Answer:
force needed for the bus to go round the corner is 50,000 N.
Explanation:
To find the force needed for the bus to go round the corner, we can use the formula for centripetal force:
F = (mv^2)/r
where F is the centripetal force, m is the mass of the object, v is the velocity of the object, and r is the radius of the circular path.
Plugging in the values given in the problem, we get:
F = (2500 kg)(5 m/s)^2 / 50 m
= 50,000 N
So the force needed for the bus to go round the corner is 50,000 N.
The basics of parking include using front, rear and side vehicle reference point limitations to establish the
appropriate positioning of the vehicle.
O a) True
O b) False
The given statement "The basics of parking include using front, rear and side vehicle reference point limitations to establish the appropriate positioning of the vehicle is true because a good driver must properly study his environment while parking. Therefore, the correct answer option is: A) true.
What is a blind spot?A blind spot can be defined as an area or portion to either side of an automobile vehicle (car), as well as the back (rear end) of a vehicle that is typically outside the field of vision of a driver, especially because it is not visible in the rear view mirror.
Who is a good driver?A good driver can be defined as an individual who has been trained and licensed to drive an automobile vehicle (car), while judiciously performing and obeying traffic signs, rules and regulations that do not pose a threat to the life and safety of other road users.
As a good driver, it is very important and critical to make use of your front, rear, and side vehicle reference point limitations through the mirrors, in order to establish an appropriate positioning of your automobile vehicle (car).
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A 3.2 microF capacitor has a potential difference of 21.0 V between its plates. How much additional charge flows into the capacitor if the potential difference is increased to 47.0 V?
Please explain well and with in depth steps for me to understand. I dont understand this chapter
An additional 83.2 micro C of charge will flow into the capacitor.
A 3.2 micro F capacitor has a potential difference of 21.0 V between its plates. An additional 83.2 micro C of charge will flow into the capacitor. The formula for the charge Q on a capacitor with capacitance C that is connected to a voltage V is given by:
Q = CV
where C is the capacitance of the capacitor in Farads, V is the potential difference across the capacitor in volts, and Q is the charge on the capacitor in coulombs. Thus, if the potential difference across the capacitor is increased from 21.0 V to 47.0 V, an additional 83.2 micro C of charge will flow into the capacitor. Capacitor is the entity that used to store the electricity in it, it is also used to generate an electricity spark in the gap between the wires of the circuit and the project just to make an gap and it is used to jump an electricity phase like wise in any circuit, it is used to provide the power and potential to make the charge jump from one place to another.
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An additional 83.2 microC of charge will flow into the capacitor.
The formula for the charge Q on a capacitor with capacitance C that is connected to a voltage V is given by:
Q = CV
where C is the capacitance of the capacitor in Farads,
V is the potential difference across the capacitor in volts, and Q is the charge on the capacitor in coulombs.
The initial charge on the capacitor is given by:Q1 = C1V1 = (3.2 microF)(21.0 V) = 67.2 microC
The final charge on the capacitor when the potential difference is increased to 47.0 V is given by:
Q2 = C2V2 = (3.2 microF)(47.0 V) = 150.4 microC
The additional charge that flows into the capacitor is equal to the difference between the final and initial charges:
ΔQ = Q2 - Q1 = 150.4 microC - 67.2 microC = 83.2 microC
Thus, if the potential difference across the capacitor is increased from 21.0 V to 47.0 V, an additional 83.2 microC of charge will flow into the capacitor.
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The energy transfer diagram shows energy transfers in an MP3 player. Useful energy is transferred away from the MP3 player by light and... what else?
Useful energy is transferred away from the MP3 player by light and sound.
What is the law of conservation of energy?
The law of conservation of energy states energy can neither be created nor destroyed but can be transformed from one form to another.
This implies that energy can be converted from one form to another such as;
kinetic energy to potential energypotential energy to kinetic energyelectrical energy to mechanical energy chemical energy to electrical energymechanical energy to electrical energylight energy to heat energyelectrical energy to lightelectrical energy to sound energylight energy to heat energysolar energy to light energyhydro energy to electrical energy, etcThe MP3 player uses the energy from electricity supplied to it to play music. The basic energy conversion process that occurs to achieve this include;
electricity → light energy → sound energy → heat energy.
Thus, MP3 player conserves energy by converting the energy supplied to it into useful energy.
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A bowling ball and a tennis ball are dropped separately in such a way that both have the same kinetic energy when they hit the ground. Were they dropped from the same height or a different height? If the latter, which one was dropped from a higher point ?
Answer:Combust Methane
Reaction
Explanation:Seperate
5.1 5.2 5.3 QUESTION 5 (Start on a new page.) A skier of mass 60 kg skies from rest down a slope inclined at an angle of 15°. The length of the incline is 75 in. He reaches the end of the clined at a velocity of 15 m-s¹. A constant frictional force acts on the skier on his way down. 15:... 75 m Write down an expression for the magnitude of the normal force acting on the skier and then calculate its magnitude. Draw a labelled free-body diagram showing ALL the forces acting on the skier as he skies down the slope. Calculate the average frictional force acting on the skier during his motion down the incline. (2) (3) (7) [12]
The frictional force that is acting on the object is 91N
What is a free body diagram?The normal force can be obtained from the equation mgcosθ. The magnitude of the normal force is;
F = 60 * 9.8 * cos 15
F = 568 N
To obtain the moving force, we must get the acceleration from;
v^2 = u^2 - 2as
Since v = 0
u^2 = 2as
a = u^2/as
a = (15)^2/2 * 75
a = 1.5 m/s^2
Then F = ma
F = 60 * 1.5 = 90 N
The coefficient of friction is 90 N/568N
= 0.16
Frictional force = μmgcosθ
Frictional force = 0.16 * 568
= 91 N
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A proton follows the path shown in (Figure 1) . Its initial speed is v0 = 1.8×106 m/s .
Part A
What is the proton's speed as it passes through point P? Express your answer to two significant figures and include the appropriate units
Incorrect; Try Again; 4 attempts remaining Enter your answer using dimensions of velocity.
The proton's speed as it passes through point P is Vp = 1.72 × 10^6 m/s
What is a proton?A proton is described as a stable subatomic particle, symbol p , H⁺, or ¹H⁺ with a positive electric charge of +1 e elementary charge.
From the question have the following parameters
A fixed charge, Q = -10 nC
Initial position of charge particle, proton (q), ro = 3mm
Final position of charge particle, proton (q),
rp = 4mm
Initial velocity of charged particle,
vo =2.8 x 10^6 m/s
Let
vp be the final speed of proton
We then Apply conservation of Energy:
Initial (Potential + kinetic) Energy = Final (Potential + kinetic) Energy
kQq ro + 1/2mVo² = kQq rp + 1/2mVp²
m = 1.67 x 10^-27
Substituting the values and converting from mm to meters, we have that)
Vp = 1.72 × 10^6 m/s
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ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. In working this problem, assume the value of "g" to be 9.8 m/s2 with two (2) significant digits unless otherwise stated. One complete wave passes a putrefying pile of poached pickerel in 0.50 seconds. The piled pickerel protrude 20 cm along the beach. Calculate its velocity. _____ cm/s 5.0 20. 10. 40.
Answer: 40 cm/s.
Explanation:
To solve this problem, we need to use the formula for velocity, which is velocity = distance/time.
We are given the time it takes for one wave to pass the pile of pickerel as 0.50 seconds and the distance that the pickerel protrude along the beach as 20 cm. Plugging these values into the formula gives us:
velocity = distance/time
= 20 cm / 0.50 s
= 40 cm/s
Since we are given the value of g with two significant digits, we should round our answer to the nearest whole number, giving us 40 cm/s.
At what separation will two charges, each of magnitude 6.0 μC, exert a force of 0.70 N on
each other?
The given magnitude of the two charges are 6μc and they exert a force of 0.7N on each other. We need to find the distance of separation between the particles.
By Coloumb's Law :-
[tex]\sf\longrightarrow F =\dfrac{1}{4\pi\epsilon_0} \dfrac{q_1q_2}{r^2} [/tex]
where
q1 and q2 are the two charges r is the distance of separation1/4πe0 = 9 * 10⁹Substitute the respective values,
[tex]\sf\longrightarrow [/tex] 0.7 = {(9*10⁹) (6*6) (10-⁶ *10-⁶) }/ r²
[tex]\sf\longrightarrow [/tex] r² = (36*9 * 10-³)/0.7
[tex]\sf\longrightarrow [/tex] r =√{ 36*9*10-³)/√7 m
[tex]\sf\longrightarrow [/tex] r = 6* 3* 10-¹ /√70 m
[tex]\sf\longrightarrow [/tex] r = 0.21 m
And we are done!
2. You are kite-surfing and your kite is pulling
you upwards at an angle of 60° with respect to
the ocean, with a force of 1200 Newtons. What
component of that force is up? How much of it
is sideways, parallel to the water?
The upward component of that force is 1039.23 N.
The parallel component of that force is 600N.
What is force?The definition of force in physics is: The push or pull on a massed object changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body.
The magnitude of force = 1200 Newtons.
Angle with respect to the ocean = 60°.
The upward component of that force is = F sin60° = 1200×sin60° N = 1039.23 N.
The parallel component of that force is = F cos60° = 1200× cos60° N = 600N.
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Obviously, most of Ms. Kontos’s students have not learned what she thought she had taught them about human vision.
Explain why many students believe the opposite of what Ms. Kontos has taught them. Base your response on contemporary principles and theories of learning and cognition.
Describe two different ways in which you might improve on this lesson to help students gain a more accurate understanding of human vision. Base your strategies on contemporary principles and theories of learning and cognition.
It is possible that students may have misunderstood the information taught by Ms. Kontos about human vision due to various factors such as prior knowledge, attention, motivation, and the way the information was presented.
How to improve on learning accuracy?To improve on this lesson and help students gain a more accurate understanding of human vision, two strategies based on contemporary principles and theories of learning and cognition are:
Incorporating visual aids and hands-on activities: By using visual aids such as diagrams, videos, and animations, students can better understand the complex processes involved in human vision. Hands-on activities such as creating simple models or simulations of the eye can also help students connect what they have learned to real-life situations.
Encouraging metacognition: Encouraging students to think about their own thinking processes, or metacognition, can help them understand their own learning style and identify areas where they need further clarification. By encouraging students to ask questions, discuss what they have learned, and reflect on their own understanding, they can build a more accurate understanding of the topic.
These strategies can help students gain a deeper and more accurate understanding of human vision and improve their learning outcomes.
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Paul exerts a force of 375 N to pull a rope 4.20 m. The rope is attached to a block and tackle (A system of multiple pulleys) which lifts a 1345 N weight to a height of 0.975 M above the floor.
A: How much work does Paul do?
B: What is the work done on the object by the block and tackle
C: What is the mechanical advantage of the block and tackle
D: How efficient is the system?
(a) The work done by Paul is 1,575 J.
(b) The work done on the object by the block and tackle is 1,311.38 J.
(c) The mechanical advantage of the block and tackle is 3.59.
(d) The efficiency of the system is 83.26%.
What is the work done by Paul?The work done by Paul is calculated as follows;
W = F x d
where;
F is the force applied by Pauld is the distance travelled by the effortW = ( 375 N ) x ( 4.2 m )
W = 1,575 J
The work done on the object by the block and tackle is calculated as follows;
W = L x d
where;
L is the loadd is the distance travelled by the loadW = ( 1345 N ) x ( 0.975 m )
W = 1,311.38 J
The mechanical advantage of the block and tackle is calculated as follows;
M.A = Load / effort
M.A = ( 1345 N ) / ( 375 N )
M.A = 3.59
The efficiency of the system is calculated as follows;
E = ( output work / input work ) x 100%
E = ( 1,311.38 J / 1,575 J ) x 100 %
E = 83.26 %
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Where are simple sugars and amino acids absorbed into blood capillaries? Where are lipids absorbed into lacteals?
Simple sugars and amino acids are absorbed into the blood capillaries of the small intestine. Lipids, on the other hand, are absorbed into the lacteals of the small intestine. The lacteals are small, specialized tubes that are part of the lymphatic system and are responsible for transporting absorbed lipids away from the small intestine and into the bloodstream.
Answer:
small intestine
Explanation:
After digestion, absorption of amino acid takes place in the small intestine which is a principal organ for the absorption of nutrients. The capillaries of villi collect the amino acid and sugars taken up by the villi into the bloodstream through diffusion. Villi are meant for absorption in the small intestine.
1.
The temperature of the melting point of ice and that of boiling point of water
at normal atmospheric pressure are marked 40 and 200
respectively on a
certain thermometer. What is
a.
b.
the temperature
the thermometer
on this thermometer
is 80.
temperature is 60°C. Ans: 25°C, 136
in °C when the reading
reading when the
Answer:
I believe this is what you was asking for.
Explanation:
A. The temperature in °C when the reading on the thermometer is 80 is 60°C.
B. The reading when the temperature is 60°C on this thermometer is 136.
question 1 - A certain type of glass is used in making flat-panel computer monitors. For light with a wavelength in air of 656.3 nm, the refractive index of the glass is nA = 1.5160. For light with a wavelength in air of 435.8 nm, nB = 1.5290. Determine the difference, lA - lB, in their wavelengths inside the glass.
The difference in the wavelength of the lights in the glass is 147.88 nm.
What is the difference in their wavelengths inside the glass?The difference in their wavelengths inside the glass is calculated by applying the following formula as shown below.
The wavelength of light A inside the glass is calculated as;
nA = ( 656.3 nm ) / ( 1.516 )
nA = 432.9 nm
The wavelength of light B inside the glass is calculated as;
nB = ( 435.8 nm ) / ( 1.529 )
nB = 285.02 nm
difference in wavelength = 432.9 nm - 285.02 nm = 147.88 nm
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Two people are playing a game of tug a war with the rope attached to a mass of 25 kg at the center. The person pulling to the left pulls with force of 20 N. The person pulling to the right pulls with a force of 10 N.
Answer: To determine the acceleration and direction of the mass, we need to consider the net force acting on the mass. The net force is calculated by subtracting the force to the right from the force to the left:
Net force = 20 N - 10 N = 10 N to the left
Using Newton's second law (F = ma), we can determine the acceleration of the mass:
a = F / m = 10 N / 25 kg = 0.4 m/s² to the left
So the direction of the acceleration and the net force are to the left, which means the mass will move to the left.
Explanation:
Answer: What will happen is that that it will go to the left and it is because the person on the left is pulling harder than the person on the right.
Explanation: I have my ways :>
Have a great day!
How much work is done in accelerating a 2000 kg car from rest to a speed of 30 m/s?
Total work done is 900KJ.
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.Work and energy are closely related to each other. Work can also be defined as the transfer of energy. In Physics, for two objects, the work done is defined as the transfer of energy from the first object to the second object. Also, energy is defined as the capacity to do work.Work Energy Principle: The change in kinetic energy of a body is equivalent to the net work done on the body.Here, Kinetic energy of car at rest is 0.
When it accelerates from rest to a speed of 30 m/s, it's kinetic energy is :
K.E = 1/2mv^2
Given, m = 2000Kg and v = 30 m/s
Putting these values in above equation, we get: K.E = 900000J = 900 KJ
We know that Work done is change in Kinetic energy.
So, W = 900KJ
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A student is conducting an experiment to compare the resistivity of two unknown materials by using two wires, each made of one of the materials and each connected in circuit: The student measures the potential difference across and current in the wires. Which of the following must be the same to be able to compare the resistivities using just the potentia difference and current measurements? Select two answers The length of each wire The cross-sectional area of each wire The potential difference across each wire The current in each wire
The length of each wire and the cross-sectional area of each wire must be the same to be able to compare the resistivities using just the potential difference and current measurements.
According to reports, a student is utilizing two wires, each constructed of one of the materials and connected in a circuit, in an experiment to compare the resistivity of two unknown materials. The student is allegedly measuring the potential difference across and current in the wires. Using only the potential difference and the current measurement, we may compare the resistivity. As resistivity is directly proportional to length of wire and area of cross section we can say it is necessary to maintain these both measurements same as to keep the resistivity same.
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To compare the resistivities using only the potential difference and current measurements, each wire's length and cross-sectional area must be the same.
What is the wire's resistance?A wire's resistance is directly inversely correlated with its cross-sectional area and directly correlated with its length. Resistance is also influenced by the conductor's substance. A conductor's or circuit element's resistance typically rises as temperature rises.
How does the resistance of a wire vary with the size of its cross-section?It is inversely related to the wire's cross-sectional area. The resistance decreases with increasing wire cross section area and increases with decreasing cross section area.
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The bucket shown below is lifted with 3 forces. Determine the force F¯2
that such that the resultant force is vertical with a magnitude of 373.15 N (resultant force points straight up). You are not given F2 or F3, but F1=249 N, θ2=26∘ and θ3=28∘, θ3=(arccos(5/3))
Answer:
220.87 N.
Explanation:
To determine the force F2 that is needed to balance the other forces and create a vertical resultant force with a magnitude of 373.15 N, we can use the principle of vector addition.
We know that the force F1 = 249 N acts at an angle of θ1 = 90° (upwards) relative to the horizontal.
We also know that F2 and F3 act at angles of θ2 = 26° and θ3 = 28° (arccos(5/3)) respectively, relative to the horizontal.
We can represent the forces F1, F2 and F3 using their horizontal and vertical components, using the following relationships:
F1x = F1 * cos(90) = 0 N
F1y = F1 * sin(90) = 249 N
F2x = F2 * cos(θ2)
F2y = F2 * sin(θ2)
F3x = F3 * cos(θ3)
F3y = F3 * sin(θ3)
the horizontal and vertical components of the resultant force, R, are the sum of the horizontal and vertical components of the individual forces.
Rx = F1x + F2x + F3x = F2 * cos(θ2) + F3 * cos(θ3)
Ry = F1y + F2y + F3y = F2 * sin(θ2) + F3 * sin(θ3) + 249 N
We know that the magnitude of the resultant force, R, is equal to 373.15 N and it is pointing upward (Ry direction)
R = sqrt(Rx^2 + Ry^2) = 373.15 N
Rx = 0 N (horizontal component is 0)
Ry = 373.15 N
From this equation and the fact that we know the value of F1y, we can find the value of F2y
F2y = Ry - F1y = 373.15 N - 249 N = 124.15 N
Using the equation of F2y = F2 * sin(θ2) we can find the value of F2
F2 = F2y / sin(θ2) = 124.15 N / sin(26) ≈ 220.87 N
So the force F2 that such that the resultant force is vertical with a magnitude of 373.15 N is 220.87 N.
It's worth to note that since the horizontal component of the resultant force (Rx) is 0, we don't know the value of F3 and it's not possible to find it.
A motorboat going downstream overcame a raft at a point A; Ï„=60min later it turned back and after some time the raft is at a distance l=6.0km from the point A. Find the flow velocity in km/h assuming the duty of the engine to be constant.
The flow velocity in km/h is 3 km/hr if the engine duty remains constant.
What is velocity?The direction of movement of the body or item is defined by velocity. Speed is fundamentally a scalar number. Velocity is, in essence, a vector quantity. It is the pace at which distance changes. It is the displacement rate of change.
Here,
Now, let's assume the velocity of boat to be v in still water.
While going down stream its velocity will be v + u
Velocity of boat relative to raft => v + u - u = + v after 1 hr distance between them will be v km.
In 1 hr raft moved by u× 1 = u km
Now while coming back
vb = -(v - u)
vr = + u
vb/r = - (v - u) - u = - v
So we see here that the relative velocity of boat with respect to raft is same as while going downstream or upstream both.
distance between them = v km.
So time in which they meet =
v/v=1 hr
So in next 1 hr they meet at some point,which will be 6 km away from A
Also in next 1 hr the raft would have traveled another u km. so total distance of meeting point from A in 2u = 6 ⇒ u = 3 km/hr
Flow velocity = speed of raft = 3 km/hr
The flow velocity in km/h assuming the duty of the engine to be constant is 3 km.
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1. A 63.2 kg mountain climber, carrying a 16.4 kg backpack, hikes up to a base camp in
preparation for a climb the next day. If she climbs a vertical distance of 1.75 km, how
much gravitational potential energy has she gained?
Answer:
1,365,140J
Explanation:
The mountain climber has gained 1365170 joule gravitational potential energy.
What is potential energy?Potential energy is the energy that an object possesses as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
Mass of the mountain climber: M= 63.2 kg.
Mass of his backpack: m = 16.4 kg.
Total mass of the mountain climber and his backpack: (M+m)
= 63.2 kg +16.4 kg
= 79.6 kg.
Vertical distance: h = 1.75 km = 1750 m.
Hence, the gravitational potential energy, she has gained = (m+M)gh
= 79.6 kg × 9.80 m/s² × 1750 m.
= 1365170 joule.
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the amount or length of a vector is called its what
A. scalar
B. Direction
C.Magnitude
D.Vector
Answer:
C.Magnitude
Explanation:
Because Vector means that a thing have direction and magnitude.
38. Which of the following is true about all or non-rule?
A) Can be applied on whole heart.
B) Minimal stimulus produces minimal response.
C) A minimal stimulus produces a maximal response.
D) The nerve trunk either responc maximally or not respond at all.
E) The response in a single nerve fiber increases with increase intensity of
stimulus.
The nerve trunk either response maximally or not respond at all. - this is true about all or non-rule. Option (D) is correct.
What is all-or-non law?
The all-or-none law in physiology states that a single nerve fiber will always respond maximally to stimulation and generate an electrical impulse with a single amplitude.
The height of the impulse will remain constant even if the stimulus's intensity or duration are raised. The nerve fiber either responds fully or not at all.
Thus, either the nerve trunk responds fully or not at all.
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A squirrel pushes a 1.1 kg Apple that is initially at rest on the ground. The net force on the Apple varies with time as shown below. What is the apple’s change in momentum between 0 ms and 20 ms?
The net force is defined as the total of all forces acting on an object. A mass can accelerate thanks to net force.
What is a net force?According to its definition, the net force is the total of all the forces operating on an object. Mass can be propelled forward by net force. In motion or at rest, another force exerts its influence on the body. When a system contains a sizable number of forces, the term "net force" is employed.
All of the forces that are applied to an object are added up to form the net force. In other words, the net force is the sum of all the forces, taking into mind that a force is a vector and that two forces that have the same magnitude but facing the opposite direction will cancel each other out.
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Please help!!
What is the impulse needed to completely stop a 1300 kg car that's driving at 18
m/h?
Impulse needed to stop the 1300 kg car driving at a speed of 18 km/h or 5 m/s is 6500 kg m/s.
What is impulse?Impulse of a moving body is the change in its momentum. The ability to make the applied force increasing the displacement of a body is called its momentum. It is the product of mass and velocity of the body.
Impulse is the product of force and time. Here, the impulse we need to calculate is required to stop the car. Hence the final momentum is zero.
Given = 1300 kg
velocity = 18 km/h = 5 m/s
then initial momentum = 1300 kg × 5 m/s = 6500 kg m/s.
Final momentum = 0
thus, impulse = 6500 kg m/s - 0 = 6500 kg m/s
Therefore, the impulse of the car needed to stop it is 6500 kg m/s against the momentum.
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C=59(F−32)The equation above shows how temperature F, measured in degrees Fahrenheit, relates to a temperature C, measured in degrees Celsius. Based on the equation, which of the following must be true?
A. temperature increase of 1 degree Fahrenheit is equivalent to a temperature increase of 59 degree Celsius.
B. temperature increase of 1 degree Celsius is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
C. temperature increase of 59 degree Fahrenheit is equivalent to a temperature increase of 1.8 degrees Fahrenheit.
As a result, claim I is accurate. According to this formula, a temperature increase of 1 degree Celsius is comparable to a temperature increase of 9/5 degrees Fahrenheit.
0F and 0C stand for what?The Celsius scale, sometimes known as the centigrade scale, is a temperature scale based on the water's freezing point at 0°C and boiling point at 100°C. A temperature scale called the Fahrenheit scale is based on the fact that water freezes at 32°F and boils at 212°F.
Why convert 95 degrees Celsius to degrees Fahrenheit?The relationship between Celsius and Fahrenheit is inversely proportional. The temperature on the Fahrenheit scale rises as the temperature does on the Celsius scale, and vice versa. The change from C to F is therefore 100/180, or 5/9. It is 180/100 or 9/5 from F to C.
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A cat with a mass of 4.50 kilograms sits on a ledge 0.800 meters above the ground. If it jumps to the ground, how much kinetic energy will it have just as it reaches the ground?
The kinetic energy of the cat of mass 4.5 kg just as it reaches the ground is 35.28 J.
What is kinetic energy?This is the energy a body acquire during motion.
To calculate the kinetic energy the cat will have just as it reaches the ground.
Note: As the cat is about to reache the ground, all the potential energy is converted to kinetic energy.
Formula:
K.E = mgh.................. Equation 1Where:
K.E = Kinetic energym = Massg = Acceleration due to gravityh = HeightFrom the question,
Given:
m = 4.5 kgh = 0.8 mg = 9.8 m/s²Substitute these values into equation 1
K.E = 4.5×0.8×9.8K.E = 35.28 J.Hence, the kinetic energy of the cat is 35.28 J.
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The position
Of a body is described by S= t^3-2t + 5 find v in m/s when t=3s
Four very long straight parallel wires, located at the corners of a square of side l, carry equal currents Io perpendicular to the page as shown in Figure. Determine the magnitude and direction of B at the center C of the square.
The magnitude and direction of B at the center C of the square is
2µNIo/πL on every corner of square.
Given that four long straight parallel wires, located at the corners of a square carry equal currents perpendicular to the page.
Side of a square = L
current in square wire = Io
Here C is located at the center then distance from any corner point to center C be r. Here r acts as the hypotenuse such that r = L/√2
We know that electric field (B) = NI/2πr and is same at every point on square. Ba = Bb = Bc = Bd
B = µNIo/2π(L/√2)
B = √2µNIo/2πL
Bnet = 4 x Bcos45 = 4 x √2µNIo/2πL x 1/√2
Bnet = 2µNIo/πL
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how did the charm quark get its name?
The charm quark got its name because it was the third type of quark discovered, after the up and down quarks. The naming convention for quarks is that they are named based on the order in which they were discovered. The first quark to be discovered was the up quark, followed by the down quark, and then the charm quark. The "charm" name was chosen as a playful reference to the way the particle was discovered, as well as its role in the symmetry of the strong nuclear force.
What is a nuclear force?The nuclear force is the force that holds the protons and neutrons in the nucleus of an atom together. It is a very strong force, much stronger than the electromagnetic force that holds the electrons in their orbits around the nucleus. The nuclear force is responsible for the stability of atomic nuclei and for the energy released in nuclear reactions. It is a short-range force, acting only over distances of about 1 to 2 femtometers (10^-15 meters).
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Imagine two charged objects on the y-axis. The first object has charge Q = + 3 μC and is located at y = 6 cm. The second object is located at y = 3.0 cm. If the force on the second object is 32.16 N and points in the positive y direction, what is the charge on the second object (in microcoulombs)?
(round to nearest hundredth)
Two charged objects are on the y axis. The first object has a charge of Q = + 3 μC and is located at y = 6 cm, and the second object is located at y = 3.0 cm, so the charge on the object is 0.36 μC or 0.40 μC.
What is the significance of the charge on the object?The charge on the object is dependent upon many factors, and to calculate the charge, Coulomb's Law is applied, which is F=kQq2/[tex]{r}^2[/tex], as here the r = 3 cm, Q = 3 μC, F = 32.16 N, k= 9×[tex]{10}^9[/tex] [tex]{Nm}^2/{c}^2[/tex] . So the q2 is derived from this and that is the charge.
Hence, two charged objects are on the y axis. The first object has a charge of Q = + 3 μC and is located at y = 6 cm, and the second object is located at y = 3.0 cm, so the charge on the object is 0.36 μC.
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