If v is the truck's final velocity, then
v² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)
v² = 1604 m²/s²
v = 40.05 m/s ≈ 40 m/s
What is the formula for finding the acceleration?
A wildebeest runs with an average speed of
4.0
m
s
4.0
s
m
What was its distance travelled in meters?
Household electricity in a particular country is supplied in the form of alternating current that varies from 180 V to −180 V with a frequency of 100 cycles per second (Hz). The voltage is thus given by the equation E(t) = 180 sin(200πt) where t is the time in seconds. Voltmeters read the RMS (root-mean-square) voltage, which is the square root of the average value of [E(t)]2 over one cycle. (a) Calculate the RMS voltage of household current in this particular country. (Round your answer to the nearest whole number of volts.) V (b) Many electric stoves require an RMS voltage of 220 V. Find the corresponding amplitude A needed for the voltage E(t) = A sin(200πt). (Round your answer to the nearest whole number of volts.) A = V
Answer:
a. 127 V b 311 V
Explanation:
a. The RMS value of E(t) = 1/T∫[E(t)]². E(t) = 180 sin(200πt). Since the frequency f = 100 cycles per second, the period, T = 1/f = 1/100 = 0.01 s.
So, 1/T∫[E(t)]² = 1/T∫[180 sin(200πt)]² = 180²/0.01∫sin(200πt)]²
Using trigonometric identity sin²Ф = (1 - cos2Ф)/2 where Ф = ωt
1/T∫[E(t)]² = 180²/0.01∫(1 - cos2Ф)/2. We integrate from 0 to T, , we have
1/T∫[E(t)]² = 180²/(0.01 × 2)(t - sin2ωt/2ω)
1/T∫[E(t)]² = 180²/(0.02[(T - (sin2π)/(2 × 200π) ) - (0 - [sin(2 × 0)]/(2 × 200π))
1/T∫[E(t)]² = 180²/(0.02)[(0.01 - 0)
1/T∫[E(t)]² = 180²/2
E(t)RMS = √1/T∫[E(t)]²
= √180²/2
= 180/√2
= 127.28 V
= 127 V to the nearest whole number
b. Since E(t)(RMS) = A/√2 where A = voltage amplitude and E(t)(RMS) = 220 V,
A = √2E(t)(RMS) =
√2 × 220 V
= 311.13 V
= 311 V to the nearest whole number
(a) Is the velocity of car A greater than, less than, or the same as the
velocity of car B?
(b) Is the initial position of car A greater than, less than, or equal to the
initial position of car B?
(c) In the time period from t = 0 tot = 1 s, is car A ahead of car B,
behind car B, or at the same position as car B?
Answer:
a. less than, b. greater than, c. ahead
Explanation:
a. ) Is the velocity of car A less than the velocity of car B b. the initial position of car A greater than the initial position of car B c. ahead In the time period from t = 0 tot = 1 s, is car A ahead of car B?.
what is velocity ?Velocity is the parameter which is different from speed, can be defined as the rate at which the position of the object is changed with respect to time, it is basically speeding the object in a specific direction in a specific rate.
Velocity is a vector quantity which shows both magnitude and direction and The SI unit of velocity is meter per second (ms-1). If there is a change in magnitude or the direction of velocity of a body, then it is said to be accelerating.
Finding the final velocity is simple but few calculations and basic conceptual knowledge are needed.
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An object that has the ability to do work has __________ energy. (4 points)
a. magnetic
b. kinetic
c. potential
d. electrical
Answer:
c. potential
Explanation:
The highway distance from Indianapolis to Denver is 1712 km. If the driving time is 29.25 hr, what is the average speed of the trip?
Answer:
54 miles speed
Explanation:
The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this information? They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.
Answer: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.
Explanation: On Edgenuity!!
The comparison is best supported by the information given in option 4. They differ due to their atomic number.
Write about beryllium?A star is a bright spheroid of plasma held together by gravity. The Sun is the most distant star from Earth.
Many additional stars may be seen with the normal eye at night, but their enormous distance from Earth causes them to appear as stationary points of light in the sky.
We are discussing the two-element beryllium (Be) and barium (Ba). The comparison is best supported by this information will be;
They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.
Hence option 4 is correct.
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A 70-m-long chain hangs vertically from a cylinder attached to a winch. Assume there is no friction in the system and that the chain has a density of 5 kg/m. Use 9.8 m/s2 for the acceleration due to gravity. a. How much work is required to wind the entire chain onto the cylinder using the winch? b. How much work is required to wind the chain onto the cylinder if a 35-kg block is attached to the end of the chain?
Answer:
a) The work required to wind the entire chain onto the cylinder using the winch is 120135.75 joules, b) The work required to wind the chain plus the block is 144162.9 joules.
Explanation:
a) Let be an infinitesimal part of the long chain, whose gravitational potential energy is:
[tex]dU_{g} = g\cdot z \,\delta m[/tex]
Where:
[tex]U_{g}[/tex] - Gravitational potential energy, measured in joules.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]m[/tex] - Mass of the long chain, measured in kilograms.
[tex]z[/tex] - Height of the portion of the long chain with respect to ground, measured in meters.
Since chain has an uniform linear density, this differential expression can be rewritten as:
[tex]dU_{g} = \lambda\cdot g \cdot z \, dz[/tex]
Where [tex]\lambda[/tex] is the linear density, measured in kilograms per meter.
We obtain the gravitational potential energy to wind the chain onto the cylinder by integration:
[tex]\Delta U_{g, chain} = \lambda\cdot g \int\limits^{z_{f}}_{z_{o}} {z} \, dz[/tex]
[tex]\Delta U_{g, chain} = \frac{\lambda\cdot g}{2} \cdot (z_{f}^{2}-z_{o}^{2})[/tex]
Where:
[tex]\Delta U_{g, chain}[/tex] - Gravitational potential energy of the entire chain, measured in joules.
[tex]z_{o}[/tex] - Initial height with respect to ground, measured in meters.
[tex]z_{f}[/tex] - Final height with respect to ground, measured in meters.
From the Work-Energy Theorem we get that work needed to wind the entire chain equals the gravitational potential energy of the entire chain:
[tex]W = \Delta U_{g, chain}[/tex]
[tex]W = \frac{\lambda\cdot g}{2} \cdot (z_{f}^{2}-z_{o}^{2})[/tex]
If we know that [tex]\lambda = 5\,\frac{kg}{m}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex] and [tex]z_{f} = 70\,m[/tex], the work needed is:
[tex]W = \frac{\left(5\,\frac{kg}{m} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{2} \cdot [(70\,m)^{2}-(0\,m)^{2}][/tex]
[tex]W = 120135.75\,J[/tex]
The work required to wind the entire chain onto the cylinder using the winch is 120135.75 joules.
b) The gravitational potential energy of the block, measured in joules, is:
[tex]\Delta U_{g,block} = m_{block}\cdot g \cdot (z_{f}-z_{o})[/tex]
Where:
[tex]m_{block}[/tex] - Mass of the block, measured in kilograms.
[tex]z_{o}[/tex] - Initial height with respect to ground, measured in meters.
[tex]z_{f}[/tex] - Final height with respect to ground, measured in meters.
According to the Work-Energy Theorem, the work needed to wind the chain plus the block equals the sum of both gravitational potential energies:
[tex]W = \Delta U_{g, chain}+U_{g,block}[/tex]
[tex]W = \frac{\lambda \cdot g}{2}\cdot (z_{f}^{2}-z_{o}^{2})+m_{block}\cdot g \cdot (z_{f}-z_{o})[/tex]
If we know that [tex]\lambda = 5\,\frac{kg}{m}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]z_{o} = 0\,m[/tex], [tex]z_{f} = 70\,m[/tex] and [tex]m_{block} = 35\,kg[/tex], the work required to wind the chain onto the cylinder if a block is attached to the end of the chain is:
[tex]W = \frac{\left(5\,\frac{kg}{m} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{2}\cdot [(70\,m)^{2}-(0\,m)^{2}]+(35\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (70\,m-0\,m)[/tex]
[tex]W = 144162.9\,J[/tex]
The work required to wind the chain plus the block is 144162.9 joules.
How much force is needed to keep a 25 N rock moving with constant speed across the level, frictionless ice?
Answer:
Explanation:
Hello friend!!!!!
The answer is 0 Newton
hope this helps
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what is the difference between weak and strong forces I need help now I will give brainliest
Answer:
weak forces are more close to loosing and strong forces are more close to wining
Explanation:
a weak force probably has less staingh than the stronger force hats probably because they don't get enough people to fight, they don't have strong weapons, or they are not getting medical treatment that probably means they are sick some may have a disease and can spread they may not have food water or other supplies.
A 7.00-kg block is stacked on top of the 2.90-kg block. What is the magnitude Fof the force, acting horizontally on the 2.90-kg block
as before, that is required to make the two blocks start to move together?
Answer:
F = 19.42 [N]
Explanation:
In order to solve this problem, we must first make a free body diagram and determine the forces acting on each body. In the attached image we can see the respective free body diagrams with the respective equilibrium equations.
In order to determine the value of the force, a static analysis must be performed on the block of 2.9 [kg] so that the value of the Force F can be determined.
A coefficient of friction value between the block of 2.9 [kg] and the ground must be taken into account in order to find the force F. a coefficient of friction value of 0.2 shall be taken
By the sum of forces on the Y-axis equal to zero, the value of the normal force N can be determined on the block of 2.9 [kg].
Then knowing that the frictional force is equal to the product of the normal force by the coefficient of friction, we can determine the frictional force.
By the sum of forces on the X-axis equal to zero, we can determine the value of the Force F, as seen in the equations posed in the attached image.
Note: the value of the Force F depends on the value of the coefficient of friction between surfaces.
A marble is thrown straight downward off of a bridge. The marble takes 3 seconds to reach a
velocity of 55 m/s. What was the initial velocity the marble was thrown
Answer:
it should be 0
Explanation:
when it was thrown it should be 0 because it hasn't moved because it was just thrown
As θ increases towards 90 what happens to the horizontal and vertical components of F?
Horizontal component , F cos θ.
Vertical component , F sin θ.
Now, as θ increases towards 90° cos θ decreases and
As θ increases towards 90° sin θ increases.
Therefore, horizontal component of F will decrease and vertical component will increase.
Hence, this is the required solution.
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Using the equation for for Newton's Second law, F=ma, solve the following problem. You have been given an object with a mass of 6g and an acceleration of 2 m/s2, what is the force?
Group of answer choices
1. 12N
2. 3N
3. 8N
4. 120N
Answer:
Should be 1.12N
Explanation:
Cause 6×2=12
Answer:
1.12 Newtons
Explanation:
F=ma, so if you convert the numbers, it's just 6 times 2.
Don't be distracted or intimidated by the units, they don't matter in this case. Force will always be in newtons, mass in grams, acceleration in m/s2 and velocity in m/s. They would only convert to their own smaller measurements.
The animal that is hunted and consumed is considered the
Predator? like they hunt their prey
Answer:
prey
Explanation:
An automobile is traveling at a constant 15 m/s, then it undergoes acceleration from that moment forward. Which statement best describes the automobile's new motion?
Answer:
d
Explanation:
We are required to write a statement that best describes the automobile's new motion.
The statement that best describes the automobile's new motion is uniform acceleration.
Motion is the change of position of a body or object with time.
Uniform Acceleration is defined as the motion of an object whose velocity increases by equal amounts in equal intervals of time, however small the time intervals may be.
The best statement to describe the automobile's new motion is called Uniform Acceleration
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I need help with this physics question, "A skateboarder rolled down the sidewalk with an initial velocity of 2.5m/s. If her acceleration was 1.7 m/s^2, what was her velocity after she had skated 130m?"
Recall that
[tex]{v_f}^2={v_i}^2+2a\Delta x[/tex]
where [tex]v_i[/tex] and [tex]v_f[/tex] are the skateboarder's velocity, respectively; [tex]a[/tex] is her acceleration; and [tex]\Delta x[/tex] is the change in her position.
Substitute everything you know and solve for [tex]v_f[/tex]:
[tex]{v_f}^2=\left(2.5\dfrac{\rm m}{\rm s}\right)^2+2\left(1.7\dfrac{\rm m}{\mathrm s^2}\right)(130\,\mathrm m)\implies v_f=448.25\dfrac{\mathrm m^2}{\mathrm s^2}\implies\boxed{v_f\approx21\dfrac{\rm m}{\rm s}}[/tex]
A cube measures 3 cm on each side and has a mass of 25 g. What is its density.
Answer:
The density is: [tex]0.926 \,\frac{g}{cm^3}[/tex]
Explanation:
Recall that density is defined as the quotient of the object's mass divided by volume. So, we calculate the volume of the 3 cm side cube:
[tex]Vol = (3 \,cm)^3 = 27 \,\,cm^3[/tex]
then the density becomes:
[tex]density=\frac{mass}{Vol} =\frac{25}{27} \,\frac{g}{cm^3} \approx 0.926 \,\frac{g}{cm^3}[/tex]
104 kg and a volume of 1,278 m3 what is the density
Answer: 0.081 kilogram/cubic meter
Explanation: p=m/v so 104/1278 is 0.081377151799687 or 0.081.
An airport has a moving walkway in a long corridor (of lengthL) designed to savepassengers time. If Tom walks through the corridor (not on the moving walkway), it takes him150 s to reach the far end. If Tom stands on the moving walkway, it takes him 100 s to reach thefar end. How long would it take Tom to reach the far end if he got on the moving walkway andwalked at his normal speed relative to the walkway itself?
Answer: 60 seconds
Explanation:
The following information can be derived from the question:
rt=d,
150r = 100
Divide through by 150
r = 100/150
r = 0.67
r = 0.67 feet/second
Fir the second part of the question,
100r=100
r = 100/100
r = 1
r= 1 feet/second
combined rate will now be:
= 0.67+1
= 1.67 feet/second
We then slot it back into the formula
rt = d
1.67t = 100
t = 100/1.67
t= 59.88 seconds
t = 60 seconds approximately
The gravitational acceleration on earth is 9.8m/s. What is the weight of a car on earth (to the nearest whole number) if it has a mass of 1360kg
Answer:
1360*9.8
=13328 joules
A house is maintained at a comfortable temperature by means of an electrical resistor heater during winter. The heater is operated at a constant current (I) under an applied voltage of 110 V. For simplicity, let us assume that the heater operates at a steady state, with 100% of conversion efficiency from the electrical energy to the internal energy of air in the house. (a) (5p) Find I if the homeowner pays $8.80/day for heating, with electricity cost $0.09/kWh. (b) (5p) Calculate the heat produced by the heater in an hour.
Answer:
a) I = 0.01029 A , b) Q = 4074.05 J
Explanation:
a) Let's work in parts, let's start by looking for the energy consumed.
For this we use a rule of three or direct proportions if 1 kWh costs $ 0.09, how much kWh is $ 8.80
Energy = 8.80 / 0.09
Energy = 97,778 kWh
to calculate the current, we must have the energy consumed per second
Let's use a rule of three if 97,778 kWh were consumed in 24 h = 86,400 s how much was consumed in 1 s
E₀ = 97.778 1/86400
E₀ = 1.13168 Ws
the power consumed is
P = E₀ / t
P = 1.13168 / 1
P = 1.13168 W
power is
P = I V
I = P / V
I = 1.13168 / 110
I = 0.01029 A
b) the heat is given by
as the efficiency is 100%
E = P t = Q
Q = 1.131368 3600
Q = 4074.05 J
______ Is the degree of exactness of a measurement; _____ Describes how well the results of measurement agree with the real value
A: accuracy, precision
B: Percision, accuracy
C: accuracy, the line of best fit
D: Percision, the line of best fit
Answer: is B. Precision, accuracy
Explanation: Precision is the degree of exactness of a measurement; Accuracy describes how well the results of a measurement agree with the real value.
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In the context of measurements, accuracy and precision are two different concepts that describe different aspects of the quality or reliability of the results obtained. The correct answer is A
Accuracy refers to how close the measured value is to the true or accepted value. It is a measure of how well the measurement reflects the actual quantity being measured. If a measurement is accurate, it means that it is on target and has a minimal deviation from the true value.
Precision, on the other hand, refers to the degree of exactness or consistency in the measurements. It measures the level of repeatability and reproducibility of the results. A precise measurement has very little variation or scatter between repeated measurements of the same quantity. Precision does not necessarily guarantee accuracy.
To summarize:
Accuracy relates to the closeness of a measurement to the true or accepted value.
Precision relates to the consistency and reproducibility of the results obtained.
In the given options, the correct answer is A: accuracy, precision. Accuracy describes how well the results of measurement agree with the real value, while precision is the degree of exactness of a measurement.
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A disc rotates about a fixed axis with an initial angular velocity of 5.0 rad/s counterclockwise. Upon completing 2 revolutions, the disc has an angular velocity of 2.5 rad/s.
(a) Find the angular acceleration of the disc. (Ans : -0.75 rad/s2 )
(b) Calculate the time taken by the disc to complete the 2 revolutions. (Ans : 3.33 s)
(c) If the disc maintains the same constant angular acceleration until it reaches 2.5 rad/s clockwise, sketch the graph of angular velocity versus time from 5.0 rad/s counterclockwise to 2.5 rad/s clockwise.
Answer:
A
Explanation:
It’s important to measure exercise shoes with the type of exercise in which you will be participating.
Answer:
True
Explanation
the right shoes will help with the comfort & it will help with limits you have on your legs.. Weights, posture,& will help with injury...
can result.
When lost fluid is not replaced adequately,
A. heat stroke
B. hypothermia
C. dehydration
D. emphysema
Answer:
Dehydration could possibly take place if lost fluid is not replaced adequately. Hypothermia can not possibly take place due to loss of fluid. Nor can emphysema. So, dehydration looks to be the more suitable answer
A baseball is hit almost straight up into the air with a speed of 23m/s. How high does it goes?
At its maximum height y, the ball has zero vertical velocity. So we have
0² - (23 m/s)² = 2 * (-g) * y
where g = 9.80 m/s² is the acceleration due to gravity. Solve for y :
y = (23 m/s)² / (2 * (9.80 m/s²))
y ≈ 27 m
If a force of 20 newtons moves an object 10 meters, what is the work?
A.
180 J
B.
2.00 J
C.
200 J
D. 210 J
Answer:
The answer is option CExplanation:
The work done by an object given it's distance and force can be found by using the formula
work done = force × distanceFrom the question
force = 20 N
distance = 10 m
The work done is
work done = 20 × 10
We have the final answer as
200 JHope this helps you
A maser is a laser-type device that produces electromagnetic waves with frequencies in the microwave and radio-wave bands of the electromagnetic spectrum. You can use the radio waves generated by a hydrogen maser as a standard of frequency. The frequency of these waves is 1,420,405,751.786 hertz. (A hertz is another name for one cycle per second.) A clock controlled by a hydrogen maser is off by only 1 s in 100,000 years. (The large number of significant figures given for the frequency simply illustrates the remarkable accuracy to which it has been measured.)A. What is the time for one cycle of the radio wave? Express your answer to three significant figures and include the appropriate units.B. How many cycles occur in 4 h ? Express your answer using three significant figures.C. How many cycles would have occurred during the age of the earth, which is estimated to be 4.6×109 years? Express your answer using three significant figures.D. By how many seconds would a hydrogen maser clock be off after a time interval equal to the age of the earth? Express your answer using three significant figures.
Answer:
a) t₀ = 0.704 10⁻¹² s, b) #cycle = 2.05 10¹⁶ cycles ,
c) #_cycles = 7,418 10³² cycles, d) Δt = 4.6 10⁴ s
Explanation:
For this exercise we must use the relationship between the period and the frequency
f = 1 / T
T = 1 / f
let's apply this equation to our case
a) The time of a cycle is
t = 1 / 1.420405 10¹²
t₀ = 0.704 10⁻¹² s
b) number of cycles in 4 h
t = 4 h (3600 s / 1h) = 14400 s
Let's use a direct rule of proportions (rule of three). If there is 1 cycle in t₀, how much cycle is there
#_cycles = t (1 / t₀)
#_cycle = 14400 s (1 cycle / 0.704 10⁻¹² s)
#_cycle = 2.0454 10¹⁶ cycles
#cycle = 2.05 10¹⁶ cycles
c) cycles since the age of the Earth
t = 4.6 10⁹ years (365 days / year) (24 h / 1 day) (3600 s / 1 h)
t = 5.2224 10²⁰ s
#_cycles = t (1 / to)
# _cycles = 5.2224 10²⁰ (1 / 0.704 10⁻¹²)
#_cycles = 7,418 10³² cycles
d) Let's use the direct proportion rule. If you have a lag of Δt₁ = 1s at t₁ = 1 10⁵ years, what is the lag (Δt) at t = 4.6 10⁹ years
Δt = t (Δt₁ / t₁)
Δt = 4.6 10⁹ years (1 s / 10⁵ years)
Δt = 4.6 10⁴ s
Question 4 (1 point)
Having the ability to play or stay active longer without getting tired explains which
Health-Related Fitness Component?
cardiovascular endurance :))
