a rock of mass m is released from rest above an airless spherical planet of mass m and radius r. the rock is released from a height r above the surface of the planet (a distance 2r from the center of the planet). what is the correct expression for the final kinetic energy of the rock just before it hits the surface of the planet?

Answers

Answer 1

E1 = [tex]E_{f}[/tex]

[tex]\frac{-GMM}{2R}[/tex] = [tex]\frac{-GMM}{R}[/tex] + [tex]\frac{1}{2} mv^{2}[/tex]

= [tex]\frac{GMM}{2R}[/tex] = [tex]\frac{1}{2} mv^{2}[/tex]

V = [tex]\sqrt{GM/R[/tex]

By the law of conservation of energy, the initial potential energy, and the final kinetic energy are equal. When an object hits the ground, its kinetic energy is converted into heat and sound energy. Energy from motion is called kinetic energy. object in motion.

Both vertical and horizontal movement has kinetic energy. Kinetic energy depends on the mass and velocity of the object. The basic reason for the existence of halves in the kinetic energy formula actually comes from special relativity from a more complete version of the kinetic energy formula. Briefly, this ½mv2 kinetic energy formula can be viewed as an approximation of special relativity.

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Related Questions

A runner is initially going 5 m/s to the right when she slows down at to 2 m/s over 10
seconds.
a) What is her acceleration?
b) How far does she travel in these 10 seconds?

Answers

Answer:

acceleration =-0.3

distance =0.16m

Explanation:

the runner was initially moving with a velocity of 5mls and attained a final velocity of 2mls because it decelerated. therefore to find its acceleration you can go by the formula a=v-u÷t

the distance can be found by the formula v²=u²+2as

line spectra from all regions of the electromagnetic spectrum, including the paschen series of infrared lines for hydrogen, are used by astronomers to identify elements present in the atmospheres of stars. calculate the wavelength of the photon emitted whe

Answers

The wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.

From the Rydberg's formula;

1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex])

R = 1.097 ×[tex]10^{7} m^{-1}[/tex]

nfinal = 3

ninitial = 5

Calculating the wavelength of the photon by substituting values, in equation 1/λ = R (1/[tex]n^{2} _{final}[/tex] - 1/[tex]n^{2} _{initial}[/tex]) , we get:

1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex]   (1/[tex]3^{2}[/tex] - 1/[tex]5^{2}[/tex])

1/λ = 1.096776×[tex]10^{7} m^{-1}[/tex] (1/9 - 1/25)

λ = 1.282 × [tex]10^{-6}[/tex] m

λ = 1282 nm

Therefore, the wavelength of the photon emitted when the hydrogen atom undergoes a transition from n = 5 to n = 3 is 1282 nm.

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Compare and contrast oxygen-16 and
oxygen-17.

Answers

Answer:

oxygen 16 has 8 protons and 8 neutrons, oxygen 17 has 8 protons and 9 neutrons

Explanation:

isotope's number is equal to the sum of its protons and neutrons

Answer:Oxygen 16 is number 16 while oxygen 17 is number 17 and oxygen 16 is also oxygen like oxygen 17.

Explanation:  Common Knowledge in my brain....

Compare and contrast an active solar heating system with a radiator system

Answers

There are two types of solar system was there:

Active solar systemPassive solar system.

What is solar system?

One system that is energies with sunlight. In other words which convert the sun energy in other energy is called solar system. It made with silicon.

What is the difference between an active solar heating system with a radiator system?

As we mentions earlier there are two types of solar system was their,

Active solar system.Passive solar system.

Active solar system: This system made with silicon bar which excites by absorb the sunlight and excites by it. It can change energy between any energies and help others to grow more. It helps to make machines to make hot water and electricity and many more. It is not cost friendly. The costs for such custom systems range from $3,000 to $10,000 depending on the size of the space.

Passive solar system: This system is very much cost sufficient solar energy generator. This energy displace the extra things like electricity, natural gas, or other  systems. It so cost friendly that by installing big windows and tress it can hold energy in day and release energy at night. This is called the radiator system as it radiates energy at night.

According to the discussion, this is the main difference between the an active solar heating system with a radiator system.

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A golfer takes three strokes to putt a golf ball into a hole. On the first stroke, the ball moves 5.1 m due east. On the second, it moves 1.8 m at an angle 20° north of east. On the third, it moves 0.50 m due north. If the golfer had instead hit the ball directly into the hole on the first stroke, what would have been the magnitude (in m) and direction of the ball's displacement? Give the direction as a positive angle measured counterclockwise from due east.

Answers

The three strokes to put the golf ball into a hole is given. we have to find the overall displacement of the golf ball and its direction measured counterclockwise due east. So, we take due east as 0°, north as 90°, and so on.

For 1st stroke, the ball moves 5.1m due east means 5.1m at 0°.

The displacement along x- direction for 1st stroke = 5.1m × cos 0° = 5.1m, and y-displacement = 5.1m × sin 0° = 0m.

For 2nd stroke, the ball moves 1.8m at an angle 20° north of east.

Its x-displacement = 1.8m × cos (20°) = 1.691m, and y-displacement = 1.8m × sin (20°) = 0.6156m.

For third stroke, the ball moves 0.50m due north, means 0.50m by 90°.

Its x-displacement = 0.5m × cos (90°) = 0m, and y-displacement = 0.5m × sin(90°) = 0.5m.

The overall x- and y- displacements of the ball are:

x = 5.1 + 1.691 + 0 m = 6.791 m, and

y = 0 + 0.6156 + 0.5 m = 1.1156 m, respectively.

And its direction is θ = y/x = 1.1156 ÷ 6.791 = 0.164° due east.

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Pick the answer that correctly completes the sentence: as a sound wave approaches an observer the frequency will _____, the wavelength will____, and the speed of sound will______.A) decrease; increase; stay the same B) increase; increase; increase C) increase; decrease; stay the same D) decrease; decrease; increase

Answers

To find

Pick the answer correctly that fits the sentence.

Explanation

In a doppler effect, when a sound source apporaches a observer, its frequency increases. As wavelength is inversely proportional so the wavelength decreases. Speed of sound ina given medium is constant, so the speed of sound doesnot change

Thus,

as a sound wave approaches an observer the frequency will increase, the wavelength will decrease, and the speed of sound will stay the same.

Conclusion

The correct option is C) increase; decrease; stay the same.

three different-mass projectiles are launched at different angles of elevation from the top of a building. each particle has the same initial kinetic energy. which particle has the greatest kinetic energy just as it impacts with the ground?

Answers

The correct option is b. The one with the lowest mass.

An object's kinetic energy is determined by

k=1/2mv^2

where

m is the object's mass.

v is the object's speed.

The three missiles in this puzzle have varying masses but the same beginning kinetic energy.

The three projectiles will all have the same kinetic energy when they hit the ground because mechanical energy is conserved, assuming there is no air resistance (because the potential energy that they have lost is the same, since they have been launched from the same height, and they reach the same final altitude, the ground).

hence,

K1=k2=k3

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Arthur walks 3 km north, and then turns east and walks 4 km. What is distance traveled and his displacement?

Answers

The distance travelled by Arthur is 7 km and his displacement is 5 km.

What is the distance covered by Arthur?

The distance travelled by Arthur during the entire motion is determined by summing the entire path covered during the motion.

Distance = 3 km + 4 km

Distance = 7 km

The displacement of Arthur during the entire motion is obtained by calculating the length of the shortest path between the initial and final position.

d = √(a² + b)

where;

a is the northward motionb is the eastward motion

d = √(3² + 4²)

d = 5 km

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a navy blue car and a mint green cars drive on two different lanes of the same same very curved road. the radius of curvature of the path of the navy blue car, which has a mass of 1616 kg, is approximately 4/5 of that of the mint green car, which instead has a mass of 1818 kg. assume that neither car skids on the road. how do the static friction forces on the two cars compare, if the drivers are on the same street, both going at the local speed limit?

Answers

The friction force ratio between navy blue car and mint green car due to the centripetal force is 10/9.

We need to know about centripetal force to solve this problem. When an object moves in a circular motion, the object is experiencing centripetal force. The magnitude of centripetal force is

Fc = m . v²/R

where Fc is the centripetal force, m is mass, v is velocity and R is the radius.

The friction force is proportional to the centripetal force

From the question, we know that

mblue = 1616 kg

mgreen = 1818 kg

Rblue = 4/5 Rgreen

vblue = vgreen

Find the centripetal force ratio

Fcblue / Fcgreen = (mblue . vblue² / Rblue) / (mgreen . vgreen² / Rgreen)

Fcblue / Fcgreen = (1616 / 4/5 Rgreen ) / (1818 / Rgreen)

Fcblue / Fcgreen = 10 / 9

Hence, the tension in the cord is 32 newton.

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a 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 11.7 cm. find the initial speed of the bullet.

Answers

the initial speed of the bullet: 520.31 m/sec

using the conservation of linear momentum we write

 m1u1 +  m2 u2 = m1 v1  +  m2v2

where u1 and u2  are the initial velocities of masses m1 and m2\

where v1, and v2  are the final velocities of masses m1 and m2\

hence  (.007) (u1)  + 1.5(0) =  1.5(v2)  +  .007(200)

using the energy equation for the block alone we get

mgh  = 1/2 m (v2[tex])^2[/tex]

hence    9.8(.0117) =.5 (v2[tex])^2[/tex]

hence v2= 1.494 m/sec

substitute it in 1

we get,

(.007) (u1)  + 1.5(0) =  1.5(1.494 )  +  .007(200)

           u1 =initial speed of the  bullet= 520.31 m/sec

What is Speed?

The definition of speed can be given as a measure of the distance travelled by an object and the time needed to travel the distance. Simply put, it is a measure of how fast an object is moving, but it does not give direction. If we get direction by speed, it is called "velocity".

Speed ​​can be calculated in science. The speed formula is a formula derived from science and is used to calculate different speeds. The formula for speed is:

[tex]Speed = \frac{Distance}{Time}[/tex]

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Look at the diagram. Calculate the Rf value for sample 7. Give your answer to two decimal places.

Answers

The Rf value of sample 7 is 0.94.

What are Rf values?

Rf (retention factor) values are values that are used to identify compounds in thin-layer chromatography.

Rf values are obtained by taking the ratio of the distance traveled by the solvent (solvent front) and that traveled by the substance or unknown compound.

Rf = distance traveled by compound / distance traveled by the solvent

The Rf value of sample 7 is calculated below:

distance traveled by compound = 33 mm

distance traveled by the solvent = 35 mm

Rf value = 33 mm/ 35 mm

Rf value = 0.94

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A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision

Answers

The magnitude of their common velocity if they move together after collision is 12.9 m/s.

What is the final velocity after collision?

The final velocity after collision is calculated by applying the principle of conservation of linear momentum as shown below.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

where;

m₁ is the mass of the carm₂ is the mass of the pedestrianu₁ is the initial velocity of the caru₂ is the initial velocity of the pedestrianv is the their common velocity after collision

(20)(16) + (5)(0.5) = v(20 + 5)

322.5 = 25v

v = 322.5/25

v = 12.9 m/s

Thus, the car and the pedestrian moved together after the collision suggestion an inelastic collision.

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The complete question is below:

A car of mass 20kg moving with a velocity of 16m/s collide with a pedestrian moving at a velocity of 0.5m/s in the same direction calculate the magnitude of their common velocity if they move together after collision if the mass of the pedestrian is 5 kg.

If a car of mass 20 kg with a velocity of 16 m/s collides with a pedestrian, then the magnitude of common velocity, if they move after the collision of masses, is 12.9 m/s.

What is Collision?

Any situation in which two or more bodies quickly exert forces on one other is referred to be a collision. The most common usage of the word "collision" relates to instances where two or more objects collide violently, while the scientific usage of the word does not refer to the amount of force involved.

According to the question, the given values are :

Mass of the car, m = 20 kg

The velocity of the car, u₁ = 16 m/s

The velocity of the pedestrian, u₂ = 0.5 m/s.

m₁ u₁ + m₂ u₂ = v (m₁ + m₂)

(20) × (16) + (5) × (0.5) = v(20 + 5)

322.5 = 25 × v

v = 322.5/25

v = 12.9 m/s

Hence, the magnitude of common velocity is 12.9 m/s.

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The complete question is :

A car of mass 20 kg moving with a velocity of 16 m/s collides with a pedestrian moving at a velocity of 0.5 m/s in the same direction, calculate the magnitude of their common velocity if they move together after a collision if the mass of the pedestrian is 5 kg.

Two ice skaters stand facing each other at rest on a frozen pond. They push off against one another and the 49 kg skater acquires a speed of 2. 10 m/s. If the other skater acquires a speed of 3. 81 m/s, what is her mass in kilograms?

Answers

Her mass is approximately equal to 27 kilograms.

How do you prove that?

First of all, you need to understand that momentum is a conserved quantity and the solution to this problem involves elastic collision.

Momentum can be defined as p = mv where p is momentum, m is mass, and v is velocity. Just like energy, momentum is a physical quantity that is conserved in an isolated system. Momentum is conserved as a result of Newton's third law, which states that [tex]F_A=-F_B[/tex].

You are given that the ice skaters bounce off each other, meaning the collision is elastic. Remember that in an elastic collision, m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂ where

m₁ is the mass of the first body, m₂ is the mass of the second body,u₁ is the initial velocity of m₁,u₂ is the initial velocity of m₂,v₁ is the final velocity of m₁, andv₂ is the final velocity of m₂.

Suppose that m₁ = 49 kg, m₂ = x, u₁ and u₂ = 0 m/s, v₁ = 2.1 m/s, and v₂ = 3.81 m/s. Then the mass of the other ice skater is as follows:

49 · 0 + x · 0 = 49 · 2.1 + x · 3.81

0 = 102.9 + 3.81x

3.81x + 102.9 = 0

3.81x = -102.9

x ≈ -27

Since a mass value can't be negative, the absolute value of x is 27. Therefore, it's her actual mass in kilograms.

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Ida Haitarun is captain of the Varsity cross country team. During the after-school practice on Tuesday, he led the team on the following run from school to a nearby park. From the road, he ran at a 20 degree angle North of East for 8 miles. Determine how far east and how far north they are from where they started.

Answers

The displacement of the team is 2.74 miles due east and 7.52 miles due north from where they started.

What is the eastward displacement of the team?

The eastward displacement of Ida Haitarun and his team during the cross country race is calculated by forming a right triangle from the displacement of the team.

The angle of inclination of the displacement is calculated as follows;

θ = 90⁰ - 20⁰ = 70⁰ (above the horizontal)

The eastward displacement is the base of the triangle and it is calculated as follows;

cos θ = base / hypotenuse side

cos 70 = base / 8 miles

base = (8 miles) x (cos 70)

base = 2.74 miles

The northward displacement is calculated as follows;

sin θ = height / hypotenuse side

sin 70 = height / 8 miles

height = (8 miles) x (sin 70)

height = 7.52 miles

Thus, the team is 2.74 miles due east and 7.52 miles due north from where they started.

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a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart

Answers

Answer:

The acceleration of the cart:

a =  0.82 m/s²

Explanation:

 Given:

m = 2.0 kg

F = 4.0 N

μ = 0.12

g = 9.8 m/s²

___________

a - ?

Friction force:

Ff = μ·m·g

2 Newton's law:

m·a = F - Ff

The acceleration of the cart:

a = ( F - Ff) /m

a =  F/m - (μ·m·g) / m

a =  F/m - μ·g

a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82  m/s²

What conditions must be met in order for work to be done?
Check all that apply.
A. The applied force must make the object move.
B. At least part of the applied force must be in the same direction as
the movement of the object.
c. The output force must be greater than the input force.
D. The work must be greater than the momentum. you

Answers

Answer: B) force must be in the same direction as movement

Explanation:

During which time interval was the motion fastest? responses 1 h to 2 h 1 h to 2 h 2 h to 3 h 2 h to 3 h 3 h to 4 h 3 h to 4 h 4 h to 5 h

Answers

Answer: 1h

Explanation:

Now assume that a satellite of mass m is orbiting the earth at a distance r from the center of the earth with speed ve. A satellite of mass 2m is orbiting mars, also at a distance r from the center of mars, with a speed vm. What is the ratio tmte , the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution? the mass of the earth is me and the mass of mars is mm.

Answers

The ratio of the time it takes the satellite circling mars to make one revolution divided by the time it takes the satellite orbiting the earth to make one revolution is (Rm/Re)^3/2.(Me/Mm)^1/2

The orbital velocity of the satellite is given by,

V = √(GM/R)

Where,

V is orbital velocity,

G is gravitational constant,

M is the mass of planet,

R is the distance from the centre of the planet to the satellite.

According to given condition,

Ve = √(GMe/Re)

Ve it the orbital velocity of earth,

Me is mass of the earth,

Re is the radius of the earth.

Also,

Vm = √(GMm/Rm)

Vm it the orbital velocity of mars,

Mm is mass of the mars,

Rm is the radius of the mars.

We know, time period of revolution,

T = distance/velocity

Time period od revolution of satelite of earth,

Te = 2πRe/√(GMe/Re)

Time period of revolution of satelite of mars,

Tm = 2πRm/√(GMm/Rm)

Now, dividing the time time period of revolution of mars by time period of revolution of earth,

Te/Tm = [2πRe/√(GMe/Re)]/[2πRm/√(GMm/Rm)]

Te/Tm = (Rm/Re)^3/2.(Me/Mm)^1/2

So the final ratio of both the time periods is (Rm/Re)^3/2.(Me/Mm)^1/2.

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remember that when dealing with collisions in 2-dimensions, momentum is conserved in each dimension. two pucks are sliding on a frictionless tabletop. block a (mass 3.94 kg) is moving to the east ( x direction) at 2.50 m/s. block b (mass 4.73 kg) is moving to the north ( y direction) at 3.00 m/s. assume the system to be both block a and block b. (note: it could be useful to make a drawing of the situation.) what is the x-component of the total momentum of the system before the collision?

Answers

The x-component of the total momentum of the system before the collision is 9.850 kgm/s.

P = MV

3.94 x 2.50 m/s = 9.850kgm/s.

The definition of momentum is "mass in motion." Since every item has mass, if it is moving, it must have momentum because its mass is in motion. The amount of motion and the speed of the motion are the two factors that determine how much momentum an item possesses. An object's linear momentum sometimes referred to as translational momentum or simply momentum is the product of its mass and velocity.

It has both a magnitude and a direction, making it a vector quantity. If an item has mass m and velocity v, then it has momentum p. Momentum can be defined as the amount of motion. Quantity may be quantified in this case since an object has momentum if it is traveling and mass.

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A force of 30.ON is acted on a block of mass 15.0kg placed on a horizontal surface but the boxdoes not move. Calculate the magnitude of the frictional force between the surfaces when theapplied force is along the horizontal and when it makes angle 60° with the horizontal.

Answers

We will have the following:

1. In the first case, we will calculate the normal force:

[tex]N=(15\operatorname{kg}\cdot9.8m/s^2)\Rightarrow N=147N[/tex]

Then, we will have that the fricion coefficient will be:

[tex]\mu_f=\frac{30.0N}{147N}\Rightarrow\mu_f=\frac{10}{49}\Rightarrow\mu_f\approx0.20[/tex]

So the magnitude of the friccional force when applied horizontally will be of 30.0N.

2. And the magnitude when applied horizontal but the block is on an inclined surface of 60°, we will have that:

[tex]F=(10/49)(15.0\operatorname{kg}\cdot9.8m/s^2)\cos (60)\Rightarrow F=15N[/tex]

So, the friction force when the force is applied, is 15N.

HELP!

Mr. Mock sets up a demonstration on a moving bus. The device consists of a ball attached with a string to a magnet. He uses the magnet to hang the ball from the top of the school bus as the bus turns the corner at a constant speed. What will the ball do?

a
The ball swings backward.

b
The ball swings forward.

c
The ball swings to the outside of the curve.

d
The ball swings toward the inside of the curve

Answers

Answer:

The ball swings to the outside of the curve (assuming that the road is level.)

Explanation:

Assume that the air resistance on the ball in this question is negligible. The only forces acting on this ball will be tension that the string exerts on this ball and the weight of the ball.

Since the ball is in a centripetal motion, the net force on this ball will point directly to the center of the curve.

Refer to the diagram attached. The net force on this ball is the vector sum of weight and tension. Since weight points downwards, tension will need to point upwards to balance weight and toward the center of the curve, so that resultant force points horizontally toward the center of the curve.

The tension on the ball points along the string away from the ball (toward the ceiling.) For the tension that the string exerts on this ball to point toward the center of the curve and upwards, the ball will need to swing away from the center of the curve (as show in the diagram.)

Therefore, the ball will swing towards the outside of the curve (away from the center of the curve.)

Calculate the area of the plates of a 1 pF parallel plate capacitor in a vacuum if the separation of the plates is 0.1 mm. [ε0=8.85×10-12C2N-1m-2 ]Select one:6.2 m214.4 m211.3 m218.4 m2

Answers

Apply:

C = A e0 / d

Where:

C = capacitance = 1pf = 1 x10^-12 F

A = area

ε0 = 8.85×10^-12

1 pf = 1 x 10^-12 F

A = Cd / ε0 = 1 x 10^-12 ( 1 x 10^-4 ) / 8.85×10^-12 = 1.13 x10 ^-5 m^2

Does anyone have an answer for this? I need it before 1:22pm (CDT)

As a scientist, you are studying the physical properties of various substances. In your line of work, how will you effectively use physical properties to identify each substance?

Answers

Answer:

I would use physical properties to identify each substance because anything with the same physical properties as previous substances in the past.

Explanation:

pls mark brainliest with the crown. I need more to level-up

What are three modern inventions that could not have been invented without the earlier contributions of sir isaac newton?.

Answers

Answer:

there are the three basic

first law also called the law of inertia

the second one is the second law of motion and its equation is

F = ma

where m is the mass and a is the acceleration

its SI units are mass is kg and Acceleration is m/[tex]s^{2}[/tex]

the third law is called the action-reaction law

also the law of gravitation in which we survive our own earth-like plane due to the basic concept of the law of gravitation because the idea of gravitation is deal with this important law

F=GmMe/[tex]R^{2}[/tex]

The G value is 6.673*10^-11

m is the mass of an object

Me is the mass of the earth in our case we consider the object and the earth.

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I need help with question 7, I just need the answer you don’t have to explain.

Answers

[tex]\begin{gathered} a=5.703\text{ }\frac{m}{s^2} \\ T=3.891\text{N} \end{gathered}[/tex]

Explanation

Step 1

free body diagram

so, for m1

m1= 10 kg

so,

[tex]\begin{gathered} \sum ^{forces}_{\text{ y}}=T_1-mg=ma \\ T_1=m_1(a+g)\Rightarrow equation(1) \\ T_1=10(a+g) \end{gathered}[/tex]

and for m2

[tex]\begin{gathered} \sum ^{forces}_{\text{ x}}=m_2g\sin (37)-T_1=m_2a \\ \text{solve for T}_1 \\ T_1=m_2g\sin (37)-m_2a \\ \text{replace} \\ T_1=(3.6\text{ kg)(9.8 }\frac{m}{s^2})\sin 37-3.6a \\ T_1=21.23\text{ -}3.6a\Rightarrow eq(2) \end{gathered}[/tex]

Step 2

now, replace in equaiotn (1) and solve for a

[tex]\begin{gathered} T_1=m_1(a+g)\Rightarrow equation(1) \\ 21.23\text{ -}3.6a=10(a+g) \\ 21.23\text{ -}3.6a=10a+10g \\ -7.2a=10a-98.1 \\ -17.2a=-98.1 \\ a=-\frac{98.1}{-17.2} \\ a=5.703\text{ }\frac{m}{s^2} \end{gathered}[/tex]

finally, replace in equation (2) to find Tension

[tex]\begin{gathered} T_1=21.23\text{ -}3.6a \\ T_1=21.23\text{ -}3.6(5.703) \\ T_2=3.891\text{N} \end{gathered}[/tex]

I hope this helps you

a winter storm that blows cold wind at least 56 km/hr and has falling or blowing snow that reduces visibility to less than 400 m for at least three hours is classified as a(n) blank . multiple choice question.

Answers

Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.

What is Blizzards?A blizzard is a severe snowstorm that lasts for a long time—typically at least three or four hours—and is marked by strong sustained winds and low visibility. When snow is not falling but rather loose snow on the ground is lifted and blasted by strong winds, the weather is called a "ground blizzard." A blizzard, according to the National Weather Service, is a storm with heavy snowfall or snow that is blowing, winds that are greater than 35 mph (56 kph), and visibility that is less than 14 mile (0.4 km) for at least three hours. There is no snow falling during some blizzards, known as ground blizzards.

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If a tenth planet were to be discovered with a sidereal period of 125 years, what would be the radius or the orbit (distance from the Sun)? In your answer you need to have the number in the first blank and the correct abbreviated units in the second blank.

Answers

From the computation and the use of the Kepler's law, the period of the orbit is period of the orbit is 25 AU.

What is Kepler's law?

The term Kepler's law has to do with the relationship between the relationship between the period of the satellite and the radius of the orbit in which the satellite is found.

According to the Kepler's law, we know that the square of the period of the satellite is directly proportional to the cube of the radius of the orbit. Having said this, we need to find the radius of the orbit and we have been told from the question as we have it above that the period of the satellite that is under consideration is  125 years.

Now;

T^2 = r^3

Given that;

T = period

r =  radius of the orbit

Then;

r = T^2/3

r = (125)^2/3

r = 25 Au

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A ball is thrown upward with an initial velocity of 20ft/s.

a ) What is the acceleration of the ball on its way up?
b ) what is the velocity of the ball at the very top of its path?
c) what is the acceleration of the ball on its way down?

Answers

Answer: the acceleration is 63737737ey

the velpcoty is is 7-922=2929

the acceleration down is 99102>2929<92

Explanation: because when the ball goes up it has to come down due to gravity, physics, and your very kind and nice mother. I hope this helped you! i bet you will ace this assignment.

a spotlight on the ground is shining on a wall away. if a woman tall walks from the spotlight toward the building at a speed of how fast is the length of her shadow on the building decreasing when she is from the building?

Answers

His shadow is shortening at a rate of dy/dt = 0.6m/s at the time.

What is triangle total degrees?

The triangle's three angles add up to a total of 180 degrees

The individual is standing at point D and has his head at point E at the time indicated in the problem.

At that moment, his shadow is visible on the wall at y = BC.

The two right triangles ABC and ADE both contain similar triangles. The ratios on their respective sides in the similar triangles are equal:

AD/AB = DE/BC

8/12 = 2/y

y = 3

If we suppose that the man is x distance from the building, then the distance from the spotlight to the man is 12 x.

12-x/12 = 2/y

1-1/12x = 2 1/y

Let's take derivatives of both sides:

-1/12dx = -2 .1/y²dy

Divide both sides by dt as follows.

-1/12.dx/dt = 2/y²dy/dt

At the time specified:

dx/dy = 1.6m/s

y = 3

Let's connect them

- 1/2 (1.6) = -2.9 dy/dt

dy/dt = 1.6/12×9/2 = 0.6m/s.

At the time in question, this is the pace at which his shadow's length is shortening.

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The complete question is:

"A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed of 1.6 m/s, how fast is the length of his shadow on the building decreasing when he is 4 m from the building?"

What is the focal length of a concave lens that forms an image with a xi value of -10.0 cm when an object is 35.0 cm from the lens?

Answers

Answer:

1 / f = 1 / object + 1 / image = 1 / 35 - 1 / 10   thin lens equation

f = o * i / (o + i)

f = -10 * 35 / (-10 + 35) = -350 / 25 = -14 cm

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