Answer:
Explanation:
Step one:
Given data
work-done in dragging the trash= 236J
applied force= 18.9N
distance moved= 24.4m
Required
The angle of the applied force
Step two:
We know that work done is
WD= F * distance
The work is the product of the horizontal component of the force and the distance.
Horizontal force = 236 ÷ 24.4
= 9.67 N
Cos θ = Horizontal force ÷ Actual force
Cos θ = (236 ÷ 24.4) ÷ 18.9 = 236 ÷ 461.16
The angle is approximately 59˚
A 20-cm-long rod with a diameter of 0.250 cm is loaded with a 5000 N
weight. If the diameter decreases to 0.210 cm, determine (i) the
engineering stress and strain at this load and (ii) the true stress and strain
at this load
Answer: the answer is 19cm
Explanation:
what causes sound to have low pitch
A.Sound Wave with high frequency.
B.sound wave with low frequency.
C.sound wave with large amplitude
D.sound wave with small amplitude
11. Which element in Figure 15.17 is likely to be a the best conductor of electricity ?
Answer:
first where is figure...
silver the is best conducter of electricity.
Four charges of equal magnitude, q = +1 uC, are placed at the four corners of a square with a side length of 1 meter located in the xy-plane. A small ball with a known charge +2 uC and an unknown mass is placed 2 meters above the center of the square (so along the z-axis).
Required:
a. What is the total force on the small ball from the four charges?
b. If the ball is in equilibrium where it was placed and we assume standard earth gravity, 9.8 m/s^2, what must the mass of the ball be?
Answer:
a) F _total = 15.08 10⁻³ N , b) m = 1,539 10⁻³ kg
Explanation:
a) To solve this problem we can use Coulomb's law to find the force created by each charge
F =[tex]k \frac{\ q_{1} q_{2} }{r_{12}^{2} }[/tex]
and the total force is
F = F₁₅ + F₂₅ + F₃₅ + F₄₅
The bold are vectros, In the exercise they indicate the charges
q₁ = q₂= q₃ = q₄ = 1 10⁻⁶ C
q₅ = 2 10⁻⁶ C
Let's set a reference system where the sphere is on the z axis and the other charges on the xy plane, let's write the coordinates of card charge
sphere (subscript 5)
x₅ = 0
y₅ = 0
z₅ = 2 m
charge 1
x = 0.5 m
y = 0.5 m
z = 0
charge 2
x = -0.5 m
y = 0.5 m
z = 0
charge 3
x = -0.5 m
y = -0.5 m
z = 0
charge 4
x = 0.5 m
y = -0.5 m
z = 0
With these values we can calculate the distance between each charge and the sphere
charge 1 and sphere
r₁₅² = (x₅ -x₁)² + (y₅ - y₁)² + (z₅ -z₁)²
substitute
r₁₅² = (0- 0.5)² + (0 - 0.5)² + (2 -0)²
r₁₅² = 0.5² + 0.5² + 2²
r₁₅² = 4.5
we can see that for the other charges the result is the same since being squared always gives positive
r₁₅ = r₂₅ = r₃₅ = r₄₅
the force created by the card charge on the sphere is the projection on the Z axis of the total force
Let's find the angle with respect to the Z axis
tan φ = r / z
where r is the magnitude of the vector in the xy plane
r = [tex]\sqrt{0.5^{2} + 0.5^{2} }[/tex]
r = 0.7071 m
φ = tan⁻¹ r / z
φ = tan⁻¹ (0.7071 / 2)
φ = 19.5
consequently the total force is
F_total = 4 F cos 19.5
F _total = [tex]4 \frac{k \ q_{1} q_{5} }{r_{15}^{2}}[/tex] cos 19.5
let's calculate
F_toal = 4 9 10⁹ 1 10⁻⁶ 2 10⁻⁶ /4.5 cos 19.5
F _total = 15.08 10⁻³ N
b) For this part indicate that the sphere is in equilibrium with the weight
F_total - W = 0
W = mg
F_total = mg
m = F_total / g
m = 15.08 10³ / 9.8
m = 1,539 10⁻³ kg
List two examples of how the land can have a dramatic change in temperature throughout the day.
Answer:
one could freeze and the second would thaw
Explanation:
sorry if its wrong
The two examples of how land can have a dramatic change in temperature
is during freezing and thawing.
Cold temperatures which is common during the winter period is
characterized by the formation of snow and freezing of smaller water
bodies.
There may be a short phase in which there is relative sunlight which melts
the frozen substances thereby forming liquids . This is usually as result of
the temperature being on the increase in the atmosphere.
Read more on https://brainly.com/question/25671319
An object has a mass of 20 kg and is placed 2 m above the ground. What is its gravitational potential energy? (PEg)
Answer:
392 JExplanation:
The potential energy of a body can be found by using the formula
PE = mgh
where
m is the mass
h is the height
g is the acceleration due to gravity which is 9.8 m/s²
From the question we have
PE = 20 × 9.8 × 2
We have the final answer as
392 JHope this helps you
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Answer:
Ro = 8.65 [g/cm³]
Explanation:
We must remember that density is defined as the ratio of mass to volume.
[tex]Ro=m/V[/tex]
where:
m = mass = 0.450 [kg] = 450 [g]
V = volumen = 52 [cm³]
Ro = density [g/cm³]
Now replacing:
[tex]Ro = 450/52\\Ro = 8.65 [g/cm^{3} ][/tex]
14. After finishing her homework, Sue climbs up a 5.00 m high flight of stairs to her bedroom
Find the magnitude of Sue's weight
and how much
work Sue does in climbing the stairs if she
has a mass of 50.0 kg? (4.90 x 2 N, 2450J)
Explanation:
Given parameters:
Height = 5m
Mass of Sue = 50kg
Unknown:
Magnitude of Sue's weight = ?
Work done by Sue = ?
Solution:
Weight is the vertical force exerted by a body in the presence of gravity.
Mathematically;
W = mg
m is the mass
g is the acceleration due to gravity = 9.8m/s²
Weight = 50 x 9.8 = 490N
Work done = Force x distance = weight x height
Work done = 490 x 5 = 2450J
Find the applied voltage of a telephone circuit that draws 0.017A through a resistance Of 5,000 ohms
a projectile is shot upward from the surface of the earth with an initial velocity of 384 ft/s. What is its velocity after 5 seconds
Answer:
335 ft/s
Explanation:
In this question, we have a very important factor missing. The equation of the projectile. So, in simplifying the question I'm going to assume an equation which you can correct thereafter
s(t) = -4.9t² + v(0)t + s0
From the question, we're told that v(0) = 384 ft/s, so if we apply that, we have
s(t) = -4.9t² + 384t + s0, where s0 = 0
On differentiating the equation, we have
s(t) = v(t) = -4.9(2t) + 384(1)
v(t) = -9.8t + 384
Now, at time t = 5 seconds, the velocity v =
v(t) = -9.8(5) + 384
v(t) = -49 + 384
v(t) = 335 ft/s
Therefore, the velocity of the projectile after 5 seconds is 335 ft/s. Please leave a like if it helped you.
Delaney loves her new kiddie pool, but she is afraid to get wet. She crawls around the outside of the pool for hours. Jocelyn says Delaney is making rotations around the pool and Jonathan says Delaney is making revolutions around the pool. Who is correct? Suppose your answer with evidence.
Answer:
Revolutions
Explanation:
How fast is a 30 kg child runnning if her kinetic energy is 500 J?
[tex]\displaystyle v = 5.7735 \ m/s[/tex]
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightEquality Properties
Physics
SI Units
Speed is m/s (meters per second)Energy is J (Joules), equal to 1 N/m (newton per meter)Mass is kg (kilograms)Energy
Kinetic Energy Formula: [tex]\displaystyle KE = \frac{1}{2} mv^2[/tex]
KE is Kinetic Energy (in J)m is mass (in kg)v is velocity (in m/s)Explanation:Step 1: Define
Mass m = 30 kg
Kinetic Energy KE = 500 J
Step 2: Solve for v
Substitute [KEF]: [tex]\displaystyle 500 = \frac{1}{2}(30)v^2[/tex]Multiply: [tex]\displaystyle 500 = 15v^2[/tex]Isolate v term: [tex]\displaystyle \frac{100}{3} = v^2[/tex] Isolate v: [tex]\displaystyle \frac{10\sqrt{3} }{3} = v[/tex]Rewrite: [tex]\displaystyle v = \frac{10\sqrt{3} }{3} \ m/s[/tex]Evaluate: [tex]\displaystyle v = 5.7735 \ m/s[/tex]An 85 kg man stands in a very strong wind moving at 15 m/s at torso height. As you know, he will need to lean in to the wind, and we can model the situation to see why. Assume that the man has a mass of 85 kg, with a center of gravity 1.0 m above the ground. The action of the wind on his torso, which we approximate as a cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground, produces a force that tries to tip him over backward. To keep from falling over, he must lean forward.
Required:
a. What is the magnitude of the torque provided by the wind force? Take the pivot point at his feet. Assume that he is standing vertically.
b. At what angle to the vertical must the man lean to provide a gravitational torque that is equal to this torque due to the wind force?
Answer:
a) [tex]T= 72.9 Nm[/tex]
b) [tex]\Theta = 5 \textdegree[/tex]
Explanation:
From the question we are told that
Mass 85kg
Speed 15m/s
Center of gravity 1.0m
Cylinder 50 cm wide and 90 cm long centered 1.2 m above the ground
a)Generally equation for force is given by
[tex]F = 0.5 p A v^2[/tex]
Mathematically solving for force exacted
[tex]F = 0.5*1.2*0.9*0.5*15^2[/tex]
[tex]F= 60.75 N[/tex]
Mathematically solving for torque
Torque,
[tex]T = r * F[/tex]
[tex]T=1.2*60.75[/tex]
[tex]T= 72.9 Nm[/tex]
b)Generally in solving for [tex]\theta[/tex]
[tex]Tan\theta = Torque/(Mass * Gravity)[/tex]
[tex]Tan\theta = (72.9)/(85 * 9.8)[/tex]
[tex]\Theta = 5 \textdegree[/tex]
Will give brainliest if correct
Please help
Answer:
85.45
Divide 4,700/55
So C.
Answer:
C.85
Explanation:
Use the equation:
v= fλ ( v=wave speed, f= frequency, λ= wavelength)
4700= 55×λ
λ=4700÷55 =85.45 =85(approximately)
Does a basketball, baseball, tennis ball, or marble MOST LIKELY have the smallest volume?
Answer: tennis ball
Explanation:
Deshaun Watson launches a football at a speed of 24.7 ms and an angle of 33° above the horizontal How far down
the football field does the football land? What is the max height the football reaches during flight?
Show work
Answer:
9.23m
Explanation:
Max height = u²sin²theta/2g
u is the speed = 34.7m/s
theta is the angle of elevation = 33°
g is the acceleration due to gravity = 9.8m/s²
Substitute into the formula
Max height = 24.7²sin²33/2(9.8)
Max height = 610.09sin²33/2(9.8)
Max height = 610.09(0.29663)/19.6
Max height = 180.97/19.6
Max Height = 9.23m
Hence the max height the football reaches during flight is 9.23m
Help pleaseeee need the answers ASAP
Answer:
- 670 kg.m/s
Explanation:
Newton's third law states that to every action, there is equal and opposite reaction force. Since the force will be same but different in direction and acted in the same time then the impulses ( force multiply by time) of the two car be same in magnitude but different in direction - 670 kg.m/s
4. What is the tan gential velocity of an object moving in a path of radius 2m with an angular velocity of
3rad/s.pls help me
Answer:
6m/s
Explanation:
The tangential velocity is the product of the linear velocity and the radius. This is expressed as;
v = wr
w is the angular velocity = 3rad/s
r is the radius = 2m
Substitute
v = 3 * 2
v = 6m/s
Hence the tangential velocity of the object is 6m/s
Suppose that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat. The change in internal energy of the spring is?
Answer: 85J
Explanation:
From the question, we are informed that when spring was wound, 100J of work was done but 15J escaped to the surrounding as heat.
Therefore, the change in internal energy of the spring will be calculated as:
ΔU = q + w
where, q = -15J
w = 100J
ΔU = -15J + 100J
= 85J
A sled weighs 10.0 kg. It is held in place on a frictionless 20.0-degree slope by a rope attached to a stake at the top of the slope. Find the tension in the rope if it is parallel to the slope. 47.9 N 37.4 N
Answer:
33.5 N
Explanation:
Given that
Mass of the sled is, m = 10 kg
Angle of slope, θ = 20°
The tension in the rope of its parallel to the slope is often given as
W * sinθ, where
W = Force on the rope and
θ = angle of the slope
Now, remember that
w = mg, where g = acceleration due to gravity, so
W = 10 kg * 9.81 m/s²
W = 98.1 N,
Going ahead to solve for tension in the slope, we have
T = W * sinθ
T = 98.1 * sin20
T = 98.1 * 0.342
T = 33.5 N
Tension in the slope is 33.5 N
Kindly leave a like if it helped you
the maximum displacement of an oscillatory motion is A=0.49m. determine the position x at which the kinetic energy of the particle is half it's elastic potential energy? (if K.E = U/2 __ x = ?)
Answer:0.4 m
Explanation:
Given
Maximum displacement A=0.49
The sum of kinetic and elastic potential energy is [tex]\frac{1}{2}kA^2[/tex]
where k=spring constant
U+K.E.=[tex]\frac{1}{2}kA^2[/tex]
when K.E.=U/2
K.E.=kinetic energy
U=Elastic potential Energy
[tex]\rightarrow \ U+\frac{U}{2}=\frac{1}{2}KA^2\\\rightarrow \ \frac{3U}{2}=\frac{1}{2}KA^2\\\rightarrow \ U=\frac{1}{3}KA^2\\\rightarrow \ \frac{Kx^2}{2}=\frac{1}{3}KA^2\\\\x=\sqrt{\frac{2}{3}}A\\x=0.4\ m[/tex]
A construction laborer holds a 20 kg sheet of wallboard 3 m above the floor for 4 seconds. During these 4 seconds how much power was expended on the wallboard
Answer:
zero
Explanation:
no distance has moved while holding the sheet...so no distance means no workdone..no workdone means no power...
detergents are used to clean the clothes why
Answer:Detergent mixes with water to remove dirt and oil from clothes. Water can't remove oil and dirt from clothes. Detergent cleans by causing a chemical reaction with water to force dirt and debris out of clothing. Detergents work with water to loosen the dirt trapped in the material of clothing and clean them away.
Explanation:May i plz have brainlist only if u wanna give me brainlist though have an nice day!
Caca box like fish no earnings play like caca
400 points in arena youa have none thats Why I wonder
Answer:
I actually have 20000 arena points thank you very much
Answer: Caca means in French lol.
⚠️Please Help Me! I Need It Now!⚠️
Answer:
A. They are moving at 60 mph
Explanation:
When looking at the car on the track pass by, the people inside appear to be moving at the same speed as the car. So if the car is going 60 mph, the people instead will appear as though they are moving at 60 mph as well.
Need help y’all ASAP please...physics
Answer:
t = 3/8 seconds
Explanation:
h=-16t^2 - 10t+6
h= 0 when it hits the ground
0=-16t^2 - 10t+6
factor out a -2
0= -2(8t^2 +5t -3)
divide by -2
0 = (8t^2 +5t -3)
factor
0=(8t-3) (t+1)
using the zero product property
8t-3 = 0 t+1 =0
8t = 3 t= -1
t = 3/8 t= -1
t cannot be negative ( no negative time)
t = 3/8 seconds
Your car gets a flat! You go from 90 kilometers per hour to a stop in 6 seconds. What is your rate of deceleration? (it's negative!) I need this asap help
Answer:
at a rate of deceleration of -15 kilometers per second
Explanation:
90/6=15
The rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².
HOW TO CALCULATE DECELERATION?The rate of deceleration can be calculated by using the following formula:
d = v - u/t
Where;
d = deceleration (m/s²)v = final velocity = 90km/h = 25m/su = initial velocity = 0km/h = 0t = time (s)d = 25 - 0/6
d = 4.16m/s²
Therefore, the rate of deceleration when a car goes from 90km/h to 0 in 6 seconds is 4.16m/s².
Learn more about deceleration at: https://brainly.com/question/4403243
A boy climbs 12.0m up an apple tree. He picks an apple and throws it horizontally with a velocity of 3.0 m/s. How far forward does the ball go before it hits the ground
Answer:
4.692m
Explanation:
The distance that this boy climbed = 12.0m
The velocity = 3.0m/s
We are to find how far forward this apple goes before it hits the ground.
We have y = 1/2gt²
X = v*t
T = 1.564 seconds
X = 3x1.564
X = 4.692m
Therefore the ball goes a distance of 4.692m forward before it then hits the ground.
why does the force of air resistance affect the motion of a person traveling at high speed more than a person walking across the room?
Answer:
yes .
Explanation:
...
;-; :) have a good day
Answer:
because on air the speed is high compared to walking
A student is creating an electromagnet for an investigation. Which feature of the electromagnet will least influence the magnetic force?
A
the material of the core
B
the brand of the battery
С
the number of wire coils
D
the che of the power source
