a uniformly charged conducting sphere of 1.22 m radius has a surface charge density of 8.13 c/m*. (a) find the charge on the sphere. (4) what ts the total electric flux leaving the surface of the sphere? (c) calculate the electric field at the surface of the sphere.

Answers

Answer 1

We select a spherical-shaped Gaussian surface that is concentric with the conducting sphere and has a little bigger radius. Gauss's law determines the flux:

ϕ= ϵ 0 q \s​ = 8.85×10 −12 C 2 /N.m 2

3.66×10 −5 C =4.1×10 6 N.m 2 /C

What makes it the Gauss law?

Gauss' Law, which bears the name of German physicist Carl Friedrich Gauss, is the third of Maxwell's four equations. According to Gauss' Law, an electric charge, qv, or static electricity, produces an electric field, E. (voltage). According to this equation, adding more charge will result in a larger electric field.

According to Gauss's Law, the flux of an electric field through a closed surface equals the contained charge divided by a constant.

Gauss's Law may be used to determine the field due to four different types of equally charged objects: a straight wire, an infinite plate sheet, a thin spherical shell, and a low evenly charged sphere.

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Related Questions

two blocks are released from the top of a building. one falls straight down while the other slides down a smooth ramp. if all friction is ignored, which one is moving faster when it reaches the bottom?

Answers

The first and second blocks move at the same speed.

What is the law of conservation of mechanical energy ?

The law of conservation of mechanical energy states that the total mechanical energy of a system is constant if the only forces acting on the system are conservative.

The total mechanical energy of a system is the sum of kinetic and potential energy.

E = KE + PE

This is the total energy, kinetic energy and potential energy of the system.

The kinetic energy of the

system is:

KE = 1/2 x m x v^{2}

This is the mass and velocity of the object.

The gravitational potential energy is:

PE = mgh

Here is the acceleration of gravity and altitude.

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a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east. a. what is her resultant displacement? b. what is the total distance she travels?

Answers

After a girl delivering newspapers travels three blocks west, four blocks north, and then six blocks east, her total displacement is 5 blocks. While the total distance covered is 13 blocks.

What is displacement?

A displacement is a vector in geometry and mechanics whose length is the smallest distance between the beginning and final positions of a moving point P.

If an item moves relative to a reference frame, such as a lecturer moving to the right of a whiteboard or a passenger moving toward the back of an airliner, the object's location changes. This shift in location is referred to as displacement.

Displacement (change in position) = Last position – initial position

To Calculate displacement, let displacement be (d)

d = -3i + 4j + 6i (-i because she turned west, +i because she turned east)

d = 3i + 4j

d = √(3² + 4²)

d = √(9 + 16)

d = √25

d = 5 blocks.

Total distance (Td_  = Sum of all the blocks traveled.

Td = 3 + 4 + 6

Td = 13 blocks.

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In general, how should you shuffle the mass in a rotating object to decrease its overall moment of inertia?.

Answers

Bring mass up against the axis of rotation. Consequently, a rotating object's overall moment of inertia will decrease due to its mass. The axis and the mass narrows as the mass moves closer together.

A measure of a body's propensity to resist angular acceleration that is calculated by summing the products of each particle's mass and square of its distance from the axis of rotation moment of inertia

A line along which an item rotates is referred to as its axis of rotation (also known as its axis of revolution). That line is typically fictitious in physics and calculus. The distance from the object's outside border to the axis of rotation is known as the radius of rotation.

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an elevator of mass m is initially at rest on the first floor of a building. it moves upward, and passes the second and third floors with a constant velocity, and finally stops at the fourth floor. the distance between adjacent floors is h. what is the net work done on the elevator during the entire trip, from the first floor to the fourth floor?

Answers

From the first floor to the fourth floor, the elevator's net work during the entire trip is -3mgh.

Given,

On the first floor of a building, an elevator with mass m is initially at rest. It ascends at a constant speed, passing second and third floors before coming to a stop at the fourth floor.

the separation between the floors is h

The distance from the first floor to the fourth floor Equals 3 hours of work = -mg(3 hours)

= -3mgh

Work Done = -3mgh

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Q3. A 3500 kg van hits a 2500 kg car with a force of 1480 N [E].
a) What force does the van experience?

Answers

The force experience by a van of 3500 kg when it hits a car of 2500 kg with a force of 1480 N is 1057.14 N.

What is force?

Force can be defined as the product of mass and acceleration.

To calculate the force experienced by the van, we use the formula below

Formula:

f = mF/M..................... Equation 1

Where:

M = Mass of the vanm = Mass of the carf = Force on the carF = Force on the van

From the question,

M = 2500 kgm = 3500 kgF = 1480 N

Substitute these values into equation 1

f = (2500×1480/3500)f = 1057.14 N.

Hence, the force experience by the van is 1057.14 N.

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the large blade of a helicopter is rotating in a horizontal circle. the length of the blade is 7.99 m, measured from its tip to the center of the circle. find the ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the center of the circle.

Answers

The ratio of the centripetal acceleration at the end of the blade to that which exists at a point located 6.16 m from the centre of the circle: 1.29

Centripetal acceleration is given by :

a = ω2R

where,

ω is the angular speed

R is the distance of the point from the centre

Let the point at the tip be A and that at distance 6.16 m from centre be B

Distance of point A from centre (RA) = 7.99 m

Distance of point B from centre (RB) = 6.16 m

Centripetal acceleration at A (aA) = ω2RA = 7.99ω2

Centripetal acceleration at B (aB) = ω2RB = 6.16ω2

The ratio (aA/aB) = 7.99/6.16 = 1.29

What is centripetal acceleration ?

centripetal acceleration is defined as the motion characteristic of an object moving along a circular path. Any object moving in a circle whose acceleration vector points towards the centre of that circle is called centripetal acceleration. You must have seen various examples of medium acceleration in your daily life. When you drive a car around a circle, your car experiences an average acceleration, and the average acceleration is also observed by a satellite orbiting the Earth. Middle means towards the centre.

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the most common type of topographic map is created by the USGS is a 7.5-minute by 7.5-minute quadrangle map (figure 3.18). this means that each side of the map is 7 minutes and 30 seconds. each minute of latitude is 1852 meters and each second of latitude is 31 meters. how many meters does this map cover in a north-south direction?

Answers

Answer: I think it's 13,000 meters

Explanation:

consider newton's 3rd law, the force that the earth exerts on a person will be equal and opposite that what the person applies to the earth. however, why don't we see the earth accelerate?

Answers

because of newton’s third law, (every action has an equal and opposite reaction), this would mean that the force we exert onto the earth is equal to the force the earth exerts into us. howver, we don’t see the earth accelerating because of the giant mass it has. with earth weighing 5.972 × 10^24 kg, compared to the average human, the force would not be that strong. in this scenario, the incredibly small amount of force we exert onto the earth causes it to move extremely slowly, which is why we don’t see it accelerating
pretty sure this is correct
hope this helped!!! :))

According to Newton's third law,  for every action there is an equal and opposite reaction. However, the land we see on earth is stationary and the force applied by us is not at all sufficient to make a movement or to accelerate.

What is Newton's third law of motion ?

According to Newton's third law, for every action there is an equal and opposite reaction. Therefore, when we apply a force on an object, the object will exerts an equal and opposite force.

According to Newton's second law of motion, the force exerted on a body is the product of mass and acceleration. Hence, the force acting on  body is directly proportional to the mass of the body and it accelerates by the applied force.

The mass of humans in earth is negligible compared to the mass of earth . Therefore, the force we exert on earth is not at all sufficient to accelerate the earth. However, earth in turn exerts an equal and opposite force.

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Minerals and vitamins are called

Answers

Answer:

micronutrients.

Explanation:

Jack and Jill takes 14 minutes to walk 340 m [West], then 129 m [South]. Calculate
a. their total displacement
b. their average speed
c. their average velocity

Answers

Answer:

a. their total displacement = 364 meters

b. their average speed      = 33.5 meters/minute

c. their average velocity    =  26 meters/minute SW

Explanation:

See attached worksheet

two power lines, each 300 m in length, run parallel to each other with a separation of 23 cm . part a if the lines carry parallel currents of 130 a , what is the magnitude of the magnetic force each exerts on the other? express your answer using two significant figures.

Answers

The magnitude of the magnetic force each exerts on the other is 4.41 N.

The magnitude of the magnetic force depends on the current through the wire, the length of the wire, and the radius of separation. It can be written as

F = μ₀ . I1 . I2 . L / (2π . a)

where F is a magnetic force, μ₀ is vacuum permeability (4π x 10¯⁷ H/m), I1 and I2 is current through the wire, L is the length of the wire and a is the radius of the wire.

From the question above, the given parameters are

L = 300 m

a = 23 cm = 0.23 m

I1 = I2 = 130 A

By substituting the parameters, we can calculate the magnetic force

F = μ₀ . I1 . I2 . L / (2π . a)

F = 4π x 10¯⁷ . 130 . 130 . 300 / (2π . 0.23)

F = 4.41 N

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a 7.26 kg bowling ball and a 0.163 kg cricket ball are simultaneously dropped from a height of 10.0 m. what can you say about the velocity of the bowling ball, vb, compared to the velocity of the cricket ball, vc, when they hit the ground?

Answers

The velocity Vb of the bowling ball will be same as that of the cricket ball when dropped simultaneously from the same height. Because the velocity while hitting the ground is not dependent of mass.

Let us consider a general case,

Let us say the ball is dropped from a height H, its final velocity on reaching the ground is V, the acceleration g will be constant because everything is happening on the earth's surface and neglecting the air drag,

So, using equation of motion,

V ²-U²=2gH

U is the initial velocity in of the ball which is zero in our case,

So,

V²=2gH

V =√2gH

As we can see, the velocity on hitting the ground is independent of the mass.

So we can say,

Vb of the balling bowl is same as that of Vc on hitting the ground.

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PLEASE HELP ME!
What holds the protons together in the nucleus?


A. electrons


B. anions


C. cations


D. neutrons

Answers

Answer:

neutrons.........................

What is the magnitude of the x-component of force ?

Answers

ANSWER

EXPLANATION

If force F keeps the object in equilibrium

Answer:

See below

Explanation:

Find the x components of all of the forces shown, add them together, the x-component of the force F will be exactly opposite ( same magnitude but 180 degrees different)

30 cos 55  +     40 cos 205   +   50 cos 320  =  19.26    <====x component sum of all of the forces shown

F  (the x component of ) will be   Either    - 19.26   At zero degrees

                                                                 Or 19.26 at 180 degrees

a passenger walks along the aisle of a train at a speed of 1.3 m/s. the train moves at a speed of 30.2 m/s with respect to the ground. calculate the relativistic correction to the classical value of the passenger speed with respect to the ground. what is the percentage of this correction?

Answers

The parameters of speed are time divided by distance.The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the metre per second (m/s) (mph).

How are speeds determined?

Speed is calculated as follows: speed = distance * time.Knowing the units for distance and time is necessary to calculate the units for speed.The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in secondsWe have provided The passengers' speed in relation to the train is 2.30 mph, not 2.30 g.Additionally, the passenger is moving at a speed of 30.2m/s relative to the ground.And at a 28 degree angle to the north-west.Therefore, the cost for us passengers will be 4.5 cost 28 and the I. component will be 30.2 signed 28.

Now that we know the train's velocity with respect to the ground, we can calculate the passengers' velocity with respect to the train by subtracting the train's velocity with respect to the ground.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to 30.2 28° I + 4.5 Cost 28° J minus 2.30 G.And after calculation, this will be equal to 3.97 G -2.30 G less, or -2.11 I.Furthermore, this will result in -2.11 I plus 1.67 G.The equation for training velocity with respect to the ground will now be as follows.The size and direction of the trend's velocity with respect to the ground must be determined.Therefore, the magnitude will be 2.11 sq plus 1.67, square root off.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to -4.5 9 28° I + 4.5 Cost 28° J minus 2.30 G.Calculating yields a value of 2.69 meters per second, and the direction is equal to 2.11 divided by 1.67, which will result in 51.63 agreement.As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

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As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

How are speeds determined?Knowing the units for distance and time is important to determine the units for speed. In this example, the units will be measured in metres per second (m/s), as the distance is measured in metres (m) and the time is measured in seconds.We have said that, rather than 2.30 g, the passengers' speed in respect to the train is 2.30 mph.In addition, the passenger is traveling at a relative speed of 30.2 m/s to the ground.Additionally, at a 28-degree northwestern angle.As a result, our guests will pay 4.5 cost 28 and the I. component will be signed at 30.2 and be.

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Air is approximately 21% o2 and 78% n2 by mass. Calculate the root-mean-square speed of each gas at 273 k.

Answers

The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2

How to solve for the root mean square method

We have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.

We have 1 j = 1 kgm²/s²

Vrms = √3rt/Mm

R = gas constant

T = temperature = 273

Mm is the molar mass

The molar mass of N₂ is = 0.02800 kg / mol

The mo;lar mass of o₂ = 0.03200 kg / mol

We have to solve first for N₂

= √3 (8.32447 * 273 / 0.028000

= √243,198.247

= 493.15

For 02

Vrms = √3 * 8.31447 * 273  / 0.03200

= √212798.466

= 461.3

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Please help me with this, it's a Kinematics Equation 2 problem!

Answers

The distance covered by the object is given as,

[tex]d=ut+\frac{1}{2}at^2[/tex]

Plug in the known values,

[tex]\begin{gathered} d=(0\text{ m/s)(9 s)+}\frac{1}{2}(2m/s^2)(9s)^2 \\ =0\text{ m+}81\text{ m} \\ =81\text{ m} \end{gathered}[/tex]

Thus, the distance covered by the object is 81 m.

Explain one recent idea that scientists have proposed for how the universe began. Consider the big bounce theory or the multiverse theory.

Answers

The most widely accepted theory about the universe is the big bang theory.

What is big bounce theory?

The Big Bounce theory refers to the universe that is expanding and contracting, move back and forth in a big-picture timeline. The Big Bang theory was happened about 13.8 billion years ago when the universe began as a tiny, dense, ball that exploded. Many astronomers use the Big Bang theory to show how the universe began. But what caused this explosion in the first thing that is still a mystery. It has passed through many stages, which can be considered cosmological theories. The flat Earth, the geocentric model, heliocentricity, galactic centricity, the Big Bang, and the Inflationary Big Bang. In the Big Bounce theory, the universe is expanding and contracting, seesawing back and forth in a massively big-picture timeline more specific theory called "Big Bounce" theory proposes that the universe could collapse to the state where it is first started and then initiate another Big Bang.

So we can conclude that The Big Bang theory says that the universe came into being from a single more than 13 billion years ago.

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an object projected horizontally from a height flies through the air before hitting the ground. the path of the projectile in the air can be described as a

Answers

The path of the projectile is parabola projected horizontally from a height flies through the air before hitting the ground.

What is projectile and what is the path of projectile in air before hitting the ground?A projectile is an object that is compelled to move under the influence of external force.And then the projectile moves freely under the influence of gravity as in here too.Here an object is projected horizontally from a height flies through the air before hitting the ground.The path of the projectile before hitting the ground would be parabola in the air .Hence when an object projected horizontally from a height flies through the air before hitting the ground, the path of the projectile in the air is parabola.

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if a certain specific amount of heat energy were absorbed by a both a pound of water and by a pound of steel, whose temperature would increase the most?

Answers

The temperature of steel would increase compared to the pound of water when certain specific amount of heat were absorbed by both .

What is temperature and why steel would have more temperature than pound of water?Temperature is the measure of degree of hotness or coldness of either a substance or a region.Here a certain amount of heat energy is absorbed by both steel and pound of water .As we know the water when falls it potential energy converts to kinetic energy.Here the temperature of steel would be far more than the pound of water because of more heat absorbed.Hence steel would be more heated.

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to stop your vehicle when the brakes fail, a. work the parking brake gradually to prevent locking up the wheels and sending the car out of control. b. pump your foot down on the accelerator. c. shift up to a higher gear to slow the car down. d. all of the above

Answers

The correct answer is option A.

To stop your vehicle when the brakes fail, work the parking brake gradually to prevent locking up the wheels and sending the car out of control.

Due to advanced technology, a complete brake failure has never occurred. However, there is the possibility of an unlikely scenario while driving your vehicle.

If you ever come across such an unfortunate situation where a brake failure occurs in your vehicle while driving here is the advice to act upon.

The few things which are essential to do are:

Keep pressing the brake pedal

Gradually pull down on the parking brake of your vehicle.

If it does not work, shift your attention to the lower gear and make sure one gear at a time to slow down your vehicle.

Drive into less hazardous areas make sure there are no people around you and do not turn off your engine until your vehicle is completely stopped.

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The gravitational force between two objects is 36 N. What will the new gravitational force be if the distance between them is tripled (x3)? A.4 N B.9 N C.18 N D.27 N

Answers

The new gravitational force when the distance between them is tripled is 4 N.

What is the gravitation force between the objects?

The gravitation force between the objects is calculated by applying Newton's law of universal gravitation.

F = Gm₁m₂/R²

where;

G is universal gravitation constantm is the mass of the objectsR is the distance between the objectsF is the force

From the equation above;

F₁R₁² = F₂R₂²

F₂ = F₁R₁²/R₂²

When the distance is tripled,

R₂ = 3R₁

F₂ = F₁R₁²/(3R₁)²

F₂ = F₁R₁²/9R₁²

F₂ = F₁/9

F₂ = 36 N/9

F₂ = 4 N

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The gravitational force between two object is 36 N then the new gravitational force will be 4 N. Hence, option A is correct.

What is gravity?

Gravity, also referred to as gravitation, is the unchanging force of attraction that binds everything together in mechanics. Being the weakest known force in nature, it has little effect on determining the intrinsic properties of common objects.

F = Gm₁m₂/ R²

From the equation above;

F₁ × R₁² = F₂ × R₂²

F₂ = F₁R₁²/R₂²

According to the question, when the distance is tripled,

R₂ = 3R₁

F₂ = F₁ R₁²/(3R₁)²

F₂ = F₁ R₁²/ 9R₁²

F₂ = F₁ / 9

F₂ = 36 N/9

F₂ = 4 N

Hence, the new gravitational force will be 4 N.

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fish are hung on a spring scale to determine their mass. (a) what is the force constant of the spring in such a scale if it stretches 6.55 cm for a 17.8 kg load?

Answers

The force constant of the spring is 2,717 × [tex]10^{3}[/tex] N/m

To solve this problem, we should understand Hooke's Law. According to this law, the displacement or magnitude of a deformation is directly proportional to the deforming force or load for relatively modest deformations of an item. Mathematically, Hooke's Law could be stated in a form of equation as written below.

[tex]F = k[/tex] Δ[tex]x[/tex]

where [tex]F[/tex] is the force, [tex]k[/tex] is the spring constant, and Δ[tex]x[/tex] is the displacement.

In this question, we have already known the value of force (as a result of multiplication between weight of the load and gravity value) and displacement.

[tex]F = 178 N[/tex]

Δ[tex]x[/tex][tex]= 0.0655 m[/tex]

By using the formula of Hooke's Law, we could calculate the value of spring constant.

[tex]F = k[/tex] Δ[tex]x[/tex]

[tex]k=F/[/tex]Δ[tex]x[/tex]

[tex]k = 178 N / 0.0655[/tex]

[tex]k = 2717 N/m[/tex]

[tex]k = 2,717[/tex] × [tex]10^{3} N/m[/tex]

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a zoologist standing on a cliff aims a tranquilizer gun at a monkey hanging from a distant tree branch. th ebarrel fo the gun is horizontla. just as the zoologigtist pulls the trigger, the monkey lets go and begins to fall. will the dark hit the monkey? neglect air resistance

Answers

The Monkey captured Bryce's spirit inside a circle of salt inside a McDonald's bathroom stall and left after escaping from Lady Bullseye. After several weeks, he finally came back and set him free.

When injected, tranquilizer-filled darts fired by tranquilizer guns temporarily sedate a person or an animal so that they can be handled (or captured) safely. The tranquilizer may be a paralytic, sedative, or anesthetic. There is a long history of using tranquilizer weapons to capture wildlife without harm. The most frequent sensations are relaxation and sleepiness. Negative feelings, stress, or anxiety might also gradually fade away once the sedative starts to work. Your entire body could experience tingling, especially in your arms, legs, hands, and feet.

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Decreasing a telescope's eyepiece focal length will:

increase magnification
decrease magnification
have no effect on magnification

Answers

Decreasing a telescope's eyepiece focal length increases magnification.

What is Magnification?

The degree to which a telescope magnifies its subject. It is equal to the focal length of the telescope divided by the focal length of the eyepiece.

By doing two things, a telescope makes celestial objects visible:

1) making very faint objects visible by collecting much more light than the human eye can by itself using a big lens or mirror.

2) enlarging the things' size to make it easier to perceive their features.

On decreasing the focal length of the eyepiece focal length the magnification will increase.

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It takes 10 seconds to accelerate from rest to rate of 8 m/s. If the mass of the car is 1,200kg. Calculate the net force acting on the car .

Answers

Answer:

960 N

Explanation:

Find acceleration

  Change in velocity / change in time

      8 /10 = .8 m/s^2

Then F = ma

            = 1200 kg  * .8 m/s^2 = 960 N

           

How long would it take an airplane to travle 1089 miles if its flying at a speed of 375 miles per hour

Answers

Answer:

2.904

Explanation:

It would take an airplane 2.904 hours to travel 1089 miles.

As a fraction, this would equal 363/125

As a percentage, this would equal 290.4%

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3. Complete the table below.
Symbol Atomic
Number
Na
Cl
Ar
Ca
11
20
Mass
Number
36
40
Number of
Protons
17
Number of Number of
Electrons
Neutrons
18
12
18

Answers

Answer:

Explanation:

Elements   Atomic No.   Mass No.   Proton No.    Electron No.   Neutron No.
Na                 11                   23                11                    11                     12


Cl                  17                   35               17                    17                     18


Ar                  18                  36                18                   18                     18


Ca                 20                 40                20                  20                    20


Atomic number = Proton number
Electron number = proton number
Mass Number = proton no. + neutron no.
Neutron number = Mass no. - proton no.

4. for the experimental runs you made, calculate the expected acceleration using the expression you found with newtons second law of motion and the specific masses used. compare the figures with your experimental results. are the experimental acceleration values low or high? why?

Answers

As the mass of an object is increased, the acceleration of the object is decreased.

According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it. This implies that as the force applied to an item increases, so does the object's acceleration. Similar to how an object's acceleration decreases as its mass increases, so do its mass.

As per Newton's second law of motion:

f = ma ------ (1)

f = (Δp) / t  ⇒ Rate of change of momentum

f = (mu - mv) / t = [m(u - v)] / t ----- (2)

From equation (1) and equation (2) we get:

[m(u-v)] / t = ma

a = (u - v) / t

The experimental acceleration value will be less than the theoretical acceleration value. because it is impossible to sustain a constant rate of velocity change for an extended period of time. The difference between practical and theoretical acceleration will therefore be smaller.

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a comet is in an elliptical orbit around the sun. its closest approach to the sun is a distance of 4.5 multiply 1010 m (inside the orbit of mercury), at which point its speed is 8.9 multiply 104 m/s. its farthest distance from the sun is far beyond the orbit of pluto. what is its speed when it is 6 multiply 1012 m from the sun? (this is the approximate distance of pluto from the sun.) speed

Answers

An elliptical orbit of a comet around the sun. The Pluton orbit is far from the sun's farthest distance. 51109.88 m/s is the speed when it is 6 x 1012 m from the sun.

given data

Vi=9.2104m/s is the comet's speed at d1=4.51010m.

When d2=61012m, the speed will be Vf.

Since there is no work done by the environment and the system's starting and final energies are equal, we can use:

[tex]E_{f}=E_{i}+W\\K_{f}+U_{f}=K_{i}+U_{i}+0\\1/2mv_{f}^{2}+\frac{-GMm}{d_{2}}=1/2mv_{i}^{2}+\frac{-GMm}{d_{i}}  \\v_{f}=\sqrt{v_{i}^2+2GMm[1/d_{2}-1/d_{1}]}[/tex]

Substitute the given values to find final velocity Vf

So

[tex]v_{f}=\sqrt{(9.2*10^{4}m/s )^2+2(6.7*10^{-11})(1.98*10^{30})[1/6*10^{12}-1/4.5*10^{10}]} \\[/tex]

[tex]v_{f}[/tex]=51109.88m/s

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