We can see from the calculations that the acceleration of the proton is 1.43 * 10^7 ms-2.
What is acceleration?Acceleration is the rate of change of velocity with time. We know that the magnetic force is obtained by;
F = qvB
q= 1.6 * 10^-19 C
v = 365 m/s
B = 4.10*10^-5 T
F = 1.6 * 10^-19 C * 365 m/s * 4.10*10^-5 T
F = 2.39 * 10^-20 N
Recall that the mass of the proton is 1.67 × 10−27 kg hence
a = F/m = 2.39 * 10^-20 N/1.67 × 10−27 kg = 1.43 * 10^7 ms-2
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Okay the question is calculate the current when 1200C of charge flows through a wire in 200 s.
Hi there!
Using the equation for current:
[tex]I = \frac{\Delta Q}{\Delta t}[/tex]
I = Current (A)
Q = Charge (C)
t = time (s)
Therefore, the current is equivalent to the amount of charge passing through a wire over a given time interval.
We can plug in the given values and solve.
[tex]I = \frac{1200}{200} = \boxed{6 A}[/tex]
Help me pls, I need it now
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7.) d
8.) b
9.) b
10.) a
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2. d
3. b
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Rick's car has a mass of 1000 kg and its brakes can apply 8000 N of force. If he is driving at 32 m/s and sees something in the road suddenly, how long will it take his car to come to a stop? Use the equation below to help you.
Answer:
Given:
m=1000kg
F=8000 N
u=32m/s
v=0m/s
Required:
T=?
Solution:
F=m × a
8000N = 1000kg × a
a = 8m/s^2
Since it's deceleration -8m/s^2
a= v - u / t
-8m/s^2 = 0 - 32m/s / T
T = 4 s
Hence the car takes 4sec to stop
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The stopping time of the car is equal to 4 seconds.
What is speed?Speed is defined as the ratio of the time distance travelled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance travelled by time. The unit of speed in miles per hour.
Given that,
m=1000kg
F=8000 N
u=32m/s
v=0m/s
The acceleration will be calculated by the formula below,
F = m × a
8000N = 1000kg × a
a = 8 m/s²
Since its deceleration -8m/s². The time taken is calculated by the formula,
a= v - u / t
-8= (0 - 32 ) / t
t = 32 / 8
t = 4 seconds
Therefore, the stopping time of the car is equal to 4 seconds.
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A 2-kg block is thrown upward from a point 20 m above the Earth's surface. At what height above Earth's surface will the gravitational potential energy of the Earth-block system have increased by 500 J?
Answer:
45.5 m
Explanation:
m = 2 kg, h = 20 m, E = 500 J, radius of earth = R, mass of earth = M
find the new height H
at h, the potential energy = -GMm/(R + h)
at H, the potential energy = -GMm/(R + H)
increase of the potential energy
= [-GMm/(R + H)] - [-GMm(R + h)]
= GMm[1/(R + h) - 1/(R + H)] = E
1/(R + h) - 1/(R + H) = E/(GMm)
(H - h)/[(R + H)(R + h)] = E/(GMm)
R + h ≈ R, R + H ≈ R
so (H - h)/R² = E/(GMm)
H - h = ER²/(GMm)
note GM/R² = g = 9.81 m/s²
so H - h = E/(mg)
H = h + E/(mg) = 20 + 500/(2*9.81) = 45.5 m
(06.02 MC)
What can a scientist use to observe very small things?
Answer:
microscopic light or Nano technology
