Acme Logistics provides "Less than truck load" (LTL) services throughout the U.S. They have several hubs where they use cross-docking to move goods from one trailer to another. Acme built its last hub 10 years ago, and it had 36 dock doors. The cost index at that time was 140, and the total cost was $6 million. Acme plans a new hub that will have 48 dock doors. The cost index now is 195, and Acme will use a capacity factor of 0.82. What is the estimated cost of the new hub?

Answers

Answer 1

Answer:

The answer is "$10.12 million"

Explanation:

To find the price of the 36 dock doors only at the current rate, just use the cost index.  

[tex]C_n=C_k \times (\frac{I_n}{I_k})\\\\[/tex]

     [tex]= 6 \times \frac{195}{140} \\\\= \$ \ 8 \ million[/tex]

Its current cost of 36 dock doors is, thus,[tex]\$ \ 8 \ million[/tex]. To calculate the price for 48 dock doors, just use the second formula now:

[tex]\to (\frac{C_A}{C_B})=(\frac{S_A}{S_B})^{X}\\\\\to C_A=C_B \times (\frac{S_A}{S_B})^{X}\\\\[/tex]

         [tex]=8 \times (\frac{48}{36})^{0.82}\\\\= \$ 10.12 \ million[/tex]


Related Questions

The 10-kg lamp is suspended from the

three equal-length cords. Determine its

smallest vertical distance s from the

ceiling if the force developed in any

cord is not allowed to exceed 50 N.

120°

A

600 mm

120°

Answers

Answer:

hello your question is incomplete attached below is the complete diagram

answer : 519 mm

Explanation:

Given the conditions it can be said that the cords are symmetric i.e. AD, BD , CD  has same value

hence ; DA = DB = DC = 600 mm

Tension in all cords are the same ( T ) = 50 N

lets assume the angle between the cords and the Z-axis is ∅

∑ Fz = 0

3 * T cos ∅  - 10*9.81 = 0

therefore ;  ∅ = 49.16°

looking at attached triangle AD0

tan ∅ = [tex]\frac{600}{s}[/tex]

Hence ; s = 519 mm  

6.A tape measure is used
A. in manufacturing industries
B. in construction industries
C. for precision measurement
D. A and B

Answers

The answer is ▼・ᴥ・▼
Answer: B ♥︎

Helium gas is compressed from 90 kPa and 30oC to 450 kPa in a reversible, adiabatic process. Determine the final temperature and the work done, assuming the process takes place (a) in a piston-cylinder device and (b) in a steadyflow compressor. [15

Answers

Answer:

T2 ( final temperature ) = 576.9 K

a) 853.4 kJ/kg

b) 1422.3 kJ / kg

Explanation:

given data :

pressure ( P1 ) = 90 kPa

Temperature ( T1 ) = 30°c + 273 = 303 k

P2 = 450 kPa

Determine final temperature for an Isentropic  process

[tex]T2 = T1 (\frac{p2}{p1} )^{(k-1)/k}[/tex]  ----------- ( 1 )

T2 = 303 [tex]( \frac{450}{90})^{(1.667- 1)/1.667}[/tex] =  576.9K

Work done in a piston-cylinder device can be calculated using this formula

[tex]w_{in} = c_{v} ( T2 - T1 )[/tex]    ------- ( 2 )

where : cv = 3.1156 kJ/kg.k  for helium gas

             T2 = 576.9K ,    T1 = 303 K

substitute given values Back to equation 2

[tex]w_{in}[/tex]  = 853.4 kJ/kg

work done in a steady flow compressor can be calculated using this

[tex]w_{in} = c_{p} ( T2 - T1 )[/tex]

where : cp ( constant pressure of helium gas )  = 5.1926 kJ/kg.K

             T2 = 576.9 k , T1 = 303 K

substitute values back to equation 3

[tex]w_{in}[/tex] = 1422.3 kJ / kg

1. The final temperature for this reversible, adiabatic process is 576.82 Kelvin.

2a. Assuming the process took place in a piston-cylinder device, the work done is equal to 853.11 kJ/kg.

2b. Assuming the process took place in a steady-flow compressor, the work done is equal to 1422.82 kJ/kg.

Given the following data:

Initial pressure = 90 kPaFinal pressure = 450 kPaInitial temperature = 30°C to K = [tex]273 + 30 = 303 \;Kelvin[/tex]

Constant, k = 1.667

Constant pressure for helium gas, [tex]C_p[/tex] = 5.1926 kJ/kg.K

Constant volume for helium gas, [tex]C_v[/tex] = 3.1156 kJ/kg.k

First of all, we would determine the final temperature for this isentropic process.

For an isentropic process, the final temperature is given by the formula:

[tex]T_2 = T_1 (\frac{P_2}{P_1})^{\frac{k-1}{k}}\\\\T_2 = 303 \times (\frac{450}{90})^{\frac{1.667-1}{1.667}}\\\\T_2 = 303 \times (5)^{\frac{0.667}{1.667}}\\\\T_2 = 303 \times 5^{0.40}\\\\T_2 = 303 \times 1.9037\\\\T_2 = 576.82 \;K[/tex]

a. In a piston-cylinder device, work done is given by the formula:

[tex]W = C_v(T_2 -T_1)\\\\W = 3.1156(576.82 -303)\\\\W = 3.1156 \times 273.82\\\\W = 853.11[/tex]

Work done, W = 853.11 kJ/kg

b. In a steady-flow compressor, work done is given by the formula:

[tex]W = C_p(T_2 -T_1)\\\\W = 5.1926(576.82 -303)\\\\W = 5.1926 \times 273.82\\\\W = 1422.82[/tex]

Work done, W = 1422.82 kJ/kg

Read more: https://brainly.com/question/22599382

Before finishing and installing a shelved cabinet you just constructed, you need to check the
nside corners for 90 degree angles. Which hand tool would meet the needs of this task?

Answers

Answer:

Carpenter's square

Explanation:

The most common hand tool used to measure or set angles with its application extending to setting angles of roofs and rafters. Another name of a Carpenter's square is a framing square.

Other hand tools that are used to measure angles are;

The combination square that allows a user to set both 90°  and 45° anglesA Bevel that allows users to set any angle they like.A Protractor that resembles a bevel but its marks are marked in an arc.An electromagnetic angle finder which gives a reading according to the measure of the arms adjusted by the user.

How do statics, Dynamics and Mechanics of materials differ from each other? *

Answers

Answer:

Statics means study of all the forces couples moments etc. for a stationary object which is in the state of rest. Whereas Dynamics deals with study of all the forces when object is in motion . In mechanics static is referred to motion(velocity) which is either zero or constant.

Steam enters a heavily insulated throttling valve at 11 MPa, 600°C and exits at 5.5 MPa. Determine the final temperature of the steam.

Answers

Answer: the final temperature of the steam 581.5 °C

Explanation:

Given that;

P₁ = 11 MPa

T₁ = 600°C

exit at; P₂= 5.5 MPa

Now from superheated steam table( p=11 MPa, T=600°C)

h₁ = 3615 kJ/kg  

h₁ = h₂ ( by throttling process and adiabatic isentholpic )

from saturated steam table at; ( h= 3615 kJ/kg, P= 5.5 MPa )

Temperature = 581.5 °C

Therefore the final temperature of the steam 581.5 °C

There are four main exit strategies for ending your involvement with a company: selling the company, liquidating the company by selling assets and releasing the cash flow to investors, selling stock to the public, or selling private stock to private investors. Which exit plan strategy will you choose for your company? Explain why

Answers

I am assuming there is no correct answer rather preference so here:

I would choose to sell stock to private investors so I as the (assuming) CEO, could receive a lump sum profit and the company could still stay afloat keeping any and all employees employed. Additionally the brand name would not be impacted as severely as if you were to just sell out to the public.

AC motor characteristics require the applied voltage to be proportionally adjusted by an AC drive whenever the frequency is changed. True or false?

Answers

The answer is false
It is false :))) hope this helps you!!

An aggregate blend is composed of 55% aggregate A (Sp. Gr. 2.631), 25% aggregate B (Sp. Gr. 2.331) and 20% sand (Sp. Gr. 2.609). The Sp. Gr. of the blend aggregate is most nearly:_______

a. 2.732
b. 2.545
c. 2.581
d. 2.614

Answers

Answer:

The right choice would be Option b (2.545).

Explanation:

The given values are:

The aggregate blend will be:

[tex]W_A[/tex] = 55%

[tex]G_ A[/tex] = 2.631

[tex]W_ B[/tex] = 25%

[tex]G_B[/tex] = 2.331

[tex]W_C[/tex] = 20%

[tex]G_C[/tex] = 2.609

Now,

On applying the formula, we get

⇒ [tex]G_{BA}=\frac{W_A+W_B+W_C}{\frac{W_A}{G_A} +\frac{W_B}{G_B} +\frac{W_C}{G_C}}[/tex]

On substituting the values, we get

⇒          [tex]=\frac{55+25+20}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}[/tex]

⇒          [tex]= \frac{100}{\frac{55}{2.631} +\frac{25}{2.331} +\frac{20}{2.609}}[/tex]

⇒          [tex]=2.545[/tex]

Seperate real and imaginary parts tan(2x+i3y)

Answers

Answer:

First you have to separate real and imaginary parts of Tan(x+iy)=Tan(z)=sin(z)/cos(z)

sinz=sin(x+iy)=sinxcos(iy)+cosxsin(iy)=sinxcoshy-icosx sinhy

cosz=cos(x+iy)=cosxcos(iy)-sinxsin(iy)=cosxcoshy−isinxsinhy

Now if you plug in Tan(z) and simplify (it is easy!) you get

Tan(z)=(sin(2x)+isinh(2y))/(cos(2x)+cosh(2y))= A+iB.

This means that

A=sin(2x)/(cos(2x)+cosh(2y)) and B= sinh(2y)/(cos(2x)+cosh(2y))

Now,

A/B=sin(2x)/sinh(2y)

If any questions, let me know.

What can firefighters do to reduce the risk to people living in Skyview?

Answers

Answer:

The City can grant higher budgets to emergency services like the Fire Department, so a higher budget will allow engineers & scientists to innovate new technology and add more fire stations across the city.

Explanation:

What is substructure work?
O Work above ground level
Work on ground level
O Work below ground level
O Work above the superstructure​

Answers

The answer is: Work below ground level.

A household oven door of 0.6-m height and 0.7-m width reaches an average surface temperature of 32°C during operation. The temperature of ambient air is 22°C. Assuming the door has an emissivity of 0.4 and the surroundings are also at 22°C, determine the heat transfer by free convection and the heat transfer by radiation.

Answers

Answer:

a)  ≈ 11.7 watts

b)  ≈ 21.4 watts

Explanation:

Given data :

Oven door dimensions : 0.6m  by 0.7m

average surface temperature = 32°c

Temperature of ambient air = 22°c

emissivity of door = 0.4

surrounding temperature = 22°c

a) Calculate heat transfer by free convection

q = 3.34 ( 0.5 * 0.7 ) (32-22 ) ≈ 11.7 watts

attached below is the detailed solution

b) calculate heat transfer by radiation

q = ∈.As б ( Ts^4 - Tsun^4 )

   = 1( 0.5*0.7 ) * 5.67 * 10^-8 [( 273+32)^4 - ( 273+22)^4 ]

   ≈ 21.4 watts

Which of the following can not be used to store an electrical charge?

Answers

i’ve been feeeling very lonely

The wood beam described below applies to Questions 15 through 17. A 2x10 wood beam is to support a service dead load (including beam self-weight) of 50 lbs/ft and a service live load of 60 lbs/ft (note that the loads given are per foot and not per square ft). The beam is part of a series of adjacent parallel beams spaced 16 inches apart. Span length is 15 ft. Assume that lateral buckling is prevented. Wood species/grade is "Red Maple", No. 1. Moisture content is less than 19% (dry). This member's service temperature is not elevated. What is the design moment strength (M'.) in kip-in? do not check bearing stresses and do not check deflection Shear strength is covered under the next question.
Question 16 For the wood beam described in Question 15, what is the design shear strength of the beam (V.) in kips? Pay attention to the requested unit!
Question 17 For the wood beam described in Questions 15 and 16, is the beam structurally adequate?
No
Yes
Not known with the information given

Answers

Answer:

1. Design moment = 30.83kip

2. Shear strength = 2.8kip

3. Yes beam is adequate.

Explanation:

Length = 15ft = 180 inches

Dead load = 50

Live load = 60

1.2x50+1.6x60

= 60+96

= 156

= 13 lbs/inch

Area = 2x10

= 20in²

Modulus Zx = bd²/6

= 2x10²/6

= 33.33in³

Bending strength = 925

Shear strength = 210

1. Design moment = 33.33x925

= 30830.25

= 30.83kip

Shear strength = 2/3*20*210

= 2800

= 2.8kip

3. Yes beam is adequate

Maximum bending moment = 2/8*13*180 = 52.65

52.65>30.83

Maximum shear

13x180/2<2.83

1.17kip<2.83kip

Briefly discuss the principle forms of communication that might be utilized in the construction industry?

Answers

Answer:

xcvjchjcnjkkhjmklk heyyyy biiiiiiiittcccchhh

Which actions would the maintenance and operations crews carry out as a building is completed and preparing to open to the public? Select all that apply.



make any last minute repairs


install new equipment and furnishings


troubleshoot solutions to any lingering problems or malfunctions


determine which new residents or company employees will occupy which offices or residences

Answers

Answer:

1. make any last minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Explanation:

Given that the role or functions of maintenance and operations crews in building construction are to ensure that the building is maintained to the required standard of use.

This involves making sure that all repairs in a building are done. The equipment is properly installed and solved any form of equipment that malfunctions.

Hence, in this case, the correct answer is:

1. make any last-minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Answer:

1. make any last minute repairs

2. install new equipment and furnishings

3. troubleshoot solutions to any lingering problems or malfunctions

Explanation:

If electrons have a path to follow, they will flow to a area with charge

Answers

Answer:

Hello there, the question is not complete, but not to worry you can check the explanation section to check how you can  solve a similar question or to be be able to solve the exact question directly.

Explanation:

The flow of electrons is what is known or refer to as Current. When energy is used on a nuclei, the electrons are forced to move from one position to the other. The direction of flow of electron is from the negative terminal which then moves to the positive terminal.

Therefore, it can be said that the positive charge determines the direction of electron flow. The starting point is the negative terminal, in which it will now move in the direction in which the positive terminal is.                    

What dimensioning error is shown in this drawing?​

Answers

There is no drawing here :(

At 1 atm, nitrogen (N2) molecules become a liquid below 77 K. Thus the vapor pressure of liquid nitrogen is 1 atm at 77 K. Use this information to estimate the binding energy of a nitrogen molecule within the liquid. Note: You may assume that the equilibrium condition for this system is NG/V = nre-A/KT', with ny =1.93 x 1031 m-3, and that the nitrogen gas is ideal.
a. 0.081 eV
b. 81 eV
c. 0.0081 eV
d. 0.81 eV
e. 8.1 eV

Answers

What did he sayyyyyyy

Watch for signs that your vehicle is actually ________ by other drivers.

Answers

Answer:

Seen

Explanation:

The correct answer to the given question is Seen

The complete sentence is:

Watch for signals that your vehicle is actually seen by other drivers.

This is the correct answer and completes the sentence given in the question.

The blank area is to be filled with the word Seen which will complete the sentence.

Type the correct answer in the box. Spell all words correctly. Ronny wants to calculate the mechanical advantage. He needs to determine the length of the effort arm and the length of the load arm. How can he find the length of the effort arm? The length of the effort arm is the distance between the _____ and the point at which effort is applied.

Answers

Answer:

Fulcrum

Explanation:

The length of the effort arm is the distance between the Fulcrum and the point at which effort is applied.

Mechanical advantage is a measure of the ratio of output force to input force in a system, used to analyze the forces in simple machines like levers and pulleys. Despite changing the forces that are applied the conservation of energy is still true and the output energy is still equal to the input energy. Typically the mechanical advantage is expressed in ideal terms, where there is no losses in energy between the input and output times, also known as 100% efficient systems.

By conservation of energy:

Fi×di=Fo×do

A 2x10 wood beam is to support a service dead load (including beam self-weight) of 50 lbs/ft and a service live load of 60 lbs/ft (note that the loads given are per foot and not per square ft). The beam is part of a series of adjacent parallel beams spaced 16 inches apart. Span length is 15 ft. Assume that lateral buckling is prevented. Wood species/grade is "Red Maple", No.1. Moisture content is less than 19% (dry). This member’s service temperature is not elevated. What is the design moment strength (M'n) in kip-in?

Answers

Answer:

The answer is "[tex]30.83 \ kip-in[/tex]"

Explanation:

[tex]\to D.L = 50 \ \frac{ lbs}{ft} \\\\\to L.L = 60\ \frac{ lbs}{ft}\\\\[/tex]

Factered load [tex]w_u= 1.2 D.L+1.6 \ D.L[/tex]

                           [tex]= 1.2 \times 50 +1.6\times 60\\\\= 60 +96\\\\=156 \ \frac{ lbs}{ft}\\\\= 131 \frac{ lbs}{in}\\\\[/tex]

[tex]A= bd= 2\times 10 = 20 \ in^2\\\\Z= \frac{bd^2}{6} =\frac{2\times10^2}{6}= 33.33 \ in^3 \\\\L= 15 \ ft = 180 \ inch[/tex]

bending strength[tex]= f_b =925 \ psi[/tex]

shear strength[tex]= f_v = 120 \ psi[/tex]

movment strength [tex]m_h= z \times f_b[/tex]

                                   [tex]= 33.33 \times 925\\\\ = 20830.25 \ lb-in \\\\ = 30.83 \ kip-in[/tex]

The utility companies often sell electric power at night at much lower prices since the demand for electric power is usually much higher during the day. The owner of a four-story Hotel would like to take advantage of this opportunity. The owner decides to design a pump piping system that delivers water from the lake to the large pool (or reservoir) located on the roof of the Hotel. The owner wants to fill the pool from sea water during the night when the electric power is cheap and to use the water during the day.

Therefore, the owner decides to hire a mechanical engineer to design this piping pump system to deliver the water from the close lake to the reservoir on the roof of the building. As a hired mechanical engineer, you are supposed to design this piping pump system by selecting the desired pipe size, flow rate and all necessary fittings, and determine the horsepower of the pump required for such a delivery.

Answers

Answer:

the electric is cheaper

Explanation:

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