A projectile is launched with an initial speed of 40 mys from the foor of a tunnel whose height is 30 m. What angle of elevation should be used to achieve the maximum possible horizontal range of the projectile?

Answers

Answer 1

Answer:

We are given the trajectory of a projectile:

y=H+xtan(θ)−g2u2x2(1+tan2(θ)),

where H is the initial height, g is the (positive) gravitational constant and u is the initial speed. Since we are looking for the maximum range we set y=0 (i.e. the projectile is on the ground). If we let L=u2/g, then

H+xtan(θ)−12Lx2(1+tan2(θ))=0

Differentiate both sides with respect to θ.

dxdθtan(θ)+xsec2(θ)−[1Lxdxdθ(1+tan2(θ))+12Lx2(2tan(θ)sec2(θ))]=0

Solving for dxdθ yields

dxdθ=xsec2(θ)[xLtan(θ)−1]tan(θ)−xL(1+tan2(θ))

This derivative is 0 when tan(θ)=Lx and hence this corresponds to a critical number θ for the range of the projectile. We should now show that the x value it corresponds to is a maximum, but I'll just assume that's the case. It pretty obvious in the setting of the problem. Finally, we replace tan(θ) with Lx in the second equation from the top and solve for x.

H+L−12Lx2−L2=0.

This leads immediately to x=L2+2LH−−−−−−−−√. The angle θ can now be found easily.


Related Questions

If a car stops suddenly, seat belts help stop the motion of the people in the car. Seat belts in cars are usually 47 mm wide.


A team of engineers is designing a car seat to hold a small child. They decide that the straps should be only 38 mm wide. Why do the straps in the car seat not need to be 47 mm wide?

A. A smaller person needs to accelerate less than a larger person.

B. Less force is needed to stop a person that has less mass.

C. A smaller person needs to accelerate more than a larger person.

D. More force is needed to stop a person that has less mass.

plase help

Answers

Answer:

B. Less force is needed to stop a person that has less mass.

Explanation:

You put a new battery into your MP3 player and listen to a song. What are the
energy transformations taking place in this system?
O A. Kinetic energy to electric energy to sound energy to potential
energy
B. Kinetic energy to potential energy to electric energy to sound
energy
C. Thermal energy to electric energy to kinetic energy to potential
energy
D. Chemical energy to electric energy to kinetic energy to sound
energy

Answers

Answer:

c

Explanation:because its the correct one

6. Estimate the line width from thermal Doppler broadening for the CaII K line at 393.3 nm for a star with a temperature of 3,000 K and a star with a temperature of 12,000 K. How does temperature affect line broadening

Answers

The line width is calculated as 121.6nm

Data;

Wave length = 393.3nmT1 = 3000kT2 = 12,000KRydberg's Formula

This is used to calculate the wavelength of an electron when it moves from one state to another.

For Lyman series, n = 1

The energy difference in the two state transitioning are

[tex]n_2[/tex] = ∞

The formula is given thus;

[tex]\frac{1}{\lambda}= R(1(n_1)^2 - \frac{1}{(n_1)^2}.Z^2\\[/tex]

R = Rydberg's constant

Z = atomic number

Since the excited electron dropped from the 1st state to the ground state, the finest line of Lyman series would be

[tex]\frac{1}{\lambda} = R(1(1)^2 - \frac{1}{2^2}).1^2\\z=1\\\lambda = \frac{4}{3} * 912A^o\\\lambda = 121.6nm[/tex]

The line width is calculated as 121.6nm

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what is the name of the scientist that discovered gravity?​

Answers

[tex] \huge\green{\overline{\underline{\rm{\purple{꧁⫷ᴀɴsᴡᴇʀ⫸꧂ }}}}} [/tex]

[tex] \large\green{\overline{\underline{\rm{\red{•••••••••••••••••••••••••}}}}} [/tex]

what is the name of the scientist that discovered gravity?

Isaac Newton

[tex] \large\green{\overline{\underline{\rm{\blue{•••••••••••••••••••••••••}}}}} [/tex]

#CarryOnLearning

#LibreAngMatuto

➡ GRAVITY

The scientist named Isaac Newton discovered the gravity. But before that Aristotle was discovered the gravity first but the calculations were poor and not enough for knowing what it is.

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What is the formula for the intensity of a spherical wave?

Answers

Answer:

When there is a point source used without directing the light or sound in a direction, the area of a sphere = 4πr 2 is used instead of the area of circle for calculating intensity. The minimum intensity of sound that a human can hear is 10 -12 Wm -2 and the maximum is 1 Wm -2.

Explanation:

(12 points, suggested time 25 minutes)
A block of mass me can be attached to a parachute of negligible mass and radius T, as shown in the two views
above. When falling, the parachute experiences an upward force of air resistance. This force increases as the speed
of the parachute increases. The falling block and parachute
speed up at first but eventually reach a constant speed
called terminal speed
(a) The dot below represents the block-parachute system when it has reached its terminal speed and is falling at
this constant speed. On the dot, draw and label the forces (not components) acting on the system. Represent each
force by a distinct arrow starting on, and pointing away from the dot.
Note: Draw the relative lengths of all vectors to reflect the relative magnitudes of all the forces.

Answers

Answer:

Explanation:

Please follow the directions here and draw out the answer yourself.

Draw two arrows of the same length. Both start on the dot but one points up and the other points down.

Label the up arrow as "Air resistance" and the down arrow as "Weight, Me*g". Make sure the two arrows have the same length and are directly opposite each other.

The free-response to the question based on the given diagram is:

Draw two arrows of the same length. Both start on the dot but one points up and the other points down.Label the up arrow as "Air resistance" and the down arrow as "Weight, Me*g". Make sure the two arrows have the same length and are directly opposite each other.

What is a Parachute?

This refers to the apparatus or equipment that is used to help a person to descend slowly from a high altitude.

Hence, given that a block of mass is attached to a parachute and while descending, it encounters air resistance, then to show the relative length of all vectors:

Two arrows of the same length needs to be drawn.One of them points in an upwards direction.The other points in the downwards direction.The arrow pointing upwards would be labeled as "Air Resistance", the other would be labeled as "Weight" and they are opposite each other.

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Odina walked down the hall at school from the cafeteria to the band room, a distance of 100.0m. A class of physics students
recorded and graphed her position every 2.0s, noting that she moved 2.6m every 2.0s. Odina was 25m from the band room
at 58s.
Please select the best answer from the choices provided
Т
F

Answers

Find distance she traveled:

100m -25m = 75m


58 seconds / 2 second intervals = 29

29 x 2.6m = 75.4 meters total.


if the distance wasn’t rounded the statement was False.


Answer: False

The answer of this question is t

Brainliest if correct Question 4 of 10
Which two changes would decrease the gravitational force between two
objects?
A. Increase the distance between the objects.
B. Decrease the mass of one of the objects.
C. Increase the mass of both objects.
D. Increase the mass of one of the objects.
O E. Decrease the distance between the objects
SUBMIT

Answers

Answer:

E is the answer of the question in my opinion

PLEASE HELP!! WILL MARK BRAINLEST!!! What are 3 types of waves?

Answers

Answer:

transverse waves, longitudinal waves, and surface waves.

How much force is required to accelerate a 800kg car by 15 m/s2

Answers

Answer:

force=12000

Explanation:

F=m*a aka force equals mass times acceleration so 800*15=12000

Answer:

12000 N

Explanation:

The equation for Force is:

[tex]Force=mass*acceleration[/tex]

We can plug in the given values into the equation:

[tex]Force=800kg*15m/s^2\\Force=12000N[/tex]

Earth what on its axis from what to what approximately every what

Could someone help me
What means what should I put in there

Answers

Answer:

Earth rotates on its axis from west to east approximately every 24 hours

Explanation:

hope this helps :)

1. What does the vertical axis represent on a position-time graph?
A. Speed of the object
B. Position of the object
C. Velocity of the object
D. Total time travelled by the object
2. What do you call a graph that is plotted in terms of the distance travelled by the
object and the time it took to cover that distance?
A. Speed-time graph
B. Position-time graph
C. Distance-time graph
D. Displacement-time graph
3. Which is TRUE about displacement?
A. How fast an object is moving
B. Change in position in a given time
C. Length of the entire path that an object travelled
D. Shortest distance between the object’s two positions
4. What does a horizontal line in the distance-time graph indicate?
A. No movement
B. Constant speed
C. Object is accelerating
D. Object is decelerating
5. When looking at a displacement-time graph, what variable should be plotted on the
y-axis and x-axis?
A. Y-axis: Time; X-axis: Distance
B. X-axis: Time; Y-axis: Distance
C. X-axis: Time; Y-axis: Displacement
D. Y-axis: Time; X-axis: Displacement
6. Which of the following illustrates acceleration?
A. Constant velocity
B. Changing direction
C. The direction does not change
D. The speed and direction remains the same
7. The following are correctly matched, EXCEPT
A. Speed: Scalar
B. Velocity: Vector
C. Distance: Scalar
D. Displacement: Scalar
What I Know
3 CO_Q3_Science 7_ Module 2
8. What does a line on a graph that is curving upwards mean in a distance-time graph?
A. The object is not moving.
B. The object has a constant speed.
C. The speed of the object is increasing.
D. The speed of the object is decreasing.
9. The following units can be used to mathematically express speed, EXCEPT
A. m
B. m/s
C. km/hr
D. miles/hr
10. Ethan is playing with his toy car. While watching him, you observed that the toy
car is accelerating. Which of the following graphs show that the toy car is
accelerating?
A B C D
11. Examine the given graph. What conclusion can you make from this graph?
A. The object is stationary.
B. The object is decelerating.
C. The object’s acceleration is increasing.
D. The object is moving at a constant speed.
For items 12-13, refer to the given figure below.
12. What does the part B of the displacement-time graph tell us about the object?
A. The object has a velocity of 2 m/s.
B. The object is not moving for 2 seconds.
C. The object travels 2 meters in 2 seconds.
D.The object travels 2 meters in 2 seconds backs to its starting position.
4 CO_Q3_Science 7_ Module 2
13. What conclusion can you make about the motion of the object after it travels from
point A to point C?
A. I and II only
B. II and III only
C. I and IV only
D. II, III, and IV only
14. Examine the graph below. Is it correct to say that the straight horizontal line on the
speed-time graph means that the object is not moving?
A. Yes, a horizontal line means that the object is at rest or stationary.
B. Yes, a straight line always means that an object is not moving at all.
C. No, a horizontal line indicates that the object has uniform acceleration.
D. No, a horizontal line indicates that the speed is not changing over time.
15. During their science class, Jessa was assigned to discuss about distance-time
graphs. In one of her graphs, Jessa shows a graph with a diagonal line that slopes
upward to the right. She explained that the graph means that an object is moving
at a constant speed. Do you think her explanation is correct?
A. No, the distance-time graph should show a horizontal straight line going to
the right.
B. No, a diagonal line that slopes upward to the right in a distance-time graph
means that the speed is increasing.
C. Yes, the motion of objects plotted in a distance-time graph has similar
interpretation if plotted in a speed-time graph.
D. Yes, a diagonal line that slopes upward to the right means that distance is
increasing constantly with time, thus an object is moving in a steady speed.

Answers

Answer:

1. Option B
2. Option C
3. Option D
4. Option C
5. Option C

Explanation:

Given the following questions:

Question one:
Your answer is option B, a position time graph is one of the most common graphs to use to describe the motion of objects. The vertical line of the position time graph is the line that would be the y axis in some math cases. This line represents the "position of the object" or option B.

Question Two:
Your answer is option C or a "distance-time graph." The vertical axis shows the distance travels, while the horizontal line shows the time the object spends in the air. Distance-time graphs are used to show the distance an object traveled, in a certain amount of time.

Question three:
Your answer is option D or "shortest distance between two positions." Displacements definition is purely moving something from its initial position. Displacement is also seen as length and distance, which is why the shortest distance between two positions would be considered as true when it comes to displacement.

Question four:
Horizontal line would be the x-axis on a normal coordinate plane, since this is a distance-time graph and the horizonal line represents time. The answer will be option C or "object is accelerating." Since a distance-time graph shows how far an object goes in a certain amount of time, the horizontal line shows how fast the object is moving while traveling that distance within that certain amount of time.

Question five:
Your answer is option C or "X-axis: Time; Y-axis: Displacement." Since we are talking about a displacement-time graph, Y-axis is the dependent variable, it is what's being measured, so that would be displacement. While x-axis is the independent variable, which is what is being tested, so the x-axis will be time.

Hope this helps.

You want to cross a river that is 30 m wide and flows to the East at 3.0 m/s . You can swim at a speed of 5.0 m/s (relative to the water). If you start from the South side of the river and want to go straight across, at what angle should you point yourself

Answers

Answer:

Approximately [tex]\text{N$37^{\circ}$W}[/tex] (approximately [tex]37^{\circ}[/tex] west of north.)

Explanation:

The velocity of the swimmer relative to the water is given to be [tex]v(\text{swimmer})= 5.0\; {\rm m\cdot s^{-1}}[/tex]. Decompose this velocity into two components:

parallel to the flow of the river: [tex]v_{\parallel}(\text{swimmer})[/tex];perpendicular to the flow of the river: [tex]v_{\perp}(\text{swimmer})[/tex].

Decompose the velocity of the current [tex]v(\text{current}) = 3.0\; {\rm m\cdot s^{-1}}[/tex] along the same set of directions.

parallel to the flow of the river: [tex]v_{\parallel}(\text{current}) = 3.0\; {\rm m\cdot s^{-1}}[/tex] to the east;perpendicular to the flow of the river: [tex]v_{\perp}(\text{current}) = 0\; {\rm m\cdot s^{-1}}[/tex] (Note that the current in the river flows along the river, not toward the banks of the river.)

The velocity of the swimmer relative to the bank would be the vector sum [tex](v(\text{swimmer}) + v(\text{current}))[/tex]. Decompose this vector sum in the same directions:

parallel to the flow of the river: [tex]v_{\parallel}(\text{swimmer}) + v_{\parallel}(\text{current})[/tex];perpendicular to the flow of the river: [tex]v_{\perp}(\text{swimmer}) + 0\; {\rm m\cdot s^{-1}} = v_{\perp}(\text{swimmer})[/tex].

Swimming straight across requires that the swimmer travel towards the banks but not along the banks. In other words, the velocity of the swimmer relative to the bank should be [tex]0[/tex] in the direction of the river: [tex]v_{\parallel}(\text{swimmer}) + v_{\parallel}(\text{current}) = 0[/tex].

Rearrange to obtain:

[tex]v_{\parallel}(\text{swimmer}) = -v_{\parallel}(\text{current})[/tex].

Thus, [tex]v_{\parallel}(\text{swimmer})[/tex] should be the exact opposite of [tex]v_{\parallel}(\text{current})[/tex].

Since [tex]v_{\parallel}(\text{current}) = 3.0\; {\rm m\cdot s^{-1}}[/tex] to the east, [tex]v_{\parallel}(\text{swimmer})\![/tex] should be [tex]3.0\; {\rm m\cdot s^{-1}\![/tex] to the west.

Refer to the diagram attached: [tex]v(\text{swimmer})[/tex] and its two components [tex]v_{\parallel}(\text{swimmer})[/tex] and [tex]v_{\perp}(\text{swimmer})[/tex] are the three sides of a right triangle, with[tex]v(\text{swimmer})= 5.0\; {\rm m\cdot s^{-1}}[/tex] as the hypotenuse.

Since the swimmer is travelling to the north, [tex]v_{\perp}(\text{swimmer})[/tex] would point northward.

The side [tex]v_{\parallel}(\text{swimmer})[/tex] would be opposite to the angle between the hypotenuse [tex]v(\text{swimmer})= 5.0\; {\rm m\cdot s^{-1}}[/tex] and north ([tex]v_{\perp}(\text{swimmer})[/tex],) Thus, the value of that angle would be:

[tex]\begin{aligned}& \arcsin\left(\frac{\text{opposite}}{\text{hypotenuse}}\right) \\ \\ =\; & \arcsin\left(\frac{3\; {\rm m\cdot s^{-1}}}{5\; {\rm m\cdot s^{-1}}}\right) \\ \approx \; & 37^{\circ}\end{aligned}[/tex].

Since [tex]v_{\parallel}(\text{swimmer})[/tex] points to the west, the direction of [tex]v(\text{swimmer})[/tex] would be approximately [tex]37^{\circ}[/tex] west of north, [tex]\text{N$37^{\circ}$W}[/tex].

If runner A is running at 7.50 m/s and runner B is running at 7.90 m/s, how long will it take runner B to catch runner A if runner A has a
55.0-m head start?

Answers

Answer:

t= 137.5 s

Explanation:

So if we are wanting to figure out how long it takes runner B to catch runner A. we must first set the slope of each runner equal to one another

Slopes:

Runner A:    y = 7.50x + 55

Runner B:    y = 7.90 x

sooooo

  7.50 x + 55 = 7.90 x

- 7.50 x          - 7.50 x

 55 = .40 x

55/.40 = .40 x / .40

x = 137.5 s

t= 137.5 s

7.50 * 137.5 + 55 =1086.25 m

7.90 * 137.5 =  1086.25 m

Runner B will catch Runner A after approximately 44.00 seconds.

To determine the time it takes for Runner B to catch Runner A, we need to consider their relative speeds and the initial distance between them.

Runner B is running faster than Runner A, so the distance between them will decrease over time. The relative speed of Runner B with respect to Runner A is the difference in their speeds:

Relative speed = Speed of Runner B - Speed of Runner A

Relative speed = 7.90 m/s - 7.50 m/s = 0.40 m/s.

Runner B needs to cover the initial distance (head start) of 55.0 meters between them. The time it takes for Runner B to catch up to Runner A can be calculated using the formula:

Time = Distance / Relative Speed.

Time = 55.0 m / 0.40 m/s = 137.5 seconds.

However, this time includes the time taken by Runner A to run the initial distance. To find the time taken by Runner B to catch Runner A after accounting for the head start, we subtract the initial time from the total time:

Time taken by Runner B = Total time - Time taken by Runner A.

Runner A's initial time = Distance / Speed = 55.0 m / 7.50 m/s = 7.3333 seconds.

Time taken by Runner B = 137.5 seconds - 7.3333 seconds = 130.1667 seconds.

Rounded to two decimal places, it takes Runner B approximately 130.17 seconds to catch up to Runner A.

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When a wire is heated, the current goes down from 0.3A to 0.26A. State how the resistance of the wire has changed

Answers

Hello there! :)

It's very wonderful to help you today!

Answer:

The resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.

Explanation:

The resistance of the wire goes up as the temperature goes up.

By Ohm's law, we have the relationship between the resistance of a conductor R, the current flowing through it, I, and the voltage across it, V,

[tex]V=R~x~I[/tex]

As described, the current through the wire decreases so, to maintain the same voltage, the resistance must increase when the wire is heated. Let's say R1 is the resistance before heating the wire and R2 is the resistance after,

[tex]V=R_{1} x~I_{1} =R_{2}~} x~I_{2}[/tex]

Let's solve for R2,

[tex]R_{2} =\frac{I_{1} }{I_{2} }~x~R_{1}[/tex]

In this case, I1 = 0.3A and I2 = 0.26A,

[tex]R_{2} =\frac{0.3A}{0.26A} ~x~R_{1} =1.15R_{1}[/tex]

Hence, the resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.

The default unit of rotational speed is 'radians per second' or 'rad/s'. If a someone sits at the edge of a 5m radius carousel and has tangential speed of 2 m/s, what is the rotational speed in rad/s?

A. 2.5
B. 3
C. 7
D. 10

Answers

The rotational speed of the person is 0.4 rad/s.

Rotational speed (rad/s)

The rotational speed of the person in radian per second is calculated as follows;

v = ωr

where;

v is linear speed in m/sr is radius in metersω is speed in rad/s

ω = v/r

ω = 2/5

ω = 0.4 rad/s

Thus, the rotational speed of the person is 0.4 rad/s.

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Which measurement has three significant figures? A 0.015m B 105m C 150m D 1.050

Answers

Answer:

B.105

Explanation:

Non-zero digits are always significant.

Zeros between significant digits are also significant.

Trailing zeros are significant only after a decimal point.

0.015 has 2 significant figures.

105 has 3 significant figures.

150 has 2 significant figures.

1.050 has 4 significant figures.

what are the steps to measure the density of a solid?

Answers

Answer:

The five steps for determining density can be found in simple form as follows, measure the mass of the container, measure the volume of the liquid(s), measure the combined mass of the liquid and the container, and then determine the mass of the liquid alone and divide the mass by the volume of it.

A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magnetic field at the center of this loop is...?

Answers

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

Current in the wire

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

Magnetic field at the center of the loop

The magnetic field at the center of the circular loop is calculated as follows;

[tex]B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T[/tex]

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tome pushed the ends of a large spring together. he had to hold on tight so the spring did not expand in his hands. what type of energy of the spring was increased?

Answers

if the bookstore sold 8 books for $66 at that rate how much was one book

(HELP PLEASE!!!)

A student is investigating the distribution of charge in a conductor. He attaches two unopened soda cans on their sides to two foam cups with tape. He sets the soda cans with the cups onto a tabletop so that they are touching one another. Then he moves a negatively charged balloon close to the left soda can The set up for the investigation is shown above.

How do the electrons move in the soda cans?

A. They move to the bottom in both cans.

B. They move from the left can to the right can

C. They move to the top of both cans.

D. They move from the right can to the left can.​

Answers

Answer:

Electrons repel one another - they will move "away" from the left side of the leftmost can- (the right can must become more negatively charged than the left can) -

B appears to be the best answer

The electrons move from the left soda can to the right soda can. The answer is (B).

When the negatively charged balloon is moved close to the left soda can, it will repel the negatively charged electrons in the soda can. This will cause the electrons to move away from the balloon and distribute themselves within the soda can.

Since the soda cans are in contact with each other, the excess electrons from the left soda can will be repelled by the negative charge on the balloon and will flow to the adjacent right soda can. The electrons will continue to move until there is no potential difference between the two cans, which means that they will stop flowing when both cans have the same amount of negative charge.

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What is the resistance of R1

Answers

Answer:

R1 is the first resistance level. It usually falls above the pivot point and below R2 but there are circumstances (see below) when the pivot point can be above R1. R1 is calculated as part of the Pivot Points calculations that traders use to determine where the market might reverse direction.

Explanation:

In the combo circuit diagrammed, R1 = 19.2 Ω, R2 = 20.7 Ω, and R3 = 25.8 Ω. Find the equivalent resistance of the circuit.

Answers

Answer:

Equivalent resistance: 13.589 Ω

Explanation:

R series = R1 + R2 + R3 ...

[tex]\frac{1}{R_{eq} } = \frac{1}{R1} +\frac{1}{R2} +\frac{1}{R3} ...[/tex]

Find the equivalent resistance of the right branch of the circuit:

[tex]R_{eq} = R_{2} +R_{3} \\R_{eq} = 20.7 + 25.8 = 46.5 ohms[/tex]

[tex]\frac{1}{R_{eq} } = \frac{1}{19.2} +\frac{1}{46.5}\\\\\frac{1}{R_{eq} } = 0.0735887097\\\\R_{eq} = 13.5890411[/tex]

What is the equivalent resistance of the following combination circuit? A 5.00 Ω resistance placed in series with a parallel combination of 9.00 Ω and 6.00 Ω ?

Answers

The equivalent resistance of the circuit is 8.6 Ω.

What is resistance?

Resistance can be defined as the opposition to current flow in an electric circuit. The S.I unit of resistance is ohms.

To calculate the equivalent resistance, we use the formula below.

Formula:

R' = R₁+(R₂//R₃)................ Equation 1

Where:

R' = Equivalent resistance of the circuit.

From the diagram,

Given:

R₁ = 5 .00 ΩR₂ = 9.00 ΩR₃ = 6.00 Ω

Substitute these values into equation 1

R' = 5+(9//6)R' = 5+[(9×6)/(9+6)]R' = 5+[54/15]R' = 5+3.6R' = 8.6 Ω

Hence, The equivalent resistance of the circuit is 8.6 Ω
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which religious group did not expand their membership by great numbers during the Second Great Awakening

Answers

Answer:

The Catholics.

Explanation:

see answer.

In the ballistic pendulum experiment, a bullet of mass 0.06 kg is fired
horizontally into a wooden block of mass 0.2 kg. The wooden block is
suspended from the ceiling by a long string. The collision is perfectly
inelastic and after impact the bullet and the block swing together until
the block is 0.12 m above its initial position. Find the velocity of the
bullet and the block just after impact. Round your answer to the
nearest tenth.

Answers

The velocity of the bullet and the block just after impact is mathematically given as

u=6.647m/s

v=1.534m/s

Velocity of the bullet and the block

Question Parameters:

In the ballistic pendulum experiment, a bullet of mass 0.06 kg is fired

horizontally into a wooden block of mass 0.2 kg.

the block is 0.12 m above its initial position.

Generally the equation for the conservation of energy  is mathematically given as

0.5(m+n)v^2=(m+n)gh

Therefore

v^2=2gh

[tex]v=\sqrt{2*9.8*0.12}[/tex]

v=1.534m/s

Hence

mu+m*0=(m+n)v

0.060*u=(0.060+0.2)*1.534

u=6.647m/s

For more information on mass

https://brainly.com/question/15959704

Brainliest if correct

Answers

Answer:

B 1,3, and 4

Explanation:

You've learned in this unit that you can change aspects of your personality by
A. taking personality tests until they tell you something has changed
B. working hard and being focused on the changes you want to make
C. waiting for your personality to change on its own
D. keeping a consistent routine and always acting in the same ways

Answers

Change aspect of personality can occur by working hard and being focused on the changes you want to make.

Personality change

A personality change can occur when an individual learns new habit. This new habit is developed or learnt through habitual responses that have stuck.

Thus, we can conclude that changing your habitual responses over time is one way to create personality change.

The only correct option is,  working hard and being focused on the changes you want to make.

Learn more about personality change here: https://brainly.com/question/13724909

Brainliest if correct

Answers

Answer:

A

Explanation:

hope it helps you make brainliest

What is the gravitational field strength of a 5 kg object that weighs 25 N?

Answers

Answer:

gravitation field strength: 5 N/kg

Explanation:

        Weight(N) = mass(kg) * gravitational field strength(N/kg)

Here given the mass: 5 kg and weight: 25 N

make sure the units are proper and make change only if different units visible. Like mass given in grams and covert it into kg. *must* and sometimes weight given in kilo-newton covert it into Newtons. *must*

using the formula:

5 * gravitational field strength = 25

gravitational field strength = 25/5

gravitational field strength = 5 N/kg

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