SOLUTION
Given the question, the following are the solution steps to answer the question.
STEP 1: Write the formula for probability
[tex]Probability=\frac{number\text{ of required outcomes}}{number\text{ of total possible outcomes}}[/tex]STEP 2: Write the outcomes of the events
[tex]\begin{gathered} number\text{ of red marbles}\Rightarrow n(red)\Rightarrow8 \\ number\text{ of blue marbles}\Rightarrow n(blue)\Rightarrow7 \\ number\text{ of green marbles}\Rightarrow n(green)\Rightarrow6 \\ number\text{ of total marbles}\Rightarrow n(total)\Rightarrow21 \end{gathered}[/tex]STEP 3: Write the formula for getting the probability that all three marbles drawn will be red
[tex]Pr(Red\text{ and Red and Red\rparen}\Rightarrow Pr(red)\times Pr(red)\times Pr(red)[/tex]STEP 4: Calculate the probability
[tex]\begin{gathered} Pr(all\text{ three are reds\rparen}\Rightarrow\frac{8}{21}\times\frac{7}{20}\times\frac{6}{19} \\ =\frac{336}{7980}=0.042105263 \\ To\text{ percentage will be to multiply by 100} \\ 4.210526316\% \\ To\text{ the nearest tenth will be:} \\ \approx4.2\% \end{gathered}[/tex]Hence, the probability, to the nearest 10th of a percent, that all three marbles drawn will be red is 4.2%
Write the first 4 terms of the sequence defined by the given rule. f(n)=n^3-1
Point S is on line segment \overline{RT} RT . Given RT=3x,RT=3x, RS=3x-5,RS=3x−5, and ST=3x-1,ST=3x−1, determine the numerical length of \overline{RT}. RT .
The numerical length of the line segment RT is 6.
Length:
Length is the measuring unit used to identifying the size of an object or distance from one point to the other.
Given,
There is a point on the line segment RT.
And the values of the pots are,
RT = 3x, RS = 3x - 5 and ST = 3x - 1.
Now we need to find the length of the line segment RT.
To find the line of the line segment RT,
We have to add the length of the segments,
That can be written as,
=> RT = RS + ST
Now, we have to apply the values of the point to the equation, then we get,
=> 3x = 3x - 5 + 3x - 1
=> 3x = 6x - 6
=> 6x - 3x - 6
=> 3x - 6
=> 3x = 6
=> x = 2
If the value of x is 2, then the length of the line segment RT is,
RT = 3x => 3 x 2 = 6
Therefore, the length of the line segment RT is 6.
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theres 2 fill in the blank boxes and 3 drop down menus, below i will list the options in the drop down menus.box 1 - apply quotient identities, apply Pythagorean identities, apply double-number identities, apply even-odd identities.box 2 - apply cofunction identities, use the definition of subtraction, apply even-odd identities, Write as one expresssion combine like terms.box 3 - apply cofunction identities, apply double-number identities, apply Pythagorean identities, apply even-odd identities.
Solution
Box 1 : Apply Quotient Identities
[tex]cotx-tanx=\frac{cosx}{sinx}-\frac{sinx}{cosx}[/tex]The answer for the first box is
[tex]\begin{equation*} \frac{cosx}{sinx}-\frac{sinx}{cosx} \end{equation*}[/tex]Box 2: Write as one expression
[tex]\begin{gathered} cotx-tanx=\frac{cosx}{s\imaginaryI nx}-\frac{s\imaginaryI nx}{cosx} \\ cotx-tanx=\frac{cosx(cosx)-sinx(sinx)}{sinxcosx} \\ cotx-tanx=\frac{cos^2x-sin^2x}{sinxcosx} \end{gathered}[/tex]The answer for the second box is
[tex]\frac{cos^{2}x-s\imaginaryI n^{2}x}{s\imaginaryI nxcosx}[/tex]Before the box 3, please note the identity
Note: Trigonometry I dentities
[tex]\begin{gathered} cos^2x-s\mathrm{i}n^2x=cos2x \\ 2sinxcosx=sin2x \end{gathered}[/tex]Box 3: Apply Double - Number Identities
[tex]\begin{gathered} cotx-tanx=\frac{cos^{2}x-s\imaginaryI n^{2}x}{s\imaginaryI nxcosx} \\ Applying\text{ the above trigonometry identities} \\ cotx-tanx=\frac{cos2x}{sinxcosx} \\ cotx-tanx=\frac{cos2x}{sinxcosx}\times\frac{2}{2} \\ cotx-tanx=\frac{2cos2x}{2sinxcosx} \\ cotx-tanx=\frac{2cos2x}{sin2x} \end{gathered}[/tex]simplify 425xy⁴/25xy²
We have the expression
[tex]\frac{425xy^4}{25xy^2}[/tex]We can already simplify x because it's both on the numerator and denominator
[tex]\frac{425y^4}{25y^2}[/tex]Now we can simplify 425/25 = 17
[tex]\frac{17y^4}{y^2}[/tex]Remember that
[tex]\frac{a^n}{a^m}=a^{n-m}[/tex]Then
[tex]17y^{4-2}=17y^2[/tex]The final result is
[tex]17y^2[/tex]If mZABD = 70°, what are mZABC and mZDBC?
mZABC=
mZDBC=
(6x+3) D
B
(9x-8)
Please help me
Answer:
Step-by-step explanation:
ABD = ABC + DBC
Eqivalent to:
78 = (5x + 3) + (5x - 5)
78 = 5x + 5x + 3 - 5
78 = 10x - 2
80 = 10x (move -2 to the left side and get 78 + 2 = 80)
8 = x (80/10 = 8)
With x = 8,
ABC = 5x - 5 = 8*5 - 5 = 40 - 5 = 35
DBC = 5x +3 = 8*5 + 3 = 40 + 3 = 43
what is the sum of -1 1/3 + 3/4
Here, we want to add two fractions
What we have to do here is to make the mixed fractin an improper one
To do this, we multiply the denominator by the standing number, and add to the numerator, then we place the value over the denominator
Thus, we have it that;
[tex]\begin{gathered} 1\frac{1}{3}\text{ = }\frac{4}{3} \\ -\frac{4}{3}+\frac{3}{4}\text{ = }\frac{-16+9}{12}=\text{ }\frac{-7}{12} \end{gathered}[/tex]When 8 is subtracted from a number and that difference is doubled, the result is 10. What is the number?
A) 6
B) 5
C) 18
D) 13
Answer:
n = 13
Step-by-step explanation:
Find the number
8 is subtracted from a number
(n-8)
that difference is doubled
2(n-8)
the result is 10
2(n-8) = 10
Solve the equation by dividing each side by 2
2(n-8)/2 = 10/2
n-8 = 5
Add 8 to each side
n-8+8 = 5+8
n = 13
Read the following scenario and write two equations we could use to solve to find for the number of cars and trucks washed. Use the variables C for cars washed and T for trucks washed. (Hint: both equations should have T and C). SCENARIO: Western's eSports Team raised money for charity by organizing a car wash. They washed a total of 80 vehicles and raised a total of $486. They charged $5 to wash a car and $7 to wash a truck.
Let:
C = Number of cars washed
T = Number of trucks washed
They washed a total of 80 vehicles, so:
[tex]C+T=80[/tex]They raised a total of $486. They charged $5 to wash a car and $7 to wash a truck. so:
[tex]5C+7T=486[/tex]Let:
[tex]\begin{gathered} C+T=80_{\text{ }}(1) \\ 5C+7T=486_{\text{ }}(2) \end{gathered}[/tex]From (1) solve for T:
[tex]T=80-C_{\text{ }}(3)[/tex]Replace (3) into (2):
[tex]\begin{gathered} 5C+7(80-C)=486 \\ 5C+560-7C=486 \\ -2C=486-560 \\ -2C=-74 \\ C=\frac{-74}{-2} \\ C=37 \end{gathered}[/tex]Replace the value of C into (3):
[tex]\begin{gathered} T=80-37 \\ T=43 \end{gathered}[/tex]They washed 37 cars and 43 trucks
Had someone explain it and I didn’t get it still
From the question:
Let f(x) = 2x² + 2x - 8
g(x) = √x - 2
We are aske to write f(g(x))
f(x) = 2x² + 2x - 8, g(x) = √x - 2
g(x) = √x - 2
= f(√x - 2)
f(√x - 2): 2x + 2√x - 2 - 12
f(g(x)) = 2x - 12 + 2√x - 2.
Graph the inequality on a plane. Shade a region below or above. Y < - 1
In order to graph the inequality on the coordinate plane, we first need to find it's border, which is delimited by the line below:
[tex]y=-1[/tex]This line is a straight line parallel to the x-axis and that passes through the y-axis at the point (0, -1). Since the original inequality has a "less" sign, we need to make this boundary line into dashes.
Now we can analyze the inequality:
[tex]y<-1[/tex]Since the signal is "<", we need to shade all the region of the coordinate plane for which y is below -1, this means that we have to paint the region below the line. The result is shown below:
please help 50 points!
Which describes a number that cannot be irrational?A. a number that represents the ratio of the circumference to the diameter of a circle B. a number that can be written as the ratio of two integers C. a number that can be used to solve an algebraic equation D. a number that represents the length of the diagnostic of a square
a number that can be written as the ratio of two integers (option B)
Explanation:Irrational number cannot be written in the fractional form
Rational numbers can be written in the form of fraction
Checking the options:
a) Circumference = πd
where d = diameter
π = Circumference/diameter
π is an irrational number
b) A number written as ratio of two intergers can be written in the form of fraction
Hence, it is rational
c) A number that we can use in solving an algebraic equation can be any real number.
From a real number, we have rational and irrational numbers. So, there is the likelihood we get an irrational number
d) side of a square = a
diagonal² = a² + a²
length of diagonal of a square = √(a² + a²) = √2a²
This can also yield either irrational or rational numbers.
A number that cannot be irrational means a number that is rational.
From the option, the only one without doubt that it is rational is a number that can be written as the ratio of two integers (option B)
In Abc,AB=5 feet and BC=3 feet.Which inequality represents all possible values for the length of AC,in feet?
The smallest value of length AC would be 5 ft - 3 ft = 2 ft while the largest length would be 5 ft + 3 ft = 8ft. The answer will be
2 < Ac < 8
The length is twice the sum of its width 3. What are the dimension of the rectangle if it’s area 216 square inches?
Assume that the width of the rectangle = x
Since the length is twice the sum of the width and 3, then
[tex]\begin{gathered} L=2(x+3) \\ L=2x+6 \end{gathered}[/tex]Since the area of the rectangle is 216 square inches, then
Multiply the length and the width, then equate the product by 216
[tex]\begin{gathered} (x)(2x+6)=216 \\ 2x^2+6x=216 \end{gathered}[/tex]Divide all terms by 2 to simplify
[tex]\begin{gathered} \frac{2x^2}{2}+\frac{6x}{2}=\frac{216}{2} \\ x^2+3x=108 \end{gathered}[/tex]Subtract 108 from both sides
[tex]\begin{gathered} x^2+3x-108=108-108 \\ x^2+3x-108=0 \end{gathered}[/tex]Now, let us factorize the trinomial into 2 factors
[tex]\begin{gathered} x^2=(x)(x) \\ -108=(-9)(12) \\ (x)(-9)+(x)(12)=-9x+12x=3x \end{gathered}[/tex]Then the factors are
[tex]x^2+3x-108=^{}(x-9)(x+12)[/tex]Equate them by 0
[tex](x-9)(x+12)=0[/tex]Equate each factor by 0, then find the values of x
[tex]x-9=0[/tex]Add 9 to both sides
[tex]\begin{gathered} x-9+9=0+9 \\ x=9 \end{gathered}[/tex][tex]x+12=0[/tex]Subtract 12 from both sides
[tex]\begin{gathered} x+12-12=0-12 \\ x=-12 \end{gathered}[/tex]Since the width can not be a negative number (no negative length)
Then the width of the rectangle = 9
Let us find the length
[tex]\begin{gathered} L=2(9)+6 \\ L=18+6 \\ L=24 \end{gathered}[/tex]Then the dimensions of the rectangle are 9 inches and 24 inches
How do you solve the system of equations by graphing? y=-3x/2 + 6y=5x - 7
The given system of equations are
y=-3x/2 + 6
y=5x - 7
We would substitute values for x into the equations and find the corresponding y values. These values would be plotted on a graph. Where the lines of both equations meet would represent the solution of the system of equations.
For the first equation,
y = - 3x/2 + 6
if x = 0, y = 3 * 0/2 + 6 = 6
If x = 1, y = - 3 * 1/2 + 6 = 4.5
if x = 2, y = - 3 * 2/2 + 6 = 3
We would plot these values on the graph
For the second equation,
y = 5x - 7
if x = 0, y = 5 * 0 - 7 = - 7
If x = 1, y = 5 * 1 - 7 = - 2
if x = 2, y = 5 * 2 - 7 = 3
We would plot these values on the graph
The diagram of the graph is shown below
Looking at the graph, at the point where both lines meet,
x = 2, y = 3
Thus, the solution is (2,3)
Describe the difference on table, graph and equation between discrete and continuous functions.
REmember that
A continuous function allows the x-values to be ANY points in the interval, including fractions, decimals, and irrational values
A discrete function allows the x-values to be only certain points in the interval, usually only integers or whole numbers.
Discrete functions have scatter plots as graphs and continuous functions have lines or curves as graphs
Which of the followingrepresents this inequality?|4x – 61 > 10
Solution:
Given the absolute inequality below:
[tex]\lvert4x-6\rvert>10[/tex]From the absolute law,
[tex]\begin{gathered} \lvert u\rvert>a \\ implies\text{ } \\ u>a\text{ } \\ or \\ u<-a \end{gathered}[/tex][tex]\begin{gathered} When\text{ 4x-6>10} \\ add\text{ 6 to both sides of the inequality,} \\ 4x-6+6>10+6 \\ \Rightarrow4x>16 \\ divide\text{ both sides by the coefficient of x, which is 4} \\ \frac{4x}{4}>\frac{16}{4} \\ \Rightarrow x>4 \end{gathered}[/tex][tex]\begin{gathered} When\text{ 4x-6<-10} \\ add\text{ 6 to both sides of the inequality,} \\ 4x-6+6<-10+6 \\ \Rightarrow4x<-4 \\ divide\text{ both sides by the coefficient of x, which is 4} \\ \frac{4x}{4}<-\frac{4}{4} \\ \Rightarrow x<-1 \end{gathered}[/tex]Plotting the solution to the inequality, we have the line graph of the inequality to be
Hence, the correct option is D.
Home Liquidators marks up its merchandise 35% on cost. What is the company’s equivalent markup on selling price?
The company’s equivalent markup on selling price is 26%.
What is markup?The markup is the gap between the selling price and the cost of a good or service. It is frequently represented as a percentage of the total cost. To cover the costs of doing business and generate a profit, a markup is added to the overall cost borne by the manufacturer of a good or service.
The following can be deduced based on the information:
Markup on cost = 35%
Cost = 100%
Selling price = 135%
Markup on selling price will be:
= (0.35/1.35 x 100)
= 26%
Therefore, the value is 26%.
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image
Determine the value of x.
Question 17 options:
A)
x = 20°
B)
x = 45°
C)
x = 4.5°
D)
x = 90°
The value of the x in the rectangle is 4.5°
Rectangle:
A rectangle is a two-dimensional shape (2D shape) in which the opposite sides are parallel and equal to each other and all four angles are right angles
Given,
Here we have the rectangle with one angle as 90°.
Here we have to find the value of x.
We know that, we we divide the rectangle as two distinct right angled triangle.
We know that, the right triangles are triangles in which one of the interior angles is 90 degrees, a right angle.
So,
20x = 90
x = 90/20
x = 4.5°
Therefore, the value of x is 4.5°.
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An item is regularly priced at $65. Lena bought it on sale for 60% off the regular price. How much did Lena pay?
The regular price of an item is $65
Lena bought it on sale for 60% off the regular price.
Then it means that she paid only (100% - 60% = 40%) of the price.
Let us find the 40% of $65
[tex]\frac{40}{100}\times\$65=\$26[/tex]Therefore, Lena paid only $26 for the item.
Select the correct answer.
What is the value of this logarithmic e ession?
log2 16 - log₂ 4
Answer:l og2(16)=x log 2 ( 16 ) = x in exponential form using the definition of a logarithm. If x x and b b are positive real numbers and b b does not equal ...
Step-by-step explanation:
Out of 441 applicants for a job 235 have over five years of experience and 106 have over five years of experience and have a graduate degreeWhat is the probability that a randomly chosen applicant has a graduate degree given that they have a five years of experience enter a fraction or round your answer to four decimal places if necessary
Probability that a randomly chosen applicant has a graduate degree given that they have a five years of experience = 106/441
Explanation:Total number of applicants, n(Total) = 441
Number of candidates that have over five years of experience, n(5 yrs) = 235
Probability that a randomly chosen applicant has over 5 years experience
[tex]\begin{gathered} P(5yrs)=\frac{n(5yrs)}{n(Total)} \\ \\ P(5yrs)=\frac{235}{441} \end{gathered}[/tex]Number of applicants that have over five years of experience and have a graduate degree, n(5 n g) = 106
Probability that a randomly selected applicant has over five years of experience and have a graduate degree
[tex]\begin{gathered} P(5\text{ n g\rparen = }\frac{n(5\text{ n g\rparen}}{n(Total)} \\ \\ P(5\text{ n g\rparen = }\frac{106}{441} \end{gathered}[/tex]Probability that a randomly chosen applicant has a graduate degree given that they have a five years of experience
[tex]\begin{gathered} P(g\text{ /5yrs\rparen = }\frac{P(5\text{ n g\rparen}}{P(5yrs)} \\ \\ P(g\text{ /5yrs\rparen = }\frac{106}{441}÷\frac{235}{441} \\ \\ P(g\text{ /5yrs\rparen=}\frac{106}{441} \end{gathered}[/tex]Exponential Regression
The table below shows the population, P. (in thousands) of a town after 12 years.
0
72
P 2400
3
2801.27
7
3608.71
12
14
4974.15 5426.17
19
6898.37
(a) Use your calculator to determine the exponential regression equation P that models the set of
data above. Round the value of a to two decimal places and round the value of b to three decimal
places. Use the indicated variables.
P =
(b) Based on the regression model, what is the percent increase per year?
96
(c) Use your regression model to find P when n = 13. Round your answer to two decimal places.
The population of the town after
P =
thousand people
(d) Interpret your answer by completing the following sentence.
years is
thousand people.
Considering the given table, it is found that:
a. The exponential regression equation is: P(t) = 2408.80(1.059)^t.
b. The yearly percent increase is of 5.9%.
c. P(13) = 5075.
d. The population of the town after 13 years is of 5075.
How to find the exponential regression equation?The exponential regression equation is found inserting the points into a calculator.
The points are given as follows:
(0, 2400), (3, 2801.27), (7, 3608.71), (12, 4974.15), (14, 5426.17), (19, 6898.37).
Using a calculator, the function is:
2408.80(1.059)^t.
The yearly percent increase rate is calculated as follows:
1 + r = 1.059
r = 1.059 - 1
r = 0.059
r = 5.9%.
Then in 13 years, the population will be given as follows:
P(13) = 2408.80(1.059)^13 = 5075.
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Solve the system of two linear inequalities graphicallySysx-2y) -5x + 10Step 1 of 3: Graph the solution set of the first linear inequalityAnswerKeypadKeyboard ShortcutsThe line will be drawn once all required data is provided and will update whenever a value is updated. The regions will be added once the line is drawn.Enable Zoom/PanChoose the type of boundary line:Solid (-) Dashed (-)Enter two points on the boundary line:10-Select the region you wish to be shaded:Submit Answer
Given:
[tex]\begin{gathered} y\leq x-2 \\ \\ y>-5x+10 \end{gathered}[/tex]Find-: Solution set of the first linear inequality.
Sol:
Graph of first inequality is:
Graph of inequality of:
[tex]y>-5x+10[/tex]Graph of the given inequality is:
The solution of inequality is:
[tex]\begin{gathered} x=2 \\ y=0 \end{gathered}[/tex]Which term is −20,155,392 for the following sequence, assuming that the pattern continues?
2, −12, 72, −432, …
a9
a10
a11
a12
The term that is the −20,155,392 in the sequence is a₁₀.
How to solve sequence?The sequence below is a geometric sequence.
Therefore, a geometric sequence can be represented as follows:
nth term = arⁿ⁻¹
where
a = first termn = number of termsr = common ratioTherefore, let's find which term is −20,155,392 for the sequence.
2, -12, 72, -432
r = -12 / 2 = 72 / -12 = -432 / 72 = -6
a = 2
Hence,
nth term = arⁿ⁻¹
−20,155,392 = 2 × -6ⁿ⁻¹
−20,155,392 / 2 = -6ⁿ⁻¹
- 10077696 = -6ⁿ⁻¹
6ⁿ⁻¹ = 10077696
6ⁿ⁻¹ = 6⁹
n - 1 = 9
n = 9 + 1
n = 10
Therefore, it's the 10th term.
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The term −20,155,392 is the tenth in the given geometric sequence.
The given sequence is below which is in a geometric pattern
2, -12, 72, -432
Here first term (a) = 2
The common ratio (r) = -12 / 2
The common ratio (r) = -6
We know that the nth term of the geometric sequence is
Tₙ = arⁿ⁻¹
Here Tₙ = −20,155,392
⇒ −20,155,392 = arⁿ⁻¹
Substitute the values of a and r in the above equation,
⇒ −20,155,392 = 2 × -6ⁿ⁻¹
⇒ −20,155,392 / 2 = -6ⁿ⁻¹
Apply the division operation,
⇒ - 10077696 = -6ⁿ⁻¹
⇒ 6ⁿ⁻¹ = 10077696
⇒ 6ⁿ⁻¹ = 6⁹
Equating exponents of the base
⇒ n - 1 = 9
⇒ n = 10
Therefore, the term −20,155,392 would be the tenth in the given sequence.
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Please help me. Will mark most brainliest.
Matthew's Maths mark increased by a factor of 3/2 this term. His new mark is 75%. Use an equation to calculate Matthew's mark last term.
We need to know about scale factor to solve the problem. Matthew's mark last term was 50%.
It is given that Matthew's marks increased by a factor of 3/2 this term. This means that whatever marks Matthew had received in his previous term, it was increased by 3/2 this term. If we consider his original marks to be x, then we can get the increased marks by multiplying x by 3/2. We know that the new marks is 75%, we need to find the value of x.
3x/2=75
x=75x2/3=25x2=50
Therefore the marks Matthew received in the previous term is 50%.
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A whole pizza is cut into twelfths. If Dexter eats 1/2 of the pizza and Landry eats 1/3 of the pizza, then 3 what fraction of the pizza remains?
Explanation
Step 1
Let
A whole pizza = 1 pizza
Dexter eats 1/2
Landry eats 1/3
x= fraction of the pizza remains
Step 2
the r
The ratio of a quarterback's completed passes to attempted passes is 5 to 8. If he attempted 16 passes, find how many passes he completed. Round to the nearest whole number if necessary.
The ratio of a quarterback's completed passes to attempted passes is 5 to 8. If he attempted 16 passes, find how many passes he completed. Round to the nearest whole number if necessary.
Let
x -----> number of quarterback's completed passes
y -----> number of quarterback's attempted passes
so
x/y=5/8 -----> x=(5/8)*y -----> equation A
y=16 -----> equation B
substitute equation B in equation A
x=(5/8)*16
x=10
therefore
the answer is 10 completed passesestimate the product by rounding to the nearest ten: 28×51×76
To estimate each number by rounding it to the nearest ten, we will look at the unit digit,
If it is less than 5, then we replace it by 0 and keep the ten-digit as it
If it is 5 or more, then we will replace it by 0 and add the ten-digit by 1
Let us do that with every number
28, the unit digit is 8 which is greater than 5, then replace it by 0 and add 2 by 1
28 rounded to 30
51, the unit digit is 1 which is less than 5, then replace it by 0
51 rounded to 50
76, the unit digit is 6 which is greater than 5, then replace it by 0 and add 7 by 1
76 rounded to 80
Now let us multiply them
[tex]28\times51\times76=30\times50\times80=120,000[/tex]The product of the given numbers is 120,000
What is the solution to the equation below? √x+9 = 11 O A. x= 2 O B. X= √ O C. x = 42 D. x = 4
answer: D. x = 4
