an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the three devices are in parallel when plugged into the same socket.) what current is drawn by the electric frying pan?

The springs inside a bathroom scale will be more compressed.

What is acceleration due to gravity?

In physics, gravitational acceleration is the acceleration of an object in free fall in a vacuum (hence no resistance). This is a steady increase in velocity caused solely by the gravitational pull. All objects accelerate at the same speed in a vacuum, regardless of their mass or composition . The measurement and analysis of these velocities is known as gravimetry.

At a fixed point on the surface, the magnitude of the Earth's gravity is the combined effect of gravity and the centrifugal force due to the rotation of the Earth. Free-fall acceleration at various points on the Earth's surface ranges from 9.764 to 9.834 m/s2 (32.03 to 32.26 ft /s2) depending on altitude, latitude and longitude . The old standard is precisely defined as 9.80665 m/s2 (32.1740 ft/s2). Locations that deviate significantly from this value are called gravity anomalies. Other effects such as lift and air resistance are not taken into account.

When the elevator accelerates and shows a higher weight reading. As the lift accelerates and descends, the springs in the bathroom scale are compressed less and the displayed weight value is reduced.

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The answer is true about the cabins in commercial airliners that require pressurization.

Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.

So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.

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Considering the definition isotopes and atomic mass of an element, the average atomic mass of element x is 12.1

The same chemical element can have the same atomic numbers, but the number of neutrons is different. These atoms are called isotopes of the element.

The atomic masses of chemical elements are calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

In this case, you know:

The average mass of the element x can be calculated as:

average mass of element x=12 amu×0.95 + 14 amu×0.05

average mass of element x= 12.1 amu

Finally, the atomic mass of the element x is 12.1.

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Answer:

490.5

Explanation:

Force = Mass × Acceleration

Since, Weight is a force and 'g' is the acceleration due to the earth's gravity,

Weight = Mass × g

Weight = 50 kg × 9.81 m/s² = 490.5 kg-m/s² or 490.5 N

The two stones will fall at the different time. But the difference between the time is just of one second.

The distance of the cliff is also considered. Here, the speed or velocity is asked. To calculate this we have to use the equation of motion.

There are three equations of motion.

We have;

The kinematic equation of motion that can be used is s = ut - (1/2)·gt²

For the first stone, we have, s₁ = ut₁ - (1/2)·gt₁²

For the second stone, we get; s₂ = ut₂ - (1/2)·gt₂²

g = The acceleration due to gravity ≈ 9.81 m/s²

s = The distance below the cliff top

The initial velocity of the stones, u = 0

To calculate the change of distance between the two stones,

we will subtract the two equation of motions are

s₁-s₂

With all the values kept together in the equation of motion, we can easily find the change of distance between the two stones.

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The elasticity and Poisson's ratio for this metal is 0.232.

What is ratio?

The realation between two numbers which shows how much bigger one quantity is than another.

Sol-

As per the given question

P=190KN

d=16 mm

Lo=50mm

X=50.1349-50=0.1349mm

Y=15.99-16=-0.01mm

The formula-

E=ó/€

Ó=P/A

A=r/4 d^2 =π/4(16)^2=201.062 mm

ó={190(1000)}201.062=944.982 Mpa

E=944.982/0.002698=350.253 GPa

€y=-0.000625

v=0.232(answer)

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a. The speed of the satellite is  244 m/s

b. The period of the satellite is 1.72 × 10⁷ s

c. The radial acceleration of the satellite is 8913 rad/s

The speed of the satellite is given by v = √(GM/R) where

So, substituting the values of the variables into the equation, we have that

v = √(GM/R)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6380 km + 300 km)

v = √(6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg /6680 km)

v = √(39.83324 × 10¹³ Nm²/kg ÷ 6.680 × 10⁶ m)

v = √(5.963 × 10⁻³ × 10⁷ Nm²/kg)

v = √(5.963 × 10⁴ Nm/kg)

v = 2.44 × 10² m/s

V = 244 m/s

So, the speed of the satellite is  244 m/s

The period of the orbit is given by T = 2πR/v where

So, substituting the values of the variables into the equation, we have

T = 2πR/v

T = 2π × 6680 km/244 m/s

T = 2π × 6680 × 10³ m/244 × 10⁵ m/s

T = 13660π × 10³ m/244 × 10⁵ m/s

T = 41971.68 × 10³ m/244 × 10⁵ m/s

T = 17201.5 × 10³ s

T = 1.72015 × 10⁷ s

T ≅  1.72 × 10⁷ s

So, the period of the satellite is 1.72 × 10⁷ s

The radial acceleration of the satellite is given by a = v²/R where

Substituting the values of the variables into the equation, we have

a = v²/R

a = (244 m/s)²/6680 km

a = 59536 m²/s²/6680 × 10³ m

a = 8.913 × 10³ rad/s

a = 8913 rad/s

So, the radial acceleration of the satellite is 8913 rad/s

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The speed with which they threw the bundle is  14 m/s.

We know that the speed of the bundle can be obtained from the use of the equations of kinematics. Now we can use the equation of the upward motion under gravity here.

Using;

v^2 = u^2 - 2gh

v = final velocity

u = initial velocity

g = acceleration due to gravity

h = height

Now;

v = 0 m/s at the maximum height

u^2 = 2gh

We now have;

u = √2gh

u = √ 2 * 9.8 * 10

u = 14 m/s

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The direction of the velocity of the clod of dirt relative to the truck just before it hits is in the same direction as that of the truck.

The direction of the velocity of the clod of dirt relative to the ground just before it hits is in the opposite direction as that of the ground.

The relative velocity of an object in motion is the velocity of that object when viewed from a reference point.

The direction of the velocity of the clod of dirt before it hits the ground is in the same direction as that of the truck.

However, compared to the ground, the direction of the relative velocity is in the opposite direction.

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Given data

*The given mass of the car is m = 1475 kg

*The maximum tension is T = 2551 N

The formula for the maximum possible acceleration of the truck is given by Newton's second law as

Substitute the known values in the above expression as

Hence, the maximum possible acceleration of the truck is a_max = 1.72 m/s^2

Answer:

the velocity of a ball at highest point is 8.5m/s

Explanation:

: The Freefall Problem

Xue,is standing on the roof of a building. Emily is standing below and tosses a ball straight upwards to Xue. It travels up past

Xue, comes back down and Xue reaches out and catches it. Xue catches the ball 6.0 m above Emily’s hands. The ball was

travelling at 12.0 m/s upwards the moment it left Emily’s hand. We would like to know how much time this trip takes.

1. Represent. Complete part A below. Indicate the y-origin for position measurements and draw a sign convention where

upwards is positive. Label the important events.

2. Represent. Complete part C below. Make sure the two graphs line-up vertically. Draw a single dotted vertical line

through the graphs indicating the moment when the ball is at its highest.

A: Pictorial Representation

Sketch, coordinate system, label givens, conversions, describe events

Event 1:

Event 2:

Event 3:

C: Physics Representation

Motion diagram, motion graphs, key events

The total length of the path traveled by an object is the distance. The change in position, from one event to another is the

displacement. Distance is a scalar quantity and displacement is a vector quantity.

3. Reason. Explain why this in this example it is relatively easy to find the displacement, but harder to find the distance.

4. Reason. The BIG 5 equations are valid for any interval of motion where the acceleration is uniform. Does the ball

accelerate uniformly during events 1 and 3? Explain D: Mathematical Representation

Describe steps, complete equations, substitutions with final statement isThere are multiple ways of solving…one

will require the use of the quadratic formula.

The other way will take additional steps.

x = -b+-under root b^2-4ac/2a

Mechanical advantage is a measure of the ratio of the output force produced to the input force applied in a system, mainly in the case of simple machines, such as levers and pulleys. It is a dimensionless quantity.

From the definition, the mechanical advantage of a simple machine is inversely proportional to the input force applied on the system. So, an increase in this force decreases the mechanical advantage of a simple machine.

For example, the mechanical advantage of a lever can be decreased by increasing the force on load arm or by reducing the force on the effort arm.

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Given data

*The given mass of the car is m = 1610 kg

*The given effective force constant is k = 5.75 × 10^4 N/m

(a)

The formula for the period of oscillation of a 1610 kg car is given as

Substitute the known values in the above expression as

Hence, the time period of oscillation of a 1610 kg car is T = 1.05 s

(b)

As from the given data, the amplitude of the oscillation of the car decreases by a factor of 5.00. Then, the expression for the amplitude of the oscillation, and the damping constant (b) is calculated as

Substitute the known values in the above expression as

Hence, the damping constant is b = 9871.2 kg/s

The acceleration of the object will be 13.33 m/s^2.

According to Newton's second law of motion,

The magnitude of Force is equal to the product of the mass of the body and the acceleration it is given ( or achieves ).

The units of force, mass and acceleration are Newton, kg and m/s^2 respectively.

In numerical terms,

Force = mass × acceleration

i.e. F = m × a

Given,

mass of the body = 15 kg

Force applied to the body = 200 N.

Putting these values in the equation,

200 = 15 × a

=> a = 200/15

=> a = 13.33 m/s^2.

Therefore, the acceleration of the given body will be 13.33 m/s^2.

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Answer:

25000Nm⁻² using rounded g figure

Explanation:

The box is in cm. It needs to be converted into SI metres.

1m = 100cm

1cm = ( 1 / 100 )m

2cm = ( 1 / 50 )m

A = ( 1 / 2500 )m²

Assume that g = 10ms⁻¹. Use your own definition.

F = 10N

P = F / A

P = 10N( 2500 )m⁻²

25000Nm⁻²

Answer:

Explanation:

Given:

m = 2 kg

a = 2 cm = 0.02 m

g =9.8 m/s²

_______________

P - ?

Area of the cube:

S = a² = 0.02² = 0,0004 m²

Gravity:

F = m·g = 2·9.8 = 19.6 N

Pressure:

p = F / S =  19.6 / 0,0004 = 49 000 N/m²

The freight train has a momentum of mv = (4.5 × 105 kg)(1.4 m/s) = 6.3 ×105 kg-m/s.

An automobile with a mass of 1800 kg would need to go at a speed of 6.3  × 105 kg-m/s ÷ 1800 kg = 350 m/s in order to have a momentum of the same magnitude. (Roughly 800 mph)

A moving body's amount of motion is referred to as momentum. It has units of kg m/s and is theoretically represented as p = m * v.

The momentum equation connects the total force exerted on a fluid element to its acceleration or rate of change of momentum and is a formulation of Newton's Second Law. You're certainly familiar with the formula F = ma, which links applied force and acceleration in solid mechanics analysis.

Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

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Answer:

Resultant force of the given forces: approximately [tex]11.2\; {\rm N}[/tex] at approximately [tex]53^{\circ}[/tex] west of south.

Explanation:

The resultant force of these forces will be:

Refer to the diagram attached. The resultant [tex]5\; {\rm N}[/tex] force to the south and the [tex]10\; {\rm N}[/tex] force to the west are perpendicular to each other, forming the two legs of a right triangle. The hypotenuse of this right triangle will be the net effect of these two forces.

Apply Pythagorean's Theorem on this triangle to find the magnitude of this net effect:

[tex]\begin{aligned}(\text{length of hypotenuse}) &= \sqrt{10^{2} + 5^{2}} \approx 11.2\end{aligned}[/tex].

Hence, the magnitude of this net effect will be approximately [tex]11.2\; {\rm N}[/tex].

Let [tex]\theta[/tex] denote the angle between this resultant force and west. In this right triangle:

[tex]\begin{aligned} \tan(\theta) &= \frac{(\text{opposite})}{(\text{adjacent})} \\ &= \frac{5\; {\rm N}}{10\; {\rm N}} \\ &= \frac{1}{2}\end{aligned}[/tex].

[tex]\begin{aligned} \theta &= \arctan\left(\frac{1}{2}\right) \approx 27^{\circ}\end{aligned}[/tex].

Hence, the angle between this resultant force and south will be approximately [tex](90^{\circ} - 27^{\circ}) = 63^{\circ}[/tex]. This resultant force will be at approximately [tex]63^{\circ}[/tex] west of south.

The net force on an object if a  force of 30 N to the right is applied to an object. An opposite force of 20 N to the left is applied to the same object is 10 N to the right. And the right option is D.

The net force is the vector sum of all the forces that act upon an object.

To calculate the net force applied to the object, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence the right option is D. 10 N to the right.

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Measures the diameter of a shotgun's barrel in terms of the quantity of lead balls needed to make the bore weigh one pound (12 gauge is the diameter of a lead ball weighing one-twelfth of a pound).

A shotgun has many projectile properties while a rifle only comes with one. Shotguns are helpful at close ranges when rifles are useful at a distance. Shotguns only have a front sight, whereas rifles have both front and rear sights.

Rifles are typically a little noisier than shotguns. Analyzing test results reveals that shotguns and rifles have decibel levels that are comparable. The typical decibel range

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At initial speed must the quarter back through the ball for it to reach the reciver.

What is initial speed

The initial speed is the velocity at which motion start.

Sol-

The horizontal velocity is Vi*cos38.6and the vertical velocity is Vi*sin38.6

horizontal

28.4=Vi*cos38.6 time find time in terms of Vi.

Vertical

hf=hi+Vi*sin38.6*t -1/2 g t^2

now hf=hi=0

so

0=Vi*sin 38.6-1/2 g t and put the expression you got for t, then solve for Vi. You will encounter the need for one trig identity.

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The problem describes a situation where a bullet is launched at a certain angle respect to the horizontal to hit in the target, given the launching conditions and the distance to the target. The formulas to compute the magnitudes involved in the projectile motion are

x=[tex]v0[/tex] cos0 t

Y=[tex]V0[/tex] sin0 t

xm=[tex]v0[/tex]² sin 20/g

[tex]Xm[/tex] is the maximum horizontal distance the object can reach when it returns to the ground (or launching height).

let's check if X is computed correctly .

The set of data is correct. We can now proceed to the required distance. We know the bullet is shot directly to the target, so the angle is 0, keeping the same speed. The new maximum distance is 150 m, so we can compute the time needed to complete the flight

since

Let's find the time from the formula

X=[tex]V0[/tex] cos0 t

t=[tex]Xm[/tex]/[tex]V0[/tex] cos0

t=150/100=1.5

Y=(9.8)(0.66)²÷2

Y=-2.134

The bullet will hit 2.134 meters below the target

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The height of the cliff is 24.2 m.

Let:

Using the Second Equation of Motion:

                               [tex]h = ut + 1/2 at^{2} \\h = 0 + 1/2 (10)(2.2)^{2} \\h = 0 + 5(2.2)^{2} \\h = 5(4.84)\\h = 24.2m[/tex]

The Second Equation of Motion establishes a relationship between displacement and time. It can be used to calculate the displacement and time, in different conditions.

The cliff was 24.2m high above the water surface, into which the cliff diver dived.

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A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0.35. The horizontal force is required for an acceleration of 2.0 m/s2 will be 54.3 N

Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object.  The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.

equation of motion will be

F(net) =  mass * acceleration

F - fr = m * a

where

F = force by which the box is moving

fr = force due to friction

m = mass of the object

a = acceleration by the object is moving

F = fr + m * a

  = (mu * N) + ma                                          where N = mg

  = (mu * mg) + ma

  = (0.35 * 10 * 9.8) + 10 * 2

  = 54.3 N

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Mechanical energy  type of energy is the sum of kinetic and potential energy in an object that is used to do work.

Potential energy plus kinetic energy are combined to form mechanical energy. It refers to the power underlying an object's location and motion. A compressed spring, for instance, has mechanical energy in the form of potential energy, while a moving vehicle has mechanical energy in the form of kinetic energy.

A sequence of blades installed on a rotor shaft in a turbine generator are pushed by a flowing fluid, including such air, water, steam, combustion gases, or water. A generator's rotor shaft rotates or spins due to the fluid's force on the blades. In turn, the generator converts the rotor's physical (kinetic) energy into electricity.

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ANSWER

B) 8.00 J

EXPLANATION

Given:

• The force applied to move the block, F = 4.00N

• The distance the block is moved, d = 2.00 m

Unknown:

• The work done on the block, W

If there is no friction between the block and the table, the only force acting upon the block in the direction of movement is the applied force F. Since the force is applied in the direction of movement, then the angle between the force and the displacement is 0, so the work done on the block is,

Hence, the work done on the block is 8.00 J.

A car is driving with a constant velocity around a circular track. The track’s radius is 156.1 m, and the car returns to its starting position in

49.3 s the car’s centripetal acceleration is 0.327 m/sec².

Rate of change of velocity with respect to time is called acceleration.

when the magnitude of velocity is constant and direction is changing

than the acceleration is centripetal acceleration.  

Given that is question radius of track  is 156.1 m and  car returns to its starting position in 49.3 s.

Velocity of car = Circumference of Circle / total time

                        = 352.308/ 49.30

                 v     = 7.14 m/sec

Centripetal acceleration = v²/r

                                         = 51.06/156.1

                                         = 0.327 m/sec²

The car’s centripetal acceleration is  0.327 m/sec².

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When a ladder with 20 ft. long is pulled along the floor away with a constant rate 1.2 ft/s, then the top of the ladder is moving toward the floor with velocity - 0.9 ft/s and there is no acceleration.

Let:

x = the distance between the bottom of the ladder from the wall

y =  the distance between the top of the ladder from the floor

When x = 12 ft, then using the Pythagorean Theorem:

x² + y² = 20²    (Equation 1)

12² + y² = 20²

y² = 20² - 12² = 16²

y = 16 ft.

Take the derivative of equation 1 with respect to t

2x . dx/dt + 2y. dy/dt = 0

Substitute x = 12, y = 16, dx/dt = 1.2 ft/s

2 . 12 . (1.2) + 2 . 16 . dy/dt = 0

dy/dt = - 0.9 ft/s

Hence, the velocity is - 0.9 ft/s

Since the floor is moving with a constant rate, the acceleration is zero.

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Answer:

Explanation:

 Given:

L  = 881.0  m

F = 28.0 N

___________

A - ?

The work :

A = L*F = 881.0 * 28.0 ≈ 24 670  J

The period of a satellite orbiting mercury 265,000 m above its surface is 100 minutes if the radius of the planet mercury is 2.43*10^6m and its mass is 3.2*10^23 kg.

v = √ G M / r

r = R + d

v = Orbital velocity

G = Gravitational constant

M = Mass of planet

r = Radius of the orbit

R = Radius of planet ( mercury )

d = Distance from surface to satellite

m = 3.2 * [tex]10^{23}[/tex] kg

R = 2.43 * [tex]10^{6}[/tex] m

d = 265000 m

G = 6.67 * [tex]10^{-11}[/tex] N m² / kg²

r = R + d

r = 2.43 * [tex]10^{6}[/tex] + 265000

r = 2.695 * [tex]10^{6}[/tex] m

v = √ ( 6.67 * [tex]10^{-11}[/tex] * 3.2 * [tex]10^{23}[/tex] ) / 2.695 * [tex]10^{6}[/tex]

v = √ 7.92 * [tex]10^{6}[/tex]

v = 2.81 * 10³ m / s

v = 2.81 km / s

v = 2 π r / T

T = Time period

T = 2 * 3.14 * 2.695 * [tex]10^{6}[/tex] / 2.81 * 10³

T = 6.02 * 10³ s

T = 100 minutes

Therefore, the period of a satellite orbiting mercury is 100 minutes

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The importance of the pressure t exerted via the string connecting the bins evaluate to the value f is T< f.

A force is a power that can trade the movement of an object. A force can encourage an item with mass to exchange its tempo, i.e., to boost up. stress can also be described intuitively as a push or a pull. A strain has both importance and path, making it a vector quantity.

considering both masses together

The acceleration of the system = a

a = f/m+m = f/2m

Now, considering one mass towards left m

T = ma

T = (f/2m)

m = f/2

T = f/2

T<f

Therefore, T must have a magnitude less than f.

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