Answer:
The sea bed is 1125 m deep.
Explanation:
Speed
It's the rate of change of the distance (d) traveled by an object over time (t).
The speed can be calculated by the formula:
[tex]\displaystyle v=\frac{d}{t}[/tex]
It's known the speed of sound in water is v=1500 m/s. A sound wave is sent to the sea bed and bounces back to the ship 1.5 seconds later.
That is the time the wave takes to travel twice the distance from the ship to the sea bed, thus the required distance uses half of that time or t=1.5/2 = 0.75 seconds.
Solving the equation for d:
d = v.t
d = 1500 m/s * 0.75 s
d = 1125 m
The sea bed is 1125 m deep.
Can someone spell the word hi for me I’ll give you 30 points
Answer:
hi poop
Explanation:
"Hi"
its spelled with an H & an I :^
Your boss at the Cut-Rate Cuckoo Clock Company asks you whatwould happen to the frequency of the angular SHM of the balancewheel if it had the same density and the same coil spring (thus thesame torsion constant), but all the balance wheel dimensions weremade one-third as great to save material.
a)By what factor would the frequency change?
b)Would the frequency increase or decrease by the factor foundin part (a)?
c)By what factor would the torsion constant need to be changedto make the smaller balance wheel oscillate at the originalfrequency?
d)Would the torsion constant need to be increased or decreasedby the factor found in part (c)?
Answer:
a) the factor between the frequencies is f ’/ f₀ = 9
b) the frequency increases f ’= 9 f₀
c) So that the frequency is equal to the initial one k ’= k₀ / 81
d) the torque constant must decrease
Explanation:
This is a simple harmonic motion, like angular velocity
w = [tex]\sqrt{\frac{k}{I} }[/tex]
where k is the torsion constant and I the moment of inertia of the flywheel.
Angular velocity and frequency are related
w = 2π f
we substitute
[tex]f= \frac{1}{2\pi } \sqrt{\frac{k}{I} }[/tex] (1)
We will use the subscript o for the system without change
f = [tex]\frac{1}{2\pi }[/tex] [tex]\sqrt{\frac{k}{I_{o} } }[/tex]
In the problem they indicate that the torsion constant remains constant, therefore we must analyze the moment of inertia, in general the flywheels are circular discs,
I = ½ M R²
Let's find the change when reducing the radius r ’= r / 3
Let's use the density
ρ = m ’/ V’
m ’= ρ V’
disk volume is
V = π r² e
suppose that the thickness is small and does not change, substitute
m ’= ρ π[tex](\frac{r}{3}) ^{2}[/tex] e = 1/9 m
Moment of inertia
I ’= ½ m’ r’²
I ’=[tex]\frac{1}{2}[/tex] [tex]\frac{1}{9}[/tex] m (\frac{r}{3}) ^{2} = 1/81 (½ m r²)
I ’= 1/81 Io
we substitute in equation 1
f ’= [tex]\frac{1}{2\pi }[/tex] \sqrt{\frac{k}{I} }
f ’= \frac{1}{2\pi } \sqrt{\frac{81k}{Io} }
f ’= 9 f₀
Let's analyze the questions
a) the factor between the frequencies is
f ’/ f₀ = 9
b) the frequency increases
f ’= 9 f₀
c) So that the frequency is equal to the initial one
k ’= k₀ / 81
d) the torque constant must decrease
A 25 kg rock falls for 1.7 seconds. How many meters tall
was the building?
Description:
So if a 25 kg rock is falling 1.7 seconds.
2.7 + 1/2 9.8 m/s² 2.7 s)
= 35.72m²
Equations:
v = 0 m/s
a = 9.8 m/s²
t = 2.7
Answer: 35.72 m
Hope this helps.
23x45 =? come here yall;) carter,kelsee, and nico
23×45=1035
Explanation:
first you multiply 5 and 3 you would get 15 tou drop the 5 and bring the 1 on top of 2 then you multiply 5 by 2 you get 10 then add 1 you get 11. once your Don's you would get 115. once your done with that cross out the five and then multiply 4 by 3 wich equals 12 drop the 2 under five and then bring 1 on top of 2 and then multiply 4 by 2 wich equals 8 and then add one and you get 9.
Why pendulum made of invar are used in clock?
Beacuse it is an alloy that is made up of nickel and iron that has low coefficient of thermal expansion.So, the length of the pendulum remains unaffected during changes in temperature.
If the density of water is 1 gram/cm3, this means that the mass of 100 cm3of water should be
Answer:
100 g
Explanation:
Or 0.1 kilograms, just count
If the density of water is 1 g/cm³, the mass of 100cm³ of water should be 100g.
DENSITY:
The density of a substance is its mass in relation to its volume. According to this question, the density of water is 1 g/cm³. This means that for every 1g (mass) of water, there contains 1cm³ (volume) of solvent. Hence, for 100cm³ of water, there should be a mass of 100g of water considering the density of water.Learn more at: https://brainly.com/question/14940265?referrer=searchResults
What is the unit for work? watt joule newton meter
Answer:
Joule
Explanation:
Joule is the SI unit of work or energy.
Answer:
joule
Explanation:
edge2020
Tomas wants to paint his bedroom. He goes to the store and buys two cans of paint.
Which simple machine would make it easier for him to open the cans?
A a lever
B. a pulley
C. an inclined plane
D. a wheel and axle
Answer:
I think the answer is c
Explanation:
I had this problem once
The number of particles outside the nucleus in the neutral atom will always equal to…?
Answer:
2,8,8
Explanation:
im not sure really what you asking but is it this the shells
A kilogram is a unit of mass and when multiplied by meters per second
squared which are the units of acceleration, it yields a derived unit known as a
Answer:
it yields a derived unit known as Newton, which is the unit of Force.
Explanation:
The formula for force is given by Newton's Second Law, which states that whenever an unbalanced force is applied to a body, it produces an acceleration in the body in the direction of force.
[tex]F = ma\\[/tex]
where, F = Force
m = mass
a = acceleration
Now, we substitute the respective S.I units of each quantity in equation:
F = Newton (N)
m = kilogram (kg)
a = acceleration = m/s²
Therefore,
[tex]N = (kg)(m/s^2)[/tex]
So, it is clear from above expression that:
When kilogram is multiplied by meter per second squared, it yields a derived unit known as Newton, which is the unit of Force.
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Answer:
15 m/s
Explanation:
Given:
F = 0.7N m = 0.25g = 0.0025kg x = 40cm = 0.4m [tex]v_{0}[/tex] = 0
Since F = ma, a = F/m = 0.7N/0.0025kg = 280m/[tex]s^{2}[/tex]
Using the Big Five, [tex]v ^{2} = v_0^{2} + 2ax[/tex], [tex]v = \sqrt{0 + 2*280m/s^2*0.4m} = \sqrt{216} m/s= 15m/s[/tex]
We have that for the Question it can be said that the speed of the marshmallow as it leaves the pipe is most nearly
v=15m/s
From the question we are told
A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly
Generally the equation for the acceleration is mathematically given as
[tex]a=\frac{Force}{mass}\\\\a=\frac{F}{m}\\\\Therefore\\\\a=\frac{0.75}{0.0025}\\\\a=280m/s^2\\\\[/tex]
Using Newtons
V^2=u^2+2as
V^2=2(280)*0.4
v=15m/s
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What are used for manufacturing paper along with chemical
Answer:
Dry-strength additives, or dry-strengthening agents, are chemicals that improve paper strength normal conditions. These improve the paper's compression strength, bursting strength, tensile breaking strength, and delamination resistance. Typical chemicals used include cationic starch and polyacrylamide derivatives.
The Demon Drop ride at the amusement park falls freely for 1.8 s after
starting from rest.
What is its displacement the end of 1.8 s?
Answer:
Explanation:
a = -g = -9.80 m/s squared
d o = 0
v o = 0
t = 1.8s
unkown:d = ?
v = ?
An object is thrown into the air at 60m/s, straight up. What is its velocity at the highest point?
Explanation:
Whenever an object is at its highest point, the velocity and acceleration of the object is zero.
Please answer ASAP for 29 points
Answer:
Explanation:
The answer is B. He needs to count backwards. So if it’s 800,700,600, and 500, you might get the answer right.
a 0.3 kg arrow is fired from a bow with a kinetic energy of 82.0 J. what is its velocity?
Answer:
When the string of a bow and arrow is pulled from equilibrium, the elastic potential energy in the bow is converted to kinetic energy of the arrow when the string is released.
Kinetic energy of an arrow can be found by using the formula KE=(mv²)/450,240 where m = mass of the arrow in grains and v = velocity of the arrow in fps.
Two factors determine the amount of energy a bow can hold. Its draw weight is the amount of force required to draw the bow. A bow's draw weight increases the farther back you pull the string.
Does a stretched bow and arrow have energy?
An arrow held in a stretched bow also contains this stored energy. Specifically, the bow has elastic potential energy. When the bow is released, the arrow will move. ... When work is done on an object, the work may be converted into either kinetic or potential energy.
Explanation:
A cyclist travels at 7 m/s and has a mass of 75 kg. Calculate the kinetic energy of the
cyclist.
3,675 )
262.5
1,837.5)
525 )
Answer:
1837.5 JExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
From the question we have
[tex]k = \frac{1}{2} \times 75 \times {7}^{2} \\ = 37.5 \times 49 \\ = 1837.5[/tex]
We have the final answer as
1837.5 JHope this helps you
PLSS HELP ASAP
two trains are moving on parallel railways with the same direction. Width of first train is 200meters and
speed 36km/h, second - 400meters speed 108km/h. Find the time, when second train paasses first.
a) 40sec
b) 50sec
c) 60sec
d) 30sec
e) Osec
Answer:d) 30 sec
Explanation:
21. For this table of data, how should the y-axis be labeled (with units)?
force applied (N)
2.5
3.2
4.8
5.4
5.5
6.3
7.6
8.2
displacement (m)
10.75
13.76
20.64
23.22
23.65
27.09
32.00
35.26
O displacement
Om
O force applied
O force applied (N)
O displacement (m)
ON
Answer:
The y-axis would be labeled with displacement (m)
Explanation:
The displacement is dependent on the force applied.
Labels should have what you measure and how your units of measure.
The x-axis would be labeleed with force applied (N)
The y-axis would be labeled with displacement (m)
How much work is done when an 8 N force moves a block 7m ?
Answer:
W = 56J
Explanation:
in physics, Work is equal to F*s
then
W = 8N*7m
W = 56J
[Please help :^)]
Hello! I have a kinetic and potential energy project due soon, and I need to write a paragraph about that stuff, but I’m not really sure how to write the paragraph. If you can, please write a paragraph that I can rephrase and use. Thank you!!
Answer:
the potentail of kinetic and potential energy
Explanation:
first explain the concept of kinetic energy (what it is and what its used for) and give examples (cars, a basketball thrown across a hall, and airplane), and do the same with potential energy (the energy an object stores, example: a streched rubber band)
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Answer:
The tangential velocity of a rotating object is:
v = r*w
where r is the radius, and w is the angular velocity.
w = 2*pi*f
where f is the frequency.
We know that the record plater does 11 revolutions in 20 seconds, then it does:
11 rev/20s = 0.55 rev/s = f
then we have:
w = 2*pi*0.55 s^-1 = 2*3.14*0.55 s^-1 = 3.454 s^-1
The radius of a record player is really variable, it is around 10 inches, so i will use r = 10in, which is the rotating part of the record player.
then the tangential velocity is:
v = 10in*3.454 s^-1 = 34.54 in/s
In which direction does the sun appear to move across the sky
Answer:east
Explanation:Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.
Answer:
it rises east and moves west through out the day and sets west
How can you warm up for baseball?
ANYONE HELP ME PLEASE!
kinetic energy and potential energy are often considered to be forms of mechanical energy. list three other forms of energy and state a source for each.
Answer:
Kinetic energy is the energy in moving objects or mass. Examples include mechanical energy , electrical energy etc.
12. A rocket, initially at rest on the ground, accelerates vertically. It accelerates uniformly until it
reaches a speed of 900 m/s after 30 s. After this period of uniform acceleration, the rocket
engine cuts out. During the next 90 s, the upward speed of the rocket decreases uniformly to
zero.
speed
m/s
times
plot a speed-time graph for the rocket for the first 120 s of it's flight
Answer:
We kindly invite you to read carefully the explanation and check the image attached below.
Explanation:
According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:
[tex]v_{f} = v_{o}+a\cdot (t-t_{o})[/tex] (1)
Where:
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
[tex]v_{f}[/tex] - Final velocity, measured in meters per second.
[tex]a[/tex] - Acceleration, measured in meters per square second.
[tex]t_{o}[/tex] - Initial time, measured in seconds.
[tex]t[/tex] - Final time, measured in seconds.
Now we obtain the kinematic equations for thrust and free fall stages:
Thrust ([tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 30\,\frac{m}{s^{2}}[/tex], [tex]t_{o} = 0\,s[/tex], [tex]0\,s\le t< 30\,s[/tex])
[tex]v = 30\cdot t[/tex] (2)
Free fall ([tex]v_{o} = 900\,\frac{m}{s}[/tex], [tex]a = -9.807\,\frac{m}{s}[/tex], [tex]t_{o} = 30\,s[/tex], [tex]30\,s \le t \le 120\,s[/tex])
[tex]v = 900-9.81\cdot (t-30)[/tex] (3)
Now we created the graph speed-time, which can be seen below.
4. What does the law of gravity state ?
Answer:
every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Explanation:
Answer: Newton's law of gravitation, states that any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them
Explanation: More of a simple answer is a law stating that any two masses attract each other with a force equal to a constant (called the gravitational constant) multiplied by the product of the two masses and divided by the square of the distance between them.
wo ships, one 200200 metres in length and the other 100100 metres in length, travel at constant but different speeds. When travelling in opposite directions, it takes 1010 seconds for them to completely pass each other. When travelling in the same direction, it takes 2525 seconds for them to completely pass each other. The speed of the faster ship, in metres per second, is
Answer:
The speed of the faster ship is 22.5 m/s
Explanation:
The length of the ships are;
Ship 1 = 200 m
Ship 2 = 100 m
The time it takes for the ships to completely cross each other when travelling in opposite directions = 10 seconds
The time it takes both ships to cross each other when travelling in the same direction = 25 seconds
Let x represent the speed of the first ship, ship 1, and y represent the speed of the second ship, ship, 2, we have;
(x + y) × 10 = 200 + 100 = 300
10·x + 10·y = 300...(1)
(x - y) × 20 = 200 + 100 = 300
20·x - 20·y = 300...(2)
Multiply equation (1) by 2, to get;
(x + y) × 10 × 2 = 300 × 2
20·x + 20·y = 600...(3)
Adding equation (1) to equation (3) gives;
20·x + 20·y + 20·x - 20·y = 600 + 300
40·x = 900
x = 900/40 = 22.5
x = 22.5
The speed of the first ship, ship 1 = x = 22.5 m/s
From equation (1), we have;
10·x + 10·y = 300
y = (300 - 10·x)/10 = (300 - 10×22.5)/10 = 7.5
y = 7.5
The speed of the second ship, ship 2 = y = 7.5 m/s
Therefore, the faster ship is ship 1 with a speed of 22.5 m/s
an electric fire is connected to a 240V supply and transfers energy at a rate of 1.0kW
how much energy passes through the fire on 1.0 h?
A) 42C
B) 250C
C) 1.5 × 10⁴C
D) 2.4 × 10⁵C
I will mark brainliest if answer is correct!
Answer:
(c) 1.5 x 10^4 C
Explanation:
we have,
P=1kW=1000w
V=240V
therefore,
P=V *I
1000=240*I
I=1000/240
I=25/6A
now,we know that
I =Q/T
Q=IT
Q=25/6*60*60. [since time =1hour i.e 60*60sec]
Q=15000C
Q=1.5 x 10^4C
The required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
Given data:
The voltage supply of the electric fire is, V' = 240 V.
The rate of energy transfer is, E' = 1.0 kW = 1000 W.
The time interval is, t = 1 h = 60 × 60 = 3600 s.
In this problem, the energy passes through the fire is nothing but the electric charges. For that we need to calculate the value of charge. So, first calculate the current flow as,
E' = V × I
Solving as,
1000 = 240 × I
I = 1000/240
I = 4.167 A
Now, the energy passes through the fire is obtained as,
Q = I × t
Q = 4.167 × 3600
[tex]Q = 1.5 \times 10^{4} \;\rm C[/tex]
Thus, we can conclude that the required amount of energy passes through the fire is of [tex]1.5 \times 10^{4} \;\rm C[/tex]. Hence, option (C) is correct.
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A 55 kg boy running at 2.0 m/s jumps onto a 2.0 kg skateboard. Calculate the
final velocity of the boy and the skateboard.
Answer:
The velocity of the boy and the skateboard is 24
