Answer: so lets say x =the exact amount of rows
so each row has 5 tree's
then a is the answer
its an equation of x·5=a
so that would be a unknown number of trees so you assume that there is more than 1 row because there is several rows so its a incomplete question
Step-by-step explanation:
There is a 50% chance of rain here and a 10% chance of rain on Mars. Therefore, there is a 45% chance that it will rain in neither place.
The statement that " There is a 45% chance that it will rain in neither place" is true.
In the question ;
it is given that
Probability of raining here = 50% = 0.5
Probability of raining on mars = 10% = 0.1
So, the probability of not raining here = 1-0.5 = 0.5
and probability of not raining on mars = 1-0.1 = 0.9
Hence the probability of rain in neither place = (probability of not raining here)×(probability of not raining on mars) .
Substituting the values , we get
probability of rain in neither place = 0.5×0.9
= 0.45
= 45%
Therefore , the statement " There is 45% chance that it will rain in neither place" is true.
The given question is incomplete , the complete question is
There is a 50% chance of rain here and a 10% chance of rain on Mars. Therefore, there is a 45% chance that it will rain in neither place.
Is the statement True or False ?
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I inserted a picture of the question Check all that apply
Recall that the line equation is of the form
[tex]y=mx+c\ldots\ldots\text{.}(1)[/tex]The points lie in the line are (2,5) and (-2,-5).
Setting x=2 and y=5 in the equa
What does slope mean?
Slope is a measure of its steepness
Mathematically,
Slope = Rise / Run
Rise = y2 - y1
Run = x2 - x1
Slope = y2 - y1 / x2 - x1
Answer:
Suppose a linear equation describes something (say, population growth). The slope is the rate (say, of growth) and the y-intercept gives the starting value.
Step-by-step explanation:
[tex]f(x) = \sqrt{ {x }^{2} - 121} [/tex]what's the inverse of this equation
EXPLANATION:
The first thing to do in the equation is to interchange the variables in order to do the inverse function and thus solve the equation correctly.
So the equation is as follows:
[tex]\begin{gathered} x=\sqrt[]{x^2-121} \\ Now\text{ we exchange }the\text{ variables x and y;} \\ x=\sqrt[]{y^2-121} \\ y=\sqrt[]{x^2+121};\text{ y}=-\sqrt[]{x^2+121} \\ \sqrt[]{x^2+121\text{ ; }-\sqrt[]{x^2+121}} \\ \text{the answer is : }\sqrt[]{x^2+121\text{ },\text{ }}\text{ }-\sqrt[]{x^2+121^{}} \end{gathered}[/tex]question 5 only. determine the missing side length QP. the triangles are not drawn to scale.
This is a simple question.
First, we can see both triangles are proportional, it means it has the same relation between its sides even if one is in a large scale and the other on a a small scale.
Now we can identify which side corresponds to which side. Once side AC is the longest one for triangle ABC it means its equivalent for triangle PQR is the side RP, so the equivalent for side AB is side QP. Once we know that we can write the following relation and calculate:
prism x imprison wire similar. the volume of prison why is 92 cm3 find the volume of prism x.
If they are similar, then their side measures are proportional
Prism X, volume = 92 cm^3
Jake and Joshua have new jobs selling gift cards at a local convenience store at the cash register, but their pay is different. Jake earns a foundational wage of $6 per hour, as well as $8 for each gift card sold. Joshua gets $4 for each gift card sold and earns a foundational wage of $6 per hour. If they each sell a certain number of gift cards in one hour, they will end up earning the same amount of pay. How many gift cards would that make up to?Write a system of equations, graph them, and type the solution.
Let x be the number of cards Jake and Joshua sell within one hour. Therefore, their earnings are given by the following expressions,
[tex]\begin{gathered} Ja=6+8x \\ Jo=6+4x \end{gathered}[/tex]Then, set Ja=Jo (both earn the same amount),
[tex]\begin{gathered} Ja=Jo \\ \Rightarrow6+8x=6+4x \end{gathered}[/tex]Solving for x,
[tex]\begin{gathered} \Rightarrow8x=4x \\ \Rightarrow4x=0 \\ \Rightarrow x=0 \end{gathered}[/tex]Then, they will earn the same within one hour only if both sell zero cards within the hour.
Graphing the system of equations,
As one can see, the intersection point is (0,6), which stands for 0 cards and $6
If the expression 1/ square root of x was placed in form x^a, then which of the following would be the value of a?
4) -1/2
1) Rewriting the expression:
[tex]\frac{1}{\sqrt[]{x}}[/tex]2) As a power we can write this way, considering that we can rewrite any radical as a power and that when we have a radical on the denominator we can rewrite it as a negative rational exponent. So we can write it out:
[tex]\frac{1}{\sqrt[]{x}}=\frac{1}{x^{\frac{1}{2}}}=x^{-\frac{1}{2}}[/tex]3) Hence, the answer is 4) -1/2
What fraction of $36,000 is $27,000?
We need to keep in mind that
36000 is 1
In order to know the fraction we need to divide 27000 between 36000, and then simplify the fraction
[tex]\frac{27000}{36000}=\frac{27}{36}=\frac{3}{4}[/tex]the fraction of 36000 that is 27000 is 3/4
how would I solve and what would the answer be?
Given that:
f(x) = |x| and g(x) = x + 6
[tex](f\circ g)(x)=|x+6|[/tex]and
[tex](g\circ f)(x)=|x|+6[/tex]I think I’m off to a good start but I’m still confused
The radius is given 3.5 ft and height is given 14 ft.
ExplanationTo find the surface area of cylinder,
Use the formula.
[tex]S=2\pi rh+2\pi r^2[/tex]Substitute the values.
[tex]\begin{gathered} S=2\pi r(h+r) \\ S=2\times3.14\times3.5(14+3.5) \\ S=384.65ft^2 \end{gathered}[/tex]The volume of cylinder is determined as
[tex]V=\pi r^2h[/tex]Substitute the values
[tex]\begin{gathered} V=3.14\times3.5^2\times14 \\ V=538.51ft^3 \end{gathered}[/tex]AnswerThe surface area of cylinder is 384.65 sq.ft.
The volume of cylinder is 538.51 cubic feet.
1 litre=1000cm³. About how many test tubes, each holding 24cm³ of water, can be filled from a
1 litre flask?
Answer: 125/3 or about 41.667
Note that you can't have 2/3 of a test tube, so the expected answer may be 42 test tubes.
Step-by-step explanation:
Write a simple algebra equation using the word problem
24x = 1000
x represents the number of test-tubes, each of which hold 24cm^3 of water.
divide both sides by 24
x = 125/3 or about 41.667
The area of a rectangle is 28m^2, and the length of the rectangle is 5 meters less than three times the width. Find the dimensions of the rectangle. L:W:
The area of a rectangle is given by the formula
[tex]A=L*W[/tex]where
A=28 m2
L=3W-5
substitute given values in the formula
[tex]\begin{gathered} 28=(3w-5)W \\ 28=3w^2-5w \\ 3w^2-5w-28=0 \end{gathered}[/tex]Solve the quadratic equation
Using the formula
we have
a=3
b=-5
c=-28
substitute
[tex]w=\frac{-(-5)\pm\sqrt{-5^2-4(3)(-28)}}{2(3)}[/tex][tex]w=\frac{5\pm19}{6}[/tex]The solutions for w are
w=4 and w=-2.33 ( is not a solution because is a negative number)
so
The width w=4 m
Find out the value of L
L=3w-5=3(4)-5=7 m
therefore
L=7 mW=4 mEnter the missing values in the area model to find 10(8y + 5)+510BoyAccording to the model above, 10(8y + 5) =Submit Answeatte
Note you have to use the value outside the bracket to multiply the inner value.
Which of the following could be the points that Jamur plots?
To solve this problem, we need to calculate the midpoint for the two points in each option and check if it corresponds to the given midpoint (-3,4).
Calculating the midpoint for the two points of option A.
We have the points:
[tex](-1,7)and(2,3)[/tex]We label the coordinates as follows:
[tex]\begin{gathered} x_1=-1 \\ y_1=7 \\ x_2=2 \\ y_2=3 \end{gathered}[/tex]And use the midpoint formula:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]Substituting our values:
[tex](\frac{-1_{}+2_{}}{2},\frac{7_{}+3_{}}{2})[/tex]Solving the operations:
[tex](\frac{1_{}}{2},\frac{10_{}}{2})=(\frac{1_{}}{2},5)[/tex]Since the midpoint is not the one given by the problem, this option is not correct.
Calculating the midpoint for the two points of option B.
We have the points:
[tex](-2,6)and(-4,2)[/tex]We follow the same procedure, label the coordinates:
[tex]\begin{gathered} x_1=-2 \\ y_1=6 \\ x_2=-4 \\ y_2=2 \end{gathered}[/tex]And use the midpoint formula:
[tex]\begin{gathered} (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ \text{Substituting our values} \\ (\frac{-2-4_{}}{2},\frac{6+2_{}}{2}) \\ \text{Solving the operations:} \\ (\frac{-6}{2},\frac{8}{2}) \\ (-3,4) \end{gathered}[/tex]The midpoint for the two points in option B is (-3,4) which is the midpoint given by the problem.
Answer: B (-2,6) and (-4,2)
the bearing from S to R is 160° what is the bearing of S from R
.
The bearing of S from R is given as;
[tex]90+90+90+70=340\degree[/tex]I need help with this question please help me asap?
Answer
Explanation
• Range (R): the amount between the upper and lower limit.
If f(x) = ln [ sin2(2x)(e-2x+1) ] , then f’(x) is
I want to solve ?
Here we will write our function in regular form using an identity.
[tex]log(ab)=loga+logb[/tex][tex]log(a/b)=loga-logb[/tex]Therefore, the rule of our function [tex]f(x)[/tex] will be as follows.
[tex]f(x)=ln(sin^2(2x))+ln(e^{-2x}+1)[/tex]The derivative of the natural logarithm [tex]ln(x)[/tex] function is of the following form.
[tex](ln(x))'=\frac{x'}{x}[/tex]It is found by dividing the derivative of the function in [tex]lnx[/tex] by the function in [tex]lnx[/tex].
For example:
[tex](ln(5x))'=\frac{(5x)'}{5x} =\frac{5}{5x} =\frac{1}{x}[/tex]According to this information, let's take the derivative of our function.
[tex]f'(x)=\frac{2sin(4x)}{sin^2(2x)} +\frac{-\frac{2}{e^{2x}} }{e^{-2x}+1}[/tex][tex]f'(x)=4cot(2x)-\frac{2}{1+e^{2x}}[/tex]Rules:[tex]((sin2x)²)'=2.2sin(2x)cos(2x)=2sin(4x)[/tex][tex](e^x)'=x'.e^x[/tex]HelppppppFunction f is a(n)functionThe graph is a reflection in thewith a verticaland atranslationunits:The domain of f isThe domain of the parent function is;The range of f isThe range of the parent function is
Answer:
In order of appearance of boxes
quadraticx-axisstretch3 (units)upall real numbersall real numbersy ≤ 3y ≥ 0Step-by-step explanation:
The given function f(x) = -2x² + 3 belongs to the quadratic family of equations. A quadratic equation has a degree of 2. The degree is the highest power of the x variable in the function f(x)
The parent f(x) = x²
Going step by step:
2x² ==> graph x² is vertically stretched by 2. For any value of x in x², the new y value is twice that the old value. For example, in the original parent function x², for x = 2, y = 4. In the transformed function 2x², for x = 2, y = 2 x 4 = 8 so it has been stretched vertically. It becomes skinnier compared to the original
-2x² => graph is reflected over the x-axis. It is the mirror image of the original graph when viewed from the x-axis perspective
-2x² + 3 ==> graph is shifted vertically up by 3 units
Domain is the set of all x-input values for which the function is defined. For both x² and -2x² + 3 there are no restrictions on the values of x. So the domain for both is the set of all real numbers usually indicated by
-∞ < x < ∞
The range is the set of all possible y values for a function y = f(x) for x values in domain.
The range of f(x) = x² is x≥ 0 since x² can never be negative
Range of -2x² + 3 is x ≤ 3 : Range of -2x² is y ≤ 0 since y cannot be negative and therefore range of -2x² + 3 is y ≤ 3
What is the slope of a line perpendicular to the line whose equation is15x + 12y = -108. Fully reduce your answer.Answer:Submit Answer
GIven:
The equation of a line is 15x+12y=-108.
The objective is to find the slope of the perpencidular line.
It is known that the equation of straight line is,
[tex]y=mx+c[/tex]Here, m represents the slope of the equation and c represents the y intercept of the equation.
Let's find the slope of the given equation by rearranging the eqation.
[tex]\begin{gathered} 15x+12y=-108 \\ 12y=-108-15x \\ y=-\frac{15x}{12}-\frac{108}{12} \\ y=-\frac{5}{4}x-9 \end{gathered}[/tex]By comparing the obtained equation with equation of striaght line, the value of slope is,
[tex]m_1=-\frac{5}{4}[/tex]THe relationship between slopes of a perpendicular lines is,
[tex]\begin{gathered} m_1\cdot m_2=-1 \\ -\frac{5}{4}\cdot m_2=-1 \\ m_2=-1\cdot(-\frac{4}{5}) \\ m_2=\frac{4}{5}^{} \end{gathered}[/tex]Hence, the value of slope of perpendicular line to the given line is 4/5.
The function table below is intended to represent the relationship y=-5x+1. However, one of the entries for y does not correctly fit the relationship with x.
Answer:
Step-by-step explanation:
none of the answers are correct
In AOPQ, 0 = 500 cm, p = 600 cm and q=380 cm. Find the measure of P to thenearest 10th of a degree.
Answer: Triangle has three sides, which are:
[tex]\begin{gathered} O=500\operatorname{cm} \\ P=600\operatorname{cm} \\ Q=380\operatorname{cm} \\ \end{gathered}[/tex]We need to find the angle p, that is right across the side P:
[tex]\angle A=\arccos (\frac{b^2+c^2+a^2}{2bc})=0.97895\text{rad}=56.09\text{degres}[/tex]This is the value of angle A
Find the area of this trapezoid. Be sure to include the correct un4 cm6 cm4 cm15 cm
So,
Here we have the following trapezoid:
Remember that the area of a trapezoid can be found if we apply the following formula:
[tex]A=\frac{1}{2}(\text{base}1+\text{base}2)\cdot\text{height}[/tex]Where bases 1 and 2 are the greater and smaller bases respectively.
So, if we replace:
[tex]\begin{gathered} A=\frac{1}{2}(15+4)\cdot4 \\ A=\frac{1}{2}(19)\cdot4 \\ A=9.5\cdot4 \\ A=38 \end{gathered}[/tex]So the area is 38cm^2.
As an incoming college freshman, Tina received a 10-year $15,100 Federal Direct
Unsubsidized Loan with an interest rate of 4.29%. She knows that she can begin making
loan payments 6 months after graduation but interest will accrue from the moment the
funds are credited to his account. How much interest will accrue while she is still in
school and over the 6-month grace period for this freshman year loan?
O $2,813.28
O $2,915.06
O $3,001.32
O $3,102.38
The interest that will accrue while the college freshman is still in school and over the 6-month grace period for this freshman year loan is, approximately, B. $2,915.06.
How is the interest determined?The interest for federal college loans is based on the simple interest formula instead of compounding.
By compounding, we mean that interest is computed on the principal and accumulated interest.
Federal Direct Unsubsidized Loan = $15,100
Number of years for college = 4 years
The number of years before repayment = 4.5 years (4 years + 6 months)
Simple interest for 4.5 years = $2,915.06 ($15,100 x 4.29% x 4.5 years)
On the other hand, one can compute the compounded interest using an online finance calculator.
Compounded Interest:N (# of periods) = 4.5 years
I/Y (Interest per year) = 4.29%
PV (Present Value) = $15,100
PMT (periodic payment) during the 4.5 years = $0
Results:
FV = $18,241.85
Total Interest = $3,141.85
Thus, the interest is Option B.
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Slope =
y-intercept = (0,
Answer:
y intercept= (0,-3)
slope= 2/1 or simplified 2
Step-by-step explanation:
A genetic experiment with
peas resulted in one sample of offspring that consisted of 447 green peas and 169 yellow peas.
a. Construct a 90% confidence interval to estimate of the percentage of yellow peas.
b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
a. Construct a 90% confidence interval. Express the percentages in decimal form.
L s p< (Round to three decimal places as needed.)
b. Based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow?
O
No, the confidence interval includes 0.25, so the true percentage could easily equal 25%
L
O Yes, the confidence interval does not include 0.25, SO the true percentage could not equal 25%
Using the z-distribution, it is found that:
a. The 90% confidence interval to estimate of the percentage of yellow peas is: (34.04%, 41.58%).
b. The correct option is: Yes, the confidence interval does not include 0.25, so the true percentage could not equal 25%.
What is a confidence interval of proportions?The bounds of a confidence interval of proportions is given according to the equation presented as follows:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which the parameters are described as follows:
[tex]\pi[/tex] is the sample proportion.z is the critical value of the distribution.n is the sample size, from which the estimate was builtThe confidence level is of 90%, hence the critical value is z = 1.645, using a z-distribution calculator.
The values of the sample size and of the estimate are given as follows:
[tex]n = 447, \pi = \frac{169}{447} = 0.3781[/tex]
Hence the lower bound of the interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3781 - 1.645\sqrt{\frac{0.3781(0.6219)}{447}} = 0.3404[/tex]
The upper bound is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.3781 + 1.645\sqrt{\frac{0.3781(0.6219)}{447}} = 0.4158[/tex]
As a percentage, the interval is given as follows: (34.04%, 41.58%).
The confidence interval does not contain 0.25, hence the true percentage would not be equal to 25%, contradicting the expectation.
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Calculate the answers. 13. An orbiting satellite is positioned 3,105 mi above the earth (rearth = 3,959 mi) and orbits the earth once every 201.3 min. Assuming its orbit is a circle, find the distance traveled in 50.0 min.
first you will calculate the speed of the orbiting satelite
[tex]\text{speed = }\frac{dis\tan ce}{time}[/tex]distance = circumference of the of the orbit
[tex]\begin{gathered} \text{circumference = 2}\times\pi\times\text{ r} \\ r\text{ = radius of the earth + the height of the satelite above the earth} \\ r\text{ = 3105+3959 =7064mi} \end{gathered}[/tex][tex]\text{circ of the orbit = }2\text{ }\times3.142\times7064=\text{ 44390.176}[/tex][tex]\text{speed = }\frac{44390.176}{201.3}\text{ = 220.52mi/min}[/tex]distance covered in 50.0 min
distance = speed X time
[tex]\text{distance = 220.52}\times50=11026mi[/tex]the distance traveled is 11026 mi
2. The area A of a rectangle is represented by the formula A = Lw, where Lis the length and wis the width. The length of the rectangle is 5. Write anequation that makes it easy to find the width of the rectangle if we knowthe area and the length.
1) Considering that the Area of a rectangle is given as:
[tex]A=lw[/tex]2) We can then write the following equation plugging into that the length= 5.
Say the area is "A", then we can find the width this way:
[tex]\begin{gathered} A=5ww \\ 5w=A \\ \frac{5w}{5}=\frac{A}{5} \\ w=\frac{A}{5} \end{gathered}[/tex]Note that we rewrote that to solve it for w (width).
All we need is to plug into the A the quantity of the area of this rectangle
Thus, the answer is w=A/5
Look at this graph: 100 90 80 60 50 20 10 10 20 30 50 60 70 80 90 100 What is the slope? Simplify your answer and write it as a proper fraction, improper fraction or integer. Submit Not feeling yet These con heo
To find the slope of the line we have to use this equation:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Now we have to replace two coordiantes in the line, so I was able to see the coordinates: (0,40) and (20,50), sothe equation become:
[tex]m=\frac{50-40}{20-0}[/tex]and we simplify so:
[tex]m=\frac{10}{20}=\frac{1}{2}[/tex]So the slope is 1/2
Use a system of equations to solve the following problem.The sum of three integers is380. The sum of the first and second integers exceeds the third by74. The third integer is62 less than the first. Find the three integers.
the three integers are 215, 12 and 153
Explanation:
Let the three integers = x, y, and z
x + y + z = 380 ....equation 1
The sum of the first and second integers exceeds the third by 74:
x + y - 74 = z
x + y - z = 74 ....equation 2
The third integer is 62 less than the first:
x - 62 = z ...equation 3
subtract equation 2 from 1:
x -x + y - y + z - (-z) = 380 - 74
0 + 0 + z+ z = 306
2z = 306
z = 306/2
z = 153
Insert the value of z in equation 3:
x - 62 = 153
x = 153 + 62
x = 215
Insert the value of x and z in equation 1:
215 + y + 153 = 380
368 + y = 380
y = 380 - 368
y = 12
Hence, the three integers are 215, 12 and 153
