Answer:
2.38 mW
Explanation:
Power is work per unit time. Work is the product of force and distance. That means ...
[tex]\text{power}=\dfrac{\text{force}\times\text{distance}}{\text{time}}=\text{force}\times\dfrac{\text{distance}}{\text{time}}\\\\\text{power}=\text{force}\times\text{velocity}[/tex]
Using the given values of force and velocity, the tadpole's power output is ...
P = (0.028 N)(0.085 m/s) = 0.00238 W = 2.38 mW
The tadpole's power output is about 2.38 mW.
if two temperatures differ by 25 degrees on Celsius scale, the difference of temperature on Fahrenheit scale is?
Answer:
25 x 9/5 = 45 degrees Fahrenheit
Explanation:
How should you solve this question. Thank you!
Explanation:
a)
R total= R1 + R2 + R3 = 50 + 25 + 10 = 85
I = V/R total = 27/85 A
V1 = IR1 = 27/85 × 50 = 270/17 v
V2 = IR2 = 27/85 × 25 = 135/17 v
V3 = IR3 = 27/85 × 10 = 54/17 v
b)
R1,2 = R1.R2/(R1+R2) = 50 × 25/75 = 50/3
R total = R1,2.R3/(R1,2 + R3) = 50/3 × 10/( 50/3 + 10) = 500/80 = 25/4
I = V/R = 27/(25/4) = 108/25 A
V1 = V2 = V3 = V = 27 v
I1 = V/R1 = 27/50 A
I2 = V/R2 = 27/25 A
I3 = V/R3 = 27/10 A
Brainliest if correct
Answer:
It's is c coz the weight is equal to the normal force
Enumerate some things you can do to make work easier and faster when working with simple machines. (2 answer)
Answer:
by increasing the distance through which force is applied, by multiplying force of speed to the energy applied
The first user who answer is correct :)
How does the nature of heat explain the occurrence of high temperature in a human body that has a fever?
Answer:
People get a fever when their brain sets the body temperature higher than normal. This may happen as a reaction to germs such as viruses or bacteria, but it can also happen as a reaction to substances that are made by the body, such as prostaglandins. Our body produces prostaglandins to fight off germs
Explanation:
5) Two cables support a mass of 100kg. One cable is perfectly horizontal, while the other
makes an angle of 40 degrees above the horizontal. Find the tension in the horizontal
cable.
T sin θ = M g = W cable supporting weight
T = 100 * 9.8 / sin 40 = 1525 N
T cos θ = Th horizontal force due to cable
Th = 1525 cos 40 = 1168 N
A 4-lb collar can slide without friction along a horizontal rod and is in equilibrium at A when it is pushed 1 in. to the right and released from rest. The springs are undeformed when the collar is at A and the constant of each spring is 2800 lb/in. Determine the maximum velocity of the collar.
The maximum velocity of the collar is 0.335 m/s.
Maximum velocity of simple harmonic motion
The maximum velocity of a simple harmonic motion occurs when the object is in equilibrium position.
K.E = U
¹/₂mv² = ¹/₂kx²
mv² = kx²
where;
k is spring constant = 2800 lb/in = 316.36 N/mx is extension = 1 in = 0.0254 mm is mass = 4 lb = 1.81 kg[tex]v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{316.36 \times 0.0254^2}{1.81} }\\\\v = 0.335 \ m/s[/tex]
Thus, the maximum velocity of the collar is 0.335 m/s.
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2. Do the results by using a larger sample demonstrate the advantage of having a larger sample in the scattering experiment? Explain.
Answer: Better to have a larger sample size to precisely calculate.
Explanation: Larger sample sizes enable the researchers to more precisely calculate the expected principles of their own data and avoid errors caused by testing a small number of potentially atypical samples.
A battery is charging. Electric current enters the battery through the ______ terminal, at a ______ potential than when it exits the battery
Electric current enters the battery through the negative terminal, at a high potential than when it exits the battery.
What is Potential difference?This is the amount of work needed to move a unit charge from a reference point to a specific point against an electric field.
In a battery, electric current moves from negative to the positive terminal with the positive terminal having a higher potential which is the point where it leaves the battery.
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Siobhan wants to measure the mass of a bag of flour. What should she use?
This depends on how big the bag is. Most commonly, the bag weighs 2 kg to 10 kg or more. With this range of weight, Siobhan should use a balance to measure the mass of the flour and record the mass in kilograms. Thus, the answer is the first choice
Answer:
A weighing scale
Explanation:
A weighing scale graduated in grams or kilograms can be used.
You're collecting data in BeyondLabz for an object in free fall, subject to air resistance. How do you know when you've collected enough data points for a single run
Enough data points would have been collected when specific data for upward and downward motion are collected.
What is a Data point?A data point is a discrete unit of information. This information is always unique.
Free fallAn object subjected to free fall is under the influence of gravity. An object subjected has different time of motion for upward and downward motion.
Thus, we can conclude that enough data points would have been collected when specific data for upward and downward motion are collected.
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what is the velocity of a 0.145kg baseball if its kinetic energy is 109 j
Answer:
The velocity of the 0.145 kg baseball is 38.7743 m/s.
General Formulas and Concepts:
Energy
Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2}mv^2[/tex]
m is mass (in kg)v is velocity (in m/s)KE is kinetic energy (in J)Explanation:
Step 1: Define
Identify.
m = 0.145 kg
KE = 109 J
Step 2: Solve for v
Substitute in variables [Kinetic Energy Formula]: [tex]\displaystyle 109 \ \text{J} = \frac{1}{2}(0.145 \ \text{kg})v^2[/tex]Simplify: [tex]\displaystyle 109 \ \text{J} = (0.0725 \ \text{kg})v^2[/tex]Isolate variable term: [tex]\displaystyle 1503.45 \ \text{J/kg} = v^2[/tex]Isolate v: [tex]\displaystyle v = 38.7743 \ \text{m/s}[/tex]Topic: AP Physics 1/C
Unit: Energy
Select the correct answer.
While Jordan was playing with her favorite doll, one of its legs fell off. Now she wants to take the doll to visit the doctor. What does Jordan's
thought process demonstrate?
O A. logic
OB. animism
O C. classification
OD. conservation
A rectangular box has side 10cm x 5cm x 2cm. If it lies on a horizontal surface and has weight 1.00N, calculate the maximum and Minimum pressure it exerts on the Surface
Answer:
P max = 1000 pa
P min = 200 pa
Explanation:
P = F/A
pressure will be maximum when surface gets minimum. so to find the maximum amount of pressure we need to calculate the minimum surface. it is 2cm×5cm = 10cm² = 0.001m² . then we have:
P = 1 / 0.001 = 1000 pa
to find minimum pressure the surface that must be chosen is 10cm×5cm = 50cm² = 0.005m² .
P = 1 / 0.005 = 200 pa
Two students side in carts opposite to one another in a spinning Ferris wheel as shown.
Student A is originally at the bottom of the Ferris wheel while student B is at the top of the Ferris wheel. As the wheel turns, student B comes to the bottom white student A arrives at the top, as shown. The Ferris wheel spins at a constant speed so the two students are traveling with constant speed. Students A and B have masses ma and mb, respectively. The Ferris wheel has a radius R. What is the magnitude of the TOTAL work done on student A in moving from the bottom to the top of the Ferris wheel? The total work is the sum of the work done by all the forces on the body; i.e. Wtotal = sum(Fd). Neglect air resistance.
Also, what is the sign of the work done on student B by the Ferris wheel in moving from the top to the bottom?
Net work done on student B by the Ferris wheel in moving from the top to the bottom is mathematically given as
net work done on A =0.
Net work doneGenerally the equation for the work energy theorem is mathematically given as
net work done on A = change in kinetic energy of A.
Where, angular velocity is constant.
change in kinetic energy = 0.
Hence, from work energy theorem,
net work done on A =0.
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with the aim of a diagram describe how a rain bow is formed
Answer:
Water droplets acts as tiny prism in the sky. The sunlight when enters these tiny droplets undergo internal reflection and also refract these rays which are dispersed causing a band of seven colors called rainbow.
Explanation:
Answer:
it us formed after the rain
A disk at rest experiences constant angular acceleration for t = 25 s, at the end of which it is spinning with a frequency of f = 55 rpm. Please answer the following questions.
A)Write a general expression for the magnitude of the angular velocity of the disk after the acceleration in terms of frequency.
B)Calculate the magnitude of the angular velocity of the disk in rad/s at time t = 25 s.
C)Write a general expression for the average angular acceleration of the disk αave in terms of angular velocity.
D) Calculate the magnitude of the average angular acceleration of the disk αave from rest to t = 25 s in rad/s2.
E)Write a general expression for the period T of the disk in terms of frequency f.
F)Calculate the magnitude of the period of the disk T at time t = 25 s in seconds.
(a) A general expression for the magnitude of the angular velocity of the disk is 2πf.
(b) The magnitude of the angular velocity of the disk is 5.76 rad/s.
(c) A general expression for the average angular acceleration of the disk is ω/t.
(d) The magnitude of the average angular acceleration of the disk is 0.23 rad/s².
(e) A general expression for the period T of the disk is 1/f.
(f) The magnitude of the period of the disk is 0.17 s.
Angular velocity
The angular velocity of the disk is the rate of change of angular displacement with time.
ω = 2πf
where;
f is the frequency
[tex]\omega = 2\pi \times 55\frac{rev}{\min} \times \frac{1 \min}{60 \ s} = 5.76 \ rad/s[/tex]
The angular velocity of the disk at time, t = 25 s is 5.76 rad/s.
Average angular acceleration of the disk[tex]\alpha = \frac{\Delta \omega }{t} \\\\\alpha = \frac{5.76}{25} \\\\\alpha = 0.23 \ rad/s^2[/tex]
Period of the diskT = 1/f
T = 1/5.76
T = 0.17 s
Thus, the period of the disk at time t = 25 s is 0.17 s.
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Perform an experiment in which you flip a switch 2,300,000 times. Write this
number in scientific notation.
O A. 23 x 10-6
O B. 2.3 x 106
O C. 0.23 x 105
O D. 0.23 x 106
Answer:
B. 2.3 x 10⁶
Explanation:
To calculate scientific notation for the number 2,300,000, we have to follow this notation
a × 10^bStep 1 :
To find a we have to write the non-zero digits placing a decimal after the first non-zero digit.
2,300,000 to 2.300000Step 2 :
Now, to find b count how many numbers of digits are there to the right of the decimal.
2.300000Hence, there are 6 digits to the right of the decimal.
Step 3 :
Since, we had found the value of a and b, we can now reconstruct the number into scientific notation.
a = 2.3
b = 6
2.3 × 10⁶Therefore, option b is correct.
The diagram shows a negative charge moving in a magnetic field.
Parallel vectors evenly spaced labeled B. There is a circle labeled v.
In which direction is the magnetic force acting on the charge?
right
left
into the screen
out of the screen
Answer:
Left
Explanation:
right on edge
Answer:
left
Explanation:
A sphere of mass M 5 1.00 kg is supported by a string that passes over a pulley at the end of a horizontal rod of length L 5 0.300 m (Fig. P17.15). The string makes an angle u 5 35.08 with the rod. The fundamental frequency of standing waves in the portion of the string above the rod is f 5 60.0 Hz. Find the mass of the portion of the string above the rod.
A fundamental frequency of 60 Hz, attached mass of 1 kg., rod length of
0.3 m gives the mass of the part of the string as 3.245 × 10⁻³ kg.
Response:
The mass of the string, m ≈ 3.245 × 10⁻³ kgHow can the mass of the part of the string be calculated?The given parameters are;
Mass of the sphere, M = 1.00 kg
Length of the rod, L = 0.300 m
Angle the string makes with the rod, θ = 35°
The fundamental frequency of the standing wave in the portion of the
string above the rod, f₁ = 60.0 Hz
Required;
The mass of the portion of the string above the rod
Solution:
The fundamental frequency in a string is given as follows;
[tex]f_1 = \mathbf{\dfrac{\sqrt{\dfrac{T}{m/l} } }{2 \cdot l}}[/tex]Where;
T = The tension in the string
m = The mass of the string
l = The length of the string
[tex]The \ tension \ in \ the \ string, \ T= \mathbf{\dfrac{M \cdot g}{sin(\theta)}}[/tex]Which gives;
[tex]T= \mathbf{\dfrac{1 \times 9.81}{sin(35)}} \approx 17.1[/tex]
The tension in the string, T ≈ 17.1 N
[tex]The \ length \ of \ the \ string, \ l=\mathbf{\dfrac{L}{cos(\theta)}}[/tex]
Therefore;
[tex]l=\dfrac{0.300}{cos \left(35^{\circ} \right)} \approx 0.366[/tex]
Therefore;
[tex]60.0 = \mathbf{\dfrac{\sqrt{\dfrac{17.1}{m/0.366} } }{2 \times 0.366}}[/tex]
Which gives;
[tex]m = \dfrac{17.1}{(60.0 \times 2 \times 0.366)^2} \times 0.366 \approx 3.245 \times 10^{-3}[/tex]
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Gravity is a force that opposes motion. true or false?
Answer:
true,because when the gravity of an object is changed the motion of the object changes
Suppose that Salim hits a 100 g fastball moving towards him at a speed of 42 m/s with his bat as shown in the image.the impulse of the fastball is 8 kg.m/s in the antiparallel direction of the initial velocity. Then the final momentum of the fastball is --------------( Suppose that the direction of the fastball toward the bat is negative and away from the bat is positive)
1.8 kg m/s
0.6 kg m/s
3.8 kg m/s
2.4 kg m/s
The final momentum of the ball is 3.8 kgm/s.
Change in momentum of the ballThe impulse received by the ball is equal to change in momentum of the ball.
J = ΔP
where;
J is the impulseΔP is change in momentumΔP = P₂ - P₁
P₂ = ΔP + P₁
Final momentum of the ballThe final momentum of the ball is calculated as follows;
P₂ = 8 + (- 0.1 x 42)
P₂ = 8 - 4.2
P₂ = 3.8 kgm/s
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A half-ring (semicircle) of uniformly distributed charge Q has radius R. What is the electric potential at its center
The electric potential at the center of the half-ring is [tex]\frac{kQ}{R}[/tex].
Electric force experienced by the chargeThe force experienced by the charge is calculated by Coulomb's law;
[tex]F = \frac{kQ^2}{R^2}[/tex]
Electric field strengthThe electric field strength is force per unit charge;
[tex]E = \frac{F}{Q} = \frac{kQ}{R^2}[/tex]
What is electric potential?The electric potential is work done in moving a charge from infinity to a certain point.
V = Ed
[tex]V = \frac{kQ}{R^2} \times R\\\\V = \frac{kQ}{R}[/tex]
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A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine:
The magnitude of the tension in the string is 9.31 N.
Tension in the stringThe magnitude of the tension in the string in the horizontal circle formed by the turn table is calculated as follows;
T = Fcos(θ)
where;
F is centripetal forceθ is inclination of the string[tex]T = \frac{mv^2}{r} \times cos(\theta)\\\\T = \frac{3 \times 4.5^2}{5} \times cos(40)\\\\T = 9.31 \ N[/tex]
Thus, the magnitude of the tension in the string is 9.31 N.
The complete question is below:
A rotating turntable (rt=4.50 m) is rotating at a constant rate. At the edge of the turntable is a mass (m = 3.00 kg) on the end of a 5.00 m - long string (L). If theta = 40.0o,determine the magnitude of the tension in the string.
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Suppose that you want to build a transformer that will convert 70 V power coming in the primary coil to 245 V power going out of the secondary coil. What is the smallest total number of turns (primary turns plus secondary turns) you need to create the transformer
Answer: 9 Turns
Explanation: primary turns + secondary turns.
The smallest total number of turns (primary turns plus secondary turns) you will need to build the transformer is 9 turns
Data obtained from the question Primary voltage (Vₚ) = 70 VSecondary voltage (Vₛ) = 245 VTotal turns =? How to determine the primary and secondary turns Primary voltage (Vₚ) = 70 VSecondary voltage (Vₛ) = 245 VPrimary turns (Nₚ) =? Secondary turns (Nₛ) =?Nₛ / Nₚ = Vₛ / Vₚ
Nₛ / Nₚ = 245 / 70
Nₛ / Nₚ = 7 / 2
Thus,
Primary turns (Nₚ) = 2 turns Secondary turns (Nₛ) = 7 turnsHow to determine the total turns Primary turns (Nₚ) = 2 turns Secondary turns (Nₛ) = 7 turnsTotal turns =?Total turns = Nₚ + Nₛ
Total turns = 2 + 7
Total turns = 9 turns
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What problem did the crew of Biosphere 2 face?
A virus from one of the animals
A loss of oxygen
One of the crew members developed cancer
The crew ran out of food.
A bridge that was 5m long has been washed out by a heavy rain. The road on the
far side of the stream is 2m lower that the road the car starts on. How fast must
the car be going to successfully jump the stream?
What would a wave with a low amplitude sound like?
A It would sound quiet.
B It would sound loud.
C It would sound squeaky.
D It would sound deep.
Answer: Your answer is A. it would sound quiet.
Hope this helps!
Answer:
I think a but not sure
Explanation:
The amplitude of a sound wave determines its loudness or volume. A larger amplitude means a louder sound, and a smaller amplitude means a softer sound.
The philosopher Robert Nozick imagined an “experience machine” to show that a core feature of utilitarianism (as conceived by Bentham and Mill) does not conform with most people’s intuitions about “the good life.” Which of these core features of utilitarianism was Nozick’s main target?
Robert Nozick opines that individuals own themselves and hence have a right to own property.
What is utilitarianism?The term utilitarianism refers to the philosophical ideology that in the use of commodities, the best options is that which maximizes utility or satisfaction derived from the commodity.
In the position of Robert Nozick, utilitarianism means that individuals own themselves and hence have a right to own property.
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The rear wheel of a 150 kg tricycle accidentally ran over a nail. The circular tip of the nail has a diameter of 0.001 m. How much pressure did the wheel of the tricycle experience assuming that the entire weight of the tricycle is concentrated on the rear wheel that ran over the nail.
The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m²
Pressure can be defined as the force acting perpendicular per unit area on the surface of a body. The S.I unit of pressure is N/m²
To calculate the pressure of the wheel of the tricycle, we use the formula below
Formula:
P = 4mg/πd².............. Equation 1Where:
P = Pressure of the tricycle wheelm = mass of the wheeld = diameter of the wheelg = acceleration due to gravityπ = pie.From the question,
Given:
m = 150 kgd = 0.001 mg = 9.8 m/s²π = 3.14Substitute these values into equation 1
P = 4(150)(9.8)/(0.001²×3.14)P = 5880/0.00000314P = 1.85×10¹⁰ N/m²Hence, The pressure experienced by the wheel of the tricycle is 1.85×10¹⁰ N/m².
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