8) If the volume of the liquid in graduated cylinder B is 90 mL, then whatis the volume of the rock?AYour answer8060B100180

Answer:

a.  

[tex]horizontal=39.9[/tex] m/s

[tex]vertical=30.1[/tex] m/s

b.

[tex]t=5.009[/tex]

c.

[tex]y=27.7[/tex]

Explanation:

Lets write down what we were given.

Angle = 37°

Initial Velocity = 50 m/s

Displacement in x direction = 200 m

Take note:

I am having some trouble with the theta symbol so let theta = [tex]N[/tex]

Lets do question C first.

We know that time is equal to  [tex]\frac{displacement}{velocity}[/tex]     aka [tex]t=\frac{x}{v}[/tex].

[tex]x=v[/tex]₀ₓ [tex]t[/tex]   ⇒  [tex]\frac{x}{v_{0x} }[/tex]   ⇒     [tex]\frac{x}{v_{0} *cos(N)}[/tex]

Now substitute the expression for t into the equation for the position.

[tex]y=(v_{0}sin(N))*(\frac{x}{v_{0}cos(N) })-\frac{1}{2}g(\frac{x}{v_{0}cos(N) }) ^{2}[/tex]

Rearranging terms, we have

[tex]y=(tan(N)*x)-[\frac{g}{2(v_{0}cos(N))^{2} } ]x^{2}[/tex]

Now lets substitute our numbers in for the variables. Then simplify.

[tex]y=(tan37*200)-[\frac{9.81}{2(50*cos37)^{2} } ]200^{2}[/tex]

[tex]y=150.7108-[\frac{9.81}{2(50*cos37)^{2} } ]200^{2}[/tex]

[tex]y=150.7108-[0.0030761]200^{2}[/tex]

[tex]y=150.7108-(0.0030761*40000)[/tex]

[tex]y=150.7108-123.0444[/tex]

[tex]y=27.7[/tex]

Now lets do question B.

Lets steal this from the last question.

We know that time is equal to  [tex]\frac{displacement}{velocity}[/tex]     aka [tex]t=\frac{x}{v}[/tex].

[tex]x=v[/tex]₀ₓ [tex]t[/tex]   ⇒  [tex]\frac{x}{v_{0x} }[/tex]   ⇒     [tex]\frac{x}{v_{0} *cos(N)}[/tex]

Now substitute the expression for t into the equation for the position.

[tex]y=(v_{0}sin(N))*(\frac{x}{v_{0}cos(N) })-\frac{1}{2}g(\frac{x}{v_{0}cos(N) }) ^{2}[/tex]

We can substitute [tex]t[/tex] for [tex]\frac{x}{v_{0}cos(N) }[/tex]

[tex]y=(v_{0}sin(N))*(t)-\frac{1}{2}g(t) ^{2}[/tex]

We can rewrite the equation as

[tex](v_{0}sin(N)(t)-\frac{1}{2}*(g(t)^{2})=y[/tex]

Now lets substitute our numbers in for the variables.

[tex](50sin(37)(t)-\frac{1}{2}*(9.81(t)^{2})=27.7[/tex]

After some painful algebra and factoring we get

[tex]30.09075115t-4.905t^{2}=27.6664[/tex]

Subtract [tex]27.6664[/tex] from both sides.

[tex]30.09075115t-4.905t^{2}-27.6664=0[/tex]

Use the quadratic formula to find the solutions.

[tex]\frac{-b+-\sqrt{b^{2}-4ac } }{2a}[/tex]

After some more painful algebra we get

[tex]t=5.00854263, 1.12616708[/tex]

1.126 does not make any sense so.

[tex]t=5.009[/tex]

Finally lets do question A.

Lets draw a triangle. We have the velocity which is the hypotenuse and we have the angle. From there we can solve for the opposite and adjacent sides.

Let [tex]A=horizontal[/tex]  and [tex]O=vertical[/tex]

[tex]cos(37)=\frac{A}{50}[/tex]

[tex]A=39.9[/tex]

[tex]sin37=\frac{O}{50}[/tex]

[tex]O=30.1[/tex]

Answer:

Explanation:

Given:

X(t) = 3 - 2*t + 3*t²

t = 3 s

_______________

V(t) - ?

a(t) - ?

Speed is the first derivative of the coordinate, acceleration is the second.

1)

V(t) = X' =  (3 - 2*t + 3*t²)' = 0 - 2 +6*t = 6*t - 2

V(3) =  6*3 - 2 = 16 m/s

2)

a(t) = X'' = V' = (6*t - 2)' = 6 m/s²

a(3) = 6 m/s²

3)

The body will stop (V = 0 ) in (t) seconds:

V(t) = 6*t - 2

0 = 6*t - 2

6*t = 2

t = 2/6 = 1/3 ≈ 0,33 s

If you push a 2.1 kg object on a table with 42N of force. The box then slowly skids to a stop over 2.2 meters, then the force of the friction would be 42 Newtons as per the concept of limiting friction.

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.

As given in the problem if push a 2.1 kg object on a table with 42N of force. The box then slowly skids to a stop over 2.2 m, then we have to find the force of the friction.

The force of the friction = The limiting friction force  

If you apply 42N of force to a 2.1-kilogram item on a table. According to the theory of limiting friction, when the box gently slides to a halt over a distance of 2.2 meters, the force of friction would be 42 Newtons.

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Work does Scott do to push a 74 kg sofa 2.1 m across the floor at a constant speed. The coefficient of kinetic friction between the sofa and the floor is 0.23 is 349 Nm.

given that :

mass = 74 kg

distance d = 2.1 m

coefficient of kinetic friction , μk  = 0.23

work done is given as :

w = fd

f = μk m g

f = 0.23 × 74 × 9.8

f = 166 N

therefore ,

work = fd

w = 168 × 2.1

w = 349 Nm

Work does Scott do to push a 74 kg sofa 2.1 m across the floor at a constant speed. The coefficient of kinetic friction between the sofa and the floor is 0.23 is 349 Nm.

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In order to determine the depth in the ocean, use the following equation:

h: depth

P: pressure = 3*Po

Po: atmospheric pressure = 1.013*10^5Pa

g: gravitational acceleration constant = 9.8m/s^2

p: density of water = 1025 kg/m^3

Replace the previoua values into the formula for h and simplify:

Hence, the depth in the ocean is approximately 20.17m

0.We are asked to determine the location of an image formed by an 7.75mm tall object that is located a distance of 17.5 cm from a convex mirror.

First, we will calculate the focal length using the following formula:

Where:

Substituting the values we get:

Solving the operations:

Now, we use the following formula:

Where:

Now, we substitute the known values:

Now, we solve for the distance of the image. First, we subtract 1/17.5 from both sides:

Solving the operation:

Now, we invert both sides:

Therefore. the location of the image is -3.7 centimeters.

The other parts are solved using the same procedure.

Part B. To calculate the size of the image we will use the following relationship:

Where:

Substituting we get:

Solving the operations on the right side:

Now, we multiply both sides by 7.75:

Solving the operations:

Therefore, the height of the iamge is 1.64 mm.

An object of mass m moves a circular path with a constant speed v. The centripetal force of the object is F. If the object's speed were halved in the mass was tripled, then the centripetal force would be 0.75 times the original centripetal force.

It is defined as motion when the object is moving in a circle with a constant speed and its velocity is changing with every moment because of the change of direction but the speed of the object is constant in a uniform circular motion.

A mass m object travels in a circle at a constant speed v. The object's centripetal force is F. The centripetal force would be 0.75 times greater if the object's mass were tripled and its speed was cut in half.

Centripetal force = m × v²/r

                            =3m × (0.5v)² / r

                            = 0.75 mv² / r

Thus, the centripetal force would become 0.75 times the original centripetal force.

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We are given a reflecting wave on a string. This can be exemplified in the following diagram:

Given:

The amplitude of the magnetic field of the electromagnetic wave is,

To find:

The amplitude of the electric field

Explanation:

Let, the amplitude of the electric field is

As we know,

Substituting the values we get,

Hence, the amplitude of the electric field is,

Explanation:

The third law of Newton says that when an object exerts a force on a second object, the first object experiences an equal and opposite force that is exerted by the second object.

So, the example that shows this law is:

C. A cannon recoils backward when it is fired.

Because the cannon e

The velocity when the pumpkin strikes the ground if it takes 3.2 seconds for it to fall: 50.78 m/s

From the definition of velocity, we can find the velocity of a falling object is:

v = v₀ + gt

Here

v₀ - 19.4 m/s , t - 3.2  seconds , g - 9.80665 m/[tex]s^2\\[/tex]

v = 19.4 + (9.86 x 3.2)

v = 50.78 m/s

Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the fastest when their motion is in the other direction. The concept of velocity is useful in these circumstances. Learn about the definition of velocity in this article as well as the distinction between speed and velocity.

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Power = 40 W

Option D

The workdone by the Hunter = 800 Joules

The weight of the couch = 500 N

Time, t = 20 seconds

Power = Workdone/Time

Power = 800/20

Power = 40 W

By equating the two forces, acceleration due to gravity g is obtained which is independent of mass

The law state that the rate of change of momentum is directly proportional to the force applied.

From Newton’s Second Law, Force F = mg. And from Newton’s Law of Universal Gravitation, Force F = GMm/r²

Where m is the mass of the satellite or the body revolving round the earth.

Equate the two forces.

mg = GMm/r²

The two m cancelled out leaving

g = GM/r²

Where

Therefore, since the mass of the satellite m has cancelled out, acceleration due to gravity g is independent of mass.

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To make the E-field at the origin become 0, we need to find the E-field at the origin before

E = kq/r^2

E1 = 12934 V/m

E2 = 12303.69 V/m

Etotal = 17851.34 V/m

17851.34 = kq/r^2

r = 8.6526 cm

ANSWER:

(a)

Potential energy = 75460 J

Kinetic energy = 38500 J

Total energy = 113960 J

(b)

The site can be used to start a colony.

STEP-BY-STEP EXPLANATION:

Given:

Mass (m) = 770 kg

Velocity (v) = 10m/s

Height (h) = 10 m

(a)

We calculate in each case the kinetic and potential energy by means of their formulas

The total energy is the sum of both calculated energies:

(b)

Since the tsunami energy is less than the energy that can destroy the colony, then the site can support a permanent colony.

Given,

The current drawn by the contact lens heating unit, I=0.05 A

The supply voltage, V=197 V

The electric power is given by the product of the current drawn and the supply voltage.

Thus the power used by the given device is given by,

On substituting the known values,

Thus the power used by the contact lens heating unit is 9.85 W

For a sine or cosine function of the form:

the perfiod is given by:

In this case we have that:

Then we have:

Therefore, the period is 10 ms

The kinematic equation which relates velocity and time is

As when the acceleratio

Answer:

have you heard of quizlet

Explanation:

they are very helpful to these things

Let's use the formula for electric current.

Where V is the power supply 120 V, and R is the resistance. Let's find the current in each bulb.

To find the net resistance, we use the following formula.

Let's use the given magnitudes.

Given that,

Modulus of vector A=4.00

The angle made by the vector A with the y axis, θ₁=33.0°

The modulus of vector B=3.20 m

The angle made by the vector B with the x-axis is θ₂=40.0+90.0=130°

The modulus of the vector C=2.70 m

The angle made by the vector C with x-axis θ₃=-90°

The x and y components of the vector can be written as

Where r is the magnitude (or modulus) of the vector and θ is the angle made by the vector.

Or a vector, in cartesian coordinates, can be written as,

Therefore, vector A is cartesian coordinates is

And the vector B is

And vector C is given by,

The given equation is

Let this represents a vector V

On substituting the known values,

(a) This is the representation with the unit vectors, where i and j are the unit vectors along the x-axis and y-axis respectively.

b) The modulus of any vector is the square root of the sum of the squares of its components.

That is, the magnitude of the vector V is

The angle of this vector with the x-axis is given by

The negative sign indicates that the vector is below the positive x-axis

Therefore the modulus of the resultant of the above equation is 8.90 m and its angle with the positive x-axis is -10.36°

At least part of the applied force must be in the same direction as the movement of the object must be met in order for work to be done.

Therefore, the correct answer is option C. At least part of the applied force must be in the same direction as the movement of the object.

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Answer:

2.75 watts

Explanation:

The power is equal to the work divided by time, so

P = W/t

Then, replacing W = 55 J and t = 20 sec, we get:

P = 55 J / 20 s = 2.75 Watts

Therefore, the power created is 2.75 watts

The amount of work done is 735J.

We all know that the potential energy U is equal to the work we must do against the force for moving an object from the reference point to the exact position.  

The work done is equal to the potential energy through the work energy theorem.

     W = mgh

here,

m = mass

g = gravitational acceleration

h = height

W = work done

   On solving the above equation

W = 25x9.8x3

W = 75x9.8

W = 735 J

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Given data

*The given moment of inertia is I = 3.45 kg.m^2

*The given braking torque is T = -9.40 N.m

*The angular distance traveled is

*The final angular speed is

The angular acceleration of the flywheel is calculated by using the torque and moment of inertia relation as

The formula for the initial angular speed of the flywheel is given by the rotational equation of motion as

Substitute the known values in the above expression as

Hence, the initial angular speed of the flywheel is 5.88 rad/s

The potential energy between two charges can be written as:

In our case, it'll be equal to:

Then, our answer is PE=9.045nJ

800 Newtons

Explanation

The average force is the force exerted by a body moving at a defined rate of speed (velocity) for a defined period of time.

the average force is given by:

and

Step 1

a) Let

now, replace

the negative sign indicates the force is in the opposite way ( the force is exerted by the nail to the hammer), so the force is opposite to the direction of the movement

so, the answer is

800 Newtons

I hope this helps you

Answer:

The two forces equal in magnitude but acting opposite in direction on a body are called balanced forces

Explanation:

Answer:

Ocean Liner because its mass is 5000 times more and the bullet's velocity squared is only 1600 times more. This means that the kinetic energy of the ocean liner will be roughly 3 times greater.

Explanation:

The kinetic energy of an object is dependent on mass and velocity.

E = ( 1 / 2 )mv²;

Energy is measured in Joules which is equal to kilogram metres squared per second squared.

1J = ( kg )( m² )( s⁻² ) or 1J = ( kg )( m² ) / ( s² )

We can substitute the mass and velocity directly into the equation because the question gives the values in metres and kilograms.

BULLET:

E = ( 1 / 2 )( 0.0014kg )( 397m / s )²;

E = ( 0.0007kg )( 157609m² )( s⁻² );

E = 110.3263kgm²s⁻²;

E = 110.3263J;

I will just skip some steps because you get the idea.

OCEAN LINER:

E = ( 1 / 2 )( 5.9107kg )( 13m / s )²;

E = 499.45415J;

Answer:

Explanation:

they both involve nuclear reactions that produce energy, but the application are not the same