Marble Events
there are 5 + 3 = 8 marbles
If one marble is selected then there are now
8 - 1 = 7 marbles
Then answer is
The two events are Dependent
Event B is dependent on Event A
Let a represent the row number in this pattern. Write a rule that tells you the number of dots, d, in row n (Hint: Your rule should begin with "d=") Row 1 Row 2 Row 3 Row 4
The rule to show the number of dots in the pattern is
d = 2aWhat is a pattern?A pattern is a repetition of items, when the repetition is in ordered then the pattern can be forecasted.
The given pattern is ordered by the rule at which it was formed. The rule helps to forecast the number of dots in the next row
How to get the rules of the patternThe information given in the question include:
Let a represent the row number in this patternA picture image shoeing the rows and dotsYour rule should begin with "d="row 1 = 2 dots
row 2 = 4 dots
row 3 = 6 dots
it can be seen that
2 * number of rows = number of dots
Hence:
d = 2 * a
d = 2a
checking the rule for the 4th row
d = 2 * 4
d = 8
counting the dots confirms the rule is okay
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Angel Corporation produces calculators selling for $25.99. Its unit cost is $18.95. Assuming a fixed cost of $80,960, what is the breakeven point in units?
The breakeven point of Angel Corporation equals to 11,500 units.
How do we get the breakeven point?Given that the unit price is $25.99, so if they sell a x units, then, the revenue is: R(x) = $25.99*x
Given that the cost per unit is $18.95, plus a fixed cost of $80,960, then, the cost of x units is: C(x) = $80,960 + $18.95*x
Now, the breakeven point is a value of x such that the cost is equal to the revenue, so we need to solve:
$25.99*x = $80,960 + $18.95*x
$25.99*x - $18.95*x = $80,960
$7.04*x = $80,960
x = $80,960/$7.04
x = 11,500 units
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Brianna's teacher asks her if these two expressions 3x + 5 and 4x are equivalent.Brianna says the expressions are equivalent because the value of each expression is 20 when x = 5.Is Brianna correct synlainthink ASAP please
Step 1
Given data
Expression 1 = 3x + 5
Expression 2 =
please help this is very difficult
Answer:
x=-6. y=6. xy=-36
x=-2. y=-3. xy=6
x=1. y=2. xy=2
(−1/2x+7/10)−(−3/4x−1/5)
The expression (−1/2x + 7/10) − (−3/4x − 1/5) has a value of 1/4x + 9/10 when simplified
How to evaluate the expression?From the question, the expression is given as
(−1/2x+7/10)−(−3/4x−1/5)
Rewrite the expression properly to make it legible
So, we have
(−1/2x + 7/10) − (−3/4x − 1/5)
Expression the above parameter as an equation
This is represented as
(−1/2x + 7/10) − (−3/4x − 1/5) = (−1/2x + 7/10) − (−3/4x − 1/5)
Open the brackets
So, we have the following equation
(−1/2x + 7/10) − (−3/4x − 1/5) = −1/2x + 7/10 + 3/4x + 1/5
Collect the like terms in the equation
(−1/2x + 7/10) − (−3/4x − 1/5) = 3/4x − 1/2x + 7/10 + 1/5
Evaluate
(−1/2x + 7/10) − (−3/4x − 1/5) = 1/4x + 9/10
The expression cannot be further simplified
Hence, the solution to the expression (−1/2x + 7/10) − (−3/4x − 1/5) is 1/4x + 9/10
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The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is %180. Answer the questions below and show all work.1. What is the common difference for the deposits made each month?2. Write an explicit formula for this arithmetic sequence. 3. What is the amount of Ginny's deposit in the 12th month?4. At what month will Ginny first make a deposit that is at least $500?
SOLUTION
The deposits Ginny makes at her bank each month form an arithmetic sequence. The deposit for month 3 is $150, and the deposit for month 5 is $ 180.
Since it follows an arithmetic sequence, T n = a + ( n- 1 ) d
Month 3 , T 3 = a+ ( 3 - 1 ) d = 150
a + 2 d = 150 --------------------- equ 1
Month 5 , T 5 = a + ( 5 - 1 ) d = 180
a + 4 d = 180 ...........................equ 2
Solving the two equations, we have :
a - a + 4 d - 2 d = 180 - 150
2 d = 30
Divide both sides by 2 , we have:
d = 15
Let us put d = 15 in equ 1 , we have a + 2 d = 150
a + 2 ( 15 ) = 150
a + 30 = 150
a = 150 - 30
a = 120
From the solution,
Month 1 = 120
Month 2 = 120 + 15 = 135
Month 3 = 135 + 15 = 150
Month 4 = 150 + 15 = 165
Month 5 = 165 + 15 = 180
1. What is the common difference for the deposits made each month? d = 15
2. Write an explicit formula for this arithmetic sequence.
Recall that Tn = a + ( n - 1 ) d
Tn = 120 + ( n - 1 ) 15
Tn = 120 + 15 n - 15
Tn = 120 - 15 + 5n
Tn = 105 + 15n
3. What is the amount of Ginny's deposit in the 12th month?
Tn = 105 + 15n
T 12 = 105 + 15 ( 12 )
T 12 = 105 + 180 = 285
4. At what month will Ginny first make a deposit that is at least $500?
Using Tn = 105 + 15 n = 500
105 + 15 n = 500
15 n = 500 - 105
15 n = 395
Divide both sides by 15 , we have :
n = 26 . 33
n = 27
find the midpoint of PQ. P(6,4) and Q(4,3)
the midpoint between two points has the following formula
[tex](\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]replace in the formula using P as point 1 and Q as point 2
[tex]\begin{gathered} (\frac{6+4}{2},\frac{4+3}{2}) \\ (\frac{10}{2},\frac{7}{2}) \\ (5,\frac{7}{2}) \\ (5,3.5) \end{gathered}[/tex]A bridge AB is to be built across a river. The point C is located 62m from B, and angle A is 80 degrees, angle C is 60 degrees. How long is the bridge
The points A, B, and C form a triangle.
From the given information in the question, the triangle ABC can be drawn to have the following parameters:
Recall the Sine Rule. Applied to the triangle above, the rule is stated as follows:
[tex]\frac{BC}{\sin A}=\frac{AC}{\sin B}=\frac{AB}{\sin C}[/tex]The length of the bridge is AB. Given that the measures of angles A and C, and side BC are known, the following ratio is used to solve:
[tex]\frac{BC}{\sin A}=\frac{AB}{\sin C}[/tex]Substituting known values, the length of AB is calculated as follows:
[tex]\begin{gathered} \frac{62}{\sin80}=\frac{AB}{\sin60} \\ AB=\frac{62\times\sin60}{\sin80} \\ AB=54.52 \end{gathered}[/tex]The bridge is 54.52 m long.
Function Notation - TransformationIll send a picture of the question
Given the vertices of the original quadilateral:
(3, 4), (5, 6), (7, 4), and (5, 3)
Vertices of the transformed quadilateral:
(-5, -6), (-3, -4), (-1, -6), and (-3, -7)
Let's describe the transformation rule used for this transformation.
To find the transformation rule, let's find the number of movements in the x-direction and y-direction that would map the original quadilateral to the transformed quadilateral by subtracting the x and y coordinates of the coresponding sides.
We have:
(x, y) ==> (-5 -3, -6 -4) ==> (-8, -10)
(x, y) ==> (-3 -5, -4, -6) ==> (-8, -10)
(x, y) ==> (-1 -7, -6 -4) ==> (-8, -10)
(x, y) ==> (-3 -5, -7 -3) ==> (-8, -10)
For all corresponding sides, we have: (x, y) ==> (-8, -10)
This means there was a shift 8 units to the left, and 10 units downwards.
Therefore, the rule for the transformation shown here is:
(x, y) ==> (x - 8, y - 10)
ANSWER:
B. f(x, y) = (x - 8, x- 10)
Order the following from least to greatest: 0.232, 1.2, 1.09, 0, 3, 0.9
Answer:
0, 0.232 , 0.9 , 1.09, 1.2 , 3
Estimate the time it would take you to drive 278 miles at38 miles per hour. Round to the nearest hour
Speed formula:
[tex]s=\frac{d}{t}[/tex]d is the distance
t is the time
As you need to find a time having the distance and speed, solve the equation above for t:
[tex]\begin{gathered} t\cdot s=d \\ t=\frac{d}{s} \end{gathered}[/tex]Use the given data to find the time:
[tex]\begin{gathered} t=\frac{278mi}{38mi/h} \\ \\ t=7.31h \\ \\ t=7h \end{gathered}[/tex]Then, it would take you 7 hours to drive 278 mi at 38mi/hDetermine whether a tangent line is shown in this figure
Given:
Required:
To determine whether a tangent line is shown in the given figure.
Explanation:
By the definition of tangent line, we know that tangent line is a straight line that touches the circle at one point.
Now consider the given figure, there is a tangent line in the given figure.
Final Answer:
Yes.
Write the complex number in polar form with argument theta between 0 and 2 pie
The answer in polar form:
[tex]=\text{ 7}\sqrt[]{2}\lbrack cos(tan^{-1}(-1)\text{ + isin}(tan^{-1}(-1)\text{ \rbrack}[/tex]The length of the diagonal of a Rectangle is 14cm,and it forms a 30 degree angle in one corner of the rectangle.What is the area of the rectangle.(A=LxW)Just number 20
Explanation
Step 1
draw the rectangle
here we have a rigth triangle,then
Let
[tex]\begin{gathered} hypotenuse=14 \\ agle=30\text{ \degree} \\ \text{adjacent side= length= l} \end{gathered}[/tex]so, we need a function that relates those values
[tex]\cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}[/tex]replace and solve for length
[tex]\begin{gathered} \cos \Theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\cos \Theta=adjacent\text{ side} \\ 14\text{ cm }\cdot\cos 30=l \\ 12.12435\text{ cm=l} \end{gathered}[/tex]Step 2
width
similarity, we need a function that relates
[tex]\sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}}[/tex]let
[tex]\text{opposite side= width=w}[/tex]replace and solve for w
[tex]\begin{gathered} \sin \text{ }\Theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{hypotenuse}\cdot\sin \Theta=opposite\text{ side} \\ 14\text{ cm }\cdot\sin \text{ 30=w} \\ 7cm=w \end{gathered}[/tex]Step 3
finally, the area of a rectangle is given by
[tex]\begin{gathered} \text{Area}=\text{ length }\cdot width \\ \text{replacing} \\ \text{Area}=(12.12\cdot7)(cm^2) \\ \text{Area}=84.87(cm^2) \end{gathered}[/tex]therefore, the answer is
[tex]\text{Area}=84.87(cm^2)[/tex]I hope this helps you
The total movie attendance in a country was 1.16 billion people in 1990 and 1.40 billion in 2008. Assume that the pattern in movie attendance is linear function of time. (Need to answer questions a-d for this question - pic attached)
a)
In order to find a function M(t), first let's identify two ordered pairs that are solutions to the equation.
From the given information, we have the ordered pairs (1990, 1.16) and (2008, 1.4).
Using these ordered pairs, let's find the slope-intercept form of a linear equation (y = mx + b)
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{1.4-1.16}{2008-1990}=\frac{0.24}{18}=0.01333 \\ \\ y=mx+b \\ 1.16=1990\cdot0.01333+b \\ b=-25.3667 \\ \\ y=0.01333x-25.3667 \end{gathered}[/tex]So the equation is M = 0.01333t - 25.3667
The independent variable represents the year (correct option: first one)
b)
The slope represents the change in M over the change in t, that is, it represents the change in attendance over a year (correct option: first one)
c)
For t = 2015, we have:
[tex]\begin{gathered} M=0.01333\cdot2015-25.3667 \\ M=26.86-25.37 \\ M=1.49 \end{gathered}[/tex]d)
For M = 1.5, we have:
[tex]\begin{gathered} 1.5=0.01333\cdot t-25.3667 \\ 0.01333t=26.8667 \\ t=2015.5 \end{gathered}[/tex]The figure below is a trapezoid:10011050mZ1 =m2 =mZ3=Blank 1:Blank 2:Blank 3:
STEP 1: Identify and Set Up
We have a trapezoid divided by a straight line that divides it assymetrically. We know from the all too famous geometric rule that adjacent angles in a trapezoid are supplementary. Mathematically, we can express thus:
[tex]100^o+<2+<3^{}=180^o=50^o+110^o+<1[/tex]Hence, from this relation, we can find our unknown angles.
STEP 2: Execute
For <1
[tex]\begin{gathered} 180^o=50^o+110^o+<1 \\ 180^o=160^o+<1 \\ \text{Subtracting 160}^o\text{ from both sides gives} \\ <1=180-120=60^o \end{gathered}[/tex]<1 = 60 degrees
For <2 & <3
We know from basic geometry that a transversal across two parallel lines gives a pair of alternate angles and as such, <1 = <3 = 60 degrees
We employ our first equation to solve for <2 as seen below:
[tex]\begin{gathered} 100^o+<2+<3^{}=180^o \\ 100^o+<2+60^o=180^o \\ 160^o+<2=180^o \\ \text{Subtracting 160}^{o\text{ }}\text{ from both sides gives:} \\ <2=180-160=20^o \end{gathered}[/tex]Therefore, <1 = <3 = 60 degrees and <2 = 20
Admission to a state fair is $10, and each ride ticket costs $2.50. Write an en
EXPLANATION
Let's call t to the number of tickets and c to the total cost, the appropiate relationship would be:
c = 2.5t + 10
The variable in the expression represents the number of tickets.
Find the cosine of angle R. Reduce the answer to the lowest terms.
Cosine formula
[tex]\cos (angle)=\frac{\text{ adjacent side}}{\text{ hypotenuse}}[/tex]Considering angle R, the adjacent side has a length of 9 units, and the hypotenuse of the triangle has a length of 15 units. Substituting this information into the above formula:
[tex]\cos (m\angle R)=\frac{9}{15}=\frac{\frac{9}{3}}{\frac{15}{3}}=\frac{3}{5}[/tex]copy and complete each problem
/20 = 11/55
Answer:
[tex]\frac{4}{20}[/tex] = [tex]\frac{11}{55}[/tex]
Step-by-step explanation:
[tex]\frac{x}{20}[/tex] = [tex]\frac{11}{55}[/tex] cross multiply and solve for x
55x = 11(22)
55x = 220 Divide both sides by 55
x = 4
Which graph represents an exponential function
This is algebra two graphing exponential functions
Answer: The Curved Line on Top
Step-by-step explanation: A positive-valued function of a real variable. So the top one
Just learned about this in Algebra 1 about 4 days ago.
Solve the compound inequality. Graph the solution-7 *x+3<4-The solutions are(Type an inequality or a compound inequality. Sim
Answer:
[tex]-10\leqslant x<1[/tex]Explanation:
To solve compound inequalities, we do the same as in an equation or inequality: we need to do the same operation in all places.
We want to solve for x:
[tex]-7\leqslant x+3<4[/tex][tex]-7-3\leqslant x+3-3<4-3[/tex][tex]-10\leqslant x<1[/tex]And that's the answer
Correctz is jointly proportional to x and y. If z = 115 when x = 8 and y = 3, find z when x = 5 and y = 2. (Round off your answer to the nearest hundredth.)
When we have a number that is jointly proportional to two other numebrs, the formula is:
[tex]a=kcb[/tex]This means "a is jointly proportional to c and b with a factor of k"
Then, we need to find the factor k.
In this case z is jointly proportional to x² and y³
This is:
[tex]z=kx^2y^3[/tex]Then, we know that z = 115 when x = 8 and y = 3. We can write:
[tex]115=k\cdot8^2\cdot3^3[/tex]And solve:
[tex]\begin{gathered} 115=k\cdot64\cdot27 \\ 115=k\cdot1728 \\ k=\frac{115}{1728} \end{gathered}[/tex]NOw we can use k to find the value of z when x = 5 and y = 2
[tex]z=\frac{115}{1728}\cdot5^2\cdot2^3=\frac{115}{1728}\cdot25\cdot8=\frac{2875}{216}\approx13.31[/tex]To the nearest hundreth, the value of z when x = 5 and y = 2 is 13.31
Show that (3 * 8 * x)⁷ = 6⁷ * 4⁷ * x⁷
Answer:
Q.E.D.
Explanation:
Given the expression
[tex](3\times8\times x)^7[/tex]We want to show that it is equal to the right-hand side.
Now, we note that: 8 = 2 x 4
Substituting 8 = 2 x 4, we have:
[tex]=(3\times2\times4\times x)^7[/tex]We then go further to get:
[tex]=(6\times4\times x)^7[/tex]Distributing the exponent, we have:
[tex]=6^7\times4^7\times x^7[/tex]This is the given right-hand side of the equation as required.
16 1 point
Triangle congruence SSS is being shown?
True
False
|||
+||
Answer:
True
Step-by-step explanation:
SSS is being shown because the two sides are known by congruence marks, and the third side is known because it is equal--the two triangles are sharing it.
for each of the following polynomial functions, write the equation of a different polynomial function that has the same key characteristic. explain your thinking.
SOLUTION
Given the question in the image, the following are the solution steps to answer the question.
STEP 1: Draw the given graph.
STEP 2: Get the function plotted on the graph.
[tex]undefined[/tex]J(-6-2)3-*NWMark this and return2--9-8-7-6-5-4-3-2-3₁ 1 2 3 4 5 61-5737-2-cd-6--7--8-2 do-9--10--11--12--13-8 9 10 11 xK(8,-9)What is the x-coordinate of the point that divides thedirected line segment from J to K into a ratio of 2:5?X == (m²²7 m )(x₂ − ×₁) + X₁m+n0 000-22Save and ExitNextSubmit
Use the given formula:
[tex]x=(\frac{m}{m+n})(x_2-x_1)+x_1[/tex]Being m: 2 and n: 5
x1: -6
x2: 8
[tex]\begin{gathered} x=(\frac{2}{2+5})(8-(-6))+(-6) \\ \\ x=\frac{2}{7}*(14)-6 \\ \\ x=4-6 \\ \\ x=-2 \end{gathered}[/tex]Then, the x-coordinate of th point that divides the directed line segment from J to K into a ratio 2:5 is -2Answer: -2Based on the two data sets represented below, complete the following sentences.Options: "greater" or "less"
We can check that the median of the dataset T is 14, and its mean is also close to 14, while the median of the dataset U is 17 and its mean is close also close to 17. We can also check that the range of the dataset T is 14 and the data is more concentrated at its center, while the range of the dataset U is 20 and the data is more dispersed.
Therefore, we can state that The center of Data Set T is less than the center of Data Set U, and the spread of Data Set T is less than the spread of Data Set U.
0 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 10401234 5 6 7 8 9 10OB.C.OD. +Reset Selection
Okay, here we have this:
Considering the provided inequation, we are going to identify how can be represented on a number line, so we obtain the following:
So the first thing we will do is factor to find the solution intervals, we have:
[tex]\begin{gathered} 3x^2-27x\leq0 \\ x(x-9)\leq0 \\ 0\leq x\leq9 \end{gathered}[/tex]According to this, we finally obtain that the solution interval is option D, because it satisfies the found interval and its endpoints are closed.
question In photograph
The equation that represents the relationship between x and y in the table is (L.) y = -5x + 3.
What is an Equation in Math?In mathematics, an equation is a relationship between two expressions that are expressed as equality on each side of the equal to sign.
Given in the table is the relationship between x and y respectively.
Substitute the values of x in the respective equations to find the value of y, the resulting value which matches the value of y in the table determines the correct equation.
J. y = -5x -27
⇒ For x = -3, y = -5(-3) - 27 = 15 -27 = -12 ≠ 18
K. y = -5x + 18
⇒ For x = -3, y = -5(-3) + 18 = 15 + 18 = 33 ≠ 18
L. y = -5x + 3
⇒ For x = -3, y = -5(-3) + 3 = 15 + 3 = 18 ≈ 18
For x = -1, y = -5(-1) + 3 = 5 + 3 = 8
For x = 2, y = -5(2) + 3 = -10 + 3 = -7
For x = 6, y = -5(6) + 3 = -30 + 3 = -27
All the values of x and y in the table satisfy the equation y = -5x + 3. Hence this is the required equation that represents the relationship.
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Plot Points & Graph Function (Table Given)
We have the next function
[tex]y=-\sqrt[]{x}+3[/tex]We need to calculate some points
x y
0 3
1 2
4 1
9 0
Let's plot the points and then we connect them in order to obtain the graph
