Answer:
The raft moves towards the shore
Explanation:
If you double the mass of both Mass 1 and the distance, how does the gravitational force change? A) The force doubles B) The force triples C) the force quadruples D) the force is half E) the force is 1/4
Answer:
Choice C)
Explanation:
Newton’s Universal Law of Gravitation
It states objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
If m1 and r are doubled, then the new force F' is:
[tex]\displaystyle F'=G{\frac {2m_{1}m_{2}}{(2r)^{2}}}[/tex]
Operating:
[tex]\displaystyle F'=G{\frac {2m_{1}m_{2}}{4r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{2}{4}G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
[tex]\displaystyle F'=\frac{1}{2}G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the value of the original force:
[tex]\displaystyle F'=\frac{1}{2}F[/tex]
This means the force is halved
Choice C)
A 20 kg cart with frictionless bearings is initially at rest on a horizontal tabletop. The cart is connected by a light string to a hanging 5 kg block. The string passes over an ideal pulley. The system is released from rest and both objects have an acceleration of magnitude a 5 kg
(a) Draw the forces (NOT components) that act on each object.
(b) Calculate the acceleration ay of the system of masses once the system is released.
Answer:
[tex]a=1.96m/s^2[/tex]
Explanation:
From the question we are told that
Mass of cart =20kg
Mass of block =5kg
Magnitude of acceleration M_a= 5 kg
Generally Force on the 20kg mass in the [tex]\bar X[/tex] is mathematically given as
[tex]\sum F=ma\\t=(20kg)a[/tex]
Generally Force on the 2kg in the[tex]\bar Y[/tex] mass is mathematically given as
[tex]\sum F=ma\\(5kg)(9.8m/s^2)-(5kg)a[/tex]
Therefore
[tex](20kg)a=(5kg)(9.8m/s^2)-(5kg)a[/tex]
[tex]a=\frac{5kg)(9.8m/s^2)-(5kg)}{25}[/tex]
[tex]a=1.96m/s^2[/tex]
Based on the information presented in the introduction of this problem, what is a sound wave? Based on the information presented in the introduction of this problem, what is a sound wave? Propagation of sound particles that are different from the particles that comprise the medium Propagation of energy that does not require a medium Propagation of pressure fluctuations in a medium
Answer:
sound is a wave that carries energy and the particles are oscillating around their equilibrium positions.
Explanation:
When the air particles are subjected to a periodic force they oscillate around their equilibrium possessions, this oscillation can propagate in the air creating a sound wave.
Therefore the sound wave is a wave that propagates energy, but the particles have only one oscillation around their equilibrium position.
These waves can be mathematically analyzed as displacement waves and since the oscillation is in the same line of the movement of the wave we can also analyze it as a pressure wave
In summary, sound is a wave that carries energy and the particles are oscillating around their equilibrium positions.
Why is temperature scalar?
Pulling on a spring with a force of 1.2 N causes a stretch of 6.4 cm. What is the spring constant for this spring?
Answer:
k=19 N/m
Explanation:
Use the equation F=kx for this problem and isolate k since that is what you're solving for (k=F/x). Plug in your values (F=1.2 N and x=0.064 m) and solve for k which is 19 N/m.
By using Hooke's law formula, the spring constant K for the spring is 18.75 N/m
The parameters given are :
Force F = 1.2N
Extension e = 6.4 cm
convert cm to m
e = 6.4 / 100
e = 0.064 m
Spring constant K = ?
From Hooke's law, It states that the extension is proportional to the force applied provided that elastic limit is not exceeded. That is,
F = Ke
Substitute all the parameters into the formula.
1.2 = 0.064K
Make K the subject of the formula
K = 1.2/0.064
K = 18.75 N/m
Therefore, the spring constant K for this spring is 18.75 N/m
Learn more here : https://brainly.com/question/15365772
A football quarterback throws a 0.408 kg football for a long pass. While in the motion of throwing, the quarterback moves the ball 1.909 m, starting from rest, and completes the motion in 0.439 s. Assuming the acceleration is constant, what force does the quarterback apply to the ball during the pass?
Answer:
The quarterback applies a force of 8.08 N to the ball during the pass.
Explanation:
To find the force we need to calculate the acceleration first so we can use the following equation:
[tex] F = ma [/tex]
Now, we can calculate the acceleration as follows:
[tex] x_{f} = x_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]
Since the ball starts from rest [tex]v_{0} = 0[/tex] and [tex]x_{0} = 0[/tex]:
[tex] a = \frac{2*x_{f}}{t^{2}} = \frac{2*1.909 m}{(0.439 s)^{2}} = 19.81 m/s^{2} [/tex]
Now we can find the force:
[tex] F = 0.408 kg*19.81 m/s^{2} = 8.08 N [/tex]
Therefore, the quarterback applies a force of 8.08 N to the ball during the pass.
I hope it helps you!
How much energy is needed to heat 1kg of copper by 20 degrees Celsius
Step by step explanation
Answer:
Q = 0.0077 J
Explanation:
Given that,
Mass of copper, m = 1 kg = 0.001 g
The change in temperature = 20°C
We need to find the energy needed to heat copper. The formula is given by :
[tex]Q=mc\Delta T[/tex]
c is the specific heat of copper, c = 0.385 J/g°C
Put values in the above formula
[tex]Q=0.001\ g\times 0.385\ J/g^{\circ} C\times 20^{\circ} C\\\\Q=0.0077\ J[/tex]
So, the energy needed to heat 1 kg of copper is 0.0077 J.
PLS HELP WILL MARK AS BRAINLIEST ANSWER
any shot in front of the 3
point line is worth how
many points? *
Answer:
1 point?
Explanation:
calculate the force required to take away a flat corcular plate of radius 0.01m from the surface of water. the surface tention of water is 0.075N/m.
Answer:
[tex]Force = 0.0047175\ N[/tex]
Explanation:
Given
[tex]T = 0.075N/m[/tex] --- Surface Tension
[tex]r = 0.01m[/tex] --- Radius
Required
Determine the required force
First, we calculate the circumference (C) of the circular plate
[tex]C= 2\pi r[/tex]
[tex]C= 2 * \frac{22}{7} * 0.01m[/tex]
[tex]C= \frac{2 * 22 * 0.01}{7}m[/tex]
[tex]C= \frac{0.44}{7}m[/tex]
[tex]C= 0.0629 m[/tex]
The applied force is then calculated using;
[tex]Force = C * T[/tex]
[tex]Force = 0.0629m * 0.075N/m[/tex]
[tex]Force = 0.0047175\ N[/tex]
Which object has the most momentum?
A toy car rolling along the floor
A child peddling their bike as fast as possible
&o
A large moving truck stopped at a red light
Help ASAP!
Everything on screenshot
Answer:
For the first one, its B) cities B and C
I'm not so sure, but I hope this helps.
An elevator travels up and down. The vertical position of the elevator in meters over time is shown below
what is the displacement of the elevator between 8s and 20s?
What is the distance traveled by the elevator between 8s and 20s
Answer:
The displacement is
-27m
The distance traveled is
27m
Dont listen to the other guys they are wrong
Explanation:
Well you see the elevator starts at 12m and 8s and moves down to 0mat 16s, traveling at a distance of 12m
The Elevator starts at 0m at 16s and moves down to -15m at 20s traveling a distance of 15m
So afterwards what you do is find the distance between 8 and 20 so do this equation
12m + 15m = 27m
So that gives you
-27
27
HOPE THIS HELPS!!!
The displacement and distance of the elevator between 8s and 20s will be -27 meters and 27 meters respectively.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
From the given graph, it is observed that;
Distance is the sum of the physical length travelled. First, the elevator travels the 15 m down and the 12-meter up. The distance travelled will be;
d= 15 +12 = 27 m
Displacement is the net distance travelled or the shortest distance. The value of the displacement can be negative. The displacement is found as;
D= -15-12 =-27 m
Hence, the displacement and distance of the elevator between 8s and 20s will be -27 meters and 27 meters respectively.
To learn more about the distance, refer to the link;
https://brainly.com/question/26711747
#SPJ2
The International Space Station has a mass of 419,455 kg. When it orbits the
Earth at an altitude of 400,000 m, what is the approximate gravitational force
on the Station due to Earth's gravity? (Recall that Earth has a radius of 6.37 x
106 m, it has a mass of 5.97 x 1024 kg, and G = 6.67 x 10-11 N·m²/kg2.)
O A. 3.9 ~ 106N
B. 2.0 x 106N
O C. 3.6 x 106N
O D. 2.8 x 106N
Answer:
[tex]F=3.6\times 10^6\ N[/tex]
Explanation:
Given that,
The mass of International Space Station, m = 419,455 kg
It orbits around the Earth at an altitude of, h = 400,000 m
The radius of Earth, [tex]r=6.37\times 10^6\ m[/tex]
The mass of the Earth, [tex]m_e=5.97 \times 10^{24}\ kg[/tex]
We need to find the approximate gravitational force on the Station due to Earth's gravity. The formula for the gravitational force between the satellite and the Earth is given by :
[tex]F=G\dfrac{mm_e}{(r+h)^2}\\\\F=6.67\times 10^{-11}\times \dfrac{419455\times 5.97 \times 10^{24}}{(6.37 \times 10^6+400000 )^2}\\\\F=3.6\times 10^6\ N[/tex]
So, the required force on the station due to Earth's gravity is [tex]3.6\times 10^6\ N[/tex].
What is the KE of a 4 kg rock rolling at 10 m/s? KE = 1/2 mv2
O 160 J
O 2003
O 40 J
O 400 J
Answer:
200J
Explanation:
0.5 *4 * 10 * 10
=200J
what is the spring potential energy of a spring that is stretched 15 cm if its spring constant is 350 n/m?
how much force is required for this stretch?
Answer:
Spring potential energy = 7.875Nm
Explanation:
Given the following data;
Extension, e = 15cm to meters = 15/100 = 0.15m
Spring constant, k = 350n/m
To find the force;
Force = spring constant * extension
Force = 350 * 0.15
Force = 52.5 Newton.
Now to find the spring potential energy we would use the formula below;
Spring potential energy = force * extension
Substituting into the equation, we have;
Spring potential energy = 52.5 * 0.15
Spring potential energy = 7.875Nm
A piece of metal with a mass of 1.9 kg, and specific heat of 200J/kg°C, and an initial temperature of 100°C is dropped into an insulated jar that contains liquid with a mass of 3.9 kg, a specific heat of 1000J/kg°C, and initial temperature of 0°C. The piece of metal is removed after 7 s, at which time its temperature is 20°C.
Required:
Find the temperature of the liquid after the metal is removed. Neglect any effects of heat transfer to the air or to the insulated jar. Answer in units of ∘C.
Answer:
7.79 °C
Explanation:
Given that
Mass of the metal, m = 1.9 kg
Specific heat of the metal, c(m) = 200 J/kgC
Initial temperature, T(0) = 100 °
Mass of liquid, M = 3.9 kg
Specific heat of liquid, c(l) = 1000 J/kgC
Initial temperature, T = 0 °C
Time taken, t = 7 s
Final temperature = 20 °C
To solve the question, we use the formula the sum of the heats gained is zero.
massmetal * cmetal (20-100) + massliquid * cliquid (T.f-0)=0
On solving for T.f
1.9 * 200 * (20 - 100) + 3.9 * 1000 * (t.f - 0) = 0
380 * -80 + 3900 * t.f = 0
-30400 + 3900t.f = 0
3900t.f = 30400
t.f = 30400 / 3900
t.f = 7.79 °C
write the realtionship between the density of a liquid and its upthrust? clarify
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 47.0 cm . The explorer finds that the pendulum completes 91.0 full swing cycles in a time of 125 s. What is the magnitude of the gravitational acceleration on this planet?
Answer:
[tex]g=9.83\ m/s^2[/tex]
Explanation:
Given that,
The length of a simple pendulum, l = 47 cm = 0.47 m
The pendulum completes 91.0 full swing cycles in a time of 125 s.
The time period of a simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{L}{g}} \\\\or\\\\g=\dfrac{4\pi^2L}{T^2}[/tex]
Also,
[tex]T=\dfrac{1}{f}\\\\T=\dfrac{t}{n}[/tex]
t is 125 s and n = 91 cycles
Substitute all the values to find g.
[tex]g=\dfrac{4\pi^2\times 0.47}{(\dfrac{125}{91})^2}\\\\g=9.83\ m/s^2[/tex]
So, the gravitational acceleration on this planet is [tex]9.83\ m/s^2[/tex].
A cart of mass m = 0.12 kg moves with a speed v = 0.45 m/s on a frictionless air track and collides with an identical cart that is stationary. The carts stick together after the collision. What is the final kinetic energy of the system?
Answer:
0.006075Joules
Explanation:
The final kinetic energy of the system is expressed as;
KE = 1/2(m1+m2)v²
m1 and m2 are the masses of the two bodies
v is the final velocity of the bodies after collision
get the final velocity using the law of conservation of momentum
m1u1 + m2u2 = (m1+m2)v
0.12(0.45) + 0/12(0) = (0.12+0.12)v
0.054 = 0.24v
v = 0.054/0.24
v = 0.225m/s
Get the final kinetic energy;
KE = 1/2(m1+m2)v
KE = 1/2(0.12+0.12)(0.225)²
KE = 1/2(0.24)(0.050625)
KE = 0.12*0.050625
KE = 0.006075Joules
Hence the final kinetic energy of the system is 0.006075Joules
A burning candle provides :
a.radiant energy
b.solar energy
c.chemical potential energy
d.thermal energy
PLZ Help ASAP
Peter wants to find out which boils faster: salt water or tap water. What procedure should he follow to conduct this experiment?
Answer:
C. Fill two identical pots with equal volumes of salt water and tap water and use a stopwatch to determine the time it takes each pot to boil.
Explanation:
A) is incorrect because Peter should have the same testing environment for both of his experiments.
He should choose the same method of boiling the salt water and tap water because the stovetop and the microwave could also affect the results and make them unreliable.
B) is incorrect because Peter should not estimate the time it takes the salt water and tap water to boil.
Peter should measure and record the amount of time that it takes these substances to boil in order to have an accurate, valid experimental thesis.
C) is correct because Peter uses the same volume of salt water and tap water, fills them into two identical pots, and uses a stopwatch to determine the amount of time it takes each pot to boil.
The stopwatch makes the experiment more valid and accurate compared to the previous methods, and the identical pots and amounts of water help this experiment become even more precise.
D) is incorrect because the variables in the experiment are not controlled amounts and will therefore produce an inaccurate and invalid experiment.
The image below represents molecules in which state of matter? *
da answer is liquiddddddddd
A particular race car can cover a quarter-mile track (402 m) in 6.40 s starting from a standstill.
Find its acceleration.
If the combined mass of the driver and race car is 485 kg, what horizontal force must the road exert on the tires?
Answer:
9520N
Explanation:
For the first part of this problem:
Given parameters:
Distance traveled = 402m
Time taken = 6.4s
Initial velocity = 0m/s
Unknown:
Find the acceleration = ?
Solution:
To solve this problem, we use on of the kinematics equation:
S = ut + [tex]\frac{1}{2}[/tex]at²
S is the distance moved
u is the initial velocity
t is the time taken
a is the acceleration
402 = (0 x 6.4) + ([tex]\frac{1}{2}[/tex] x a x 6.4²)
402 = 20.48a
a = 19.63m/s²
Second problem:
Given parameters:
Mass of the driver and race car combined = 485kg
So;
Horizontal force = mass x acceleration
Horizontal force = 485 x 19.63 = 9520N
Answer:7.1*10^3
Explanation:
define what is false
Answer: not according with truth or fact/ incorrect.
Explanation:
To say that the rights to life, liberty, and
property are unalienable means that they
According to Newton's Universal Law of Gravitation, when the distance between two interacting objects doubles, the gravitational force is
Answer:
If the distance doubles, the gravitational force is divided by 4
Explanation:
Newton’s Universal Law of Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: 6.67\cdot 10^{-11}~Nw*m^2/Kg^2
If the distance between the interacting objects doubles to 2r, the new force F' is:
[tex]\displaystyle F'=G{\frac {m_{1}m_{2}}{(2r)^{2}}}[/tex]
Operating:
[tex]\displaystyle F'=\frac{1}{4}G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Substituting the original value of F:
[tex]\displaystyle F'=\frac{1}{4}F[/tex]
If the distance doubles, the gravitational force is divided by 4
prove the identity
Trigonometry grade 10
Answer:
and is in photo given.I didn't get time to type.
A student must perform an experiment in which two objects travel toward each other and collide so that the data collected can be used to show that the collision is elastic within the acceptable range of experimental uncertainty. Which of the following measuring tools, when used together, can the student use to verify that the collision is elastic?
A. A motion detector.
B. A meterstick.
C. A balance.
D. A stopwatch.
Answer:
A. A motion detector.
C. A balance.
Explanation:
An elastic collision can be defined as a type of collision in which the total kinetic energy possessed by the colliding bodies remain the same.
This ultimately implies that, in an elastic collision the maximum amount of kinetic energy possessed by the colliding bodies is conserved (kinetic energy is not lost) after the collision.
In this scenario, a student must perform an experiment in which two objects travel toward each other and collide so that the data collected can be used to show that the collision is elastic within the acceptable range of experimental uncertainty.
The measuring tools, which when used together, can be used by the student to verify that the collision is elastic are a motion detector and a balance.
Basically, the motion detector is an electronic device that can be used to determine the initial and final velocity of the objects while the balance would be used to take a measurement of the mass possessed by the objects.
In the diagram, the block is sliding at a constant velocity down a rough incline, which makes a 45 degree angle to the horizontal. Which of the following statements is NOT true?
A) The magnitude of the Net Force is equal to the magnitude of Force C.
B) The magnitude of Force A is equal to the magnitude of Force B
C) The magnitude of Force B is equal to the magnitude of Force D
D) The coefficient of friction between the block and the ramp is equal to 1.
Answer:
I haven't done physics for a while, but with the information given I don't understand how D could be correct, so I think D is your anwser
Explanation:
First aid for a strain or a sprain
A) the FITT formula.
B) ineffective.
C) the RICE formula. .
D) the ABC formula
Answer: C) the RICE formula
Explanation:
Particularly for the treatment of injury associated with the sprain or strain one can get relieve in pain and swelling on the damaged area by promoting flexibility and healing of that area utilizing the RICE formula. R- rest, I- Ice, C- Compression, and E- Elevation. Resting and restricting any activity can help in enhancing the healing process. The application of ice will reduce pain and swelling. The injured area can be compressed by using a tight bandage. This will also help in reducing the swelling. Keeping the injured body part at an elevation like on a pillow can also reduce the swelling.
