Add these fractions using fraction bars after choosing a common denominator Use the fraction bar inactivate to find the difference

Add These Fractions Using Fraction Bars After Choosing A Common Denominator Use The Fraction Bar Inactivate

Answers

Answer 1

The fractions you have to add are 1/3 and -5/6

[tex]\frac{1}{3}+(-\frac{5}{6})[/tex]

The denominators are "3" and "6"

The common denominator between both numbers is 6.

6*1=6

3*2=6

Multiply 1/3 by factor 2 so that both fractions will have the same denominator

[tex]\frac{1}{3}\cdot2=\frac{1\cdot2}{3\cdot2}=\frac{2}{6}[/tex]

Now you can add both fractions

[tex]\frac{2}{6}+(-\frac{5}{6})=\frac{2}{6}-\frac{5}{6}=\frac{2-5}{6}=-\frac{3}{6}[/tex]

The result is not in its most reduced form, to siplify the fraction divide both the numerator and denominator by 3

[tex]-\frac{3}{6}\div3=-\frac{1}{2}[/tex]

The result is -1/2, in the number line:

Add These Fractions Using Fraction Bars After Choosing A Common Denominator Use The Fraction Bar Inactivate

Related Questions

While reviewing the previous day’s arrest report, a police sergeant that seven suspects were arrested, all of whom had either one or two previous arrests. Including yesterday arrests, there were 16 total among them. How many suspects had had less than two prior arrests?

Answers

ANSWER :

EXPLANATION :

Michael wants to save $55,000.00 for a down payment on a home. How much will he need to invest in anaccount with 8.5% APR, compounding daily, in order to reach his goal in 3 years?

Answers

Step 1. The information that we have is:

The final amount that Michael wants to save is:

[tex]A=55,000[/tex]

We will call that amount A.

The annual percentage rate of the investment, which we will label as r, is:

[tex]r=8.5[/tex]

We will need this annual percentage rate represented as a decimal number, therefore, we divide it by 100:

[tex]\begin{gathered} r=8.5/100 \\ r=0.085 \end{gathered}[/tex]

The time of the investment, t, is 3 years:

[tex]t=3[/tex]

And it is compounded daily, let n be the number of times of compounding in a year:

[tex]n=365[/tex]

Step 2. We need to find the initial amount of the investment, which will be called P or principal.

The formula we will use to find it is:

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

Step 3. Substituting the known values:

[tex]55,000=P(1+\frac{0.085}{365})^{(365)(3)}[/tex]

From this equation, we need to solve the operations and solve for P, the principal amount of the investment.

Step 4. Simplifying the equation:

[tex]55,000=P(1+0.0002328767)^{1095}[/tex]

Continue simplifying:

[tex]\begin{gathered} 55,000=P(1.0002328767)^{1,095} \\ 55,000=P(1.2904233) \end{gathered}[/tex]

Then, we solve for P:

[tex]\begin{gathered} \frac{55,000}{1.2904233}=P \\ 42,621.6726=P \end{gathered}[/tex]

Rounding to the nearest cent (2 decimal places) The amount that he needs to invest is $42,621.67

Answer: $42,621.67

What are the coordinates of the four vertices and the two foci?

Answers

[tex]\begin{gathered} \frac{(x-2)^2}{36}+\frac{(y+1)^2}{25}=1 \\ \text{Foci} \\ F1\text{ (}h+c,k\text{)} \\ F2(h-c,k) \\ (h,k)=(2,-1) \\ c=\sqrt[]{a^2-b^2} \\ \text{from the equation} \\ a^2=36 \\ b^2=25 \\ c=\sqrt{36-25} \\ c=\sqrt{11} \\ Foci\text{ 1= (2}+\sqrt{11},-1) \\ Foci\text{ 2= (2-}\sqrt[]{11},-1) \\ \text{Vertices } \\ V1=(h+a,k) \\ V2=(h-a,k) \\ V1=(2+6,-1) \\ V1=(8,-1) \\ V2=(2-6,-1) \\ V2=(-4,-1) \end{gathered}[/tex]

B.
The scale of figure A to figure B is 1 to 2. If the area of figure A is 7 ft2, what is the area of figure B?
OA. 3.5 ft²
OB. 35 ft²
OC. 14 ft²
OD. 28 ft²

Answers

I think it’s B goodluck!!

need help with this as soon as possible, answer quick

Answers

Answer:

Given points are,

A'(2,3) and A(3,-4), under the translation.

we get the graph as,

where B is A(3,-4) and A is A'(2,3).

A translation by 1 unit left and 7 units up.

Answer is:

A translation by 1 unit left and 7 units up.

Which factoring do we use and why and how to know the difference between factoring simple trinomial and perfect square

Answers

By definition, a perfect square trinomial is a trinomial that can be written as the square of a binomial. It is in the form:

[tex]a^2+2ab+b^2=(a+b)(a+b)[/tex]

The simple trinomial is in the form:

[tex]ax^2+bx+c[/tex]

Not all the simple trinomials can be written as the square of a binomial, then we need to check if the trinomial follows the structure of the perfect square trinomial. If it doesn't, then the factors won't be the same, and this is the main difference.

a. The given trinomial is:

[tex]x^2+5x+6[/tex]

If it is a perfect square trinomial then:

[tex]\begin{gathered} a^2=x^2 \\ a=x \\ b^2=6 \\ b=\sqrt[]{6} \\ 2ab=5x \\ 2\cdot x\cdot\sqrt[]{6}\ne5x \\ \text{Then it is not a perfect square trinomial} \\ x^2+5x+6=(x+3)(x+2)\text{ It is a simple trinomial} \end{gathered}[/tex]

b. The given trinomial is:

[tex]x^2+6x+9[/tex]

Let's check if it is a perfect square trinomial:

[tex]\begin{gathered} a^2=x^2\to a=x \\ b^2=9\to b=\sqrt[]{9}=3 \\ 2ab=2\cdot x\cdot3=6x \\ \text{This is a perfect square trinomial, then } \\ x^2+6x+9=(x+3)(x+3)=(x+3)^2 \end{gathered}[/tex]

Show that Polygon ZSCH
is a Scaled copy of
Polygon XJYN.

Answers

As ratio is not given, we cannot prove that they are scaled copy.

Define scaled copy.

Corresponding portions, or parts that are at the same location in relation to the remainder of each figure, exist in both the original figure and its scaled copy. These components could be angles, points, or segments. Polygon 2, for instance, is a scaled-down version of Polygon 1. There is a point in Polygon 2 for each point in Polygon 1.

Given,

Polygon ZSCH is a Scaled copy of Polygon XJYN.

We simply calculate the ratio of the lengths of the two corresponding sides of two polygons to determine the scale factor. The scaling factor is known as such and the polygons are similar if the ratio is the same for all matching sides.

As ratio is not given, we cannot prove that they are scaled copy.

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Determine the angle relationship. Drag the correct answer to the blank. what is the angle relationship of < 3 & <7

Answers

we have that

between m<3 and m<7 -----> no relationship (because q and p are not parallel)

Part 2

the relationship between m<12 and m<10

is

vertical angles

m<12=m<10 ------> by vertical angles

Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.

Answers

Hayley's rectangular bedroom is 6 meters by 5 meters. What is the diagonal distance from one corner to the opposite corner? If necessary, round to the nearest tenth.

Apply the Pythagorean Theorem

c^2=a^2+b^2

we have

a=6 m

b=5 m

c^2=6^2+5^2

c^2=36+25

c^2=61

square root c=7.8 m

answer is 7.8 meters

What are three ratios equivalent to 9/5?

Answers

The given ratio is 9/5

This ratio is already in the simplified form. To find equivalent ratios, we would multiply the numerator and denominator by constant numbers. We have

If we multiply by 2, it becomes

9 * 2/5 * 2 = 18/10

If we multiply by 3, it becomes

9 * 3/5 * 3 = 27/15

If we multiply by 4, it becomes

9 * 4/5 * 4 = 36/20

Thus, three equivalent ratios are

18/10, 27/15 and 36/20

a computer program is in Shannon's computer carries out a single mathematical operation in 1.5 * 10 over 6 seconds how much time would the program take to complete 2.5 * 10/3 mathematical operations

Answers

Question:

Solution:

This computer program carries out a single mathematical operation in

[tex]1.5x10^{-6}\text{ seconds}[/tex]

then, to complete 2.5 x 10^3 mathematical operations the program will take a time of:

[tex](1.5x10^{-6})(2.5x10^3)=3.75x10^{-3}[/tex]

thus, the correct answer is:

[tex]3.75x10^{-3}[/tex]

The coordinates of triangle LMN are shown.YL(-1,4)XN (4, -1)M(-1, -3)What is the length of LM? Enter the answer in the box.unit(s)

Answers

Given data:

The given coordinate of L is (-1,4).

The given coordinate of M is(-1, -3).

The expression for LM length is,

[tex]\begin{gathered} LM=\sqrt[]{(-1-(-1))^2+(-3-4)^2} \\ =\sqrt[]{0+49} \\ =7 \end{gathered}[/tex]

Thus, the LM length is 7 units.

O EQUATIONS AND INEQUALITIESSolving a word problem with three unknowns using a linear...

Answers

Given:

The sum of three numbers is 81, The third number is 2 times the second, The first number us 9 moe than the second.

Required:

We need to find all the numbers

Explanation:

Assume that a, b and c are the first, second and third numbers respectively.

By given ststement

[tex]\begin{gathered} a+b+c=81\text{ .....\lparen i\rparen} \\ c=2b\text{ .....\lparen ii\rparen} \\ a=b+9\text{ .....\lparen iii\rparen} \end{gathered}[/tex]

substitute c and a in equation (i)

[tex]\begin{gathered} b+9+b+2b=81 \\ 4b=72 \\ b=18 \end{gathered}[/tex]

now put value of b in equation (ii) and (iii)

[tex]c=2*18=36[/tex]

and

[tex]a=18+9=27[/tex]

FInal answer:

first number a = 27

second number b = 18

third number c = 36

Find the equation of the linear function represented by the table below in slope-intercept form. Answer: y=

Answers

Answer:

y = 2x + 6

Explanation:

The slope-intercept form of a linear equation can be found as:

[tex]y=m(x-x_1)+y_1[/tex]

Where m is the slope and it is calculated as:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

And (x1, y1) and (x2, y2) are values from the table. So, we can replace (x1, y1) by (0,6) and (x2, y2) by (1, 8):

Then, the slope is:

[tex]m=\frac{8-6}{1-0}=\frac{2}{1}=2[/tex]

Therefore, the equation of the line is:

[tex]\begin{gathered} y=2(x-0)+6 \\ y=2x+6 \end{gathered}[/tex]

So, the answer is y = 2x + 6

In a robotics competition, all robots must be at least 37 inches tall to enter the competition.Read the problem. Which description best represents the heights a robot must be?Any value less than or equal to 37Any value greater than or equal to 37Any value greater than 37Any value less than 37

Answers

Solution

Since the robots must be at least 37 inches tall to enter the competition.

Therefore, the height of any robot must be Any value greater than or equal to 37

Decide whether or not the number 46/45 Could represent the probability

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Solution

- A probability, by definition, is a fraction that is less than or equal to 1.

- The number 46/45 is a number greater than 1.

- Thus, the number 46/45 CANNOT be a probability

A line passes through the point (-6,1) and has a slope of -5/2

Write an equation in slope - intercept form for this line .

Answers

Answer: [tex]y=-\frac{5}{2}x+16[/tex]

Step-by-step explanation:

The equation in point-slope form is [tex]y-1=-\frac{5}{2}(x+6)[/tex]. To find the equation in slope-intercept form, isolate [tex]y[/tex].

[tex]y-1=-\frac{5}{2}(x-6)\\\\y-1=-\frac{5}{2}x+15\\\\y=-\frac{5}{2}x+16[/tex]

Question is stated in picture. The figure is a triangular piece of cloth

Answers

Answer:

Alternative D - 8 sin(35°)

Step-by-step explanation:

Sin(x) is defined as:

[tex]\begin{gathered} \sin (x)=\frac{\text{Opposite side}}{Hypotenuse\text{ }} \\ \end{gathered}[/tex]

In this exercise,

BC is the opposite side to 35°

AC is the hypotenuse and measures 8 in

Then:

[tex]\begin{gathered} \sin (35\degree)=\frac{BC}{8} \\ \sin (35\degree)\cdot8=BC \\ BC=8\sin (35\degree) \end{gathered}[/tex]

Hello can you please help me with problem number 12

Answers

Turn the 48in to ft

[tex]\begin{gathered} 1ft=12in \\ \\ 48in\times\frac{1ft}{12in}=4ft \end{gathered}[/tex]

Then, 48 inches is equal to 4ft.

Comparing the given quatities you get that:

48inches > (greater than) 3ft

Each year, a scientist measures the water level of a local lake. Negative numbers indicatethat the water level is below its historical average. Which list shows the water levels in orderfrom highest to lowest?0.7, 0.38, 0.09, – 0.41, – 0.60.7, 0.38, 0.09,-0.6,- 0.41-0.6, 0.38, – 0.41, 0.09, 0.70.38, 0.09, 0.7,– 0.6 – 0.410.38, 0.7, 0.09 – 0.41, -0.6

Answers

Answer:

-0.6, -0.41, 0.09, 0.39, 0.7

Step-by-step explanation:

Negative numbers: The higher the absolute number, the lower it is. For example, -2 is lower than -1.

Positive numbers: The lower the absolute number, the lower it is. For example, 1 is lower than 2.

In this question:

We have these following values:

0.7, 0.39, 0.09, -0.41, -0.6

Ranking from lowest to highest, it is:

-0.6, -0.41, 0.09, 0.39, 0.7

use your theorem from 2-37 about the angles in a triangle to find in the diagram below. show all work.

Answers

We have that, for any triangle, the sum of all its angles equals 180. In this case, we have the following:

[tex]96+2x+(x+12)=180[/tex]

Now we solve for x to get the following:

[tex]\begin{gathered} 96+2x+x+12=180 \\ \Rightarrow2x+x=180-96-12 \\ \Rightarrow3x=72 \\ \Rightarrow x=\frac{72}{3}=24 \\ x=24 \end{gathered}[/tex]

We have that x = 24, now to find the angles, we substitute this value on each expression:

[tex]\begin{gathered} 2x \\ x=24 \\ \Rightarrow2(24)=48 \\ x+12 \\ \Rightarrow24+12=36 \end{gathered}[/tex]

therefore, the remaining angles are 48° and 36°

The line 3x + 4y - 7 = 0 is parallel to the line k . x + 12y + 3 = 0. What is the value of k?

Answers

The function is solved below

What is a function?

The function is instantly given a name, such as a, in functional notation, and its description is supplied by what it does to the input x, using a formula in terms of x. Instead of sine, put sine x. (x). Leonhard Euler invented functional notation in 1734. Some commonly used functions are represented with a symbol made up of many letters (usually two or three, generally an abbreviation of their name). In this scenario, a roman font is typically used, such as "sine" for the sine function, rather than an italic font for single-letter symbols. A function is also known as a map or a mapping, however some writers distinguish between "map" and "function."

The function can be written as

3x+4y-7 = 0

or, y = (-3/4)x + 7/4

so, slope = -3/4

and other function is

kx+12y+3 = 0

or, y = (-k/12)x - 1/4

so, slope = -x/12

Given the lines are parallel, so slopes are equal

i.e., -3/4 = -k/12

or, k = (3/4)12 = 9

Hence, the value of k is 9.

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If a red and a blue fair six sided die are rolled what is the probability the result is 8 or divisible by 3?

Answers

SOLUTION:

Step 1:

In this question, we are given that;

If a red and a blue fair six-sided die are rolled.

What is the probability the result is 8 or divisible by 3?

Step 2:

The table for the two dice rolled together is as shown below:

Green 1 2 3 4 5 6

Red

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

Step 3:

The probability that the result is 8 =

[tex]\begin{gathered} =\text{ }\frac{\nu mber\text{ of 8}}{\text{Total number }} \\ =\text{ }\frac{5}{36} \end{gathered}[/tex]

Next,

The probability that the result is divisible by 3

=

[tex]\frac{12}{36}[/tex]

Finally, the probability that the result is 8 or divisible by 3, we have that:

[tex]\frac{5}{36}+\frac{12}{36}\text{ =}\frac{17}{36}[/tex]



In ACDE, J is the centroid. If JG=21 find CG. D F G C E H

Answers

Let's begin by identifying key information given to us:

We have triangle CDE

J is the centroid

[tex]\begin{gathered} JG=21 \\ \text{The centroid of a triangle divides }\frac{2}{3\text{ }}\text{the distance from}verte\text{x to midpoint of the sides} \\ \Rightarrow JG=\frac{2}{3}CG \\ \Rightarrow21=\frac{2}{3}CG=\frac{63}{2} \\ \therefore CG=\frac{63}{2}=31.5 \end{gathered}[/tex]

given the residual plot below, which of the following statements is correct?

Answers

Let me explain this question with the following picture:

We can recognize a linear structure when all the points have a pattern that seems like a straight line as you can see above for example.

In the graph of your question, we can see that the points don't have a definited pattern and that's clearly not seemed like a straight line.

Therefore, the answer is option B:

There is not a pattern, so the data is not linear.

160 is what percent of the sum of 100 and 120 and 160

Answers

42.105%

1) Let's first add thosse numbers up: 100 +120+160 =380

2) Now we can write out the following ratio, to find out what percentage is equivalent to 160 out of that 380:

[tex]\begin{gathered} 160----x \\ 380----100 \\ \frac{160}{380}=\frac{x}{100} \\ 380x=16000 \\ \frac{380x}{380}=\frac{16000}{380} \\ x=42.105\% \end{gathered}[/tex]

Note that we had to cross multiply that.

3) Hence, the answer is 160 is approximately 42.105% of 380

I got the first part I’m not sure of the 2nd is it 38.5

Answers

We will have the following:

The surface area of the onion can be best modeled by a sphere. Base on the model, the approximate area of the onion is 38.5 square inches:

[tex]A_s=4\pi(\frac{3.5}{2})^2\Rightarrow A_s\approx38.5[/tex]

the rate of change at which the water level rises is ___ centimeters per minutes. so, involving the equation ____ for y gives a y-value equal to___

Answers

We will have the following:

The rate at which the water rises is 13/4 cm per minute.

So, solvinng the equation:

[tex]\frac{13}{4}=\frac{y}{12}[/tex]

For y gives a value for y equal to:

[tex]y=\frac{13\cdot12}{4}\Rightarrow y=39[/tex]

Solve the following system algebraically. y= x2 - 9x + 18 y = x - 3

Answers

we have

y=x^2-9x+18 -----> equation A

y=x-3 ------> equation B

Solve the system of equations

substitute equation B in equation A

x^2-9x+18=x-3

x^2-9x+18-x+3=0

x^2-10x+21=0

Solve the quadratic equation using the formula

[tex]x=\frac{-b\pm\sqrt[\square]{b^2-4ac}}{2a}[/tex]

we have

a=1

b=-10

c=21

substitute the given values

[tex]\begin{gathered} x=\frac{-(-10)\pm\sqrt[\square]{(-10)^2-4(1)(21)}}{2(1)} \\ \\ x=\frac{10\pm\sqrt[\square]{100-84}}{2} \\ \\ x=\frac{10\pm\sqrt[\square]{16}}{2} \\ \\ x=\frac{10\pm4}{2} \\ \\ x=7 \\ x=3 \end{gathered}[/tex]

Find the value of y for x=7

y=x-3

y=7-3=4

the first solution is (7,4)

Find the value of y for x=3

y=3-3=0

the second solution is (3,0)

therefore

the answer is the first option

Jim began a 156 mile bike trip to build up stamina . Unfortunately his bike chain broke so he finished walking. Th whole trip took 6 hours. If Jim walks at a rate of 5 miles per hour and rides at 33 miles per hour find the amount he spent on the bike.

Answers

This diagram represents the problem

We know that distance = speed*time; D=S*t

Total distance: 156 miles

time: 6 h

Speed1: 33 miles/h

Speed2: 5 miles/h

for interval 1:

[tex]\begin{gathered} D_1=S_1\cdot t_1 \\ D_1=33\cdot t_1 \end{gathered}[/tex]

for interval 2:

[tex]\begin{gathered} D_2=S_2\cdot t_2 \\ D_2_{}=5\cdot t_2 \end{gathered}[/tex]

for the whole trip: -Eq 1. Distance

[tex]\begin{gathered} D=D_1+D_2 \\ D=33\cdot t_1+5\cdot t_2 \\ 156=33\cdot t_1+5\cdot t_2 \end{gathered}[/tex]

and also: -Eq 2. Time

[tex]\begin{gathered} t=t_1+t_2 \\ 6=t_1+t_2 \end{gathered}[/tex]

Now we have a system of 2 equations with 2 unknowns.

Let's solve it!

[tex]\begin{gathered} 156=33t_1+5t_2 \\ t_1=\frac{156-53t_2}{33} \\ \frac{156-5t_2}{33}+t_2=6 \\ t_2=\frac{3}{2} \\ t_1=\frac{156-5\cdot\frac{3}{2}}{33} \\ t_1=\frac{9}{2} \end{gathered}[/tex]

We can see that he spent 4.5 hours riding the bike and 1.5 h walking

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