A balloon has a volume of 1785 mL at 25°C, if the volume of balloon changes to 1.25 L, what is the new temperature in degree Celcius atconstant pressure and amount?

Answer

The element that is oxidized is Si and the one that is reduced is F₂.

Explanation

Si + 2F₂ → SiF₄

The given reaction is an oxidation-reduction (redox) reaction:

Oxidation: Si → Si⁴⁺ + 4e⁻

Reduction: 2F₂ + 4e⁻ → 4F⁻

Si is a reducing agent, and F₂ is an oxidizing agent.

An oxidizing agent gains electrons and is reduced in a chemical reaction.

A reducing agent loses electrons and is oxidized in a chemical reaction.

Therefore, the element that is oxidized is Si and the one that is reduced is F₂.

The equation that is the net description of the ions involved is;[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]

The term net ionic equation has to do with the final ionic equation which does not include the spectator ions. What I mean by the spectator ions are those ions that do not undergo a change in a chemical reaction. The first step when we want to write the net ionic equation is first to write down the molecular equation and balance the equation accordingly.

We shall now show the balanced overall reaction equation of the process

Thus, the balanced molecular equation of this reaction is; [tex]Na_{2} CO_{3} (aq) +2 HCl(aq) ----- > NaCl(aq) +H_{2} O(l) + CO_{2} (g)[/tex]

The net ionic equation is;

[tex]CO_{3} ^{2-} (aq) + 2H^{+} (aq)----- > H_{2} O(l) + CO_{2} (g)[/tex]

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Chemistry => Measurements => Significant Figures

Significant figures correspond to the number of digits in a number. We have to take into account the following:

• Zeros at the beginning of a number or at the end are not counted as digits, but zeros in between the number should be counted.

• When we write a number in scientific notation, the 10 that accompanies the number should not be counted.

Following these indications, let's count the significant figures of each given number:

In summary, we have the answer will be:

1SFs

3.00 m

4.0x10^3 mL

3SFs

50 100 00g

80.10 mL

60.4 °C

6SFs

9018.17 kg

2.0724moles

Given the balanced chemical reaction between Na2CO3 and CaCl2 expressed as:

Given the following parameters

Mass of CaCl₂ = 115g

Determine the moles of CaCl₂

According to stochiometry, 1 mole of CaCl2 prodcues 2 moles of NaCl. The moles of NaCl requred is given as:

Therefore moles of NaCl made is 2.0724moles

Answer

number of moles = 0.171 mol

Explanation

Given

Volume of oxygen = 4.0 L

Temperature = 37 °C = 310 K

Pressure = 110 kPa = 1.08562 atm

we know R = 0.082 L.atm.k/mol

Required: number of moles

Solution

To solve this problem, use the ideal gas law

PV = nRT

n = PV/RT

n = (1.08562 x 4.0 L)/(0.082 L.atm.k/mol x 310 K)

n = 0.171 mol

This element is nonmetal and appears in the periodic table.

The number that represents the position of the elements is called, the atomic number, it also represents the number of protons = numbers of electrons an atom has.

Answer: D. the atomic number

Isopropyl alcohol + water = Solution

Solute = Isopropyl alcohol

Solvent = water

% V/V = mL of solute / 100 ml of solution

Now we have 655 mL of solution.

32.0 % V/V means 32 mL of Isopropyl alcohol dissolved in 100 mL of solution.

So,

32 mL Isopropyl alcohol ------------------- 100 mL Solution

x ------------------- 655 mL Solution

x represents the volume of Isopropyl alcohol in 655 mL of solution

Now

Alcohol: 209.6 mL

Water: 655 mL (solution = Alcohol + Water) - 209.6 mL (alcohol) = 445.4 mL of water

The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine is 493 nanometer.

The formula to calculate Energy is given as follows :

E = BE / Na

E = energy

BE = bond energy = 243 KJ / mol

Na = Avogadro number = 6.02 × 10²³

substituting the values in the formula:

E = 243 × 10³ / 6.02 × 10²³

E = 4.03 × 10⁻¹⁹ J

By using Einstein equation for photon , we can calculate the shortest wavelength :

E = (h c) / λ

E = energy

h = Planck constant = 6.626 × 10⁻³⁴ J.s

c = speed of light =  3 × 10⁸ m/s

λ = wavelength

therefore,

λ = (hc )/ E

λ =( 6.626 × 10⁻³⁴ J.s × 3 × 10⁸ m/s ) /  4.03 × 10⁻¹⁹ J

λ = 4.93 × 10⁻⁷ m

λ = 493 × 10 ⁻⁹ m

1 nm = 1 × 10 ⁻⁹ m

Shortest wavelength = 493 nanometer.

Thus, The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol  is 493 nanometer.

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If 1.53 g of copper is heated with excess sulfur to yield 1.76 g of copper (I) sulfide, the percent yield would be  75.43%.

The percent yield of a reaction is the actual yield relative to the theoretical yield of the same reaction.

The percent yield of a reaction is mathematically expressed as:

Percent yield = actual yield/theoretical yield x 100%.

Let us now consider the reaction in question. The equation of the reaction is given as:

[tex]Cu + S --- > CuS[/tex]

The mole ratio of the copper that reacts to the copper sulfide that is formed is 1:1.

Recall that: mole = mass/molar mass

The molar weight of copper is 63.55 g/mol

Mole of 1.53 g copper = 1.53/63.55

                           = 0.024 moles

The equivalent mole of copper sulfide produced will also be 0.024 moles.

The molar mass of CuS is 95.61 g/mol

Mass of 0.024 moles CuS = 0.024 x 96.61

                                      = 2.32 g

2.32 g is the theoretical yield of the reaction. But 1.76 g of copper sulfide is the actual yield.

Percent yield = 1.75/2.32 x 100%

                      = 75.43%

Thus, the percent yield of the reaction, if 1.53 g of copper is heated with excess sulfur to produce 1.76 g of copper (I) sulfide, is 75.43%.

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The products of the double displacement reactions are given in the equations of the reaction below:

a. 3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)

Iron (iii) hydroxide is obtained as a precipitate

b. CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)

No double displacement reaction occurs as both products are soluble.

Double displacement reactions are reactions in which there is an exchange of radicals by two compounds when solutions of the compounds are added together.

In a double displacement reaction, an insoluble precipitate is obtained since one of the products of the double displacement reaction is insoluble in aqueous solutions.

The products of the double displacement reactions are given in the equations of the reaction below:

a. Reaction between Sn(OH)₂ and FeBr₃

3 Sn(OH)₂ (aq) + 2 FeBr₃ (aq) ---> 3 SnBr₂ (aq) + 2 Fe(OH)₃ (s)

Iron (iii) hydroxide is obtained as a precipitate

b.  Reaction between CsNO₃ and KCI

CsNO₃ (aq) + KCI (aq) ---> CsCl (aq) + KNO₃ (aq)

No double displacement reaction occurs as both products are soluble.

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Physical properties are the ones that describe the behavior of the substances when exposed to different physical changes.

In this case, the one that describes a physical change is water when heated forms steams. In this case water changes its state of matter but it is still the same substance, there is not chemical change, just physical.

The correct answer is Water when heated forms steams.

Answer:

60.0 mL of 0.322 M potassium iodide are combined with 20.0 mL of 0.530 M lead (II) nitrate.

How many grams of lead (II) iodide will precipitate? (you must write your own reaction)

Explanation:

Let's analyze each option to find what best fit as an answer:

A - the function of a catalyst is to lower the energy of activation in a reaction, causing it to occur in a faster way. Since this question is not much about energy or kinetics, this would be the best fit, adding a catalyst or not adding it would not be too influential in the shift of the reaction.

B - Increasing the pressure in a reaction containing gases will mostly favor the side with a lower value of moles, smaller amount of moles = less pressure, so if we add more pressure, the reaction will shift towards the side of the products

C - If we treat heat as a reactant, if we add more temperature, it will shift towards the products, to counteract this increase of temperature

D - Adding reactants will favor the reaction to shift towards the products

Therefore the answer is letter A

1) List the known and unknown quantities.

First experiment:

Reactants

Phosphorus: 7.97 g.

Bromine: excess.

Product

Phosphorus tribromide: 69.65 g.

Second experiment

Reactants

Phosphorus: 12.05 g.

Bromine: 61.68 g.

Product

Phosphorus tribromide: unknown.

2) Write and balance the chemical equation.

3) Convert the masses.

3.1-Convert the mass of P to moles of P.

The molar mass of P is 30.97 g/mol.

3.2-Convert the mass of Br to moles of Br.

The molar mass of Br2 is 159.8080 g/mol.

4) Which is the limiting reactant?

4.1-How many moles of Br2 do we need to use all of the P?

The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.

We need 0.583635 mol Br2 and we have 0.38596 mol Br2. We do not have enough Br2. This is the limiting reactant.

4.2-How many moles of P do we need to use all of the Br2?

The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.

We need 0.25731 mol P and we have 0.38909 mol P. We have enough P. This is the excess reactant.

5) Moles of phosphorus tribromide produced from the limiting reactant.

Limiting reactant: 0.38596 mol Br2.

The molar ratio between Br2 and PBr3 is 3 mol Br2: 2 mol PBr2.

6) Conver the moles of Pbr3 to mass of PBr3.

The molar mass of PBr3 is 270.6858 g/mol.

The mass of PBr3 produced in the reaction is 69.65 g PBr3.

.

10.7 grams

The formula for calculating the molarity of a solution is given as:

Given the following parameters

molarity of NaOH = 1.11M

volume of solution = 241.0mL = 0.241L

Find the moles of NaOH

Determine the mass of solute (NaOH)

Hence the grams of solute that would be used to prepare the solution is 10.7grams

First, we assume STP conditions and Ideal gas conditions.

In STP conditions, we say that:

1 mol of any gas = 22.4 L (liters)

Procedure:

1 mol Xe ------ 22.4 L (STP)

4.51 moles Xe ------- X

X = 101 L

Answer: 101 L

The molecular formula for the compound that contains 4.90 g N and 11.2 g O is N₂O₄

We'll begin by obtaining the empirical formula for the compound. This is illustrated below:

Divide by their molar mass

N = 4.9 / 14 = 0.35

O = 11.2 / 16 = 0.7

Divide by the smallest

N = 0.35 / 0.35 = 1

O = 0.7 / 0.35 = 2

Thus, the empirical formula of the compound is NO₂

Finally, we shall determine the molecula formula. Details below

Molecular formula = empirical × n = molar mass

[NO₂]ₙ = 92

[14 + (16×2)]ₙ = 92

46n = 92

Divide both side by 46

n = 92 / 46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

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Complete question:

Find the molecular formula for a compound that contains 4.90 g N and 11.2 g O. The molar mass of the compound is 92.0 g/mol.

General nucleus and electron attraction explained

We can say this:

The net positive charge from the nucleus (remember that protons are in the nucleus) that an electron can feel attraction from, is the effective nuclear charge. The core electrons (electrons are on shells around the nucleus) are said to shield the valence electrons from the full attractive forces of the pro

Step 1

Molarity is defined as:

Molarity (M or mol/L) = Moles of lead (II) oxide/Volume of solution (L)

Molarity = mass of lead (II) oxide/molar mass of lead (II) oxide x volume (L) (1)

-------------------------

Step 2

The molar mass of PbO = 223 g/mol

PbO = lead (ll) oxide

------------------------

Step 3

Data provided:

Molarity = 0.75 M

Mass of PbO = 75 g

------------------------

Step 4

Procedure:

The volume of the solution is cleared from (1):

Volume (L) = mass PbO/(molar mass PbO x Molarity)

Volume (L) = 75 g/(223 g/mol x 0.75 mol/L) = 0.45 L approx.

Answer: Volume = 0.45 L

The theoretical percentage yield of copper  is 70%

This is further explained below.

Generally, the equation for  yield is mathematically given as

[tex]yield =\frac{\text { mote no. of product }}{\text { mote no. of reactant }} \times 100$[/tex]

Here, Based on Theoretical Yield

[tex]\begin{aligned} \text { mole rio. of reactant } &=-\frac{0.5}{63.546} \text { mole } \\ \end{aligned}$[/tex]

Based on the Actual yield

mole rio. of Product=0.35/63.546 mole

(Here atomic man of Cu=63.546g/mol )

Therefore, we apply the initially stated equation for %yield

So,  %yield =[tex]\frac{\frac{0.35}{63.546}}{\frac{0.5}{(63.546}} \times 100 \%$[/tex]

=[tex]\frac{0.35}{0.5} \times 100 \%\\[/tex]

=0.7 *100%

=70%

In conclusion,  the percentage yield is 70%

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Answer

The process that is NOT reversible is Burning butane in a candle lighter

Explanation

All other processes can be reversed

The bulk properties of a substance (macroscopic) such as electrical conductivity can be caused by the microscopic such as electrical forces in the atoms through the movement of free electrons.

This is referred to as the measure or the degree in which a substance conducts electricity and how the electric current moves within a substance.

The electrical conductivity which is macroscopic can be caused by the microscopic such as electrical forces as a result of the electrons moving in the body. The movement of the electron is usually from the negative to the positive terminal of the body.

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Density relates the mass of a compound to its volume. We will first find the mass of the solution using the density and volume given. We have the following equation:

We clear the mass,

So, the mass of paint is 13950 g. Now the mass percentage of the lead in the paint will be calculated as follows:

The mass percentage of lead in the paint is 0.24%.

ppm concentration means the quantity of solute in milligrams (mg) is in a liter (L) of a solution. So, to calculate ppm concentration we will divide the milligrams of lead (II) nitride between the liters of paint:

The ppm of lead in the paint is 11033ppm.

Answer

c. Fe2(SO4)3

Explanation

The polyatomic ion (SO₄)⁻² has a net charge of -2 and iron (III) ion, Fe⁺³ has an oxidation number of +3. For a compound to be formed between them, two of Fe⁺³ will need three of the polyatomic ion, (SO₄)⁻² and the formula of the compound will be Fe2(SO4)3.

A solution of Calcium Chloride was made, we are asked to find the concentration of the initial solution.

We will apply the following equation to find it:

Where,

C1 is the initial concentration we have to find

V1 is the initial volume, 45mL

C2 is the final concentration, 0.182M

V2 is the final volume, 50. mL

We clear C1 and replace the known data;

The molarity of the stock solution is 0.202M

Answer: 0.202M

The likely to be TRUE about a hair sample that is four centimeters long and lacks a root or follicular tissue is there will be mitochondrial DNA present (Option A).

Mitochondrial DNA is a type of genetic material that is independent of nuclear DNA and is contained in an organelle known as mitochondrion. These organelles (mitochondria) are the energy factors of the cell because they generate ATP through the process of cellular respiration.

Generally, the cells that contain cell nuclei also contain different organelles such as mitochondria, and this observation also includes the hair cell follicles that are differentiated specialized types of cells present in the hair.

Therefore, with this data, we can see that mitochondrial DNA  is different from nuclear DNA and it is found in tissues that are subject to differentiation such as follicular tissues which need energy to differentiate.

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KOH. Option B is correct

A chemical compound are made up of more than one element combined together. According to the question, we need to determine the formula that represents a compound.

The compound there is KOH since it contains three elements (Potassium, Oxygen and Hydrogen)

A solid has an identifiable shape and volume. A liquid has a fixed volume and an ill-defined shape. A gas has an undefined shape and a fixed volume.

A solid is something that has a specific shape and volume. The definition of a liquid is something that has a fixed volume but no fixed shape. A gas is described as something that has neither a fixed shape nor a fixed volume.

A solid has a distinct volume and shape, a liquid has a distinct volume but no distinct shape, and a gas lacks both.

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The boiling point of the solution is 80.93°C.

We know that the boiling point has to do with the temperature at which the pressure inside the system is the same as the atmospheric pressure. Now we know that the boiling point of the pure benzene is 80.1 °C.

Also;

ΔT = K m i

ΔT = boiling point elevation

K = boiling point constant

m = molality

i = Van Hoff factor

ΔT = 2.53°C /m * 0.33 m * 1

ΔT =  0.83°C

Boiling point of the solution =  0.83°C + 80.1 °C

= 80.93°C

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Answer:

Explanation:

Answer to the 1st one. I have my doubts for the second one so didn't post :)