A diesel train left Abuja and traveled west. One hour later a freight train left traveling 50 mph faster in an effort to catch up to it. After three hours of freight train finally caught up. Find the diesel train’s average speed.

Answers

Answer 1

The speed at which diesel train was moving is = 150mph

In the above question, it is given that,

Let the speed of the diesel train which left Abuja be x mph

then, speed of freight train which is moving 50 mph faster than diesel train = (50 + x)mph

Further, the freight train finally caught up the diesel train after three hours

So time taken by freight train = 3 hours

While time taken by diesel train would 1 hour more than freight train as its moving slower = 3 + 1 = 4 hours

Now, it is given that both the trains finally catch up, it means the distance travelled by both the trains would be equal

We know that,

Speed = [tex]\frac{Distance}{Time}[/tex]

Distance = Speed x Time

Distance travelled by Diesel train = distance travelled by Freight train

4x = 3(50 + x)

4x = 150 + 3x

x = 150 mph

Hence, the speed at which diesel train was moving is = 150mph

While, the speed at which freight train was moving is = (150 + x)mph = (150 + 50)= 200mph

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Related Questions

3 166.40 266.24 3. Consider the following functions which all have an or decay? By what percent? Rewrite as (1+r) or (1-r) f(t) = 30(1.04) p(x) = 30(0.65)Solve f(t)

Answers

ANSWER

Function f(t) represents a growth by 4%

EXPLANATION

If the function represents a decay it is written as:

[tex]f(t)=a(1-r)^t[/tex]

and if it represents a growth it's:

[tex]f(t)=a(1+r)^t[/tex]

We can see if it's a growth or decay by looking at the number we have between parenthesis: if it's greater than 1, then it's a growth and if it's less than 1 then it's a decay.

For function f(t) we have

[tex]1+r=1.04[/tex]

Therefore, r = 0.04 which, expressed as a percent is 4%

11) a- 15 > 40-6 +3a) 12) 366b-1) > 18 - 3b a-151-46-67+1-useBay 9-15 124-12a atiza324+15 13a339 ay/9 13) 26 + m 2 5(-6 +3m) 14) 20-2p>-2lp

Answers

Answer

11) a > 3

12) b > (2/3)

Explanation

11) a - 15 > -4 (-6 + 3a)

a - 15 > 24 - 12a

a + 12a > 24 + 15

13a > 39

Divide both sides by 13

(13a/13) > (39/13)

a > 3

In graphing inequality equations, the first thing to note is that whenever the equation to be graphed has (< or >), the circle at the beginning of the arrow is usually unshaded.

But whenever the inequality has either (≤ or ≥), the circle at the beginning of the arrow will be shaded.

Then, the direction of the graph depends on the direction of the inequality sign, for example, the answer here says a is greater than 3. So, the graph will start with an unshaded circle and cover the numbers greater than 3.

12) 3 (6b - 2) > (8 - 3b)

18b - 6 > 8 - 3b

18b + 3b > 8 + 6

21b > 14

Divide both sides by 21

(21b/21) > (14/21)

b > (2/3)

This answer is similar to that of number 11. For the graph, it will start with an unshaded circle and move towards the numbers greater than (2/3)

Hope this Helps!!!

The graph shows the distance a car traveled, y, in x hours: What is the rise-over-run value for the relationship represented in the graph?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

point 1 (2 , 60) x1 = 2 y1 = 60

point 2 (4 , 120) x2 = 4 y2 = 120

Step 02:

slope formula

[tex]m\text{ = }\frac{y2-y1}{x2-x1}[/tex][tex]m\text{ = }\frac{120-60}{4-2}=\text{ }\frac{60}{2}=30[/tex]

The answer is:

30

8. In order to reach the top of a hill which is 250 feet high, one must travel 2000 feet straight up a road
which leads to the top. Find the number of degrees contained in the angle which the road makes with the
horizontal.

Answers

7.18° the angle which the road makes with the horizontal.

Define Trigonometric functions

The trigonometric functions are real functions which relate an angle of a right-angled triangle to ratios of two side lengths.

Given,

Height of hill = 250 feet

Length of the slope = 2000 feet

find the angle,

we know, sin(x) = perpendicular / hypotenuse

sin(x) = 250 / 2000

x = sin^-1 (0.125)

x = 7.18°

Hence, 7.18° the angle which the road makes with the horizontal.

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Araceli filled a cone-shaped container with a variety of colored sand to give as a gift to a friend. The volume of a cone is represented by the expression below, where r is the radius of the base of the cone and h is the height of the cone.radius = 3 1/23 5/3 is the height

Answers

The volume of the cone is 45.28 cubic inches.

The amount of sand inside the cone is measured by its volume.

Based on the numbers for the radius and height, the cone's volume is 45.28 cubic inches.

The volume of a cone is the measure of how much space a cone takes up. Cone height and base radius both affect how much space the cone takes up.

The volume of the cone is given by V = [tex]\frac{1}{3}\pi r^{2} h[/tex]

The value of the radius is r = [tex]3\frac{1}{23} = \frac{70}{23}[/tex]

The value of Height is h = [tex]3\frac{5}{3} = \frac{14}{3}[/tex]

So, the Volume of the cone =[tex]V =\frac{1}{3}\pi r^{2} h[/tex]

[tex]V =\frac{1}{3}\pi r^{2} h\\\\V = \frac{1}{3}\pi (\frac{70}{23}) ^{2} \frac{14}{3} \\\\V = 45.28[/tex]

The volume of the cone is 45.28 cubic. inches

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Solve the Equation , I tried multiplying that 6 to the numbers in the parentheses but i couldnt get it

Answers

To start we will do what you said, multiply the 6, so:

6*(n-4)=3n

6n-6*4=3n

6n-24=3n

6n=3n+24

6n-3n=24

3n=24

n=24/3

n=8

So the answer is: 8

162-317-3113-510Is this relation a function?

Answers

can you see my messages?

Watch the video and then solve the problem given below.Click here to watch the video.Solve the inequality both algebraically and graphically. Give the solution in interval notation and draw it on a number line graph.x−54

Answers

Given the inequality below:

[tex]\frac{x-5}{4}<\frac{9}{5}[/tex]

Solving algebraically as shown below:

[tex]\begin{gathered} \frac{x-5}{4}<\frac{9}{5} \\ \text{Lcm of the denominator(4 and 5) is 20} \\ \text{mltiply through by the Lcm(20)} \\ 20\times\frac{(x-5)}{4}<20\times\frac{9}{5} \end{gathered}[/tex][tex]\begin{gathered} 5(x-5)<4\times9 \\ 5x-25<36 \\ 5x<36+25 \\ 5x<61 \\ x<\frac{61}{5} \\ x<12.2 \end{gathered}[/tex]

Solving graphically as shown below the plotting of x < 12.2

The number line graph is the number line showing x < 61/5, as shown below:

The interval notation of the solution is (- ∞, 61/5) or (- ∞, 12.2)

The cost, c(x) in dollars per hour of running a trolley at an amusement park is modelled by the function [tex]c(x) = 2.1x {}^{2} - 12.7x + 167.4[/tex]Where x is the speed in kilometres per hour. At what approximate speed should the trolley travel to achieve minimum cost? A. About 2km/h B about 3km/h C about 4km/D about 5km/hr

Answers

The equation is modelled by the function,

c(x) = 2.1x^2 - 12.7x + 167.4

The general form of a quadratic equation is expressed as

ax^2 + bx + c

The given function is quadratic and the graph would be a parabola which opens upwards because the value of a is positive

Since x represents the speed, the speed at which the he

Create a quadratic function in one of the forms and show how to convert it to the other two forms.

Answers

Create a quadratic function in one of the forms and show how to convert it to the other two forms.

Step-by-step explanation:

1) Standard form: y = ax2 + bx + c where the a,b, and c are just numbers.

[tex]y=ax^2+bx+c[/tex]

2) Factored form: y = (ax + c)(bx + d) again the a,b,c, and d are just numbers.

[tex]y=(ax+c)(bx+d)[/tex]

3) Vertex form: y = a(x + b)2 + c again the a, b, and c are just numbers.

[tex]y=a(x+b)^2+c[/tex]

The vertex of the parabola is written as (h, k) where b is the x - coordinate and c - is the y - coordinate

using the given quadratic function f(x)=x^2+2x-15, find the following information"Coordinates of x- intercept(zero) as ordered pairs"

Answers

the given expression is

f(x) = x^2 + 2x - 15

we will find x intercept by putting f(x) = 0

x^2 + 2x - 15 = 0

x^2 + 5x - 3x - 15 = 0

x(x +5) -3(x + 5) = 0

(x +5) (x -3) = 0

x = -5 & x = 3

so the ordered pairs are

(-5, 0) and (3, 0)

Question 1
Is the sequence arithmetic: 78, 785, 7855, 78555, ...
O No
5 pts
Yes
Next >

Answers

The sequence is not arithmetic

What is a sequence?

A sequence in mathematics is an enumerated collection of items in which repetitions are permitted and order is important. It, like a set, has members (also called elements, or terms). The length of the series is defined as the number of items (which might be infinite). Unlike a set, the same components can occur numerous times in a sequence at various points, and the order does important. Formally, a sequence may be defined as a function from natural numbers (the sequence's places) to the items at each point. The concept of a sequence may be extended to include an indexed family, which is defined as a function from an arbitrary index set.

The given sequence 78, 785, 7855, 78555, ... is not arithmetic.

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How far is the girl from the monument that is 30 ft high? Round your answer to a nearest foot. Show your work.

Answers

Given:

The diagram is shown alongside.

The height of the monument is 30 ft high.

The angle of elevation is 63 degrees

The objective is to find the distance between the monument and where the girl is standing.

Since it forms a right angled triangle so we can apply trigonometric ratios:

Now,

[tex]\tan 63^{\circ}=\frac{perpendicular}{\text{base}}[/tex]

Perpendicular = 30 ft

Base = ?

Substituting the values,

[tex]\begin{gathered} \tan 63^{\circ}=\frac{30}{\text{base}} \\ \text{Base}=\frac{30}{\tan63^{\circ}} \\ \text{base}=\frac{30}{1.962610} \\ \text{base}=15.285767422\text{ ft} \end{gathered}[/tex]

Therefore, the girl is at a distance of 15 ft from the monument.

Given the set of all even integers between and including -18 to -6 , what is the probability of choosing a multiple of -6 from this set?1/93/74/9

Answers

TheseGiven the set: {-18, -16, -14, -12, -10, -8, -6}

This is 7 numbers

Multiplies of -6 are:

[tex]\begin{gathered} -6\times1=-6 \\ -6\times2=-12 \\ -6\times3=-18 \end{gathered}[/tex]

This is 3 numbers

Therefore, the probability is given by:

[tex]P=\frac{multiplies\text{ of }-6}{total\text{ set }}[/tex]

So:

[tex]P=\frac{3}{7}[/tex]

Answer: 3/7

Cleo can paint a room in 8 hours, while Phil can paint the same room in 6 hours. If they paint theroom together, how long will it take them to paint the room?How many hours and how many minutes?

Answers

According to the given data we have the following:

Cleo can paint a room in 8 hours, so this is=1/8x

Phil can paint the same room in 6 hours=1/6x

In order to calculate how long it take them to paint the room we would solve the following equation:

(1/6)(x)+(1/8)(x)=1

To solve this equation we would first multiply both sides by 24

Hence:

24*(1/6)(x)+24*(1/8)(x)=24

4x+3x=24

7x=24

x=24/7

x= 3 3/7 hours

Therefore It will take them 3 and 3/7 hours to pain the room.

In minutes it will take to them 205 minutes.

Match each expression on the left with its sum on the right. Some answer options on the right will not be used.

Answers

To match the expression with the sum, what you have to do is solve each sum.

Remember that to sum/subtract two fractions, both of them should be expressed using the same denominator,

1)

[tex]-\frac{2}{3}+\frac{5}{6}[/tex]

The denominators of these fractions are "3" and "6", the least common denominator between both values is 6. To express the first fraction as its equivalent with denominator 6, you have to multiply it by 2:

[tex]-\frac{2\cdot2}{3\cdot2}+\frac{5}{6}=-\frac{4}{6}+\frac{5}{6}[/tex]

Now you can proceed to add both fractions:

[tex]-\frac{4}{6}+\frac{5}{6}=\frac{-4+5}{6}=\frac{1}{6}[/tex]

The result for this sum is 1/6

2)

[tex]\frac{7}{12}+(-\frac{3}{4})[/tex]

First, simplify both symbols, when a plus symbol and a minus symbol and next to each other, the plus sign gets canceled:

[tex]\frac{7}{12}+(-\frac{3}{4})=\frac{7}{12}-\frac{3}{4}[/tex]

To subtract both fractions the first step is to express them using the same denominator. The least common denominator between 12 and 4 is 12, to express -3/4 as its equivalent with denominator 12, you have to multiply the fraction by 3:

[tex]\frac{7}{12}-\frac{3\cdot3}{4\cdot3}=\frac{7}{12}-\frac{9}{12}[/tex]

Next, subtract both fractions:

[tex]\frac{7}{12}-\frac{9}{12}=\frac{7-9}{12}=-\frac{2}{12}[/tex]

The result is no in its simplest form, 2 and 12 are divisible by 2, so to simplify the fraction you have to divide the numerator and denominator by 2:

[tex]-\frac{2\div2}{12\div2}=-\frac{1}{6}[/tex]

The result for this expression is -1/6

3)

[tex]-\frac{1}{4}+\frac{3}{8}[/tex]

Same as before, the first step is to express both fractions with the same denominator. the least common denominator for both fractions is 8. To express -1/4 as its equivalent with denominator 8, you have to multiply the fraction by 2

[tex]-\frac{1\cdot2}{4\cdot2}+\frac{3}{8}=-\frac{2}{8}+\frac{3}{8}[/tex]

Next, add both fractions:

[tex]-\frac{2}{8}+\frac{3}{8}=\frac{-2+3}{8}=\frac{1}{8}[/tex]

The result for this sum is 1/8

So the corresponding matches are:

[tex]\begin{gathered} 1)-\frac{2}{3}+\frac{5}{6}=\frac{1}{6} \\ 2)\frac{7}{12}+(-\frac{3}{4})=-\frac{1}{6} \\ 3)-\frac{1}{4}+\frac{3}{8}=\frac{1}{8} \end{gathered}[/tex]

How do I tell if a parabola has a minimum or a maximum?

Answers

We can write the equation of a parabola in two different ways:

The standard form:

[tex]\begin{gathered} y=ax^2+bx+c \\ a\ne0 \end{gathered}[/tex]

And the vertex form:

[tex]y=a(x-h)^2+k[/tex]

If the parabola has a minimum or a maximum depends on the leading coefficient (the coefficient of x²) or in both cases the coefficient a.

Let's see the cases:

[tex]a>0_{\text{ }}(a_{\text{ }}is_{\text{ }}positive)[/tex]

If a is positive, the parabola opens upwards, so the parabola has a minimum.

[tex]a<0_{\text{ }}(a_{\text{ }}is_{\text{ }}negative)[/tex]

If a is negative, the parabola opens downwards, so the parabola has a maximum

Express 2x-3y=-6 into y=mx+b

Answers

For this problem, we are given a certain expression and we need to write it in the "y=mx+b" form.

We need to isolate the "y" variable on the left side to solve this problem. We have:

[tex]\begin{gathered} 2x-3y=-6\\ \\ 2x-3y-2x=-6-2x\\ \\ \frac{-3y}{-3}=\frac{-6}{-3}-\frac{2x}{-3}\\ \\ y=2+\frac{2}{3}x\\ \\ y=\frac{2}{3}x+2 \\ \\ \end{gathered}[/tex]

The expression is y = (2/3)x+2.

A governor has been working to decrease the unemployment rate but it has gone up by 3%. In an effort to undermine the governor, a media outlet releases a bar graph comparing the unemployment rate before and after the governor took office.Which of the following tactics did the media outlet use to create this graph?A. Comparison chartsB. SizingC. Missing informationD. Axis and scaling manipulation

Answers

From the given graph, let's determine the tactics which the media outlet used to create the graph.

From the graph, we can see that the scaling of the y-axis was manipulated.

The numbers in the y-axis starts from 8%, while a normal graph is suposed to start from 0%.

Although the graph is correct, but the scaling of the y-axis is misleading. This is because when you look at the graph, you will think there is a major difference between unnemployment before and unemployment after.

Therefore, the tactics the media outlet used to create this graph can be said to be Axis and Scaling manipulation.

Axis and scaling manipulation is a method used in producing misleading graphs to make the data look worse or better than it actually is. This method leads to incorrect conclusions,

ANSWER:

D. Axis and Scaling manipulation.

help ! it may or may not have multiple answers

Answers

From the given problem, there are 3 computer labs and each lab has "s" computer stations.

So the total number of computers is :

[tex]3\times s=3s[/tex]

Mr. Baxter is ordering a new keyboard and a mouse for each computer, since the cost of a keyboard is $13.50 and the cost of a mouse is $6.50.

Each computer has 1 keyboard and 1 mouse, so the total cost needed for 1 computer is :

[tex]\$13.50+\$6.50[/tex]

Since you now have the cost for 1 computer, multiply this to the total number of computers which is 3s to get the total cost needed by Mr. Brax :

[tex]3s\times(13.50+6.50)[/tex]

Using distributive property :

[tex]a(b+c)=(ab+ac)[/tex]

Distribute s inside the parenthesis :

[tex]3(13.50s+6.50s)[/tex]

One answer is 1st Option 3(13.50s + 6.50s)

Simplifying the expression further :

[tex]\begin{gathered} 3(13.50s+6.50s) \\ =3(20.00s) \end{gathered}[/tex]

Another answer is 4th Option 3(20.00s)

You have 1/5 of a box of erasers and you need to share them with 3 total people, including yourself. What fraction of the box should each person get?

Answers

You have 1/5 of a box of erasers

Number of box of erasers = 1/5.

you need to share them with 3 total people, including yourself

Total number of people = 3 + 1( yourself)

Total number of people = 4

Since, we have to distribute the box of erasers to 4 people

So, divide 1/5 by 4:

[tex]\begin{gathered} \frac{1}{5}\text{ }\div4=\frac{\frac{1}{5}}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5}\times\frac{1}{4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{5\times4} \\ \frac{1}{5}\text{ }\div4=\frac{1}{20} \end{gathered}[/tex]

The fraction of the box that each person will get is 1/20

Answer: 1/20

flying against the wind, an airplane travels 7840 kilometers in 8 hours. flying with the wind, the same plane travels 5280 kilometers in 4 hours. what is the rate of the plane in still air and what is the rate of the wind?

Answers

Answer:

The rate of the plane in still air is 1150km/hr and the rate of the plane in the wind is 170km/hr.

Explanations:

The formula for calculating distance is expressed as:

[tex]\begin{gathered} dis\tan ce=\text{speed}\times\text{time} \\ d=st \end{gathered}[/tex]

Let the rate of the plane in still air be "x"

Let the rate of the plane in the wind be "y"

if flying against the wind, an airplane travels 7840 kilometers in 8 hours, then;

8 (x - y) = 7840

x - y = 980 ........................ 1

If flying with the wind, the same plane travels 5280 kilometers in 4 hours

4 (x + y) = 5280

x + y = 1,320 ......................2

Add both equations:

x + x = 980 + 1320

2x = 2,300

x = 2300/2

x = 1150 km/hr

Substract x = 1150km/hr into equation 1.

x - y = 1320

1150 + y = 1320

y = 1320 - 1150

y = 170km/hr

Hence the rate of the plane in still air is 1150km/hr and the rate of the plane in the wind is 170km/hr

I got the picture and will send it to you show the coordinates of the points that create the shape of the image

Answers

We have the following:

[tex]\begin{gathered} P(1-1,-3+3)\rightarrow P^{\prime}(0,0) \\ Q(3-1,-1+3)\rightarrow Q^{\prime}(2,2) \\ R(4-1,-3+3)\rightarrow R^{\prime}(3,0) \end{gathered}[/tex]

now,

The answer is:

Given the equations and the table below, what is the first x-value when the y-value of equation 2 is greater than the y-value of equation 1 after the functions first intersect?Equation 1: f(x)=5x^3Equation 2: f(x)=2x+3

Answers

the first x value, when the y-value of the equation is greater than the y value of equation one, is x=15

Because the y-value of equation 2 with x=15 is 32771, while the y-value of equation 1 is 16875

How to solve this problem? (the answer is 262 Hz). i want to know the step by step on how to solve the equation given. if it helps, i am a grade 10 student. (YES, this is a MATH problem)

Answers

Answer:

The frequency of middle C = 262 Hz

Explanation:

The formula for calculating the frequency, F hertz, of a note n seminotes above the concert pitch is:

[tex]F\text{ = 440(}\sqrt[12]{2})^n[/tex]

This can be re-written as:

[tex]F=440(2^{\frac{n}{12}})[/tex]

Middle C is 9 semitones below the concert pitch

That is, n = -9

To find the frequency of middle C, substitute n = -9 into the equation for F

[tex]\begin{gathered} F=440(2^{\frac{-9}{12}}) \\ F\text{ = 440(}0.5946) \\ F\text{ = }261.62\text{ Hz} \\ F\text{ = 262 Hz (to the nearest hertz)} \end{gathered}[/tex]

The frequency of middle C = 262 Hz


Jenna bought a package of 2 chicken drumsticks. If the package weighed 0.232 kg, what is the average weight of
each drumstick?

Answers

Answer:

0.116

Step-by-step explanation:

[tex]\frac{0.232}{2}[/tex] = 0.116

Lines AD and BC are parallel. What is the angle measurement of Angle DAE(Point A)?D150°45°BсFYour answer

Answers

Solution

For this case we can find the angle:

m < ECB = 30º

And we can find the angle CEB and we got:

m < CEB = 180 -30 - 45 = 105

And then the angle DAE would be:

m < DAE = 30º

Given f(x) = 2x - 1 h(x) = x^2 + 1Find f[h(7)]

Answers

Answer:

[tex]f\lbrack h(7)\rbrack\text{ = 99}[/tex]

Explanation:

Given the functions:

[tex]\begin{gathered} f(x)=2x-1 \\ h(x)=x^2+1 \end{gathered}[/tex]

We want to find:

[tex]f\lbrack h(7)\rbrack[/tex]

First of all, we need to find:

[tex]f\lbrack h(x)\rbrack[/tex]

This is done by inserting the value of h(x) into f(x)

So, we have:

[tex]\begin{gathered} f\lbrack h(x)\rbrack=2(x^2+1)-1 \\ =2x^2+2-1 \\ =2x^2+1 \end{gathered}[/tex]

Substituting 7 for x in f[h(x)], we have f[h(7)]

[tex]\begin{gathered} f\lbrack h(7)\rbrack=2(7^2)+1 \\ =2(49)+1 \\ =98+1 \\ =99 \end{gathered}[/tex]

Which is what we are looking for.

I’m a parent and I’m not sure I’m understanding this question the practice test question says “How would you take apart 14 to solve 28 - 14? The choices are 7 and 710 and 4 12 and 220 and 8. I said 7 and 7

Answers

There are several ways of taking apart the number 14:

1 and 13

2 and 12

3 and 11

4 and 10

5 and 9

6 and 8

7 and 7

Nevertheless, as we can see by the note below that exercise,

"Have your child take apart 16 to make a ten to find 87 - 16",

we can conclude that the exercise is asking how to take apart 14 to make a ten. By doing so, the subtraction operation (28 - 14) gets simpler since you could subtract 4, and then subtract the ten:

14 = 10 + 4 (1 ten and 4 units)

So, when we do 28 - 14, we can do that in two steps:

• 28 - 4 = ,24

,

• 24, - 10 = 14

Therefore, based on the note below exercise 6, the expected answer is

10 and 4

What is the the measure and length of arc MC

Answers

As given by the question

There are given that the measuring circle.

Now,

From the given circle, the length of the MN is 28 units, because the half of the length of the MN is 14. So just multiply by 2 into half of the given value.

Hence, the length of MN is 28 units.

Now,

For the measure of MN:

The measurement of the angle MN is 74 degrees.

Hence, a measure of arc MN is 74 degrees. and the length of segment MN is 28 units.

Other Questions
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