A particle with a charge of +7.4 C is separated from another charged particle with a charge of
-3.6 uC by a distance of 1.4 m. Find the direction and the magnitude of electrostatic force
between the particles.

Answers

Answer 1

Explanation:

9 × 10^-3 × 13.59 = 0.122 N

A Particle With A Charge Of +7.4 C Is Separated From Another Charged Particle With A Charge Of-3.6 UC
Answer 2

The given question is incorrect I think the question you asking is:

A particle with a charge of +7.4μC is separated from another charged particle with a charge of -3.6μC by a distance of 1.4 m. Find the direction and the magnitude of the electrostatic force between the particles.

The electrostatic force between the particles is 0.122N. The direction of the force is from the negatively charged particle to the positively charged particle.

What is electrostatic force?

The electrostatic force is the force of attraction or repulsion between two charged particles due to their electric charges. It is a fundamental force in nature and is described by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

Here in the Question,

Given Data:

Charge of particle 1 (q1) = +7.4 μC = 7.4 × 10^-6 C

Charge of particle 2 (q2) = -3.6 μC = -3.6 × 10^-6 C

Distance between the two particles (r) = 1.4 m

Coulomb's constant (k) = 8.99 × 10^9 N·m^2/C^2

Using Coulomb's law:

Electrostatic force (F) = (k * |q1| * |q2|) / r^2

where |q1| and |q2| are the magnitudes of the charges.

Substituting the values, we get:

F = (8.99 × 10^9 N·m^2/C^2) * (7.4 × 10^-6 C) * (3.6 × 10^-6 C) / (1.4 m)^2

F = 0.12219≈0.122

Therefore, The electrostatic force between the particles is 0.122N. Since one of the charges is negative, the force will be attractive, pulling the particles toward each other.

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