A light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center. What forces are exerted by the sawhorses on the board

Answers

Answer 1

Answer:

8N and 32N

Explanation:

Given that a  light board, 10 m long, is supported by two sawhorses, one at one edge of the board and a second at the midpoint. A small 40-N weight is placed between the two sawhorses, 3.0 m from the edge and 2.0 m from the center.

To calculate the forces that are exerted by the sawhorses on the board, we must consider the equilibrium of forces acting on the board.

Let the two upward forces produce by the saw horses be P1 and P2

Assuming that the weight is negligible

Sum of the upward forces = sum of the downward forces.

P1 + P2 = 40 ....... (1)

Also, the sum of the clockwise moment = sum of the anticlockwise moments.

Let's assume that the board is uniform. The weight will act at the centre.

Taking moment at the centre:

P1 × 5 + 40 × 2 = 0

P1 = 40 / 5

P1 = 8N

Substitute P1 into equation 1

8 + P2 = 40

P2 = 40 - 8

P2 = 32N

Answer 2

Answer:

56

Explanation:


Related Questions

What is the acceleration of gravity on Earth?

Answers

Answer:

9.807 m/s²

Explanation:

PLS make me brainliest

Answer:

[tex]\huge\boxed{\sf 9.8 \ m/s^2}[/tex]

Explanation:

The acceleration due to gravity is g the value of which is 9.8 m/s².

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

Select the best answer for the question.
7. What does the term "single-pole" mean in a schematic?
A. The switch has only two positions: on or off.
B. The switch is always on.
C. The switch doesn't use a contact.
D. The switch has only one contact inside the switch.
Mark for review (Will be highlighted on the review page)
<< Previous Question
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Answers

Answer:

the correct answer is A

Explanation:

In an electrical circuit the switch can be of two types: unipolar and bipolar.

The bipolar switch refers to a three-contact switch that allows the polarity in the circuit to be reversed.

The unipolar switch has only two contacts so the polarity of the circuit is in one direction and the switch serves to interrupt the passage of electrons in the circuit.

Consequently the correct answer is A

All four of these pulleys are lifting the same amount of weight. Which one requires the least amount of force to lift it?

Answers

Answer: From the attached image, the pulley that requires least amount of force to lift the weight is pulley D.

Explanation:

A pulley is a circular disc made of steel or wood which can rotate freely about its axis, passing through its centre and perpendicular to its plane. The axel of the pulley is supported at its end by a framework called the block. There are three types of pulley system they include:

--> Fixed pulley: The load is connected to one end of a string passing over the pulley and the effort is applied at the other end.

-->Moveable pulley: The load is attached to a movable pulley with one end fixed to the string and hooked.

--> Compound pulley ( the block and tackle system): These are multiple pulley system in which extra fixed pulleys are added to the block fastened to the over head beam, and corresponding extra pulleys are added to the moveable block. The mechanical advantage is INCREASED due to increased number of pulleys. Each pulley is able to turn independently.

From the attached diagram, the pulley with the highest mechanical advantage is pulley D. This is so because the number of ropes supporting the moveable load is 4 (excluding the rope attached to the effort applied) is greater than the rest of other pulley in the options. This in turn DECREASES the amount of force necessary to lift the load.

An object A with a kinetic energy of 800 joules moving horizontally is subjected to a force of 100 Newtons, which is the opposite of motion as it moves from point X to point Y. XY distance is 2 m. What is the energy of A at point Y?

Answers

Answer:

d = 8 [m]

Explanation:

To solve this problem we must use the principle of conservation of energy, where the mechanical energy in a state plus the work done on the body, must be equal to the mechanical energy in the state Y. This can be easily represented in the following equation.

[tex]E_{x}+W_{x-y}=E_{y}[/tex]

where:

Ex = Mechanical energy in X [J]

Wx-y = Work among states x and y [J]

Ey = Mechanical energy in Y [J].

The key to being able to understand this problem is that in state X, we only have kinetic energy, while the energy in state Y is equal to zero (there is no movement). The work is equal to the product of force by distance, as work acts in the opposite direction to movement, this has a negative sign.

[tex]800 - F*d = 0\\100*d = 800\\d = 800/100\\d = 8 [m][/tex]

A cyclist is coasting at 13 m/s when she starts down a 460 m long slope that is 30 m high. The cyclist and her bicycle have a combined mass of 70 kg. A steady 15 N drag force due to air resistance acts on her as she coasts all the way to the bottom. What is her speed at the bottom of the slope?

Answers

Answer:

The value is  [tex]v = 23.6 \ m/s[/tex]

Explanation:

From the question we are told that

   The velocity is [tex]u = 13 \ m/s[/tex]

    The  length of the slope is [tex]l = 460 \ m[/tex]

    The height of the slope is [tex]h = 30 \ m[/tex]

     The mass of the cyclist and her bicycle is [tex]m = 70 \ kg[/tex]

   The drag force is  [tex]F = 15 \ N[/tex]

Generally from the law of energy conservation we have that

      [tex]PE + KE_t = W * KE_b[/tex]

Here [tex]PE[/tex] is the potential energy at the top of the slope which is mathematically represented as

       [tex]PE = m* g * h[/tex]

=>     [tex]PE = 70 * 9.8 * 30[/tex]  

=>     [tex]PE = 20580 \ J[/tex]

and   [tex]KE_t[/tex] is the kinetic energy at the top of the slope which is mathematically represented as

        [tex]KE_t = \frac{1}{2} * m * u^2[/tex]

=>     [tex]KE_t = \frac{1}{2} * 70 * 13^2[/tex]

=>     [tex]KE_t = 5915 \ J[/tex]

And  W is the work done by the bicycle which is mathematically represented as

       [tex]W = F * l[/tex]

=>     [tex]W = 15 * 460[/tex]

=>     [tex]W = 6900 \ J[/tex]

and [tex]KE_b[/tex] is the kinetic energy at the bottom of the slope which is mathematically represented as

       [tex]KE_b = \frac{1}{2} * m * v^2[/tex]

=>    [tex]KE_b = \frac{1}{2} * 70 * v^2[/tex]

=>    [tex]KE_b = 35 v^2[/tex]

So

       [tex]20580 + 5915 = 6900 + 35 v^2[/tex]

=>    [tex]v = 23.6 \ m/s[/tex]

 

Solid state physics uses the. Theory to understand how the large-scale properties of solids result from their atomic scale structure

Answers

Answer:

Quantum theory

Explanation:

The scientific foundation in quantum mechanics is quantum theory, which describes the existence and behavior of mass and antimatter at the subatomic particles levels. Quantum theory and quantum theory are often related to as the existence and behavior of matter in the universe at that stage.

If you want to The Midoriya Talent show then Anyone Is welcome Pls show your talents then the ID is 999-8470-3327 and the Password is 355130

Answers

It’s 4:36 I in the morning go to bed pls

Answer:

it is of brainlee

I'd and also a password

I want to save it because my phone battery is low so don't delete my answer

jujuju on da beati dont knowww

Answers

Answer:

The answer is Juju knows. Pplease mark as solved and thanks

Explanation:

Answer

Explanation:

Answer

Explanation:Answer

Explanation:Answer

Explanation:Answer

Explanation:Answer

Explanation:

Research Galileo’s work on falling bodies. What did he want to demonstrate? What opinions or theories was he trying to refute? What arguments did he use to persuade others that he was right? Did he depend on experiments, logic, findings of other scientists, or other approaches?

Answers

Answer:

Explanation:

Galileo's famous argument against the Aristotle's theory of falling bodies goes like this. "Let's say heavy objects do fall faster than light ones. Then it seems the heavier weight will fall with the lighter weight acting, as it were, a bit like a parachute. In that case, the two balls will together fall more slowly than the heavy weight would on its own. On the other hand, once the two weights are tied together and held out over the parapet, they have effectively combined their weights, becoming one greater weight... they must therefore fall even faster than the heavy weight would on its own." Contradiction. Hence weight has no effect on falling rates.

Some philosophers are very fond of this argument. Gendler uses it as a prototypical example of how "reasoning about particular entities within the context of an imaginary scenario can lead to rationally justified conclusions". Snooks goes further saying "it is striking that one leaves the falling balls example with something approaching certainty for its outcome". And Brown goes all the way and claims that Aristotle's theory is "self-contradictory", and we gain a priori knowledge here. The argument does give off that flavor of "synthetic a priori" reasoning, as in geometry but without images. But is it a proof or a fallacy? Even Gendler admits that some "obvious" premises are missing, and Atkinson even calls it a "non-sequitur" for similar reasons. But Galileo's logic is not questioned it seems. Shouldn't it be?

Galileo proved force causes acceleration. Galileo concluded from the law of parabolic fall that bodies fall on Earth at a constant acceleration and that gravity, which pulls all bodies down, is constant.

What is Galileo's law of falling bodies?

According to Galileo's law of free fall, in the absence of any resistance from the air, all bodies fall with the same acceleration, regardless of their mass. This law was developed by Galileo. The application of Newtonian mechanics demonstrates that this law is only a close approximation.

A water clock was utilized in the process of timekeeping. Galileo demonstrated that motion on an inclined plane had a constant acceleration, and that this acceleration was only dependent on the angle of the plane and not the mass of the rolling body. This demonstrated that the acceleration of free falling bodies is the same.

Galileo proposed that in the absence of air, all bodies, regardless of how much matter they contain, would fall at the same rate in relation to the earth. It appears that Aristotle considered all media to be viscous, and he argued that heavier bodies fall at a faster rate.

Learn more about Galileo’s experiment, here:

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If an object has more mass then it will have...

A: less intertia
B: more inertia
C: more volume
D: less volume

Answers

It’s c hope that helps

g calculate the effectiveness radiation dosage in sieverts for a 79 kg person who is exposed 6.8x10^9

Answers

Answer:

The answer is "[tex]\bold{dosage = 0.031 rem}[/tex]"

Explanation:

please find the complete question in the attached file.

Given value:

[tex]m = 79\ kg \\\\n = 3.4 \times 10^9 \\\\E = 5.5 \times 10^{-13} \\\\ RBE = 15[/tex]

[tex]\to E = n E\\[/tex]

        [tex]= 3.4 \times 10^9 \times 5.5 \times 10^{-13} \\\\ = 1.87 \times 10^{-3}[/tex]

[tex]\to E(absorbed) = 1.87 \times 10^{-3} \times 0.87 = 1.63 \times 10^{-3}[/tex]

calculating the radiation absorbed per kg:

[tex]= \frac{1.63 \times 10^{-3}}{79} \\\\ = 2.06 \times 10^{-5} \\\\ = 0.00206 \ rad[/tex]

[tex]\to Dosage = 0.00206 \times 15 \\[/tex]

                 [tex]= 0.031 \ \ rem[/tex]

Hydropower is alternative source of energy​

Answers

Answer:

Hydropower is an alternate source!Its expensive and takes up large spaces and many natural resources Takes homes of natural species.

Answer:

because Hydropower is fueled by water, so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels, such as coal or natural gas. Hydroelectric power is a domestic source of energy, allowing each state to produce their own energy without being reliant on international fuel sources.

Explanation:

please mark as brainlest

what do illusions indicate about the relationship between our eyes and brains​

Answers

Answer:

Illusions indicate that the brain does not totally rely on the eye to make visual perceptions of reality. It sometimes generates perceptions of reality based on assumptions of how it should be.

Explanation:

Our brains and eyes together with the optical nerves linking them together, form part of the complex visual system of the body.

An illusion occurs when there is a mismatch between the perceived reality by the brain and the actual reality of what exists. Whenever this happens, it shows that some of the time, the brain does not always rely on a complete optical signal/information from the eye in order to make a perception. The brain at times tends to "complete the image" using the little information available alongside personal experiences and this often leads to misperception.

A cube slides down the surface of a ramp at a constant velocity. What is the magnitude of the
frictional force that acts on the cube due to the surface?

a. The weight of the cube

c. The component of weight of the cube perpendicular to the plane

b. The component of the normal reaction at the surface parallel to the plane

d. The component of weight of the cube parallel to the plane

Answers

A . The weight of the cube

Convert 1 x 10-3 nm to m. given: 1 m = 1,000,000,000 nm

Answers

Answer:

l m = 1000000000 nm

? = 0.001

= 0

A 23 g bullet is accelerated in a rifle barrel 62 cm long to a speed of 593 m/s. Use the work-energy theorem to find the average force exerted on the bullet while it is being accelerated. Answer in units of N.

Answers

Answer:

The average force exerted on the bullet while it is being accelerated is 6,522.52 N.

Explanation:

Given;

mass of the bullet, m = 23 g = 0.023 kg

length of the barrel, L = 62 cm = 0.62 m

speed of the bullet, v = 593 m/s

Applying work-energy theorem;

the work done in accelerating the bullet in the riffle = kinetic energy acquired by the bullet.

W = K.E

F x d = ¹/₂mv²

where;

d is the is the distance traveled by the bullet in the riffle = L

F(0.62) = ¹/₂ x 0.023 x (593²)

F(0.62) = 4043.964

F = (4043.964) / (0.62)

F = 6,522.52 N

Therefore, the average force exerted on the bullet while it is being accelerated is 6,522.52 N.

Which equation shows the correct relationship between mechanical energy, kinetic energy, and potential energy?
ME = KE + PE
O ME + KE = PE
O ME = KE - PE
O ME + PE = KE

Answers

Answer:

ME= KE+PE

Explanation:

just took quiz

The correct relationship between mechanical energy, kinetic energy, and potential energy is ME= KE + PE, the correct option is A.

What is mechanical energy?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

The expression for total mechanical energy is as follows

[tex]ME = KE + PE[/tex]

As total mechanical energy is the sum of all the kinetic as well potential energy stored in the system.

Learn more about mechanical energy

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Acceleration and force are proportional

Answers

Answer:

whats the question tho

An incompressible fluid flows steadily through a pipe that has a change in diameter. The fluid speed at a location where the pipe diameter is 8.8 cm is 2.4 m/s. Calculate the flow speed at a location where the diameter has narrowed to 5.80 cm

Answers

Answer:

The value is [tex]v_2 = 5.53 \ m /s[/tex]

Explanation:

From the question we are told

  The pipe diameter at location 1 is  [tex]d = 8.8 \ cm = \frac{8.8 }{10} = 0.88 \ m[/tex]

   The velocity at location 1 is  [tex]v_1 = 2.4 \ m /s[/tex]

   The diameter at location 2 is  [tex]d_2 = 5.80 \ cm = 0.58 \ m[/tex]

Generally the area at location 1 is  

       [tex]A_1 = \pi * \frac{d^2}{ 2}[/tex]

=>     [tex]A_1 = \pi * \frac{0.88^2}{ 2}[/tex]

=>     [tex]A_1 = 3.142 * \frac{0.88^2}{ 2}[/tex]

=>     [tex]A_1 = 1.2166 \ m^2[/tex]

Generally the area at location 1 is  

       [tex]A_2 = \pi * \frac{d_1^2}{ 2}[/tex]

=>     [tex]A_2 = \pi * \frac{0.58^2}{ 2}[/tex]

=>     [tex]A_2 = 0.528 \ m^2[/tex]

Generally from continuity equation we have that

     [tex]A_1 * v_1 = A_2 * v_2[/tex]

=>   [tex]1.2166 * 2.4 = 0.528 * v_2[/tex]

=>   [tex]1.2166 * 2.4 = 0.528 * v_2[/tex]

=>    [tex]v_2 = 5.53 \ m /s[/tex]

PLEASE HELP ITS DUE TODAY

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.
-Find the hang time for the projectile.
-Find the initial speed of a projectile.
-What are the x and y components of the projectile’s velocity the moment before it strikes the ground?
-At what speed will the projectile strike the ground?

Answers

Answer:

30.9 m

Explanation:

x = 129.9 m y = 30.9 m First of all, let's calculate the horizontal and vertical velocities involved h = 50.0cos(30) = 43.30127 m/s v = 50.0sin(30) = 25 m/s The horizontal distance is simply the horizontal velocity multiplied by the time, so 43.30127 m/s * 3 s = 129.9 m So the horizontal distance traveled is 129.9 m, so x = 129.9 m The vertical distance needs to take into account gravity which provides an acceleration of -9.8 m/s^2, so we get d = 25 m/s * 3s - 0.5*9.8 m/s^2 * (3 s)^2 d = 75 m - 4.9 m/s^2 * 9 s^2 d = 75 m - 44.1 m d = 30.9 m So the vertical distance traveled is 30.9 m, so y = 30.9 m


What causes the Earth's spherical shape

Answers

Answer:

spherical shape

Explanation:

The Earth is massive enough that the pull of gravity maintains its roughly spherical shape. Most of its deviation from spherical stems from the centrifugal force caused by rotation around its north-south axis. This force deforms the sphere into an oblate ellipsoid.

Why is the sun so far away

Answers

Answer:

If it was close we would die.

Explanation:

Probably has something to do with the earths original formation.

Hahahahahahahahahahahah

You pull a 70-kg crate at an angle of 30° above the horizontal. If you pull with a force of 600N and the coefficient of kinetic friction is .4, how far will it move in 3 seconds?

Answers

Answer:

Explanation:

Force of friction acting on the body = μ mg cosθ

= .4  x 70 x 9.8 x cos30

= 237.63 N

component of weight = mgsinθ

= 70 x 9.8 x sin30

= 343 N  

Net upward force = 600 - mgsinθ - μ mg cosθ

= 600 - 343 - 237.63

= 105.37 N

acceleration in upward direction = 105.37 / 70

= 1.5 m /s²

s = ut + 1/2 a t²

= 0 + .5 x 1.5 x 3²

= 6.75 m .

The crate will move at a distance of 1.215 m in 3 seconds.

How do you calculate the distance of motion?

Given that the mass m of the crate is 70 kg and the angle above the horizontal is 30°. External force F on the crate is 600 N and the coefficient of friction is 0.4.

The friction force applied to the crate is calculated as given below.

Friction force = [tex]\mu mgcos \theta[/tex]

Where [tex]\mu[/tex] is the friction constant, g is the gravitational acceleration and [tex]\theta[/tex] is the angle above the horizontal.

Friction Force = [tex]0.4\times 70\times 9.8\times cos30^\circ[/tex]

Friction force = 237.63 N.

There is a force applied on the crate due to its weight is calculated as given below.

Force (weight component) = [tex]mgsin\theta[/tex]

Force (weight component) = [tex]70\times 9.8\times sin 30^\circ[/tex]

Force (weight component) = 343 N.

The net force applied to the crate is given below.

Net force = External force - friction force - force (weight component)

Net force F' = [tex]600 - 237.63 - 343[/tex]

Net force F' = 19.37 N.

The acceleration of the crate can be calculated as given below.

[tex]a = \dfrac {F'}{m}[/tex]

[tex]a =\dfrac {19.37}{70}[/tex]

[tex]a = 0.27 \;\rm m/s^2[/tex]

Hence the distance traveled by the crate in 3 seconds is calculated by the formula given below.

[tex]s = ut + \dfrac {1}{2} at^2[/tex]

Where, s is the distance, u is the initial velocity, a is the acceleration and t is the time of motion of the crate.

[tex]s = 0\times 3 + \dfrac {1}{2} \times 0.27 \times 3^2[/tex]

[tex]s = 1.215[/tex]

Hence we can conclude that the crate will move a distance of 1.215 m in 3 seconds.

To know more about the force, follow the link given below.

https://brainly.com/question/26115859.

A 15 kg cart is pushed on a frictionless surface from rest horizontally by a 30 N force. What is the cart's acceleration?
b. How far wil it travel in 10 seconds?
c. What is its velocity at the end of 10 seconds?

Answers

Answer:

a. The cart's acceleration is 2 m/s^2

b. The cart will travel 100 m

c. The speed is 20 m/s

Explanation:

a. The acceleration of the cart can be calculated using Newton's second law:

F = m.a

Solving for a:

[tex]\displaystyle a=\frac{F}{m}[/tex]

The cart has a mass of m=15 Kg and is applied a net force of F=30 N, thus:

[tex]\displaystyle a=\frac{30}{15}[/tex]

[tex]a=2\ m/s^2[/tex]

b.

Now we use kinematics to find the distance and speed:

[tex]\displaystyle x = v_o.t+\frac{at^2}{2}[/tex]

The cart starts from rest (vo=0). The distance traveled in t=10 seconds is:

[tex]\displaystyle x = 0*10+\frac{2*10^2}{2}[/tex]

[tex]x = 100\ m[/tex]

The cart will travel 100 m

c.

The final speed is calculated by:

[tex]v_f=0+2*10=20\ m/s[/tex]

The speed is 20 m/s

(question 1) A person with a mass of 50 kilograms pushes a 2000-kilogram car to the right with a force of 500 Newtons. What is the force that the car applies to the person?

(question 2) An ice skater with a mass of 50 kilograms pushes another skater (with a mass of 40 kilograms) with a force of 25 newtons. How much acceleration does the 50-kg skater have?

(question 3) Two people are moving a heavy desk. One person pulls to the right with a force of 25 newtons, while the other pushes to the right with a force of 50 newtons. There is also 29 newtons of friction pointing to the left. what is the net force on the desk?

(question 4) Two people are trying to pull 5-kilogram block in opposite directions. The first person pulls to the right with a force of 25 newtons, and the second person pulls to the left with a force of 15 newtons. What is the acceleration of the block?

IK its a lot but I need help please

Answers

Answer:

q1: 0.5m/s2

Explanation:

An electric motor takes 30 s to lift a box of mass 45 000g to a height of 1.7 m. Calculate the power of the electric motor.

Answers

Power P is the amount of energy E transferred or converted per unit time t, and is expression is:

P = E/t

The necessary energy to lift the box its the work of against the Gravity Force, and is given by:

E = mgh

Then the power is:

P = E/t

P = mgh/t

P = (45 kg)(9.8 m/s²)(1.7 m )/ 30

P = 24.99 W

P ≈ 25 W

True or False: The motion of the plates over the surface of the Earth occurs at a noticeable and fairly rapid rate.

Answers

I think its Falseeeee

Plants in the rainforest

Answers

that was a little random

A student walks 4 blocks east, 7 blocks west, 1 block east and then 2 blocks west in an hour what is their velocity

Answers

Answer:

4 blocks west is final displacement. So 4 blocks per hour

A ball is thrown in the air at an angle of 60.0° to the ground, with an initial speed of 30m/s. How far from its original position does it land?

Answers

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:bkdbjkfej jf jfekjwniorigoexhndvgkj...............aplokdiuhyfgbv ..............................................

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