A freight train moves due north with a speed of 8 m/s. The mass of the train is 6 x 106 kg. How fast would a 1500 kg automobile have to be moving due north to have the same momentum as the train

Answers

Answer 1

The freight train has a momentum of mv = (4.5 × 105 kg)(1.4 m/s) = 6.3 ×105 kg-m/s.

An automobile with a mass of 1800 kg would need to go at a speed of 6.3  × 105 kg-m/s ÷ 1800 kg = 350 m/s in order to have a momentum of the same magnitude. (Roughly 800 mph)

A moving body's amount of motion is referred to as momentum. It has units of kg m/s and is theoretically represented as p = m * v.

The momentum equation connects the total force exerted on a fluid element to its acceleration or rate of change of momentum and is a formulation of Newton's Second Law. You're certainly familiar with the formula F = ma, which links applied force and acceleration in solid mechanics analysis.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

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Related Questions

10. Unless a light ray comes into contact with a surface or enters a different material, it travels in a​

Answers

Unless a light ray comes into contact with a surface or enters a different material, it travels in a​ straight line.

When light enters a medium with a different speed or transitions from a fast to a slow medium, refraction occurs. According to Snell's law, if a light ray is incident ordinarily on the surfaces, then deviating from the normal will always lengthen the travel time.

Theoretically, sine (angle of incidence)*index of refraction of the incident media = sine (angle of refraction)*index of refraction of the refractive medium

Sine (0)=0 because the angle of incidence is 0 degrees.

As a result, the light ray will travel straight.

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how do the kinetic energy of each of the following objects compare to one another? i. object of mass 3 kg traveling at constant velocity of 4 m/s in the x x direction ii. object of mass 1 kg traveling at constant velocity of 8 m/s in the x x direction iii. object of mass 3 kg traveling at constant velocity of 3 m/s in the x x direction and -3 m/s in the y y direction

Answers

The kinetic energy of each of the following objects compare to one another as: II > I > III

As we know the kinetic energy is follows as:

K.E. = 1/2m[tex]v^{2}[/tex]

(i) Object 1

mass = 3kg

velocity = 4m/s

K.E. = 1/2m[tex]v^{2}[/tex]

K.E. = 1/2×3×4×4

K.E. = 24J

(ii) Object 2

mass = 1kg

velocity = 8m/s

K.E. = 1/2m[tex]v^{2}[/tex]

K.E. = 1/2×1×8×8

K.E. = 32J

(iii) Object 3

mass = 3kg

velocity = -3m/s

K.E. = 1/2m[tex]v^{2}[/tex]

K.E. = 1/2×3×(-3)×(-3)

K.E. = 13.5J

Therefore, the kinetic energy of each of the following objects compare to one another as: II > I > III

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name two powers of the president

Answers

Answer:

The President can issue executive orders, which direct executive officers or clarify and further existing laws.

The President also has the power to extend pardons and clemencies for federal crimes.

Explanation:

what velocity must a car with a mass of 1260 kg have in order to have the same momentum as a 2240 kg pickup truck traveling at 24 m/s to the east? answer in units of m/s

Answers

The velocity of the car is 46.48 m/s.

What is velocity?

velocity is directional speed of a object in motion as an induction of it's rate of change in position observed from a particular frame of reference and as measured by a particular standard of time.

Sol- The linear momentum of a body is defined as the product of its mass and its velocity, given by-

P = mv

According to the question the momentum of the truck is-

Pr=2250×25 kgm /s

Pr=56250 kgm/s

Now we can see the momentum of the car and the truck must be same that is Pc=Pr

1210×v =56250 kgm/s

v= 56250/1210

v= 46.48 m/s

Thus the velocity of the car is 46.48m/s .

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a plane, diving with constant speed at an angle of 53.0o with the vertical, releases a projectile at an altitude of 730 m. the projectile hits the ground 5.00s after release. a) what is the speed of the plane?

Answers

The speed of the plane = 202m/s

What is speed ?

Speed is what it means. the speed at which an object's location changes in any direction. The distance travelled in relation to the time it took to travel that distance is how speed is defined. Speed is a scalar quantity since it just has a direction and no magnitude.

To make equations like Eq. immediately applicable, we accept the textbook's use of positive direction options. Directly beneath the release point, at ground level, is the coordinate origin.. The coordinate origin is at ground level directly below the release point. We write θo = −37.0degree

 for the angle measured from +x, since the angle φo = 53.0 degree

 measured in the problem is in the -y direction. The graphic below depicts the problem's basic configuration.

(A) The plane's speed at the point of release determines the projectile's initial speed. Given

that y0 = 730m and y=0 at t=5.00s,

to find v  : y−yo  =(v sinθo)t− 1/2gt^2 ⇒0.730m=v

sin(−37.0 degree )(5.00s)− 1/2(9.80m/s^2 )(5.00s) ^2

which yields v  =202m/s.

the speed of the plane = 202m/s

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how do you find the average force applied for a wind-up toy car while it is speeding up? It speeds up for .8s and has a velocity of .741 m/s. Total motion is 220 cm over 2.70s. Converted the cm into m (100 cm = 1 M) any help?

Answers

The average force applied for a wind-up toy car while it is speeding up is 0.926m (N), where m is the mass of the toy.

What is the average force applied to an object?

The average force applied on an object is determined by applying Newton's second law of motion.

Mathematically, the average force applied on an object is given as;

F = ma

where;

m is the mass of the objecta is the acceleration of the object

The acceleration of the wind up toy is calculated as follows;

a = v/t

where;

v is the velocity of the wind-up toyt is the time of motion of the toy

a = (0.741 m/s) / (0.8 s)

a = 0.926 m/s²

Substitute the value of the mass of the wind-up toy and its acceleration into the force equation to determine the average force applied to the toy.

F = m(0.926)

F = 0.926m (Newton)

Thus, the average force applied for a wind-up toy car while it is speeding up is 0.926m (N), where m is the mass of the toy.

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if a cylindrical space station 275 mm in diameter is to spin about its central axis, at how many revolutions per minute ( rpmrpm ) must it turn so that the outermost points have an acceleration equal to gg ?

Answers

Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm

What is Rotation speed ?

The rate at which the Aeroplan should begin rotating into takeoff attitude is known as V r.

V r, the rotational speed, cannot be lower than V1. A subsequent rejected takeoff may not be achievable within the remaining runway length and is likely to result in a Runway Excursion if it is more than V1 and it is discovered that, at V r, rotation cannot be completed.

V r depends on the weight of the aircraft and the flap position, but it can also change according on temperature, pressure, and altitude.

Gravitational acceleration = g = 9.8 m/s2

Diameter of the space station = D = 275 m

Radius of the space station = R

R = D/2

R = 275/2

R = 137.5 m

Angular speed of the space station = [tex]\omega (rad/s[/tex])

Centripetal acceleration at the outermost points = ac = g = 9.8 m/s2

ac = [tex]\omega2R\\[/tex]

9.8 =[tex]\omega2(137.5)[/tex]

[tex]\omega \\[/tex]= 0.267 rad/s

Converting from rad/s to rpm,   (1 revolution = [tex]2\pi radians[/tex] , 1 minute = 60 seconds)

\omega = 0.267 [tex]\times (\frac{60}{2\pi })[/tex]

\omega = 2.55 rpm

Rotation speed of the space station so that the outermost points have an acceleration equal to 'g' = 2.55 rpm

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7 The distance-time graph for a motorcyclist riding
off from rest is shown in Figure 1.2.18.
a Describe the motion.
b
Calculate how far the motorbike moves in
30 seconds.
c Calculate the speed.

Answers

Answer:

a) Uniform rectilinear motion

b) 600 m

c) 20 m/s

Explanation:

a) average velocity is described as the change of position divided by the time of travel, so v= ∆x/∆t. This is a linear function (y = mx+ q) which is the same structure of the equation needed to calculate average velocity (x2= x1 + vt). If you do the ratio between a distance and the corresponding time you'll see that the average velocity is the same, which is typical of this kind of motion.

b) At the the time of 30 seconds the corresponding distance on the y axis is 600 m.

c) Again, v=∆x/∆t and we can rewrite is as v=x2-x1/t. If you take the same data we've used before you can write v= 600m-0/ 30s= 20 m/s. The average velocity is 20 m/s.

a uniformly charged conducting sphere of 1.22 m radius has a surface charge density of 8.13 c/m*. (a) find the charge on the sphere. (4) what ts the total electric flux leaving the surface of the sphere? (c) calculate the electric field at the surface of the sphere.

Answers

We select a spherical-shaped Gaussian surface that is concentric with the conducting sphere and has a little bigger radius. Gauss's law determines the flux:

ϕ= ϵ 0 q \s​ = 8.85×10 −12 C 2 /N.m 2

3.66×10 −5 C =4.1×10 6 N.m 2 /C

What makes it the Gauss law?

Gauss' Law, which bears the name of German physicist Carl Friedrich Gauss, is the third of Maxwell's four equations. According to Gauss' Law, an electric charge, qv, or static electricity, produces an electric field, E. (voltage). According to this equation, adding more charge will result in a larger electric field.

According to Gauss's Law, the flux of an electric field through a closed surface equals the contained charge divided by a constant.

Gauss's Law may be used to determine the field due to four different types of equally charged objects: a straight wire, an infinite plate sheet, a thin spherical shell, and a low evenly charged sphere.

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two objects were lifted by machine. one object had a mass of 2kg, and was lifted at a speed of 2m/s. the other had a mass of 4kg and was lifted at a rate of 3m/s. Which object had more potental energy while it was being lifted a distance of 10 meters?

Answers

The object having mass 4kg will have greater potential energy as it has larger mass.


What is potential energy  ?

Potential energy is a form of stored energy that is dependent on the relationship between different system components. A spring's potential energy rises when it is compressed or stretched. If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised. Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.

U=m g h

The object having mass 4kg will have greater potential energy as it has larger mass.



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two automobiles, each of mass 800 kg , are moving at the same speed, 18 m/s , when they collide and stick together. at what speed does the wreckage move if one car was driving north and one east?

Answers

14.14 m/s speed does the wreckage move if one car was driving north and one east

Based on the moment of momentum conservation in the x-direction,

1000 20 = (1000 + 1000) yields v _y v y = 10 m/s.

result = 14.14 m/s

What makes momentum so crucial?

An object's mass, velocity, and direction are all related by momentum. Force arises from any change in momentum. In order to ascertain the force exerted on the item, a change in momentum is utilised.

Force and momentum are distinct even though they appear to be the same physical quantity. Whether a body is being pulled or pushed, force is often defined as an outside action. The measure of how much motion there is inside a moving body is called momentum, on the other hand.

Unlike force, which refers to a push or pull action, momentum refers to the amount of motion in a moving body. Force modifies a body's momentum. While momentum varies while acceleration is constant, force does not.

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g an angry rhino with a mass of 3000 kg charges directly toward you with a speed of 5.00 m/s. before you start running, as a distraction, you throw a 0.180 kg rubber ball directly at the rhino with a speed of 6.89 m/s. determine the speed of the ball (in m/s) after it bounces back elastically toward you.

Answers

Answer:

Duck to avoid the ball and dodge the rhino’s attack and then try and climb the nearest tree. Hope that helps.

Explanation:

For me I’d say it’d be instinct for the answer.

When you prepare a kettle of stew over a camp fire, the stew is warmed in a variety of ways. Explain the combination of processes.

Answers

The combination of processes through which the stew is being warmed include conduction, convection and radiation.

What is heat transfer?

Heat transfer is defined as the phenomenon whereby heat generated in a medium is being transferred to another location by phase changes.

The transfer of heat occurs in the following combination processes such as:

Thermal Conduction: the transfer of heat through direct contact of the pot of stew with the camp fire.

Thermal Convection: the transfer of heated stew at the base of the pot to the stew of the topmost part is through this process.

Thermal radiation: this is the heat waves from the camp fire that heats the pot of stew.

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can somebody help me with this?

Answers

Answer: (D) thrust has overcome the drag force

Explanation: In order for the plane to move forward, the backward force will have to be overcome. As thrust is a force in the opposite direction of drag so it can cancel out the backward pull of drag and move forward.

An elevator in a hotel starts at ground level. It rapidly moves up to the third floor, where it stops to unload passengers. The elevator then descends to the basement at a slower speed than before.

Identify whether or not the graph correctly represents the story. Explain your answer in 1-2 sentences.

Answers

The graph does not correctly represent the story because the elevator descends to the basement at a faster speed than before.

What is the upward motion of an elevator?

An elevator going up shows uniform linear motion, as elevator will move in a straight line with a constant speed.

This type of motion can be shown using a straight line graph.

The downward motion of an elevator descending or moving downwards can be explained as follows;

An elevator moving downwards shows uniform linear motion, as elevator will move in a straight line with a constant speed.

From the given graph we can conclude the following;

During the upward motion of the elevator, at point A, the elevator moved up gradually.At point B the elevator maintained a constant speedduring the downward motion at point C, the moved down more quickly than during the upward motion.

Thus, from the greater steepness of the downward motion of the elevator than the upward motion, we can conclude that the elevator descends to the basement at a faster speed than before.

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i would appreciate it if you could help me if would help a bunch on getting caught up with my work.

Answers

2. Experiment:

We need to make a circuit to test which of the materials are conductors and insulators.

Build the circuit as shown below.

If the light bulb is on then it is a conductor otherwise it is an insulator.

Keep replacing the material one by one to test all the materials.

50 N of force is applied to a spring and its length increases by 25 cm. If the spring is obeying Hooke's law, what force would be required to give it an extension of 75 cm?

Answers

I think the spring constant is not changing

how does heat move from the inside to the outside in the outer 30% of the sun? through neutrinos released by nuclear fusion by convection: hot gas rises and cool gas sinks by radiation: photons bounce around heating up the gas by sound waves

Answers

Heat moves from the inside to the outside in the outer 30% of the sun by hot gas rises and cool gas sinks by radiation.

Radiation is the exchange of heat vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is imperceptible. As it were a little parcel comes as obvious light.

Energy from the sun is exchanged through space and the earth's climate to the earth's surface. Since this vitality warms the earth's surface and environment, a few of it is or gets to be heat vitality.

Even though you're encompassed by discussion, the discussion has nothing to do with this exchange of heat.

Heat lights, that keep food warm, work in the same way. Radiation is the exchange of warm vitality through space by electromagnetic radiation. Most of the electromagnetic radiation that comes to the soil from the sun is undetectable.

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A man is pulling on a rope with a force of 44 N
directed at an angle of 63◦
to the horizontal.
What is the x-component of this force?
Answer in units of N.

Answers

Answer:

20 N

Explanation:

Vertical component will be   44 sin 63

HORIZONTAL component is  44 cos 63  N = 19.97 =~ 20 N

The atomic number of aluminum is 13. What is the correct designation of the electron configuration of aluminum?.

Answers

Aluminum has the following electron configuration: 1s2, 2s2, 2p6, 3s2, and 3p1.

According to the information supplied, aluminum has an atomic number of 13. That makes it abundantly evident that the nucleus of any atom that is an isotope of aluminum will contain 13 protons. The proton number will be equal to the number of electrons surrounding the nucleus. There will be 13 electrons as a result.

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now assume that a satellite of mass mmm is orbiting the earth at a distance rrr from the center of the earth with speed vevev e . a satellite of mass 2m2m2m is orbiting mars, also at a distance rrr from the center of mars, with a speed vmvmv m . what is the ratio tmte

Answers

The ratio between centripetal force of satellite b and satellite a is 2vm²/ ve².

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

From the question, we know that

ma = m

mb = 2m

va = ve

vb = vm

ra = rb = r

Find the centripetal force ratio

Fcb / Fca = (mb . vb²/Rb) / (ma . va²/Ra)

Fcb / Fca = (2m . vm²/r) / (m . ve²/r)

Fcb / Fca = 2 . vm²/ ve²

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If an object is thrown horizontally, travels with an average x-component of its velocity equal to 5m/s, and does not hit the ground, what will be the x-component of the displacement after 20s?

Answers

Answer:

100 m

Explanation:

5  m/s   *   20 s = 100 m

On his trip from home to school, Noah Omwerk drives along three streets after exiting the driveway. He drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. Determine the magnitude of Noah's resultant displacement. And the angle from East to South.

Answers

The resultant displacement of Noah from the question is  2.9 miles.

What is the resultant displacement?

The displacement is a vector quantity. Recall that a vector quantity is going to posses both a magnitude and a direction as we can see. This implies that the result of the vector which is the single vector that has the combines effect in magnitude and direction as all the vectors put together would be obtained by a geometric rather than an algebraic method. We now have to apply the rules that are used to obtain the resultant vector in each of the cases that does apply here.

We are now told that he drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. The resultant of the vector in the North - South direction is; 1.85 miles - 0.35 miles = 1.5 miles.

Then the general resultant vector is obtained from;

R = √(1.5)^2 + (2.43)^2

R = 2.9 miles

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after driving a portion of the route, the taptap is fully loaded with a total of 23 people including the driver, with an average mass of 65 kg per person. in addition, there are three 15- kg goats, five 3- kg chickens, and a total of 25 kg of bananas on their way to the market. assume that the springs have somehow not yet compressed to their maximum amount. how much are the springs compressed?

Answers

The compression of the spring at the given weight is 61 cm.

Given,

The spring constant is k =2.4 × 10⁴ N/m

mass of each of the 23 persons, = 65 kg

mass of each of the 3 goats, = 15 kg

mass of each of the 5 chickens, = 3 kg

mass of the bananas, = 25 kg

The total mass of all the passengers contained in the laptop is calculated as;

total mass of the persons = 23 x 65 = 1495 kg

total mass of the goats = 3 x 15 = 45 kg

total mass of the chickens = 5 x 3 = 15 kg

the total mass of the bananas = 25 kg

The total mass = (1495 + 45 + 15 + 25)kg

1The total mass = 580 kg

The calculation for the lengthy of spring:-

F = kx

x = F/k = mg/k

x = (1495*9.8)/2.4*10^4

x = 0.610 m

x = 61 cm

Hence, the compression of the spring at the given weight is 61 cm.

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A student throws a rock upwards. The rock reaches a maximum height 2.4 seconds after it is released.
How fast was the rock thrown?

Answers

From Kinematics, the equation for final velocity is

v = [tex]v_{0}[/tex] +at

where [tex]v_{0}[/tex]  is the initial velocity, 'a' is the acceleration of the rock, and t is the time taken.

Given, that the rock is thrown upwards and it takes time t = 2.4s to reach a maximum height. So, its acceleration is a= -g= -9.8 m/[tex]s^{2}[/tex] and final velocity is v = 0m/s. To find initial velocity of the rock, rearrange above velocity equation.

⇒[tex]v_{0}[/tex]  = v - at

⇒[tex]v_{0}[/tex]  = 0 - (-9.8m/[tex]s^{2}[/tex] × 2.4s)

∴ [tex]v_{0}[/tex]  = 23.52 m/s.

Thus, the rock was thrown with a velocity 23.52 m/s.

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a 20kg is pulled along a horizontal surface by a fp of 50.on applied at 25 degrees angle above the horizontal. consider friction, and assume a coefficient of kinetic friction of 0.20. calculate the acceleration

Answers

The net acceleration of the block is about -2.04m/s².

The mass of the block is 20Kg. The force applied is 50 N and the angle at which the force is applied is 25°. The coefficient of friction is 0.20.

When the block will be pulled along horizontal by applying Force fat an angle A, then there will be two components of force one along vertical fsinA and one along horizontal fcosA.

The friction will be in opposite direction,

So, we can say, the net Force F on the block is,

F = Fr - fcosA

Ma = uN -fcosA

Where,

a is the acceleration of the block,

M is the mass of the block,

N is the normal force,

f is the applied force and,

u is the coefficient of friction.

Putting all the values,

20(a) = 0.2(50)sin(25°) - 50cos(25°)

20a = 0.2(0.42)(50)-50(0.9)

20a = 4.2 - 45

20a = 40.8

a = -2.04m/s².

The net acceleration of the block is -2.04m/s².

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Neptune has a mass that is about 17 times the mass of earth. the distance between the sun and neptune is about 30.1 times the distance between the sun and earth. if the gravitational force between the sun and earth is 3.5 x 1028 n, which is closest to the force between neptune and the sun? 6 x n 6 x n 6 x n 6 x n

Answers

We would weigh 114 kg on Neptune if we weighed 100 kg on Earth. In comparison, we would experience much lower gravity on the Moon (16.5%) or Mars (37.6%).

Neptune is much larger than Earth. In fact, its mass is 17 times that of the Earth. Neptune's surface gravity is approximately 110% that of Earth's, so if you weigh 100 pounds on Earth, you would weigh 110 pounds on Neptune (assuming you could find someplace to, well, stand). M is subdivided into two parts, m1 and m2. The ratio of m1/M for which the gravitational attraction between the two parts becomes maximum at a given separation is. 1:1.

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Answer:

6 x 10^26 N

Explanation:

a cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. the lift is performed in three stages, each requiring a vertical distance of 10.0 m. (1) first, the initially stationary spelunker is accelerated to a speed of 5.30 m/s. (2) then he is then lifted at the constant speed of 5.30 m/s. (3) finally he is decelerated to zero speed. how much work is done on the 73.0 kg rescuee by the force lifting him during each stage?

Answers

Mass m = 73kg

Vertical height in each stage h = 10 m

A). Initial speed u = 0

Final speed v = 4.3m / s

Work done W= mgh + ( 1/ 2) m[v 2 - u 2 ]

= 7063.2 +665.64

= 7728.84 J

B).Work done W = mgh

= 7063.2J

C).Work done W  = mgh + ( 1/ 2) m [ V 2 - v 2 ]

Where  V = final speed

= 0

v =4.3m / s

Substitute the values we get  W =7063.2 - 665.64

= 6397.56 J

To slow down a vehicle The vehicle slows down when it sees a police car. Thesaurus synonyms, antonyms, and examples. slow down. Slowing down The car slowed down and stopped next to her. A motionless object has zero velocity. If an object has zero acceleration its velocity must be constant.

Whenever an object's acceleration is in the same direction as its velocity, the car is accelerating and is said to be accelerating. If the acceleration is simultaneously opposed to the speed, the car is said to be slower and slower. Delay slows down: An unexpected slowdown in your car could mean you're running out of gas.

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a soccer ball is kicked from the ground with an initial speed of 19.5 m/s at an upward angle of 45o. a player 55m away in the direction of the kick starts running to meet the ball at that instant. what must be his average speed if he is to meet the ball just before it hits the ground?

Answers

Answer:

R = V^2 sin 2θ / g        range formula

R = 19.5^2 * 1 / 9.80 = 38.8 m

Vx = 19.5 cos 45 = 13.8 m/s       horizontal speed

t = R / Vx = 38.8 / 13.8 = 2.81 sec

v = (55 - 38.8) / 2.81 = 5.76 m/s   (about 12.9 mph)

A child boards a bus for summer camp. His mom is waiting next to the bus. The bus begins
moving 3 m/s east with respect to the ground. The child is walking 0.5 m/s west towards the back
of the bus with respect to the bus. The mother begins running 1 m/s east with respect to the
ground, chasing after the bus and thoroughly humiliating her child. What is the child's velocity

a) relative to the ground?

b) relative to the mother?

Answers

Answer:

a) relative to the ground

Explanation:

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