What carries electrons from the power supply to a load?
a) Ground
b) Neutral
c) Hot
d) Resistance
You have landed a summer job as the technical assistant to the director of an adventure movie shot here in Arizona. The script calls for a large package to be dropped onto the bed of a fast moving pick-up truck from a helicopter that is hovering above the road, out of view of the camera. The helicopter is 235 feet above the road, and the bed of the truck is 3 feet above the road. The truck is traveling down the road at 40 miles/hour. You must determine when to cue the assistant in the helicopter to drop the package so it lands in the truck. The director is paying $20,000 per hour for the chopper, so he wants you to do this successfully in one take. If t = 0 is the time that filming starts at and you can assume that the truck is already at speed, at what time should the helicopter release the package and how far back from the drop site should it be at t = 0?
Answer:
a
[tex]t = 3.798 \ s [/tex]
b
[tex]S = 67.91 \ m [/tex]
Explanation:
From the question we are told that
The height of the helicopter is [tex]h= 235 ft[/tex]
The height of the bed of the truck is [tex]h_b = 3 \ ft[/tex]
The speed of the truck is [tex]v = 40 \ miles / hour = \frac{40 * 1609.34}{3600} = 17.88 \ m/s[/tex]
Generally the distance between the truck bed and the helicopter is mathematically represented as
[tex]H = h - h_b[/tex]
=> [tex]H = 235 -3[/tex]
=> [tex]H = 232 \ ft [/tex]
Converting to meters
[tex]H = \frac{ 232}{3.281} = 70.7 \ m [/tex]
Generally the time at which the helicopter should drop the package is mathematically represented as
[tex]t = \sqrt{\frac{2 * H}{g} }[/tex]
[tex]t = \sqrt{\frac{2 * 70.7}{9.8} }[/tex]
[tex]t = 3.798 \ s [/tex]
Generally distance of the helicopter from the drop site at time t = 0 s is
[tex]S = v * t[/tex]
=> [tex]S = 17.88 * 3.798[/tex]
=> [tex]S = 67.91 \ m [/tex]
what are two benefits of scientific using a diagram to model the water cycle
Answer:
it can show changes that occur in many different parts of earth at the same time
it can be used to show as much detail as is present in the actual water cycle
Explanation:
apex(i hope i helped)
A horse is grazing for food it trots rightward 15 m to eat a carrot then walks rightward 20 m to another carrot then turns leftward to walk 4 m to bite an apple the horse walks a total of 74 s
Answer:
The horse's average speed is 0.527 m/sExplanation:
step one:
In this problem, we are not asked explicitly what to solve for, but given the following data we can solve for the average speed
step two:
We know that average speed = total distance/total time taken
total distance= 15m+20+4m= 39m
total time= 74 seconds
step three:
average speed= 39/74
average speed= 0.527 m/s
The horse's average speed is 0.527 m/s
Answer:
.42 | Speed
.527 | Velocity
A 75-kg piano is hoisted on a crane and delivered throughout the window of a 6th story apartment (20 meters above ground). What is the potential energy of the piano?
Answer:
P = 14700 J
Explanation:
Given that,
Mass of a piano, m = 75 kg
It is delivered throughout the window of a 6th story apartment which is 20 m above the ground.
We need to find the potential energy of the piano. It is given by :
P = mgh
Putting all the values,
P = 75 kg × 9.8 m/s² × 20 m
P = 14700 J
So, the potential energy of the piano is 14700 J.
What is the average speed in miles per hour of the car that traveled 200 miles in 5.5 hours
Answer:
36.4 mph
Explanation:
Average speed is [tex]\frac{distance}{time}[/tex].
After substitution, this is [tex]\frac{200}{5.5}[/tex].
The average speed, therefore, reduces to 36 [tex]\frac{4}{11}[/tex] mph, or about 36.4 mph.
A man walks 1.80 km north and then 2.75 km east, all in 3.00 hours.(a)What is the magnitude (in km) and direction (in degrees north of east) of his displacement during the given time?magnitude km direction ° north of east(b)What is the magnitude (in km/h) and direction (in degrees north of east) of his average velocity during the given time?magnitude km/h direction ° north of east(c)What was his average speed (in km/h) during the same time interval?km/h
Answer:
1. Displacement = 3.29 km
b. His direction is [tex]33.21^{o}[/tex] north of east
2. Average velocity is 1.10 km/h
b. His direction is [tex]33.21^{o}[/tex] north of east
3. Average speed = 1.52 km/h
Explanation:
1. Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]
= [tex]\sqrt{1.8^{2} + 2.75^{2} }[/tex]
= [tex]\sqrt{10.8025}[/tex]
= 3.2867
Displacement = 3.29 km
b. tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{1.8}{2.75}[/tex]
= [tex]tan^{-1}[/tex]0.6546
= 33.20878
θ = [tex]33.21^{o}[/tex]
His direction is [tex]33.21^{o}[/tex] north of east
2. Average velocity = [tex]\frac{displacement}{time}[/tex]
= [tex]\frac{3.29}{3}[/tex]
= 1.09667
Average velocity is 1.10 km/h
b. His direction is [tex]33.21^{o}[/tex] north of east.
3. average speed = [tex]\frac{total distance}{time}[/tex]
total distance covered = 1.80 km + 2.75 km
= 4.55 km
Average speed = [tex]\frac{4.55}{3}[/tex]
= 1.5167
Average speed = 1.52 km/h
Longitudional waves travel through a series of ________ and ___________.
compressions; rarefactions
oscillations; propagations
destructions; constructions
disturbances; oscillations
Answer:
compressions; rarefactions
Explanation:
3A car travelling at initial velocity 30m/s overtake a bus which was 120m
ahead. The bus then moves with initial velocity 10m/s and accelerate at
5ms-2.
when will the bus also now overtake the car,
what is the time interval
between the arrival of the two cars if the car is to travel a total distance of
450m .
The bus is 120 m ahead of the car, so the car covers this distance in
120 m = (30 m/s) t
t = (120 m) / (30 m/s)
t = 4 s
Now take the car's position at the moment the car overtakes the bus to be the origin.
Car's position at time t :
x = (30 m/s) t
Bus's position at time t :
x = (10 m/s) t + 1/2 (5 m/s²) t²
The bus overtakes the car when their positions are equal:
(30 m/s) t = (10 m/s) t + 1/2 (5 m/s²) t²
t / (2 s) ((5 m/s) t - 40 m) = 0
t = 0 or t = (40 m) / (5 m/s) = 8 s
If the car travels a total distance of 450 m, then it does so after
450 m = (30 m/s) t
t = (450 m) / (30 m/s)
t = 15 s
The bus overtakes the car in the first 12 s of this journey, so both vehicles reach the same destination with 3 s between them.
Which of the following statements are true? Check all that apply. Atoms with the same atomic number have the same number of electrons Atoms with the same atomic number have the same number of neutrons Atoms with the same atomic number can have different numbers of electrons Atoms with the same number can have different numbers of neutrons
Answer:
Two correct answers (the first one and the last one listed):
Atoms with the same atomic number have the same number of electrons.
Atoms with the same atomic number can have different numbers of neutrons.
Explanation:
There are two correct answers:
Atoms with the same atomic number have the same number of electrons. This is because neutral atoms have the same number of electrons than of protons in the nuclei. And the number of protons in the nucleus characterize the particular element and is called the "Atomic number."
and
Atoms with the same atomic number can have different numbers of neutrons. These constitute the isotopes of the element characterized by the given atomic number.
Answer:
The correct answers are actually the last two, C and D.
Explanation:
I answered according to what the other answer said the first time, got it wrong. Answered according to the comment the second time, also got it wrong. C and D are the two answers edge said were correct after I got it wrong.
What is matter using the word mass, atom, and.molecular
Please answer quick please thank you
Which term describes energy stored inside the nucleus of an atom?
A.light
B.thermal
C.nuclear
D.chemical
Answer:
C would be the answer
Explanation:
15. When objects are moved further apart from each other, the force of
gravity between them
Answer: Newtons First law.
Explanation: Not enough information.
Name as many Greek Gods and Goddesses as you can. What do you know about them?
Answer:
Zeus, Poseidon, Hera, Aphrodite, Ares, Hades
Explanation:
Zeus is the king of gods. Poseidon is god of the sea. Hera is goddess of Marriage, Ares is god of war. Hades god/lord or the underworld.
Convert 26.4 mi to km
Answer:
42.48 [km]
Explanation:
To convert miles to kilometers we must know the conversion factor which is equal to:
[tex]1.609[\frac{km}{mi} ][/tex]
We make the product of the value required by the conversion factor:
[tex]26.4[mi]*1.609[\frac{km}{mi} ]\\\\[/tex]
26.4*1.609 = 42.48 [km]
A remote-controlled plane has a mass of 0.386 kg and flies in a circle with a radius of 75 m. The centripetal force on the plane is 4.0 N.
What is the tangential speed of the plane?
Answer:
28 m/s
Explanation:
correct
Answer:
b
Explanation:
A dog walking to the right with a speed of 1.5 m s 1.5 s m 1, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction sees a cat and speeds up with a constant rightward acceleration of magnitude 12 m s 2 12 s 2 m 12, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.
Answer: 8.62
Explanation: it’s the answer. :)
Answer:
8.62
Explanation:
khan academy
A 75 kg doctor delivers a 4 kg baby and holds it at arm's length (0.3 m). Using the Universal Law of Gravitation formula below, identify F, G, m1, m2, r. *
Answer:
m₁ = 75 kg
m₂ = 4 kg
r = 0.3 m
G = 6.67 x 10⁻¹¹ Nm²/kg²
F = 2.223 x 10⁻⁷ N
Explanation:
Given;
mass of the doctor, m₁ = 75 kg
mass of the baby, m₂ = 4 kg
length of the doctor's arm, r = 0.3 m
universal gravitation constant, G = 6.67 x 10⁻¹¹ Nm²/kg²
The gravitational force F, is calculated as;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67*10^{-11})(75 \ kg) (4 \ kg)}{(0.3 \ m)^2} \\\\F = 2.223 *10^{-7} \ N[/tex]
You are watching your friend play hockey. In the course of the game, he strikes the puck in such a way that, when it is at its highest point, it just clears the surrounding 2.70 m high Plexiglas wall that is 12.9 m away.
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
[tex]v_y = 5.14 \ m/s[/tex]
b
[tex]\Delta t = 0.5248 \ s [/tex]
Explanation:
From the question we are told that
The maximum height is H = 2.70
The Range is R = 12.9 m
Generally from projectile motion we have that
[tex]Range = \frac{ u^2 sin2(\theta)}{g}[/tex]
[tex]12.9 = \frac{ u^2 sin2(\theta)}{g}[/tex]
Generally from trigonometric identity
[tex]sin 2(\theta) = 2sin (\theta) cos(\theta)[/tex]
So
[tex]12.9 = \frac{ u^2 2sin(\theta) cos(\theta)}{g}[/tex]
=> [tex]u^2 * 2sin(\theta) cos(\theta) = 12.9 * g[/tex]
[tex]u^2 * 2sin(\theta) cos(\theta) = 12.9 * 9.8[/tex]
[tex]u^2 *2sin(\theta) cos(\theta) = 126.42 \ \cdots (1)[/tex]
Also the maximum height is
[tex]H = \frac{u^2 sin^2 (\theta)}{2g}[/tex]
=> [tex]2.70 = \frac{u^2 sin^2 (\theta)}{2g}[/tex]
=> [tex]u^2 sin^2 (\theta) = 2.70 * 2 * g[/tex]
=> [tex]u^2 sin^2 (\theta) = 2.70 * 2 * 9.8[/tex]
=> [tex]u^2 sin^2 (\theta) = 52.92\cdots (2)[/tex]
Dividing equation 2 by (1)
[tex]\frac{u^2 sin^2 (\theta)}{u^2 *2sin(\theta) cos(\theta)} =\frac{52.92}{126.42 }[/tex]
=> [tex]tan(\theta ) = \frac{52.92}{126.42 }[/tex]
=> [tex]\theta = tan^{-1} [0.4186][/tex]
=> [tex]\theta =22.71^o [/tex]
So
From equation 1
[tex]u^2 *2sin(22.71) cos(22.71) = 126.42 \ \cdots (1)[/tex]
=> [tex]u = 13.322 \ m/s[/tex]
Generally the vertical component of the initial velocity is mathematically evaluated as
[tex]v_y = usin (\theta)[/tex]
=> [tex]v_y = 13.322 * sin (22.71)[/tex]
=> [tex]v_y = 5.14 \ m/s[/tex]
Generally the time taken is mathematically represented as
[tex]\Delta t = \frac{u sin (\theta )}{g}[/tex]
=> [tex]\Delta t = \frac{13.322 sin (22.71 )}{9.8}[/tex]
=> [tex]\Delta t = 0.5248 \ s [/tex]
Franklin needs to ship a box with FedEx. In order to calculate his shipping costs, he needs to measure the mass of the package. What is the base unit that he should use in this case?
A. meter B. liter C. gram
Answer:
meter
Explanation:
please mark as brainlist answer
A constant force is applied to a body that is already moving. The force is directed at an angle of 60 degrees to the direction of the body's velocity. What is most likely to happen is that: the body will stop moving. the body will move in the direction of the force. the body's velocity will increase in magnitude but not change direction. the body will gradually change direction more and more toward that of the force while speeding up. the body will first stop moving and then move in the direction of the force.
Answer:
the body will gradually change direction more and more toward that of the force while speeding up.
Explanation:
From the question we were told that constant force is applied to a body that is already moving
if the applied force is in opposite direction to the motion of the object, there would be deceleration.
Whenever a force is applied to moving body , acceleration will occur in the body if the force and the motion of the body act in the same direction.
However in case of the question since the force is directed at an angle of 60 degrees to the direction of the body's velocity then the body will gradually change direction more and more toward that of the force while speeding up.
.
For a rigid axisymmetric satellite, the mass moment of inertia about its long axis is 1000 kg$m2 , and the moment of inertia about transverse axes through the center of mass is 5000 kg$m2 . It is spinning about the minor principal body axis in torque-free motion at 6 rad/s with the angular velocity lined up with the angular momentum vector H. Over time, the energy degrades due to internal effects and the satellite is eventually spinning about a major principal body axis with the angular velocity lined up with the angular momentum vector H. Calculate the change in rotational kinetic energy between the two states. {Ans.: 14.4 kJ}
Answer: Delta T = - 14.4 kJ
Explanation:
Firstly the initial momentum of the satellite is;
H0 = L0*W0
L0 is the momentum of inertia of the satellite about its longer axis (1000 kg.m^2) and Wo is the initial angular velocity of the satellite ( 6 rad/s)
now we substitute
H0 = 1000 kg.m^2 * 6 rad/s
H0 = 6000 kg.m^2
Now the initial rotational kinetic energy of the satellite is;
0o = 1/2L0W0^2
we substitute
T0 = 1/2 * (1000 kg.m^2) * (6 rad/s)^2
T0 = 18000
Next is the final angular momentum of the satellite;
H = IW
I is the moment of inertia of the satellite about its transverse axes through center of mass (5000 kgm^2)
we know that the law of conservation angular momentum, the total initial angular momentum of the satellite is equal to the total final angular momentum of the satellite.
simply put H = H0
we know that our H0 = 6000 kgm^2
so we substitute
H0 = IW
6000 kg.m^2 = 5000 kgm^2 * W
W = 1.2 rad/s
The final rotational kinetic energy of the satellite is;
T = 1/2IW^2
T = 1/2 * 5000 kgm^2 * 1.2^2
T = 3600 J
so the change in rotational kinetic energy of the satellite is;
Delta T = T - T0
Delta T = 3600 - 18000
DeltaT = - 14400 J
Delta T = - 14.4 kJ
QUESTION 5
Insomnia is a sleep disorder most characterized by
a. chronic problems in getting adequate sleep.
b. frequent, reflexive gasping for air.
C. potentially troublesome dream enactments.
d. sudden and irresistible onsets of sleep during normal waking periods.
N
Answer:
D) sudden and irresistible on sets of sleep during normal waking periods
Explanation:
D because Narcolepsy (sudden and irresistible on sets of sleep during normal waking periods) is a part of insomnia
À A car moves with an initial velocity of 18 m/s due north. Find the velocity of the car after 7 Os if
(a) its acceleration is 1.5 m/s2 due north. (b) its acceleration is 1.5 m/s2 due south
Answer:
(a) [tex]v_f=28.5m/s[/tex]
(b) [tex]v_f=7.5m/s[/tex]
Explanation:
Hello.
(a) In this case since the car is moving at an initial velocity of 18 m/s due north, the final velocity is computed considering the acceleration as positive since it is due north as well:
[tex]v_f=v_0+at=18m/s+1.5m/s^2*7s\\\\v_f=28.5m/s[/tex]
(b) In this case, since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:
[tex]v_f=v_0+at=18m/s-1.5m/s^2*7s\\\\v_f=7.5m/s[/tex]
Best regards.
(a) The final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due north is 28.5 m/s.
(b) The final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due south is 7.5 m/s.
Given data:
The initial velocity of car due north is, u = 18 m/s.
The time interval is, t = 7.0 s.
(a)
For the acceleration of 1.5 m/s2 due north, the final velocity of car can be obtained from the first kinematic equation of motion as,
[tex]v = u +at[/tex]
Here, v is the magnitude of final velocity of car.
Solving as,
[tex]v = 18+(1.5)7\\\\v = 28.5 \;\rm m/s[/tex]
Thus, we can conclude that the final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due north is 28.5 m/s.
(b)
since the car is moving due north by the acceleration is due south it is undergoing a slowing down process, thereby the acceleration is negative therefore the final velocity turns out:
[tex]v'=u+(-a)t\\\\v'=18+(-1.5)7\\\\v' = 7.5 \;\rm m/s[/tex]
Thus, we can conclude that the final velocity of car after 7.0 s for an acceleration is 1.5 m/s2 due south is 7.5 m/s.
Learn more about the linear acceleration here:
https://brainly.com/question/14214161
A car speeds up and accelerates for 5.1 seconds at a rate of 2.2 m/s2. if the car's initial velocity was 9.3 m/s, what was the car's final velocity
after accelerating?
-9.7m/s
-11.2m/s
1.9m/s
20.5m/s
Recall the definition of average acceleration:
a = (v - u)/∆t
where u and v are the initial and final velocities, respectively.
So we have
2.2 m/s² = (v - 9.3 m/s) / (5.1 s)
v - 9.3 m/s = (2.2 m/s²) * (5.1 s)
v = 9.3 m/s + (2.2 m/s²) * (5.1 s)
v = 20.52 m/s ≈ 21 m/s
Help ASAP). Draw additional masses to show how the block can be made to move toward point A. Be sure to draw the string and label the mass of the block. For full credit, draw the minimum number of blocks required to make the block move toward point A. Will Mark Brainliest
Answer:
Given that the block have two applied masses 250 g at East and 100 g at South. In order to make a situation in which block moves towards point A, we have to apply minimum number of masses to the blocks. In order to prevent block moving toward East, we have to apply a mass at West, equal to the magnitude of mass at East but opposite in direction. Therefore, mass of 250 g at West is the required additional mass that has to be added. There is already 100 g of mass acting at South, that will attract block towards South or point A. No need to add further mass in North-South direction.
A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull the mass, stretching the spring beyond the equilibrium position a distance A, and release it from rest. The mass then begins to oscillate in simple harmonic motion with amplitude A. During one period, the mass spends part of the time in regions where the magnitude of its displacement from equilibrium is greater than (0.30)A— that is, when its position is between −A and (−0.30)A, and when its position is between (0.30)A and A. What total percentage of the period does the mass lie in these regions?
Answer:
Δt'/ T% = 90.3%
Explanation:
Simple harmonic movement is described by the expression
x = A cos (wt)
we find the time for the two points of motion
x = - 0.3 A
-0.3 A = A cos (w t₁)
w t₁ = cos -1 (-0.3)
remember that angles are in radians
w t₁ = 1.875 rad
x = 0.3 A
0.3 A = A cos w t₂
w t₂ = cos -1 (0.3)
w t₂ = 1,266 rad
Now let's calculate the time of a complete period
x= -A
w t₃ = cos⁻¹ (-1)
w t₃ = π rad
this angle for the forward movement and the same time for the return movement in the oscillation to the same point, which is the definition of period
T = 2 t₃
T = 2π / w s
now we can calculate the fraction of time in the given time interval
Δt / T = (t₁ -t₂) / T
Δt / T = (1,875 - 1,266) / 2pi
Δt / T = 0.0969
This is the fraction for when the mass is from 0 to 0.3, for regions of oscillation of greater amplitude the fraction is
Δt'/ T = 1 - 0.0969
Δt '/ T = 0.903
Δt'/ T% = 90.3%
A truck is moving at 2.0 m/s accelerates at a rate of +2.00 m/s2. It does this over a distance of 400.0m. Find the final velocity.
If v is the truck's final velocity, then
v² - (2.0 m/s)² = 2 * (2.00 m/s²) * (400.0 m)
v² = 1604 m²/s²
v = 40.05 m/s ≈ 40 m/s
You take a couple of capacitors and connect them in series, to which you observe a total capacitance
of 4.8 µF. However, when you connect them in parallel, their combined capacitance is 35 µF.
Determine the value of each capacitor
Answer:
Approximately [tex]\rm 5.7\; \mu F[/tex] and approximately [tex]29\; \rm \mu F[/tex].
Explanation:
Let [tex]C_1[/tex] and [tex]C_2[/tex] denote the capacitance of these two capacitors.
When these two capacitors are connected in parallel, the combined capacitance will be the sum of [tex]C_1[/tex] and [tex]C_2[/tex]. (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)
[tex]C(\text{parallel}) = C_1 + C_2[/tex].
On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:
[tex]\displaystyle \frac{1}{C(\text{series})} = \frac{1}{C_1} + \frac{1}{C_2}[/tex].
(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field ([tex]V[/tex]) between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored [tex](Q)[/tex] stays the same.)
The question states that:
[tex]C(\text{parallel}) = 35\; \rm \mu F[/tex], and[tex]C(\text{series}) = 4.8\; \rm \mu F[/tex].Let the capacitance of these two capacitors be [tex]x\; \rm \mu F[/tex] and [tex]y\; \rm \mu F[/tex]. The two equations will become:
[tex]\displaystyle \left\lbrace \begin{aligned}& x + y = 35 \\ & \frac{1}{x} + \frac{1}{y} = \frac{1}{4.8}\end{aligned}\right.[/tex].
From the first equation:
[tex]y = 35 - x[/tex].
Hence, the [tex]y[/tex] in the second equation here can be replaced with [tex](35 - x)[/tex]. That equation would then become:
[tex]\displaystyle \frac{1}{x} + \frac{1}{35 - x} = \frac{1}{4.8}[/tex].
Solve for [tex]x[/tex]:
[tex]\displaystyle \frac{x + (35 - x)}{x \, (35 - x)} = \frac{1}{4.8}[/tex].
[tex]x\, (35 - x) = 4.8[/tex].
[tex]x^2 - 35 \, x + 168 = 0[/tex].
Solve this quadratic equation for [tex]x[/tex]:
[tex]x \approx 5.7[/tex] or [tex]x \approx 29.3[/tex].
Substitute back into the equation [tex]y = 35 - x[/tex] for [tex]y[/tex]:
[tex]x \approx 5.7[/tex] and [tex]y \approx 29.3[/tex], or[tex]x \approx 29.3[/tex] and [tex]x \approx 5.7[/tex].In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately [tex]5.7\; \rm \mu F[/tex] and approximately [tex]29\; \rm \mu F[/tex] (both values are rounded to two significant digits.)
Which of the following statements about Gaussʹs law are correct? (There may be more than one correct choice.) Question 3 options: Gaussʹs law is valid only for symmetric charge distributions, such as spheres and cylinders. If there is no charge inside of a Gaussian surface, the electric field must be zero at points of that surface. Only charge enclosed within a Gaussian surface can produce an electric field at points on that surface. If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface.
Answer:
If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface.
Explanation:
Option A is incorrect because, given this case, it is easier to calculate the field.
Option B is incorrect because, in a situation where the surface is placed inside a uniform field, option B is violated
Option C is also incorrect because it is possible to be a field from outside charges, but there will be an absence of net flux through the surface from these.
Hence, option D is the correct answer. "If a Gaussian surface is completely inside an electrostatic conductor, the electric field must always be zero at all points on that surface."
