A soccer ball is kicked upward from a height of 6 ft with an initial velocity of 96 ft/s. How high will it go? Use -32 ft/s? forthe acceleration caused by gravity. Ignore air resistance.

At an amusement park there is a ride in which cylindrically shaped chambers spin around a central axis and the radius of a chamber            r= 0.387 m

Given

  Mass of the person m = 70.2 kg

  speed v = 3.09 m/s

  Force F = 560N

-------------------------------------------

  We have the formula for the force is given by

           F = ( mv2) /r

 The radius of the chamber is given b y

          r = ( mv2) /F

           =  ( ( 70.2 kg)(3.09 m/)2) /(560N)

         r=0.387 m

A circle's or a sphere's radius is the distance along a line connecting its centre and perimeter. From any point on the circle's or sphere's circumference to the centre, the radius' length is constant. Its length is halved by its diameter. The radius is a line segment connecting the centre of a circle or sphere to its perimeter or boundary in geometry.You'll require more effort as you reduce the radius because you're dividing by a lower force.

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We will have that the power will be:

So, the power was 220 Watts.

If we are to write 3500 in units with the appropriate prefixes, this would be 3.5kg.

This refers to the metric system that is used and accepted internationally and is used as a standard for the measurement of items

Hence, when it comes to the use of SI Units, the name of the unit with the prefixes deka, hecto, and kilo are used, meaning, respectively, 10, 100, and 1000.

With this in mind, 1000 units would make one kilo and if we are to write this mathematically this would be 3500 divided by 1000 which is 3500/100, and which would be 3,5.

Therefore, the correct answer is 3.5kg.

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Answer:

3*10^3 g or 0.3*10^4 g

Explanation:

Answer:

I rephrased your question:

Two objects with equal masses are in motion. which object will have more kinetic energy?

A) the object with the greater speed

B) the object with the greater density  

C) the object with the greater acceleration

D) the object with the greater acceleration

E) the object with the greater volume

F) the object with the greater volume

Explanation:

Kinetic Energy is equal to (1/2)mv^2, where m is the mass and v is the velocity.

-----

A) the object with the greater speed   YES

B) the object with the greater density  NO

C) the object with the greater density  NO

D) the object with the greater acceleration MAYBE.  Acceleration means energy is being added, so it depends on how much and the masses of each object.

E) the object with the greater volume  NO

Answer:

Explanation: Two objects with equal masses are in motion. Which object will have more kinetic energy?

Responses

the object with the greater density

the object with the greater volume

the object with the greater acceleration

the object with the greater speed

Answer: The object with the greater speed

A chemical element with the symbol Be and atomic number 4 is known as beryllium. Beryllium is a solid at room temperature and is categorized as an alkaline earth metal. The molar mass of beryllium (atomic number 4) is 9.012 g/mol. Accordingly, if all 6.22x1023 Beryllium atoms were put together in a mole, they would weigh 9.012g on a triple beam balance.

The atomic mass unit serves as the unit of measurement for mass (amu). A mass unit of an atom is 1.66 x 10-24 gram. The mass of one nucleon, which can be either a single proton or neutron, is roughly equal to one unified atomic mass unit, which is numerically equivalent to 1 g/mol.

In the aircraft industry in particular, beryllium is employed in gears and cogs. A silvery-white metal is beryllium. It has a low density and is relatively soft. Gyroscopes, springs, electrical contacts, spot-welding electrodes, and non-sparking tools all use beryllium in alloys with copper or nickel.

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The conclusion reached by the student who is most warranted is that the comet originates between the Sun and the asteroid belt.

Can humans survive on an aster?

The magnetic field and atmosphere that protect humans on Earth from harm are absent on asteroids. One approach to shield yourself from dangerous radiation is to live inside an asteroid. It is expected that humans would be sufficiently protected from radiation by excavating 100 meters beneath an asteroid.

How likely is it that an asteroid will strike Earth?

While space rocks of this size are most likely to reach Earth only about once every hundred million years, NEOs that are 50 to 100 meters (164 to 328 feet) broad have the potential to strike much more frequently—roughly every thousand years.

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Comets orbit the Sun in incredibly eccentric paths. They move in close proximity to the Sun from the outer solar system to the inner solar system via their orbits. Comets may have carried water and other materials to Earth through crashes early in the planet's history.

As the comet approaches the Sun, the outer ice layers melt and create a luminous coma, which causes comet tails to develop. This gas and dust are pushed into a long tail by particles streaming from the Sun. Always facing away from the Sun is the tail. The coma appears vivid because it reflects sunlight . Comets only briefly appear when they are close to the Sun. As they move, they appear to vanish.

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The value of electric field is 2.247 V/m. Yes, the observed value and calculated values of electric field match.

The electric field will be calculated using the formula -

E = kq/r². In this formula, E stands for electric field, k represents constant of proportionality, q is the charge of electron and r is the distance. As per the known fact, the value of k is 8.89×10⁹ N m²/C² and value of q is 1.6×[tex] {10}^{ - 19} [/tex] C.

Keep the values in formula for calculation of electric field.

E = (8.89×10⁹ × 1.6×[tex] {10}^{ - 19} [/tex])/2²

Taking square in denominator

E = (8.89×10⁹ × 1.6×[tex] {10}^{ - 19} [/tex])/4

Performing multiplication and division

E = 2.247 V/m

Thus, the observed and calculated electric field is 2.247 V/m, which is equal in both the cases.

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The complete question is attached in the diagram.

a)The total resistance of the rod R = 2.1 * 10^(3)Ω

b) current Density when voltage ΔV is applied between two ends is J(x) = [tex]=\frac{12\sigma_o\Delta V}{L}[/tex]

c) Steady-state electric field is E(x) = [tex]\frac{12\Delta V}{L^3} x^2\hat{i}[/tex]

a) Consider a small slice of the rod of thickness dx situated at a distance x from the center of the rod.

L = length of rod = 2cm, d= diameter = 0.5cm,  

Given [tex]\sigma(x)=\sigma_oL^2/x^2[/tex]     where σ is the rod's conductivity.

[tex]\sigma_o = 4 * 10^{-2}(\Omega.m)^{-1}[/tex]        (given)

The resistance dR of this small section of the rod is

dR=[tex]\frac{\rho_rdx}{A}=\frac{dx}{\sigma_rA} = \frac{4x^{2} dx}{\sigma_o L^2\pi d^2}[/tex]

The total resistance of the rod can be found by the integral of these smalls sections over the whole rod

[tex]R = \int\limits^{L/2}_{-L/2} \, dR = \int\limits^{L/2}_{-L/2} \,\frac{4x^2dx}{\sigma_oL^2\pi d^2}=\frac{4x^3}{3\sigma_oL^2\pi d^2} |_{-L/2}^{L/2} = \frac{L}{3\sigma_o\pi d^2}[/tex]

⇒R = (2*10^(-2)) / (3 * 4 * 10 ^(-2)* π * 0.5 * 10^(-2))

⇒R = 2.1 * 10^(3) Ω

Thus the total resistance of the rod R = 2.1 * 10^(3) Ω

b)The current density when voltage ΔV is applied between two ends is given by

J(x) [tex]=\frac{I}{A}=\frac{4\Delta V}{R\pi d^2} =\frac{12\sigma_o\Delta V}{L}[/tex]

c) the steady-state electric field is  

[tex]E(x) = \frac{J(x)}{\sigma} =\frac{12\sigma_o \Delta V / L}{\sigma_o L^2 / x^2} \hat{i} = \frac{12\Delta V}{L^3} x^2\hat{i}[/tex]

The question is incomplete. The full question is probably " A cylindrical glass rod is heated with a torch until it conducts enough current to cause a light bulb to glow. The rod has a length of L=2.0cm, and a diameter of d= 0.5cm, and its ends, plated with the material of infinite conductivity, are connected to the rest of the circuit. When red hot, the rod’s conductivity varies with position x measured from the center of the rod as [tex]\sigma(x)=\sigma_oL^2/x^2[/tex] with [tex]\sigma_o = 4 * 10^{-2}(\Omega.m)^{-1}[/tex]  a)What is the resistance of the glass rod?  Express your answer both symbolically and as a value in ohms. b)When a voltage ΔV is applied between the two ends, what is the current density J(x)?  c)What is the steady-state electric field E(x)? "

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The magnitude of the least acceleration the monkey must have if it is to lift the package off the ground: is 9.8 m/[tex]s^2[/tex]

From free body diagram,

The minimum acceleration of the monkey of mass (m) to lift the package off the ground is

[tex]m_{1}a_{min} = m_2g -m_1g\\a_{min} = \frac{m_2 - m_1}{m_1} g \\a_{min} = \frac{28 - 14}{14} 9.8 m/s^2 \\ \\a_{min} = 9.8 m/s^2 \\\\\\[/tex]

Mass is the amount of matter in a physical body. It  also measures the body's inertia, the resistance to acceleration when a net force is applied. The mass of an object also determines  its gravitational force on other objects. The basic SI  unit of mass is the kilogram. Mass is best understood as the amount of matter  in any object or body. Everything we see around us has mass. For example, a table, a chair, a bed, a football, a glass, and even air have mass.

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Overdriving is driving at a speed making the stopping distance longer than the distance illuminated by headlights.

Typically, one can utilize their headlights to schedule stops in dimly lit or low visibility locations. Typically, one can measure their stopping distance using the visible light cone in the headlights. Exceeding the stopping distance that the headlights highlight is overdriving. Thus, driving too fast and leaving little room to stop in an emergency is known as overdriving the headlights.

When the lights are far enough ahead of a person to illuminate the road, one should often stop so that they can see any approaching impediments. When one is traveling at a rate of speed that prevents them from stopping in that lit region, that rate of speed is taken into account.

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At the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

Let the mass on earth be m.

As we know:

Now, calculate as follows:

Therefore, at the summit of the mountain, the mass is 60.18 kg, the weight is 600 N, and the mass is unaltered.

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​

The object took 15.3 seconds to reach the ground when released.Then the height of the object just prior to being released will be 1147 m.

Gravity, g of is a downward force acting on a body which is moving or at rest at positioned at a height h from the surface.

Gravity is the downward acceleration of a moving body and it have value equal to 9.8 m/s². If the time taken to hit the ground when released from a height is t, then thee equation connecting this time, height h and g is written as follows;

h = 1/2 gt².

Hence, the height of the object prior to the point of releasing is calculated as follows:

h = 1/2 9.8 m/s² × (15.3 s )²

  = 1147 m.

Therefore, height of the object just prior to being released will be 1147 m.

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Answer:

Explanation:

Given:

V₁ = 20 m/s

ΔS = 200 m

V₂ = 15 m/s

___________

S - ?

Car motion equation:

X₁ = V₁*t = 25*t

X₂ = ΔS  + V₂*t = 200 + 15*t

Since the second car overtook the first, then:

X₁ = X₂

25*t = 200 + 15*t

5*t = 200

t = 200 / 5 = 40 с

Distance:

S = ΔS + V₂*t = 200 + 15*40 = 200 + 600 = 800 m

Correct answer:

A) 800 m

Answer:

It takes 0.47 seconds for the OJ to reach the ground.

Explanation:

d = vi*t + (1/2)at^2

(-1.1) = (0)t + (1/2)(-9.8)t^2

-1.1 = -4.9t^2

0.22445 = t^2

0.47s = t

The average force is  F = 2722.5N

This law of interaction states that when one body exerts a force on a second body, the second body exerts an equal and opposite force on the first body. This is the law of action and reaction, which helps explain why you feel the impact when you collide with another bumper car.

When the car hits something at low speed, the foam and fenders absorb the energy, pushing the bumper back and using the crumple zone to cushion the impact. Shattering the bumpers, fenders, and foam limits the damage you can do to the cars and the people inside them. means equal to the sum.

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The bird's average speed when he flies 10 m/s for 3 s, 15 m/s for 3s and 20 m/s for 4 s is 15.5 m/s. The right option is C 15.5 m/s

Average speed can be defined as the ratio of the total distance to the total time traveled by an object.

To calculate the average speed of the bird, we use the formula below.

Formula:

From the question,

Givne:

Substitute these values into equation 1

Hence, the average velocity of the bird is 15.5 m/s.

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Given:

The length of the pipe is L.

The third harmonic has teh wavelength,

To find:

The type of the pipe

Explanation:

The wavelength of the harmonics for a pipe closed at one end is,

The wavelength of the harmonics for a pipe open at both the ends is,

Here,

The given wavelength is,

which resembles the form,

Hence, the pipe is open at the other end.

Answer:

The speedometer of a car reveals information about the instantaneous speed of your car. It shows your speed at a particular instant in time.

Explanation:

The magnitude of electromotive force is 0.32 volts.

We need to know about the electromotive force of induction to solve this problem. The emf induction appears when there is any change in magnetic flux. The magnitude of emf can be determined by

ε = N dΦ / dt

where N is coil turns, ε is electromotive force, dΦ is change in magnetic flux and dt is time interval.

From the question above, the parameters given are

B = 0.047 T

dt = 0.34 s

N = 10

A = 0.23 m²

Find the change in magnetic flux

dΦ = (B . A)

dΦ = ( 0.047 . 0.23 )

dΦ = 0.01081 Tm²

By substituting the given parameters, we can calculate electromotive force

ε = N . dΦ / dt

ε = 10 . 0.01081 / 0.34

ε = 0.32 volt

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Wake turbulence is near maximum behind a jet transport just after take off because of the high angle of attack and high gross weight.

Explanation:

Every aircraft generates wake turbulence while in flight. Wake turbulence is a function of an aircraft producing lift, resulting in the formation of two counter-rotating vortices trailing behind the aircraft.

Wake turbulence from the generating aircraft can affect encountering aircraft due to the strength, duration, and direction of the vortices. Wake turbulence can impose rolling moments exceeding the roll-control authority of encountering aircraft, causing possible injury to occupants and damage to aircraft. Pilots should always be aware of the possibility of a wake turbulence encounter when flying through the wake of another aircraft, and adjust the flight path accordingly.

Wake turbulence is near maximum behind a jet transport just after take off because of the high angle of attack and high gross weight.

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The energy loss can increase or decrease.

In modern houses and systems, insulation is created to maintain heat and reduce losses.

P = ( AΔT ) / R

P is the heat flow, A is the insulated area, T is the temperature difference, and R represents the correlation between the insulation's thermal conductivity and thickness.

In this instance, they suggest that both the flow and the isolated area are growing. We have numerous options.

In this instance, the flow grows faster than the isolated area, increasing heat loss.

The quantity of insulation needed to increase (R) will cause the heat flow to grow by the same amount as the isolated area while keeping losses constant

Losses will reduce if the rate of heat transfer increases more slowly than the area that is insulated.

The two rises in this instance suggest that the heat requests may increase or decrease.

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The beat frequency is 3 beats/sec.

Beat frequency(n) can be found by using the following formula:

n=f2-f1, where f2 and f1 are the given frequencies

n= 515-512

n= 3 beats/sec

Therefore the beat frequency when 512 Hz and 512Hz tuning forks are sounded together is 3 beats/sec.

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The average fluid velocity (in m/s) is 3.636 m/s.

The volume of fluid moving past a spot in a given amount of time is measured as the flow rate. Circular and noncircular pipelines both experience fluid flow in daily life.

From the question we have given:

The diameter of the pipe (l) is  3.00 cm or 0.0300 m.

The magnetic field (B) is  0.550 T.

The hall voltage (E) is  60.0 mv or 60 x 10⁻³ v.

  [tex]v = \frac{E}{Bl}[/tex]

The average fluid velocity can be calculated using the equation E = Blv.

In this instance, the width really corresponds to the diameter:

[tex]v = \frac{60 \;*\; 10^{-3} \;V}{0.0165\; m} \\[/tex]

[tex]v = 3.636 \;m/s[/tex]

Thus, the average fluid velocity is 3.636 m/s.

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Based on the data in the chart, it can be concluded that as mass increases, so does thermal energy, because the thermal energy of a substance is highly dependent on its temperature and mass.

Thermal energy always moves from a higher temperature area to a lower temperature area. When a block of ice comes into contact with a colder substance, such as liquid nitrogen or dry ice, thermal energy moves from the ice to the colder substance.

Because mass measures the amount of material in a sample, thermal energy is determined by the mass and temperature of the object. The more significant the mass of the object, the more particles there are in the model, and the more significant the thermal energy.

Thermal energy is the energy contained in the motion and vibration of its molecules.

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The mass of the rock with a kinetic energy of 113J and a speed of 6.2m/s is approximately 5.88 kilograms.

Kinetic energy is simply the energy a body possesses due to its motion;

It is expressed as;

K.E = 1/2 × m × v²

Given the data in the question;

To determine the mass of the rock, plug the given values into the Kinetic energy formular and solve for m.

K.E = 1/2 × m × v²

113kgm²/s² = 1/2 × m × ( 6.2m/s )²

113kgm²/s² = 1/2 × m × 38.44m²/s²

113kgm²/s² = m × 19.22m²/s²

m = 113kgm²/s² / 19.22m²/s²

m = 5.88kg

Therefore, the mass of the rock is 5.88 kilograms.

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a) The normal force on the block of mass M is 76.383 N in magnitude.

b) The hanging block goes upward in one direction.

c) The block's acceleration has a common magnitude of 8.11 m/s2.

d) The string's tension measurement is 161.19 N in magnitude.

e) After 2.0 seconds, the speed of the hanging mass is 5.695 seconds.

Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to size or quantity.

It's given that:

M = 45.2 kg.

µk = 0.10.

m = 9.0 kg.

angle = 30 degree

A) The block's mass M and the normal force's strength N:

N - mgcosθ = 0

= 9 * 9.8cos 30

= 76.383N

B) The hanging block's direction shifts upward.

C) the typical magnitude of the acceleration of the block is

Mg - T = Ma

(Mg - T) / M = a

(45.2 * 9.8 - 76.383) / 45.2 = a

[tex]8.11\frac{m}{s^{2} } = a[/tex]

D) the string's tension, T, in terms of magnitude

T - mg = ma

T = ma + mg

T = 9 * 8.11 + 9 * 9.81

T = 161.19N

E) the dangling mass's speed after a delay of 2.0 seconds

v² - u² = 2as

v² - 0² = 2as

v² = 2as

v = √2as

v = √2*8.11*2

v = 5.695 m/s

COMPLETE QUESTION: Two blocks are connected by a light but sturdy string wrapped around a mass-less pulley. The rough inclined surface makes an angle of 30 degrees with the horizontal. The block on the inclined surface has a mass M = 45.2 kg. Assume the coefficient of kinetic friction between the union of mass M and the inclined plane is µk = 0.10. The vertically hanging block has mass m = 9.0 kg. Assume the blocks begin their motion from rest.

(a) (10 points) What is the magnitude N of the normal force on the block of mass M?

(b) (5 points) In What direction does the hanging block m move, up or down? Circle one.

(c) (18 points) What is the common magnitude of the acceleration of the blocks?

(d) (14 points) What is the magnitude T of the tension in the string?

(e) (6 points) What is the speed of the hanging mass after a time period of 2.0 seconds?

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Answer:

Explanation:

Given,

Time ( t ) = 90 seconds

Distance ( d ) = 10 meter

To find : Speed ( v ) = ?

Formula : -

v = d/t

v = 10/90

v = 1/9 m/s ( meters per second )

Hence,

1/9 m/s is the speed walk in 90 seconds for the 10 meter trail.

If the speed of the car is increased by 65%, the stopping distance of the car will be increased by 272.25%.

Let us say, the car is moving with velocity U, the stopping time of the car is T and the stopping distance of the block is d,

Now, we should use the equation of motion,

U²-V² =2aD

Where,

U is initial velocity,

V is final velocity,

D is the stopping distance,

a is the acceleration.

We know, at the final velocity will be zero,

So,

U² = 2aD

U =√(2aD)

Now, if the speed is increased by 65%, let us say the stopping distance becomes D'.

So,

U+65%U = √(2aD')

165U/100 = √(2aD')

Now, putting U = √(2aD),

165√(2aD)/100 = √(2aD')

(1.65)²D = D'

D' = 2.7225D

Now,

∆D = D' - D/D × 100

∆D = 2.7225 × 100

∆D = 272.25%

So, the stopping distance increased by 272.25%.

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If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be  Decreased and the resonant frequency would be unchanged.

What is capacitor ?

Frequency is the rate at which something occurs over a particular period of time or in a given sample.

Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.

It is defined as-

XL= 2πfL

Xc= 1/2πfC

So when reactances are equal we have-

XL=Xc

2πfL= 1/2πfC

f^2=1/4π^2LC

f=1/2π√LC

The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.

The impedance of a parallel LC circuit is:

Z(w)= jL w^2-w^2•/w

In a series LC circuit, when w

, the impedance becomes equal to 0.

Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.

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If a car can go from 0 - 69 mi/hr in 8.0 seconds, then the final speed after 5.0 seconds would be 41.6 m/s, if its starting speed was 50 mi/hr.

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.

The acceleration of the car If a car can go from 0-69mi/hr in 8.0 seconds,

69 miles / hour = 69 × 1609 / 3600

                          = 30.83 m / s

v = u + at

30.83 = 0 + a × 8.0

a = 30.83 / 8.0

  = 3.85 meters / second²

50 miles per hour = 50 × 1609 / 3600

                              = 22.35 m / s

The velocity of the car after 5 seconds,

v = 22.35 + 3.85 × 5

  = 41.6 m / s

Thus, the velocity of the car after 5 seconds would be 41.6 m / s.

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