex]2 + 2[/tex]

Step-by-step explanation:

Do this and it come answer

Answer:

B. Commutative property

Step-by-step explanation:

In commutative property, changing the order of the operands will not change the result.

5 + 2 = 7  &

2 + 5 = 7

r² x height x pi x 4 divide by 3

no word form r² x h x pi x 4/3