Given data
*The given mass of the car is m = 1475 kg
*The maximum tension is T = 2551 N
The formula for the maximum possible acceleration of the truck is given by Newton's second law as
[tex]\begin{gathered} T=ma_{\max } \\ a_{\max }=\frac{T}{m} \end{gathered}[/tex]Substitute the known values in the above expression as
[tex]\begin{gathered} a_{\max }=\frac{2551}{1475} \\ =1.72m/s^2 \end{gathered}[/tex]Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2
scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as , where is in nm. if a 295-nm-thick coating is placed on glass for what visible wavelengths will the reflected light have maximum constructive interference?
The wavelength of the reflected light will have a range from 360 nanometers to 700 nanometers.
Constructive Interference may be defined as the process which occurs when the maxima of any two waves add up and the amplitude of the resulting wave will be equal to the sum of the two individual waves. According to the question thickness of coating, d = 295 nm and wavelength varies as n = [(30nm) ^1/2]/λ^1/2.
Also, the wavelength will be expressed as
λ = 2nd/M where M = 1,2,3......
λ = 2d[(30nm)^1/2]/Mλ^1/2
λ^3/2 = (d60nm^1/2)/M
λ = ∛d² 3600 nm/M
Now, if M = 1 then,
λ = ∛295² 3600nm/1 = 679.18 nm
Now, if M = 2 then,
λ = ∛295² 3600nm/2 = 679.18 nm
Now, if M = 3 then,
λ = ∛295² 3600nm/3 = 326.51 nm
So, the range is approximately 360 nm to 700 nm.
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Complete Question:
Scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as n = 30.0 nm1/2 /l1/2, where l is in nm. If a 295-nm-thick coating is placed on glass 1n = 1.502 for what visible wavelengths will the reflected light have maximum constructive interference?
How do these forces affect the car's
movement?
Thrust, Lift, Drag, and Weight are four opposing forces that affect every vehicle, whether it's a car, truck, boat, airplane, helicopter, or rocket.
What is force?A force is an influence that can cause an object's motion to change. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force exist as a vector quantity because it has both magnitude and direction. A mass object's velocity changes when it is pushed or pulled. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction. The term "force" has a specific meaning. At this level, it is perfectly acceptable to refer to a force as a push or a pull.To learn more about force, refer to:
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If the force of gravity acting on an object is 40N and the object has a mass of 2.8k, what is the acceleration due to gravity?
Answer:
0.07
Explanation:
2.8/40 = 0.07
Force Problem: Four concurrent forces are applied to a 5 Kg mass: 50 N North, 25 N East, 35 N South, and 35 N West.
a. Find the resultant force on the mass.
b. Find the acceleration of the mass.
c. What equilibrium force will sustain equilibrium?
d. What will be the acceleration of the object if it’s mass doubles?
e. Find the equilibrium force if all the initial forces are doubled.
A) Net horizontal force:
Fx= -35 + 25 + -10N
Net vertical force
Fy= 50 - 35 = 15N
Net force
F^2 = fX^2 +Fy^2
F= 18N
B.) Acceleration of system
a=18/5=3.6m/s^2
C). Equilibriant force must be equal to the net force above
F1= 18N
D.) Acceleration becomes half
a1= a/2 =1.8m/s^2
E.) Equilibrant force also doubles
F" = 2F' = 36N
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A car is traveling on a highway. the distance (in miles) from its destination and the time (in hours) is given by the equation d = 420 minus 65 t. what is the slope of the line represented by the equation? what is the practical meaning of the slope? a. m = 420; the total distance is 420 miles. b. m = 65; the car is traveling 65 miles per hour. c. m = negative 65; the car is traveling 65 miles per hour. d. m = negative 420; the total distance is 355 miles.
HELP!
Noble gases are the ____________________.
A. most reactive of all elements
B. least consistent of all elements
C. most consistent of all elements
D. least reactive of all elements
Answer: Most consistent of all elements (if consistency here denotes stability)
if not, then the answer will be (D)
Explanation:
Nobel gasses have full outermost electron shells which means that they are very stable and do not need to lose, gain, or share electrons to gain stability. So they do not react with other elements to form ionic or covalent bonds
Q3. A 3500 kg van hits a 2500 kg car with a force of 1480 N [E].
a) What force does the van experience?
The force experience by a van of 3500 kg when it hits a car of 2500 kg with a force of 1480 N is 1057.14 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the force experienced by the van, we use the formula below
Formula:
f = mF/M..................... Equation 1Where:
M = Mass of the vanm = Mass of the carf = Force on the carF = Force on the vanFrom the question,
M = 2500 kgm = 3500 kgF = 1480 NSubstitute these values into equation 1
f = (2500×1480/3500)f = 1057.14 N.Hence, the force experience by the van is 1057.14 N.
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complete the table=x =0 2 3 4 6 8 y=30 27 24
Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc
hope i helped
Explanation:
dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. rob left some time later driving in the same direction at an average speed of 48 km/h. after driving for five hours rob caught up with dan. how long did dan drive before rob caught up?
Dan drove for 6 hours before catching up with Rob who left his home sometime later than Dan.
Dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. Let d1 be Dan's start in km.
Rob left some time later driving in the same direction at an average speed of 48 km/h. Let d2 be rob's start in km.
Let t1 be the time between dan and rob's leaving.
After Rob leaves, Dan travels around 40×5 =200km.
During the same time, rob travels a distance of
48×5=240km
d1= 240-200
= 40 km
t1 = 40/40 = 1
So Dan traveled 1 more hour, which means he traveled for 6 hours.
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_______ energy is defined as stored energy.
Answer:
Potential energy
Explanation: Potential energy is represented as a stored energy.
An 85.0 kg man stands on a spring scale in an elevator when it begins to accelerate upwards. If the scale at that moment indicates that his "weight" is 1020 N, what is the acceleration of the elevator?
2.20 m/s^2 is the acceleration of the elevator.
Option c is correct answered .
What does the scale read when the elevator accelerates upward?If you stand on a scale in an elevator accelerating upward, you feel heavier because the elevator's floor presses harder on your feet, and the scale will show a higher reading than when the elevator is at rest. On the other hand, when the elevator accelerates downward, you feel lighter.
How do you find the acceleration of an elevator with weight?support force F = mass x acceleration + weight
For a mass m= kg, the elevator must support its weight = mg = Newtons to hold it up at rest. If the acceleration is a= m/s² then a net force= Newtons is required to accelerate the mass.
Fnet = m a
Fn + (-Fg) = m a
a = 1020 - (85)(9.8) /85
a = 2.20 m/s^2
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A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides
The free body diagram of the crate can be shown as,
Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.
A llama runs until reaching its top speed. A graph of the llama's velocity over time is shown
below.
What is the llama's average acceleration from 15 to 20 seconds?
The average acceleration for that time interval will be zero because the velocity is constant.
What is acceleration?If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the earth, and a car stopped at a stop sign are a few instances of acceleration. Through these illustrations, we can see that acceleration happens whenever a moving object changes its direction or speed, or both.
What is velocity?Velocity and speed describe how quickly or slowly an object is moving. We frequently encounter circumstances when we must determine which of two or more moving objects is going faster. If the two are travelling on the same route in the same direction, it is simple to determine which is quicker. It is challenging to identify who is moving the fastest when their motion is in the other direction. The concept of velocity is useful in these circumstances. Learn about the definition of velocity in this article as well as the distinction between speed and velocity.
the velocity is constant at -20 m/s. Hence the average acceleration for that time interval will be zero because the velocity is constant.
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Answer:
0
Explanation:
i did it on khan academy
To find the density of an object you would use a graduated cylinder to find what characteristic of the obiect? A)mass b)length c)volume d)weight
Answer:
C Volume
Explanation:
You would use a graduated cylinder with liquid in it to see how much is displaced when the object is placed in it to determine the volume of the object
In an arena football game, the quarterback throws a pass so that it reaches the top of the stadium at the peak of its flight. If he threw the ball at an angle of 64 degrees and the stadium is 34 meters high, calculate the velocity with which he threw the ball and the distance the ball traveled.
Formulas for projectile motion:
Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g
Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g
where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.
Given:
Angle of projection, α = 64°
Maximum height of projectile, h = 34 m.
To find: Initial velocity (u), and horizontal distance travelled (R).
Rearrange 'h' equation for 'u',
u sin(α) = [tex]\sqrt{2gh}[/tex]
⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]
Substitute given values.
⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)
⇒ u = 25.81 / 0.899 m/s
∴ u = 28.71 m/s
This is the velocity with which the ball was thrown.
The distance travelled by the ball can be calculated by using the equation,
R = [tex]u^{2}[/tex] sin(2α) / g
Substitute the given values.
⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8
⇒ R = 649.53 / 9.8
∴ R = 66.27 m.
This is the distance travelled by the ball.
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Forces with magnitudes of v = 135 newtons and u = 280 newtons act on a hook (see figure). The angle between the two forces is 45°. Find the direction and magnitude of the resultant of these forces. (Hint: Write the vector representing each force in component form, then add the vectors. Round your answers to two decimal places.)
To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:
[tex]\begin{gathered} \vec{v}= \\ \text{ where } \\ v\text{ is the magnitude } \\ \theta\text{ is the angle of the vector with respect to the positive x-axis.} \end{gathered}[/tex]For force u we notice that its magnitude is 280 N and its angle is zero, then we have:
[tex]\begin{gathered} \vec{u}=<280\cos0,280\sin0> \\ \vec{u}=<280,0> \end{gathered}[/tex]For force v we know that its magnitude is 135 N and its angle is 45°, then we have:
[tex]\begin{gathered} \vec{v}=<135\cos45,135\sin45> \\ \vec{v}=<95.46,95.46> \end{gathered}[/tex]Now that we have both vectors in component form we add them to get the resultant in component form:
[tex]\begin{gathered} \vec{F}=\vec{u}+\vec{v} \\ \vec{F}=<280,0>+<95.46,95.46> \\ \vec{F}=<375.46,95.46> \end{gathered}[/tex]Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:
[tex]\begin{gathered} F=\sqrt{F_x+F_y} \\ \theta=\tan^{-1}(\frac{F_y}{F_x}) \end{gathered}[/tex]Plugging the values we found for the components we have:
[tex]\begin{gathered} F=\sqrt{375.46^2+95.46^2} \\ F=387.41 \end{gathered}[/tex]and
[tex]\begin{gathered} \theta=\tan^{-1}(\frac{95.46}{375.46}) \\ \theta=14.27 \end{gathered}[/tex]Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°
one steel ball and one aluminum ball are the same size but the steel ball weighs twice as much as the other. the balls are dropped from the roof of a single-story building at the same instant of time. the time it takes the balls to reach the ground below will be:
It is same for both the balls. Due to the fact that balls fall freely regardless of their weight, both metallic balls take the same amount of time to reach the ground.
When two identically sized objects are dropped from a certain height, they will fall with gravitational acceleration (g). The weight of the objects will not affect how long it takes them to reach the ground. The density of the medium in which an object is dropped affects how long it takes for each object to travel there. Due to the influence of gravity and the same medium, we can therefore infer that both metal balls will take the same amount of time to reach the ground (air). Experiments have been conducted in vacuum rooms and show that when the balls are released from the top of the store, the acceleration of attraction to the floor is gravity and it has a value of 9.8 meters/square second regardless of its weight.
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cepheid stars are useful to astronomers as indicators of group of answer choices white-dwarf star behavior. the mechanics of eclipsing variable stars. distance, particularly to stars in our galaxy and to nearby galaxies. stars with very high speed motion.
Option b cepheid stars are useful to astronomers as indicators of distance, particularly to stars in our Galaxy and to nearby galaxies.
An astronomer is a scientist who focuses on the stars, planets, galaxies and other extraterrestrial natural phenomena. The study of astronomy includes everything in the cosmos that is outside of our solar system. This includes celestial bodies that we can see with our unaided eyes, such as the Sun, Moon, planets, and stars. Additionally, it contains celestial bodies like distant galaxies and minute particles that we can only see with telescopes or other tools. On a more urgent level, astronomy aids in our research into how to extend the survival of our species. Studying the Sun's impact on Earth's climate and how it will effect weather, water levels, etc., for instance, is crucial. The broad discipline of natural science known as astronomy is concerned with celestial objects, such as those in the solar system, galaxies, and extragalactic objects. The majority of the fieldwork participants are students who specialize in this broad discipline.
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If centripetal force is towards the center and gravitational force is also towards the center how can we be lighter at the equator?
ANSWER and EXPLANATION
We want to determine why a person weighs lighter at the equator.
At the equator, an object will weigh slightly less as a result of the slightly greater centripetal force and the slight increase in distance from the center of gravity of the earth due to the equatorial bulge. This would imply a decrease in the gravitational force that an object experiences.
In other words, the earth is not a perfect sphere, and so, at the equator, an object will be slightly farther from the center.
That is the answer.
The speed of sound depends on all of the following properties except:
a
Type of element
b
Composition of the medium or type of matter
c
Density
d
Temperature
Answer:
d: temperature
Explanation:
temperature doesn't have anything to do with sound
The velocity-time equation for a golf cart isVA= (1 m/s) + (-0.5 m/s?)t (a) What is the cart's initial velocity? (b) What is the cart's acceleration?
If the velocity-time equation for a golf cart is v = (1 m/s) + (-0.5 m/s)t , then the initial velocity of the cart would be 1 m / s and the acceleration of the cart would be - 0.5 m / s² .
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem the velocity-time equation for a golf cart is
v = (1 m/s) + (-0.5 m/s)t ,
The initial velocity of the cart at t = 0 would be 1 m / s.
By differentiating the given equation of the velocity,
The acceleration of the cart would be -0.5 m / s.
Thus, the initial velocity would be 1 m / s and the acceleration would be -0.5 m / s.
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Hey surveyor is drawing property lines . He draws one line that is 25.0 m long and is 20° south of west.  how long is the western component of the vector he has drawn?
Answer:
23.5 m
Explanation:
25 m * cos 20 =23.5 m
If a car travels 1,000 m in 60 seconds how fast is it going?
Answer:
see below
Explanation:
1000 m / 60 s = 16 2/3 m/s
an elevator of mass m is initially at rest on the first floor of a building. it moves upward, and passes the second and third floors with a constant velocity, and finally stops at the fourth floor. the distance between adjacent floors is h. what is the net work done on the elevator during the entire trip, from the first floor to the fourth floor?
From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.
Given,
On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.
the separation between the floors is h
The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)
= -3mgh
Work Done = -3mgh
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6. A ball rolls off a table and falls 0.75 m to the floor, landing with a speed of 4.0 m/s. 1. What is the acceleration of the ball just before it strikes the ground? 2. What was the initial speed of the ball? 3. What initial speed must the ball have if it is to land with a speed of 5.0 m/s?
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Displacement
1 ) In vertical motion,
v = 4 m / s
s = 0.75 m
u = 0
4² = 0 + ( 2 * a * 0.75 )
a = 16 / 1.5
a = 10.67 m / s²
2 ) The initial speed of the ball,
Resolving the velocity into its horizontal and vertical components,
[tex]V_{y}[/tex]² = [tex]U_{y}[/tex]² + 2 a s
[tex]V_{y}[/tex]² = 0 + ( 2 * 9.8 * 0.75 )
[tex]V_{y}[/tex] = 3.83 m / s²
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
4² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 16 - 14.67
[tex]V_{x}[/tex] = 1.15 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 1.15 m / s
3 ) If the ball lands with a speed of 5.0 m/s,
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
5² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 25 - 14.67
[tex]V_{x}[/tex] = 3.2 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 3.2 m / s
Therefore,
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
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a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad. what is its final angular velocity? how much time elapses while it turns through the 300 radians?
If a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad , then the final angular velocity would be 48.96 rad /s and 12.24 seconds elapse while it turns through the 300 radians.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
By using the second equation of motion given by Newton,
S = ut + 1/2at²
300 = 0 + 0.5 × 4 × t²
t² =300 /2
t = 12.24 seconds
The final angular velocity = 0+ 12.24 × 4
= 48.96 rad /s
Thus, 12.24 seconds elapse while it turns through the 300 radians.
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Mosses are located in which zone of deciduous forests? a. tree stratum b. ground c. shrub d. herb please select the best answer from the choices provided a b c d
Answer
Ground Zone
Explanation
The final zone is the Ground zone. It contains lichen, club mosses, and true mosses. The deciduous forest has four distinct seasons, spring, summer, autumn, and winter. In the autumn the leaves change color.
Answer: B Ground
Explanation:
a 6.0-kg fish swimming 1.1 m/s swallows an absentminded 1.0-kg fish swimming toward it at a speed that brings both fish to a halt immediately after lunch. find the speed of the approaching smaller fish before lunch.
The speed of the approaching smaller fish before lunch is 6m/s.
What is the speed?The entire distance that an object travels in a predetermined amount of time is the definition of speed.
Given that the speed v₁ of big fish is 1 m/s and mass m₁ is 6kg. The mass m₂ of small fish is 1 kg.
Both fish have linear momentum of,
p₁ = m₁v₁ + m₂v₂
Where,
p₁ is the initial linear momentum
v₂ is the speed of the small fish.
Since both fish are traveling in the same direction and v is their ultimate meeting velocity, the final linear momentum will be given as,
p₂ = (m₁ + m₂) v
Linear momentum is held constant hence,
p₁ = p₂
m₁v₁ + m₂v₂ = (m₁ + m₂) v
The fish's final speed will be zero because they stopped moving., so
m₁v₁ + m₂v₂ = 0
v₂ = - m₁v₁/m₂
v₂ = -6×1/1
v₂ = -6
The negative symbol indicates that the tiny fish are swimming against the current.
The speed of the approaching smaller fish before lunch is 6m/s.
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What two pieces of information would you need in order to measure the masses of stars in an eclipsing binary system?.
The two pieces of information would you need in order to measure the masses of stars in an eclipsing binary system include the following below:
The time between eclipses.The average distance between the stars.What is Eclipsing binary system?This refers to the different process which occurs in the solar system in which two close stars move in an orbit in space in relation to Earth such that the light of one can at times be hidden behind the other.
The masses of stars can be measured in this system through measuring the time between the eclipses so so to ascertain the accurate differences observed.
The average distance between stars provide more information about mass as a lighter one will most likely be faster which is therefore the reason why it was chosen as the correct choice.
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Answer:
Time between eclipses and the average distance between the stars
Explanation:
What are three sources of errors in a center of gravity lab experiment
The centre of gravity, in physics, is an imaginary point in a body of matter where for convenience in certain calculations,
What are three sources of errors in a center of gravity?Sources of errors for the center of gravity of an irregularly shaped object: -environmental error: when the wind blows it may remove the irregularly shaped object from equilibrium. add: density variations, shape variations say, thickness], inability to measure precisely, inability to compute precisely. For example, as a result of a number of the center of gravity measurements, we may have the best estimate of the true value for the acceleration due to gravity, the center of gravity is the point between which the force of gravity move on a thing or system. In most mechanics problems the gravitational pasture is assumed to be constant. The center of gravity is then in entirely the same position as the center of mass.
So we can conclude that It is important to know the center of gravity because it predicts the behavior of a moving body when acted on by gravity.
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