The relative motion of gaseous particles increases with increase in the temperature of the gas molecules just like the motion of popcorn in a popper increases when heat is applied to the popper.
What is kinetic theory of gas?The kinetic theory of gases or matter states that matter consists of tiny particles which are constant motion, colliding with one another and with walls of the containing vessels.
Just like a popcorn in a popcorn popper pops when heat is applied to the popper, gases contained in a cylinder increases their speed when they acquire more kinetic energy as the temperature of the cylinder increases.
Thus, the motion of gas particles depends on the temperature of the containing vessel so also does the random motion of popcorn depends on the temperature of the popper.
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what is happening in each section by looking at the slope
Answer:
a - constant speed walking north (positive)
b,c,d - accelerating north (positive)
e - stopped
f - negative walking at a constant speed
Explanation:
When the line is straight with a constant slope the person is hiking at a constant speed. If the line curves they are accelerating if it is flat they are not moving and if it has a negative slope the hiker is moving south
help plssss
Your car is traveling at an initial speed of Vo. At t = 0, you start increasing your speed at a constant acceleration. After 20s, the speed of the car is 54 km/ h, after 60 s — 108 km/ h.
a) What was your acceleration?
b) What was your initial speed?
c) What was the speed after 40s?
Given Data:
The applied acceleration is constant.
speed of the car after time,t1 = 20s, is V1= 54 km/h = 15 m/s
speed of the car after time,t2 = 60s, is V2= 108 km/h = 30m/s
we use the formula, V = Vo + a x t
where, Vo is the initial speed, a is the acceleration(constant),
t is the time taken by the object.
a) Acceleration = rate of change of speed with time = V2 - V1 / t2 - t1
a = 30-15/60-20
a = 15/40 = 0.375 m/[tex]{s^{2} }[/tex]
b) Initial speed, Vo = V1 - a x t1
= 15 - 0.375 x 20
= 7.5 m/s
c) Speed after 40 s, V = Vo + a x t, t = 40s
= 7.5 + 0.375 x 40
= 22.5 m/s
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When you prepare a kettle of stew over a camp fire, the stew is warmed in a variety of ways. Explain the combination of processes.
The combination of processes through which the stew is being warmed include conduction, convection and radiation.
What is heat transfer?Heat transfer is defined as the phenomenon whereby heat generated in a medium is being transferred to another location by phase changes.
The transfer of heat occurs in the following combination processes such as:
Thermal Conduction: the transfer of heat through direct contact of the pot of stew with the camp fire.Thermal Convection: the transfer of heated stew at the base of the pot to the stew of the topmost part is through this process.Thermal radiation: this is the heat waves from the camp fire that heats the pot of stew.Learn more about heat energy here:
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a uniformly charged conducting sphere of 1.22 m radius has a surface charge density of 8.13 c/m*. (a) find the charge on the sphere. (4) what ts the total electric flux leaving the surface of the sphere? (c) calculate the electric field at the surface of the sphere.
We select a spherical-shaped Gaussian surface that is concentric with the conducting sphere and has a little bigger radius. Gauss's law determines the flux:
ϕ= ϵ 0 q \s = 8.85×10 −12 C 2 /N.m 2
3.66×10 −5 C =4.1×10 6 N.m 2 /C
What makes it the Gauss law?Gauss' Law, which bears the name of German physicist Carl Friedrich Gauss, is the third of Maxwell's four equations. According to Gauss' Law, an electric charge, qv, or static electricity, produces an electric field, E. (voltage). According to this equation, adding more charge will result in a larger electric field.
According to Gauss's Law, the flux of an electric field through a closed surface equals the contained charge divided by a constant.
Gauss's Law may be used to determine the field due to four different types of equally charged objects: a straight wire, an infinite plate sheet, a thin spherical shell, and a low evenly charged sphere.
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a thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nc. if the electrons are uniformly distributed on the surface, what are the strength and direction of the electric field
While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity. They cannot be added directly, but they can be vectorially inserted.
What are the electric field's strength and direction?A physical field called an electric field surrounds electrically charged particles and attracts or repels all other charged particles nearby. It can also refer to the physical field surrounding a system of charged particles.
While negative point charges always move in the direction of the opposing electric field, positive point charges always move in the other direction. An electric field is a vector quantity.
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now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte
The ratio between centripetal force of satellite b and satellite a is 2vm²/ ve².
We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is
Fc = m . v²/R
where Fc is the centripetal force, m is mass, v is velocity and R is the radius.
From the question, we know that
ma = m
mb = 2m
va = ve
vb = vm
ra = rb = r
Find the centripetal force ratio
Fcb / Fca = (mb . vb²/Rb) / (ma . va²/Ra)
Fcb / Fca = (2m . vm²/r) / (m . ve²/r)
Fcb / Fca = 2 . vm²/ ve²
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how does the total kinetic energy of a cannon and cannonball system change as the mass of the cannon increases and the energy of the blast remains the same?
When the cannon's mass grows and the blast's energy stays constant, the total kinetic energy also stays constant.
What is kinetic energy?Kinetic energy is the force that propels motion, which can be seen in the movement of a particle, an object, or a group of particles. A person walking, a baseball being thrown, a piece of food falling from a table, and a charged particle in an electric field are all instances of objects in motion that use kinetic energy.
Kinetic energy is the kind of power that an object has as a result of motion. It is known as the effort necessary to move a body.
It is important to keep in mind that when the cannon's mass increases while the blast's energy stays constant, the total kinetic energy will also stay constant.
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a soccer ball is kicked from the ground with an initial speed of 19.5 m/s at an upward angle of 45o. a player 55m away in the direction of the kick starts running to meet the ball at that instant. what must be his average speed if he is to meet the ball just before it hits the ground?
Answer:
R = V^2 sin 2θ / g range formula
R = 19.5^2 * 1 / 9.80 = 38.8 m
Vx = 19.5 cos 45 = 13.8 m/s horizontal speed
t = R / Vx = 38.8 / 13.8 = 2.81 sec
v = (55 - 38.8) / 2.81 = 5.76 m/s (about 12.9 mph)
f a stone is thrown vertically upward from the surface of the moon with a velocity of 10 m/s, its height (in meters) after seconds is . (a) what is the velocity of the stone after 7 seconds? (b) what is the velocity of the stone after it has risen 25 m?
a) The velocity of stone after 7 seconds is 1.62 m/sec.
b) The velocity of the stone after it has risen 25 m is -[tex]\sqrt{17}[/tex]
a) h(t) = 10t - 0.83[tex]t^{2}[/tex]
velocity = [tex]\frac{dh}{dt}[/tex](t) = 10 - 2*0.83*t
[tex]\frac{dh}{dt}[/tex] (7) = 10 - 2*0.83*7
= 1.62 m/sec
The stone after 7 seconds is 1.62 m/sec
b) h(t) = 25
10t - 0.83[tex]t^{2}[/tex] = 25
t = 50/83 (10 + [tex]\sqrt{17}[/tex])
[tex]\frac{dh}{dt}[/tex] = 10 - 2*0.83*(50/83)(10 + [tex]\sqrt{17}[/tex])
= 10 - (10 + [tex]\sqrt{17}[/tex])
= - [tex]\sqrt{17}[/tex] m/sec.
The stone after it has risen 25 m is - [tex]\sqrt{17}[/tex] m/sec.
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The correct answer is option C.
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. The average intensity of Wave 1 is nine times the intensity of Wave 2.
By comparing the two electromagnetic waves, we get:
Maximum Electric Field Strength of Wave(1) = 3 x Maximum Electric Field Strength of Wave (2), i.e.
[tex]E_{1}[/tex] = 3 x [tex]E_{2}[/tex]
Now comparing the average intensities of the two waves. we get [tex]\frac{I1}{I2}[/tex]
The average intensity of electromagnetic wave 1 can be expressed as:
[tex]I_{1}[/tex] = [tex]\frac{1}{2}[/tex] x ε0 x [tex]E1^{2}[/tex] x c ------- (1)
Now, the average intensity of the electro-magnetic wave 2 can be expressed as:
[tex]I_{2}[/tex] = [tex]\frac{1}{2}[/tex] x ε0 x [tex]E2^{2}[/tex] x c -----(2)
Now comparing equations 1 and 2 we get.
[tex]\frac{I1}{I2}[/tex] = [tex]E1^{2}[/tex] / [tex]E2^{2}[/tex]
[tex]\frac{I1}{I2}[/tex] = ( 3 x [tex]E2)^{2}[/tex]/ [tex]E2^{2}[/tex]
[tex]\frac{I1}{I2}[/tex] = 9
Thus, we can say that the average intensity of Wave 1 is nine times the intensity of Wave 2.
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The complete question is:
Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of Wave 2. How do the average intensities of the waves compare?
a. The average intensity of Wave 1 is three times the intensity of Wave 2.
b. The average intensity of Wave 2 is three times the intensity of Wave 1.
c. The average intensity of Wave 1 is nine times the intensity of Wave 2.
d. The average intensity of Wave 2 is nine times the intensity of Wave 1.
5.4 a picture frame hung against a wall is suspended by two wires attached to its upper corners. if the two wires make the same angle with the vertical, what must this angle be if the tension in each wire is equal to 0.75 of the weight of the frame? (ignore any friction between the wall and the picture frame.,
If the two wires make the same angle with the vertical, the angle must be 83.6⁰.
What is the angle between the wires?
The angle between the two wires is determined by applying the principle of parallelogram law of vector addition.
R² = a² + b² - 2abcosθ
where;
R is the resultant vector = weight of the frame = Wa is tension in first wire = 0.75Wb is the tension in the second wire = 0.75Wθ is angle between the two wiresW² = (0.75W)² + (0.75W)² - 2(0.75W x 0.75W) cosθ
W² = 1.125W² - 1.125W² cosθ
W² = 1.125W²(1 - cosθ)
W²/1.125W² = 1 - cosθ
0.8889 = 1 - cosθ
cosθ = 1 - 0.8889
cos θ = 0.1111
θ = arc cos(0.1111)
θ = 83.6⁰
Thus, the angle between the two wires is determined as 83.6⁰.
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if a cylindrical space station 275 mm in diameter is to spin about its central axis, at how many revolutions per minute ( rpmrpm ) must it turn so that the outermost points have an acceleration equal to gg ?
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
What is Rotation speed ?
The rate at which the Aeroplan should begin rotating into takeoff attitude is known as V r.
V r, the rotational speed, cannot be lower than V1. A subsequent rejected takeoff may not be achievable within the remaining runway length and is likely to result in a Runway Excursion if it is more than V1 and it is discovered that, at V r, rotation cannot be completed.
V r depends on the weight of the aircraft and the flap position, but it can also change according on temperature, pressure, and altitude.
Gravitational acceleration = g = 9.8 m/s2
Diameter of the space station = D = 275 m
Radius of the space station = R
R = D/2
R = 275/2
R = 137.5 m
Angular speed of the space station = [tex]\omega (rad/s[/tex])
Centripetal acceleration at the outermost points = ac = g = 9.8 m/s2
ac = [tex]\omega2R\\[/tex]
9.8 =[tex]\omega2(137.5)[/tex]
[tex]\omega \\[/tex]= 0.267 rad/s
Converting from rad/s to rpm, (1 revolution = [tex]2\pi radians[/tex] , 1 minute = 60 seconds)
\omega = 0.267 [tex]\times (\frac{60}{2\pi })[/tex]
\omega = 2.55 rpm
Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm
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mass of bullet 0.25kg, velocity of bullet 230kg, mass of gun 9kg. What is the recoil speed of the gun
The recoil speed of the gun is 6.39m/s
What is recoil speed of the gun ?
After firing the bullet, the bullet moves forward with a large momentum and the gun moves backward with an equal momentum. Let m and M be the masses of bullet and gun, respectively. If v and V are the velocities of the bullet and gun, respectively after the firing then:-
0= mv+ MV
Therefore V=-mv/M
The negative sign indicates that the gun moves in a direction to that of
the bullet.
m1v1 = m2v2
m1 = mass of bullet
v1 = velocity of bullet
m2 = mass of gun
v2 = velocity of gun
m1v1=m2v2
0.25*230=9*v2
v2=0.25*230/9 = 6.39m/s
The recoil speed of the gun is 6.39m/s
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a four-wheeled tractor whose operating weight is 47,877 lb is pulled up a road whose slipe is 3.5% at a unifrom speed. if the average tension in the towing cable is 4,860 lb, what is the rolling resistance of the road?
The rolling resistance of the road is 203.02lb per ton
R=P/W where W=47877lb/(2000lb/ton)=23.985 ton
R=4860lb/23.985ton
R=203.02lb per ton.
Rolling resistance, occasionally known as rolling friction or rolling drag, is the pressure resisting the movement when a frame rolls on a surface. Its miles are mainly caused by non-elastic consequences; that is, no longer all of the energy needed for deformation of the wheel, roadbed, and so on., is recovered when the stress is removed.
Tire rolling resistance is the power that your vehicle needs to send to your tires to hold movement at a steady velocity over a surface. In other words, it is the effort required to maintain a tire rolling. the principal contributor to rolling resistance is the process known as hysteresis.
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two people push a 2,159. kg car to get it started. an acceleration of at least 3.4 m/s2 is required to start the car. assuming both people apply the same magnitude force in the same horizontal direction, how much force will each need to apply if friction between the car and the road is 310 n? express your answer in scientific notation. n
The force needed to be applied by each person is 5.150×10^3 N.
The required acceleration is 3.4 m/s2 and the mass of the car is 2,159 kg.
According to Newton's second law:
F = ma
F = 2,159 × 3.4.
F = 7340.6 N
Adding the force of friction into it
F = 7340 + 310
F = 7650.6 N
Since two people need to apply the force
F = 7650 N / 2
F = 3,825.3 N
or
F = 3.825×10^3 N
The force applied by each person to push the car is 3.825×10^3 N.
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What is the magnitude of the force that must be applied for the system below to be balanced?
Answer:
20 N
Explanation:
logically it'd be 20 N due to the fact that it's a rectangular shape. You pretty much look at the counterpart and copy and paste it to the other side.
two automobiles, each of mass 800 kg , are moving at the same speed, 18 m/s , when they collide and stick together. at what speed does the wreckage move if one car was driving north and one east?
14.14 m/s speed does the wreckage move if one car was driving north and one east
Based on the moment of momentum conservation in the x-direction,
1000 20 = (1000 + 1000) yields v _y v y = 10 m/s.
result = 14.14 m/s
What makes momentum so crucial?An object's mass, velocity, and direction are all related by momentum. Force arises from any change in momentum. In order to ascertain the force exerted on the item, a change in momentum is utilised.
Force and momentum are distinct even though they appear to be the same physical quantity. Whether a body is being pulled or pushed, force is often defined as an outside action. The measure of how much motion there is inside a moving body is called momentum, on the other hand.
Unlike force, which refers to a push or pull action, momentum refers to the amount of motion in a moving body. Force modifies a body's momentum. While momentum varies while acceleration is constant, force does not.
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is it possible for the magnetic force on a charge moving in a magnetic field to be zero? (b) is it possible for the electric force on a charge moving in an electric field to be zero? (c) is it possible for the resultant of the electric and magnetic forces on a charge moving simultaneously through both fields to be zero?
a) Yes, provided that the speed is parallel to the magnetic field.
b) No, it is not possible electric field to be zero.
c) No. the magnetic force can be zero.
How do magnetic forces work?Magnets, which can be used to repel or attract other things, exert a force known as magnetism. One of the fundamental forces of nature, electromagnetic, is one of the components of this potent physical phenomenon. A magnetic field is produced when electrically charged particles, which are present in all matter, move.
Briefing:a)Yes, provided that the speed is parallel to the magnetic field.
b) No, the electric force acting on a charge travelling in an electric field cannot be zero since the electric field's amplitude and direction are independent of the motion or velocity of the charged particles.
c) No, the electric force cannot be zero because it is unaffected by the motion of the particles, but the magnetic force can be zero.
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how do the kinetic energy of each of the following objects compare to one another? i. object of mass 3 kg traveling at constant velocity of 4 m/s in the x x direction ii. object of mass 1 kg traveling at constant velocity of 8 m/s in the x x direction iii. object of mass 3 kg traveling at constant velocity of 3 m/s in the x x direction and -3 m/s in the y y direction
The kinetic energy of each of the following objects compare to one another as: II > I > III
As we know the kinetic energy is follows as:
K.E. = 1/2m[tex]v^{2}[/tex]
(i) Object 1
mass = 3kg
velocity = 4m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×3×4×4
K.E. = 24J
(ii) Object 2
mass = 1kg
velocity = 8m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×1×8×8
K.E. = 32J
(iii) Object 3
mass = 3kg
velocity = -3m/s
K.E. = 1/2m[tex]v^{2}[/tex]
K.E. = 1/2×3×(-3)×(-3)
K.E. = 13.5J
Therefore, the kinetic energy of each of the following objects compare to one another as: II > I > III
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a step-up transformer has a primary coil with 150 loops and a secondary coil with 2000 loops. if the primary coil is supplied with a household current of 120 v and 15 a, what voltage is produced in the secondary current?
Voltage produced in the secondary voltage is 1,600 V
What is a current transformer (C.T.) ?A current transformer (C.T.) is a type of "transducer" that produces an alternating current in a secondary winding that is proportional to the current sensed in the primary winding. Current transformers reduce high voltage currents to much lower values and provide a convenient way to safely monitor the actual current flowing in AC transmission lines using a standard ammeter. The working principle of a simple current transformer is slightly different from that of a normal voltage transformer. To calculate voltage in the secondary coil:
N₁/N₂ = V₁/V₂
where;
N₁ is number of turns in primary coil
N₂ is number of turns in secondary coil
V₁ is voltage in primary coil
V₂ is voltage in secondary coil
Now for the given case,
150/2000 = 120/V₂
V₂ = (120 x 2000)/150
V₂ = 1,600 V
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can somebody help me with this?
Answer: (D) thrust has overcome the drag force
Explanation: In order for the plane to move forward, the backward force will have to be overcome. As thrust is a force in the opposite direction of drag so it can cancel out the backward pull of drag and move forward.
7 The distance-time graph for a motorcyclist riding
off from rest is shown in Figure 1.2.18.
a Describe the motion.
b
Calculate how far the motorbike moves in
30 seconds.
c Calculate the speed.
Answer:
a) Uniform rectilinear motion
b) 600 m
c) 20 m/s
Explanation:
a) average velocity is described as the change of position divided by the time of travel, so v= ∆x/∆t. This is a linear function (y = mx+ q) which is the same structure of the equation needed to calculate average velocity (x2= x1 + vt). If you do the ratio between a distance and the corresponding time you'll see that the average velocity is the same, which is typical of this kind of motion.
b) At the the time of 30 seconds the corresponding distance on the y axis is 600 m.
c) Again, v=∆x/∆t and we can rewrite is as v=x2-x1/t. If you take the same data we've used before you can write v= 600m-0/ 30s= 20 m/s. The average velocity is 20 m/s.
an airplane travels from a to b and back with no wind in 4h and 48 min; same airplane travels from a to b and back, with wind speeds of 100mph, and this time takes 5hrs instead; what is the distance between a and b?
The distance between the points A and B is 6000 miles.
Let us assume that the distance between the points a and b is D.
Now, we know, airplane takes 4 hours and 48 minutes to move from a to b and back with no wind
Let us say the speed of the airplane is V.
So, we know,
Average Speed = total distance/total time
The distance between a to b and back is 2D.
So, we can write,
V = 2D/4.8
2D = V(4.8)
With wind of speed V'=100mph, it take 5 hours for the airplane to go from a to b ane back.
The average velocity of airplane in wind is,
V + V' = 2D/5
Putting value of 2D,
V + V' = V(4.8)/5
5(V + 100) = 4.8V
5V + 500 = 4.8V
0.2V = -500
V = -2500mph
The negative sign only means that we have taken the opposite direction, so that is not a problem and we can ignore it,
So,
We know,
2D =V(4.8)
D = 2500(4.8)/2
D = 6000 miles.
So, the distance between the two points is 6000 miles.
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A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it is released.
How fast was the rock thrown?
From Kinematics, the equation for final velocity is
v = [tex]v_{0}[/tex] +at
where [tex]v_{0}[/tex] is the initial velocity, 'a' is the acceleration of the rock, and t is the time taken.
Given, that the rock is thrown upwards and it takes time t = 2.4s to reach a maximum height. So, its acceleration is a= -g= -9.8 m/[tex]s^{2}[/tex] and final velocity is v = 0m/s. To find initial velocity of the rock, rearrange above velocity equation.
⇒[tex]v_{0}[/tex] = v - at
⇒[tex]v_{0}[/tex] = 0 - (-9.8m/[tex]s^{2}[/tex] × 2.4s)
∴ [tex]v_{0}[/tex] = 23.52 m/s.
Thus, the rock was thrown with a velocity 23.52 m/s.
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Can someone help me pls, i also have 3 more questions like this :D
The water molecules in the gas phase have more kinetic energy than in the liquid phase. The molecules in the liquid phase must absorb energy from the surroundings to enter the gas phase.
What is a hot spring?A hot spring can be defined as a natural or an artificially-induced phenomena in which very hot groundwater flows out from the Earth's crust due to the heat energy that is present in the geosphere.
What is a phase change?A phase change simply refers to the change in the state (phase) of matter of a given chemical compound or substance in the following ways:
Gas to solidSolid to liquidLiquid to gasLiquid to solidGenerally speaking, the water molecules in the gas phase typically possesses more kinetic energy than in the liquid phase and as such, it would have to absorb more energy from the surroundings in order to enter the gas phase.
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One drops a penny from top of the Empire State Building on the ground below. The hight of the Empire State Building is 443m How long will it take for a penny yo strike the ground assuming no air resistance
Answer:
See below
Explanation:
Assuming no resistance
DISTANCE = 1/2 a t^2
443 = 1/2 (9.81)t^2 Shows t = 9.5 seconds
Consider a 3-atom molecule a-b-a for which b has a total of only two valence electrons. If you assume that b is a group ii metal, what is the bond angle for a-b-a? please answer in degrees to the nearest whole number.
The bond angle of the molecule to the nearest degree is 120 degrees.
What is the VSEPR theory?According to the valence shell electron pair repulsion theory (VSEPR). We know that the bond angle that an atom has with its neighbors which also call the dihedral angle of the compound is affected by the number of atoms that surround the central atom in the molecule.
Let us recall that when we have two atoms that surround the central atom then we are going to have a three atom compound which has a trigonal planar geometry and has a bond angle of 120 degrees.
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if both the mass of a simple pendulum and its length are doubled, the period will if both the mass of a simple pendulum and its length are doubled, the period will increase by a factor of 0.71. increase by a factor of 2. be unchanged. increase by a factor of 4. increase by a factor of 1.4
The mass of the bob has no bearing on the pendulum's time period.The time duration would therefore remain the same if the mass of the bob doubled.
Solve the problem ?
The equation of motion for the pendulum can be found by using Newton's second rule for rotational systems: =ImgsinL=mL2d2dt2 and then rearranged as d2dt2+gLsin=0 d 2 d t 2 + g L sinIf the angular displacement's amplitude is sufficiently modest, the tiny angle... The length of the rope and the acceleration caused by gravity determine the time it takes for a simple pendulum to swing.When a simple pendulum's length is increased by four times, its period doublesWe currently have the simple pendulum era, which is the simple one to square root of and upon you.Now that the length has been extended, terrible food, we will have an easy quality to buy into L. A. Banjo's square root.This will be equivalent to dividing my by L squared and G by 4²That also is.Since the only factor in this situation is time, we will go into great detail.So, if the basic pendulum's length is raised by a factor of four, its time period will also double.That choice will be the right response. On Earth, a pendulum's swing is only greatly influenced by the length of its string.Students could question why a pendulum's period is solely determined by the length of the string.
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a plane, diving with constant speed at an angle of 53.0o with the vertical, releases a projectile at an altitude of 730 m. the projectile hits the ground 5.00s after release. a) what is the speed of the plane?
The speed of the plane = 202m/s
What is speed ?
Speed is what it means. the speed at which an object's location changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Speed is a scalar quantity since it just has a direction and no magnitude.
To make equations like Eq. immediately applicable, we accept the textbook's use of positive direction options. Directly beneath the release point, at ground level, is the coordinate origin.. The coordinate origin is at ground level directly below the release point. We write θo = −37.0degree
for the angle measured from +x, since the angle φo = 53.0 degree
measured in the problem is in the -y direction. The graphic below depicts the problem's basic configuration.
(A) The plane's speed at the point of release determines the projectile's initial speed. Given
that y0 = 730m and y=0 at t=5.00s,
to find v : y−yo =(v sinθo)t− 1/2gt^2 ⇒0.730m=v
sin(−37.0 degree )(5.00s)− 1/2(9.80m/s^2 )(5.00s) ^2
which yields v =202m/s.
the speed of the plane = 202m/s
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A child boards a bus for summer camp. His mom is waiting next to the bus. The bus begins
moving 3 m/s east with respect to the ground. The child is walking 0.5 m/s west towards the back
of the bus with respect to the bus. The mother begins running 1 m/s east with respect to the
ground, chasing after the bus and thoroughly humiliating her child. What is the child's velocity
a) relative to the ground?
b) relative to the mother?
Answer:
a) relative to the ground
Explanation:
