A spinner with 10 equal sections, numbered 1 to 10, is spun. Then a coin is flipped. What is the probability that the spinner will land on 3 and the coin will land on heads?

12%
20%
5%
10%

Answer:

Step-by-step explanation:(Probability of landing on 3)*(Probability of landing on heads) = (1/10)*(1/2) = (1/20) or 0.05 or 5%

The probability that the spinner will land on 3 and the coin will land on heads is 5%.

Option C is the correct answer.

It is the chance of an event to occur from a total number of outcomes.

The formula for probability is given as:

Probability = Number of required events / Total number of outcomes.

We have,

Sample space of spinning a spun of 10 sections and flipping a coin.

= (1, 2, 3, 4, 5, 6, 7, 8, 9, 10) x {H, T}

= {(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), 6, T), (7, H), (7, T), (8, H), )(8, T), (9, H), (9, T), (10, H), (10, T) }

The number of possible outcomes = 20.

Number of outcomes with 3 and heads = 1

i.e (3, H)

The probability of landing on 3 and heads.

= 1/20

= 0.05

In terms of percentage.

= 0.05 x 100

= 5%

Thus,

The probability of landing on 3 and heads is 5%.

Learn more about probability here:

https://brainly.com/question/14099682

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