A sector of a circle has a central angle of 60∘ . Find the area of the sector if the radius of the circle is 9 cm.

Answers

Answer 1

Step-by-step explanation:

area of a sector is theta ÷360 ×πr²

A Sector Of A Circle Has A Central Angle Of 60 . Find The Area Of The Sector If The Radius Of The Circle

Related Questions

A car used 15 gallons of gasoline when driven 315 miles. Based on this information, which expression should be used to determine the unit rate of miles per gallon of gasoline?

Answers

Given trhat a car used 15 gallons of gasoline to cover 315 miles.

The expression that will be used to determine the unit rate of miles per gallon of gasoline is:

[tex]\frac{315\text{ miles}}{15\text{ gallons}}[/tex]

ANSWER:

[tex]\frac{315\text{ miles}}{15\text{ gallons}}[/tex]

This is a non graded practice that I am doing. I don’t under these questions 5-11

Answers

7. The intersection of two intersecting lines is a point.

In the given image, we see that lines NQ and ML intersect at point P.

Therefore, the intersection of NQ and ML is P.

f(x) = -2x² + 2x
Find f(-8)

Answers

Answer:

f(-8)= -112

Step-by-step explanation:

-2(-8)^2 + 2(-8)

-2(-64) + 16

-128 + 16

= -112

hope this helped

have a good day :)

calculate the slope of a line passing through the given points (5,-2) and (5,-3)

Answers

Given the points (5,-2) and (5,-3), we can find the slope of the line that passes through them with the following formula:

[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{-3-(-2)}{5-5}=\frac{-1}{0} \end{gathered}[/tex]

since we have that the slope is not defined, the line that passes through the points (5,-2) and (5,-3) is the vertical line x=5

The cost of 5 gallons of ice cream has a varianceof 36 with a mean of 36 dollars during the summer.What is the probability that the samplean would differ from the true mean by more than 0.6 dollars if a sample of 107 5-gallon pails is randomly selected? Roundyour answer to four decimal places.

Answers

Given:

[tex]\begin{gathered} Variance=36 \\ mean=36 \end{gathered}[/tex]

To Determine: The samplean would differ from the true mean by more than 0.6 dollars

Solution

Please note that standard deviation is the square root of variance

[tex]\begin{gathered} SD=\sqrt{Variance} \\ SD=Standard-deviation \\ SD=\sqrt{36}=6 \end{gathered}[/tex][tex]\begin{gathered} S.E=\frac{SD}{\sqrt{n}} \\ S.E=Standard-Error \\ n=107 \\ S.E=\frac{6}{\sqrt{107}}=0.5800 \end{gathered}[/tex]

Please note that Z is the number of SE(standard error away from the mean. Therefore

[tex]\begin{gathered} Z=\frac{0.6}{0.5800} \\ Z=1.0345 \end{gathered}[/tex][tex]P(|Z|<1.0345)[/tex][tex]P(|Z|<1.0345)=1-P(Z<-1.0345)=1-0.1515=0.8485[/tex]

Hence the probability is 0.8485

Read the following scenario and develop a method for answering the question posed. Be sure to define all variables used, justify your thinking mathematically, and fully answer the questions posed in complete sentences. Orbital Toys sells two types of sets of magnetic spheres, silver, and brass. The store owner, Lucy Ball, pays $8 and $16 for each one set of silver magnetic spheres and brass magnetic spheres respectively. One set of silver magnetic spheres yields a profit of $5 while a set of brass magnetic spheres yields a profit of $7. Ms. Ball estimates that no more than 2000 sets of magnetic spheres will be sold every month and she does not plan to invest more than $20,000 in the inventory of these sets. How many sets of each type of magnetic spheres should be stocked in order to maximize her total monthly profit? What is her maximum monthly profit?

Answers

8 dlls for silver

16 dlls for brass

5 dlls profit silver

7 dlls profit spheres

Then the price is

8+5= 13 dlls for silver

16+7=23 dlls for brass

Let S and B be the amount of magnetic silver and brass sphers that are sold, respectively.

Then, Ms. Ball estimation is that

[tex]S+B\leq2000[/tex]

Also, she doesn't want to invest more than 20000, so

[tex]\begin{gathered} 8S+16B\leq20000 \\ S+2B\leq2500 \end{gathered}[/tex]

The objective function is

[tex]V=5S+7B[/tex]

Subjected to:

[tex]\begin{gathered} S+B\leq2000 \\ S+2B\leq2500 \\ S\ge0,\text{ B}\ge0 \end{gathered}[/tex]

GRAPH

The interection is at

[tex]\begin{gathered} S=2000-B \\ S=2500-2B \\ 2000-B=2500-2B \\ B=500 \\ S=2000-500 \\ S=1500 \end{gathered}[/tex]

So, the extremes must be at (0,1250), (1500,500), (2000,0) , (0,0).

So, if we replace the points

[tex]\begin{gathered} V(0,1250)=5(0)+7(1250)=8750 \\ V(1500,500)\text{ = 5(1500)+7(500)=}11000 \\ V(2000,0)=5(2000)+7(0)=10000 \end{gathered}[/tex]

So, the amount she will need to stock to maximize her profit is 1500 of silver and 500 of brass, and the maximum profit is going to be 11000 dlls.

Calculating a rate of change

What is the vertical change form Point A to Point B?


What is the horizontal change from Point A to Point B ?


What is the rate of change shown on the graph? Give the answer as a decimal rounded to the nearest tenth, if necessary?

Answers

Hello there. To solve this question, we'll have to remember some properties about rate of change.

Given the points A and B from a line, we want to determine the vertical change and the horizontal change between the points and then, using these values, determine the rate of change of the function (the line passing through them).

For this, we first find the coordinates of the points.

[tex]A=(2,1)\text{ and }B=(4,2)[/tex]

The vertical change is the difference between the y-coordinates of the points, hence

[tex]y(B)-y(A)=2-1=1[/tex]

The horizontal change is given by the difference between the x-coordinates of the points, therefore

[tex]x(B)-x(A)=4-2=2[/tex]

The rate of change of this function is, finally, given by the ratio between the vertical (rise) and horizontal (run) changes of the function:

[tex]\dfrac{1}{2}=0.5[/tex]

This is the rate of change of this function.

Triangle LMN is drawn with vertices at L(−2, 1), M(2, 1), N(−2, 3). Determine the image vertices of L′M′N′ if the preimage is rotated 90° clockwise. L′(1, 2), M′(1, −2), N′(3, 2) L′(−1, 2), M′(−1, −2), N′(−3, 2) L′(−1, −2), M′(−1, 2), N′(−3, −2) L′(2, −1), M′(−2, −1), N′(2, −3)

Answers

ANSWER

L'(1, 2), M'(1, -2), N'(3, 2)

EXPLANATION

The rule for rotating a point (x, y) 90° clockwise is,

[tex](x,y)\rightarrow(y,-x)[/tex]

So, the vertices of triangle LMN will be mapped to,

[tex]\begin{gathered} L(-2,1)\rightarrow L^{\prime}(1,2) \\ M(2,1)\rightarrow M^{\prime}(1,-2) \\ N(-2,3)\rightarrow N^{\prime}(3,2) \end{gathered}[/tex]

Hence, the image has vertices L'(1, 2), M'(1, -2), N'(3, 2).

Find the area round to two decimal places as needed

Answers

To find the area of an obtuse triangle you have to multiply the base of the triangle by the vertical height and divide the result by 2 following the formula:

[tex]A=\frac{b\cdot h}{2}[/tex]

The base of the triangle is b= 7 miles and the height is h= 8 miles, using these lengths calculate the area as follows:

[tex]\begin{gathered} A=\frac{7\cdot8}{2} \\ A=\frac{56}{2} \\ A=28mi^2 \end{gathered}[/tex]

The area of the triangle is 28 square miles.

hi help I've been trying to solve this for an hour and I just really need the correct answer please help

Answers

First we can se the points that each line passes, and those are:

(-1, 5) & (0, 2)

(-5, -2) & (0, -4)

From this, we calculate each function, that is:

*Line 1:

[tex]m_1=\frac{2-5}{0-(-1)}\Rightarrow m_1=-3[/tex]

And we calculate the first function:

[tex]y-2=-3(x-0)\Rightarrow y=-3x+2[/tex]

*Line 2:

[tex]m_2=\frac{-4-(-2)}{0-(-5)}\Rightarrow m_2=-\frac{2}{5}[/tex]

And we calculate the second function:

[tex]y+4=-\frac{2}{5}(x-0)\Rightarrow y=-\frac{2}{5}x-4[/tex]

So the system is:

Can you please help me out with a question

Answers

AS shown in the figure:

The measure of arc RT = 27

The measure of arc FN = 105

The measure of angle FUN will be as follows:

[tex]m\angle\text{FUN}=\frac{1}{2}(105+27)=\frac{1}{2}\cdot132=66[/tex]

So, the answer is option C. 66

the answer is C. yw!

which is the BEST first step in order to solve this equation15 + 2/3 a = -5a.subtract 15 from both sides b.subtract 2/3 feom both sides c.add 5 to both sides d.multiply by 3 on both sides

Answers

In order to solve this equation, we need to isolate the variable a in one side of the equation.

Since we have the number 15 in the same side of the variable, the best first step would be removing this number 15 from this side, and we do this by subtracting 15 from both sides.

Therefore the answer is a.

Real number between 0 and 6 will be picked according to the probability distribution shown in the figure. Regions under the curve are liable with A, B, C, and D. The area of each is shown in the table. Use the figure and table to answer the parts

Answers

Part A

The probability that a real number between 1 and 4 is picked

P=PB+PC

P=0.15+0.50

P=0.65

Part B

The probability that a real number between 2 and 6 is picked

P=PC+PD

P=0.50+0.30

P=0.80

Please tell me if these are correct if theyre not please help and tell me which ones are the right answers

Answers

Answer:

They're correct

Step-by-step explanation:

Reflects the given the coordinates points across the y - axis

Answers

Answer:

Explanation:

The reflection over the line y = x gives the following transformation of coordinates

[tex](x,y)\to(y,x)[/tex]

therefore, for our case the transformation gives

[tex]\begin{gathered} S(-2,5)\to S^{\prime}(5,-2) \\ T(-3,0)\to T^{\prime}(0,-3) \\ U(1,-1)\to U^{\prime}(-1,1)_{} \end{gathered}[/tex]

which are our answers!

The graphical representation of a point and its reflection about the line y =x is the following:

In a certain​ chemical, the ratio of zinc to copper is 4 to 11. A jar of the chemical contains 528 grams of copper. How many grams of zinc does it contain.

Answers

If the ratio of zinc to copper is 4 to 11. A jar of the chemical contains 528 grams of copper. Then 192 grams of zinc does it contain

What is Ratio?

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

Given that,

In a certain​ chemical, the ratio of zinc to copper is 4 to 11.

i.e 4:11 or 4 /11

If A jar of the chemical contains 528 grams of copper

We need to find how many grams of zinc does it contain.

Let us consider it as x.

Form a equation,

4/11=x/528

4×528=11x

2112=11x

Divide both sides by 11

192=x

Hence 192 grams of zinc does it contain.

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Cisco Enterprises in Ontario purchased the following in a single month all-inclusive of taxes:
16,000 units of network routers at $79.25 each

Answers

Answer:

1268000

Step-by-step explanation:

16000x79.25=1268000

Which information will prove a quadrilateral is a square?O All 4 sides are congruentO All 4 sides are congruent and all 4 angles are right anglesO All 4 angles are right anglesO Both pairs of opposite sides are parallel

Answers

Answer

All 4 sides are congruent and all 4 angles are right angles

Step-by-step explanation

In a square, all the four sides measure the same (they are congruent). And the four angles are right angles, that is, they measure 90°

Find the volume of a cone with a height of 8 m and a base diameter of 12 mUse the value 3.14 for it, and do not do any rounding.Be sure to include the correct unit in your answer.

Answers

The volume V of a cone with radius r and height h is:

[tex]V=\frac{1}{3}\pi r^{2}h[/tex]

And the radius is half the diameter. Since this cone has a diameter of 12 m, the radius is:

[tex]r=\frac{12m}{2}=6m[/tex]

And the height is 8m. Thus, the volume V is:

[tex]\begin{gathered} V=\frac{1}{3}\pi(6m)^28m \\ \\ V=\frac{\pi}{3}(36m^2)8m \\ \\ V=\frac{\pi}{3}(288)(m^2\cdot m) \\ \\ V=\pi\cdot\frac{288}{3}m^3 \\ \\ V=96\pi m^{3} \end{gathered}[/tex]

Now, using 3.14 for π, we obtain:

[tex]\begin{gathered} V=96\cdot3.14m^3 \\ \\ V=301.44m^{3} \end{gathered}[/tex]

Therefore, the volume of that cone is 301.44m³.

A city has a population of 230,000 people. Suppose that each year the population grows by 4.25%. What will the population be after 12 years?

Answers

Answer:

379,001.

Explanation:

The population of the city grows by 4.25%.

This is a constant factor and models an exponential function.

An exponential population function is of the form:

[tex]\begin{gathered} P(n)=P_0(1+r)^t \\ P_o=\text{Initial Population} \\ r\text{ = growth rate} \\ t\text{ =time in years} \end{gathered}[/tex]

From the given problem:

[tex]P_0=230,000,r=4.25\%=0.0425,t=12years[/tex]

This then gives us:

[tex]\begin{gathered} P(12)=230000(1+0.0425)^{12} \\ =230000(1.0425)^{12} \\ =379,001 \end{gathered}[/tex]

The population after 12 years will be approximately 379,001.

What is the slope: (-2, 1) (5,-2)

Answers

Answer:  slope = -3/7

Step-by-step explanation:

m(slope) = (y2-y1)/(x2-x1)

m = (-2+-1)/(5--2)

m = (-2-1)/5+2)

m = -3/7

Solve the inequality and graph the solution set.3 ≤ 4x + 1 < 9

Answers

Okay, here we have this:

Considering the provided inequality, we are going to solve it and graph the solution set, so we obtain the following:

3 ≤ 4x + 1 < 9

3 -1≤ 4x + 1 -1< 9-1

2 ≤ 4x < 8

2/4 ≤ 4x/4 < 8/4

1/2 ≤ x < 2

In interval notation the solution set will be: [1/2, 2)

And if we plot this solution interval we get:

Where the solution set will be the purple part.

Express the interval using inequality notation(1,6)

Answers

The interval (1, 6) contains all the real numbers between 1 and 6, not including any of the endpoints.

This can be written in inequality notation as:

x >1 AND x < 6

But there is a shorter way to write the interval by combining both inequalities:

1 < x < 6

114. If plane X averages 800 mph and plane Y averages 400 mph, how manyhours will plane X travel before it overtakes plane Y if plane Y has a 2 hourand 30 minute head start?a.1b. 2c. 5d. 72

Answers

To determine the time taken for the plane X to travel:

If plane X averages 800 mph and plane Y averages 400 mph

Distance column is found by multiplying the rate

by time.

The time taken for plane Y to travel = 2hr 30 minutes = 2.5hrs head start

Be sure to distribute the 400(t +2.5)for Plane Y,

and Plane X to distribute 800t

As they cover the same distance

[tex]\begin{gathered} Dis\tan ce\text{ is equal ,} \\ 800t=400(t+2.5) \\ 800t=400t+1000 \\ 800t-400t=1000 \\ 400t=1000 \\ t=\frac{1000}{400} \\ t=2\frac{1}{2}hr \end{gathered}[/tex]

Therefore the plane X will travel for 2 1/2 hours

Hence the correct answer is Option B

The cargo of the truck welghs no more than 2,800 pounds.Use w to represent the weight (in pounds) of the cargo.

Answers

We know that

• The truck weighs no more than 2,800 pounds.

This problem is about inequalities.

"no more" indicates an inequality sign, specifically, it shows that we should use "less than or equal to", because this sign indicates the same as the problem do.

Therefore, the expression of the truck weight is

[tex]w\leq2,800[/tex]

A construction crew is lengthening a road. Let y represent the total length of the road (in miles). Let x represent the number of days the crew has worked. Suppose that x and y are related by the equation y=53 + 2x. Answer the questions below. Note that a change can be increased or a decrease. For an increase, use a positive number. For a decrease, use a negative number. What was the road’s length when the crew started working?What is the change per day in the road’s length?

Answers

Given the equation:

[tex]y=53+2x[/tex]

Where y represents the total length of the road (in miles), and x represents the number of days the crew has worked.

(a) What was the road’s length when the crew started working?

When the crew started working we have x = 0. Then:

[tex]\begin{gathered} y=53+2\cdot0 \\ \therefore y=53\text{ miles} \end{gathered}[/tex]

The road's length is 53 miles.

(b) What is the change per day in the road’s length?

The change per day in the road's length is 2 miles/day.

hello I don't know if you can help me with this but I no am doing something wrong. because at the bottom its not spelling right

Answers

8. The difference of three and a number means x+3 or x-3 because in both equations you have three units plus or minus the number X.

10. '"4 times the sum of a number and three" means

[tex]4\cdot(x+3)=4x+12[/tex]

Letter D

Determine the a coordinates of the critical points/numbers for the function f(x)= x/x^2+5
○ x=0, x= -√5, and x = √5
○ x=0
○ No critical points
○ x = √5
○x= -√5 and x = √5

Answers

The critical points for the given function f(x) are -√5 and √5.

so option d is the correct answer.

What is the critical point?

A critical point is the part of the domain of a function where the derivative is either equal to zero or the function is not differentiable.

Differentiate the given function f(x)=x/(x²+5)

f'(x)=((x²+5)-x(2x))/(x²+5)²

Using the Quotient Rule for differentiation.

What is Quotient Rule?

A method for finding the derivative or differentiation of a function that is given as a ratio or division of two differentiable functions in calculus is known as the quotient rule.

We get f'(x)=5-x²/(x²+5)²

So the derivative is zero at -√5 and √5 and non differentiable at -√5

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A food safety guideline is that the mercury in fish should be below one part per million (ppm). listed below are the amounts of mercury found in tuna sushi sampled at different stores in a major city. construct a 98% confidence interval estimate of the mean amount of mercury in the population. does it appear that there’s too much mercury in tuna sushi?0.58 0.82 0.10 0.88 1.32 0.50 0.92

Answers

Answer:[tex]Confidence\text{ Interval= }0.413\text{ < }\mu<1.047[/tex]

Explanation:

The amounts of mercury found in tuna sushi sampled at different stores are:

0.58, 0.82, 0.10, 0.88, 1.32, 0.50, 0.92

Number of samples, N = 7

[tex]\begin{gathered} \text{The mean, }\mu\text{ = }\frac{0.58+0.82+0.10+0.88+1.32+0.50+0.92}{7} \\ \mu\text{ = }\frac{5.12}{7} \\ \mu\text{ =}0.73 \end{gathered}[/tex]

Standard deviation

[tex]\begin{gathered} \sigma\text{ = }\sqrt[]{\frac{\sum ^{}_{}{(x_1-\mu)^2}}{N}} \\ \sigma\text{ = }\sqrt[]{\frac{(0.58-0.73)^2+(0.82-0.73)^2+(0.10-0.73)^2+(0.88-0.73)^2+(1.32-0.73)^2+(0.50-0.73)^2+(0.92-0.73)^2}{7}} \\ \sigma\text{ =}\sqrt[]{\frac{0.9087}{7}} \\ \sigma\text{ =}\sqrt[]{0.1298} \\ \sigma\text{ = }0.36 \end{gathered}[/tex]

The confidence interval is given by the equation:

[tex]\begin{gathered} CI\text{ = }\mu\pm z\frac{\sigma}{\sqrt[]{N}} \\ CI=0.73\pm2.33(\frac{0.36}{\sqrt[]{7}}) \\ CI\text{ = }0.73\pm0.32 \\ CI\text{ = (0.73-0.317})\text{ to (0.73+0.317)} \\ CI\text{ = }0.413\text{ < }\mu<1.047 \end{gathered}[/tex]

15÷6%=
A. 1004
B. 100
C. 24
D. 24

Answers

none it would be 250
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