Answer:
it's 9m
Explanation:
Answer:
9m
Explanation:
edge2o2o
What type of energy transfer occurs
when two objects touch?
O conduction
O induction
O convection
Answer:
conduction
Explanation:
SUBJECT: ASTRONOMY -- TOPIC: Time Dilation
Find the time interval measured by your stationary watch if your friend’s watch measures 1.0 year while she is traveling at 0.87c aboard a futuristic interstellar rocket.
Answer:
You can determine if the ship is moving by lying down and measuring your height.
Explanation:
Describe the role of the
nucleus in cell activities.
Answer:the nucleus controls and regulates the activities of the cell
Explanation:trust me bro
Answer:
The nucleus controls and regulates the activities of the cell and carries the genes, structures that contain the hereditary information.
Page 1:Page 2:
A web chart titled Map with a center circle connected to 4 outer circles.
Of the two organizational aids, which one would be the most useful for showing chronological order: the web or the sequence chart?
Answer:
or the other answer is venn diagram if your on another question
Explanation:
Answer:
the answer is c on edg
Explanation:
A 30-gram arrow, moving at 60 m/s, hits a stationary 240-gram apple. The arrow passes through the apple, and is measured on the other side, moving at 55 m/s. What is the final velocity of the apple?
Answer: ouch
Explanation:
4
2 points
Which of the following is a vector quantity?
O Velocity
O
Time
Speed
оо
Distance
Answer:
Velocity Has vector Quantity
A 1.2-kg object moving at 5.0 m/s collides with and sticks to a 4.8-kg object initially at rest. What is the amount of kinetic energy lost by the system during this collision?
Answer:
-15J
Explanation:
Step one:
given data
m1= 1.2kg
v1= 5 m/s
m2= 4.8kg
v2= 0 m/s
Required
The kinetic energy lost
Step two:
The kinetic energy before impact is KE1
[tex]KE1= 1/2mv^2\\\\KE1= 1/2*1.2*5^2\\\\KE1= 15J[/tex]
KE after impact is KE2
[tex]KE2= 1/2*(m1+m2)v2\\\\KE2= 1/2*(6)0\\\\KE2= 0 J[/tex]
The loss in Kinetic energy is
Loss in KE= KE2-KE1
Loss in KE= 0-15
Loss in KE= -15J
Which one of the the following occurs when sodium forms an ionic bond?
Answer:
An atom of sodium (Na) donates one of its electrons to an atom of chlorine (Cl) in a chemical reaction, and the resulting positive ion (Na+) and negative ion (Cl−) form a stable ionic compound (sodium chloride; common table salt) based on this ionic bond.
Explanation:
All the info i can give you
a ball is thrown with a speed of 17.7 m/s at an angle of 49.8° above the horizontal. how much time does the ball need to reach a height of 4.7 m above the release point ?
Answer:
The ball needs approximately [tex]0.41\; \rm s[/tex] to reach that height for the first time.
Explanation:
The initial speed of the ball [tex]17.7\; \rm m \cdot s^{-1}[/tex]. However, what would be the initial vertical speed of this ball?
The angle of elevation is [tex]\theta = 49.8^\circ[/tex]. Consider the initial speed of this ball as the length of the hypotenuse of a right triangle. If the angle of elevation is one of the two acute angles of this triangle, the initial vertical speed of this ball would be the leg opposite to that angle.
[tex]\displaystyle \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}}[/tex].
[tex]\displaystyle \sin \theta = \frac{v(\text{vertical, initial})}{v(\text{initial})}[/tex].
Therefore:
[tex]\begin{aligned}&v(\text{vertical, initial})\\ &= v(\text{initial}) \cdot \sin\theta \\ &= 17.7\; \rm m \cdot s^{-1} \times \sin \left(49.8^\circ\right) \approx 13.5\; \rm m \cdot s^{-1}\end{aligned}[/tex].
Let [tex]t[/tex] denote the time (in seconds) required for the ball to reach a height of [tex]4.7\; \rm m[/tex].
Let [tex]g[/tex] denote the acceleration because of gravity (typically [tex]g \approx 9.81\; \rm m \cdot s^{-2}[/tex] near the surface of the earth.) The height of the ball [tex]t[/tex] seconds after it was thrown would be: [tex]\displaystyle \frac{1}{2}\, g \cdot t^{2} + v(\text{vertical, initial}) \cdot t[/tex].
Assume that [tex]g \approx 9.81\; \rm m \cdot s^{-2}[/tex]. Set the value of this expression for height to [tex]4.7\; \rm m[/tex] and solve for [tex]t[/tex]:
[tex]\displaystyle \frac{1}{2} \times 9.81 \, t^{2} + 13.5 \, t = 4.7[/tex].
Either [tex]t \approx 0.41[/tex] or [tex]t \approx 2.3[/tex] will satisfy this equation. Both of these two values are reasonable. The first value for [tex]t[/tex] ([tex]0.41\; \rm s[/tex]) is the time required for the ball to reach a height of [tex]4.7\; \rm m[/tex] for the first time. The second value ([tex]2.3\; \rm s[/tex]) is the time required for the ball to come under that height on its way back to the ground. The question seems to be asking only for the first (the smaller one) of these two times.
An object is placed on the moveable piston of a cylinder filled with a gas. The object exerts a downward force F on the piston that accelerates the piston downward, compressing the gas. Which of the following is a correct description of the magnitude of the upward force exerted by the piston on the object?
a. The force exerted by the piston on the object is equal to FF.
b. The force exerted by the piston on the object is less than FF because the piston is accelerating downward.
c. The force exerted by the piston on the object is greater than F because the gas exerts an upward force on the piston.
d. The force exerted by the piston cannot be compared to FF without knowing the magnitude of the acceleration of the piston and pressure of the gas.
Answer:
b. The force exerted by the piston on the object is less than F because the piston is accelerating downward.
Explanation:
Given that object exerts a downward force F on the piston that accelerates the piston downward.
An object can accelerate if the net force acting on it is non-zero.
Here, the piston is acceleration in the downward direction, so the net for on the piston is in the downward direction.
Force due to object, F, is in the downward direction while the force exerted by the piston on the object is in the upward direction.
As the acceleration of the piston is in the downward direction, so the downward force is more.
Therefore, the force exerted by the piston on the object is less than F because the piston is accelerating downward.
Hence, option (b) is correct.
Write one to two sentences explaining whether this passage from the story is exposition, rising action, climax, or resolution: “The announcer turned to point to the winner and found himself alone. Arm in arm the champions had already left the ring.”
Answer:
This passage is part of the resolution because it shows what happens after the climax. It wraps up the conflict, and then the story is over.
Explanation: cause I am smart thats why
The highest surface temperature on any of the solar system’s planets is found on Venus. Partly because of its nearness to the sun and partly because of the extreme pressure of its atmosphere, the average daytime temperature on Venus is 453°C. What is this temperature in degrees Fahrenheit and in kelvins?
Answer:
Fahrenheit ⇒ 847.4 °FKelvin ⇒ 726.15KExplanation:
To convert Celsius to Fahrenheit, use the following formula;
= (°C * 9/5) + 32
= (453 * 9/5) + 32
= 847.4 °F
To convert Celsius to Kelvin, use the following;
= °C + 273.15
= 453 + 273.15
= 726.15K
Pls help quick too.................
Answer:
Pulley = Flag Pole
Screw = Side latch
Wedge = Scissors
Wheel and axle = Car
What is the launch speed of a projectile that rises vertically above the Earth to an altitude equal to 14 REarth before coming to rest momentarily
Answer:
v = 1.078 10⁴ m / s
Explanation:
To solve this exercise we can use conservation of mechanical energy
Starting point. Just clearing
Em₀ = K + U = ½ m v² - G m M / [tex]R_{e}[/tex]
Final point. At r = 14R_{e}
Em_{f} = U = -G m M / 14R_{e}
how energy is conserved
Em₀ = [tex]Em_{f}[/tex]
½ m v² - G m M /R_{e} = -G m M / 14R_{e}
½ v² = G M / R_{e} (-1/14 + 1)
v² = 2 G M / R_{e} 13/14
we calculate
v² = 2 6.67 10⁻¹¹ 5.98 10²⁴ / 6.37 10⁶ 13/14
v = √ (1,16 10⁸)
v = 1.078 10⁴ m / s
The launch speed of a projectile that rises above the earth will be
v = 1.078 10⁴ m / s
What is speed?
Speed is defned as the movement of any object with respect to the time the formula of speed is given as the ratio of the distance with time.
To solve this exercise we can use conservation of mechanical energy
Starting point. Just clearing
[tex]E_{mo} = K + U = \dfrac{1}{2}m v^2 - \dfrac{G m M} { r}[/tex]
Final point. At[tex]r = 14R_{e}[/tex]
[tex]Em_{f} = U = \dfrac{-G m M }{14R_{e}}[/tex]
how energy is conserved
[tex]E_{mo }= \dfrac{1}{2} m v^2 -\dfrac{-G m M }{R_{e}} = \dfrac{-G m M }{ 14R_{e}}[/tex]
[tex]\dfrac{1}{2} v^2 = \dfrac{G M }{ R_{e} (\dfrac{-1}{14} + 1)}[/tex]
[tex]v^2 = \dfrac{2 G M} { R_{e} \dfrac{13}{14}}[/tex]
we calculate
[tex]v^2 = \dfrac{2 6.67 \times10^{-11}\times 5.98 \times 10^{24}} { 6.37 \times 10^{6} \times \dfrac{13}{14}}[/tex]
[tex]v = \sqrt{ (1,16\times 10^8)}[/tex]
v = 1.078 10⁴ m / s
Hence the launch speed of a projectile that rises above the earth will be
v = 1.078 10⁴ m / s
To know more about speed follow
https://brainly.com/question/4931057
types of polarization physics
Answer:
Linear polarization.
Circular polarization.
Elliptical polarization.
The writing on the passenger-side mirror of your car says "Warning! Objects are closer than they appear." There is no such warning on the driver's mirror. Consider a typical convex passenger-side mirror with a focal length of -80 cm . A 1.5 m -tall cyclist on a bicycle is 30 m from the mirror. You are 1.4 m from the mirror, and suppose, for simplicity, that the mirror, you, and the cyclist all lie along a line.
- You are 2.2 m from the image of the cyclist
A) What is the image height?
B) What would the image height have been if the mirror were flat?
C) What is the angular size of the image of the cyclist?
D) What would the angular size of the cyclist's image have been if the mirror were flat?
E) Explain why is there a warning label on the passenger-side mirror?
Answer:
kdfjnfkasd
Explanation:
What causes sound energy to be produced? *
Speed
instruments
Vibration
Fluency
Read each scenario and then answer the question. Scenario A: A 3 StartFraction N over m EndFraction spring is compressed a distance of 1.0 m. Scenario B: A 6 StartFraction N over m EndFraction spring is compressed a distance of 0.8 m. Scenario C: A 9 StartFraction N over m EndFraction spring is compressed a distance of 0.6 m. Scenario D: A 12 StartFraction N over m EndFraction spring is compressed a distance of 0.4 m. Which scenario generates the most elastic potential energy?
Answer:
The correct answer is B
Explanation:
Answer:
B
Explanation:
edge2o2o
Why do you think the process of photosynthesis and respiration are interrelated?
Answer:
The processes of photosynthesis and respiration are interrelated because the products of such processes are used as reactants for one process. One product of photosynthesis is oxygen. This oxygen is used in the process of respiration as a reactant producing carbon dioxide which is used as a reactant for photosynthesis.
the_____ climate is the coldest climate region and includes
Answer:
the POLAR climate is the coldest climate region and includes...
Explanation:
It includes the ice cap ,and Artic and tundra climates
A person pushes a 10 kg box from rest and accelerates it to a speed of 4 m/s with a constant force. If the box is pushed for a time of 2.5 s, what is the force exerted by the person?
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration a is such that
4 m/s = a (2.5 s) → a = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude F such that
F = (10 kg) (1.6 m/s²) = 16 N
A 25-g string is stretched with a tension of 43 N between two fixed points 12 m apart. What is the frequency of the second harmonic?
Answer:
The frequency of the second harmonic ([tex]2f_o[/tex]) is 11.97 Hz.
Explanation:
Given;
mass of the string, m = 25 g = 0.025kg
tension on the string, T = 43 N
length of the string, L = 12 m
The speed of wave on the string is given as;
[tex]v = \sqrt{\frac{T}{\mu} }[/tex]
where;
μ is mass per unit length = 0.025 / 12 = 0.002083 kg/m
[tex]v = \sqrt{\frac{43}{0.002083} }\\\\v = 143.678 \ m/s[/tex]
The wavelength of the first harmonic wave is given as;
[tex]L = \frac{1}{2} \lambda _o\\\\\lambda _o = 2L \\\\\lambda _o = 2 \ \times \ 12\\\\\lambda _o = 24 \ m[/tex]
The frequency of the first harmonic is given as;
[tex]f_o = \frac{v}{\lambda _o} = \frac{v}{2L} = \frac{143.678}{24} = 5.99 \ Hz\\\\[/tex]
The wavelength of the second harmonic wave is given as;
[tex]L = \lambda_1 \\\\\lambda_1 = 12 \ m[/tex]
The frequency of the second harmonic is given as;
[tex]f_1 = \frac{v}{\lambda _1} = \frac{143.678}{12} = 11.97 \ Hz = 2(\frac{v}{\lambda _0}) = 2f_o[/tex]
Therefore, the frequency of the second harmonic ([tex]2f_o[/tex]) is 11.97 Hz.
What is the correct Lewis structure for group 5A element, arsenic?
Answer:
A
Explanation:
Because Arsenic is in group 15 it will receive 5 valence electrons Start out by adding one dot around the symbol for Arsenic. You'll end up with 4 around it and all you have to do is add another one.
How do insects aid in crime scene investigations
Answer:
They can figure out when the person died, possibly the nature of crime, it can also detect if the body was moved in certain area.
Explanation:
2. What is the kinetic energy of an 80 kg football player running at 8m/s? *
O A. 2560J
O B. 320J
O C. 2560 W
O D.320 W
HELPPPPP
Answer:
the answer is A!! 2560 J
A pilot engages the control wheel steering (CWS) of a conventional autopilot and carries out a manoeuvre in roll. When the control wheel is released, the autopilot will:
Answer: Maintain the flight altitude obtained at that moment.
Explanation:
An autopilot is a system used without the pilot's direct assistance to guide an aircraft. Only a steady heading and altitude could be maintained by early autopilots, but modern autopilots are capable of monitoring any aspect of the flight envelope from just after take-off until landing.
About how far apart must you hold your hands for them to be separated by 1.6 nano-light-second (the distance light travels in 1.6 ns)? Assume that the speed of light is 2.998*108 m/s.
Answer:
d = 0.479 m
Explanation:
Given that,
The distance light travels in = 1.6 ns
The speed of light is [tex]2.998\times 10^8\ m/s[/tex]
The speed of an object is given by distance traveled divided by time.
[tex]c=\dfrac{d}{t}\\\\d=ct\\\\d=2.998\times 10^8\times 1.6\times 10^{-9}\\\\=0.479\ m[/tex]
Hence, the required distance is 0.479 m.
One cubic meter of a saturated soil sample has a total mass of 2400 kg. The solids have a specific gravity of 2.70. The dry density of the soil is most nearly:
Answer:
6480kg/m³
Explanation:
Specific gravity is expressed as;
S = density of substance being measured/Density of the reference sample
Reference sample is the saturated soil
Density of the saturated soil = Mass/Volume
Density of the saturated soil = 2400/1
Density of the saturated soil = 2400kg/m³
Given
Specific gravity = 2.70
Get the dry density of the soil
Dry density of the soil = Specific gravity * Density of the saturated soil
Dry density of the soil = 2.70 * 2400
Dry density of the soil = 6480kg/m³
Hence the dry density of the soil is most nearly 6480kg/m³
Which force represented by the arrow at B? a. force of friction b. force of gravity c. tension force d. normal force
Answer:
A. Force of friction
Explanation:
Find the diagram attached
From the diagram we can see that the force B is acting up on the body along the plane. This force is the force that prevents the body from sliding down the plane. Originally, the body on the line will tend to slide down the incline even without application of a force hence the reason of an opposing force that must act in the opposite direction is counter this motion to make the body be in a state of equilibrium. Hence the required force is force of friction since it is am opposing force acting in the direction opposite to the moving force acting on the body.
I need help with this answer
Answer:
double replacement
Explanation:
sorry if im wrong
