Answer:
It is 15
Explanation:
The accelration decreases over time and it it is 13
If we had fusion power, then we could have spacecraft that travel at 10% light speed. If we had spacecraft that travel at 10% light speed, we could send probes to other stars. Therefore, if we had fusion power, we could send probes to other stars.
a. True
b. False
Answer:
True
Explanation:
Many nuclear scientists believe that when fusion power is used in powering spacecraft, this will shorten the travel time to planetary bodies.
However, one may wonder: what is fusion power? In simple words, it is a form of energy that uses heat released when lighter elements combine together to form heavier elements. In this fusion process, a huge amount of energy is released which can be harnessed and termed fusion power.
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. The egg just misses the cornice on the way down and passes a point 30.0 m below its starting point 5.00 s after it leaves the thrower’s hand. Ignore air resistance.
(a) What is the initial speed of the egg?
(b) How high does it rise above its starting point?
(c) What is the magnitude of its velocity at the highest point?
(d) What are the magnitude and direction of its acceleration at the highest point?
(e) Sketch ay−t,vy−ta y −t,v y −t, and y-t graphs for the motion of the egg.
Answer:
1. 18.5m/s
2. 17.5 m
3. 0 at its highest point
4. Direction is downwards
Explanation:
1. This egg is thrown vertically from a height
Yo = 0. This egg then falls to the point y = -30.0 at t = 5seconds
Y-Yo = V0t - 1/2gt²
-30-0 = V0(5)-1/2(9.8)(5²)
-30 = 5v0 - 4.9x25
-30 = 5V0 - 122.5
-30+122.4 = 5v0
V0 = 92.5/5
= 18.5m/s
this is the initial speed of the egg
2. When the egg is at a maximum height it would have a velocity equal to 0
V² = V0² - 2*g*y
V = 0, V0 = 18.5, g = 9.8
0 = 18.5²-2x9.8*y
342.25-19.6y = 0
342.25 = 19.6y
Divide through by 19.6
Y = 342.25/19.6
Y = 17.5m
this value is how high it rises above starting point
3.
The magnitude of velocity is = 0 at its highest point
4.
This egg falls under gravity. Therefore the acceleration due to gravity has a constant magnitude and direction. Magnitude = 9.8m/s and it's direction is downwards.
5. Please check attachment for graph
A tennis ball is shot straight up with an initial velocity of 34 m/s. What is its velocity two seconds after launch?
Answer:
The speed after 2 seconds is 14.4 m/s
Explanation:
Vertical Launch Upwards
In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.
The speed changes from an initial value vo to a final value vf, given by:
[tex]v_f=v_o-g.t[/tex]
Where g is the gravitational acceleration ([tex]9.8\ m/s^2[/tex])
The tennis ball is shot up with an initial speed of vo=34 m/s. We are required to find the final speed at t=2 s:
[tex]v_f=34-9.8*2[/tex]
[tex]v_f=14.4\ m/s[/tex]
The speed after 2 seconds is 14.4 m/s
the velocity after 2 seconds of launch is 14.4 m/s
the initial velocity(a) is 34m/s
the time(t) is 2 seconds
acceleration(a) due to gravity is 9.8g
the formula is
v= u - at
v= 34 -(9.8)(2)
= 34 - 19.6
= 14.4 m/s
hence the final velocity is 14.4 m/s
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A ball is thrown straight upward with an initial speed v0. When it reaches the top of its flight at height h, a second ball is thrown straight upward with the same initial speed. Do the balls cross paths at height 1/2h, above 1/2h, or below 1/2h
Answer:
The balls cross paths above 1/2h
Explanation:
Let's analyze the picture when the first ball is at the top of its flight and the second ball starts to flight.
When the second ball is thrown it has the maximum speed and the first ball starts with an initial velocity equal to zero. We know that they will cross at the same time, hence the second ball will travel a longer distance, due to its velocity, than the first ball.
Therefore, the correct answer is above the midpoint of h (1/2h).
I hope it helps you!
prove the identity
Trigonometry grade 10
Answer:
and is in photo given.I didn't get time to type.
To say that the rights to life, liberty, and
property are unalienable means that they
What do you think is the hardest problem for Divine Command Theory to overcome, and why?
Explanation:
One problem with opting for number 1 in the above dilemma is that it becomes difficult if not impossible to conceive of God as morally good, because if the standards of moral goodness are set by God's commands, then the claim “God is morally good” is equivalent to “God obeys His own commands”.
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You exert a 100-N force on a pulley system to lift 300-N. What is the mechanical advantage of this system? How many sections of rope support weight?
Answer:
Mechanical advantage = 3
Explanation:
You exert a 100-N force on a pulley system to lift 300-N.
The mechanical advantage of the system is given by the ratio of output force to the input force.
Here, output force = 300 N and input force = 100 N
Mechanical advantage,
[tex]m=\dfrac{300}{100}\\\\m=3[/tex]
Mechanical advantage is 3 it means that there are 3 sections of rope support. Hence, this is the required solution.
HIGHLIGHT the correct answer: a.) As the skater goes up the hill, his kinetic energy: increases / decreases / stays constant b.) As he goes up the hill, his potential energy: increases / decreases / stays constant c.) As he goes up the hill, his mechanical energy: increases / decreases / stays constant d.) As he goes down the hill, his kinetic energy: increases / decreases / stays constant e.) As he goes down the hill, his potential energy: increases / decreases / stays constant f.) As he goes down the hill, his mechanical energy: increases / decreases / stays constant
Answer:
a) Kinetic energy decreases, b) Potential energy increases, c) Mechanical energy stays constant, d) Kinetic energy increases, e) Kinetic energy increases, f) Mechanical energy stays constant.
Explanation:
a) Let suppose that the skater is a conservative system. If he goes up the hill, gravitational potential energy is increased at the expense of kinetic energy. In a nutshell, his kinetic energy decreases.
b) His potential energy increases.
c) Mechanical energy is the sum of gravitational potential and kinetic energies, since skater is conservative, then mechanical energy stays constant.
d) If he goes down the hill, his kinetic energy is increased at the expense of gravitational potential energy. In a nutshell, his kinetic energy increases.
e) His potential energy decreases.
f) Mechanical energy is the sum of gravitational potential and kinetic energies, since skater is conservative, then mechanical energy stays constant.
Answer:
The answer would be what the other guy said
Explanation:
Traveling waves are generated on a string fixed at both ends. The string has a length L, a linear mass density m, and a tension T. Which of the following will cause the wave speed to increase?
I. Using the same string but increasing the tension.
II Using a longer string with the same μ and T.
III. Using a string with the same L and T but a smaller μ.
a. I only
b. II only
c. III only
d. I or II
d. I or III
Answer: d. I or II
Explanation: A traveling wave has speed that depends on characteristics of a medium. Characteristics like linear density (μ), which is defined as mass per length.
Tension or Force ([tex]F_{T}[/tex]) is also related to the speed of a moving wave.
The relationship between tension and linear density and speed is ginve by the formula:
[tex]|v|=\sqrt{\frac{F_{T}}{\mu} }[/tex]
So, for the traveling waves generated on a string fixed at both ends described above, ways to increase wave speed would be:
1) Increase Tension and maintaining mass and length constant;
2) Longer string will decrease linear density, which will increase wave speed, due to their inversely proportional relationship;
Then, ways to increase the wave speed is
I. Using the same string but increasing tension
II. Using a longer string with the same μ and T.
A ball is thrown upward from the ground with an initial speed of 21.4 m/s; at the same instant, another ball is dropped from a building 18 m high. After how long will the balls be at the same height above the ground
Answer:
after 0.8411 seconds, the balls are at the same height
Explanation:
given the data in the question;
we take a look at the equation which relates the vertical displacement of the object, time elapsed, initial velocity and acceleration of the object;
Δy = [tex]V_{i}[/tex]t + [tex]\frac{1}{2}[/tex] [tex]a_{y}[/tex]t²
where Δy is the vertical displacement, [tex]V_{i}[/tex] is the initial velocity, [tex]a_{y}[/tex] is acceleration of the object and t is time elapsed.
Now let h represent the height above ground level where they meet.
so the distance moved by the falling ball will be;
18 m - h
The ball is moving freely under the influence of gravity.
so [tex]a_{y}[/tex] = -g
Using kinematic relation a freely falling ball
Δy = [tex]V_{i}[/tex]t + [tex]\frac{1}{2}[/tex] [tex]a_{y}[/tex]t²
-( 18 m - h ) = 0 - [tex]\frac{1}{2}[/tex]gt²
-18 m + h = - [tex]\frac{1}{2}[/tex]gt²
h = 18 m - [tex]\frac{1}{2}[/tex]gt² --------- let this be equ1
Now lets apply kinematic relation to the raising ball
h = (21.4 m/s)t - [tex]\frac{1}{2}[/tex]gt² ----------- let this be equ 2
so equ1 = equ2
18 m - [tex]\frac{1}{2}[/tex]gt² = (21.4 m/s)t - [tex]\frac{1}{2}[/tex]gt²
18 m = (21.4 m/s)t
t = 18 m / 21.4 m/s
t = 0.8411 s
Therefore, after 0.8411 seconds, the balls are at the same height
Need help with the middle question
Answer:
2.84 s.
Explanation:
From the question given above, the following data were obtained:
Length (L) of string = 2 m
Period (T) =?
The period of oscillation can be obtained as follow:
T = 2π√(L/g)
NOTE:
Pi (π) = 3.14
Acceleration due to gravity (g) = 9.8 m/s².
T = 2 × 3.14 × √(2/9.8)
T = 6.28 × √(2/9.8)
T = 2.84 s
Therefore, the period of oscillation is 2.84 s
Conservation of energy is explained as a scientific law and not a _______ because it does not explain why energy is conserved
Answer:
Theory
Explanation:
Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.
A law is a the statement of a scientific fact. It is a product of repeated experiment and observation through time. Most laws do not explain the reason for the logic behind their premise.
A theory on the other hand provides an explanation for an observed phenomenon. Most theories are no immutable. They are often changed when new finds are reported or made.
Laws are immutable and they stand still.
The International Space Station has a mass of 419,455 kg. When it orbits the
Earth at an altitude of 400,000 m, what is the approximate gravitational force
on the Station due to Earth's gravity? (Recall that Earth has a radius of 6.37 x
106 m, it has a mass of 5.97 x 1024 kg, and G = 6.67 x 10-11 N·m²/kg2.)
O A. 3.9 ~ 106N
B. 2.0 x 106N
O C. 3.6 x 106N
O D. 2.8 x 106N
Answer:
[tex]F=3.6\times 10^6\ N[/tex]
Explanation:
Given that,
The mass of International Space Station, m = 419,455 kg
It orbits around the Earth at an altitude of, h = 400,000 m
The radius of Earth, [tex]r=6.37\times 10^6\ m[/tex]
The mass of the Earth, [tex]m_e=5.97 \times 10^{24}\ kg[/tex]
We need to find the approximate gravitational force on the Station due to Earth's gravity. The formula for the gravitational force between the satellite and the Earth is given by :
[tex]F=G\dfrac{mm_e}{(r+h)^2}\\\\F=6.67\times 10^{-11}\times \dfrac{419455\times 5.97 \times 10^{24}}{(6.37 \times 10^6+400000 )^2}\\\\F=3.6\times 10^6\ N[/tex]
So, the required force on the station due to Earth's gravity is [tex]3.6\times 10^6\ N[/tex].
write the realtionship between the density of a liquid and its upthrust? clarify
Answer:
B = ρ g V_liquid
the thrust is proportional to the density of the liquid
Explanation:
The density of a liquid is defined as the relationship between the mass and the volume of the liquid
ρ = m / V
The upward push of the liquid is given by the principle of Archimedes Archimedes establishes that the push is equal to the weight of the dislodged liquid
B = W_liquid
B = m _liquid g
we substitute mass for density
B = ρ g V_liquid
therefore we see that the thrust is proportional to the density of the liquid
A transverse, sinusoidal wave travels in a string and can be described by the function: y(x,t)=0.87 sin(21x−4.9t). What is the speed of this wave?A transverse, sinusoidal wave travels in a string and can be described by the function: . What is the speed of this wave?
A. 0.18 m/s
B. 9.2 m/s
C. 4.3 m/s
D. 0.23 m/s
Answer:
D. 0.23m/s
Explanation:
Given the equation of a wave expressed as;
y(x,t)=0.87 sin(21x−4.9t)
Comparing with the standard equation of a wave;
y(x,t)= Asin(2πx/λ−2πft) where;
f is the frequency
λ is the wavelength
On comparing;
2πx/λ = 21x
2π/λ = 21
λ = 2π/21
λ = 2(3.14)/21
λ = 6.28/21
λ = 0.299m
Get the frequency f;
2πft = 4.9t
2πf = 4.9
f = 4.9/2π
f = 4.9/2(3.14)
f = 4.9/6.28
f = 0.78Hz
Get the speed of the wave
Speed = frequency * wavelength
Speed = 0.299 * 0.78
Speed = 0.233m/s
Hence the speed of the wave is 0.23m/s
An elevator travels up and down. The vertical position of the elevator in meters over time is shown below
what is the displacement of the elevator between 8s and 20s?
What is the distance traveled by the elevator between 8s and 20s
Answer:
The displacement is
-27m
The distance traveled is
27m
Dont listen to the other guys they are wrong
Explanation:
Well you see the elevator starts at 12m and 8s and moves down to 0mat 16s, traveling at a distance of 12m
The Elevator starts at 0m at 16s and moves down to -15m at 20s traveling a distance of 15m
So afterwards what you do is find the distance between 8 and 20 so do this equation
12m + 15m = 27m
So that gives you
-27
27
HOPE THIS HELPS!!!
The displacement and distance of the elevator between 8s and 20s will be -27 meters and 27 meters respectively.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
From the given graph, it is observed that;
Distance is the sum of the physical length travelled. First, the elevator travels the 15 m down and the 12-meter up. The distance travelled will be;
d= 15 +12 = 27 m
Displacement is the net distance travelled or the shortest distance. The value of the displacement can be negative. The displacement is found as;
D= -15-12 =-27 m
Hence, the displacement and distance of the elevator between 8s and 20s will be -27 meters and 27 meters respectively.
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What do ocean waves and sound waves have in common? A. Both are transverse waves. B. both are longitudinal waves C. Both are electromagnetic waves. D. Both exhibit the same particle-to-particle interaction. E. Both are mechanical waves.
Answer:
E. Both are mechanical waves
A piece of metal with a mass of 1.9 kg, and specific heat of 200J/kg°C, and an initial temperature of 100°C is dropped into an insulated jar that contains liquid with a mass of 3.9 kg, a specific heat of 1000J/kg°C, and initial temperature of 0°C. The piece of metal is removed after 7 s, at which time its temperature is 20°C.
Required:
Find the temperature of the liquid after the metal is removed. Neglect any effects of heat transfer to the air or to the insulated jar. Answer in units of ∘C.
Answer:
7.79 °C
Explanation:
Given that
Mass of the metal, m = 1.9 kg
Specific heat of the metal, c(m) = 200 J/kgC
Initial temperature, T(0) = 100 °
Mass of liquid, M = 3.9 kg
Specific heat of liquid, c(l) = 1000 J/kgC
Initial temperature, T = 0 °C
Time taken, t = 7 s
Final temperature = 20 °C
To solve the question, we use the formula the sum of the heats gained is zero.
massmetal * cmetal (20-100) + massliquid * cliquid (T.f-0)=0
On solving for T.f
1.9 * 200 * (20 - 100) + 3.9 * 1000 * (t.f - 0) = 0
380 * -80 + 3900 * t.f = 0
-30400 + 3900t.f = 0
3900t.f = 30400
t.f = 30400 / 3900
t.f = 7.79 °C
Can someone help me with this
Answer:
Explanation:
try the fourth one :)
A student must conduct an experiment in which a block is pulled across a horizontal surface by a spring scale so that a nonzero change in momentum of the block can be determined for a specific time interval. The student also has access to measuring tools that are found in a typical physics laboratory. Which of the following experiments could the student conduct to determine the change in momentum of the cart?
a. Attach the spring scale to the block, and pull the block at a constant speed as it travels across the horizontal surface. Record the force that the spring scale exerts on the block. Use a stopwatch to determine the time that the block is in motion.
b. Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Record the force that the spring scale exerts on the block. Use a stopwatch to determine the time that the block is in motion.
c. Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Use the motion detector to record the speed of the block at the beginning of the time interval and at the end of the time interval.
d. Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Use the motion detector to record the speed of the block at the beginning of the time interval and at the end of the time interval. Use a meterstick to measure the distance traveled by the block in the given time interval
Complete option C is;
Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Use the motion detector to record the speed of the block at the beginning of the time interval and at the end of the time interval. Use a mass balance to measure the mass of the block
Answer:
B: Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Record the force that the spring scale exerts on the block. Use a stopwatch to determine the time that the block is in motion.
C: Attach the spring scale to the block, and pull the block so that its speed increases as it travels across the horizontal surface. Use the motion detector to record the speed of the block at the beginning of the time interval and at the end of the time interval. Use a mass balance to measure the mass of the block
Explanation:
We know that formula for change in momentum is;
Ft = m(v - u)
Where left hand side is impulse and right hand side is change in momentum.
Now, looking at the options, the most accurate will be options B and C because they depict the accurate parameters needed to calculate change in momentum unlike option A and D that deal with constant speed and & distance respectively which we don't need to calculate change in momentum.
The image below represents molecules in which state of matter? *
da answer is liquiddddddddd
The ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is
A 1:1
B 1:3
C 1:1.63 E18
D 1:1.67 E-27
E 1:9.11 E-31
Answer: A 1:1
Explanation:
They both have a magnitude of 1.6 x 10^-19 C.
The ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is 1:1 option (A) is correct.
What is an atom?It is a basic unit of matter everything is made from the atom. It consists of three small particles in it named electron, proton, and neutron. The electron has a negative charge, a proton has a positive charge, and a neutron has no charge.
We know the charge on the proton:
[tex]\rm Q_p = 1.6 x 10^{-19} \ C[/tex]
And charge on the electron:
[tex]\rm Q_e = -1.6 x 10^{-19} \ C[/tex]
The absolute value of charge on the electron:
[tex]\rm |Q_e| = 1.6 x 10^{-19} \ C[/tex]
[tex]\rm \dfrac{\rm Q_p} {\rm |Q_e| }= \dfrac{1.6 x 10^{-19}}{ 1.6 x 10^{-19}}[/tex]
= 1:1
Thus, the ratio of the magnitude of the charge of a proton compared to the magnitude of the charge on an electron is 1:1 option (A) is correct.
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How many times more acidic is solution A with a pH of 3.4 than solution B with a pH of 8.4?
Solution A is _________ times more acidic than solution B.
(Use scientific notation. Use the multiplication symbol in the math palette as needed. Round to the nearest tenth as needed.)
Answer:
Solution A is 1 x 10⁵ times more acidic than solution B
Explanation:
The pH scale is a logarithmic scale used to express the acidity or basicity of a solution.
The values are written from 1 - 14 with 1 being the most acidic and 14 a basic solution.
Each interval is ten folds more concentrated than the next because it is a logarithmic scale.
Since the pH of A = 3.4
pH of B = 8.4
The difference = 8.4 - 3.4 = 5.0
So, Solution A is 1 x 10⁵ times more acidic than solution B
The dotted lines and arrows represent
A student must perform an experiment in which two objects travel toward each other and collide so that the data collected can be used to show that the collision is elastic within the acceptable range of experimental uncertainty. Which of the following measuring tools, when used together, can the student use to verify that the collision is elastic?
A. A motion detector.
B. A meterstick.
C. A balance.
D. A stopwatch.
Answer:
A. A motion detector.
C. A balance.
Explanation:
An elastic collision can be defined as a type of collision in which the total kinetic energy possessed by the colliding bodies remain the same.
This ultimately implies that, in an elastic collision the maximum amount of kinetic energy possessed by the colliding bodies is conserved (kinetic energy is not lost) after the collision.
In this scenario, a student must perform an experiment in which two objects travel toward each other and collide so that the data collected can be used to show that the collision is elastic within the acceptable range of experimental uncertainty.
The measuring tools, which when used together, can be used by the student to verify that the collision is elastic are a motion detector and a balance.
Basically, the motion detector is an electronic device that can be used to determine the initial and final velocity of the objects while the balance would be used to take a measurement of the mass possessed by the objects.
Helge, Steve, and Heidi are sitting on a sled on a slope covered with a hard snow. The sled is stationary. The friends have different suggestions for how to make the sled start moving:
Helge: If one of us gets off, the sled will start moving.
Steve: We should invite another person to join us, and then the sled will start moving.
Heidi: We should get off the sled, polish the bottom of the sled to make it smoother, and sit back down on it. The sled will then start moving.
Who suggests the correct solution? Select the correct equation for acceleration ax along the incline. Assume the x-axis is directed down along the incline, and the y-axis is directed normal to the incline. Let μs and θ denote the coefficient of static friction and the angle the incline makes with the horizontal, respectively.
Answer:
Heldi is right
Explanation:
It will not move even if more people or one person gets off it will stay the same til a force pushes down on it.
A particular race car can cover a quarter-mile track (402 m) in 6.40 s starting from a standstill.
Find its acceleration.
If the combined mass of the driver and race car is 485 kg, what horizontal force must the road exert on the tires?
Answer:
9520N
Explanation:
For the first part of this problem:
Given parameters:
Distance traveled = 402m
Time taken = 6.4s
Initial velocity = 0m/s
Unknown:
Find the acceleration = ?
Solution:
To solve this problem, we use on of the kinematics equation:
S = ut + [tex]\frac{1}{2}[/tex]at²
S is the distance moved
u is the initial velocity
t is the time taken
a is the acceleration
402 = (0 x 6.4) + ([tex]\frac{1}{2}[/tex] x a x 6.4²)
402 = 20.48a
a = 19.63m/s²
Second problem:
Given parameters:
Mass of the driver and race car combined = 485kg
So;
Horizontal force = mass x acceleration
Horizontal force = 485 x 19.63 = 9520N
Answer:7.1*10^3
Explanation:
First aid for a strain or a sprain
A) the FITT formula.
B) ineffective.
C) the RICE formula. .
D) the ABC formula
Answer: C) the RICE formula
Explanation:
Particularly for the treatment of injury associated with the sprain or strain one can get relieve in pain and swelling on the damaged area by promoting flexibility and healing of that area utilizing the RICE formula. R- rest, I- Ice, C- Compression, and E- Elevation. Resting and restricting any activity can help in enhancing the healing process. The application of ice will reduce pain and swelling. The injured area can be compressed by using a tight bandage. This will also help in reducing the swelling. Keeping the injured body part at an elevation like on a pillow can also reduce the swelling.
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 47.0 cm . The explorer finds that the pendulum completes 91.0 full swing cycles in a time of 125 s. What is the magnitude of the gravitational acceleration on this planet?
Answer:
[tex]g=9.83\ m/s^2[/tex]
Explanation:
Given that,
The length of a simple pendulum, l = 47 cm = 0.47 m
The pendulum completes 91.0 full swing cycles in a time of 125 s.
The time period of a simple pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{L}{g}} \\\\or\\\\g=\dfrac{4\pi^2L}{T^2}[/tex]
Also,
[tex]T=\dfrac{1}{f}\\\\T=\dfrac{t}{n}[/tex]
t is 125 s and n = 91 cycles
Substitute all the values to find g.
[tex]g=\dfrac{4\pi^2\times 0.47}{(\dfrac{125}{91})^2}\\\\g=9.83\ m/s^2[/tex]
So, the gravitational acceleration on this planet is [tex]9.83\ m/s^2[/tex].