Answers
The equation of a circle in center-radius form, is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]-Where the coordinates of the center of the circle are (h,k) and the radius of the circle is r.
From the given graph, we can see that the coordinates of the center are (-2,4) and the radius of the circle is 2.
a)
To determine the equation of the circle in center-radius form, replace h=-2, k=4 and r=2
[tex]\begin{gathered} \Rightarrow(x-(-2))^2+(y-(4))^2=2^2 \\ \Rightarrow(x+2)^2+(y-4)^2=4 \end{gathered}[/tex]Therefore, the equation of the circle in center-radius form is:
[tex](x+2)^2+(y-4)^2=4[/tex]b)
To find the equation of the circle in general form, expand the parentheses and take all the terms to the left member:
[tex]\begin{gathered} (x+2)^2+(y-4)^2=4 \\ \Rightarrow x^2+2(2)(x)+(2)^2+y^2-2(4)(y)+4^2=4 \\ \Rightarrow x^2+4x+4+y^2-8y+16=4 \\ \Rightarrow x^2+4x+y^2-8y+20=4 \\ \Rightarrow x^2+4x+y^2-8y+20-4=0 \\ \Rightarrow x^2+4x+y^2-8y+16=0 \end{gathered}[/tex]Write the quadratic terms first:
[tex]\Rightarrow x^2+y^2+4x-8y+16=0[/tex]Therefore, the equation of the circle in general form, is:
[tex]x^2+y^2+4x-8y+16=0[/tex]Related Questions
Is 5/6 equivalent to 0.832
Answers
Answer: No
Step-by-step explanation:
1 divided by 6 would be 16 and 4/6. So you would have to multiply 16 and 4/6 by 5, add them together, and then divide by 10 to get the decimal. 16 * 5 = 80. 4/6 * 5 = 20/6. 80/10 = 8. 20/6 divided by 10 = 10/6. 8+10/6 is not equal to .832
Graph the equation and find the x-coordinate of the x-intercept:1.5x - 3y = 7Round to the nearest hundredth
Answers
We can begin by finding the x-intercept. This is the point at which the graph crosses the horizontal axis. This point is given when the y-value of the function is 0, then, we can solve the equation for y = 0 and find the value for x:
[tex]\begin{gathered} 1.5x-3y=7\to y=0 \\ 1.5x-3\cdot(0)=7 \\ 1.5x=7 \\ x=\frac{7}{1.5} \\ x\approx4.67 \end{gathered}[/tex]The x value of the x-intercept of the equation is approximately 4.67.
This is a linear equation, to build the graph we just need 2 points and join them with the line.
The x-intercept is the point (4.67, 0). Another easy point to find and build the graph can be the y-intercept, which is given when x = 0. Replacing in the equation:
[tex]\begin{gathered} 1.5x-3y=7\to x=0 \\ 1.5\cdot(0)-3y=7 \\ -3y=7 \\ y=\frac{-7}{3} \\ y\approx-2.33 \end{gathered}[/tex]With this, the other point we can use to graph the equation is (0, -2.33).
Drawing both points on a cartesian plane:
Both points (x and y-intercepts) are drawn in red.
Use the times and corresponding closing prices of the stock to create coordinate pairs. Let X represent the number of weeks since the first at a point, and Y represent the closing price of each time. So, X equals zero represents the data point from five years ago. There are 52 weeks in a year, and you can write the time for each closing price recorded in terms of weeks that have passed since five years ago, when X equals zero. Fill in the table to represent your data as coordinate pairs
Answers
Combining both tables we get:
The area in square millimeters of a wound has decreased by the same percentage every day since it began to heal. The table shows the wound's area at the end of each day.
Answers
Given the table showing the number of days since wound began to heal and area of wound in square millimeters
To determine the statement that are correct from the option provided
From the table shown it can be seen that as the day increases by 1, the area of wound in square millimeters decreases by a common ratio of
[tex]\frac{20}{25}=\frac{16}{20}=\frac{12.8}{16}=\frac{10.24}{12.8}=0.8[/tex]Suppose that an expression to represent the area of wound is
[tex]ab^c[/tex]The modelled expression from the table is
[tex]\begin{gathered} a=25 \\ b=0.8 \\ c=n-1 \\ \text{Therefore, we have} \\ 25(0.8^{n-1}) \end{gathered}[/tex]Let us use the modelled expression to verify each of the given conditions
The modelled expression can be simplified as shown below:
[tex]\begin{gathered} 25(0.8^{n-1}) \\ \text{Note},\text{ using indices rule} \\ \frac{a^n}{a}=a^{n-1} \\ \text{Therefore:} \\ 0.8^{n-1}=\frac{0.8^n}{0.8} \end{gathered}[/tex]Then, we have the modelled expression becomes
[tex]25(0.8^{n-1})=25\times\frac{0.8^n}{0.8}=\frac{25}{0.8}\times0.8^n=31.25(0.8^n)[/tex]From the two modelled expression we can see that
[tex]\begin{gathered} \text{when:} \\ c=n-1,a=25,b=0.8 \\ c=n,a=31.25,b=0.8 \end{gathered}[/tex]Then we can conclude that the two conditions that are true from the options are
If the value of c = n, the value of a is 31.25, and
If the value of c = n, the value of b is 0.8
helpppppppppp!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
(f o g)(x) = 8x³ + 2x - 6
(g o f)(x) = 2x³ + 2x - 12
Step-by-step explanation:
f(x) = x³ + x - 6; g(x) = 2x
(f o g)(x) = f(g(x))
f(g(x)) = (2x)³ + (2x) - 6
f(g(x)) = 8x³ + 2x - 6
(g o f) = g(f(x))
g(f(x)) = 2(x³ + x - 6)
g(f(x)) = 2x³ + 2x - 12
I hope this helps!
Han and clan are stuffing enveloppes Han can stuff 20 envelopes in one minute and Clare can stuff 10 envelopes in one minute. They start working together on a pile of 1000 envelopes. How long does it take them to finish the pile.
Answers
uff = Given
Han can stuff 20 envelopes in one minute
Clare can stuff 10 envelopes in one minute
Together they start working on a pile off 1000 envelope.
Find
How long does it take them to finish the pile.
Explanation
as we have given
in one minute , Han can stuff = 20 envelope
in one minute , Clare can stuff = 10 envelope
together in one minute , they can stuff =
[tex]\begin{gathered} 20+10=30 \\ \\ \end{gathered}[/tex]we know that the number of time it will take to finish stuffing would be number of envelope / joint rate = 1000/30
so , time taken to finish the pile =
[tex]\begin{gathered} \frac{1000}{30} \\ \\ \frac{100}{3} \\ \\ 33\frac{1}{3} \\ or \\ 33min20sec \end{gathered}[/tex]Final Answer
Hence , the time taken by them to finish the pile is 33 minutes 20 seconds
If the distance from the too of the building to the tip of its shadow is 150ft, what is the length of the buildings shadow
Answers
In order to know the length of the shadow, we will use a trigonometric function in this case for the data given and the distance we want to find we will use the sine
[tex]\sin (75)=\frac{S}{150}[/tex]we isolate S
[tex]S=\sin (75)\cdot150=144.89[/tex]the length of the shadow is 144.89ft
help please A sandwich shop has three kinds of bread, seven types of meat, and four types of cheese. How many different sandwiches can be made using one type of bread, one meat, and one cheese?
Answers
Types of combinations of
Bread, Meat , CHeese
How many combinations of B M CH can be made.
There are 3, 7 and 4 types of food , respectively
Made a tree of possibilities
Then, for every 3 , there are 7 possibilities. Multiply both
3 x 7 = 21
And for every 7 , there are 4 possibilities . Multiply then
3x 7 x 4 = 84 possible type of sandwiches
Enter the correct answeach column.5. Bellatrix Lestrange keeps her money in GringottsWizarding Bank. She decided to take $100,000out of her vault and split it among three differentaccounts. She placed part in a savings accountpaying 3% per year, twice as much in Wizard bondspaying 5.5%, and the rest in a mutual fund thatreturned 4%. Her income from these investmentsafter one year was $4,480. How much did Bellatrixplace in each account?11223334.44HOW MUCH DID BELLATRIX PLACE IN THEMUTUAL FUND?556670N (0088
Answers
Assum,e that she put x in the account of 3%
So in wizard bonds, she put twice so it is 2x
The rest in the account of 4%
The rest is 100,000 - x - 2x = 100,000 - 3x
The rule of the investment is :
[tex]I=\text{prt}[/tex]I is the interest, P is the money she invested, r is the rate and t is the time
We will make equation for each account
[tex]\begin{gathered} I_1=x(\frac{3}{100})(1)=0.03x_{} \\ I_2=(2x)(\frac{5.5}{100})(1)=0.11x \end{gathered}[/tex][tex]I_3=(100,000-3x)(\frac{4}{100})(1)=4000-0.12x[/tex]The sum of the interest is 4,480, so add them and equate the sum by 4,480 to find the value of x
0.03x + 0.11x + 4000 - 0.12x = 4,480
Add like terms in the left side
0.02x + 4000 = 4,480
Subtract 4000 from both sides
0.02x + 4000 - 4000 = 4,480 - 4000
0.02x = 480
Divide both sides by 0.02
x = 24,000
The value in the mutual fund is 100,000 - 3x, so substitute s by 24,000
The mutual fund = 100,000 - 3(24,000) = 100,000 - 72,000 = 28,000
The mutual fund = $28,000
what is 2x2 and 3x0 and 3x3 and 4x4
Answers
4, 0, 9, and 16
i am stuck on this question. any help would be greatly appreciated
Answers
step 1
determine the slope of the given line
y=(3/5)x-17
The slope is m=3/5
Remember that
If two lines are parallel, then their slopes are equal
that means
The slope of the parallel line to the given line is m=3/5 too
step 2
Find out the equation of the line parallel to the given line
y=mx+b
we have
m=3/5
point (-5,15)
substitute and solve for b
15=(3/5)(-5)+b
15=-3+b
b=18
therefore
The equation of the line is
y=(3/5)x+18A teacher gets snacks for the class for $50 and also purchases 6 boxes of pencils. The teacher spent a total of $62. Write an equation that models the situation with x, the cost of one box of pencils.
Answers
Answer:
50 + 6x = 62
Explanation:
If x represents the cost of one box of pencils and the teacher got snacks for $50, purchased 6 boxes of pencils, and spent a total of $62, we can write the equation that models the above situation as shown below;
[tex]50+6x=62[/tex]Graph the line with the given slope m and y-intercept b.
m = 4,b=-5
Answers
The graph of the linear equation can be seen in the image at the end.
How to graph the linear equation?
The general linear equation is.
y = m*x + b
Where m is the slope and b is the y-intercept.
Here we know that m = 4 and b = -5, so we have:
y = 4*x - 5
To graph this line, we need to find two points.
Evaluating in x = 0 we get:
y = 4*0 - 5 = -5
Evaluating in x = 2 we get:
y = 4*2 - 5 = 8 - 5 = 3
So we have the points (0, -5) and (2, 3), so now we need to graph these points and connect them with a line, the graph can be seen below:
Learn more about linear equations:
https://brainly.com/question/1884491
#SPJ1
8. Anna withdrew $50 from her checking account. She spent $28 on a pair of shoes. What fraction of her money does Anna have left?
Answers
Explanation:
If she spent $28 of the $50 she withdrew, she now has:
[tex]50-28=22[/tex]$22
The fraction is:
[tex]\frac{22}{50}=\frac{11}{25}[/tex]Answer:
Anna has 11/25 of her money left.
Graph the reflection of the polygon in the given line #5 Y=2
Answers
We have the next image
the line of reflection is the line in red
the original polygon ABCD is the one in blue
the reflected polygon A'B'C'D' is the one in green
Let f(x)=5x.Let g(x)=5x−7.Which statement describes the graph of g(x)with respect to the graph of f(x)? g(x)is translated 7 units down fromf(x).g(x)is translated 7 units left fromf(x).g(x)is translated 7 units right from f(x).g(x)is translated 7 units up fromf(x).
Answers
Given
[tex]\begin{gathered} f(x)=5x \\ g(x)=5x-7 \end{gathered}[/tex]According to rules of transformation:
f(x)+c shift c units up and f(x)-c shift c units down.
For the given function g(x) = 5x-7, 7 is being subtracted from 5x.
Where 5x is represented by f function.
Therefore, we could apply the rules of transformation f(x)-c shift c units down.
Here the value of c is 7.
Answer: g(x) is translated 7 units down from f(x)
T is in seconds and L is the length of the pendulum in centimeters. Find the period of the pendulum of the given lengths. Give your answer to two decimal places using 3.14 for π. Show and explain your work below. a. L = 23 cm b. L = 192 cm
Answers
The period of the pendulum in each case is given as follows:
a. L = 23 cm: 0.96 s.
b. L = 192 cm: 2.78 s.
Period of pendulumThe period of a pendulum is defined according to the following equation:
P = 2π sqrt(L/g)
In which the parameters are as follows:
L is the length of the pendulum which we want to find the period.g = 9.8 m/s² is the acceleration of the pendulum due to the gravity.For a length of 23 cm = 0.23m, in item a, considering 3.14 for π, the period is calculated as follows:
P = 6.28 x sqrt(0.23/9.8) = 0.96 s.
In item b, the length is of 192 cm = 1.92 m, as each cm has 100 m, hence the period is given by:
P = 6.28 x sqrt(1.92/9.8) = 2.78 s.
More can be learned about the period of a pendulum at https://brainly.com/question/26449711
#SPJ1
A system of equations is shown below. Solve for x.
y = x² - 6x + 4
y = x + 1
Answers
The value of x in the given quadratic equations is either -2.7 or -11.3.
What are quadratic equations?A quadratic equation is a second-degree algebraic equation in x. ax² + bx + c = 0, where a and b are coefficients, x is the variable, and c is the constant term, is the quadratic equation in its simplest form.
Given first equation, y = x²- 6x + 4 second equation, y = x +1
Put the value of y in the first equation to get
x + 1 = x² - 6x + 4
Solving this equation
x² - 7x + 3 = 0
Using quadratic formula,
x = - b ± [tex]\frac{\sqrt{(b^{2}- 4ac)}}{2a}[/tex]
x = - 7 ± [tex]\frac{\sqrt{(-7)^{2}- 4(3)}}{2}[/tex]
x = - 7 ± 4.3
Therefore in the given quadratic equations, the value of x can be either -2.7 or -11.3
For more information on quadratic equations, visit:
https://brainly.com/question/1863222
#SPJ13
creat an espression that includes the zero property of exponents the multiplication property of exponents and the power of a power property of exponents
Answers
All in one, or one expression for each property?
a) Zero property
[tex]\text{ (x + y)}^0\text{ = 1}[/tex]b) Multiplication property
[tex]\text{ x}^2\cdot x^5=x^{2+5}=x^7[/tex]c) Power property
[tex]\text{ (x}^2)^3=x^{2\cdot3}=x^6[/tex]d) All in one (this is the expression)
[tex]\mleft\lbrace\text{(x}^0)(x^3)\mright\rbrace\text{ }(x^2)^5[/tex][tex]\text{ }\mleft\lbrace1(x^3\mright)\}(x^{10})[/tex]
The top-selling Red and Voss tire is rated 60000 miles, which means nothing. In fact, the distance the tires can run until wear-out is a normally distributed random variable with a mean of 72000 miles and a standard deviation of 7000 miles.A. What is the probability that the tire wears out before 60000 miles?Probability = What is the probability that a tire lasts more than 80000 miles? Probability=
Answers
a. 0.0436
b. 0.1271
We are given the following:
Distance (x) = 60,000
Mean (u) = 72,000
Standard Deviation(s) = 7,000
We are also told that it is a normal disribution relationship. The formula for ND is as follows:
z = (x - u) / s
Now we can continue with part a and b as follows:
a) P (x < 60,000)
= P (z < (60000 - 72000) / 7000)
= P (z < -1.714)
We can find the corresponding z score by looking at a z score table, and we find th probability to be 0.0436
b) P ( x > 80,000)
= P(z > (80000 - 72000) / 7000)
= P( z > 1.143)
We find the corresponding z score to be 0.8729, now we can substract this from 1 sinsce our probability is larger than the given distance (meaning we are trying to find the area to the right of the z score) to find our final answer:
1 - 0.8729 = 0.1271
Supposed g is a one-to-one function with the following valuesg(-7)= -6g(11)= -1
Answers
Given:
The function g(x) is one-one.
[tex]g(-7)=-6[/tex][tex]g(11)=-1[/tex]Required:
We need to find the values of the inverse image of the function g(x).
Explanation:
Recall that the image of distinct elements of the function is distinct.
There exist an inverse of g(x) since g(x) is one to one.
The inverse image of the given can be written as follows.
Consider the equation
[tex]g(-7)=-6[/tex][tex]g^{-1}g(-7)=g^{-1}(-6)[/tex][tex]g^{-1}(-6)=-7[/tex][tex]g(11)=-1[/tex][tex]g^{-1}g(11)=g^{-1}(-1)[/tex][tex]g^{-1}(-1)=11[/tex]Final answer:
[tex]g^{-1}(-6)=-7[/tex][tex]g^{-1}(-1)=11[/tex]I need to help finding the length of the arc shown in red..
Answers
We have the next formula to find the length is
[tex]\text{arc length }=\text{ 2}\pi r(\frac{\theta}{360})[/tex]where
r=10
theta=45°
[tex]\begin{gathered} \text{arc length=}2\pi(10)\frac{45}{360}=\frac{5}{2}\pi \\ \end{gathered}[/tex]the arc length is 5/2 pi cm
Write the tangent ratios for LP and 4Q. If needed, reduce!P12R160Not drawn to scaletan P=tan Q =
Answers
Given: The right triangle PQR as shown
To Determine: The tangents of P and Q
Solution
Given a right triangle, the tangent of any angle can be determine
Note that the side facing the right angle is the hypothenuse, the side facing the angle is the opposite and the other side is the adjacent.
Determine the opposite and the adjacent for angle P in the triangle PQR given
[tex]\begin{gathered} Note; \\ tan\theta=\frac{opposite}{adjacent} \\ tanP=\frac{16}{12} \\ tanP=\frac{4}{3} \end{gathered}[/tex]Under certain conditions, the velocity of a liquid in a pipe at distance r from the center of the pipe is given by V = 400(3.025 x 10-5--2) where Osrs5,5x10 -3. Writeras a function of V.r=where the domain is a compound inequality(Use scientific notation. Use integers or decimals for any numbers in the expression.)Le
Answers
Solving the equation for r:
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-r^2) \\ r^2=9.025\cdot10^{-5}-\frac{V}{400} \\ r=\sqrt[]{9.025\cdot10^{-5}-\frac{V}{400}} \end{gathered}[/tex]With the first equations, we can establish some limits for V:
With the lowest value for r (r=0):
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-0^2) \\ V=400(9.025\cdot10^{-5}) \\ V=3.61\cdot10^{-2} \end{gathered}[/tex]With the highest value for r (r=9.5x10^-3)
[tex]\begin{gathered} V=400(9.025\cdot10^{-5}-(9.5\cdot10^{-3})^2) \\ V=400(9.025\cdot10^{-5}-9.025\cdot10^{-5}) \\ V=400(0) \\ V=0 \end{gathered}[/tex]According to the radius range, velocity can be between 0 and 3.61x10^-2
It is also necessary to check the domain of the function considering it is a square root. The argument of an square root cannot be less than 0. Then:
[tex]\begin{gathered} 9.025\cdot10^{-5}-\frac{V}{400}\ge0 \\ 9.025\cdot10^{-5}\ge\frac{V}{400} \\ V\leq400(9.025\cdot10^{-5}) \\ V\leq3.61\cdot10^{-2} \end{gathered}[/tex]This is the same limit for velocity obtained before. Then, we can say for velocity that:
[tex]0\leq V\leq3.61\cdot10^{-2}[/tex]food cost for your restaurant is about $.38 on the dollar. that means for every dollar in sales, you spend 38 cents in food cost.figure out the food cost for the following days’ sales:monday:$3,459.00tuesday:$2,976.81wednesday:$3,185.32thursday:$3,562.91friday:$4,582.13saturday:$4,820.36
Answers
The Solution.
Monday's sales is $3459.00
The food cost for Monday is
[tex]\text{ Food cost = 0.38}\times3459=\text{ \$1314.42}[/tex]Tuesday's sales is $2976.81
The food cost for Tuesday is
[tex]\text{Food cost = 0.38}\times2976.81=\text{ \$}1131.19[/tex]Wednesday's sales is $3185.32
The food cost for Wednesday is
[tex]\text{ Food cost = 0.38}\times3185.32=\text{ \$}1210.42[/tex]Thursday's sales is $3562.91
The food cost for Thursday is
[tex]\text{Food cost = 0.38}\times3562.91=\text{ \$}1353.91[/tex]Friday's sales is $4582.13
The food cost for Friday is
[tex]\text{Food cost = 0.38}\times4582.13=\text{ \$}1741.21[/tex]Saturday's sales is $4820.36
The food cost for Saturday is
[tex]\text{Food cost = 0.38}\times4820.36=\text{ \$}1831.74[/tex]Convert to fractional Notation 4 19/100
Answers
to solve this we need to convert the number 4 to a fraction with denominator 100 and add both fractions
to do that we can multiply 4 and 1 by 100, like this:
[tex]\frac{4\cdot100}{1\cdot100}=\frac{400}{100}[/tex]now we can add the fractions
[tex]\frac{400}{100}+\frac{19}{100}=\frac{419}{100}[/tex]So the answer is: 419/100
The table shows the total cost c for the number of aquarium tickets purchased t. Write an equationthat can be used to find the cost c oft aquarium tickets. Use the equation and complete the table tofind the cost of 7 tickets.7Number of Tickets, tCost, cWrite an equation3$29.2510 12$97.50 $117.00(Use the operation symbols in the math palette as needed. Use integers or decimals for any numbers in the equatioDo not include the $ symbol in your answer.)
Answers
We can model the cost and number of tickets by a linear equation of the form
[tex]c=mt+b[/tex]Where c is the cost, t is the number of tickets.
m is the slope of the equation and b is the y-intercept.
First, let us find the slope which is given by
[tex]m=\frac{c_2-c_1}{t_2-t_1}[/tex]You can take any two pairs of values from the table.
[tex]m=\frac{117-97.50}{12-10}=\frac{19.5}{2}=9.75[/tex]The slope is 9.75 and the equation becomes
[tex]c=9.75t+b[/tex]Now we need to find the y-intercept (b)
Choose any one pair of values from the table and substitute them into the above equation and solve for b.
Let's choose (12, 117)
[tex]\begin{gathered} c=9.75t+b \\ 117=9.75(12)+b \\ 117=117+b \\ b=117-117 \\ b=0 \end{gathered}[/tex]The y-intercept is 0 so the equation is
[tex]c=9.75t[/tex]Now to find the cost of 7 tickets, simply substitute t = 7 into the above equation
[tex]\begin{gathered} c=9.75t \\ c=9.75(7) \\ c=68.25 \end{gathered}[/tex]Therefore, the cost of 7 tickets is $68.25
Use a calculator to evaluate the expression. (Do not round until the final answer. Then round to three decimal places as needed.)
Answers
2.303
1) For the following expression:
[tex]\frac{\ln30+\ln15}{\log_{10}30+\log_{10}15}[/tex]We can simplify that and then round it off to the nearest thousandth:
2) Let's rewrite them simplifying using the logarithm property of multiplication:
[tex]\begin{gathered} \frac{\ln30+\ln15}{\log_{10}30+\log_{10}15}= \\ \frac{\ln(30\cdot15)}{\log_{10}30+\log_{10}15}= \\ \frac{\ln(30\cdot15)}{\log_{10}(30\cdot15)}= \\ \frac{\ln(450)}{\log_{10}(450)}= \end{gathered}[/tex]Note that the base of the Natural Log is the Euler's number "e" so let's move on now using the calculator, finally:
[tex]\frac{\ln(450)}{\log_{10}(450)}=\frac{6.10924}{2.65321}=2.30258\ldots\approx2.303[/tex]Note that only at the last step we have rounded it off. And that's the
answer
For what value of x does 32x93x-4?oo 2o 3o 4
Answers
Solution
[tex]3^{2x}=9^{3x-4}[/tex]We can do the following:
[tex]3^{2x}=3^{2(3x-4)}[/tex]And we have this:
[tex]2x=6x-8[/tex][tex]4x=8[/tex][tex]x=\frac{8}{4}=2[/tex]true or false 16/24 equals 30 / 45
Answers
True.
Given:
The equation is, 16/24 = 30/45.
The objective is to find true or false.
The equivalent fractions can be verified by, mutiplying the denominator and numerator of each fraction.
The fractions can be solved as,
[tex]\begin{gathered} \frac{16}{24}=\frac{30}{45} \\ 16\cdot45=24\cdot30 \\ 720=720 \end{gathered}[/tex]Since both sides are equal, the ratios are equivalent ratios.
Hence, the answer is true.
