D=44.13, Horizontal velocity is unimportant. The time it takes the cannon ball to fall to the ground is the key to determining the height of the cliff. where that cannon is present.
The speed of any projectile travelling along a Horizontal velocity is known as the horizontal velocity. When a particle or object is launched into the air at an angle other than 90 degrees, it moves along the trajectory path and changes the shape of the curve to a parabolic one.
the speed at which velocity changes over time. Due to its magnitude and direction, acceleration is a vector quantity. The first derivative of velocity with respect to time or the second derivative of position with respect to time are further examples. This is called acceleration.
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m.
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Answer: D=44.13, Vertical velocity is not significant. The height of the cliff can be calculated using the time it takes the cannonball to hit the earth. where there is that gun.
Explanation: The horizontal velocity is the rate at which any projectile is moving along a plane. A particle or object that is propelled into the air at an angle other than 90 degrees goes along the trajectory line and transforms the curve's shape into a parabolic one.
the rate of change of velocity over time. Acceleration is a vector number because of its size and directional characteristics. Additional examples are the second derivative of location with respect to time or the first derivative of velocity with respect to time. Here is
Distance to the ground is d = 1/2gt^2,
where g is the acceleration rate of gravity (9.80665 m/s^2)
and t = 3 secs.
d = .5×9.80665×9 = 44.13 m
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Use the velocity vs time graph below for objects A and B to answer the given question.If A has the greater value pick answer choice AIf B has the greater value pick answer choice Bif A = B pick answer choice =.Which object has the greater Instantaneous Velocity at t = 5s?
Given the velocity versus time graph of an object.
From the graph, the velocity of object A is constant as the line representing its velocity is horizontal. The velocity of object a is decreasing with time. That is, object B is decelerating.
From the graph, at t=5 s the value of the instantaneous velocity of object A is 0 m/s.
And the value of the instantaneous velocity of object B is the same throughout the graph. And the value is 4 m/s.
Thus the value of the instantaneous velocity of object B is greater than that of object A.
Thus the correct answer is B has the greater value
Find the coefficient of static friction between the ramp and object with the following
Horizontal length of ramp: 75cm
Vertical length of ramp: 19cm
mass of object: 128g
The coefficient of static friction between the ramp of 75 cm horizontal length and a vertical length of 19 cm and object with a mass of 128 g is 0.25
Since the ramp forms a right angled triangle,
tan θ = Opposite side / Adjacent side
Opposite side = Vertical length of ramp = 19 cm
Adjacent side = Horizontal length of ramp = 75 cm
tan θ = 19 / 75
θ = [tex]tan^{-1}[/tex] ( 0.25 )
θ = 14°
m = 128 g = 0.128 kg
g = 9.8 m / s²
W = m g
W = 0.128 * 9.8
W = 1.25 N
Since the object is in static condition,
∑ [tex]F_{y}[/tex] = 0
N - [tex]W_{y}[/tex] = 0
N - W cos θ = 0
N = 1.25 * cos 14°
N = 1.25 * 0.97
N = 1.21 N
F[tex]_{s}[/tex] = μ[tex]_{s}[/tex] N
F[tex]_{s}[/tex] = Static frictional force
μ[tex]_{s}[/tex] = Co-efficient of static friction
N = Normal force
Since the object is in static condition,
∑ [tex]F_{x}[/tex] = 0
F[tex]_{s}[/tex] - [tex]W_{x}[/tex] = 0
F[tex]_{s}[/tex] = W sin θ
F[tex]_{s}[/tex] = 1.25 * sin 14°
F[tex]_{s}[/tex] = 1.25 * 0.24
F[tex]_{s}[/tex] = 0.3 N
μ[tex]_{s}[/tex] = F[tex]_{s}[/tex] / N
μ[tex]_{s}[/tex] = 0.3 / 1.21
μ[tex]_{s}[/tex] = 0.25
Therefore, the coefficient of static friction between the ramp and object is 0.25
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A 14 kg boulder is pushed off a cliff with velocity v = ( 14.0 m/s ) + ( 2.0m/s ) y . Will the object experience a larger vertical or horizontal acceleration?
The object will eventually experience a large vertical acceleration since the vertical velocity increases as the object moves downwards.
What is horizontal motion of a projectile?The horizontal motion of a projectile is the motion of the projectile along a horizontal path.
The horizontal distance of a projectile is not affected by gravity and hence the horizontal speed of a projectile remains constant. That is the initial horizontal velocity is equal to the final horizontal velocity of the projectile.
However, the during the vertical motion an object, the vertical velocity decreases as the object moves upwards and eventual becomes zero when the object reaches the maximum height.
As the object begins to move downwards the vertical velocity increase and eventually become maximum before the object hits the ground.
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what is the tension in a tow rope that is used to accelerate a 1700-kg car at 0.5 m/s2? (ignore the effects of friction.) a) assuming the tow rope is completely horizontal? b) assuming the tow rope is 400 above the horizontal?
The tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
F = m a
F = Net force
m = Mass
a = Acceleration
m = 1700 kg
a = 0.5 m / s²
∑ [tex]F_{x}[/tex] = m a
T = m a
T = 1700 * 0.5
T = 850 N
b ) Assuming the tow rope is 40° above the horizontal,
θ = 40°
Resolving the tension force into its horizontal component,
Tx = T cos θ
∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]
Tx = 1700 * 0.5
T cos 40° = 850
T = 1103.9 N
Therefore, the tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
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similar to the case in the experiment you use two rubber bands, side to side first, to hold a weight of 3 reference objects. then, as in the experiment, the bands are pulled apart in their free ends until they form an angle of 30 degrees with respect to the horizontal. what are the deformations observed in these bands? ...
Three units deformations observed in these bands.
What forces do a rubber band encounter?Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.
The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.
Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.
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coherent light of frequency is shone through a single slit with a gap width equal to a. an interference pattern is observed on the screen a distance behind the slit. what effect will each of the following alterations have on the width of the central bright spot on the screen? a. decrease the gap width. b. decrease the frequency of the light. c. decrease the distance from the slit to the screen.
Coherent light at this frequency passes through a single slit with an interval width equal to the effect of each of the following changes on the width of the central bright spot on the screen. reduce gap width
Two wave sources are coherent if they have the same frequency and waveform. Interference is an ideal property of waves that allows for fixed interference. The central bright band of the single slit diffraction pattern is generated by constructive interference from all secondary sources.
The width of the center band is inversely proportional to the slot width. Coherence is a fixed ratio between wave phases in a beam of radiation of one frequency. The wavelengths of two rays are coherent when the phase difference is constant. Inconsistent if there are random or changing phase relationships. When two waves are monochromatic and in phase, they are said to be coherent. A coherent source is one that generates those waves. With the help of these waves, you can study the properties of the light path. For this purpose, one beam is transmitted along the intended track, and the other is transmitted to the control test.
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an object is launched from ground level with an initial speed of 24.6 meters/second at an upward angle of 0.595 radians above the horizontal (90 degrees is about 1.57 radians). how far will it travel horizontally before hitting the ground?
The object will travel 55.67 meters horizontally before hitting the ground.
The object is launched with speed 24.6 meters/second.
The angle at which the object is launched is 0.595 radians.
We know,
90° = 1.57 radians
1 radian = 90°/1.57
So,
0.595 radians = 90°(0.595)/1.57
0.595 radians = 34°
The horizontally distance R travelled by the projectile can be given by,
R = U²sin2A/g
Where, U is the initial speed,
A is the angle at which object is launched,
g is acceleration due to gravity,
Putting all the values,
R = (24.6)²sin(68°)/10
R = 55.67 meters.
The horizontal range is 55.67 meters.
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A car starts from rest and reaches a speed of 26 m/s in 8.5 seconds. What is the acceleration of the car? Round to 4 decimal places if necessary
ANSWER
3.0588 m/s²
EXPLANATION
Given:
• The final speed of the car, v = 26 m/s
,• The initial speed of the car, u = 0 m/s - remember that it starts from rest
,• The time it takes the car to reach the final speed, t = 8.5 s
Find:
• The acceleration of the car, a
The speed of an object is given by the equation,
[tex]v=u+at[/tex]In this case, u = 0 m/s, so we have,
[tex]v=at[/tex]Solving for a and replacing the known values,
[tex]a=\frac{v}{t}=\frac{26\text{ }m/s}{8.5\text{ }s}\approx3.0588\text{ }m/s^2[/tex]Hence, the acceleration of the car is 3.0588 m/s², rounded to four decimal places.
a lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline and its light makes four revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p?
A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min
3*10/9*8pi = dx/dt
80pi/3 = dx/dt
dx/dt = 83.78 km/min
Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.
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a 95 kg man lying on a surface of negligible friction shoves a 74 g stone away from himself, giving it a speed of 4.0 m/s. what speed does the man acquire as a result?
As a result of the law of conservation of momentum, the man will acquire a speed of 3 . 10⁻³ m/s
The law of conservation of momentum states thta:
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Where:
u₁ , u₂ = initial velocity of object 1 and object 2
v₁ , v₂ = final velocity of object 1 and object 2
Since both the man and the shove are initially at rest, hence u₁ , u₂ = 0.
Therefore,
m₁v₁ + m₂v₂ = 0
Parameters given:
m₁ = 95 kg
m₂ = 74 gram = 74 . 10⁻³ kg
v₂ = 4 m/s
Plug these parameters into the equation:
95 . v₁ + 74 . 10⁻³ . 4 = 0
v₁ = 3 . 10⁻³ m/s
Hence, the man acquire a speed of 3 . 10⁻³ m/s, which is very small.
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What human activities increase the levels of greenhouse gases released?
Answer: There are many human activities that have negative effects on the environment such as the release of greenhouse gas. Some include; transporting, industry and factories, burning of fossil fuels, agriculture, deforestation, and the release of chemicals into the atomsphere.
Explanation:
Transporting and factories emit gasses such as carbon dioxide, which is toxic and can affect the environment. The burning of fossil fuels also releases carbon dioxide into the air, leading to the massive spread of global warming. Deforestation can lead to less oxygen and more carbon dioxide in the air, and can also cause global warming. Animals can also lose their habitats.
Answer:
humans burn fossil fuels to generate electricity, to keep buildings warm, power cars etc. As a result, waste gases are being produced such as carbon dioxide
Human Activities:
- driving cars, carbon dioxide is released
-burning things e.g wood
-small loads of laundry, wasting
-heating
what is the speed of the block when it has moved a distance of 0.0150 m from its initial position? (at this point the spring is compressed 0.0220 m .)
The speed of the block when it has moved a distance of 0.0150 m from it's initial position is 0.32 m/s .
When a spring is compressed by a force F, the potential energy is stored on it.
If the spring is released, the potential energy turns into kinetic energy.
The object is replaced by the call-back force which occurs on the spring F' = K.∆x
K= 815 N/m
∆x= 0.0190 m
F' = 815.0.019 = 15.8 N
Ff= k.m.g
Ff = 0.35 . 2.55. 9.81 = 8.76 N friction force acceleration of object is-
a= F' - Ff/m
V^2 = 2.a . displacement
V^2 = 2.264. 0.0200.
V^2 = 0.1056
V=√0.1056.
V= 0.32 m/s
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A force of 10 n stretches a particular spring by 2 cm. How far would a 20 n force stretch that same spring?.
For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law
so, 20 N force stretch 4 cm.
What is the Hooke's law ?Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object.It is the fundamental principle underlying the manometer, spring scale, and clock balance wheel. Hooke's law is the underlying principle of seismology, acoustics, and molecular mechanics.Hooke's spring law usually applies to any elastic object of any complexity, as long as the deformation and stress can be expressed by a single number that can be both positive and negative.For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :
F=kx
where
F = Force
k = is spring
constant
x = stretches
here
10/ 2 = 20/ x
x -= 4 cm .
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Mr. Mangan now sees a hoard of zombies running toward him. There are toomany for him to fight, so he makes a run for it. Starting from rest andaccelerating at a rate of 7 m/s2, he reaches a final velocity of 25 m/s. Howmuch time did it take for him to reach his final velocity?
Given data
*The given initial velocity is u = 0 m/s
*The given acceleration is a = 7 m/s^2
*The given final velocity is v = 25 m/s
The formula for the time taken to reach his final velocity is given by the kinematic equation of motion as
[tex]\begin{gathered} v=u+at \\ t=\frac{v-u}{a} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} t=\frac{25-0}{7} \\ =3.57\text{ s} \end{gathered}[/tex]Thus, the time taken to reach his final velocity is t = 3.57 s
when the radius of a circular phase space plot changes, what does this mean? a. momentum is conserved. b. momentum is not conserved. c. energy is not conserved. d. energy is conserved.
Answer is b, momentum is not conserved.
Explanation:
L = r × p
So when the radius of a circular phase space plot changes, the Momentum is not conserved because farther the mass is from the center of rotation, the larger the angular momentum.
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The speed of sound in a particular gas is 675 m/s. A sound wave propagating in this material has a wavelength offifteen meters. What is the frequency of this sound?knowns and unknownsolveright answer
Given, Speed of the sound, v=675 m/s
The wavelength of the wave, λ=15 m
Relation between speed, wavelength, and frequency of a wave is given by
[tex]v=f\lambda[/tex]Where f is the frequency of the sound.
On substituting the known values,
[tex]675=f\times15[/tex]Which gives us,
[tex]f=\frac{675}{15}=45\text{ Hz}[/tex]Therefore the frequency of the sound in the given medium is 45 Hz.
You push with 310N of force to move a 25 kg box across the floor. If the coefficient of kinetic friction between the box and the floor is .21, what is the net force on the box?
The net force will be the difference between the applied force and frictional force which is 258.6 N
What is Force ?Force can be simply defined as push or pull. It is the product of mass and acceleration. It is a vector quantity and it is measured in Newton.
If you push with 310N of force to move a 25 kg box across the floor. If the coefficient of kinetic friction between the box and the floor is .21
The normal force N on the box = mg
N = mg
N = 25 × 9.8
N = 245 N
The frictional force f = μN
where μ = coefficient of friction
f = 0.21 × 245
f = 51.45 N
The net force on the box = F - f
Where F = force applied
f = frictional force
Net force = 310 - 51.45
Net force = 258.6 N
Therefore, the net force on the box is 258.6 N
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What is the acceleration of a car that goes from
rest to 25 m/s in 5.0 s?
Answer:
5 m/s^2
Explanation:
Acceleration is change in velocity / change in time
Accel = 25 m/s / 5 s = 5 m/s^2
Kinetic theory told us that gas particles are moving constantly and bumping into anything in their path. The collisions of these particles in the gas result in ___________ .
a
Energy conversion
b
Pressure
c
Creation of new forms of matter
d
Potential energy
According to the research, the correct option is d. Kinetic theory told us that gas particles are constantly moving and bumping into anything in their path. The collisions of these particles in the gas result in Potential energy.
What is Kinetic theory?It is the model of matter that, starting from the definition of an ideal gas from the point of view, explains the behavior of matter at the molecular level when it is subject to certain conditions.
In this sense, it studies the behavior of molecules and their interactions, where the energy that is capable of being developed during the collision of small particles is first converted into potential energy associated with the position of a body.
Therefore, we can conclude that the kinetic theory explains the interactions that occur in gas particles, where kinetic and potential energy can influence their state.
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in real life, is it possible to replicate the experiment newton is performing in the simulation? can you actually swing a ball in a horizontal circle with a perfectly horizontal string? explain your answer
No, it is not possible to replicate the experiment which Sir Newton had performed .
What is circular motion ?
A circular path is followed by an object as it moves along at a constant speed is termed a circular motion
The wire cannot be completely straight or horizontal, as you might expect given its weight. Gravity (mg) and the tension of the rope are the two forces that are constantly exerting pressure on the ball, ignoring the weight of the rope.
These must have a vector total that is mv2/r in the radial direction. The tension force must have an opposing vertical component in order to balance the vertical gravity pull, hence the rope cannot be perfectly horizontal. The angle will be less as the mass is rotated more quickly. Additionally, the mass moves in a perfectly horizontal motion in the absence of resistive losses. The same holds true if the youngster swinging the rope precisely balances the losses.
What is centrifugal acceleration ?
From inside the automobile, it seems as though you are being pushed out of the turn's centre. The centrifugal force is a hypothetical force. This effect is more pronounced the sharper the curve and the faster you are travelling.
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most interstellar clouds are made mostly of hydrogen (because hydrogen is the most common element in the universe). why are these clouds usually dominated by the color red?
The interstellar clouds that are made mostly of hydrogen are usually dominated by the color red because of its strong visible emission lines
Hydrogen is the most common element in the universe because a hydrogen is a pair of protons and electrons. Since they are oppositely charged they attract each other and it is easier to bond without the need of any external forces.
Red is colour in visible light spectrum with longest wavelength and has the lowest frequency. Because of its longer wavelength it can travel much farther distances than other colours in visible spectrum.
Therefore, these clouds usually dominated by the color red because of its strong visible emission lines
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the circuit breaker that protects a power window circuit opens whenever the window is lowered. technician a says the internal resistance of the motor is too high. technician b says the window regulator may be sticking causing high mechanical resistance. who is correct?
Both technicians A and B are correct. Hence, option C.
An ammeter is used to measure the electrical current in the circuit. An ammeter should be placed into series with the circuit being tested.
The ammeter can be connected either on the power side or on the ground side of the motor but the only condition is it should be connected in the series.
Internal resistance refers back to the opposition to the float of cutting-edge supplied by using the cells and batteries themselves ensuing inside the era of heat. internal resistance is measured in Ohms. the connection among inner resistance (r) and emf (e) of cell s given through. e = I (r + R)
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Disclaimer:- your question is incomplete, please see below for the complete question.
The circuit breaker that protects a power window circuit opens whenever the window is lowered. technician a says the internal resistance of the motor is too high. technician b says the window regulator may be sticking causing high mechanical resistance. who is correct?
A. A only
B. B only
C. Both A and B
D. Neither A nor B
Study the graph shown below. It is a graphic of a car trip taken by Amber and Ken. The starting position (0,0) is their home.
Graph of position versus time, with position on the y axis from 0 to 75 miles and time on the x axis from 0 to 8.5 hours. Segment 1 goes from 0,0 to 1,30. Segment 2 goes from 1,30 to 3,50. Segment 3 goes from 3,50 to 4,50. Segment 4 goes from 4,50 to 5,70. Segment 5 goes from 5,70 to 6,70. Segment 6 goes from 6,70 to 7,30. Segment 7 goes from 7,30 to 8,0.
How far had they traveled after four hours of travel?
a
30 miles
b
40 miles
c
50 miles
d
60 miles
The distance that they had traveled after four hours is given by:
c 50 miles.
How to find the distance traveled?We are given the a set of points (x,y) in this problem, in which the input and the output are defined as follows:
Input: x is the number of hours.Output: y is the distance traveled, in miles, after a time of x hours.The endpoints of the segments are as follows:
(0,0): Initially, 0 miles were traveled.(1,30): 30 miles were traveled in one hour.(3, 50): 50 miles were traveled in three hours.(4,50): 50 miles were traveled in four hours.Hence, the distance that they had traveled after four hours is given by 50 miles, and option c is the correct option in the context of this problem (how long they had traveled).
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Scripture Spotlight: Proverbs 6:6-11
the term sluggard comes from slugs, which move like snails, s-l-o-w-l-y. What is the message of the above passage? Read it in several Bible versions
Answer: A sluggard is someone who is habitually lazy or inactive. Such a person does not take personal responsibility for his own life. The word sluggard is used 14 times in the book of Proverbs. In each case, the Bible condemns laziness and warns of the consequences of being a sluggard.
Proverbs 6:9 asks two rhetorical questions, highlighting one of the main traits of a sluggard: “How long will you lie there, you sluggard? / When will you get up from your sleep?” Verse 6 tells the sluggard to learn a lesson from an industrious insect: “Go to the ant, you sluggard; / consider its ways and be wise!”
Explanation:
a very thin horizontal, 2.00-m long, 5.00-kg uniform beam that lies along the east-west direction is acted on by two forces. at the east end of the beam, a 200-n force pushes downward. at the west end of the beam, a 200-n force pushes upward. what is the angular acceleration of the beam?
The angular acceleration of the beam of length 2 meters and mass 5 kg is 240 radian/s².
The length of the rod is 2 meters, the mass of the rod is 5kg, a force of 200N is applied downward in the east direction while a force of 200N applied upward in west direction.
We know,
That the torque on a body is,
T = Fr
T is torque,
F is the force,
r is the perpendicular distance from the axis of rotation.
So, assuming the centre of the beam as the axis of rotation, the torque on the body is,
T = 200(1)+200(1)
T = 400N-m
We also know,
That torque on the body is,
T = IA
Where I is moment of inertia of the beam,
A is the angular acceleration of the body,
We know, moment of inertia of the beam assuming the centre of the rod as axis of rotation is,
I = MR²/12
M is the mass of the body,
R is the length of the rod,
So,
I = 5(2)²/12
I = 20/12 kg-m²
So, now we can write,
T = 20/12A
As both are value of torque, so,
20/12A = 400
A = 240 radian/s²
The angular acceleration is 240 radian/s².
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A hiker walks 5.00 kilometers due north and then 7.00 kilometers due east.
What is the magnitude of her resultant displacement?
Answer:
8.6 km
Explanation:
Use Pythagorean theorem
D^2 = 5^2 + 7^2
= 25 + 49
D = sqrt (74) = 8.6 km
If you had access to a personal DNA machine, what would you analyze and why?
If I had access to a personal DNA machine, I would analyze my ancestry and my health condition.
Just for curiosity you can compare your DNA to your parents DNA to find whose trait you received the most. Through DNA testing one can find where their ancestors lived and which group of people they interacted with.
In terms of analyzing DNA for health condition one can identify if they have any genetic diseases and it can also be used to identify cancer in its early stages so that it can be cured. It can also be used to identify the diseases an unborn fetus might inherit.
Therefore, if I had access to a personal DNA machine, I would analyze my ancestry and my health condition.
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Both speed and velocity measure how fast something is moving. However, since speed is not a _________ it does not require a(n) ___________ .
Responses
A scalar, directionscalar, direction
B quantity, unitquantity, unit
C magnitude, unitmagnitude, unit
D vector, direction
A force of 2.0 × 102 newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43, what is the weight of the crate?
A force of 2.0 × 10² newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43, then the weight of the crane would be 686 Newtons.
What is the mechanical advantage?Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = output force(load) /input force (effort)
As given in the problem a force of 2.0 × 10² newtons is applied to a lever to lift a crate. If the mechanical advantage of the lever is 3.43,
The weight of the crane = 200 × 3.43
= 686 Newtons
Thus, the weight of the crane would be 686 Newtons.
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Two drops of mercury each has a charge on 5.44 nC and a voltage of 235.15 V. If the two drops are merged into one drop, what is the voltage on this drop?
To find the voltage of the combined drops, we can just add the voltage of both drops together.
2(235.15) = 470.3 Volts
