At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.
What is Mass?Weight is the force of gravity acting on an item, whereas mass is the amount of matter that makes up the object. Weight varies from place to place yet mass is constant everywhere you are in the cosmos. Kilograms are used to measure mass.Let the mass on earth be m.
Given, W= 600N, g= 9.97 N/kg(top of mountain)As we know:
The formula for Weight = mass x acceleration due to gravity at place W=m*gNow, calculate as follows:
m = W/g= 600*9.97mass = 60.18 kgW= m*g= 60.18 * 9.97= 600NWeight = 600NTherefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.
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The speed of sound depends on all of the following properties except:
a
Type of element
b
Composition of the medium or type of matter
c
Density
d
Temperature
Answer:
d: temperature
Explanation:
temperature doesn't have anything to do with sound
Please help me with this, it's a Kinematics Equation 2 problem!
The distance covered by the object is given as,
[tex]d=ut+\frac{1}{2}at^2[/tex]Plug in the known values,
[tex]\begin{gathered} d=(0\text{ m/s)(9 s)+}\frac{1}{2}(2m/s^2)(9s)^2 \\ =0\text{ m+}81\text{ m} \\ =81\text{ m} \end{gathered}[/tex]Thus, the distance covered by the object is 81 m.
scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as , where is in nm. if a 295-nm-thick coating is placed on glass for what visible wavelengths will the reflected light have maximum constructive interference?
The wavelength of the reflected light will have a range from 360 nanometers to 700 nanometers.
Constructive Interference may be defined as the process which occurs when the maxima of any two waves add up and the amplitude of the resulting wave will be equal to the sum of the two individual waves. According to the question thickness of coating, d = 295 nm and wavelength varies as n = [(30nm) ^1/2]/λ^1/2.
Also, the wavelength will be expressed as
λ = 2nd/M where M = 1,2,3......
λ = 2d[(30nm)^1/2]/Mλ^1/2
λ^3/2 = (d60nm^1/2)/M
λ = ∛d² 3600 nm/M
Now, if M = 1 then,
λ = ∛295² 3600nm/1 = 679.18 nm
Now, if M = 2 then,
λ = ∛295² 3600nm/2 = 679.18 nm
Now, if M = 3 then,
λ = ∛295² 3600nm/3 = 326.51 nm
So, the range is approximately 360 nm to 700 nm.
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Complete Question:
Scientists are testing a transparent material whose index of refraction for visible light varies with wavelength as n = 30.0 nm1/2 /l1/2, where l is in nm. If a 295-nm-thick coating is placed on glass 1n = 1.502 for what visible wavelengths will the reflected light have maximum constructive interference?
What are three sources of errors in a center of gravity lab experiment
The centre of gravity, in physics, is an imaginary point in a body of matter where for convenience in certain calculations,
What are three sources of errors in a center of gravity?Sources of errors for the center of gravity of an irregularly shaped object: -environmental error: when the wind blows it may remove the irregularly shaped object from equilibrium. add: density variations, shape variations say, thickness], inability to measure precisely, inability to compute precisely. For example, as a result of a number of the center of gravity measurements, we may have the best estimate of the true value for the acceleration due to gravity, the center of gravity is the point between which the force of gravity move on a thing or system. In most mechanics problems the gravitational pasture is assumed to be constant. The center of gravity is then in entirely the same position as the center of mass.
So we can conclude that It is important to know the center of gravity because it predicts the behavior of a moving body when acted on by gravity.
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the most common type of topographic map is created by the USGS is a 7.5-minute by 7.5-minute quadrangle map (figure 3.18). this means that each side of the map is 7 minutes and 30 seconds. each minute of latitude is 1852 meters and each second of latitude is 31 meters. how many meters does this map cover in a north-south direction?
Answer: I think it's 13,000 meters
Explanation:
A car is traveling on a highway. the distance (in miles) from its destination and the time (in hours) is given by the equation d = 420 minus 65 t. what is the slope of the line represented by the equation? what is the practical meaning of the slope? a. m = 420; the total distance is 420 miles. b. m = 65; the car is traveling 65 miles per hour. c. m = negative 65; the car is traveling 65 miles per hour. d. m = negative 420; the total distance is 355 miles.
consider newton's 3rd law, the force that the earth exerts on a person will be equal and opposite that what the person applies to the earth. however, why don't we see the earth accelerate?
According to Newton's third law, for every action there is an equal and opposite reaction. However, the land we see on earth is stationary and the force applied by us is not at all sufficient to make a movement or to accelerate.
What is Newton's third law of motion ?According to Newton's third law, for every action there is an equal and opposite reaction. Therefore, when we apply a force on an object, the object will exerts an equal and opposite force.
According to Newton's second law of motion, the force exerted on a body is the product of mass and acceleration. Hence, the force acting on body is directly proportional to the mass of the body and it accelerates by the applied force.
The mass of humans in earth is negligible compared to the mass of earth . Therefore, the force we exert on earth is not at all sufficient to accelerate the earth. However, earth in turn exerts an equal and opposite force.
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a 7.26 kg bowling ball and a 0.163 kg cricket ball are simultaneously dropped from a height of 10.0 m. what can you say about the velocity of the bowling ball, vb, compared to the velocity of the cricket ball, vc, when they hit the ground?
The velocity Vb of the bowling ball will be same as that of the cricket ball when dropped simultaneously from the same height. Because the velocity while hitting the ground is not dependent of mass.
Let us consider a general case,
Let us say the ball is dropped from a height H, its final velocity on reaching the ground is V, the acceleration g will be constant because everything is happening on the earth's surface and neglecting the air drag,
So, using equation of motion,
V ²-U²=2gH
U is the initial velocity in of the ball which is zero in our case,
So,
V²=2gH
V =√2gH
As we can see, the velocity on hitting the ground is independent of the mass.
So we can say,
Vb of the balling bowl is same as that of Vc on hitting the ground.
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a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad. what is its final angular velocity? how much time elapses while it turns through the 300 radians?
If a wheel has a constant angular acceleration of 4 rad/s2. starting from rest, it turns through 300 rad , then the final angular velocity would be 48.96 rad /s and 12.24 seconds elapse while it turns through the 300 radians.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
By using the second equation of motion given by Newton,
S = ut + 1/2at²
300 = 0 + 0.5 × 4 × t²
t² =300 /2
t = 12.24 seconds
The final angular velocity = 0+ 12.24 × 4
= 48.96 rad /s
Thus, 12.24 seconds elapse while it turns through the 300 radians.
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if a certain specific amount of heat energy were absorbed by a both a pound of water and by a pound of steel, whose temperature would increase the most?
The temperature of steel would increase compared to the pound of water when certain specific amount of heat were absorbed by both .
What is temperature and why steel would have more temperature than pound of water?Temperature is the measure of degree of hotness or coldness of either a substance or a region.Here a certain amount of heat energy is absorbed by both steel and pound of water .As we know the water when falls it potential energy converts to kinetic energy.Here the temperature of steel would be far more than the pound of water because of more heat absorbed.Hence steel would be more heated.To know more about temperature visit:
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cepheid stars are useful to astronomers as indicators of group of answer choices white-dwarf star behavior. the mechanics of eclipsing variable stars. distance, particularly to stars in our galaxy and to nearby galaxies. stars with very high speed motion.
Option b cepheid stars are useful to astronomers as indicators of distance, particularly to stars in our Galaxy and to nearby galaxies.
An astronomer is a scientist who focuses on the stars, planets, galaxies and other extraterrestrial natural phenomena. The study of astronomy includes everything in the cosmos that is outside of our solar system. This includes celestial bodies that we can see with our unaided eyes, such as the Sun, Moon, planets, and stars. Additionally, it contains celestial bodies like distant galaxies and minute particles that we can only see with telescopes or other tools. On a more urgent level, astronomy aids in our research into how to extend the survival of our species. Studying the Sun's impact on Earth's climate and how it will effect weather, water levels, etc., for instance, is crucial. The broad discipline of natural science known as astronomy is concerned with celestial objects, such as those in the solar system, galaxies, and extragalactic objects. The majority of the fieldwork participants are students who specialize in this broad discipline.
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How do these forces affect the car's
movement?
Thrust, Lift, Drag, and Weight are four opposing forces that affect every vehicle, whether it's a car, truck, boat, airplane, helicopter, or rocket.
What is force?A force is an influence that can cause an object's motion to change. A force can cause a mass object to change its velocity, or accelerate. Intuitively, force can be described as a push or a pull. A force exist as a vector quantity because it has both magnitude and direction. A mass object's velocity changes when it is pushed or pulled. Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction. The term "force" has a specific meaning. At this level, it is perfectly acceptable to refer to a force as a push or a pull.To learn more about force, refer to:
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The velocity-time equation for a golf cart isVA= (1 m/s) + (-0.5 m/s?)t (a) What is the cart's initial velocity? (b) What is the cart's acceleration?
If the velocity-time equation for a golf cart is v = (1 m/s) + (-0.5 m/s)t , then the initial velocity of the cart would be 1 m / s and the acceleration of the cart would be - 0.5 m / s² .
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².
As given in the problem the velocity-time equation for a golf cart is
v = (1 m/s) + (-0.5 m/s)t ,
The initial velocity of the cart at t = 0 would be 1 m / s.
By differentiating the given equation of the velocity,
The acceleration of the cart would be -0.5 m / s.
Thus, the initial velocity would be 1 m / s and the acceleration would be -0.5 m / s.
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one steel ball and one aluminum ball are the same size but the steel ball weighs twice as much as the other. the balls are dropped from the roof of a single-story building at the same instant of time. the time it takes the balls to reach the ground below will be:
It is same for both the balls. Due to the fact that balls fall freely regardless of their weight, both metallic balls take the same amount of time to reach the ground.
When two identically sized objects are dropped from a certain height, they will fall with gravitational acceleration (g). The weight of the objects will not affect how long it takes them to reach the ground. The density of the medium in which an object is dropped affects how long it takes for each object to travel there. Due to the influence of gravity and the same medium, we can therefore infer that both metal balls will take the same amount of time to reach the ground (air). Experiments have been conducted in vacuum rooms and show that when the balls are released from the top of the store, the acceleration of attraction to the floor is gravity and it has a value of 9.8 meters/square second regardless of its weight.
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Hey surveyor is drawing property lines . He draws one line that is 25.0 m long and is 20° south of west.  how long is the western component of the vector he has drawn?
Answer:
23.5 m
Explanation:
25 m * cos 20 =23.5 m
dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. rob left some time later driving in the same direction at an average speed of 48 km/h. after driving for five hours rob caught up with dan. how long did dan drive before rob caught up?
Dan drove for 6 hours before catching up with Rob who left his home sometime later than Dan.
Dan left the white house and drove toward the recycling plant at an average speed of 40 km/h. Let d1 be Dan's start in km.
Rob left some time later driving in the same direction at an average speed of 48 km/h. Let d2 be rob's start in km.
Let t1 be the time between dan and rob's leaving.
After Rob leaves, Dan travels around 40×5 =200km.
During the same time, rob travels a distance of
48×5=240km
d1= 240-200
= 40 km
t1 = 40/40 = 1
So Dan traveled 1 more hour, which means he traveled for 6 hours.
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To find the density of an object you would use a graduated cylinder to find what characteristic of the obiect? A)mass b)length c)volume d)weight
Answer:
C Volume
Explanation:
You would use a graduated cylinder with liquid in it to see how much is displaced when the object is placed in it to determine the volume of the object
an elevator of mass m is initially at rest on the first floor of a building. it moves upward, and passes the second and third floors with a constant velocity, and finally stops at the fourth floor. the distance between adjacent floors is h. what is the net work done on the elevator during the entire trip, from the first floor to the fourth floor?
From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.
Given,
On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.
the separation between the floors is h
The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)
= -3mgh
Work Done = -3mgh
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Q3. A 3500 kg van hits a 2500 kg car with a force of 1480 N [E].
a) What force does the van experience?
The force experience by a van of 3500 kg when it hits a car of 2500 kg with a force of 1480 N is 1057.14 N.
What is force?Force can be defined as the product of mass and acceleration.
To calculate the force experienced by the van, we use the formula below
Formula:
f = mF/M..................... Equation 1Where:
M = Mass of the vanm = Mass of the carf = Force on the carF = Force on the vanFrom the question,
M = 2500 kgm = 3500 kgF = 1480 NSubstitute these values into equation 1
f = (2500×1480/3500)f = 1057.14 N.Hence, the force experience by the van is 1057.14 N.
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Air is approximately 21% o2 and 78% n2 by mass. Calculate the root-mean-square speed of each gas at 273 k.
The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2
How to solve for the root mean square methodWe have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.
We have 1 j = 1 kgm²/s²
Vrms = √3rt/Mm
R = gas constant
T = temperature = 273
Mm is the molar mass
The molar mass of N₂ is = 0.02800 kg / mol
The mo;lar mass of o₂ = 0.03200 kg / mol
We have to solve first for N₂
= √3 (8.32447 * 273 / 0.028000
= √243,198.247
= 493.15
For 02
Vrms = √3 * 8.31447 * 273 / 0.03200
= √212798.466
= 461.3
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In an arena football game, the quarterback throws a pass so that it reaches the top of the stadium at the peak of its flight. If he threw the ball at an angle of 64 degrees and the stadium is 34 meters high, calculate the velocity with which he threw the ball and the distance the ball traveled.
Formulas for projectile motion:
Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g
Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g
where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.
Given:
Angle of projection, α = 64°
Maximum height of projectile, h = 34 m.
To find: Initial velocity (u), and horizontal distance travelled (R).
Rearrange 'h' equation for 'u',
u sin(α) = [tex]\sqrt{2gh}[/tex]
⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]
Substitute given values.
⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)
⇒ u = 25.81 / 0.899 m/s
∴ u = 28.71 m/s
This is the velocity with which the ball was thrown.
The distance travelled by the ball can be calculated by using the equation,
R = [tex]u^{2}[/tex] sin(2α) / g
Substitute the given values.
⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8
⇒ R = 649.53 / 9.8
∴ R = 66.27 m.
This is the distance travelled by the ball.
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A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides
The free body diagram of the crate can be shown as,
Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.
If centripetal force is towards the center and gravitational force is also towards the center how can we be lighter at the equator?
ANSWER and EXPLANATION
We want to determine why a person weighs lighter at the equator.
At the equator, an object will weigh slightly less as a result of the slightly greater centripetal force and the slight increase in distance from the center of gravity of the earth due to the equatorial bulge. This would imply a decrease in the gravitational force that an object experiences.
In other words, the earth is not a perfect sphere, and so, at the equator, an object will be slightly farther from the center.
That is the answer.
Mosses are located in which zone of deciduous forests? a. tree stratum b. ground c. shrub d. herb please select the best answer from the choices provided a b c d
Answer
Ground Zone
Explanation
The final zone is the Ground zone. It contains lichen, club mosses, and true mosses. The deciduous forest has four distinct seasons, spring, summer, autumn, and winter. In the autumn the leaves change color.
Answer: B Ground
Explanation:
Forces with magnitudes of v = 135 newtons and u = 280 newtons act on a hook (see figure). The angle between the two forces is 45°. Find the direction and magnitude of the resultant of these forces. (Hint: Write the vector representing each force in component form, then add the vectors. Round your answers to two decimal places.)
To find the resultant force we will first find the component force of the forces given, to do this, we need to remember that any vector can be express in component form by:
[tex]\begin{gathered} \vec{v}= \\ \text{ where } \\ v\text{ is the magnitude } \\ \theta\text{ is the angle of the vector with respect to the positive x-axis.} \end{gathered}[/tex]For force u we notice that its magnitude is 280 N and its angle is zero, then we have:
[tex]\begin{gathered} \vec{u}=<280\cos0,280\sin0> \\ \vec{u}=<280,0> \end{gathered}[/tex]For force v we know that its magnitude is 135 N and its angle is 45°, then we have:
[tex]\begin{gathered} \vec{v}=<135\cos45,135\sin45> \\ \vec{v}=<95.46,95.46> \end{gathered}[/tex]Now that we have both vectors in component form we add them to get the resultant in component form:
[tex]\begin{gathered} \vec{F}=\vec{u}+\vec{v} \\ \vec{F}=<280,0>+<95.46,95.46> \\ \vec{F}=<375.46,95.46> \end{gathered}[/tex]Once we have the resultant force in component form we can find its magnitude and direction if we remember that they are given by:
[tex]\begin{gathered} F=\sqrt{F_x+F_y} \\ \theta=\tan^{-1}(\frac{F_y}{F_x}) \end{gathered}[/tex]Plugging the values we found for the components we have:
[tex]\begin{gathered} F=\sqrt{375.46^2+95.46^2} \\ F=387.41 \end{gathered}[/tex]and
[tex]\begin{gathered} \theta=\tan^{-1}(\frac{95.46}{375.46}) \\ \theta=14.27 \end{gathered}[/tex]Therefore, the magnitude of the resultant force is 387.41 N and the direction is 14.27°
an object projected horizontally from a height flies through the air before hitting the ground. the path of the projectile in the air can be described as a
The path of the projectile is parabola projected horizontally from a height flies through the air before hitting the ground.
What is projectile and what is the path of projectile in air before hitting the ground?A projectile is an object that is compelled to move under the influence of external force.And then the projectile moves freely under the influence of gravity as in here too.Here an object is projected horizontally from a height flies through the air before hitting the ground.The path of the projectile before hitting the ground would be parabola in the air .Hence when an object projected horizontally from a height flies through the air before hitting the ground, the path of the projectile in the air is parabola.To know more about projectile visit:
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complete the table=x =0 2 3 4 6 8 y=30 27 24
Answer: (x=1 y=30) (x=2 y=27) (x=3 y=24) (x=4 y=21) (x=5 y=18) (x=6 y=15) (x=7 y=12) (x=8 y=9) (x=9 y=6) (x=10 y=3) etc its going down by 3 so 30-3=27 27-3=24 24-3=21 etc
hope i helped
Explanation:
4. for the experimental runs you made, calculate the expected acceleration using the expression you found with newtons second law of motion and the specific masses used. compare the figures with your experimental results. are the experimental acceleration values low or high? why?
As the mass of an object is increased, the acceleration of the object is decreased.
According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it. This implies that as the force applied to an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so do its mass.
As per Newton's second law of motion:
f = ma ------ (1)
f = (Δp) / t ⇒ Rate of change of momentum
f = (mu - mv) / t = [m(u - v)] / t ----- (2)
From equation (1) and equation (2) we get:
[m(u-v)] / t = ma
a = (u - v) / t
The experimental acceleration value will be less than the theoretical acceleration value. because it is impossible to sustain a constant rate of velocity change for an extended period of time. The difference between practical and theoretical acceleration will therefore be smaller.
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the large blade of a helicopter is rotating in a horizontal circle. the length of the blade is 7.99 m, measured from its tip to the center of the circle. find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the center of the circle.
The ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the centre of the circle: 1.29
Centripetal acceleration is given by :
a = ω2R
where,
ω is the angular speed
R is the distance of the point from the centre
Let the point at the tip be A and that at distance 6.16 m from centre be B
Distance of point A from centre (RA) = 7.99 m
Distance of point B from centre (RB) = 6.16 m
Centripetal acceleration at A (aA) = ω2RA = 7.99ω2
Centripetal acceleration at B (aB) = ω2RB = 6.16ω2
The ratio (aA/aB) = 7.99/6.16 = 1.29
What is centripetal acceleration ?
centripetal acceleration is defined as the motion characteristic of an object moving along a circular path. Any object moving in a circle whose acceleration vector points towards the centre of that circle is called centripetal acceleration. You must have seen various examples of medium acceleration in your daily life. When you drive a car around a circle, your car experiences an average acceleration, and the average acceleration is also observed by a satellite orbiting the Earth. Middle means towards the centre.
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6. A ball rolls off a table and falls 0.75 m to the floor, landing with a speed of 4.0 m/s. 1. What is the acceleration of the ball just before it strikes the ground? 2. What was the initial speed of the ball? 3. What initial speed must the ball have if it is to land with a speed of 5.0 m/s?
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
v² = u² + 2 a s
v = Final velocity
u = Initial velocity
a = Acceleration
s = Displacement
1 ) In vertical motion,
v = 4 m / s
s = 0.75 m
u = 0
4² = 0 + ( 2 * a * 0.75 )
a = 16 / 1.5
a = 10.67 m / s²
2 ) The initial speed of the ball,
Resolving the velocity into its horizontal and vertical components,
[tex]V_{y}[/tex]² = [tex]U_{y}[/tex]² + 2 a s
[tex]V_{y}[/tex]² = 0 + ( 2 * 9.8 * 0.75 )
[tex]V_{y}[/tex] = 3.83 m / s²
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
4² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 16 - 14.67
[tex]V_{x}[/tex] = 1.15 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 1.15 m / s
3 ) If the ball lands with a speed of 5.0 m/s,
V² = [tex]V_{x}[/tex]² + [tex]V_{y}[/tex]²
5² = [tex]V_{x}[/tex]² + 3.83²
[tex]V_{x}[/tex] = √ 25 - 14.67
[tex]V_{x}[/tex] = 3.2 m / s
[tex]V_{x}[/tex] = [tex]U_{x}[/tex] = 3.2 m / s
Therefore,
1 ) Acceleration of the ball just before it strikes the ground = 10.67 m/s²
2 ) The initial speed of the ball = 1.15 m / s
3 ) The initial speed of the ball if the ball lands at 5.0 m/s = 3.2 m / s
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