Briefly discuss the principle forms of communication that might be utilized in the construction industry?
Answer:
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The 10-kg lamp is suspended from the
three equal-length cords. Determine its
smallest vertical distance s from the
ceiling if the force developed in any
cord is not allowed to exceed 50 N.
120°
A
600 mm
120°
Answer:
hello your question is incomplete attached below is the complete diagram
answer : 519 mm
Explanation:
Given the conditions it can be said that the cords are symmetric i.e. AD, BD , CD has same value
hence ; DA = DB = DC = 600 mm
Tension in all cords are the same ( T ) = 50 N
lets assume the angle between the cords and the Z-axis is ∅
∑ Fz = 0
3 * T cos ∅ - 10*9.81 = 0
therefore ; ∅ = 49.16°
looking at attached triangle AD0
tan ∅ = [tex]\frac{600}{s}[/tex]
Hence ; s = 519 mm
Seperate real and imaginary parts tan(2x+i3y)
Answer:
First you have to separate real and imaginary parts of Tan(x+iy)=Tan(z)=sin(z)/cos(z)
sinz=sin(x+iy)=sinxcos(iy)+cosxsin(iy)=sinxcoshy-icosx sinhy
cosz=cos(x+iy)=cosxcos(iy)-sinxsin(iy)=cosxcoshy−isinxsinhy
Now if you plug in Tan(z) and simplify (it is easy!) you get
Tan(z)=(sin(2x)+isinh(2y))/(cos(2x)+cosh(2y))= A+iB.
This means that
A=sin(2x)/(cos(2x)+cosh(2y)) and B= sinh(2y)/(cos(2x)+cosh(2y))
Now,
A/B=sin(2x)/sinh(2y)
If any questions, let me know.
Which of the following can not be used to store an electrical charge?