We have the following:
The intersection with the x-axis is when the value of y is 0, that is, the computer already has a value of 0 and has no commercial value.
we found it like this
[tex]\begin{gathered} 0=-400x+4000 \\ 400x=4000 \\ x=\frac{4000}{400} \\ x=10 \end{gathered}[/tex]which means that in 10 years, the computer does not represent a commercial value
to calculate the number of years that have passed when the computer has a value of 2000, y = 2000, therefore we replace
[tex]\begin{gathered} 2000=-400x+4000 \\ 400x=4000-2000 \\ x=\frac{2000}{400} \\ x=5 \end{gathered}[/tex]This means that in a total of 5 years the value of the computer will be $ 2000
in the diagram the figures are simular, what is x?triangle with 30cm and 13cmtriangle with 24cm and x
If the figures are similar, the proportion between the corresponding sides is the same.
The side of 30 cm corresponds to the side of 24 cm, and the side of 13 cm corresponds to the side of x cm.
So if the proportion is the same, we have that:
[tex]\begin{gathered} \frac{30}{24}=\frac{13}{x} \\ 30\cdot x=24\cdot13 \\ x=\frac{24\cdot13}{30}=\frac{4\cdot13}{5}=\frac{52}{5}=10.4 \end{gathered}[/tex]So the value of x is 10.4 cm, therefore the answer is b.
What is the smallest degree of rotation that will map a regular 96-gon onto itself? ___ degrees
The smallest degree of rotation is achieved through the division of the full circumference over the total number of sides
[tex]\frac{360\text{ \degree}}{96}=3.75\text{ \degree}[/tex]The answer would be 3.75°
The post office offers flat-rate mailing of packages: $1.50 for a package weighing less than 4 oz, $2.50 for a package weighing 4 oz to less than 8 oz, and $3.50 for a package weighing 8 oz to 12 oz. write an equation that would represent the situation.
To solve the problem, we will define a function that given the weight of the package, will determine the cost of the mailing. Let x be the weigth of the package in oz and let f(x) be the cost of mailing the package. We are told that if the weight is less than 4, then the rate is 1.50. So, in math notation that would be f(x) = 1.50 if x<4. Now, we are told that if the package weights between 4 and less than 8, then the rate is 2.50. So, that is f(x) = 2.50 if 4<=x<8. Finally, we are told that if the package weights between 8 and 12, the cost is 3.50. So f(x) = 3.50 if 8<=x<=12. So the final math expression for f(x) is
1.50 if x<4
f(x) = 2.50 if 4<=x<8
3.50 if 8<=x<=12.
30 randomly selected students took the statistics final. If the sample mean was 84, and the standard deviation was 12.2, construct a 99% confidence interval for the mean score of all students
The confidence interval for the mean score of the 30 randomly selected students is: 99% CI {78.26, 89.73}
What is confidence interval?Confidence interval is the range of values for which which is expected to have the values at a certain percentage of the times.
How to construct a 99% confidence intervalGiven data form the question
99% confidence interval
30 randomly selected students
mean sample = 84
Standard deviation = 12.2
Definition of variables
confidence level, CI = 99%
mean sample, X = 84
standard deviation, SD = 12.2
Z score, z = 2.576
from z table z score of 99%confidence interval = 2.576sample size, n = 30
The formula for the confidence interval is given by
[tex]CI=X+Z\frac{SD}{\sqrt{n} }[/tex] OR [tex]CI=X-Z\frac{SD}{\sqrt{n} }[/tex]
[tex]=84+2.576\frac{12.2}{\sqrt{30} }[/tex]
=[tex]=84+2.576*2.2274[/tex]
= 84 + 5.7378 OR 84 - 5.7378
= 89.7378 OR 78.2622
= 89.73 to 78.26
The confidence interval for the mean score of all students is 78.26 to 89.78
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Can anybody help me out with this? I would really appreciate it! I don't need a huge explanation just the answer and a BRIEF explanation on how you got it.
The range of the following function is
[tex]\mleft\lbrace y>1\mright\rbrace[/tex]We can also call the range of a function an image, the range or image of a function is a set, we can see this set looking at the graph and see which values of y the function have, remember that we can have the same y value for different x value, looking at our graph we can see that this function comes from high y values, have a vertex on (3,1), in other words, it stops at y = 1 and then start growing again, and go on repeated values of y, then we can say that the image (values of y that the function assumes) is all values bigger than 1, therefore {y > 1}.
I need help with this question can you please help me
Given the following question:
[tex]\begin{gathered} x^2+3x-5=0 \\ \text{ Convert using the quadratic formula:} \\ x^2+3x-5=0=x_{1,\:2}=\frac{-3\pm\sqrt{3^2-4\cdot\:1\cdot\left(-5\right)}}{2\cdot\:1} \\ x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1} \\ \text{ Solve} \\ 3^{2}-4\times1(-5) \\ 1\times-5=-5 \\ 3^2-4\times-5 \\ 3^2=3\times3=9 \\ =29 \\ =\sqrt{29} \\ x_{1,\:2}=\frac{-3\pm \sqrt{29}}{2\cdot \:1} \\ \text{ Seperate the solutions:} \\ x_1=\frac{-3+\sqrt{29}}{2\cdot \:1} \\ x_2=\frac{-3-\sqrt{29}}{2\cdot\:1} \\ \text{ Simplify} \\ 2\times1=2 \\ x=\frac{-3+\sqrt{29}}{2} \\ x=\frac{-3-\sqrt{29}}{2} \end{gathered}[/tex]Your answers are the first and second options.
how many millielters are in 1/5 liters
We know,
1 liter=1000 milliter.
So, millilters in 1/5 liters is,
[tex]\frac{1}{5}liter\times\frac{1000\text{ milliter}}{1\text{ liter}}=200\text{ milliter}[/tex]Therefore, there are 200 milliters in 1/5 liters.
hailey is going to rent an apartment for $864 a month in addition to the first month's rent when moving in a security deposit of $216 is required what will be the total payments required when moving in
We are given that a total amount is $864, if a deposit of $216 is given, then the total amount to pay is the following:
[tex]864-216=648[/tex]Therefore, there is $648 to pay.
Katie opened a savings account and deposited 1,000.00 as principal the account earns 4% interest compounded quarterly what is the balance after 6 years
P = $1000
r = 4% = 4/100 = 0.04
t = 6 years
Therefore,
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=1000(1+\frac{0.04}{4})^{4\times6} \\ A=1000\times1.26973464853 \\ A=1269.73464853 \\ A=\text{ \$1269.73} \end{gathered}[/tex]Do the data in the table you made support the notion the arch is not a parabola? Explain why.
The parabola that has the height and width similar to the Gateway arc, gives;
(a) The quadratic equation of the parabola is presented as follows;
[tex] f(x) = -6.991 \times 10^{-3} \cdot x^2 + 4.181 \cdot [/tex]
(b) The completed table is presented as follows;
Width. Height
567. 63.12
478. 225.67
308. 459.2
What is the shape of the graph of a quadratic function?The shape of a quadratic function is a parabola, which is either upward facing or downward facing
(a) The given dimensions of the arc are;
Height = 625
Width at the base = 598
The points on the parabola are therefore;
(0, 0), (598÷2, 625) = (299, 625), (598, 0)
The equation of the parabola is of the form;
f(x) = a•x² + b•x + c, which gives;
f(0) = 0 = a×0² + b×0 + c = c
c = 0
f(299) = 625 = a×299² + b×299 + 0...(1)
f(598) = 0 = a×598² + b×598...(2
(a×598² + b×598) - 2×(a×299² + b×299) = 0 - 2×625
a•178802 = -2×625
a = -2×625 ÷ 178802
a ≈ -6.991 × 10^(-3)
b ≈ 4.181.
The equation is therefore;
[tex] f(x) = -6.991 \times 10^{-3} \cdot x^2 + 4.181 \cdot [/tex]
(b)
The table of values is completed as follows;
When the width is 567 feet, x = 299 - 567÷2 = 15.5
[tex] \displaystyle{f(15.5) = -6.991 × 10^{-3} \times 15.5² + 4.181 \times 15.5 approx 63.12} [/tex]
When the width is 478 feet, x = 299 - 478÷2 = 60
[tex] \displaystyle{f(60) = -6.991 × 10^{-3} \times 60² + 4.181 \times 60 approx 225.67} [/tex]
When the width is 308 feet, x = 299 - 308÷2 = 145
[tex] \displaystyle{f(145) = -6.991 × 10^{-3} \times 145² + 4.181 \times 145 approx 459.2} [/tex]
The table is therefore presented as follows;
Width. Height
567. 63.12
478. 225.67
308. 459.2
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A batting cage charges a flat fee of $5 to practice and th Write an equation that models the charges (C) in terms of the number of bucket balls (b) that you use: O C = 1.50 b + 5 O C = 5 b + 1.50 6 Ob = 1.60 C + 5 Ob = 5 C + 1.50
we have
C -----> total charge
b -----> number of buckets of balls
Remmeber that
the equation of the line in slope intercept form is equal to
y=mx+b
where
m is the slope and b is the initial value or y-intercept
In this problem
m=$1.50 per buckey
b=$5
therefore
y=1.50x+5
or
C=1.50b+5
answer is first optionFind the maximum value:13, 18, 27, 12, 38, 41, 32, 15, 32
We can find the maximum value by creating a list of the provided numbers from the smallest to the largest.
[tex]12,13,15,18,27,32,32,38,41[/tex]As we see on the list, the last number and the largest is 41. Some tools are used to solve this kind of problem like the diagram of leaves and stems, a table os fre
I need help with this practice problem solving This is the subject trigonometry
Given the fucntion:
f(x) = tanx
Let's graph the function and input the correct values in the box.
• To find the y-intercept of the function, input 0 for x and solve:
[tex]\begin{gathered} f(0)=\tan 0 \\ \\ f(0)=0 \end{gathered}[/tex]Therefore, the y-intercept is:
(0, 0)
• The period of the function:
The fundamental period of a tangent function is π.
Now, let's find points on the graph:
Therefore, the points are:
[tex]\mleft(-\frac{\pi}{3},-\sqrt{3}\mright),\mleft(-\frac{\pi}{4},-1\mright),\mleft(0,0\mright),\mleft(\frac{\pi}{4},1\mright),\mleft(\frac{\pi}{3},\sqrt{3}\mright)[/tex]ANSWER:
The tangent function's period is π . The y-intercept of the function is (0, 0).
The points are:
[tex](-\frac{\pi}{3},-\sqrt[]{3}),(-\frac{\pi}{4},-1),(0,0),(\frac{\pi}{4},1),(\frac{\pi}{3},\sqrt[]{3})[/tex]Find the Z-score for which 5% of the distributions area lies between-z and z
The equation that will represent this situation will be:
[tex]\begin{gathered} P(-z\le x\le z)=P(x\le z)-(1-P(x\le z))=0.05 \\ \end{gathered}[/tex]Thus:
[tex]\begin{gathered} P(x\le z)-1+P(x\le z)=0.05 \\ 2\cdot P(x\le z)-1=0.05 \\ 2\cdot P(x\le z)=0.05+1 \\ 2\cdot P(x\le z)=1.05 \\ P(x\le z)=\frac{1.05}{2} \\ P(x\le z)=0.525 \end{gathered}[/tex]If we check in a standard normal table. the z-score that corresponds to a probability of 0.525 is 0.063.
Answer: z-score is 0.063.
Find the exact value of sin A and cos A where a = 9 and b = 10 and
Given data:
a=9 , b = 10
use the phythagoras theorem,
[tex]c=\sqrt[]{a^2+b}^2[/tex][tex]\begin{gathered} c=\sqrt[]{9^2+10^2} \\ c=\sqrt[]{81+100} \\ =\sqrt[]{181} \end{gathered}[/tex]thus,
[tex]\sin A=\frac{opp}{\text{hypo}}[/tex][tex]\text{sinA}=\frac{9}{\sqrt[]{181}}[/tex]and,
[tex]undefined[/tex]I don’t understand how to get the second x intercept
In this problem
the vertex is given ------> (40/2,12)-------> (20,12)
The first intercept is (0,0)
therefore
second intercept is
x-intercept=20+20=40
(40,0) is the coordinates of the second x-intercept
(the vertex is the midpoint between the first and second x-intercept)
see the attached figure
Write an equation in the form r(x) = p(x) / q(x) for each function shown below.Pls see pic for details
c.
The line equation is of the form
[tex]y=mx+c\ldots(1)[/tex]From the graph, we observe and find these points
(1,5) and (0,4) lie on the given line.
Substituting x=1, y=5 in equation (1), we get
[tex]5=m(1)+c[/tex][tex]m+c=5\ldots\text{.}(2)[/tex]Substituting x=0, y=4 in equation (1), we get
[tex]4=m(0)+c[/tex][tex]c=4[/tex]Substituting c=4 in equation (2), we get
[tex]m+4=5[/tex][tex]m=5-4[/tex][tex]m=1[/tex]Substituting c=4,m=1 in equation (1), we get
[tex]y=x+5[/tex]We need to write this equation in the form of r(x) = p(x) / q(x).
[tex]r(x)=\frac{p(x)}{q(x)}\ldots(3)[/tex]Let r(x)=x+5, q(x)=x, and subsitute in the equation , we get
[tex]x+5=\frac{p(x)}{x}[/tex]Using the cross-product method, we get
[tex]x(x+5)=p(x)[/tex][tex]x\times x+x\times5=p(x)[/tex][tex]x^2+5x=p(x)[/tex]Substitute values in equation (3), we get
[tex]x+5=\frac{x^2+5x}{x}[/tex]Hence the required equation is
[tex]x+5=\frac{x^2+5x}{x}[/tex]Leila runs at 12 mph find the number of miles she can travel if she runs for 2 hours
20 POINTS ANSWER I WILL MARK BRAINLIEST!!!!!!!!!!
Answer: 24 mph
Step-by-step explanation:
If she can run 12 mph/ 12 miles per hour
She runs for 2 hours
12 · 2 = 24
when you isolate the variable, what must you do to keep the equation balanced x-3=7?
Answer:
To isolate the variable, we have to add 3 to both sides of the equation to keep the equation balanced.
So x = 10
Explanation:
Given the below equation;
[tex]x-3=7[/tex]To isolate the variable, we have to add 3 to both sides of the equation to keep the equation balanced;
[tex]\begin{gathered} x-3+3=7+3 \\ x=10 \end{gathered}[/tex]Bill Jensen deposits $8500 with Bank of America in an investment paying 5% compounded semiannually. Find the interest in 6 years
Amount deposited = $8500
Rate = 5%
time for interest = 6years
Compounded semiannually
The formula for semiannually is
[tex]A=P(1+\frac{r}{100n})^{nt}[/tex]From the given information
P = $8500
r = 5
t = 6
Since the investment was compounded semiannually then
n = 2
Substitute the values into the formula
This gives
[tex]A=8500(1+\frac{5}{100\times2})^{6\times2}[/tex]Solve for A
[tex]\begin{gathered} A=8500(1+0.025)^{12} \\ A=8500(1.025)^{12} \\ A=11431.56 \end{gathered}[/tex]To find the interest
Recall
[tex]I=A-P[/tex]Where I, is the interest
Hence
[tex]\begin{gathered} I=\text{\$}11431.56-\text{\$}8500 \\ I=\text{\$}2931.56 \end{gathered}[/tex]Solve the equation 7-(5t-13)=-25-15b+21+5b=-19
Let's solve the following expressions:
a.) 7 - (5t - 13) = -25
[tex]\text{ 7 - (5t - 13) = -25}[/tex][tex]\text{ 7 - 5t + 13 = -25}[/tex][tex]\text{ 20 - 5t = -25}[/tex][tex]\text{-5t = -25 - 20}[/tex][tex]\text{-5t = -4}5[/tex][tex]\frac{\text{-5t}}{-5}\text{ = }\frac{\text{-4}5}{-5}[/tex][tex]\text{ t = 9}[/tex]Therefore, t = 9
b.) -15b + 21 + 5b = -19
[tex]-15b+21+5b=-19[/tex][tex]-10b+21=-19[/tex][tex]-10b=-19\text{ - 21}[/tex][tex]-10b=-40[/tex][tex]\frac{-10b}{-10}=\frac{-40}{-10}[/tex][tex]\text{ b = 4}[/tex]Therefore, b = 4
Please look at the image below. By the way this is my homework.Use the definition of congruence to decide whether the two figures are congruent. Explain your answer. Give coordinate notation for the transformations you use.
Congruent Shapes
Two congruent shapes have the same size and shape, which means all of their side lengths are equal and all of their internal angles are congruent (have the same measure),
All of the rigid transformations map the original figure to a congruent figure. One of the transformations is the reflection.
The image shows two shapes SRQP and EDCB. They seem to have the same shape and size, but it must be proven by finding the appropriate transformation used.
Comparing the corresponding vertices we can find that out. For example, the coordinates of S are (-6,4) and the coordinates of E are (4,4). The x-coordinate of the midpoint between them is
xm = (-6+4)/2 = -1
Now analyze the points P(-8,2) and B(6,2). The x-coordinate of the midpoint is:
xm = (-8+6)/2 = -1
For the points R(-4,-6) and D(2,-6):
xm = (-4+2)/2 = -1
For the points Q(-9,-4) and D(8,-4):
xm = (-9+8)/2 = -0.5
Since this last pair of corresponding points don't have the same axis of symmetry as the others, the shapes don't have the same size and angles, thus they are not congruent
For both shapes to be congruent, the coordinates of Q should have been (-10,-4)
You go to a candy store and want to buy a chocolate
To find the amount of servings, we just need to divide the entire bar weight by the serving weight. Solving this calculation, we have
[tex]\frac{14.8}{2.4}=\frac{37}{6}=6.166666666..\text{.}[/tex]A car travels 273 miles in 6 hours. How muchtime will it take traveling 378 miles
hello
the car travels 273 miles in 6 hours, how many hours will it take to travel 378 miles.
let the number of unknown hours be represented by x
[tex]\begin{gathered} 273mi=6\text{hrs} \\ 378mi=\text{xhr} \\ \text{cross multiply bith sides} \\ 273\times x=6\times378 \\ 273x=2268 \\ \text{divide both sides by 273} \\ \frac{273x}{273}=\frac{2268}{273} \\ x=8.3076\text{hrs} \end{gathered}[/tex]the car spent approximately 8.31 hours to travel a distance of 378 miles
what would be the value if m in a angle on 50 degrees and 10m
50 + 10m = 90 Reason: This is a right angle, which sum up to 90 degree.
10m = 90 - 50
10m = 40
m = 40/10
m = 4
Writing and evaluating a function modeling continuous exponential growth or decay given two outputs
Explanation
The model has the form
[tex]y=ae^{-kt}[/tex]Where a=initial amount
y= final amount
K= growth rate constant
t= time
When 140 kg of substance is left after 7 hours, the formula can be remodeled to be.
[tex]\begin{gathered} 140=400e^{-7k} \\ e^{-7k}=\frac{140}{400} \\ e^{-7k}=\frac{7}{20} \\ \ln (e^{-7k})=\ln (\frac{7}{20}) \\ -7k=\ln (\frac{7}{20}) \\ k=\frac{\ln(\frac{7}{20})}{-7} \\ \therefore k=\frac{\ln (\frac{20}{7})}{7} \end{gathered}[/tex]Therefore, the first solution is
[tex]y=400e^{-\ln (\frac{20}{7})\frac{t}{7}}[/tex]For part b we have 16 hours.
[tex]\begin{gathered} y=400e^{-\ln (\frac{20}{7})\frac{t}{7}}=400e^{-\ln (\frac{20}{7})\frac{16}{7}} \\ y=36.302\approx36\operatorname{kg}\text{ (To the nearest whole number)} \end{gathered}[/tex]Thus, the answer is 36kg
If you are given odds of 5 to 6 in favor of winning a bet, what is the probability of winning the bet?
5 to 6 odds means that, out of 11 possible outcomes, odds are that there will be 5 of one kind of outcome and 6 of another kind of outcome.
In this case, you are given 5 to 6 odds, which means that out of 11 possible outcomes you will win a bet 5 times, and lose it 6.
In fraction, it will look like this:
[tex]\frac{11}{11}\text{ \lparen these are all the possible outcomes, which equals 1\rparen = }\frac{5}{11}(the\text{ outcomes in which you win, which equals .4545, so 45.45\%\rparen + }\frac{6}{11}\text{ \lparen the outcomes in which you lose, which equals 0.5454, so 54.54\% \rparen}[/tex]Because of that, the probability of winning the bet is 45.45%, and in a fraction, it is 5/11, which means you will win in 5 out of 11 scenarios.
(A) The lines have different slopes and intersect at one point?(B) The lines have the same slope and y intercept.?(C) The lines are parallel and do not intersect.?(D) The lines have the same slope and y-intercept.?(E) Infinitely many solutions.?(F) They are the same line.? (G) No Solution ? (H) One solution.?
Recall that if two lines have the same slop then these two lines are parallel to each other.
the y-intercept is an x-coordinate of the point where the line intersects at the y-axis.
Consider graph 1.
The line intersects at one point and has different slopes, hence this has one solution.
(A) and (H) is true for graph 1.
Consider graph 2.
The lines have the same slope, therefore parallel but there is no y-intercept point.
This have infinitely many solutions.
They are also the same line.
(E) and (F) is true for this graph 2.
Consider graph 3.
The lines have the same slope and they are parallel.
It gives B) is correct
They do not intersect since parallel does not intersect each other.
It gives C) is correct
There is no solution since they do not intersect.
It gives G) is correct.
These lines have intercepted at -1 and -4.
It gives D) is correct
B), D), C), G), D) are correct for graph 3.
Results:
Options Graph
A) 1
B) 3
C) 3
D) 3
E) 2
F) 2
G) 3
H) 1
A car's cooling system has a capacity of 20 quarts. Initially, the system contains a mixture of 7 quarts of antifreeze and 13 quarts of water. Water runs into the system at the rate of 1 gal min , then the homogeneous mixture runs out at the same rate. In quarts, how much antifreeze is in the system at the end of 5 minutes? (Round your answer to two decimal places.)
After 5 minutes there will be 2.29376 quarts of antifreeze in the system.
Given,
The capacity of the cooling system of a car = 20 quarts
The mixture in the system is 7 quarts of antifreeze and 13 quarts of water.
The running rate of water = 1 gal/min
Homogenous mixture also runs 1 gal/min
We have to find the antifreeze in the system at the end of 5 minutes;
Here,
1 quart = 0.25 gallons
7 x 0.25 = 1.75 gallons of antifreeze
13 x 0.25 = 3.25 gallons of water
1 = 0.2 of 5
Minute 1 = 1.75 x 0.8 = 1.4Minute 2 = 1.4 x 0.8 = 1.12Minute 3 = 1.12 x 0.8 = 0.896Minute 4 = 0.896 x 0.8 = 0.7168Minute 5 = 0.7168 x 0.8 = 0.573440.57344 gallons = 2.29376 quarts
After 5 minutes there will be 2.29376 quarts of antifreeze in the system.
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If I am in San Juan, then
I am in Puerto Rico.
State whether the following
statement is inverse, converse,
contrapositive.
If I am not in San Juan,
then I am not in Puerto
Rico.
The statement "If I am not in San Juan, then I am not in Puerto Rico." is the inverse and contrapositive statement because it is inverse of "If I am in San Juan, then I am in Puerto Rico."
What is inverse?The inverse function of a function f in mathematics is a function that reverses the operation of f. If and only if f is bijective, then the inverse of f is true. A function that "undoes" another function is called an inverse. In other words, if f(x) produces y, then y entered into the inverse of f produces x. An invertible function is one that has an inverse, and the inverse is represented by the symbol f⁻¹.
What is contrapositive?When you reverse the hypothesis and the conclusion in a statement and reject both of them, you have a contrapositive statement. When the hypothesis and the conclusion are switched in this example and both are negated, the outcome is: If it is not a triangle, then it is not a polygon.
Here,
The statement is "If I am in San Juan, then I am in Puerto Rico."
So the contrapositive and inverse will be:
"If I am not in San Juan, then I am not in Puerto Rico."
Because it is the opposite of "If I am in San Juan, then I am in Puerto Rico," the statement "If I am not in San Juan, then I am not in Puerto Rico" is the inverse and contrapositive statement.
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