A student pushes a 0.5 kg lab cart with a force of 3 Newtons. Determine the acceleration of the cart in
m/s2.

Answers

Answer 1

Answer:

The acceleration is  6 [tex]\frac{m}{s^2}[/tex]

Explanation:

Use Newton's second law to solve the problem:

[tex]Force = mass\,\,*\,\,acceleration\\3\,N = 0.5\,\,kg\,*\,a\\a = \frac{3}{0.5} \frac{m}{s^2} \\a=6\,\,\frac{m}{s^2}[/tex]

Answer 2

the acceleration of the cart given its mass and force exerted is 6m/s².

Given the data in the question;

Mass of lab cart; [tex]m = 0.5kg[/tex]

Force applied; [tex]F = 3N[/tex]

Acceleration of cart; [tex]a = \ ?[/tex]

To determine the acceleration of the cart, we use the expression from Newton's second law of Motion:

[tex]F = m* a[/tex]

Where F is force exerted, m is mass and a is acceleration

We substitute our given values into the equation

[tex]3N = 0.5kg \ * \ a\\\\3kgm/s^2 = 0.5kg\ *\ a\\\\a = \frac{3kgm/s^2}{0.5kg} \\\\a = 6m/s^2[/tex]

Therefore, the acceleration of the cart given its mass and force exerted is 6m/s².

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Related Questions

A rock is thrown vertically upward from the origin of a reference frame. The rock reaches the peak of its trajectory and then it returns back to the origin where it comes to rest. Using the upward direction as positive, select True or False for the following statements. False The acceleration of the rock is negative throughout the whole motion. True The position of the rock is positive or zero throughout the whole motion. False The velocity of the rock is positive throughout the whole motion. False The acceleration of the rock is zero at the peak of the trajectory

Answers

Answer:

The acceleration of the rock is negative throughout the whole motion. (TRUE)

The acceleration of the rock is zero at the peak of the trajectory (FALSE)

The velocity of the rock is positive throughout the whole motion (FALSE)

The position of the rock is positive or zero throughout the whole motion (TRUE)

The velocity of the rock is positive throughout the whole motion (FALSE)

Explanation:

1)The acceleration of the rock is negative throughout the whole motion. (TRUE)

Using the upward direction as positive

Then, The acceleration of the rock is negative throughout the whole motion.

2)The acceleration of the rock is zero at the peak of the trajectory.(FALSE)

Only the velocity can be zero at the peak the trajectory, the acceleration is not zero

3)The velocity of the rock is positive throughout the whole motion (FALSE)

Using the upward direction as positive, The velocity of the rock is only positive when going in upward direction and vice versa

4)The position of the rock is positive or zero throughout the whole motion (TRUE)

When the rock get down it will have a zero position, then when it get to the peak it will have positive position

A runner runs the 100 meter dash in 16.6 seconds. What is their average speed? (in meters per second) SOMEBODY PLEASE HELP ME!!!

Answers

Formula: s = d/t

s = speed

d = distance

t = time

We are given the distance and time, so we can use that to solve for the speed.

s = 100/16.6

s ≈ 6.02m/s

Best of Luck!

A cube measures 3 cm on each side and has a mass of 25 g. What is its density.

Answers

Answer:

The density is:   [tex]0.926 \,\frac{g}{cm^3}[/tex]

Explanation:

Recall that density is defined as the quotient of the object's mass divided by volume. So, we calculate the volume of the 3 cm side cube:

[tex]Vol = (3 \,cm)^3 = 27 \,\,cm^3[/tex]

then the density becomes:

[tex]density=\frac{mass}{Vol} =\frac{25}{27} \,\frac{g}{cm^3} \approx 0.926 \,\frac{g}{cm^3}[/tex]

A 70​-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and that the chain has a density of 5 ​kg/m. Use 9.8 m/s2 for the acceleration due to gravity. a. How much work is required to wind the entire chain onto the cylinder using the​ winch? b. How much work is required to wind the chain onto the cylinder if a 35​-kg block is attached to the end of the​ chain?

Answers

Answer:

a) The work required to wind the entire chain onto the cylinder using the winch is 120135.75 joules, b) The work required to wind the chain plus the block is 144162.9 joules.

Explanation:

a) Let be an infinitesimal part of the long chain, whose gravitational potential energy is:

[tex]dU_{g} = g\cdot z \,\delta m[/tex]

Where:

[tex]U_{g}[/tex] - Gravitational potential energy, measured in joules.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]m[/tex] - Mass of the long chain, measured in kilograms.

[tex]z[/tex] - Height of the portion of the long chain with respect to ground, measured in meters.

Since chain has an uniform linear density, this differential expression can be rewritten as:

[tex]dU_{g} = \lambda\cdot g \cdot z \, dz[/tex]

Where [tex]\lambda[/tex] is the linear density, measured in kilograms per meter.

We obtain the gravitational potential energy to wind the chain onto the cylinder by integration:

[tex]\Delta U_{g, chain} = \lambda\cdot g \int\limits^{z_{f}}_{z_{o}} {z} \, dz[/tex]

[tex]\Delta U_{g, chain} = \frac{\lambda\cdot g}{2} \cdot (z_{f}^{2}-z_{o}^{2})[/tex]

Where:

[tex]\Delta U_{g, chain}[/tex] - Gravitational potential energy of the entire chain, measured in joules.

[tex]z_{o}[/tex] - Initial height with respect to ground, measured in meters.

[tex]z_{f}[/tex] - Final height with respect to ground, measured in meters.

From the Work-Energy Theorem we get that work needed to wind the entire chain equals the gravitational potential energy of the entire chain:

[tex]W = \Delta U_{g, chain}[/tex]

[tex]W = \frac{\lambda\cdot g}{2} \cdot (z_{f}^{2}-z_{o}^{2})[/tex]

If we know that [tex]\lambda = 5\,\frac{kg}{m}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex] and [tex]z_{f} = 70\,m[/tex], the work needed is:

[tex]W = \frac{\left(5\,\frac{kg}{m} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{2} \cdot [(70\,m)^{2}-(0\,m)^{2}][/tex]

[tex]W = 120135.75\,J[/tex]

The work required to wind the entire chain onto the cylinder using the winch is 120135.75 joules.

b) The gravitational potential energy of the block, measured in joules, is:

[tex]\Delta U_{g,block} = m_{block}\cdot g \cdot (z_{f}-z_{o})[/tex]

Where:

[tex]m_{block}[/tex] - Mass of the block, measured in kilograms.

[tex]z_{o}[/tex] - Initial height with respect to ground, measured in meters.

[tex]z_{f}[/tex] - Final height with respect to ground, measured in meters.

According to the Work-Energy Theorem, the work needed to wind the chain plus the block equals the sum of both gravitational potential energies:

[tex]W = \Delta U_{g, chain}+U_{g,block}[/tex]

[tex]W = \frac{\lambda \cdot g}{2}\cdot (z_{f}^{2}-z_{o}^{2})+m_{block}\cdot g \cdot (z_{f}-z_{o})[/tex]

If we know that [tex]\lambda = 5\,\frac{kg}{m}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex], [tex]z_{f} = 70\,m[/tex] and [tex]m_{block} = 35\,kg[/tex], the work required to wind the chain onto the cylinder if a block is attached to the end of the chain is:

[tex]W = \frac{\left(5\,\frac{kg}{m} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{2}\cdot [(70\,m)^{2}-(0\,m)^{2}]+(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (70\,m-0\,m)[/tex]

[tex]W = 144162.9\,J[/tex]

The work required to wind the chain plus the block is 144162.9 joules.

the summer camps had field from the campus to fragrance hill. they traveled at an average speed of 65 km/h in the first 2 hours. after that they traveled at another average speed of 78 km/h if the distance between the campus and fragrance hill is 364 km, what was the total time for a field trip

Answers

Answer:

5 hours

Explanation:

so if they traveled an average speed of 65 km/h then that means they traveled 130 km (2*65). Then the remaining distance to travel will be 364-130, or 234 km. If you travel at 78 km /h, then it will take you 234/78, or 3 more hours to reach Fragrance Hill. Add 2 and 3 to get a total of 5 hours

______ Is the degree of exactness of a measurement; _____ Describes how well the results of measurement agree with the real value

A: accuracy, precision
B: Percision, accuracy
C: accuracy, the line of best fit
D: Percision, the line of best fit

Answers

Answer: is B. Precision, accuracy

Explanation: Precision is the degree of exactness of a measurement; Accuracy describes how well the results of a measurement agree with the real value.

Brainiest Please

In the context of measurements, accuracy and precision are two different concepts that describe different aspects of the quality or reliability of the results obtained. The correct answer is A

Accuracy refers to how close the measured value is to the true or accepted value. It is a measure of how well the measurement reflects the actual quantity being measured. If a measurement is accurate, it means that it is on target and has a minimal deviation from the true value.

Precision, on the other hand, refers to the degree of exactness or consistency in the measurements. It measures the level of repeatability and reproducibility of the results. A precise measurement has very little variation or scatter between repeated measurements of the same quantity. Precision does not necessarily guarantee accuracy.

To summarize:

Accuracy relates to the closeness of a measurement to the true or accepted value.

Precision relates to the consistency and reproducibility of the results obtained.

In the given options, the correct answer is A: accuracy, precision. Accuracy describes how well the results of measurement agree with the real value, while precision is the degree of exactness of a measurement.

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A maser is a laser-type device that produces electromagnetic waves with frequencies in the microwave and radio-wave bands of the electromagnetic spectrum. You can use the radio waves generated by a hydrogen maser as a standard of frequency. The frequency of these waves is 1,420,405,751.786 hertz. (A hertz is another name for one cycle per second.) A clock controlled by a hydrogen maser is off by only 1 s in 100,000 years. (The large number of significant figures given for the frequency simply illustrates the remarkable accuracy to which it has been measured.)A. What is the time for one cycle of the radio wave? Express your answer to three significant figures and include the appropriate units.B. How many cycles occur in 4 h ? Express your answer using three significant figures.C. How many cycles would have occurred during the age of the earth, which is estimated to be 4.6×109 years? Express your answer using three significant figures.D. By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth? Express your answer using three significant figures.

Answers

Answer:

a)  t₀ = 0.704 10⁻¹² s,  b)   #cycle = 2.05 10¹⁶ cycles ,  

c)    #_cycles = 7,418 10³² cycles,  d)   Δt = 4.6 10⁴ s

Explanation:

For this exercise we must use the relationship between the period and the frequency

       f = 1 / T

       T = 1 / f

let's apply this equation to our case

a) The time of a cycle is

       t = 1 / 1.420405 10¹²

       t₀ = 0.704 10⁻¹² s

b) number of cycles in 4 h

       t = 4 h (3600 s / 1h) = 14400 s

Let's use a direct rule of proportions (rule of three). If there is 1 cycle in t₀, how much cycle is there

      #_cycles = t (1 / t₀)

      #_cycle = 14400 s (1 cycle / 0.704 10⁻¹² s)

      #_cycle = 2.0454 10¹⁶ cycles

      #cycle = 2.05 10¹⁶ cycles

c) cycles since the age of the Earth

     t = 4.6 10⁹ years (365 days / year) (24 h / 1 day) (3600 s / 1 h)

     t = 5.2224 10²⁰ s

    #_cycles = t (1 / to)

    # _cycles = 5.2224 10²⁰ (1 / 0.704 10⁻¹²)

    #_cycles = 7,418 10³² cycles

d) Let's use the direct proportion rule. If you have a lag of Δt₁ = 1s at t₁ = 1 10⁵ years, what is the lag (Δt) at t = 4.6 10⁹ years

        Δt = t (Δt₁ / t₁)

        Δt = 4.6 10⁹ years (1 s / 10⁵ years)

        Δt = 4.6 10⁴ s

How much force is needed to keep a 25 N rock moving with constant speed across the level, frictionless ice?

Answers

Answer:

Explanation:

Hello friend!!!!!

The answer is 0 Newton

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Distance vs Displacement
As an object moves, its location undergoes change. There are two quantities that are used to describe the changing location. One quantity - distance
accumulates the amount of total change of location over the course of a motion. Distance is the amount of ground that is covered. The second quantity -
displacement - only concerns itself with the initial and final position of the object. Displacement is the overall change in position of the object from start to
finish and does not concern itself with the accumulation of distance traveled during the path from start to finish.

True or False: An object can be moving for 10 seconds and still have zero displacement.

A. True
B. False

Answers

Answer:

A

Explanation:

Because u can just go back to where u started in just ten seconds

A vehicle travels 53 km both north and east. What is the
vehicle's displacement?

Answers

75km

I dont really know how to do the math but thats what my teacher told me when i asked

When the vehicle travels 53 km both north and east, then the resultant displacement of the vehicle would be 74.95 kilometers.

What is displacement?

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard.

Displacement describes this shift in location.

As given in the problem when the vehicle travels 53 km both north and east, then we have to find the resultant displacement of the vehicle,

The vehicle's displacement in the north direction = 53 kilometers

The vehicle's displacement in the east direction =53 kilometers

The resultant vehicle's displacement= √(53² + 53²)

                                       = √5618

                                       = 74.95 kilometers

Thus ,the resultant displacement of the vehicle is 74.95 kilometers in the northeast direction.

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Which of these is an example of the conversion of kinetic energy into gravitational potential energy?
Group of answer choices

a bicyclist coasting down a long hill

a car engine moving the car forward

a roller coaster car moving toward the top of a rise in the tracks

a thrown ball falling toward the ground after passing through the top part of its motion​

Answers

Answer:

a roller coaster car moving toward the top of a rise in the tracks

Explanation:

A roller coaster car moving toward the top of a rise in the tracks is an example of the conversion of kinetic energy into gravitational potential energy , therefore the correct answer is option C.

What is mechanical energy ?

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total potential energy stored energy in the system which is represented by total potential energy .

As given in the problem we have to find out Which of these is an example of the conversion of kinetic energy into gravitational potential energy ,

A roller coaster car moving toward the top of a rise in the tracks is an example of the conversion of kinetic energy into gravitational potential energy , therefore the correct answer is option C .

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An automobile is traveling at a constant 15 m/s, then it undergoes acceleration from that moment forward. Which statement best describes the automobile's new motion?​

Answers

Answer:

d

Explanation:

We are required to write a statement that best describes the automobile's new motion.

The statement that best describes the automobile's new motion is uniform acceleration.

Motion is the change of position of a body or object with time.

Uniform Acceleration is defined as the motion of an object whose velocity increases by equal amounts in equal intervals of time, however small the time intervals may be.

The best statement to describe the automobile's new motion is called Uniform Acceleration

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As θ increases towards 90 what happens to the horizontal and vertical components of F?

Answers

Horizontal component , F cos θ.

Vertical component , F sin θ.

Now, as θ increases towards 90° cos θ decreases and

As θ increases towards 90° sin θ increases.

Therefore, horizontal component of F will decrease and vertical component will increase.

Hence, this is the required solution.

A house is maintained at a comfortable temperature by means of an electrical resistor heater during winter. The heater is operated at a constant current (I) under an applied voltage of 110 V. For simplicity, let us assume that the heater operates at a steady state, with 100% of conversion efficiency from the electrical energy to the internal energy of air in the house. (a) (5p) Find I if the homeowner pays $8.80/day for heating, with electricity cost $0.09/kWh. (b) (5p) Calculate the heat produced by the heater in an hour.

Answers

Answer:

a)   I = 0.01029 A , b)   Q = 4074.05 J

Explanation:

a) Let's work in parts, let's start by looking for the energy consumed.

For this we use a rule of three or direct proportions if 1 kWh costs $ 0.09, how much kWh is $ 8.80

           Energy = 8.80 / 0.09

           Energy = 97,778 kWh

to calculate the current, we must have the energy consumed per second

           

Let's use a rule of three if 97,778 kWh were consumed in 24 h = 86,400 s how much was consumed in 1 s

            E₀ = 97.778 1/86400

            E₀ = 1.13168 Ws

           

the power consumed is

           P = E₀ / t

           P = 1.13168 / 1

           P = 1.13168 W

power is

           P = I V

           I = P / V

           I = 1.13168 / 110

           I = 0.01029 A

b) the heat is given by

     

           

as the efficiency is 100%

          E = P t = Q

          Q = 1.131368 3600

          Q = 4074.05 J

A disc rotates about a fixed axis with an initial angular velocity of 5.0 rad/s counterclockwise. Upon completing 2 revolutions, the disc has an angular velocity of 2.5 rad/s.
(a) Find the angular acceleration of the disc. (Ans : -0.75 rad/s2 )
(b) Calculate the time taken by the disc to complete the 2 revolutions. (Ans : 3.33 s)
(c) If the disc maintains the same constant angular acceleration until it reaches 2.5 rad/s clockwise, sketch the graph of angular velocity versus time from 5.0 rad/s counterclockwise to 2.5 rad/s clockwise.

Answers

Answer:

A

Explanation:


A 7.00-kg block is stacked on top of the 2.90-kg block. What is the magnitude Fof the force, acting horizontally on the 2.90-kg block
as before, that is required to make the two blocks start to move together?

Answers

Answer:

F = 19.42 [N]

Explanation:

In order to solve this problem, we must first make a free body diagram and determine the forces acting on each body. In the attached image we can see the respective free body diagrams with the respective equilibrium equations.

In order to determine the value of the force, a static analysis must be performed on the block of 2.9 [kg] so that the value of the Force F can be determined.

A coefficient of friction value between the block of 2.9 [kg] and the ground must be taken into account in order to find the force F. a coefficient of friction value of 0.2 shall be taken

By the sum of forces on the Y-axis equal to zero, the value of the normal force N can be determined on the block of 2.9 [kg].

Then knowing that the frictional force is equal to the product of the normal force by the coefficient of friction, we can determine the frictional force.

By the sum of forces on the X-axis equal to zero, we can determine the value of the Force F, as seen in the equations posed in the attached image.

Note: the value of the Force F depends on the value of the coefficient of friction between surfaces.

If a force of 20 newtons moves an object 10 meters, what is the work?
A.
180 J
B.
2.00 J
C.
200 J
D. 210 J

Answers

Answer:

The answer is option C

Explanation:

The work done by an object given it's distance and force can be found by using the formula

work done = force × distance

From the question

force = 20 N

distance = 10 m

The work done is

work done = 20 × 10

We have the final answer as

200 J

Hope this helps you

How does the electric potential energy between two negatively charged
particles change if one particle's charge is reduced by a factor of 3?

Answers

Explanation:

The electric potential energy is given by :

[tex]U=\dfrac{kq_1q_2}{r}[/tex]

k is electrostatic constant

r is the distance between charges q₁ and q₂

It is clear that the potential energy is directly proportional to the charges. It means if one particle's charge is reduced by 3, its electric potential energy is reduced by 3.

Answer:

Reduced by a factor of 3.

Explanation:

Household electricity in a particular country is supplied in the form of alternating current that varies from 180 V to −180 V with a frequency of 100 cycles per second (Hz). The voltage is thus given by the equation E(t) = 180 sin(200πt) where t is the time in seconds. Voltmeters read the RMS (root-mean-square) voltage, which is the square root of the average value of [E(t)]2 over one cycle. (a) Calculate the RMS voltage of household current in this particular country. (Round your answer to the nearest whole number of volts.) V (b) Many electric stoves require an RMS voltage of 220 V. Find the corresponding amplitude A needed for the voltage E(t) = A sin(200πt). (Round your answer to the nearest whole number of volts.) A = V

Answers

Answer:

a. 127 V b 311 V

Explanation:

a. The RMS value of E(t) = 1/T∫[E(t)]². E(t) = 180 sin(200πt). Since the frequency f = 100 cycles per second, the period, T = 1/f = 1/100 = 0.01 s.

So, 1/T∫[E(t)]² = 1/T∫[180 sin(200πt)]² = 180²/0.01∫sin(200πt)]²

Using trigonometric identity sin²Ф = (1 - cos2Ф)/2 where Ф = ωt

1/T∫[E(t)]² = 180²/0.01∫(1 - cos2Ф)/2. We integrate from 0 to T, , we have

1/T∫[E(t)]² = 180²/(0.01 × 2)(t - sin2ωt/2ω)

1/T∫[E(t)]² = 180²/(0.02[(T - (sin2π)/(2 × 200π) ) - (0 - [sin(2 × 0)]/(2 × 200π))

1/T∫[E(t)]² = 180²/(0.02)[(0.01 - 0)

1/T∫[E(t)]² = 180²/2

E(t)RMS = √1/T∫[E(t)]²

= √180²/2

= 180/√2

= 127.28 V

= 127 V to the nearest whole number

b. Since E(t)(RMS) = A/√2 where A = voltage amplitude and E(t)(RMS) = 220 V,

A = √2E(t)(RMS) =

√2 × 220 V

= 311.13 V

= 311 V to the nearest whole number

The gravitational acceleration on earth is 9.8m/s. What is the weight of a car on earth (to the nearest whole number) if it has a mass of 1360kg

Answers

Answer:

1360*9.8

=13328 joules

A power boat pulls a water skier 2.6 km maintaining a
tension of 250 N in the rope to the skier. How much work is
done on the water skier by the rope?

Answers

Answer:

W = 650 [kJ]

Explanation:

The definition of work is denoted by the product of force by the distance traveled by the body, this distance traveled corresponds to the direction of the force.

In this case we have:

d = distance = 2.6[km] = 2600 [m]

F = force = 250 [N]

W = F*d = 250 * 2600 = 650000 [J] or 650 [kJ]

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this information? They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.

Answers

Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation: On Edgenuity!!

The comparison is best supported by the information given in option 4. They differ due to their atomic number.

Write about beryllium?

A star is a bright spheroid of plasma held together by gravity. The Sun is the most distant star from Earth.

Many additional stars may be seen with the normal eye at night, but their enormous distance from Earth causes them to appear as stationary points of light in the sky.

We are discussing the two-element beryllium (Be) and barium (Ba). The comparison is best supported by this information will be;

They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Hence option 4 is correct.

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The highway distance from Indianapolis to Denver is 1712 km. If the driving time is 29.25 hr, what is the average speed of the trip?

Answers

Answer:

54 miles speed

Explanation:

what does Conosive mean?​

Answers

Answer: adjective. having the quality of corroding or eating away; erosive. harmful or destructive; deleterious: the corrosive effect of poverty on their marriage. sharply sarcastic; caustic: corrosive comments on the speaker's integrity.

Explanation:

A marble is thrown straight downward off of a bridge. The marble takes 3 seconds to reach a
velocity of 55 m/s. What was the initial velocity the marble was thrown

Answers

Answer:

it should be 0

Explanation:

when it was thrown it should be 0 because it hasn't moved because it was just thrown

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Using the equation for for Newton's Second law, F=ma, solve the following problem. You have been given an object with a mass of 6g and an acceleration of 2 m/s2, what is the force?
Group of answer choices

1. 12N

2. 3N

3. 8N

4. 120N

Answers

Answer:

Should be 1.12N

Explanation:

Cause 6×2=12

Answer:

1.12 Newtons

Explanation:

F=ma, so if you convert the numbers, it's just 6 times 2.

Don't be distracted or intimidated by the units, they don't matter in this case. Force will always be in newtons, mass in grams, acceleration in m/s2 and velocity in m/s. They would only convert to their own smaller measurements.

The animal that is hunted and consumed is considered the

Answers

Predator? like they hunt their prey

Answer:

prey

Explanation:

What is the formula for finding the acceleration?

Answers

The correct answer is A=V-U/T

A baseball is hit almost straight up into the air with a speed of 23m/s. How high does it goes?

Answers

At its maximum height y, the ball has zero vertical velocity. So we have

0² - (23 m/s)² = 2 * (-g) * y

where g = 9.80 m/s² is the acceleration due to gravity. Solve for y :

y = (23 m/s)² / (2 * (9.80 m/s²))

y ≈ 27 m

The __________ of exercise determines the health and fitness benefit of the exercise. A. frequency B. intensity C. time D. type Please select the best answer from the choices provided. A B C D

Answers

Answer:

c- Time

Explanation:

The time will tell depending on the person who is exercising, the rate of time, the  workout time. & limits on weights....

Answer:

The guy above me is wrong the real answer is D

Explanation:

Other Questions
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