A) What is the wavelength of electromagnetic radiation that has a frequency of 5.97 x 10MHz? (1 MHz = 1 x 10 Hz)​

Answer:

Carbon dioxide is composed of one carbon atom covalently bonded to two oxygen atoms. It is a gas (at standard temperature and pressure) that is exhaled by animals and utilized by plants during photosynthesis. Carbon dioxide, CO2, is a chemical compound composed of two oxygen atoms and one carbon atom

Explanation:

Answer:

Carbon dioxide is composed of one carbon atom covalently bonded to two oxygen atoms. It is a gas (at standard temperature and pressure) that is exhaled by animals and utilized by plants during photosynthesis. Carbon dioxide, CO2, is a chemical compound composed of two oxygen atoms and one carbon atom.

Explanation:

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Answer:

[tex]\Delta S=54.3\frac{J}{K}[/tex]

Explanation:

Hello!

In this case, for the given reaction, we can write the equation to compute the entropy change as shown below:

[tex]\Delta s=2\Delta S_{Fe}+\Delta S_{Al_2O_3}-2\Delta S_{Al}-\Delta S_{Fe_2O_3}[/tex]

Letting:

[tex]\Delta s_{Fe}=27.3\frac{J}{mol*K}\\\\ \Delta s_{Fe_2O_3}=84.4\frac{J}{mol*K}\\\\\Delta s_{Al}=28.3\frac{J}{mol*K}\\\\\Delta s_{Al_2O_3}=51.00\frac{J}{mol*K}[/tex]

We obtain the entropy change per mole of Fe2O3(s):[tex]\Delta s=2*27.3\frac{J}{mol*K}+84.4\frac{J}{mol*K}-2*28.3\frac{J}{mol*K}-51.0\frac{J}{mol*K} \\\\\Delta s=31.4\frac{J}{mol*K}[/tex]

Finally, the total entropy change when 1.73 moles of Fe2O3(s) react turns out:

[tex]\Delta s=31.4\frac{J}{mol*K}*1.73mol\\\\\Delta S=54.3\frac{J}{K}[/tex]

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The given question is incomplete, the complete question is:

The LD50 value for ethyl alcohol given orally to rats is 10.3 g/kg. What volume in milliliters of 100 proof vodka (50% v/v ethanol) would be likely to kill a typical 360-g rat?

Answer:

The correct answer is 9.4 ml.

Explanation:

Based on the given information, in rats the LD50 of ethyl alcohol is 10.3 g/kg.

As 1 Kg is 1000 grams

Now the value of LD50 of ethyl alcohol in rats is 10.3 grams/ 1000 grams

The volume of the lethal dose of vodka for a 360 gram rat would be,  

= 360 g × (10.3 g/1000 g)

= 3708 × 10⁻³ g

= 3.708 g

Now the volume of vodka can be determined by using the formula,  

V = mass/density

The density of ethanol is 0.789 g/ml

The volume would be,  

V = 3.708 g/0.789 g/ml

V = 4.70 ml

As 50 percent of Vodka is ethanol, the volume of vodka needed to kill a rat is,  

= 2 × Volume of ethanol

= 2 × 4.70 g/ml

= 9.4 ml

Answer:

Density of unit cell ( rhodium) = 12.279 g/cm³

Explanation:

Given that:

The radius (r) of a rhodium atom = 135 pm

The atomic mass of rhodium = 102.90 amu

For a face-centered cubic unit cell,

[tex]r = \dfrac{a}{2\sqrt{2}}[/tex]

where;

a = edge length.

Making "a" the subject of the formula:

[tex]a = 2 \sqrt{2} \times r[/tex]

[tex]a = 2 \times 1.414 \times 135 \ pm[/tex]

a = 381.8 pm

to cm, we get:

a = 381.8 × 10⁻¹⁰ cm

However, recall that:

[tex]density \ of \ unit \ cell = \dfrac{mass \ of \ unit \ cell}{volume \ of \unit \ cell}[/tex]

where;

mass of unit cell = mass of atom × numbers of atoms per unit cell

Also;

[tex]mass\ of\ atom =\dfrac{ atomic \ mass}{Avogadro \ number}[/tex]

[tex]mass\ of\ atom =\dfrac{ 102.9}{6.023 \times 10^{23}}[/tex]

Recall also that number of atoms in a unit cell for a  face-centered cubic = 4

So;

[tex]mass \ of \ unit \ cell= \dfrac{102.90}{6.023 \times 10^{23}}\times 4[/tex]

mass of unit cell = 6.83380375 × 10⁻²² g

[tex]Density \ of \ unit \ cell = \dfrac{6.83380375 \times 10^{-22}}{(381.8\times 10^{-10})^3}[/tex]

Density of unit cell ( rhodium) = 12.279 g/cm³

The density of rhodium is equal to 12.4g/cm^3

Data;

The radius of a FCC is calculated as

[tex]r = \frac{a}{2\sqrt{2} }\\a = 2\sqrt{2} * r\\a = 2 * 1.414 * 135 = 381.8pm = 381.8 * 10^-^1^0cm\\[/tex]

The formula of density is given as

[tex]\rho = \frac{mass}{volume}\\[/tex]

The mass of a unit cell = mass of atom * number of atoms per unit cell.

[tex]mass of atom = \frac{atomic mass}{avogadro's number} = \frac{102.90}{6.023*10^2^3}\\[/tex]

For BCC number of atom in unit cell = 4

mass of unit cell = [tex]\frac{102.90}{6.02*10^2^3} * 4[/tex]

This makes the density of the atom equal to

[tex]\rho = \frac{\frac{102.90}{6.02*10^2^3} }{(381*10^-^1^0)^3}* 4\\ \rho = 12.4 g/cm^3[/tex]

The density of Rhodium is 12.4 g/cm^3

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Answer:

Other factors shape earths surface are:

Factors that Shape Earth's Surface.

Unit Notes.

 Plate Tectonics. Continental Drift. ...

Results of plate movement. ...

 Weathering. ...

 Erosion and Deposition.

Depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction, or a misleading result.

An explosion is a sudden increase in volume accompanied by a tremendous energy release that typically results in the production of high temperatures and the discharge of high-pressure gases. High explosive detonations produce supersonic explosions that move through shock waves.

Explosions often fall into one of three categories: chemical, mechanical, or nuclear. Every kind of explosion has the potential to be devastating and serious, wreaking unimaginable damage on the local populace, environment, and infrastructure.

What causes gamma ray bursts is one of the largest unsolved questions of all. These bursts, which happen around once every day, are the most powerful explosions known to science.

Thus, depending on the factors, combining two chemicals that aren't designed to interact might result in an explosion, an unintended chemical reaction.

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Answer: the last one

Explanation:

Answer:

Metal is copper.

Explanation:

Mass of a metal, m = 54 g

Heat energy required, Q = 773 J

The temperature changes from 63.0 °C to 100.0 °C.

We need to identify the metal. Heat required to raise the temperature is given by :

[tex]Q=mc\Delta T[/tex]

c is specific heat of the metal

We can identify the metal by finding its specific heat.

[tex]c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{773}{54\times (100-63)}\\\\=0.386\ J/g^{\circ} C[/tex]

The metal is copper. Its specific heat is [tex]0.386\ J/g^{\circ} C[/tex].

Answer:

the answer is b I am sure

Answer:

27.29%

Explanation:

Answer: A.

Explanation: The poles get the least amount of sunlight throughout the year.

Answer:

Hydrogen is your answer because lithium and hydrogen both have 1 electron in their outermost energy level

Answer:

1 because the last one is 1 and the previous shell was complete.

Answer: A)1

Explanation:

Valence electrons are always in Thebes last shell and last number of the configuration.

Answer:

it's easier to lose one electron because it's less work for the atom to do and easier to lose one than gain a whole 7, because the atom wants to gain a full outer shell as soon as possible

Explanation:

Molar mass of CaCl2 = 110.98g/mol

Moles of CaCl2 = 30.0 / 110.98 = 0.270mol

Moles of AgCl = 0.270mol * 2 = 0.540mol

Mass of AgCl = 0.540mol * (143.32g/mol) = 77.39g.

Answer:

77.5

Explanation:

You gotta round.

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Answer:

So since there are 16 electrons in sulfur and the first layer of electrons in an orbital shell has a max of two, the first layer will be full. The second layer has a max of 8, so that will also be full. The third layer also has a max of 8 but will not get filled up since there are only 6 electrons left. These are the valence electrons. The orbital diagram will usually look like this:

( O = nucleus, . o = electron)

   o o

o  O  o o

     o

Explanation:

First, a quick revision of radioactive decay:

During alpha decay, an alpha particle is emitted from the nucleus —- it is the equivalent of a helium atom (i.e. it has a mass of 4 and an atomic number of 2). So, let's take the following question:

Polonium-210 is a radioisotope that decays by alpha-emission. Write a balanced nuclear equation for the alpha decay of polonium-210.

In symbols, the equation becomes

210/84Po--->?+4/2HE

The sums of the superscripts and of the subscripts must be the same on each side of the equation.

Take 4 away from the mass number (210-4 = 206)

Take 2 away from the atomic number (84-2 = 82). Lead is element number 82.

So, the equation is

210/84 Po--->206/82Pb+4/2He

Now let's try one for beta decay — remember that, in beta decay, a neutron turns into a proton and emits an electron from the nucleus (we call this a beta particle)

Write a balanced nuclear equation for the beta decay of cerium-144)

In nuclear equations, we write an electron as 0^-1e.

144/58Ce-->144/59Pr+^0-1e

Here's a fission reaction.

A nucleus of uranium-235 absorbs a neutron and splits in a chain reaction to form lanthanum-145, another product, and three neutrons. What is the other product?

We write a neutron as 1/0n, so the equation is

235/92U +1/0n--->145/57La+X+3 1/0n

Sum of superscripts on left = 236. Sum of superscripts on right = 148. So  X

must have mass number = 236 – 148 = 88.

Sum of subscripts on left = 92. Sum of subscripts on right = 57. So  X

must have atomic number = 92 – 57 = 35. Element 35 is bromine.

The nuclear equation is

235/92U+1/0n--->145/57La+88/35Br+31/0N

A nuclear decay leads to the formation of a product that has a different isotope from that of the parent.

A nuclear equation has to do with an equation in which one isotope is transformed into a different isotope.

For 200/84Po;

200/84Po ----> 4/2 He + 196/82Pb

For 244/96Cm

244/96Cm -----> 4/2 He + 240/94Pu

For bismuth-210

210/83Bi ----->  4/2 He + 206/81Tl

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Answer:

Cesium is an Element in the Periodic table with atomic number 55, symbol Cs and belongs to the first group of the metals which is Alkali metals.

Ionization energy (IE) is defined as the amount of energy consumed by a ground state gaseous atom to discharge an electron which will results in a formation of a Cation

It forms ions be releasing the electron

              [tex]Cs(g) + IE[/tex]   → [tex]Cs^+ + e^-[/tex]         IE= 38.939 KJ

Answer:

cells come from pre existing cells

Answer:

The entropy change in a chemical reaction is given by the sum of the entropies of the products minus the sum of the entropies of the reactants.

Explanation:

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Answer:

aldehyde

Explanation:

Aldehydes are a large class of reactive organic compounds (R-CHO) having a carbonyl functional group attached to one hydrocarbon radical and a hydrogen atom.

So, when terminal alkynes, for example, 1-heptyne react on Hydroboration oxidation(i.e. disiamylborane followed by treatment with basic hydrogen peroxide), the formation of aldehyde occurs.

Answer:

The answer is make observations

Explanation:

Observing is the first step of the experimental method.

Answer:

V₂ = 60.47L

Explanation:

Given data:

Initial volume = 40.0 L

Initial pressure = 12.7 KPa

Final volume = ?

Final pressure = 8.4 KPa

Solution:

The given problem will be solved through the Boyls law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

12.7 KPa× 40.0 L = 8.4 KPa × V₂

V₂ = 12.7 KPa× 40.0 L/ 8.4 KPa

V₂ = 508 KPa. L / 8.4 KPa

V₂ = 60.47L

The volume of the ammonia gas if it's pressure is changed to 8.4 KPa is 60.5 L

From the question given above, The following data were obtained:

Initial pressure (P₁) = 12.7 KPa

Initial volume (V₁) = 40 L

Final pressure (P₂) = 8.4 KPa

Temperature = constant

Using the Boyle's law equation, the final volume of the ammonia can be obtained as illustrated below:

P₁V₁ = P₂V₂

12.7 × 40 = 8.4 × V₂

508 = 8.4 × V₂

Divide both side by 8.4

V₂ = 508 / 8.4

Therefore, the final volume of the ammonia gas is 60.5 L

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Answer:

d = 14.9 g/mL

Explanation:

Given data:

Mass of metal = 22.4 g

Volume of eater = 3.2 mL

Volume of water + metal = 4.7 mL

Density of metal = ?

Solution:

Volume of metal:

Volume of metal = volume of water+ metal - volume of water

Volume of metal = 4.7 mL - 3.2 mL

Volume of metal = 1.5 mL

Density of metal:

d = m/v

d = density

m = mass

v = volume

d = 22.4 g/ 1.5 mL

d = 14.9 g/mL

Answer:

Cakes, breads and other foods that contain leavening agents rise more quickly at higher altitudes, because gases produced by the agents expand faster than at sea level. The loaves may collapse if the gases dissipate before the proper temperature is reached. Most baking recipes can be adjusted for high altitudes.

Explanation:

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Answer:

Explanation:

because they have complete valence shell thats why they are not reactive towards chemical reaction and are quite stable